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4/18/2011 The Short Circuit Current Gain lecture 1/8 Jim Stiles The Univ. of Kansas Dept. of EECS The Short-Circuit Current Gain hfe Consider the common emitter “low-frequency” small-signal model with its output short-circuited. + v be - r π m be g v ( ) b i ω C o r ( ) c i ω + v ce - ( ) i v ω B + - E

The Short Circuit Current Gain Lecture

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  • 4/18/2011 The Short Circuit Current Gain lecture 1/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    The Short-Circuit Current Gain hfe

    Consider the common emitter low-frequency small-signal model with its output short-circuited.

    + vbe -

    r m beg v

    ( )bi

    C

    or

    ( )ci

    + vce -

    ( )iv

    B

    + -

    E

  • 4/18/2011 The Short Circuit Current Gain lecture 2/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Boring! Tell me something I dont already know

    In this case we find:

    ( ) ( )( )

    c m be

    m b

    i g v g r i

    ==

    But we know that:

    C CTm

    T B B

    I IVg r V I I

    = = =

    Therefore: ( )( )

    c

    b

    i

    i =

    Just as we expected!

  • 4/18/2011 The Short Circuit Current Gain lecture 3/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    When the input signal is changing rapidly Now, contrast this with the results using the high frequency model: Evaluating this circuit, it is evident that the small-signal base current is:

    ( )1( ) ( )b

    i v j C Cr

    = + +

    While the small-signal collector current is: ( )( ) ( )c m i v g jC=

    + vbe -

    r mg v

    B C

    or + vce -

    C

    C

    ( )bi ( )ci

    + -

    ( )iv

    E

    - vce +

  • 4/18/2011 The Short Circuit Current Gain lecture 4/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Heres something you did not know Therefore, the ratio of small-signal collector current to small-signal base current is:

    ( )( )( ) 1

    m c

    b

    r g j r Ci i j r C C

    = + +

    Typically, we find that m g C , so that we find:

    ( )( )( ) 1

    mc

    b

    r gi i j r C C

    + +

    and again we know:

    C CT m

    T B B

    I IVr g V I I

    = = = Therefore:

    ( )( )( ) 1

    c

    b

    i i j r C C

    + +

  • 4/18/2011 The Short Circuit Current Gain lecture 5/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Your BJT is frequency dependent! We define this ratio as the small-signal BJT (short-circuit) current gain,

    ( )feh :

    ( )( )

    ( )( ) 1

    cfe

    b

    i h i j r C C

    + +

    Note this function is a low-pass function, were we can define a 3dB break frequency as:

    ( )1

    r C C

    = +

    Therefore: ( )

    ( )( ) 1

    cfe

    b

    i h i j

    +

  • 4/18/2011 The Short Circuit Current Gain lecture 6/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    This is how we define BJT bandwidth Plotting the magnitude of ( )feh (i.e.,

    2( )feh ) we find that:

    We see that for frequencies less than the 3 dB break frequency, the value of

    ( )feh is approximately equal to beta:

    ( )fe h <

    log

    2(dB)( )hfe

    2log

    T 0 dB

    20 dB/decade

  • 4/18/2011 The Short Circuit Current Gain lecture 7/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    This should SO remind you of op-amps

    Note then for frequencies greater than this break frequency:

    ( )1fe

    h j

    j

    =+

    >

    Note then that ( ) 1feh = when = . We can thus define this frequency as T , the unity-gain frequency:

    T

    so that: ( ) 1.0fe Th = =

  • 4/18/2011 The Short Circuit Current Gain lecture 8/8

    Jim Stiles The Univ. of Kansas Dept. of EECS

    Dj vu; all over again We can therefore state that:

    ( ) Tfe h

    = >

    and also that:

    ( )fe h <