Mares Medrano Cynthia Fernanda

Por integraciòn numèrica

∫1

6

ex2

dx

n=5

y=f(x) X simpson 3/8 simpson 1/8

2.718281828 1 x0

54.59815 2 x1

8103.083915 3 x2

8886110.496 4 x3 x0

72004899033 5 x1

4.31123x1015 6 x2

∫x0

x3

ex2

= 38

[ (2.718281828⧾8886110.496)⧾2 (54.59815 )⧾3 (8103.083915 ) ]⧾Er=¿

13329207.75

∫x0

x2

ex2

= 13

[ (8886110.496⧾4.31123E15 )⧾4 (72004899033 )⧾3 (0 ) ]⧾ Er=¿1437173192000000

∫1

6

ex2

dx= ∫x0

x2

ex2 ⧾ ∫

x0

x3

ex2 = 1437173205000000