THUYẾT MINH ĐỒ ÁN CÔNG NGHỆ CHI TIẾT DẠNG TRỤC

Sinh vin thc hin: Nguyn Quyt GVHD: Trng Honh Sn CTM1-K53 MSSV: 20082150

n mn hc cng ngh ch to my Page 1

I HC BCH KHOA H NI Cng ha x hi ch ngha Vit Nam

VIN C KH c lp- t do- hnh phc

B MN CNG NGH CH TO MY

NHIM V:

THIT K N MN HC CNG NGH CH TO MY

H v tn: Nguyn Quyt lp: CTM1-K53

I/ u thit k:

Thit k quy trnh cng ngh ch to chi tit dng: TRC

II/ Cc s liu ban u:

Sn lng hng nm: 10000 chi tit

iu kin sn xut: my cng c truyn thng

III/ Ni dung cc phn thuyt minh v tnh ton:

1. Phn tch chc nng lm vic ca chi tit

2. Phn tch tnh cng ngh trong kt cu ca chi tit

3. Xc nh dng sn xut

4. Chn phng php ch to phi

5. Lp th t cc nguyn cng (v s g t,k hiu,nh v,kp

cht,chn my,chn dao,k hiu chiu chuyn ng ca dao v chi tit)

6. Tnh lng d cho mt b mt(mt trn ngoi,trong hoc mt

phng)V tra lng d cho cc b mt cn li

7. Tnh ch ct cho 1 nguyn cng(cho nguyn cng cn thit k

g) v tra ch ct cho cc nguyn cng cn li

8. Tnh thi gian gia cng c bn cho tt c cc nguyn cng.

9. Tnh v thit k 1 g( s g t,lc kp,thit k cc c cu ca

g,tnh sai s chun,sai s kp cht,sai s mn,sai s iu chnh,sai s ch



to cho php,t yu cu k thut ca g,lp bng k khai cc chi tit

g, thit k g gia cng t kch thc,tp thuyt minh phi c bn gc

nhim v thit k v bn v chi tit)

IV/ Phn bn v:

1. Chi tit lng phi: 1 bn (kh A0 hay A1)

2. S nguyn cng: 1 bn ( kh A0)

3. g: 1 bn ( kh giy A0 hay A1)

H ni ngy 30 thng 8 nm 2011

Ngi nhn: ging vin hng dn:

(h tn v ch k) (h tn v ch k)



Li ni u

Mn hc cng ngh ch to my ng vai tr quan trng trong

chng trnh o to k s v cn b k thut v thit k v ch to cc loi

my, cc thit b phc v cc ngnh cng nghip, nng nghip, giao thng

vn ti ...

n mn hc cng ngh ch to my k 9 l mt trong cc n c

tm quan trng nht i vi mt sinh vin khoa c kh. n gip cho sinh

vin hiu nhng kin thc hc khng nhng mn cng ngh ch to my

m cc mn khc nh: my cng c, dng c ct... n cn gip cho

sinh vin c hiu dn v thit k v tnh ton mt qui trnh cng ngh ch

to mt chi tit c th.

c s gip v hng dn tn tnh ca thy Trng Honh Sn

trong b mn cng ngh ch to my n nay n mn hc ca em

hon thnh. Tuy nhin vic thit k n khng trnh khi sai st em rt

mong c s ch bo ca cc thy v s ch bo ca cc bn.

Em xin chn thnh cm n thy Trng Honh Sn gip em

hon thnh cng vic c giao.

H Ni, ngy 06/8/2011



I.Phn tch chc nng lm vic ca chi tit:

*Chi tit tit c thit k l chi tit Trc Qut Trn:

Vi sn lng 10.000 chic/ nm iu kin sn xut truyn thng

- Vt liu ch to trc l thp C45.

- chi tit chu ti trng v mment xon kh ln

- Nhng kch thc quan trng l nhng b mt lp ghp, i hi chnh

xc cao v hnh dng hnh hc v v tr tng quan.Nhng b mt ny i

hi pha m bo bng b mt, ng tm, vung gc cc b mt

cn thit trc lm vic c lu di, trnh gy mi mn cho cc b

mt.

-kch thc on trc c ng knh 17dng lp ln nh hng ln nht ti cht lng chi tit,cc b mt khc t nh hng ti cht lng ca

chi tit

* Cc yu cu k thut ca chi tit l:

- Mt tr A cn c gia cng vi chnh xc, bng b mt cao

lp vi chi tit khc.

- ng tm gia mt lp ghp A v 17 l 0,02mm. - vung gc gia cc ng tm phi chnh xc, nm trong khong 0,1

/100mm bn knh.

II. Phn tch tnh cng ngh trong kt cu ca chi tit:

- Trc c ng knh gim dn v hai pha cc b mt ca trc c kh nng

gia cng c bng cc dao thng thng c th tin dao thng sut

- ng knh trc nh nht c th m vn m bo chc nng lm vic



- L/D



Trong :

Q1: khi lng ca chi tit

V: th tch ca chi tit

: khi lng ring ca vt liu

Th tch ca chi tit (tnh gn ng):

V=L.d2/4=11.73.142.22/4= 0.0445(dm3)

Vi thp = 7.852 Kg/dm3

Ta c: Q=0.04457.852=0.350(Kg)

Da vo gi tr tnh toan cua N v Q1 tra bangr 2.6 ta xc nh dc dng

sn xut ca sn phm l lot ln

IV.Chn phng php ch to phi

Dng sn xut l lot ln, chi tit l trc bc c chnh ng knh khng

ln nn ta dng phi cn nng, tit din trn cho chnh xc thng v

cao, gim ng k c lng d gia cng, gp phn gim gi thnh sn

phm.

V.Th t nguyn cng

5.1 Thit k s b nguyn cng

* Nguyn cng 1: gia cng to chun

Kha mt u v khoan hai l tm: tin hnh trong mt nguyn cng, ng

thi thc hin phay mt u v hai khoan l tm c hai pha trn ma

chuyn dung

*Nguyn cng 2: tin th v tin tinh mt ngoi ca trc



G trc trn hai mi tm ca my tin ren vt vn nng, tin th v tinh

trong mt ln g t tin th mt ngoi,tin tinh on trc c ng knh

17 dng lp ln *Nguyn cng 3: ln nhm on trc c ng knh 19 dng l Stato *Nguyn cng 4: Khoan, doa l 6 trn my khoan ng *Nguyn cng 5: Khoan l 8 trn my khoan ng *Nguyn cng 6: Khoan cc l 6,8 trn my khoan ng *Nguyn cng 7: nhit luyn chi tit t cng yu cu

*Nguyn cng 8: mi th, mi tinh on trc c ng knh 17 dng lp ln.Mi phng mt phn trn trc tai v tr cn gia cng l trn trc trn

my mi chuyn dung

*Nguyn cng9: kim tra ng tm ca on trc lp ln

5.2 Thit k nguyn cng

*Nguyn cng 1:kha mt u v khoan l tm

-nh v v kep cht: dy l nguyn cng u tin nn chun gia cng l



chun th,l mt tr ngoi ca phi.Chi tit gia cng c nh v v kp

cht trn khi V t nh tm

-Chn my:chon may chuyn dng 6902M2 cng sut ng c N = 3kW(tra bng 9-31s tay CNCTM tp 3)

-chn dao : dao phay mt u bng thp gi P18 c kch thc D = 50mm,L

=36mm, d = 22mm, s rng 10 (tra bng 4-92 s tay CNCTM tp 1)

Mi khoan tm chuyn dng P18

*Nguyn cng 2: tin th, tin tinh, mt ngoi ca trc

-nh v v kp cht:nh v bng 2 l tm, g trn hai mi tm.dng tc

kp truyn chuyn ng quay cho trc.lc kp theo phng dc trc

-Chon my: my tin ren vt vn nng 1K62

-Chn dao: dao tin ngoi thn thng gn mnh hp kim cng

Kch thc H = 16mm; B = 10mm; L =100mm ; = 45 dao tin rnh thn cong gn mnh thp gi P18

Kch thc H = 16mm; B = 10mm; L =100mm

(tra bng 4-5 v 4-8 s tay CNCTM tp 1)



*Nguyn cng 3:ln nhm on trc 19

-nh v v kp cht:nh v bng 2 l tm, g trn hai mi tm.dng tc

kp truyn chuyn ng quay cho trc.lc kp theo phng dc trc

-Chn my :my mai trn ngoi 3A130

-Dng c ln nhm : S dng con ln tr

*Nguyn cng 4: khoan doa l 6



-nh v v kp cht: dnh v bng 2 khi V ngn khng ch 4 bc t do,vai

trc t ln than khi V khng ch 1 bc t do

-Chn my: my khoan ng 2A125 c dng knh mi khoan c bn

trung bnh ln nht l 25.Cng sut ca my N = 2.8kW(tra bng 9-1b s tay CNCTM tp 3)

-Chon dao:- mi khoan rut g bng thp gi ui cn,loi ngn c ng

knh d =5.8mm c cc kch thc: chiu di L =138mm,chiu di lm vic l

=57mm, mi doa lin khi chui tr P18 c kch thc D = 2 16mm, L =

49170mm, l =11 52mm(tra bng 4-42 ; 4-47s tay CNCTM tp 1)

*Nguyn cng 5: khoan l 8 -nh v v kp cht: dnh v bng 2 khi V ngn khng ch 4 bc t do,vai

trc t ln than khi V khng ch 1 bc t do

-Chn my: my khoan ng 2A125 c dng knh mi khoan c bn

trung bnh ln nht l 25.Cng sut ca my N = 2.8kW(tra bng 9-1b s tay CNCTM tp 3)



-Chon dao :- mi khoan rut g bng thp gi ui cn,loi ngn c ng

d =8mm c cc kch thc: chiu di L=156mm,chiu di lm vic l= 75mm

*Nguyn cng 6:khoan l 8, khoan l 12 -nh v v kp cht: dnh v bng 2 khi V ngn khng ch 4 bc t do,u

trc t ln phin t khng ch 1 bc t do lc kp theo phng vung gc

vi trc.

-Chn my: my khoan ng 2H125 c dng knh mi khoan c bn

trung bnh ln nht l 25.Cng sut ca my N = 2.8kW (tra bng 9-1b s tay CNCTM tp 3)

-Chon dao :- mi khoan rut g bng thp gi ui cn,loi ngn c ng

knh d =12mm c cc kch thc: chiu di L =182mm,chiu di lm vic l

= 101mm v d = 8mm c cc kch thc: chiu di L =156mm,chiu di lm

vic l = 75mm (tra bng 4.42 s tay CNCTM tp 1)



*Nguyn cng 7: nhit luyn v sa li l tm

*Nguyn cng 8:mi 2 mt tr ngoi 17 nh v v kp cht:nh v bng 2 l tm, g trn hai mi tm.dng tc kp

truyn chuyn ng quay cho trc.lc kp theo phng dc trc

-Chn my :my mi trn ngoi 3A110B,my c cng sut la N = 2,2 kW

-Chon :chn loi profin thng co kich thc D =325mm H = 1 40 mm,d = 1 68mm(tra s bng 4-170tay CNCTM tp 1)



*Nguyn cng 9 :kim tra

VI.Tnh ton lng d gia cng

V chi tit gia cng dc g trn 2 mi tm nn sai s g t theo phng

hng knh trong trng hp ny gd=0.



Lng d gia cng ti thiu c tnh theo cng thc:

2Zmin=2(RZ i-1+Tai-1+i-1) Sai lch v v tr khng gian ca phi c xc nh nh sau:

= (c2+ lt2 )1/2

c: lch tm l Ta c: c =k.L k: cong n v trn 1mm chiu di. L: chiu di mt gia cng L= 61mm

Tra bng 3.7 HDTK ACN CTM k= 0.15m c= 0.1561=9.15m lt: cong tm lt=( ph2/4 + 0.252)1/2 ph tra bng 3.53 S tay CNCTM tp 1 ta c c=1.1mm 0.25_ sai s do iu chnh my khi khoan l tm

lt=( 1.12/4 + 0.252)1/2 = 0.604 = 604m Do sai lch v v tr khng gian ca phi l: = (6042 + 9.152)1/2 604m Sai lch khng gian cn li sau tin th

1 = 0.06 ph = 0.06 604 = 37m Sai lch khng gian cn li sau tin tinh

2 = 0.04 ph = 0.04 604 = 25m Sai lch khng gian cn li sau tin th

3 = 0.02 ph = 0.02 604 = 12m



Gi tr Ta , Rz ca bc cng ngh tra theo bng 3.5 HDTKDACNCTM

Dung sai ca mi bc cng ngh tra bng 3.91 S tay CNCTM tp 1

Ta c :

Lng d ti thiu sau khi tin th :

2Zmin1 =2(150 + 150 + 604) = 2 904m

Lng d ti thiu sau khi tin tinh

2Zmin2 =2(50 + 50 + 37) = 2 137m

Lng d ti thiu sau khi mi th :

2Zmin3 =2(30 + 30 + 25) = 2 85m

Lng d ti thiu sau khi mi tinh :

2Zmin4 =2(10 + 20 + 12) = 2 42m

Kch thc tnh ton cc chi tit :

Mi th : dt3 = 17.001 + 2 0.042 = 17.085 mm

Tin tinh : dt2 = 17.084 + 2 0.085 = 17.225 mm

Tin th : dt1 = 17.225 + 2 0.137 = 17.592 mm 17.6 mm Phi : dph = 17.592 + 2 0.904 = 19.337 mm 19.4 mm Kch thc gii hn ln nht :

Mi tinh : dmax4 = 17.001 + 0.013 = 17.014 mm

Mi th : dmax3 = 17,085 +0.085 = 17.137 mm

Tin tinh: dmax2 = 17.225 + 0.130 = 17.355 mm

Tin th : dmax1 = 17.8 + 0.210 = 18.01 mm

Phi : dmaxph = 19.4 + 1.1 = 20.5 mm

Lng d gii hn :



Zghimax : lng d gii hn ln nht

Zghimim : lng d gii hn nh nht

Ta c :

Mi tinh : 2Z4max = 17.137 17.014 =123m

Mi th : 2Z3max= 17.385 17.137 =248m

Tin tinh : 2Z2max = 18.01 17.385 =625m

Tin th : 2Z1max= 20.05 18.01 =2490m

Mi tinh : 2Z4min = 17.085 17.001 =84m

Mi th : 2Z3min = 17.225 17.085 =170m

Tin tinh : 2Z2min = 17.60 17.255 = 345m

Tin th : 2Z1min = 19.4 17.6 =1800m

Lng d tng cng ln nht:

Z0max = Zmax = 123 + 248 + 624 +2490 =3486 m Lng d tng cng nh nht:

Z0min = Zmin = 84 + 170+ 345 +1800 =2399 m Lng d danh ngha :

Z0dn = Z0min +700 1 =3098m

700_ gii hn di ca phi

1_ gii hn di cua chi tit

Kch thc danh ngha ca ng knh :

d0dn= 17.001 + 3.098 =20.099 mm 20.1mm



Kim tra chnh xc ca tnh ton th hin :

Z0max Z0min =ph ct Tht vy:

3486 2399 =1100 13 =1087

Lng d gia cng cc kch thc gii hn trung gian ca mt trc

Bc

cng ngh

Cc thnh phn ca

lng d (m)

Lng

d tnh

ton

Zmin

(m)

Kch

thc

tnh

ton dti

(mm)

Dung

sai (mm)

Kch thc gii

hn (mm)

Lng d

gii hn

(m)

Rza

Ta a

b

dmin dmax Zbmin Zbmax

Phi 150 150 604 0 - 20,5 1,1 19,4 20,5 - -

Tin th 50 50 37 0 2904 17,8 0,21 17,8 18,01 1800 2490 Tin tinh 30 30 25 0 2137 17,225 0,13 17,225 17,355 345 625 Mi th 10 20 12 0 285 17,085 0,085 17,085 17,137 170 248 Mi tinh 5 15 - 0 242 17,001 0,013 17,001 17,014 84 123 Tng cng

2399 3486

*Tra lng d cho cc b mt cn li:

-kha mt u: 3mm

-Doa l 6: 0,1mm -khoan l 12: 2mm



VII.Xc inh ch ct

7.1 tnh ch ct cho nguyn cng thit k g

a. khoan l 8 bng mi khoan rut g thp gi, D = 8 mm *Chiu su ct , t= 4 mm

*Lng chy dao S

Theo bng 5-25 ( STCNCTM) tp 2 ta c :

Lng chay dao th Ssb = 0.150.2 (mm/vng)

Chn Ssb = 0.2 mm/vng

S = Ssbkhc = 0.2 (0.910.751) = 0.135mm/vng

Chn S = 0.15mm/vng

* Tnh tc ct khi khoan l :

. Vt= ymv

qv

STKDC

+ H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1 , ta c:

+ H s Cv=7 q=0.4 y=0.7 m=0.2

+ H s iu chnh chung cho tc ct tnh n cc i kin thc t :

Kv=Kmv.Kuv.Klv

+ Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)

Kmv=

vn

b

750=

9.0

610750

= 0.83

+ Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6

STCNCTM1)Kuv=1

+ Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)



Klv= 1

Tui bn trung bnh ca mi khoan T=25(pht) (bng 5-30 STCNCTM1)

Vt = 1183.015.02587

7.02.0

4.0

=26.49(m/pht)

S vng quay trc chnh l :

nt=

D

Vt.

.1000

=814.349.261000

=1054.54(vng/pht)

+Chn theo my nm = 1120 (vng/pht) , cp tc 10 . Do

Vt = 100011208

= 28.15 (m/pht)

* Tnh lc chiu trc Po (N) v m men xon M (Nm).

- Cng thc tnh l Po v m men xon M khi khoan l l .

. pyq

M kSDCx = 10 ; pyq

p kSDC = 10

-Tr s Cm ;Cp v cc s m c tra trong bng 5-32 .

CM = 0.0345 , q=2 , y=0.8 (h s cho m men )

CP = 68 , q=1 , y = 0.7

kP : H s tnh n cc yu t gia cng thc t

kP= kmP= 75.075.0

750610

=0.81

Mx= 100.034582 0.150.8 0.81 = 3.92 (N.m)

Po = 106880.15 0.70.81 = 1167.74( N )

- Cng thc tnh cng sut ct :



Ne = 9750.nM x = 3.921060/9750 = 0.43 kW

- So snh vi cng thc my :

Nc Ne - Ngha l : 0.047 kW 2.2 0.8 = 1.76 kW

- Vy my 2H125 cng sut gia cng l 8 b. khoan l 6 bng mi khoan rut g thp gi, D =5.8 mm *Chiu su ct , t= 2.9 mm

*Lng chy dao S


Lng chay dao th Ssb = 0.10.15 (mm/vng)

Chn Ssb = 0.15 mm/vng

S = Ssbkhc = 0.15 (0.910.751) = 0.1mm/vng

Chn S = 0.1mm/vng


. Vt= ymv

qv

STKDC

+ H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1, ta c:

Cv=7 q=0.4 y=0.7 m=0.2


Kv=Kmv.Kuv.Klv

Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)



Kmv=

vn

b

750=

9.0

610750

= 0.83

Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6 STCNCTM1)

Kuv=1

Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)

Klv= 1


Vt = 1183.01.0258.57

7.02.0

4.0

=30.9(m/pht)


nt=

D

Vt.

.1000

=8.514.39.301000

=1695.8(vng/pht)

- Chn theo my nm = 1500(vng/pht) , cp tc 11 . Do

Vt = 100015008.5

= 27.33 (m/pht)


- Cng thc tnh l Po v m men xon M khi khoan l l .

. pyq

M kSDCx = 10 ; p

yqp kSDC = 10

-Tr s Cp ; CMv cc s m c tra trong bng 5-32 .

CM = 0.0345 , q=2 , y=0.8 (h s cho m men )

CP = 68 , q=1 , y = 0.7



kP : H s tnh n cc yu t gia cng thc t kP= kmP=75.075.0

750610

=0.81

Mx= 100.03455.82 0.10.8 0.81 = 1.49 (N.m)

Po = 10685.80.1 0.70.81 = 637.4( N )

-Cng thc tnh cng sut ct:

Ne = 9750.nM x = 1.491500/9750 = 0.23 kW

- So snh vi cng thc my:

Nc Ne - Ngha l : 0.23 kW 2.2 0.8 = 1.76 kW

- Vy my 2H125 cng sut gia cng l 6 c. Doa l 6 bng , D =6 mm *Chiu su ct , t= 0.1 mm

*Lng chy dao S


Chn S = 0.8mm/vng


. Vt= yxmv

qv

StTKDC

. H s Cv v cc s m dng cho khoan cho bng 5-28 STCNCTM1 ,

ta c:

+ H s Cv=10.5 q=0.3 x = 0.2 y=0.65 m=0.4




Kv=Kmv.Kuv.Klv

. Kmv : h s ph thuc vo vt liu gia cng (bng 5-145-4)

Kmv=

vn

b

750=

9.0

610750

= 0.83

. Kuv: h s ph thuc vo vt liu dng c ct (bng 5-6

STCNCTM1)Kuv=1

. Klv: h s ph thuc vo chiu su khoan (bng 5-31 STCNCTM1)

. Klv= 1


Vt = 1183.08.01.02565.10

65.02.04.0

3.0

=7.54(m/pht)


nt=

D

Vt.

.1000

=614.354.71000

=400(vng/pht)

- Chn theo my nm = 450(vng/pht) , cp tc 7 . Do

Vt = 10004506

= 8.48 (m/pht)


- Cng thc tnh l Po v m men xon M khi doa l l .

. ZDStCx yzx

p

=10021

; p

yqp kSDC = 10

-Tr s CP v cc s m c tra trong bng 5-32 .

CP = 68 , q=1 , y = 0.7



kP : H s tnh n cc yu t gia cng thc t kP= kmP= 75.075.0

750610

=0.81

-Tr s Cp v cc s m c tra trong bng 5-23

Cp = 200 x = 1 y = 0.75

Mx= 2000.1 0.080.75 610 = 0.9 (N.m)

Po = 106860.08 0.70.81 = 564.04( N )

- Cng thc tnh cng sut ct :

Ne = 9750.nM x 0.9450/9750 = 0.042 kW

- So snh vi cng thc my :

Nc Ne - Ngha l : 0.042 kW 2.2 0.8 = 1.76 kW

- Vy my 2H125 cng sut gia cng l 6 7.2 tra ch ct ch nguyn cng cn li

*Nguyn cng 1

Phay mt u:lng chy dao Sz = 0.05 mm/vng(bng 5-119 S tay

CNCTM tp 2)

Vn tc ct V =54 m/ph

(bng 5-119 S tay CNCTM tp 2)

Tc quay ca trc chnh: n = DV

1000=

2414.3541000

=716 vng/ph

Ly theo my nm =750 vng/ph



Vn tc ct thc t V = 1000

24750 =57.3 m/ph

Khoan l tm

*Nguyn cng 2:

-Tin th 22 : chiu su ct t = 2mm

Lng chy dao S = 0.3 mm/vng (bng 5-60 S tay CNCTM tp 2)

Vn tc ct Vtb =106 m/pht

Tui bn dng c T = 90 pht (bng 5-66 S tay CNCTM tp 2)

Vc = Vtb hc = 1060.9110.9 =86.8 m/ph

Tc quay ca trc chnh: n = D

V

1000=

2414.38.861000

=1151 vng/ph



241000 =75.4 vng/ph

Cng sut ct N =1.7 kW (bng 5-68 S tay CNCTM tp 2)

Cng sut ca ng c N = 7.5k W. Vy Nyc



Tc quay ca trc chnh: n = DV

1000=

2214.38.861000

=1255 vng/ph



221250 =86.4 vng/ph





Tui bn dng c T = 90 pht (bng 5-66 S tay CNCTM tp 2)

Vc = Vtb hc = 1060.9110.9 =86.8 m/ph


V

1000=

1914.38.861000

=1454 vng/ph



191500 =89.5 vng/ph





Lng chy dao S = 0.1mm/vng

Tc ct V = 35m/ph


V

1000=

19351000

=586vng/ph



19600 =35.8 vng/ph





Vn tc ct thc t V =1000

12475 =17.9 m/ph

Cng sut ct N (tra bng 5-88 s tay CNCTM tp 2) N = 0.8 kW

So snh vi cng thc my :

Nc Ne - Ngha l : 0.8 kW 2.2 0.8 = 1.76 kW

-khoan l 8 Chiu su ct t = 4 mm

Lng chy dao S (tra bng 5-87 s tay CNCTM tp 2)

S=0.16mm/vng

Tc ct V (tra bng 5-86 s tay CNCTM tp 2) V =17m/ph

Tc quay trc chnh n = D

V

1000=

8171000

= 676 vng/ph

Ly theo my n = 600 vng/ph

Vn tc ct thc t V =1000

8600 =15 m/ph

Cng sut ct N (tra bng 5-88 s tay CNCTM tp 2) N = 0.8 kW

So snh vi cng thc my :

Nc Ne - Ngha l : 0.8 kW 2.2 0.8 = 1.76 kW Nguyn cng 7 :nhit luyn

Nguyn cng 8: mi trc 17 *mi th

Tra bng 5-203 s tay CNCTM tp 2



Lng chy dao ngang S = 3mm/ph

S vng quay ca chi tit nct = 300 vng/ph

*mi tinh

Tra bng 5-204 s tay CNCTM tp 2

Lng chy dao ngang S = 2.33mm/ph

S vng quay ca chi tit nct = 500 vng/ph

VIII. Tnh thi gian gia cng c bn cho tt c cc nguyn cng:

Thi gian gia cng cho cc nguyn cng c tnh nh sau:

Tng = Tcb + Tph + Tphv + Tk

- Tcb l thi gian gia cng c bn c tnh theo s gia cng c th

(bng 5.35.9)

- Tl thi gian ph Tph=10% Tcb

- Tpv l thi gian phc v: Tphv = Tpvkt + Ypvtc

Tpvkt: l thi gian phc v k thut Tpvkt=3% Tcb

Tpvtc: l thi gian phc v t chc Tpvtc=2% Tcb

Tphv =5% Tcb

- Tk l thi gian ngh ca cng nhn Tk=10% Tcb

Vy Tng = Tcb + Tph + Tphv + Tk=125%Tcb

Nguyn cng 1 : Kha mt u v khoan l tm

Khoan l tm: phtnSLL

Tcb 26,01,0.50067

.1

=

+=

+=

mmL

mmggdL

7

65,030cot215,3)25,0(cot

21

=

=+=+=



Phay mt u: phtnS

LLLTcb 099,05,0.75010522

.21

=

++=

++=

Thi gian ca nguyn cng 1: Tng1 = 1,25(0,26+0,099) =0,449 pht

Nguyn cng 2: Tin th v tin tinh ng knh trc

Tin th 22:

mmLmmL

mmtgtg

tL

1173)31(

32452)25,0(

2

1

=

==

=+=+=

pht

nSLLLTcb 41,03,01000

33117.

21=

++=

++=

Tin th 19:

mmLmmL

mmtgtg

tL

1053)31(

32452)25,0(

2

1

=

==

=+=+=

pht

nSLLLTcb 30,03,01250

33105.

21=

++=

++=

Tin th 16,5:

mmL

mmtgtg

tL

41

32452)25,0(1

=

=+=+=

pht

nSLLTcb 1,005,0.750

341.

1=

+=

++=

Tin bn tinh 17:



mmLmmL

mmtgtg

tL

92)31(

32452)25,0(

2

1

=

==

=+=+=

pht

nSLLLTcb 1,022,0.1500

2392.

21=

++=

++=

Tin tinh 17:

mmLmmL

mmtgtg

tL

92)31(

32452)25,0(

2

1

=

==

=+=+=

pht

nSLLL

Tcb 13,0213,0.15002392

.21

=++

=++

=

Tin sn rnh:

mmLmmL

12)31(2

=

==

pht

nSLL

Tcb 15,031,0.600213

.1

=+

=+

=

Tin vt mp:

mmLmmL

12)31(2

=

==

pht

nSLLTcb 06,021,0.1000

213.

1=

+=

+=

Thi gian ca nguyn cng 2:

Tng2 = 1,25(0,41+0,3+0,1+0,1+0,13+0,15+0,06) =1,563 pht



Nguyn cng 3:ln nhm

phtnthT

ctcb 11,001,0.450

5,025,1.

25,1 ===

Thi gian ca nguyn cng 3:Tng3 = 1,250,11=0,138

Nguyn ng 4: khoan doa l 6 Khoan:

mmL

mmL

mmgdDL

5,162)31(

7)25,0(cot2

2

1

=

==

=+

=

pht

nSLLL

Tcb 11,015,0.1500275,16

.21

=

++=

++=

Doa

mmLmmL

mmgdDL

5,162)31(

7)25,0(cot2

2

1

=

==

=+

=

pht

nSLLLTcb 08,08,0.400

275,16.

21=

++=

++=

Thi gian ca nguyn cng 4:Tng4 = 1,25(0,11 +0,08) =0,238 pht

Nguyn cng 5: khoan l 8

mmL

mmgdDL

13

10)25,0(cot21

=

=+

=

pht

nSLL

Tcb 14,015,0.11201013

.1

=

+=

+=

Thi gian ca nguyn cng 5:Tng5 = 1,250,14=0,175



Nguyn cng 6: khoan l 8; 12 L12

mmL

mmgdDL

34

14)25,0(cot21

=

=+

=

pht

nSLL

Tcb 51,02,0.4753414

.1

=

+=

++=

l 8

mmLmmmmL

mmgdDL

243)31(

10)25,0(cot2

2

1

=

==

=+

=

pht

nSLLLTcb 39,016,0.600

31024.

21=

++=

++=

Thi gian ca nguyn cng 6:Tng6 = 1,25(0,51+0,39) =1,125 pht

Nguyn cng 8: mi th v mi tinh

Mi th: Tcb = 0,15ld = 0,15917 =0,023 pht

Mi tinh: Tcb = 0,18ld = 0,18917 =0,028 pht

Thi gian ca nguyn cng 8:Tng8 = 1,25(0,023+0,028) =0,064 pht

Tng thi gian gia cng:

T=0,449+1,563+0,138+0,238+0,175+1,125+0,064 =3,752 pht

IX.thit k g gia cng chi tit

9.1Xc nh kch thc bn my : my khoan ng 2H125

Khong cch t ng tm truicj chnh ti tr : 250mm



Khong cch ln nht t mt trc chnh ti bn : 700mm

Kch thc b mt lm vic ca bn my : 400450 mmmm

Dch chuyn ln nht ca trc chnh : 170 mm

Lc tin dao : 900 kG

Cng sut ca my : 2.2 kW

9.2 Xc nh phng php nh v

S dng c nh v l 2 khi V ngn khng ch 4 bc t do,vai ca tr t vo

mt bn ca khi V khng ch 1 bc t do,.d tng cn vng cho chi tit

khi gia cng s dng them cht t ph t vo du trc 16.5 9.3 kch th nh v:

+phin dn +cht t ph



Khi V

9.4 xc nh phng chiu ca lc ct,lc kp

*lc ct:mi khoan di t trn xung,lc doc P tu tren xung,momen xoan

theo chieu quay cua mui khoan(nhu hinh ve)

*luc kp: phng ca lc kp vung gc vi trc,hng t trn

xung,im t ca lc gia hai khi V



9.5 xc nh lc kp

Khi khoan tat hay lc do li ct sinh ra c xu hng lam chi tit quay

quang trc ca n.do kt cu ca g nn khi khoan l 6 lc P0 c xu hng lm lt chi ti tit.nn khi tnh lc kp ta phi tnh cho ca 2 trng hp

*Khi khoan,doa l 6 momen xon ln nht khi ta khoan l nn lc kp dc tnh cho trng hp nguy him nht l khoan l.

n gin ta coi phn lc ti cht t ph bng lc dc trc khi khoan v

lc kp cht gy ra phn lc trn khi V

Ta c:

Mms = R ( N f1 + P0 f2 +Wf3 ) = K MX

N =

2sin

W

Suy ra:

2sin

13

20

ff

fPRMK

Wx

+

=

P0: lc ct theo phng thng ng

R: bn knh ca trc ti im nh v R=16,5mm

f1, f2 , f3: ln lt l h s ma st gia trc v khi V, cht t ph v m k ly: f1 =0,2 ; f2 = 0,3 ; f3 =0,45

K: h s an ton

K0: h s an tondnh mc.trong mi trng hp K0 =1.5

K1 :H s k dn lng d khng du khi gia cng K1 =1

K2: H s k n cn dao lm tng lc khi ct K2 =1.5

K3: H s k dn v ct khng lien tc lm tng lc ct K3 = 1



K4: H s k dn ngun sinh lc khng n nh khi kp bng tay K4 = 1.3

K5 :H s k nvij tr ca tay quay co cu kp c thun tin khng K5 =1

K6 :H s k n momen lt phi quay quang dim ta K6 =1

K = K0 K1 K2 K3 K4 K5 K6 =2,925

Thay s vo biu thc ta tnh c W = 99,5 N

9.6 chn c cu kp vad c cu sinh lc

C cu kp phi tha mn cc yu cu:khi kp phi gi ng v tr ca

phi,lc kp to ra phi ,khng lm bin dng chi tit,kt cu nh

gn,thao tc thun li v an ton.Vi cc yu cu dy ta chon c cu kp

bng ren vt n,sinh lc bng tay

9.7Xc nh sai s ch to cho php v yu cu k thut ca g:

*sai s ch to cho php Sai s g nh hng n sai s kch thc gia cng,nhng phn ln n

nh hng n sai so tng quan v tr gia b mt gia cng v b mt

chun.khi khoan chnh xc ca kch thc v v tr b mt gia cng ph

thuc vo v tr tng quan gia cc chi tit nh v trn g

Sai s g t dc tnh theo cng thc:

222222222 dcmctkcdgkcgd ++++=++=

Trong :

-c :sai s do chun nh v khng trng vi gc kch thc, y

chun nh v l mt ngoi ca trc,gc kch thc l ng tm ca trc

nn s c sai s chun,d thy sai s chun bng dung sai kch thc on

trc 17. Nn c = 30m -kc sai s do lc kp gy ra do



d thy kc = 0

-m : Sai s mn tnh theo cng thc

m= =0.18 Trong :

: h s ph thuc vo kt cu nh v N : s lng chi tit( 15000 chi tit)

Ta c: m = 0.1811000 =19 m -dc: sai s sinh ra do qu trnh lp rp v iu chnh g.Sai s iu

chnh ph thuc vo kh nng iu chnh v dng c iu chnh khi lp

rp.Trong thc t tnh ton ta c th ly dc =5m.

-gd: sai s g t, khi tnh ton g ta ly gi tr sai s g t cho

php [gd] =1/3 vi l dung sai nguyn cng gd =40 m - ct sai s ch to cho php ca g (cn xc nh khi ch to g)

[ct] c tnh theo cng thc: [ ] ( )22222 cmdckcgdct +++=

Thay s ta tnh c: [ ] ( ) mct 1830195040 2222 =+++=

*yu cu k thut ca g - khng song song gia dng tm ca khi V v mt phng y g

0,018mm/100mm chiu di. - ng lc tm ca hai khi V0,018mm/100mm bn knh -Sai s v tr tng quan ca cc chi tit trn g0,1mm/100mm chiu

di

-Cc chi tit nh khi V, bc dn, phin dn u phi gia cng t cp chin

xac cp 7, c ti t cng t 5060 HRC



-Hnh dng v yu cu k thut ca cc chi tit nh m kep, n kp, bu-

long dai c, vt,cht tr dm bo theo tiu chun quy nh ca nh nc.

-Thn g c kh ng sut d

-Cc cnh ca g khng c cnh sc. Dung sai cc kch thc t do c

chnh xc cp 8



TI LIU THAM KHO

1.Hng dn thit k n cng ngh ch to my

GS.TS. Nguyn c Lc-Lu Vn Khang

Nh xut bn khoa hc k thut-2006

2.S tay cng ngh ch to my tp:1,2,3

Ch bin: GS.TS. Nguyn c Lc


3.Atlat g

GS. TS. Trn Vn ch


4. g

GS. TS. Trn Vn ch


5.Cng ngh ch to my

Ch bin: GS.TS. Trn Vn ch




MC LC

Trang

Nhim v thit k 1

Li ni u 3

I.Phn tch chc nng lm vic ca chi tit 4

II. Phn tch tnh cng ngh trong kt cu ca chi tit 4

III. Xc nh dng sn xut 5

IV. Chn phng php ch to phi 6

V/. Lp th t cc nguyn cng 6

VI. Tnh lng d cho mt b m 13

VII. Tnh ch ct cho 1 nguyn cng 18

VIII. Tnh thi gian gia cng c bn cho tt c cc nguyn cng 30

IX. Tnh v thit k g 34

Ti liu tham kho 41

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