TUGAS MERENCANA KONSTRUKSI BAJA

Nama : Bob Ericson Sagune

NIM : 12050534262

Dosen Pembimbing : M. Imaduddin, S.T., M.T.

Jarak Gording

Kemiringan atap = 150

Sin α = 0.2588 ; Cos α = 0.9659 ; Tg α = 0,2679

Panjang sisi miring = ½ bentang : cos α = 9 : 0.9659 = 9,3177 m

Tinggi kuda-kuda = ½ bentang x tg α = 9 x 0,2679 = 2,411 m

Jarak antar gording = 9,3177 : 9 = 1,03 m

I. Analisis Beban

A. D (Beban Mati)

1. Penutup/atap fiber cement (Sumber : https://keramiklokal.wordpress.com) = 20 kg/m2 = 120 kg/m

2. Beban/berat gording profil size : 200 x 75 x 20 x 3.2 (mm) = 9,27 kg/m

3. Aksesoris = (120 kg/m + 9,27 kg/m) x 10 % = 12,93 kg/m.

qD = 120 kg/m + 9,27 kg/m + 12,93 kg/m = 142,2 kg/m qDy = qD x cos α = 142, 2 kg/m x cos 15 = 137,35 kg/m

B. Beban Hidup

Pekerja = 100 kg

C. Beban Hujan

Hujan = 25 kg/m2 = 25 kg/m2 x 6 m = 150 kg/m

A. Angin (W)

Beban angin = 40 kg/m2 x 6 m = 240 kg/m

II. Analisa Struktur : Gording

A. Momen (MD ; ML ; MH ; MW)

1. MD = 18

. qD . L2 =

18

. 142,2 .62 = 639,9 kgm

a. MDx = 1/8. qD. Cos α . L2 = 1/8. 142,2 kg/m. 0.9659. 62 = 618,079 kg

b. MDy = 1/8. qD. Sin α. L/3 = 1/8. 142,2 kg/m. 0,2588. 6/3 = 9,200 kg

2. ML = 14

. P . L = 14

. 100 .62=900 kgm

a. MLx = ¼. qL. Cos α. L = ¼ . 100 kg. 0,9659. 6 = 144,885 kgm

b. MLy = ¼. qL. Sin α. L/3 = ¼. 100 kg. 0,2588. 6/3 = 12,79 kgm

3. MH = 1/8. qH. L2 = 1/8. 150 kg/m. 62 m = 675 kg/ma. MHx = 1/8. qH . cos α. L2 = 1/8. 150 kg/m . 0,9659 . 62 m = 651,98

kg

b. MHY = 1/8. qH. Sin α . L/3 = 1/8. 150 kg/m. 0,2588. 6/3 m = 9,705 kg

4. MW = 1/8. qW. L2 = 1/8. 240 kg/m. 62 m = 1080 kg

a. MWx = 0

b. MWy = MW = 1080 kg

III. Tabel Momen

A. Arah X

MUx MDx MLx MHx MWx Keterangan

1784,863 618,079 144,885 651,98 0 1.2D + 1.6H + 0.8W

B. Arah Y

MUy MDy MLy MHy MWy Keterangan

1412,280 9,200 12,79 9,705 1080 0.9D + 1.3W

MUxmaks = 1784,863 MUymaks = 1412,280