Trắc nghiệm môn thiết bị đo lường tự động

1NGN HNG CU HI TRC NGHIM MN THIT B & H THNG IU KHIN TNG

Chng 1 Khi nim chung1. H thng iu khin t ng gm mt ng vo, mt ng ra c xem l h thng iu khin:

A. SISOB. MIMOC. SIMOD. MISO

2. Trong s hnh v, chn pht biu ng:

A. Thnh phn (1) l ngun iu khin trong h thng sn xut t ngB. Thnh phn (2) thc thi gii thut iu khinC. S khng m t c phng thc iu khin trong h thngD. Thnh phn (3) quyt nh cht lng iu khin trong h thng

3. Chn pht biu ng cho cc ngun truyn ng ca h thng sn xut:A. H thng iu khin kh nn khng c kh nng iu khin tuyn tnhB. Ly hp l mt ngun truyn ng in-cC. Ngun truyn ng thy lc c c cu chp hnh l h pitng-xylanhD. H thng iu khin kh nn cho cng sut vn hnh ln.

4. Chn pht biu sai cho cc ngun truyn ng ca h thng sn xut:A. H thng iu khin kh nn c kh nng qu ti.B. Ngun truyn ng l ng c bc c chnh xc ph thuc vo gc bc.C. Ngun truyn ng thy lc c kh nng iu khin v tr chnh xcD. Cng sut vn hnh ca ngun thy lc b hn ngun kh nn.

5. Chn loi ngun truyn ng hp l cho m hnh iu khin trong hnh v

A. ng c mt chiu.B. ng c bc.C. ng c kh nn.D. ng c xoay chiu.

6. Chn pht biu ng v cc b iu khin dng trong h thng sn xut:

2A. Cc b iu khin logic kh trnh c u im hn so vi cc thit k iu khin theo tip im slng ng vo-ra trong h thng.B. Cc h thng nhng c kch thc nh gn.C. Mi gii thut iu khin qu trnh ch tng thch vi mt b iu khin.D. My tnh c th iu khin qu trnh m khng cn s h tr ca cc thit b ngoi vi thm vo.

7. Trong s iu khin vng kn truyn thng, thnh phn no c chc nng cung cp thng tint i tng:

A. B iu khinB. C cu chp hnhC. Cm binD. Tn hiu t

8. Loi cm bin no c th xc nh c v tr v khong cch:A. Cm bin loi ng ra analogB. EncoderC. Cm bin p sutD. Cc cu trn u ng

9. Chn loi cm bin o tc :A. Cm bin ng ra dng ON/OFFB. EncoderC. TachometterD. Cc cu trn u ng

10. Cc b iu khin PMAC(Programable Multi-Axies Controller) c s dng ch yu iukhin:

A. H thng nhngB. Cc my CNCC. Qu trnh cng nghip.D. H thng kh nn-thy lc.

11. H thng nhngB. Cc my CNCC. Qu trnh cng nghip.D. H thng kh nn-thy lc.

12. thit k h thng iu khin v n nh nhit , chng ta cn cc thnh phn no sau y:A. Cp nhit inB. Mch cng sutC. B iu khin v khuch i vi saiD. Cc cu trn u ng

13. Ch tiu u tin cn nh gi cho mt h thng iu khin t ng:A. chnh xc (Sai s)B. Tnh n nhC. vt lD. Thi gian p ng

14. Cm bin tch cc c u ra:A. Ngun p, ngun dngB. Ngun dng, in dungC. in cm, tng trD. Ngun dng, t cm

15. Bin tn l phn t no trong h thng iu khin tc ng c AC:A. B iu khinB. C cu chp hnhC. Ngun ng lcD. Tn hiu t cho u vo

316. Cm bin l thit b dng bin i cc i lng no sau y:a. i lng vt l.b. i lng in.c. i lng dng ind. i lng in p

17. Cm bin l thit b dng bin i cc i lng no sau y:e. i lng khng in.f. i lng in.g. i lng dng inh. i lng in p

18. Cm bin l k thut chuyn cc i lng vt l thnh:i. i lng khng in.j. i lng in.k. i lng p sut.l. i lng tc .

19. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) thm. (m) l i u ran. (m) l u voo. (m) l phn ng ca cm binp. (m) l i in

20. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) thq. (m) l i lng khng inr. (m) l i lng ins. (m) l dng int. (m) l tr khng

21. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) thu. (m) l i lng kch thch ca cm binv. (m) l i u ra ca cm binw. (m) l i lng phn ng ca cm binx. (m) l i lng in ca cm bin

22. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) th:a) (s) l i lng khng in ca cm binb) (s) l i lng in ca cm binc) (s) l i lng kch thch ca cm bind) (s) l i lng vt l ca cm bin

23. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) th:a) (s) l i lng khng in ca cm binb) (s) l i lng phn ng ca cm binc) (s) l i lng kch thch ca cm bind) (s) l i lng u vo ca cm bin

24. i lng (m) l i lng cn o ca cm bin c biu din bi hm s=F(m) th:y. (s) l i lng vt l ca cm binz. (s) l i lng u ra ca cm binaa. (s) l i lng kch thch ca cm binbb. (s) l i lng u vo ca cm bin

25. Mt cm bin c gi l tuyn tnh trong mt di o xc nh nucc. Trong di ch c nhy khng ph thuc vo i lng odd. Trong di ch c sai s khng ph thuc vo i lng oee. Trong di ch c nhy ph thuc vo i lng off. Trong di ch c sai s ph thuc vo i lng o

26. Phng trnh biu din ng thng tt nht c lp bng phng php no

4gg. Phng php tuyn tnhhh. Phng php phi tuynii. Phng php bnh phng ti thiujj. Phng php bnh phng ln nht.

27. ng cong chun ca cm bin l:A. ng cong biu din s ph thuc ca i lng in (s) u ra ca cm bin vo gi tr ca ilng o (m) u vo.B. ng cong biu din sai s ca i lng in (s) u ra ca cm bin v gi tr ca i lngo (m) u vo.C. ng cong biu din s ph thuc ca i lng khng mang in (s) u ra ca cm bin vogi tr ca i lng o (m) u vo.D. ng cong biu din s ph thuc ca i lng khng kch thch (s) u ra ca cm bin vogi tr ca i lng phn ng (m) u vo.

28. ng cong chun c th biu din:A. Bng lit kB. Biu thc i s v thC. nhyD. Sai s

29. Mc ch ca chun cm bin l :A. Xc nh tn hiu u ra cm bin thuc loi noB. Xc lp mi quan h gia i lng in u ra v i lng o, trn c s xy dng ngcong chunC. Xc nh sai lch trong qu trnh o ca cm binD. Tm c tnh vt l ca cm bin

30. Cng thc tng qut xc nh nhy ca cm bin :A. mSS = .

B.m

SS

=

C.imm

m

SS=

=

D.m

SS

=

31. Cc cm bin Analog thng cho mi quan h gia ng vo vt l v ng ra tnh cht in lng thng nh:

A. Loi b cc nh hng ca tc ng mi trng xung quanhB. Phng php tuyn tnh ha ng c tnh ca cm binC. Trit tiu sai lch trong qu trnh o ca cm binD. Chnh c nhy cho cm bin

32. Khi chun ho cm bin ta tin hnh vi N im o, phng trnh c dng: s = am + b, h s ac tnh

kk. ( )

= 22

...

ii

iiii

mmN

msmsNa

ll. ( )

= 22

2...

ii

iiiii

mmN

msmmsa

mm. ( )

+= 22

...

ii

iiii

mmN

msmsNa

5nn. ( )

+= 22

2...

ii

iiiii

mmN

msmmsa

33. Khi chun ho cm bin ta tin hnh vi N im o, phng trnh c dng: s = am + b, h s ac tnh

oo. ( )

= 22

...

ii

iiii

mmN

msmsNb

pp. ( )

= 22

2...

ii

iiiii

mmN

msmmsb

qq. ( )

+= 22

...

ii

iiii

mmN

msmsNb

rr. ( )

+= 22

2...

ii

iiiii

mmN

msmmsb

34. Xc nh pht biu ng cho cc loi sai s khi s dng cm bin:A. Sai s h thng khng khc phc c, cn sai s ngu nhin th c th khc phcB. Sai s h thng c th khc phc c, cn sai s ngu nhin th khngC. C sai s h thng v sai s ngu nhin u c th khc phcD. C sai s h thng v sai s ngu nhin u khng th khc phc

35. Cm bin nhit c ch to da trn nguyn l no sau y:A. Hiu ng nhit inB. Hiu ng ha nhitC. Hiu ng p inD. Hiu ng cm ng

36. Cm bin p lc c ch to da trn nguyn l no sau y:A. Hiu ng nhit inB. Hiu ng ha nhitC. Hiu ng p inD. Hiu ng cm ng

37. Cm bin o tc chuyn ng quay c th c ch to da trn nguyn l no sau y:A. Hiu ng quang inB. Hiu ng quang-in tC. Hiu ng p inD. Hiu ng cm ng in t

38. Hiu ng Hall c ng dng thit k loi cm bin no sau y:A. Cm bin o t thngB. Cm bin o bc x nh sngC. Cm bin o dng inD. Cm bin o tc

39. Hnh v sau m t cho nguyn l ch to ca cm bin no:

a. Hiu ng nhit inb. Hiu ng ho nhit

6c. Hiu ng p ind. Hiu ng cm ng in t


a. Hiu ng nhit inb. Hiu ng ho nhitc. Hiu ng p ind. Hiu ng cm ng in t


e. Hiu ng nhit inf. Hiu ng ho nhitg. Hiu ng p inh. Hiu ng cm ng in t


i. Hiu ng nhit inj. Hiu ng ho nhitk. Hiu ng p inl. Hiu ng cm ng in t


m. Hiu ng nhit inn. Hiu ng ho nhito. Hiu ng quang in tp. Hiu ng Hall


7q. Hiu ng nhit inr. Hiu ng ho nhits. Hiu ng quang in tt. Hiu ng Hall

45. Hnh v sau minh ha hot ng ca?

a/ Cm bin t. b/ Cm bin in cm.c/ ng dng ca cm bin HALL. d/ Cm bin dng hiu ng HALL

46. T hnh v p ng ca cm bin sau hy cho bit (tdm) gi l g?

u. Thi gian tr khi tngv. Thi gian tr khi gim

8w. Thi gian tngx. Thi gian gim

47. T hnh v p ng ca cm bin sau hy cho bit (tdc) gi l g?

y. Thi gian tr khi tngz. Thi gian tr khi gimaa. Thi gian tngbb. Thi gian gim

48. T hnh v p ng ca cm bin sau hy cho bit (tm) gi l g?

cc. Thi gian tr khi tngdd. Thi gian tr khi gimee. Thi gian tngff. Thi gian gim

49. T hnh v p ng ca cm bin sau hy cho bit (tc) gi l g?

9gg. Thi gian tr khi tnghh. Thi gian tr khi gimii. Thi gian tngjj. Thi gian gim

50. Cm bin tch cc l cm bin c p ng l:a. in tchb. in trc. t cmd. in dung

51. Cm bin tch cc l cm bin c p ng l:a. in pb. in trc. t cmd. in dung

52. Cm bin tch cc l cm bin c p ng l:a. Dng inb. in trc. t cmd. in dung

53. Cm bin th ng l cm bin c p ng l:a. in dungb. Dng inc. in pd. in tch

54. Cm bin th ng l cm bin c p ng l:a. t cmb. Dng inc. in pd. in tch

55. Cm bin th ng l cm bin c p ng l:a. in trb. Dng inc. in pd. in tch

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56. Vng lm vic nh danh ca cm bin l:a. L vng lm vic nh danh tng ng vi nhng iu kin s dng bnh thng ca cm bin.b. L vng m cc i lng nh hng cn nm trong phm vi khng gy nn h hng.c. L vng m cc i lng nh hng vt qua ngng ca vng khng gy nn h hng

nhng vn cn nm trong phm vi khng b ph hy.d. L vng m cm bin phi tin hnh chun li cm bin

57. Vng khng gy nn h hng:kk. L vng lm vic nh danh tng ng vi nhng iu kin s dng bnh thng ca

cm bin.ll. L vng m cc i lng nh hng cn nm trong phm vi khng gy nn h hng.mm. L vng m cc i lng nh hng vt qua ngng ca vng khng gy nn

h hng nhng vn cn nm trong phm vi khng b ph hy.nn. L vng m cm bin phi tin hnh chun li cm bin

58. Vng khng ph hu:oo. L vng lm vic nh danh tng ng vi nhng iu kin s dng bnh thng ca

cm bin.pp. L vng m cc i lng nh hng cn nm trong phm vi khng gy nn h hng.qq. L vng m cc i lng nh hng vt qua ngng ca vng khng gy nn h

hng nhng vn cn nm trong phm vi khng b ph hy.rr. L vng c th thng xuyn t ti m khng lm thay i cc c trng lm vic ca

cm bin.59. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in dung, ng ra thng hb. Cm bin in dung, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng60. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in dung, ng ra thng hb. Cm bin in dung, ng ra thng ng

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c. Cm bin siu m, ng ra thng hCm bin siu m, ng ra thng ng61. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in cm, ng ra thng hb. Cm bin in cm, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng62. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in cm, ng ra thng hb. Cm bin in cm, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng63. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in t, ng ra thng hb. Cm bin in t, ng ra thng ngc. Cm bin quang, ng ra thng hd. Cm bin quang, ng ra thng ng64. Cho bit hnh sau l k hiu ca cm bin loi:

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a. Cm bin t, ng ra thng hb. Cm bin t, ng ra thng ngc. Cm bin siu quang, ng ra thng hd. Cm bin siu quang, ng ra thng ng65. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin t, ng ra thng hb. Cm bin t, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng66. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin t, ng ra thng hb. Cm bin t, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng67. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in dung, ng ra thng hb. Cm bin in dung, ng ra thng ng

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c. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng68. Cho bit hnh sau l k hiu ca cm bin loi:

a. Cm bin in dung, ng ra thng hb. Cm bin in dung, ng ra thng ngc. Cm bin siu m, ng ra thng hd. Cm bin siu m, ng ra thng ng69. Hnh sau l cch mc ti cho:

ss. Cm bin ng ra loi PNPtt. Cm bin ng ra loi NPNuu. Cm bin ng ra loi relayvv. Cm bin ng ra loi Opto

70. Hnh sau l cch mc ti cho

ww. Cm bin ng ra loi PNPxx. Cm bin ng ra loi NPNyy. Cm bin ng ra loi relayzz. Cm bin ng ra loi Opto

71. Cho bit hnh sau l s mch o:

a. Nhit bng cp nhit inb. in th b mtc. Khuch i thut tond. Mch kh in p lch

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72. Cho bit hnh sau l s mch o:

a. Nhit bng cp nhit inb. in th b mtc. Khuch i thut tond. Mch kh in p lch73. Cho bit hnh sau l s mch o:



a. Nhit bng cp nhit inb. Cu Wheastonec. Khuch i thut tond. Mch kh in p lch

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Chng 2 Cm bin tim cn T - Dung - Siu m1. Cm bin tim cn l loi cm bin c ng ra dng:

a. ON/OFF.b. Analog.c. ON/OFF v Analog.d. Bt k.

2. Vng m ca cm bin siu m nm .a. Trc cm bin v nm ngoi tm o.b. Trc cm bin v nm hai bn bp hng.c. Mt khong ngn ngay trc mt cm bin.d. Sau cm bin.

3. Hin tng Forecasting l hin tng:a. L hin tng m cm bin siu m ny ghi nhn tn hiu phn x hoc trc tip t cm bin

siu m khc.b. L hin tng phn x gc sai lch ca cm bin.c. L hin tng c cho ca cm bin vi nhaud. L qu trnh sng siu m truyn i v phn x qua cc b mt ri quay li cm bin mt cch

khng mong mun..4. Hin tng crosstalk l hin tng:

a. L hin tng lm lch c khong cch ng, cm bin siu m phi hng vung gc vib mt chng ngi vt cn o

b. L hin tng m cm bin siu m ny ghi nhn tn hiu phn x hoc trc tip t cm binsiu m khc.

c. L hin tng phn x gc sai lch ca cm bin.d. L hin tng c cho ca cm bin vi nhau

5. Hin tng crosstalk l hin tng:a. L hin tng m cm bin siu m ny ghi nhn tn hiu phn x hoc trc tip t cm bin

siu m khc.b. L hin tng phn x gc sai lch ca cm bin.c. L hin tng lm lch c khong cch ng, cm bin siu m phi hng vung gc vi

b mt chng ngi vt cn od. L cc chm tia phn x c nng lng phn x thp hn.

6. Hin tng crosstalk l hin tng:a. L hin tng c cho ca cm bin vi nhau.b. L hin tng phn x gc sai lch ca cm bin.c. L hin tng lm lch c khong cch ng, cm bin siu m phi hng vung gc vi


7. Hin tng crosstalk l hin tng:a. L qu trnh sng siu m truyn i v phn x qua cc b mt ri quay li cm bin mt cch

khng mong mun.b. L hin tng phn x gc sai lch ca cm bin.c. L hin tng lm lch c khong cch ng, cm bin siu m phi hng vung gc vi


8. C my loi sinh ra hin tng crosstalk:a. Mt loi.b. Hai loi.c. Ba loi.d. Bn loi.

9. Hin tng no sau y l mt trong hai loi ca hin tng crosstalk:

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a. Hin tng cm bin siu m ny ghi nhn tn hiu ca cm bin siu m kia trn cng robot.b. Hin tng nhiu robot hot ng trong cng mt mi trng v cm bin siu m ny khng

ghi nhn c tn hiu ca cm bin siu m kia bng cch trc tip hoc gin tipc. Hin tng cm bin siu m ny ghi nhn tn hiu ca mi trng xung quanh.d. Hin tng cm bin siu m ny khng ghi nhn c tn hiu ca cm bin siu m kia trn

cng robot..10. Hin tng no sau y l mt trong hai loi ca hin tng crosstalk:

a. Hin tng cm bin siu m ny khng ghi nhn c tn hiu ca cm bin siu mkia trn cng robot.

b. Hin tng nhiu robot hot ng trong cng mt mi trng v cm bin siu m nyghi nhn tn hiu ca cm bin siu m kia mt cch trc tip hoc gin tip.

c. Hin tng nhiu robot hot ng trong cng mt mi trng v cm bin siu m nykhng ghi nhn c tn hiu ca cm bin siu m kia bng cch trc tip hoc gintip

d. Hin tng cm bin siu m ny ghi nhn tn hiu ca mi trng xung quanh.11. Sng siu m c truyn trong khng kh vi vn tc?

a. C= 343km/sb. C343m/sc. C434k m/sd. C = 434m/s

12. Khi dng cm bin siu m pht hin vt, cc vt no sau y c khong cch pht hin xanht:

a. Vt xp.b. Ba cc-tngc. Kim loid. Vt trong sut

13. Cm bin no sau y khng o c mc nc:A. Cm bin siu mB. Phao bin trC. Cm bin p sutD. Cm bin quang

14. S khc nhau c bn gia loi NPN v PNP ca cng mt loi cm bin:A. Thi gian p ngB. chnh xcC. Mc logic ng raD. nhy ca cm bin

15. Cm bin t khng c kh nng pht hin vt liu no sau y:A. Lon nhmB. Bn my bng thpC. Hp sa bng giyD. Mi khoan bng ng

16. Khong cch ci t tt nht cho cm bin tim cn t l:A. 50% - 60% khong cch pht hinB. 60% - 70% khong cch pht hinC. 70% - 80% khong cch pht hinD. 80% - 90% khong cch pht hin

17. S khc nhau chnh gia cm bin t khng tip im v cm bin in cm l:a/ Cu to ca cun dy to t trng. b/ B dao ng LC bn trong chng.c/ Mch pht hin ngng (trigger). d/ Tt c u sai.

18. Cm bin in cm pht hin kim loi da vo nguyn tc no sau y?.

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a/ Hnh thnh dng in xoy trn vt th lm mc tiu v tng dn bin dao ng mch LC.b/ Hnh thnh dng in xoy bn trong cm bin lm tng bin dao ng mach LC.c/ Hnh thnh dng in xoy trn vt th lm mc tiu dn n lm gim dn bin mch

LC.d/ Hnh thnh dng in xoy trn vt th lm mc tiu v cm bin lm tt LC.

19. Cm bin no c phm vi cm nhn thay i theo dy ca vt liu:A. Cm bin tim cn tB. Cm bin tim cn in cmC. Cm bin siu mD. Cm bin quang

20. Cm bin tim cn in dung c c tnh g:A. Ch pht hin vt lm t vt liu kim loiB. Pht hin cc vt lm t cc vt liu khc nhauC. Ch pht hin vt lm t vt liu phi kimD. Ch pht hin vt mang t tnh

21. u im ca cm bin tim cn in dung so vi cm bin tim cn t l:A. Khong cch pht hin vt xa hnB. C kh nng pht hin vt liu l cht lngC. Tn hiu ng ra l AnalogD. chnh xc cao hn

22. Ng ra ca cm bin siu m:A. Tn hiu Analog hay ON-OFF(Logic)B. Tn hiu v tuynC. Tn hiu khng in.D. Tn hiu in t

23. Ng ra ca cm bin tim cn t :A. AnalogB. ON-OFF(Logic)C. T trngD. Tn s

24. Ng ra ca cm bin quang l :A. AnalogB. ON-OFF (Logic)C. ON/OFF v AnalogD. Tn s

25. Khong cch tc ng (Rated Distance) Sn trong cm bin tim cn:a. L mt gi tr l thuyt m n khng ph thuc vo tnh ton nh sai s ca qu trnh

sn xutb. L khong cch hot ng tt iu kin ngun in cung cp n nh vi nhit dao

ng trong khong t 23oC 0.5oC.c. L khong cch chuyn mch c tnh ton theo iu kin in p v nhit l

thuyt.d. L khong cch chuyn mch cho s hot ng ca cm bin tim cn trong phm vi

iu kin hot ng c c th chp nhn c m bo.26. Khong cch hot ng hiu qu (Effective Operating Distance) Sr trong cm bin tim cn

a. L mt gi tr l thuyt m n khng ph thuc vo tnh ton nh sai s ca qu trnhsn xut

b. L khong cch hot ng tt iu kin ngun in cung cp n nh vi nhit daong trong khong t 23oC 0.5oC.

c. L khong cch chuyn mch c tnh ton theo iu kin in p v nhit lthuyt.

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d. L khong cch chuyn mch cho s hot ng ca cm bin tim cn trong phm viiu kin hot ng c c th chp nhn c m bo.

27. Khong cch hot ng chc chn (Guaranteed Operating Distance) Sa trong cm bin timcn

a. L mt gi tr l thuyt m n khng ph thuc vo tnh ton nh sai s ca qu trnhsn xut

b. L khong cch hot ng tt iu kin ngun in cung cp n nh vi nhit daong trong khong t 23oC 0.5oC.

c. L khong cch chuyn mch c tnh ton theo iu kin in p v nhit lthuyt.

d. L khong cch chuyn mch cho s hot ng ca cm bin tim cn trong phm viiu kin hot ng c c th chp nhn c m bo.

28. Khong cch chuyn mch hu ch (Useful Switching Distance) Su trong cm bin tim cn:a. L mt gi tr l thuyt m n khng ph thuc vo tnh ton nh sai s ca qu trnh

sn xutb. L khong cch hot ng tt iu kin ngun in cung cp n nh vi nhit dao

ng trong khong t 23oC 0.5oC.c. L khong cch chuyn mch c tnh ton theo iu kin in p v nhit l

thuyt.d. L khong cch chuyn mch cho s hot ng ca cm bin tim cn trong phm vi

iu kin hot ng c c th chp nhn c m bo.29. Hnh sau m t cho nguyn tc ch to cm bin tim cn g:

a. Cm bin t.b. Cm bin in dungc. Cm bin quangd. Cm bin sin m

30. Hnh sau m t cho hin tng ch to cm bin tim cn no:

a. Cm bin t.b. Cm bin in dung

19

c. Cm bin quangd. Cm bin sin m

31. Cm bin t khng c kh nng pht hin vt no sau y:A. Mi khoan bng ngB. Khun dp bng thpC. Chai thy tinhD. Np chai bng nhm

32. Chn cu hi sai m t cho vt chun khi s dng cm bin tim cn tA. Hnh dngB. Vt liuC. Kch cD. in p

33. Yu t no ca i tng khng nh hng n khong cch o ca cm bin t:A. Kch cB. Vt liuC. B dyD. Mu sc

34. Vt liu no c khong cch pht hin xa nht nu s dng cm bin tim t:A. NhmB. StC. ngD. Cht do

35. pht hin hp cha cht lng hay khng, ta c th s dng cm bin:A. Quang khuch tnB. in dungC. Tim cn tD. in cm

36. i vi cm bin tim cn. Nu vt tc ng ln b mt cm bin nh hn vt th chun (testobject) khong cch pht hin ca cm bin s:

a. Tng.b. Gim.c. Khng i.d. Khng th pht hin c.

37. i vi cm bin tim t. Cc vt liu c t tnh hoc kim loi c cha st s c khong cchpht hin nh th no so vi cc vt liu khng c cha t tnh hoc cha st

a. Gn hn.b. Xa hn.c. Khng nh hng.d. Khng th pht hin c.

38. i vi cm bin tim t. Cc vt cm bin thuc nhm kim loi khng c t tnh, khongcch pht hin cng xa th:

a. B dy ca vt cng mng.b. B dy ca vt cng dy.c. Khng nh hng.d. Khng th pht hin c.

39. Hnh v sau m t cho ta nguyn l hot ng ca loi cm bin no:

20

a. Cm bin in cm.b. Cm bin in dung.c. Cm bin quang.d. Cm bin siu m.

40. Cm bin tim cn loi in cm pht hin vt bng kim loi da vo nguyn tc no sau y?a.Hnh thnh dng in xoy trn vt cn pht hin v tng dn bin dao ng mch LC.b.Hnh thnh dng in xoy bn trong cm bin lm tng bin dao ng mach LC.c.Hnh thnh dng in xoy trn vt cn pht hin dn n lm gim dn bin mchLC.d.Hnh thnh dng in xoy trn vt cn pht hin v v khng lm thay i bin daong ca mch LC.

41. Chc nng ca cm bin tim cn loi in cm:a.Pht hin vt th kim loi.b.Pht hin vt th phi kim loi.c.Pht hin vt th c hng s in mi ln hn khng kh.d.Pht hin c c vt th bng kim loi ln phi kim.

42. Theo hnh bn di l dng ng ra ca mt loi cm bin (ON/OFF), ng ra ny c tn gi lgi?

a.Relayb.Reedc.PNPd.NPN

43. Theo hnh bn di l dng ng ra ca mt loi cm bin (ON/OFF), ng ra ny c tn gi lgi?

a.Relayb.Reedc.PNPd.NPN

44. Cch mc no l ng nht ?

21

a. c.

b. d.a.Hnh ab.Hnh bc.Hnh cd.Hnh d

45. Cch mc no l ng nht?

a. c.

22

b. d.a.Hnh ab.Hnh bc.Hnh cd.Hnh d

46. Nguyn tc hot ng ca cm bin tim cn loi in dung:a.S thay i t trng u cm bin khi c vt cn pht hin i vo vng pht hin cacm bin.b.Da theo nguyn tc tnh in (s thay i in dung gia vt cn pht hin v u cmbin).c.S thay i in dung gia vt cn pht hin v t.d. p lc tc ng ln u cm bin.

47. Chc nng ca cm bin tim cn loi in dung:a.Ging nh chc nng ca cm bin tim cn loi in cmb.C th pht hin ra mi loi vt thc.Ch pht hin c cc vt lm bng phi kim.d.Pht hin ra c cc vt th c hng s in mi ln hn hng s in mi ca khngkh.

48. Khi cm bin tim cn loi in dung pht hin ra vt th :a.Gi tr in dung to bi vt cn pht hin v u d cm bin gim.b.Gi tr in dung to bi vt cn pht hin v u d cm bin tng.c.Gi tr in dung to bi vt cn pht hin v u d cm bin dao ng lin tc.d.Gi tr in dung to bi vt cn pht hin v u d cm bin khng i.

49. pht hin c dch chuyn ca pittong trong xilanh th ngi ta thng dng cm bin g?a.Cm bin tim cn loi in cmb.Cm bin tim cn loi in dungc.Cm bin tim cn loi td.Cm bin quang.

50. pht hin ra s thay i ca mc cht lng trong bnh cha ta nn dng loi cm bin nosau y:

a.Cm bin tim cn loi in cmb.Cm bin tim cn loi in dungc.Cm bin tim cn loi td.Cm bin quang.

51. pht hin ra c hay khng c np chai(kim loi) trong dy chuyn sn xut nc ngt ta cth dng loi cm bin no sau y(chn cu ng nht):

a.Cm bin tim cn loi in cmb.Cm bin tim cn loi in cm hoc loi in dungc.Cm bin tim cn loi in dung.d.Cm bin t.

23

52. o m s vng xoay ca mt ng c th ngi ta s dng loi cm bin no sau y:a.Cm bin tim cn loi in cmb.Cm bin tim cn loi in cm hoc loi in dungc.Cm bin tim cn loi in dung.d.Cm bin t.

53. c im v ngun sng ca cm bin siu m?a.C tn s nh hn 10kHzb.C tn s nh hn 20kHzc.C tn s nm trong khon t 10kHz n 20kHz.d.C tn s ln hn 20kHz.

54. Cng dng ca cm bin siu m?a.Ch pht hin c vt bng kim loib.Ch pht hin c vt phi kimc.Pht hin ra tt c cc vtd.Ch pht hin ra c nhng vt c h s phn x sng m thanh ln.

55. c im ca cm bin siu m?a.Sng siu m ca cm bin c truyn i trong khng kh vi vn tc 300 m/sb.Sng siu m ca cm bin c truyn i trong khng kh vi vn tc 243m/sc.Sng siu m ca cm bin c truyn i trong khng kh vi vn tc 343 m/sd.Sng siu m ca cm bin c truyn i trong khng kh vi vn tc 143m/s

56. c im ca cm bin siu m?a.Qung ng i ca sng siu m cm bin siu m bng 2 ln khong cch t cmbin ti vt cn pht hin.b.Qung ng i ca sng siu m cm bin siu m bng 3 ln khong cch t cmbin ti vt cn pht hin.c.Qung ng i ca sng siu m cm bin siu m bng 4 ln khong cch t cmbin ti vt cn pht hin.d.Qung ng i ca sng siu m cm bin siu m bng 1 ln khong cch t cmbin ti vt cn pht hin.

57. Vng cht ca cm bin siu m?a.L vng m cm bin khng pht hin ra vt v nm lin k vi u d ca cm bin .b.L vng m cm bin pht hin ra vtc.L vng m cm bin pht hin ra vt nhng tin cy khng cao.d.L vng m cm bin khng pht hin ra vt , vng ny lun l vng sau lng vt cnpht hin.

58. nghing ca vt cn pht hin phi nh th no cm bin siu m c th pht hin ra vt?

a.+/- 3 .b.+-10 c.+/- 1 d.+/ -5

59. u im no ca cm bin siu m sau l nga. Khong cch m cm bin c th pht hin vt th xa.

24

b. Sng phn hi ca cm bin ph thuc mu sc ca b mc i tng hay tnh chtphn x nh sng ca i tng.

c. Tn hiu p ng ca cm bin tim cn siu m analog l t l phi tuyn vi khongcch.

d. Cho hu ht mi trng hp.60. u im no ca cm bin siu m sau l ng

a. Khong cch m cm bin c th pht hin vt th rt gn.b. Sng phn hi ca cm bin khng ph thuc mu sc ca b mc i tng hay tnh

cht phn x nh sng ca i tng.c. Tn hiu p ng ca cm bin tim cn siu m analog l t l phi tuyn vi khong

cch.d. Cho hu ht mi trng hp.

61. u im no ca cm bin siu m sau l nga. Khong cch m cm bin c th pht hin vt th rt gn.b. Sng phn hi ca cm bin ph thuc mu sc ca b mc i tng hay tnh cht

phn x nh sng ca i tng.c. Tn hiu p ng ca cm bin tim cn siu m analog l t l tuyn tnh vi khong

cch.d. Cho hu ht mi trng hp.

62. Nhc im no ca cm bin siu m sau l nga. Cm bin tim cn siu m yu cu i tng c mt din tch b mt ti thiu (gi tr

ny ty thuc vo tng loi cm bin).b. Sng phn hi cm bin nhn c hon ton khng chu nh hng ca cc sng m

thanh tp m.c. Cm bin tim cn siu m khng cn mt khong thi gian sau mi ln sng pht i

sn sng nhn sng phn hi.d. Cm bin tim cn siu m gii hn khong cch pht hin kh ln.

63. Nhc im no ca cm bin siu m sau l nga. Cm bin tim cn siu m yu cu i tng c mt din tch b mt ln nht (gi tr

ny ty thuc vo tng loi cm bin).b. Sng phn hi cm bin nhn c c th chu nh hng ca cc sng m thanh tp

m.c. Cm bin tim cn siu m khng cn mt khong thi gian sau mi ln sng pht i


64. Nhc im no ca cm bin siu m sau l nga. Cm bin tim cn siu m yu cu i tng c mt din tch b mt rt ln (gi tr


thanh tp m.c. Cm bin tim cn siu m yu cu mt khong thi gian sau mi ln sng pht i


65. Nhc im no ca cm bin siu m sau l nga. Cm bin tim cn siu m yu cu i tng c mt din tch b mt rt ln (gi tr


thanh tp m.c. Cm bin tim cn siu m khng cn mt khong thi gian sau mi ln sng pht i

sn sng nhn sng phn hi.d. Cm bin tim cn siu m gii hn khong cch pht hin nh nht.

25

66. Cm bin in dung pht hin vt th l do? Ba/Ti u cm bin pht ra mt t trng.b/ Ti u cm bin pht ra mt in trng.c/Ti u cm bin c dng in xoy.d/ Ti u cm bin nam chm.

67. Cm bin in cm pht hin c vt th l do?a/Ti u cm bin pht ra mt t trng.b/ Ti u cm bin pht ra mt in trng.c/Ti u cm bin c dng in xoy.d/ Ti u cm bin c nam chm.

68. Cm bin in dung dng a/ pht hin vt th kim loi.b/ Pht hin vt th phi kim loi.c/ Pht hin vt th c hng s in mi ln hn khng kh.d/ Pht hin mc nc.

69. Cm bin in cm dng a/ pht hin vt th kim loi.b/ Pht hin vt th phi kim loi.c/ Pht hin vt th c hng s in mi ln hn khng kh.d/ Pht hin mc nc.

70. Cm bin in cm dng ?a/ Pht hin cc vt th c tnh phi kim.b/ Pht hin cc vt th c tnh kim loi.c/ Pht hin cc vt th c tnh rn.d/ Pht hin cc vt th lng

71. Cm bin in dung dng pht hin cc vt th?a/ C tnh phi kim.b/ Kim loi.c/ Rn.d/ C hng s in mi ln hn khng kh.

72. Cm bin t dng pht hin cc vt th?a/ C tnh phi kim.b/ Kim loi.c/ C t tnh.d/ C tnh in.

73. Da vo cu to b thu pht cm bin th cm bin quang chia thnha/ 2 loi b/ 3 loi. c/ 4 loi. d. 5 loi.

74. Cm bin in dung loi tim cn pht hin vt da theo nguyn tc noa. Tnh in.b. in ngc. in t.d. T trng

75. i vi cm bin in dung loi tim cn, khi vt tin gn n b mt tc ng ca cm binth

a. Tn s mch dao ng trn cm bin s thay i.b. Bin mch dao ng trn cm bin s thay i.c. dn sng trn sng ra ca cm bin s thay i.d. Cng sng ra cm bin s thay i.

76. i vi cm bin in dung loi tim cn, khi vt tin gn n b mt tc ng ca cm binth

a. Tn s mch dao ng trn cm bin s tng.

26

b. Bin mch dao ng trn cm bin s tng.c. Bin mch dao ng trn cm bin s gim.d. Tn s mch dao ng trn cm bin s gim.

77. i vi cm bin in dung loi tim cn, gia 2 bn cc t l chn khng v khi cha c vtt gia hai bn cc th in dung C s l

a.d

AC r 0=

b.dAC 0=

c.edAC r

=

0

d.ed

AC

=0

78. i vi cm bin in dung loi tim cn, gia 2 bn cc t l khng kh v khi cha c vt tgia hai bn cc th in dung C s l

a.d

AC r 0=

b.dAC 0=

c.edAC r

=

0

d.ed

AC

=0

79. i vi cm bin in dung loi tim cn, gia 2 bn cc t l chn khng v khi c vt tgia hai bn cc th in dung C s l

a.d

AC r 0=

b.dAC 0=

c.edAC r

=

0

d.ed

AC

=0

80. i vi cm bin in dung loi tim cn, gia 2 bn cc t l khng kh v khi c vt t giahai bn cc th in dung C s l

a.d

AC r 0=

b.dAC 0=

c.edAC r

=

0

d.ed

AC

=0

27

Chng 3 Cm bin Quang1. Cu to c bn ca cm bin quang gm:

A. u pht v u thuB. B khuch i nh sngC. Thu knh hi tD. Thu knh phn k

2. Cm bin c kh nng khuch tn thuc loi cm bin:A. Cm bin p sutB. Cm bin quangC. Cm bin siu mD. Cm bin pht x

3. u im ca cm bin quang thu pht c lp so vi cm bin quang thu pht chung l:A. Khong cch pht hinB. chnh xcC. Tnh n nhD. nh hng bi b mt vt liu

4. u im ca cm bin quang thu pht chung so vi cm bin quang thu pht c lp l:A. Gim bt dy dnB. chnh xcC. Tnh n nhD. nh hng bi b mt vt liu

5. Cm bin no sau y b nh hng bi b mt, mu sc ca vt nn:A. Cm bin quang thu pht chungB. Cm bin quang thu pht ringC. Cm bin quang khuch tnD. Cm bin quang phn x gii hn

6. Khi c yu cu trit tiu nn (ng dng khng b nh hng bi nn), ta nn chn cm binno:

A. Cm bin quang loi thu pht chungB. Cm bin quang phn x gii hnC. Cm bin quang khuch tnD. Cm bin quang loi t khong c cch

7. Cm bin mu thit k da vo cc mu sc ch o noA. , xanh l cy, tmB. Xanh l cy, tm, vngC. Xanh dng, , nuD. , xanh l cy, xanh dng

8. Vng cht (vng m) ca cm bin quang l vng:A. Cm bin khng pht hin c vtB. Cm bin khng hot ngC. Cm bin b ph hyD. Giao gia vng pht v vng thu

9. Theo nguyn tc thu pht, ngi ta thng chia cc loi cm bin quang thnh bao nhiu loi:a.1b.2c.3d.4.

10. c im chnh ca cm bin quang loi Through Beam:a.Gm hai b phn thu pht c lp.b.Gm hai b phn thu pht chung.c.Gm hai b phn thu pht chung, c t trn cng mt trc ng thng.

28

d.Gm hai b phn thu pht c lp, c t trn cng mt trc ng thng.11. c im chnh ca cm bin quang loi Retro Replective:

a.Gm hai b phn thu pht c lp v mt ming gng phn x.b.Gm hai b phn thu pht chung v mt ming gng phn xc.Gm hai b phn thu pht chung, c t trn cng mt trc ng thng.d.Gm hai b phn thu pht c lp, c t trn cng mt trc ng thng.

12. c im chnh ca cm bin quang loi Diffuse Replective:a.Gm hai b phn thu pht c lp.b.Gm hai b phn thu pht chungc.Gm hai b phn thu pht chung, c t trn cng mt trc ng thng.d.Gm hai b phn thu pht c lp, c t trn cng mt trc ng thng.

13. Nu xt v khong cch pht hin th loi cm bin quang no c khong cch pht hin xanht.

a.Loi xuyn tm (through-beam)b.Lai Diffuse Replectivec.Loi phn xd.Loi khuch tn.

14. Nu xt v khong cch pht hin th loi cm bin quang no c khong cch pht hin thpnht.

a.Loi xuyn tm (through-beam)b.Lai Diffuse Replectivec.Loi phn xd.Loi Retro Replective.

15. Trong cc loi cm bin quang th loi no sau y c tm o xa nht:a/ Loi xuyn tm (through-beam). b/ Loi phn x (Retro-reflective).c/ Loi khuch tn (Diffuse). d/ Loi hng ngoi.

16. ng dng cm bin quang cng nghip ch yu dng trong lnh vc no sau y?a/ Gia nh. b. cng nghip. c/ cng cng. d/ m sn phm.

17. Nguyn l ch to cm bin si quang da voa. Cm bin giao thoa k Fabry-Perot.b. Cm bin Diffuse Replectivec. Cm bin Retro Replectived. Cm bin Through Beam18. Loi cp quang no c dng truyn cho cm bin si quanga. Loi ng trc.b. Loi ngu nhinc. Loi 50/50d. Tt c cc cu trn u ng.19. Loi cp quang no c dng truyn cho cm bin si quanga. Loi ng trc.b. Loi c in tr 50c. Loi c in tr 100d. Tt c cc cu trn u ng.20. Loi cp quang no c dng truyn cho cm bin si quanga. Loi 50/50.b. Loi c in tr 50c. Loi c in tr 100d. Tt c cc cu trn u ng.21. Loi cp quang no c dng truyn cho cm bin si quanga. Loi ngu nhin.b. Loi c in tr 50

29

c. Loi c in tr 100d. Tt c cc cu trn u ng.22. Chun ngun cung cp mt chiu cho cc thit b cm bin trong cng nghip l

a.12 v 24 (volt)b.5 v 12 (volt)c.5 v 24 (volt)d.5 (volt)

23. Cm bin quang l g?A.Cm bin quang l loi cm bin o v tr ca vt.B.Cm bin quang l loi cm bin o dch chuyn ca vt.C.Cm bin quang hot ng da theo phng php quang hnh hc gm ngun pht sngkt hp vi u thu quang ( thng l t bo quang in).D.C 3 cu u ng.

24. Cm bin t dung :A.Pht hin kim loiB.Pht hin phi kimC.Tt c u saiD.Tt c u ng

25. Cm bin quang l:A.Cm bin pht hin v tr.B.Cm bin pht hin vt khi c s thay iC. Hot ng da theo phng php quang hnh hc.D. Cm bin pht hin v tr, cm bin pht hin vt khi c s thay i

26. Theo tn hiu ng ra cm bin quang c my loi:A.2B.3C.4D.5

27. Cm bin quang in hot ng da trn nguyn l chung:A.Thay i in cm khi c nh sang thch hp tc ngB.Thay i in dung khi c nh sang thch hp tc ngC.Thay i trng thi in khi c nh sng thch hp tc ngD.Thay i nhy khi c nh sng thch hp tc ng

28. Cm bin quang thng c dung ph bin nht :A.o dng, pB.o in trC.ng/ngt, iu khinD.Bo v qu ti

29. Cm bin quang thu pht chung thuc loi cm bin:A.Thu pht chungB.Thu pht clpC.Ch c thuD.Ch c pht

30. Cm bin quang thu pht chung c:A. Mt u thu, mt u phtB. Hai u thuC. Hai u phtD.u thu pht chung

31. Cm bin quang phn x gng thuc loi:A.Thu pht chungB.Thu pht c lp

30

C. Hai u thuD. Hai u pht

32. Cm bin quang phn x c b khuch i thuc loiA.Thu pht chungB.Thu pht c lpC. Hai u thuD. Hai u pht

33. Phn loi theo nguyn l hot ng ca cm bin quang hnh bn di thuc loi no

A.Thu, pht chung (phn x)B.Thu, pht c lpC.Khuch tnD.Nhim x


A.Thu, pht chung (phn x)B.Thu, pht c lpC. Khuch tnD. Nhim x


A.Thu, pht chung (phn x)B.Thu, pht c lpC.Khuch tnD.Nhim x

36. Trnh by nguyn l hot ng ca mt mch ng dng t bo quang dn nh hnh sau

31

A.Khi c nh sang thch hp chiu vo, in tr ca t bo quang dn gim mnh dn n dngin ln chy qua cun dy Role lm ng/m cc tip im.B.Khi c nh sang thch hp chiu vo, in p ca t bo quang dn tng ln lm ng/ mcc tip im ca Role.C.Khi c nh sang thch hp chiu vo, in dung ca t bo quang dn gim mnh dn ndng in ln chy qua cuc dy Role lm ng/m cc tip imD.Khi c nh sang thch hp chiu vo, in cm ca t bo quang dn gim mnh dn ndng in ln chy qua cuc dy Role lm ng/m cc tip im

37. Cho bit phn loi theo nguyn l hot ng ca 2 cm bin trong hnh sau:

A.Cm bin 1 thu pht chung (phn x), cm bin 2 loi thu pht c lpB.Cm bin 1 loi khuch tn, cm bin 2 loi thu pht c lpC.Cm bin 1 loi thu pht c lp, cm bin 2 loi thu pht chung (phn x)D.Cm bin 1 loi khuch tn, cm bin 2 loi pht chung ( phn x)

38. Cho bit phn loi theo nguyn l hot ng ca 2 cm bin trong hnh sau:

A.Cm bin 1 loi khuch tn, cm bin 2 loi thu pht c lpB.Cm bin 1 loi thu pht c lp, cm bin 2 loi thu pht chung (phn x)C.Cm bin 1 loi khuch tn, cm bin 2 loi pht chung ( phn x)D.Tt c u sai

39. Quang in tr l phn t th ng c gi tr in tr ph thuc voA.Cng ngun sang chiu voB.Bc song ngun sng chiu voC.Thi gian chiu sangD.Cng v bc sng ngun sng chiu vo

40. Cho cm bin nh hnh di, khi c tn hiu ng vo cm bin th ng ra s cho u ra mc:

32

A.Mc 0B.Mc 1C.Tu vo cch mc tiD.Khng c tn hiu ra

33

Chng 4 Cm bin v tr v khong cch1. Cm bin o c v tr v khong cch c ng ra l

a. ON/OF.b. Analogc. ON/OFF v Analogd. Dng sng bt k

2. Cm bin o v tr v khong cch c o theo phng php no sau ya. Phn t cm bin gn vi vt di ng, tn hiu o l mt hm ph thuc v tr trong phn t

cm bin, thng thng l tr khng.b. Phn t cm bin gn vi vt c nh, tn hiu o l mt hm ph thuc v tr trong phn t

cm bin, thng thng l in p.c. Phn t cm bin gn vi vt di ng, tn hiu o l mt hm khng ph thuc v tr trong phn

t cm bin m thng hm ny l tr khng.d. Phn t cm bin gn vi vt c nh, tn hiu o l mt hm khng ph thuc v tr trong phn

t cm bin, thng thng l tr khng.3. Cm bin in cm o khong cch ng ra analog thng c cc loi no sau ya. Loi c mt mch t, loi hai mch t v loi c li t di ng.b. Loi c mt mch t, loi hai mch t v loi c ba mch t.c. Loi c hai mch t, loi ba mch t v loi c li t c nh.d. Loi c hai mch t, loi ba mch t v loi c bn mch t.4. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t c khe t bin thin.b. Loi c hai mch t.c. Loi c ba mch t.d. Loi c li t di ng5. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t c khe t bin thin.b. Loi c hai mch t hnh xuyn.c. Loi c ba mch t.d. Loi c li t di ng6. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

34

a. Loi c mt mch t c khe t bin thin.b. Loi c hai mch t hnh ch U.c. Loi c ba mch t.d. Loi c li t di ng

7. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t.b. Loi c hai mch t.c. Loi c ba mch t.d. Loi c li t di ng8. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t hnh ch U.b. Loi c hai mch t.c. Loi c ba mch t.d. Loi c li t di ng9. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t hnh ch xuyn.b. Loi c hai mch t.c. Loi c ba mch t.d. Loi c li t di ng10. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

35

a. Loi c mt mch t hnh ch xuyn.b. Loi c hai mch t.c. Loi c mt mch t hnh ch U.d. Loi c li t di ng11. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t hnh ch xuyn.b. Loi c hai mch t.c. Loi c mt mch t hnh ch U.d. Loi c li t di ng12. Hnh v sau m t cho cm bin in cm ng ra analog thuc loi

a. Loi c mt mch t hnh ch xuyn.b. Loi c hai mch t.c. Loi c mt mch t hnh ch U.d. Loi c li t di ng13. nhy ca cm bin t cm khi khe h khng kh thay i ( s = const)a. 2

0

1

+

=

=

o

oLLS

36

b. 2

0

1

=

=

o

oLLS

c.0

0

s

Ls

LS =

=

d.0s

Ls

LS =

=

14. nhy ca cm bin t cm khi thay i tit din khng kh (= const)a. 2

0

1

+

=

=

o

oLLS

b. 2

0

1

=

=

o

oLLS

c.0

0

s

Ls

LS =

=

d.0s

Ls

LS =

=

15. Cm bin cm ng t mch t hnh xuyn s thay i ph thuc v khong cch khe khng khv gi tr in cm thay i phi tuyn v c gi tr

a. )1()(0

0

2

dL

kdnL +=+=

b. )1()(0

0

2

dL

kdnL ==

c. )1()(0

0

3

dL

kdnL +=+=

d. )1()(0

0

3

dL

kdnL =+=

16. Cm bin cm ng t mch t loi 2 mch t th gi tr ca 2 cun dy trn hai mch t ctnh

a. [ ])(101

1xd

LL

+= ; [ ])(1

022

xdL

L++

= b. [ ])(1

011

xdL

L+

= ; [ ])(102

2xd

LL

+=

c. [ ])(101

1xd

LL

++= ; [ ])(1

022

xdL

L++

= d. [ ])(1

011

xdL

L

= ; [ ])(102

2xd

LL

= 17. Cm bin h cm o khong cch ng ra analog c m t nh hnh sau l loi no

37

a. Loi h cm c khe khb. Loi vi saic. Loi c ba mch td. Loi c hai mch t

18. Cm bin h cm o khong cch ng ra analog c m t nh hnh sau l loi no

a. Loi h cm c khe khb. Loi vi saic. Loi c hai mch td. Loi c ba mch t


a. Loi h cm c khe khb. Loi vi saic. Loi c hai mch td. Loi c bin p


a. Loi h cm c khe khb. Loi vi saic. Loi c hai mch td. Loi c bin p


38

a. Loi h cm c khe khb. Loi vi saic. Loi c ba mch td. Loi c hai mch t


a. Loi h cm c khe khb. Loi vi saic. Loi c hai mch td. Loi c ba mch t

23. nhy ca cm bin h cm o khong cch ng ra analog loi c khe h khng kh vi sthay i ca chiu di khe h khng kh (s=const) c tnh:B

a. 2

00

02

0

20 11

+

=

=

=

EksES

b. 2

00

02

0

20 11

+

=

+

=

=

EksES

c. 2

00

02

0

20 11

=

+

=

=

EksES

d. 2

00

02

0

20 11

=

=

=

EksES

24. nhy ca cm bin h cm o khong cch ng ra analog loi c khe h khng kh nhaykhi tit din khe h khng kh s thay i ( const) c tnh

a.o

o

s

Ekss

ES ==

=

0

b.o

o

ss

Eks

ES ==

=

0

39

c.o

ss

Ekk

s

ES ==

=

0d.

o

o

s

Ekss

ES ==

=

0

25. LVDT l thit b dng o:a. lch phi tuyn.b. vn tc gc.c. lch tuyn tnh.d. Gc quay trn.

26. Bin p bin i sai phn tuyn tnh (LVDT) l:a. Khng c gii hn cho phn gii, to in p AC ng ra.b. Khng c gii hn cho phn gii,, to in p DC ng ra.c. Cm bin v tr c phn gii thp, to in p AC ng ra.d. Cm bin v tr c phn gii thp, to in p DC ng ra.

27. B bin i sai phn tuyn tnh (LVDT) l b bin i thuc loi bin i g:a. C in.b. T - in.c. Nhit in.d. Ha in.

28. Bin p bin i sai phn tuyn tnh (LVDT) nh hnh v, in p cun s cp l Vi v nuli st nm ng trng tm ca bip p th bin in p ng ra (Vo) l:

a. 0V b. V1+V2 c. V1-V2 d. Vi29. Bin p bin i sai phn tuyn tnh (LVDT) nh hnh v, in p cun s cp l V v nu

li st nm lch khi v tr trng tm ca bip p th bin in p ng ra (Vo) l:

a. V1+V2 b. V1-V2 c. V/2 d. 2V

30. Bin p bin i sai phn tuyn tnh (LVDT) c cu to nh hnh v, in p V1 v V2 ngccc tnh nhau l do:

40

a. Hai cun dy qun to ra p V1 v V2 ngc chiu nhau.b. Hai cun dy qun to ra p V1 v V2 cng chiu nhau.c. Ngun s cp Vi l xoay chiu.d. Li st t di chuyn.

31. Bin p bin i sai phn tuyn tnh (LVDT) c cu to nh hnh v, in p V1 v V2 c bin thay i l do:

a. Hai cun dy qun to ra p V1 v V2 ngc chiu nhau.b. Hai cun dy qun to ra p V1 v V2 cng chiu nhau.c. Ngun s cp Vi l xoay chiu.d. Li st t di chuyn.

32. Bin p bin i sai phn tuyn tnh (LVDT) c cu to nh hnh v, khi li st t dch chuyngn v cun dy V1 th:

a. p ra V1 tng v V2 gim.b. p ra V1 gim v V2 tng.c. p ra V1 tng v V2 tng.d. p ra V1 gim v V2 gim.

33. Bin p bin i sai phn tuyn tnh (LVDT) c cu to nh hnh v, khi li st t dch chuyngn v cun dy V2 th:

41

a. p ra V1 tng v V2 gim.b. p ra V1 gim v V2 tng.c. p ra V1 tng v V2 tng.d. p ra V1 gim v V2 gim.

34. tnh ton in p ng ra ca b bin p bin i sai phn tuyn tnh (LVDT) thng sdng mch no sau y:

a.Mch khch i vi sai.b.Mch khuch i o.c.Mch khuch i cng.d.Mch khuch tr.

35. Cho s khi m t cho b sai phn tuyn tnh (LVDT) nh hnh v, dng sng ra ti vLVDTl:

a.AC dng sinb.DC khng thngc.DC thngd. Dng sng bt k.

36. Cho s khi m t cho b sai phn tuyn tnh (LVDT) nh hnh v, dng sng ra ti vREC l:

a.AC dng sinb.DC khng thngc.DC c lc thngd. Dng sng bt k.

37. Cho s khi m t cho b sai phn tuyn tnh (LVDT) nh hnh v, dng sng ra ti vo l:

a.AC dng sinb.DC khng thngc.DC thngd. Dng sng bt k.

38. tnh c in p vi sai ng ra Vo ca b sai phn tuyn tnh nh hnh v, Cch u nino sau y l ng

42

a.A1 u vo A2, B1 u vo B2 ly lm Vo.b.A2 u vo B1, A1 u vo B2 ly lm Vo.c.A2 u vo B2, A1 u vo B1 ly lm Vo.d.B1 u vo B2, A1 u vo A2 ly lm Vo.

39. LVDT l thit b dng oa/ Gc quay.b/ Gia tc.c/ lch tuyn tnh.d/ Chiu di vt th.

40. Bin p bin i sai phn tuyn tnh (LVDT) l:a/ Mt cm bin dng o vn tc di.b/ Cm bin v tr c phn gii cao to in p DC ng ra.c/ Cm bin v tr c phn gii cao to in p AC ng ra.d/ Cm bin v tr c phn gii cao m hai cun th cp lun lch pha nhau 180 .

Hnh 841. Hnh 8 l cu to bn trong ca:

a/ My bin p. b/ B bin i in p 2pha.

c/ Bin p bin i sai phn tuyn tnh (LVDT) . d/ Cun nghch lu.42. Cm bin in dung loi o khong cch ng ra analog l c ch to da trn nguyn l no

sau y:Aa. Nguyn l l da trn s thay i ca in dung khi c s dch chuynb. Nguyn l l da trn s thay i ca in cm khi c s dch chuync. Nguyn l l da trn s thay i ca h cm khi c s dch chuynd. Nguyn l l da trn s thay i ca quang in khi c s dch chuyn43. Cm bin in dung loi o khong cch ng ra analog loi no sau y l nga. Khong cch bin thin, din tch bn cc bin thin, in mi bin thin v loi vi sai.b. in trng bin thin, din tch bn cc bin thin, in mi bin thin v loi vi sai.c. Khong cch bin thin, t trng bin thin, in mi bin thin v loi vi sai.d. Khong cch bin thin, h cm, in mi bin thin v loi vi sai.44. Cm bin in dung loi o khong cch ng ra analog , phn t cm ng c bn ca cm bin

in dung bao gm 2 cc ca mt t in c in dung C l hm ph thuc vo cc thnh phnno sau y

43

a. Khong cch d gia 2 cc ca t in, din tch bn cc A v hng s in mi.b. Khong cch d gia 2 cc ca t in, in tch trn 2 bn cc v hng s in mi.c. Khong cch d gia 2 cc ca t in, din tch bn cc A v hng s in cm.d. Khong cch d gia 2 cc ca t in, in tch trn 2 bn cc v hng s in trng.45. Hnh sau l loi no ca cm bin in dung loi o khong cch ng ra analog

a. Loi khong cch bin thinb. Loi din tch bn cc bin thinc. Loi in mi bin thind. Loi vi sai46. Hnh sau l cm bin in dung o khong cch c ng ra analog loi khong cch bin thin,

biu thc tnh tr s in dung C khi x thay i l

a.x

Ax

AxC r 0)( ==

b.x

Ax

AxC r == 0)(

c.x

Ax

AxC r +=+= 0)(

d.x

Ax

AxC r //)( 0 ==

47. Hnh sau l cm bin in dung o khong cch c ng ra analog loi khong cch bin thin,biu thc tnh nhy ca cm bin khi x thay i l

a. 20

x

AdxdCS r==

b. 20

x

AdxdCS r==

c. 20

x

AdxdCS r ==

44

d. 20

x

AdxdCS r +==

48. Hnh sau l loi no ca cm bin in dung loi o khong cch ng ra analog

a. Loi khong cch bin thinb. Loi din tch bn cc bin thinc. Loi in mi bin thind. Loi vi sai49. Hnh sau l cm bin in dung o khong cch c ng ra analog loi din tch bn cc bin

thin, biu thc tnh tr s in dung C khi x thay i l

a.d

wxAx

AC r )(0 ==

b.d

wxAx

AC r )(0 +==

c.d

wxAx

AC r )(0 +==

d.d

wxAx

AC r )(0 ++== 50. Hnh sau l loi no ca cm bin in dung loi o khong cch ng ra analog

a. Loi khong cch bin thinb. Loi din tch bn cc bin thinc. Loi in mi bin thind. Loi vi sai

45

51. Hnh sau l cm bin in dung o khong cch c ng ra analog loi in mi bin thin, biuthc tnh tr s in dung C khi x thay i l

a. [ ]xlwC )( 1220 =b. [ ]xlwC )( 1220 +=c. [ ]xlwC )( 1220 +=d. [ ]xlwC )( 1220 ++=52. Hnh sau l loi no ca cm bin in dung loi o khong cch ng ra analog

a. Loi khong cch bin thinb. Loi din tch bn cc bin thinc. Loi in mi bin thind. Loi vi sai53. Hnh sau l cm bin in dung o khong cch c ng ra analog loi vi sai, biu thc tnh tr

s in dung vi sai khi d thay i l

a. )(2

)()( 22000

21 dddlw

ddlw

ddlwCC rrr

+

=

+

=

b. )(2

)()( 22000

21 dddlw

ddlw

ddlwCC rrr

=

++

=

46

c. )(2

)()( 22000

21 dddlw

ddlw

ddlwCC rrr

=

+

=

d. )(2

)()( 22000

21 dddlw

ddlw

ddlwCC rrr

+

=

++

=

54. Cm bin quang in loi o khong cch ng ra analog gm b pht v b thu nh sng cngun sng c s dng l

a. Diode pht quang hay diode lazer.b. Diode pht quang hay diode zener.c. Diode pht quang hay diode schottky.d. Diode pht quang hay diode shockley.55. Cm bin quang in o khong cch ng ra analog c ngun sng c s dng diode pht

quang th cc nh sng no sau y c s dnga. Tia sng hng ngoib. Tia sng ca nh trng.c. Tia sng sng siu m.d. Bt k tia sng no.56. Cm bin lazer o khong cch ng ra analog. Cm bin ny dng o dch chuyn khng

cn tip xc v hot ng ca cm bin da trn nguyn la. Mt tia lazer chiu ln vt v c phn x li v sau khi qua h thng thu knh s tc ng

ln cm bin v tr.b. Mt tia ca nh sng trng chiu ln vt c phn x li v sau khi qua h thng thu knh s

tc ng ln cm bin v tr.c. Cm bin lazer o khong cch da trn thi gian T t khi pht ra chm sng lazer n khi

nhn c chm sng phn xd. Cm bin lazer o khong cch da trn thi gian T t khi pht ra chm sng phn x n khi

nhn c chm sng ti57. Cm bin siu m o khong cch ng ra analog. Cm bin ny dng o dch chuyn

khng cn tip xc v hot ng ca cm bin da trn nguyn la. Mt tia sng siu m chiu ln vt v c phn x li v sau khi qua h thng thu knh s tc

ng ln cm bin v tr.b. Mt tia ca nh sng trng chiu ln vt c phn x li v sau khi qua h thng thu knh s

tc ng ln cm bin v tr.c. Cm bin siu m o khong cch da trn thi gian T t khi pht ra chm sng siu m n

khi nhn c chm sng phn xd. Cm bin siu m o khong cch da trn thi gian T t khi pht ra chm sng phn x n

khi nhn c chm sng ti58. Chit p dng pht hin gc quay nh hnh di, tm in p ng ra (ln lc) ca chit p

ti v tr 90 v 200 so vi v tr ban u (b qua tt c sai s)?

a.5.7V v 2,6Vb.5,0V v 2,6Vc.5.2V v 5,7V

47

d.5.3V v 4,7V59. Chit p dng pht hin gc quay nh hnh di, gc v tr ca tay my khi in p ng ra l

7,2V (b qua tt c sai s)

a. V tr 252 so v tr ban ub. V tr 119 so v tr ban uc. V tr 118 so v tr ban ud. V tr 117 so v tr ban u

60. xc nh sai s ti tuyn tnh (ett) ti theo gi tr in tr ca mt chit p c k hiu v ctuyn theo hnh v, vi R l sai s in tr ln nht, Rpot l in tr ton b ca chit p.Cng thc no sau y l ng:

a.pot

tt RRx

e100

= b.

=

100xett c. 100Rx

Re

pottt

= d. 100x

ett

=

61. Mt chit p quay mt vng 350 c sai s tuyn tnh l 0,1 ni ngun 5V, chit p c gi trin tr tng cng l 10K. Vy sai s ti ln nht theo gi tr in tr:

a.10b. 1c. 100d. 0,1

62. Mt chit p quay mt vng 350 c sai s ti ln nht l 5, ngun cung cp cho chit p5V, chit p c gi tr in tr tng cng l 10K. Vy sai s tuyn tnh l bao nhiu:

a.0,05%b. 0,10%c. 0,24%d. 0,17%

48

63. xc nh sai s ti tuyn tnh (ett) theo gc quay ca mt chit p c k hiu v c tuyntheo hnh v, vi l gc sai s ln nht, l gc quay ln nht ca chit p. Cng thc nosau y l ng:

a. 100x

ett

= b.

=

100xett c. 100Rx

Re

pottt

= d.pot

tt RRx

e100

=

64. Chit p quay mt vng 350 , sai s tuyn tnh l 0.2% v ni vi ngun 10V. Vy sai s titheo gc quay ln nht l:

a.0,7 b.0,5 c.0,4 d.1,05

65. Chit p quay mt vng 350 , sai s ti ln nht l 1,3o v ni vi ngun 10V. Vy sai stuyn tnh s l:

a.0,37 %b.0,25%c.0,34%d.1,05%

66. Chit p dng pht hin gc quay nh hnh di, tm in p ng ra ca chit p ti v tr202 (b qua tt c sai s)?

a.5.77Vb.5.55Vc.5.22Vd.5.33V

67. Chit p dng pht hin gc quay nh hnh di, gc v tr ca tay my khi in p ng ra l3.4V(b qua tt c sai s)?

a. V tr 120 b. V tr 119 c. V tr 118 d. V tr 117

49

68. Chit p c in tr tng cng l 10Kohm nh hnh di, s dng nh l mt bin tr. Gi scon trt ang v tr trung tm bin tr, tm sai s ti khi mch giao tip c in tr v cngln?

a.0 Vb.0.1 Vc.0.2 Vd.0.3 V

69. Chit p c in tr tng cng l 10Kohm nh hnh di, s dng nh l mt bin tr. Gi scon trt ang v tr 2/5 ca bin tr, tm sai s ti khi mch giao tip c in tr l100Kohm(tnh gn ng)?

a.0 Vb.0.094 Vc.0.02 Vd.0.07 V

70. Chit p quay mt vng 350 sai s tuyn tnh l 0.3% v ni vi ngun 10 V. Tm sai s gcln nht?

a.2.05 b.1.05 c.3.03 d.4.02

71. in tr dy qun c cu to nh gm 250 vng dy qun, tng in tr l 1 K, gc quay chophp ti a l 340 . Tm phn gii ca bin tr?

a.0.45%b.0.4%c.0.35%d.0.3%.

72. in tr dy qun c cu to nh gm 250 vng dy qun, tng in tr l 1 K, gc quay chophp ti a l 300 . Khi s dung bin tr lm chit p, tm phn gii ca chit p?

a.1.2 b.1.4 c.2.2 d.2.4

50

73. Bin p bin i sai phn tuyn tnh (LVDT) nh hnh 8, nu li st nm ng trng tm cabip p th bin in p ng ra (V0) l:a/ V1+V2 b/ V1 c/ V2 d/ 0

Hnh 174. Bin tr (Hnh 1) c th dng nh mt cm bin v tr o gc quay hay o s dch chuyn

tuyn tnh th phi tha mn cc yu cu no sau y?a. C gi tr in tr nhb. in tr thay i phi tuyn theo s dch chuyn con trt.c. in tr thay i tuyn tuyn theo s dch chuyn con trt.d. C a v c cng ng.

75. Mch nh hnh 2, ng c c iu khin ch t 0 n 300 . Bin tr c gi hn t 0 ti350 , ng vi in p ra t 0 ti 10VDC. Tnh in p ng ra ti v tr 82 ?

Hnh 2a/ 2.5V b/ 3V c/ 2.34V d/ 2.4V

76. Mch nh hnh 3a v 3b. Hnh 3a th ng ra ca con trt cha gn ti (h mch), Hnh 3b thng ra c gn ti. C hai con trt cng nm v tr im gia bin tr. Sai s khi c ti vkhng ti l?

Hnh 3a/ 0.12V b/ 0.2V c/ 0.15V d/ 0.1V

77. Tay my c gn nh hnh 4, t s bnh rng l 2:1. Nu tay my quay mt gc 10 thin p ng ra ca bin tr (Vpot ) bng bao nhiu?

51

Hnh 4a/ 0.3V b/ 0.5V c/ 0.25V d/ 0.29V

78. T s bnh rng trong hnh 16 l?.

Hnh 16a/ 2 b/ 3 c/ 4. d/ 5

79. Cho c cu nh hnh di, t s bnh rng l 2:1. Nu tay my quay mt gc 10 k t v trban u (0 ) th p ng ra ca bin tr l bao nhiu?

a.0.5Vb.0.275Vc.0.285Vd.0.3 V

80. Encoder n (loi tng i) a quay loi ba Track th s cA. Hai track c s rnh bng nhau nhng lch nhau 90 v mt track c mt rnhB. Hai track c s rnh ging nhau hon ton v mt track c mt rnhC. Ba track c s rnh bng nhau nhng lch nhau 120 D. Hai track c s rnh bng nhau nhng lch nhau 180 v mt track c mt rnh

81. S xung pht ra t Encoder trong mt vng quay da vo :

52

A. S a code trong EncoderB. phn gii ca EncoderC. S lng b led pht thu trong EncoderD. S Track trong Encoder

82. Mt Encoder c phn gii l 1000 th khi n quay c 1/4 vng, s xung ta thu c:A. Xp x 200B. Xp x 250C. Xp x 300D. Xp x 450

83. Chn pht biu sai:A. Encoder c th o dch chuyn di v dch chuyn gcB. Encoder tuyt i khng gi c thng tin v v tr khi mt inC. Mc in p cp cho Encoder thng thng t 5VDC n 24VDCD. phn gii ca Encoder ni ln chnh xc ca Encoder

84. t c phn gii 1024, Encoder tuyt i x l bao nhiu bit:A. 8B. 10C. 12D. 16

85. Encoder gia s tng (Incremental Encoder) c ti a bao nhiu dy :A. 12B. 10C. 8D. 6

86. Xung A v B ca encoder gia s tng (Incremental Encoder) c chc nng m:A. S vng quay v chiu quay.B. Chiu quay v khong cch.C. Khong cch v v tr.D. S vng quay v khong cch

87. chnh xc ca encoder quang loi tng i (incremental encoder) ph thuc vo?a/ Kch thc. b/ S xung m encoder to ra. c/ S knh. d/ Chiu

quay.88. Hnh 5 l cu to bn trong ca mt encoder quang. Encoder ny c th dng ?

Hnh 5a/ Xc nh chiu quay b/ o tc quayc/ o tc quay v xc nh hng quay. d/ Tt c u ng.

89. Hnh 6 l cu to bn trong ca mt encoder quang. Encoder ny dng ?

53

Hnh 6a/ Xc nh chiu quay b/ . m s vng quay v xc nh gc lch.

c/ o tc quay v xc nh hng quay. d/ Tt c sai.90. Ta thng chia encoder thnh cc loi nh sau:

a.Encoder quang, encoder tng i.b.Encoder tuyt i, encoder tng ic.Encorder tuyt i, encoder tng i, encoder mt/hoc hai knh.c.Encoder 1 knh, encoder 2 knh, encoder tng i/tuyt i

91. Cu to c bn ca mt encoder quang loi tng i:a.Mt b thu pht quang.b.Gm mt a plastic hoc quang t gia cc b thu pht quang.c.Gm mt a plastic hoc quang t gia mt b thu pht quang.d.Gm nhiu b thu pht quang.

92. c im ca encoder quang loi tng i mt knh:a.Gm mt hoc hai b thu pht quang.b.Gm mt b thu pht quang.c.Gm mt hoc hai b thu pht quang, trong c mt b thu pht quang xc nh v trtham chiu ca cm bin.d.Gm hai b thu pht quang t lch nhau mt gc 90 .

93. c im ca encoder quang loi tng i mt knh:a.Xc nh c c v tr ln chiu quayb.Ch xc nh c chiu quayc.Ch xc nh c v trd.Khng xc nh c gc quay.

94. Mt encoder quang gm 360 rnh, bt u quay t v tr tham chiu chun. Cm bin m 110rnh theo chiu kim ng h v 30 rnh theo chiu ngc li, ri 40 rnh theo chiu kim ngh. Tm v tr hin ti:

a.110 theo chiu kim ng h.b.110 theo chiu ngc chiu kim ng hc.120 theo chiu kim ng h.d.120 theo chiu ngc chiu kim ng h.

95. Mt encoder quang loi mt knh gm 360 rnh, bt u quay t v tr tham chiu chun. Cmbin m 120 rnh theo chiu kim ng h v 30 rnh theo chiu ngc li, ri 40 rnh theochiu kim ng h. Encoder c ni vi mch m. Mi xung vo mch m s tng ln mt,gi s gi tr b m ban u l 0. Tm gi tr ca b m:

a.190.b.110c.120d.150 .

96. c im ca encoder quang loi tng i hai knh:

54

a.Gm mt hoc hai b thu pht quang.b.Gm mt b thu pht quang.c.Gm mt hoc hai b thu pht quang, trong c mt b thu pht quang xc nh v trtham chiu ca cm bin.d.Gm hai b thu pht quang t lch nhau mt gc 90 .

97. c im ca encoder quang loi tng i hai knh:a.Xc nh c c v tr ln chiu quayb.Ch xc nh c chiu quayc.Ch xc nh c v trd.Khng xc nh c gc quay.

98. Hnh sau c sng ra ca CW v CCW l:

a.

b.

c.

d.99. Cho h thng cm bin v tr nh trong hnh di. S dng encoder loi 250 xung/vng. Gi tr

hin ti ca b m l 00010001. Tm v tr gc hin ti?

CCW

CW

V1

V2

V1

V2

CCW

V1

V2

V1

V2CW

CCW

CW V1

V2

V2

V1

CCW

CW V1

V2

V1

V2

55

a.24.45 b.24.48 c.32.45 d.32.48

100. c im ca encoder tuyt i?a.Ng ra c dng m s c bit.b.Ng ra l dng xung bnh thng

c.Ng ra ging encoder tng id.Ng ra c dng m Ascii.

101. c im ca trng thi ng ra encoder tuyt i?a.Trng thi v tr ca encoder b mt i khi mt ngun cung cpb.Ging encoder tng i.c.Trng thi v tr ca encoder vn c lu li khi mt ngun cung cp.d.Ty thuc vo mch bn trong ca encoder.

102. Cc dng m thng gp ng ra ca encoder tuyt i:a.Binary, Asciib.Ascii, BCDc.BCD, Gray, Asciid.BCD, Gray, Binary

103. in p cp ngun thng gp ca cc loi encoder l:a.5,12,24,36. (volt)b.24, 36 (volt)c.5,12,24 (volt)d.36 (volt)

104. Chun v dng in mt chiu ng ra ca cm bin dng trong cng nghip l:a.0-30 mAb.0-25 mAc.0-24 mAd.0-20 mA

105. Mt encoder quang tng i (incremental encoder) c 360 xung. Nu t v tr ban u(v tr 0 ), encoder m 100 xung theo chiu kim ng h, 30 xung theo chiu ngc li, ri45 xung theo chiu kim ng h. V tr hin ti ca encoder l?a/ 110 theo chiu kim ng h. b/ 50 theo chiu ngc chiu kim ng h.c/ 115 theo chiu kim ng h. d/ 30 theo chiu ngc chiu kim ng h.

106. Hnh 7 l hnh ct cu to bn trong ca mt encoder quang loi hai knh V1 v V2 btr lch nhau 90 (CW &CCW l hng cng v ngc chiu kim ng h). Mch no sauy c chc nng gii m chiu quay encoder?

56

Hnh 7a/ b/

DEM LEN4

1

16

15

14

J

CLK

K

Q

Q

H1

1

23V1

DEMXUONG

12

V2

U17B

4

56

4

1

16

15

14

J

CLK

K

Q

Q

H2

1

23

DEM LEN

V1DEMXUONG

12

V2

U17B

4

56

c/ d/

4

1

16

15

14

J

CLK

K

Q

Q

V1 DEMXUONG

DEM LEN

U17B

4

56

1

23

V2

H3

4

1

16

15

14

J

CLK

K

Q

Q

V1

DEMXUONG

DEM LEN

4

56

1

23

V2

H4

107. in p cp trc tip cho encoder thng l:a/ 12VDC b/ 5VDC c/ 9VDC d/ 24VDC.

108. Encoder thng c chia lm my loi chnh:a.1b.2c.3d.4

109. B phn th (Potentiometer) c k hiu nh hnh v, cng thc no dng tnh gitr in tr ca ng ra:

a. ( )LlRlR n= b. ( )

0

nRlR = c. ( ) LlRlR n 2

= b. ( )02

nRlR =

110. B phn th (Potentiometer) c k hiu nh hnh v, cng thc no dng tnh gitr in tr ca ng ra:

57

a. ( )LlRR n= b. ( )

0 nRR = c. ( ) L

lRR n 2= b. ( )

02 nRR =

111. Mch c c cu v k hiu nh hnh v, motor quay bin tr c gii hn t 0 ti 350, ng vi in p ra t 0 ti 10VDC. Tnh in p ng ra ti v tr 75 ?

a. 2,14V b. 2,24V c. 2,34V d. 2,44V112. Cho mch nh hnh. Hnh bn tri th ng ra ca con trt cha gn ti (h mch), hnh

bn phi th ng ra c gn ti. C hai con trt cng nm v tr im gia bin tr. Sai s khikhng ti l?

a. 0,0 V b. 0,12V c. 0,15V d. 0,18V113. Cho mch nh hnh. Hnh bn tri th ng ra ca con trt cha gn ti (h mch), Hnh

bn phi th ng ra c gn ti. C hai con trt cng nm v tr im gia bin tr. in trthc ca mch (in tr phn na di ca bin tr) khi c ti l?

a. 4,76k b. 47,6 k c. 476 d. 4,76114. Cho mch nh hnh. Hnh bn tri th ng ra ca con trt cha gn ti (h mch), Hnh

bn phi th ng ra c gn ti. C hai con trt cng nm v tr im gia bin tr. in png ra ca bin tr khi c ti l?

58

a. 4,88V b. 48,8V c. 0,48V d. 4,76V115. Cho mch nh hnh. Hnh bn tri th ng ra ca con trt cha gn ti (h mch), Hnh

bn phi th ng ra c gn ti. C hai con trt cng nm v tr im gia bin tr. Sai s khic ti l?

a. 0,12V b. 0,0V c. 0,15V d. 0,1V116. Tay my c gn nh hnh v, t s bnh rng l 2:1. Nu motor quay mt gc 120

so vi v tr ban u th in p ng ra ca bin tr (Vpot ) bng bao nhiu?

a. 7,9V b. 4,9V c. 8,9 V d. 3,4V117. Hy cho bit hnh v sau l loi cm bin no:

a.Cm bin v tr dy qun loi cn gt.b.Cm bin v tr loi tnh tuyn thng.c.Cm bin lc cng loi dy qun.d.Cm bin p sut loi in tr dy

118. Hy cho bit cm bin hnh v sau c phn gii l:

59

a.Mt vng dy qun.b. Mt so vi gc ban u.c.Mt mm so vi v tr ban u.d.Mt volt so vi in p ban u

119. Cm bin v tr loi in tr dy qun c cu to nh hnh v c cu to gm 10 b, mib c in tr 100. Tng s vng dy c qun 200 vng, gc quay cho php ti a l 350o.in tr tng cng ca cm bin l:

a.1k b.10k c.100k d.1000k120. Cm bin v tr loi in tr dy qun c cu to nh hnh v c cu to gm 10 b, mi

b c in tr 100. Tng s vng dy c qun 200 vng, gc quay cho php ti a l 350o.in tr mt vng dy qun l:

a.5 b. 2 c.1 d.10121. Cm bin v tr loi in tr dy qun c cu to nh hnh v c cu to gm 10 b, mi

b c in tr 100. Tng s vng dy c qun 200 vng, gc quay cho php ti a l 350o.Tm phn gii ca bin tr tnh theo % gi tr in tr l:

a.0,5% b.1% c.5% d.2%122. Cm bin v tr loi in tr dy qun c cu to nh hnh v c cu to gm 10 b, mi

b c in tr 100. Tng s vng dy c qun 200 vng, gc quay cho php ti a l 350o.Tm phn gii ca bin tr tnh theo l:

a.1,75o b. 17,5o c. 0,5o d. 0,75o

60

Chng 5 Cm bin lc v p sut

1. Cm bin lc c ch to da trn s thay i v nguyn tc no sau ya. Thay i in tr theo lc cng.b. Thay i in p theo lc cng.c. Thay i dng in theo lc cng.d. Thay i in t theo lc cng.

2. Cm bin lc c ch to da trn s thay i v nguyn tc no sau ya. Lc qun tnh.b. Lc co - gin.c. Lc n hid. Lc ht ca tri t.

3. Khi b ko gin ra th gi tr in tr ca cm bin lc sa. Tng ln.b. Gim xung.c. Khng thay i.d. Tu thuc vo hng ko gin.

4. Khi b nn co li th gi tr in tr ca cm bin lc sa. Tng ln.b. Gim xung.c. Khng thay i.d. Tu thuc vo hng nn co.

5. n di ca cm bin lc c tnha.

b.

c.

d.6. Trong mch hnh v, ngha ca RD l?

a/ in tr Gauge. b/ in tr ca cm bin. c/ in tr b nhit. d/ in tr t.7. Trong mch hnh v sau th V1 =?

61

a/DG

Gs

RRRVV+

=1 b/G

Ds

RRRVV

+=

11 c/

GD

Ds

RRRVV+

=1 d/G

Gs

RRRVV

+=

11

8. Nguyn l hot ng ca strain gauge l :a. Nng n ra, lnh co lib. in tr thay i ph thuc chiu di v tit din ca dyc. in tr ph thuc vo bn cht ca dyd. C hai p n b v c

9. o in tr bin thin trn strain gauge ngi ta dng?a. ng h VOM.b. Dng voltmeter v amperemeter => R=U/I.c. Dng cu wheatstone.d. Dng cng thc R= L/A.

10. Hnh v sau m t cm bin lc cngg. Khi lc tc ng theo chiu nh hnh v, th gi tr intr ca vt o sc cn 1 s:

a.Tng ln mt lng nh.b.Gim mt lng nh.c.Thng thay i.d.Bng khng.

11. Hnh v sau m t cm bin lc cng. Khi lc tc ng theo chiu nh hnh v, th gi tr intr ca vt o sc cn 2 s:

a.Tng thm mt lng R.b.Gim mt bt lng R.c.in tr khng thay i.d. thay i trn hai vt o l bng nhau.

62

12. straingain thng dng mch o l mcha. Cu Wheatstone c mt phn t thay ib. Cu Wheatstone c hai phn t thay ic. Cu Wheatstone c ba phn t thay id. Cu Wheatstone c bn phn t thay i

13. Cho loadcell c s nh hnh. Phn straingain ph t gn vi straingain chnh vi mc chg:

a.Khng b thay i bi lc tc ng, m bo b nhit vi strain gain chnhb. kch thc loadcell nh hnc.Thay i c bi lc tc ng ring cho tng loi straingain trn.d.Chu thay i bi lc tc ng chung.

14. Cm bin lc cng kiu chuyn i in tr c chia lm my loia. Hai loi.b. Ba loi.c. Bn loi.d. Nm loi.

15. Cm bin lc cng kiu chuyn i in tr, kiu no sau y l ng:a. Chuyn i in tr lc cng dy mnh.b. Chuyn i in tr lc cng l mng.c. Chuyn i in tr lc cng mng mngd. Tt c cc cu trn u ng.

16. Cm bin lc cng kiu chuyn i in tr, kiu no sau y l nga. Chuyn i in tr lc cng dy mnh.b. Chuyn i dng in lc cng l mng.c. Chuyn i in p lc cng mng mng.d. Chuyn i dng in lc cng dy mnh.

17. Cm bin lc cng kiu chuyn i in tr, kiu no sau y l nga. Chuyn i dng in lc cng dy mnh.b. Chuyn i in tr lc cng l mng.c. Chuyn i in p lc cng mng mng.d. Chuyn i dng in lc cng dy mnh.

18. Cm bin lc cng kiu chuyn i in tr, kiu no sau y l nga. Chuyn i in p lc cng dy mnh.b. Chuyn i dng in lc cng l mng.c. Chuyn i in tr lc cng mng mng.d. Chuyn i dng in lc cng dy mnh.

19. Cm bin lc cng kiu chuyn i in tr c ba thng s chnh no sau ya. Kch thc ca , gi tr in tr ca cm bin, dng in ti a cho phpb. mng ca cm bin, gi tr in tr ca cm bin, dng in ti a cho phpc. Kch thc ca , gi tr in p ca cm bin, dng in ti a cho phpd. Gi tr in p ca cm bin, gi tr in tr ca cm bin, dng in ti a cho php

63

20. nh hng ca cm bin lc cng dng o theo cu Wheatstone nh hnh v sau l

a. Hn ch c dy ni nhng khng hon ton.b. nh hng bi dy ni.c. Loi b nh hng ca nhit.d. To sai s21. nh hng ca cm bin lc cng dng o theo cu Wheatstone nh hnh v sau l

a. Hn ch c dy ni nhng khng hon ton.b. nh hng bi dy ni.c. Loi b nh hng ca nhit.d. To sai s22. nh hng ca cm bin lc cng dng o theo cu Wheatstone nh hnh v sau l

a. Hn ch c dy ni nhng khng hon ton.b. nh hng bi dy ni.c. Loi b nh hng ca nhit.d. To sai s23. Cm bin lc loi Strainguage hot ng da trn nguyn tc no?

a.Lc tc ng thay i th chiu di strainguage thay i

64

b.Lc tc ng thay i th bn knh ca Straingause thay i.c.Lc tc ng thay i th din tch Strainguage thay i.d.Lc tc ng thay i th in tr Strainguage thay i

24. Hng s Gauge (GF: gauge factor) c tnh theo biu thc no sau y:

a. RLLRGF

.

.

=

b. RLLRGF

=

c. RLLRGF

//

=

d.LLRRGF

++

=

Hng s Gauge (GF: gauge factor) dng m t mi lin ha. Gia n di v in tr.b. Gia n di v lc tc ng.c. in tr v lc tc ng.d. in tr v p sut.Hng s Youngs modulus (E) dng m t mi lin ha. Gia n di v in tr.b. Gia n di v lc tc ng.c. in tr v lc tc ng.d. in tr v p sut.Hng s Youngs modulus (E) c tnh theo biu thc no sau y

a.R

E = .b.

=E .

c. LE = .

d.RLE = .

25. Gi s Straingause c lp mch nh hnh bn di, in p V1 ?

a.Vs R1/(Rg+R2)b.Vs Rg(Rd+R2)c.Vs Rg(R1+Rg)d.Vs R1g(Rd+R2)

26. Gi s Straingause c lp mch nh hnh bn di, in p V2 ?

65

a.Vs Rd/(Rg+R2)b.Vs Rd(Rd+R2)c.Vs Rd(R1+Rg)d.Vs R(Rd1+R2)

27. Gi s Straingause c lp mch nh hnh bn di, khi straingauge b tc ng mt lc,straingauge thay i mt lng in tr R, tnh in p ng ra ca mch cu ?

a.Vs 4R/Rb.Vs R /4Rc.R /4 Vsd.R 4/Vs

28. Phn straingain ph t gn vi straingain chnh vi mc ch g?

a.Khng b thay i bi lc tc ng, m bo b nhit vi strain gain chnhb.Chu thay i bi lc tc ng, b nhit vi straingain chnhc.Ging nh straingain chnh.d.Chu thay i bi lc tc ng.

29. Khi b tr straingauge lm loadcell theo mch cu bn phn, th cng thc tnh p ng ra khistraingaue b tc ng bi lc v thay i mt lng nh R(theo hnh bn di) l:

66

e. Vo = Vs R/4Rf. Vo = Vs R/Rg. Vo = Vs R/2Rh. Vo = Vs R/3R


a.Vo = Vs R/4Rb.Vo = Vs R/Rc.Vo = Vs R/2Rd.Vo = Vs R/3R

31. Load cell lc cng thng dng mch o l mcha. Cu Wheatstone c mt phn t thay ib. Cu Wheatstone c hai phn t thay ic. Cu Wheatstone c ba phn t thay id. Cu Wheatstone c bn phn t thay i

32. Loadcell thy lc (Hydraulic load cells) l loi loadcell o c trng lng nh s thay ia. p sut cht lngb. Cn bng thu kh.c. Cn bng lc.d. Cu in tr cn bng Wheatstone33. Loadcell kh nn (Pneumatic load cells) l loi loadcell o c trng lng nh s thay ia. p sut cht lngb. Cn bng thu kh.c. Cn bng lc.d. Cu in tr cn bng Wheatstone34. Loadcell lc cng (Strain-gauge load cells) l loi loadcell o c trng lng nh s thay ia. p sut cht lngb. Cn bng thu kh.c. Cn bng lc.d. Cu in tr cn bng Wheatstone35. Cm bin lu lng s dng cc nguyn l sau y

67

a. p sut sai lch ( Differential Pressure), th ch (Positive displacement)b. To xoy (Vortex/Swir generation), tua bin, nhitc. T trng (Electromagnetic), khi lng (Mass)d. Tt c cc cu trn u ng36. Mi lu cht ca cm bin lu lng c c trng bi nhng yu t no:a. Khi lng ring, h s nht ng lc, h s nht ng hc.b. Khi lng ring, p sut, h s nht ng hc.c. Khi lng ring, nhit , h s nht ng lc.d. Khi lng ring, h s nht ng lc, tc xoy.37. H s nht ng lc c tnh theo phng trnh no sau y

a.u

rg.9

...2 2 =

b.u

rg.9

...2 2 =c.

u

rg.9

...2 =

d. 22

.9...2

u

rg =38. H s nht ng hc c tnh theo phng trnh no sau y

a. 310.

=v

b. 210.

=v

c. 2

310.

=v

d. 32 10.

=v

39. Tr s Reynold c tnh theo phng trnh no sau ya.

DuRe ..=

b. DuRe ..

2

=

c. 2..

DuRe =

d. 2.. DuRe =

40. H s nht ng lc l i lng c c trng bia. Tnh nht ca lu chtb. Quan h gia tnh nht v khi lng ring ca lu chtc. Dng chy ca lu cht trong ng dnd. Th tch ca khi lu cht

41. H s nht ng hc l i lng c c trng bia. Tnh nht ca lu chtb. Quan h gia tnh nht v khi lng ring ca lu chtc. Dng chy ca lu cht trong ng dn

68

d. Th tch ca khi lu cht42. Tr s Reynold l i lng c c trng bi

a. Tnh nht ca lu chtb. Quan h gia tnh nht v khi lng ring ca lu chtc. Dng chy ca lu cht trong ng dnd. Th tch ca khi lu cht

43. Cc phn t bin dng thng dng trong cm bin p sut l g ?a. Mng n hi hoc mng dob. L xo ng, ng hnh trc. Xiphngd. Tt c cu trn u ng.

44. p sut l g ?a. L p lc trn mt n v din tch.b. p sut l i lng c gi tr bng t s gia lc tc dng ln b mt din tch.c. p sut l i lng c gi tr bng t s gia lc tc dng vung gc ln b mt din tch.d. Tt c cu trn u ng.

45. Cng vic no sau y th cn thit phi dng cm bin o lu lng:a. nh lng cht lng trong bnh cha v c th tch khng xc nhb. o khong cch trong bnh v c th tch xc nhc. o p sut trong bnh v th tch khng xc nhd. o lu lng kh trong bnh khong cch khng xc nh.46. Mc tiu no sau y th cn thit phi dng cm bin o lu lng:a. nh lng c cht lng trong bnh cha c th tch xc nhb. Lu lng nh n p sut v nhit c. o khong cch trong bnh v c th tch xc nhd. o lu lng kh trong bnh khong cch khng xc nh.47. Mc tiu no sau y th cn thit phi dng cm bin o lu lng:a. nh lng cht lng trong bnh cha c th tch khng xc nhb. Lu lng khng nh n p sut v nhit c. o khong cch trong bnh v c th tch xc nhd. o th tch xng bm trm xng48. Trng hp no sau y th cn thit phi dng cm bin o lu lng:a. nh lng cht lng trong bnh cha c th tch xc nhb. Lu lng khng nh n p sut v nhit nhiuc. Tnh ton v phn b h thng ng dn (nc hoc gas) cho ph hpd. o khong cch trong bnh v c th tch xc nh49. Cm bin p sut dng o trong trng hp no saua. Tng gim p sut ca cc cht lngb. Tng gim p sut ca cht kh.c. Tng gim lu lng ca cht kh.d. Tng gim lu cht ca cht rn50. Cm bin p sut dng o trong trng hp no saua. o lu cht ca cc cht lngb. o s tng gim p sut ca cht kh.c. o lu cht lu lng ca cht kh.d. o lu cht ca cht rn51. Cm bin p sut dng phng php o bng lu lng th b phn to chnh lch p sut

c dng la. ng co trc tip trn dng chy.b. Khng to ng co trc tip trn dng chy.

69

c. Van iu tit kh.d. Tuabin52. Cm bin p sut dng phng php o Pitot tube th b phn to chnh lch p sut c

dng la. ng co trc tip trn dng chy.b. Khng to ng co trc tip trn dng chy.c. Van iu tit kh.d. Tuabin53. Chn phng n sai cho nhng l do dng phng php o p suta. Khng an tonb. nh hng hot ng ca h thngc. Tit kim chi phd. o c p sut s tm c cc i lng khc54. Chn phng n sai cho nhng l do dng phng php o p suta. An tonb. khng b nh hng hot ng ca h thngc. Tit kim chi phd. o c p sut s tm c cc i lng khc55. Chn phng n sai cho nhng l do dng phng php o p suta. An tonb. nh hng hot ng ca h thngc. Khng tit kim chi phd. o c p sut s tm c cc i lng khc56. Chn phng n sai cho nhng l do dng phng php o p suta. An tonb. khng b nh hng hot ng ca h thngc. Tit kim chi phd. o c p sut th khng tm c cc i lng khc

58. Cm bin p sut c ch to da theo nguyn tc no sau y:a.Bin p sut thnh lc.b.Bin p sut thnh in.c. Bin p sut thnh nhit.d. Bin p sut thnh t.

59. Cng thc no sao y dng st nh p sut tc dng ln vt trong nguyn l ch to cmbin p sut:

a.dSdFp =

b.dFdSp =

c.dSdp =

d.dTdBp =

60. o in tr bin thin trn strain gauge ngi ta dng:a. Cu phn th.b. Dng voltmeter v amperemeter.c. Dng cu wheatstone.d. Dng cng thc tnh in tr dy.

61. Trong s mch hnh sau, khi strain gauge b tc ng pht biu no sau y l ng:

70

a. in tr RG khng i. b. in tr RG s bng RD.c. in tr RG s tng. d. in tr RG s gim.

62. Trong mch hnh v sau, cng dng ca in tr RD l?

a. in tr Gauge. b. in tr ca cm bin. c. in tr b nhit. d. in tr t.63. Trong mch hnh v th V1 =?

a.DG

Gs

RRRVV+

=1 b.G

Ds

RRRVV

+=

11 c.

GD

Ds

RRRVV+

=1 d.G

Gs

RRRVV

+=

11

64. Trong mch hnh v th V2 =?

a.DG

Gs

RRRVV+

=2 b.G

Ds

RRRVV

+=

12 c.

GD

Ds

RRRVV+

=2 d.G

Gs

RRRVV

+=

12

65. Trong mch nh hnh v th in p ng ra Vo =V c tnh:

71

a.( )

( )( )DGDG

S RRRRRRRRVV++

=21

12 b. ( )( )( )DGDG

S RRRRRRRRVV+

=21

12

c.( )

( )( )DGDG

S RRRRRRRRVV+

=21

12 d. ( )( )( )DGDG

S RRRRRRRRVV

=21

12

66. Cng thc tnh n di ca strain gauge l:a. =L/L b. =L/L c. =R/R d. =R/R

67. Cng thc no tnh h s Gauge (GF):

a.

LL

RR

GF

= b.

RR

LL

GF

= c.

LR

RL

GF

= d.

RL

LR

GF

=

68. Cng thc no th hin mi lin h gia h s n di v in tr ca strain gauge:

a.GF

RR

= b.GF

LL

= c.GF

LR

= d.GF

RL

=69. Hnh v sau l s k hiu cho straingauge dng mch loi:

a.Cu in tr bn phnb. Cu in tr ton phnb. Cu in tr phd. Cu in tr chnh

70. Hnh v sau l s k hiu cho straingauge dng mch loi:

a.Cu in tr bn phn.b. Cu in tr ton phn.

72

b. Cu in tr ph.d. Cu in tr chnh.

71. Khi b tr straingauge lm loadcell theo mch cu bn phn, th cng thc tnh p ng ra khistraingaue b tc ng bi lc v thay i mt lng nh R (theo hnh bn di) l:

a. Vo = Vs R/4Rb. Vo = Vs R/Rc. Vo = Vs R/2Rd. Vo = Vs R/3R


a. Vo = Vs R/4Rb. Vo = Vs R/Rc. Vo = Vs R/2Rd. Vo = Vs R/3R

73

Chng 6 Cm bin nhit 1. Vic xc nh thang o nhit c da vo:

a. Cc nh lut v nhit ng hc.b. Cc nh lut v thu lcc. Cc nh lut v c hcd. Cc nh lut v ho hc

2. Thang o nhit c da voa. nh lut Carnotb. nh lut Kelvinc. nh lut Celsiusd. nh lut Fahrenheit

3. Thang o nhit Celsius c pht minh bia. Nh khoa hc ngi Thy inb. Nh khoa hc ngi Anhc. Nh khoa hc ngi H Land. Nh khoa hc ngi Php

4. Thang o nhit Kelvin c pht minh bia. Nh khoa hc ngi Thy inb. Nh khoa hc ngi Anhc. Nh khoa hc ngi H Land. Nh khoa hc ngi Php

5. Thang o nhit Fahrenheit c pht minh bia. Nh khoa hc ngi Thy inb. Nh khoa hc ngi Anhc. Nh khoa hc ngi H Land. Nh khoa hc ngi Php

6. i vi cm bin nhit dng kim loi, khi ta tng nhit ln cm bin th in tr ca kimloi ca cm bin ny s

e. Tngf. Gimg. Khng ih. Ph v lin kt gia cc phn t

7. i vi cm bin nhit dng bn dn, khi ta tng nhit ln cm bin th in tr ca chtbn dn ca cm bin ny s

i. Tngj. Gimk. Khng il. Ph v lin kt gia cc phn t

8. Trong cc cht sau y cht no c in tr gim nhanh nht khi tng nhit m. Than.n. ngo. Stp. Silic.

9. Trong cc cht sau y cht no c in tr tng nhanh nht khi tng nhit :q. Than.r. ngs. Stt. Silic.

10. Trong cc cht sau y cht no c in tr gim khi tng nhit u. Than, Silic.v. ng, Than

74

w. St, Silicx. Silic, ng

11. Trong cc cht sau y cht no c in tr tng khi tng nhit a. Than, Silic.b. ng, Thanc. St, Silicd. St, ng

12. Biu thc no sau y m t s thay i in tr theo nhit cho in tr kim loie. R(t) = R0 (1 + A.t + B.t2 + C.t3 +)a. R(t) = R0 (1 + A.t + B.t2 + C[t - 1000C].t3)b. R(t) = R0 (1 + A.t +B.t2 +D.t4 +F.t6)

c. ( ) ))11

.((0

0.

TTB

eRtR

=

13. Biu thc no sau y m t s thay i in tr theo nhit cho nhit in tr Platina. R(t) = R0 (1 + A.t + B.t2 + C.t3 +)b. R(t) = R0 (1 + A.t + B.t2 + C[t - 1000C].t3)c. R(t) = R0 (1 + A.t +B.t2 +D.t4 +F.t6)

d. ( ) ))11

.((0

0.

TTB

eRtR

=

14. Biu thc no sau y m t s thay i in tr theo nhit cho nhit in tr Nickena. R(t) = R0 (1 + A.t + B.t2 + C.t3 +)b. R(t) = R0 (1 + A.t + B.t2 + C[t - 1000C].t3)c. R(t) = R0 (1 + A.t +B.t2 +D.t4 +F.t6)

d. ( ) ))11

.((0

0.

TTB

eRtR

=

15. Biu thc no sau y m t s thay i in tr theo nhit cho nhit in tr bn dn (silic)e. R = R0 (1 + A.t + B.t2 + C.t3 +)a. R = R0 (1 + A.t + B.t2 + C[t - 1000C].t3)b. R = R0 (1 + A.t +B.t2 +D.t4 +F.t6)

c. ( ) ))11

.((0

0.

TTB

eRtR

=

16. C bao nhiu phng php o nhit ?a.1b.2c.3d.4

17. Nguyn l hot ng ca RTD?a.Theo nguyn l nhit in tr dngb.Theo nguyn l nhit in tr mc.Khi nhit tng in tr gimd.Rt kh xc nh c, ph thuc vo tm nhit m c th l nhit in tr dnghoc m.

18. Khi dng RTD o nhit th ngi ta thng dng mch cu chuyn thnh p ng ra lv:

a.Khi nhit thay i th in tr thay i rt lnb.Khi nhit thay i th in tr thay i rt nh.c. thu c mc p n nhd. khuch i tt tn hiu.

19. c im cu to ca Thermistor?a.Cu to t nhng thanh kim loi

75

b.Cu to ging vi RTDc.Cu to ging vi TCd.Cu to t nhng vt liu bn dn.

20. c im ca Thermistor?a.Khi nhit tng th in tr tng.b.Khi nhit tng th in tr gimc.a s c h s nhit in tr dngd.a s c h s nhit in tr m.

21. c im cu to ca Thermocouple?a.L mt thanh kim loi.b.Cu to t hai thanh kim loi lm t mt loi vt liu.c.Cu to t hai thanh kim loi lm t hai vt liu khc nhau khng ni chung nhau.d.Cu to t hai thanh kim loi lm t hai loi vt liu khc nhau, hai u c tip xcnhit vi nhau.

22. c im hot ng ca TC nh hnh v o nhit ta cn:

a.Phi bit c nhit ca mt trong hai mi ni.b.Khng cn bit nhit ca c hai mi ni.c.o nhit da vo s thay i in tr gia hai mi ni.d.Ging vi RTD.

23. Thermocouple l cm bin tc ng ce. u vo l nhit , u ra l in pf. u vo l nhit , u ra l dng ing. u vo l nhit , u ra l in trh. u vo l nhit , u ra l chiu di

24. Thermocouple l cm bin hot ng da trn hiu nga. Seebeckb. Carnotc. Fahrenheitd. Resistance

25. RTD (Resistance Temperature Detector) l loi cm bin thng dng o nhit theo:a.Phng php trc tip.b. Phng php gin tip.c.Phng php quang.d.o theo bc x in t.

26. TC l loi cm bin thng dng o nhit theo:a.Phng php trc tip.b. Phng php gin tip.c.Phng php quang.d.o theo bc x in t.

27. Cm bin nhit PT100 l loi cm bin nhit dng o nhit theo cch o:a.Trc tipb.Gin tipc.C trc tip v gin tip u cd.o thng qua mt mch giao tip khc

76

28. Cm bin nhit c t tn PT100, s 100 ch cho ta bit iu g?a.in tr ca cm bin l 100b.Dng qua cm bin l 100mA.c.in p cp ti a cho cm bin l 100V.d.y ch l m s ca nh sn sut.

29. Phng php no sau y thuc loi o nhit theo cch o gin tip:a. Phng php quang (Optical Pyrmeter)b. Phng php dng in tr cht bn dnc. Phng php in tr kim loid. Phng php cp nhit in (Thermocouple)

30. Phng php no sau y thuc loi o nhit theo cch o gin tip:a. Phng php dng in tr cht bn dnb. Phng php bc x in t ( Photon Detector)c. Phng php in tr kim loi (Photon Detector)d. Phng php cp nhit in (Thermocouple)

31. Phng php xc nh nhit ca Thermocouple bng cch no sau ya. C nh nhit chun bng nc .b. C nh nhit chun bng nc si.c. Thay i nhit chun bng nc .d. Thay i nhit chun bng nc si.32. Phng php xc nh nhit ca Thermocouple bng cch no sau ya. C nh nhit chun bng mch in t.b. C nh nhit chun bng nc si.c. Thay i nhit chun bng nc .d. Thay i nhit chun bng bng mch in t.33. Hy cho bit in p o ti V hnh sau ph thuc vo phn t no khi ta t nng T1:

a. J3 v J4b. R3 v R4c. R2 v R3d. R4 v R234. i vi Thermocouple, nu c mt vt liu kim loi th 2 chn gia hai nhit ngu nh hnh

v th

a. in p ra khng b nh hngb. in p ra b nh hng

77

c. Nhit ra khng b nh hngd. Nhit ra b nh hng

35. i vi Thermocouple, nu c mt vt liu kim loi th 2 chn gia hai nhit ngu nh hnhv, pht biu no sau y l ng

a. Vic ny bo m cho vic i dy dib. Vic ny bo m cho vic i ghp nhiu cm binc. Vic ny bo m cho vic t nng cm bind. Vic ny bo m cho vic tnh ton in ra cho cm bin

36. i vi Thermocouple, nu ta ni 2 kim loi A v B bi mt kim loi th 3 C th

a. in p o cng khng nh hngb. in p ra b nh hngc. Nhit ra khng b nh hngd. Nhit ra b nh hng

37. Hnh v sau m t cho cch o no ca Thermocouple

a. o gin tip.b. o trc tip.c. o da vo nhit nc .d. o da vo mch in t38. Hnh v sau m t cch xc nh nhit ca Thermocouple, nhit ti nhit ngn no s

cha bit ti

a. T1.b. T3.c. T2.d. T1 v T339. Cc kim loi c chn la ch to Thermocouple da vo cc tiu ch no sau ya. nhy, n nh, tnh tng thch vi h thng o, chi ph hp l.

78

b. Chu nhit cao, n nh, tnh tng thch vi h thng o, kim loi phi dy.c. nhy, chu nhit cao, tnh tng thch vi h thng o, kim loi phi dy.d. nhy, kim loi phi dy, chu nhit cao, chi ph hp l.40. in p Vout ca mch cu dng trong mch chuyn i cm bin c gi tr l

a.

=43

3

21

2

RRR

RRRVV inout

b.

+

+=

43

3

21

2

RRR

RRRVV inout

c.

++

+=

43

3

21

2

RRR

RRRVV inout

d.

+

=43

3

21

2

RRR

RRRVV inout

41. in p VB ca mch cu dng trong mch chuyn i cm bin c gi tr l

a. 21

2

RRRVV inB +

=

b. 212

RRRVV inB

=

c. 43

3

RRRVV inB +

=

d.43

3

RRRVV inB

=

42. in p VD ca mch cu dng trong mch chuyn i cm bin c gi tr l

79

a. 21

2

RRRVV inD +

=

b. 212

RRRVV inD

=

c. 43

3

RRRVV inD +

=

d.43

3

RRRVV inD

=

43. Khi nhit o kim loi ca RTD nm trong tm o th R thay i tuyn tnh vi nhit vcng thc no sau y biu din cho trng hp ny

a.

).(1 00

TTRR

=

b.).(1 0

0

TTR

R+=

c.

200

0

).(2).(1 TTTTRR

+=

d. 2000

).(2).(1 TTTTR

R=

44. Khi nhit o cho kim loi ca RTD nm ngoi tm o th R thay i tuyn tnh vi nhit

v cng thc no sau y biu din cho trng hp ny

a.

).(1 00

TTRR

=

b.).(1 0

0

TTR

R+=

c.

200

0

).(2).(1 TTTTRR

+=

d. 2000

).(2).(1 TTTTR

R=

45. Mch o ca Thermistor thng c dng l mcha. Cu b. Cu c. Cu d. Cu y .46. Mch o ca RTD thng c dng l mcha. Cu b. Cu

80

c. Cu d. Cu y .47. Phng php o trc tip c hn ch no sau ya. Khng th o nhit trn din tch lnb. Tm o qu ln.c. Khng nh hng cu trc h thng cn o.d. Khng o c vt ang ng yn48. Phng php o trc tip c hn ch no sau ya. Khng o c nhng vt ang chuyn ngb. Tm o qu ln.c. Khng nh hng cu trc h thng cn o.d. Khng th o nhit trn din tch nh49. Phng php o trc tip c hn ch no sau ya. Khng o c nhng vt ang ng ynb. Tm o nh (ch dng trong tm t -190oC n 1063oC).c. Khng nh hng cu trc h thng cn o.d. Khng th o nhit trn din tch nh50. Phng php o trc tip c hn ch no sau ya. C th nh hng n cu trc h thng cn o nhit .b. Tm o qu ln.c. Khng nh hng cu trc h thng cn o.d. Khng th o nhit trn din tch nh51. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt ang di chuyn.b. Tm o rt nh.c. Xc nh nhit nh hng n i tng cn o.d. Xc nh nhit lm thay i cu trc ca vt cn o52. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt c b mt rt nh.b. Tm o rt nh.c. Xc nh nhit m khng gy nh hng n i tng cn o.d. Xc nh nhit lm thay i cu trc ca vt cn o53. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt c b mt rt nh.b. Tm o rt nh.c. Xc nh nhit gy nh hng n i tng cn o.d. Xc nh nhit m khng lm thay i cu trc ca vt cn o54. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt c b mt rt nh.b. Xc nh nhit ca mt vt rt nng khng th o c bng dng c thng thng.c. Xc nh nhit gy nh hng n i tng cn o.d. Xc nh nhit lm thay i cu trc ca vt cn o55. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt c b mt rt nh.b. Xc nh nhit ca mt vt nm trong khu vc nguy him.c. Xc nh nhit gy nh hng n i tng cn o.d. Xc nh nhit lm thay i cu trc ca vt cn o56. Phng php o gin tip c u no sau ya. Xc nh nhit ca mt vt c b mt rt nh.b. Xc nh nhit ca mt khu vc c din tch rng.c. Xc nh nhit gy nh hng n i tng cn o.

81

d. Xc nh nhit lm thay i cu trc ca vt cn o57. Nguyn l o nhit cch ly da voa. Nhit ca mt vt c b mt ca vt.b. Nhit ca vt da trn bc x in t vt pht ra.c. Nhit gy nh hng n i tng cn o.d. Nhit lm thay i cu trc ca vt cn o58. Nguyn l o nhit cch ly da voa. Nhit ca mt vt c b mt ca vt.b. sng ca dy tc bng n vi sng ca vt cn o.c. Nhit gy nh hng n i tng cn o.d. Nhit lm thay i cu trc ca vt cn o59. Hy cho bit mch sau c tn gi l g

a. Mch cu Wheatstone , ngun pb. Mch cu Wheatstone , ngun pc. Mch cu Wheatstone , ngun dngd. Mch cu Wheatstone , ngun dng60. Hy cho bit mch sau c tn gi l g


a. Mch cu Wheatstone , ngun pb. Mch cu Wheatstone , ngun pc. Mch cu Wheatstone , ngun dngd. Mch cu Wheatstone , ngun dng

Vo

R

VB

R+R

R-R

R

Vo

R+R

VB

R+R

R

R

R

Vo

VB

R+R

R

R

82

62. Hy cho bit mch sau c tn gi l g

a. Mch cu Wheatstone loi bn cu, ngun pb. Mch cu Wheatstone loi cu y , ngun pc. Mch cu Wheatstone loi bn cu, ngun dngd. Mch cu Wheatstone loi cu y , ngun dng63. Hy cho bit mch sau c tn gi l g

a. Mch cu Wheatstone loi bn cu, ngun pb. Mch cu Wheatstone loi cu y , ngun pc. Mch cu Wheatstone loi bn cu, ngun dngd. Mch cu Wheatstone loi cu y , ngun dng64. Hy chn p n ng tnh Vo ca mch sau

a.

b.

c.

d.65. Hy chn p n ng tnh Vo ca mch sau

VB2

RR+R/2Vo=

Vo=VB4

RR+R/2

VBRRVo=

VB2

RRVo=

R

Vo

VB

R+R

R

R

Vo

R+R

VB

R+R

R-R

R-R

Vo

R

VB

R+R

R-R

R

83

a.

b.

c.


a.

b.

c.


a.

Vo=VB4

RR+R/2

Vo

R+R

VB

R+R

R-R

R-R

VB2

RR+R/2Vo=

Vo=VB4

RR+R/2

VBRRVo=

VB2

RRVo=

Vo

R

VB

R+R

R-R

R

VB2

RR+R/2Vo=

Vo=VB4

RR+R/2

VBRRVo=

VB2

RRVo=

Vo

R+R

VB

R+R

R

R

84

b.

c.

d.68. Hy chn p n ng ch sai s tuyn tnh ca mch sau

a. 0,5%b. 0,25%c. 0,05%d. 0%69. Hy chn p n ng ch sai s tuyn tnh ca mch sau



Vo

R

VB

R+R

R-R

R

Vo

R+R

VB

R+R

R

R

R

Vo

VB

R+R

R

R

VB2

RR+R/2Vo=

VBRRVo=

VB2

RRVo=

85

a. 0,5%b. 0,25%c. 0,05%d. 0%

72. Hy cho bit mch sau c tn gi l g



Vo

R+R

R+R

R

R

IB

R

Vo

IB

R+R

R

R

Vo

R+R

VB

R+R

R-R

R-R

86

a. Mch cu Wheatstone , ngun pb. Mch cu Wheatstone , ngun pc. Mch cu Wheatstone , ngun dngd. Mch cu Wheatst

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