uan Cua Mai Lan

THIT K MNG LI IN KHU VC GM MT NGUN IN V MT S PH TI KHU VC

THIT K MNG LI IN KHU VC GM MT NGUN IN V MT S PH TI KHU VCCHNG I: PHN TCH NGUN V PH TI*********

I S A L:

6

1N5

4

3

2

1.1. Nhng s liu ngun cung cp.

Ngun c cng sut v cng ln.1.2. Nhng s liu v ph ti.

Trong h thng in thit k gm 6 ph ti ( t ph ti 1 n ph ti 6).

+ Trong c ph ti 1 n ph ti 5 thuc h loi I chim 83,3%.

+ Ph ti 6 l h loi III chim 16,7%.S liu tnh ton ca cc ph ti cho trong bng di yPh tiThuc h loiSmax(MVA)Smin

(MVA)Pmax(MW)Pmin(MW)Qmax(MVAr)Qmin(MVAr)cos(yu cu caUH(kV)

1I422135,717,8522,2611,130,85T22

2I302025,51715,910,60,85KT22

3I433036,5525,522,7915,90,85KT22

4I492441,6520,425,9712,720,85KT22

5I462839,123,824,3814,840,85KT22

6III372231,4518,719,6111,660,85T22

Tng209,95123,25

Trong :Cng sut tiu th ca cc ph ti khc nhau, cng sut tiu th cc tiu bng 58,7% ph ti cc i.

Pmin = 58,7% Pmax.

Smax = Pmax+ jQmax.

Smin= Pmin+jQmin. Tmax= 5000h (thi gian s dng cng sut cc i).

II- Phn tch ngun v ph ti2.1 Ngun inTrong thit k li in, vic phn tch ngun in nm vng c im v s liu ca ngun, thun li cho vic tnh ton. Ta s dng ngun c cng sut v cng ln:- Ngun cng sut v cng ln l ngun c in p u cc khng thay i v bin d c xy ra s c g sau n

- Cng sut ngun ln (57) ln cng sut ti.2.2 Ph ti- Cc h ph ti loi I l nhng h quan trng, v vy phi d phng chc chn. Mi ph ti phi c cp in bng mt l ng dy kp v hai my bin p lm vic song song m bo cp in lin tc cng nh m bo cht lng in nng mt ch vn hnh. Khi ngng cp in c th lm hng sn phm, h hi thit b gy nh hng ln n hot ng ca ph ti.

- Cc h ph ti loi III l cc h ph ti t quan trng hn nn gim chi ph u t ta ch cn cp in bng mt ng dy n v mt my bin p.

- Yu cu iu chnh in p. Trong mng in thit k cc h 2,3,4,5 c yu cu iu chnh in p khc thng. phng php ny lch in p phi tha mn cc ch nh sau:

Ch ph ti cc i: du% 5% Um.

Ch ph ti cc tiu: du% 0% Um.

Ch s c:

0% du% 5% Um.

Cc ph ti 1 v 6 c yu cu iu chnh in p thng nn phm vi chnh in p ch cc i, cc tiu, s c l:

-2,5% Um. du% +10% Um.- Tt c cc ph ti u c in p h nh nhau l 22 kV, h s cng sut ca cc h u cos( = 0.85.III- Cn bng cng sut trong h thng in

c im c bit ca ngnh sn xut in nng l in nng do cc nh my in trong h thng sn xut v cn bng vi in nng tiu th ca cc ph ti.Do vy cn bng cng sut nhm n nh ch vn hnh ca h thng.

Do y ta s dng ngun c cng sut v cng ln nn c th p ng vi cng sut v cht lng in p cho cc ph ti.Ta khng cn cn bng cng sut.

CHNG II: D KIN CC PHNG N, TNH TON S BLA CHN PHNG N*********2.1 Chn in p nh mc cho li in

La chn cp in p nh mc cho mng in l nhim v rt quan trng, v tr s in p nh hng trc tip n cc chi ph kinh t, k thut ca mng in. chn c cp in p hp l phi tha mn cc yu cu sau:

Phi p ng c yu cu m rng ph ti sau ny. m bo tn tht in p t ngun n ph ti.

- Khi in p cng cao th tn tht cng sut cng b, s dng t kim

loi mu (I nh). Nhng in p cng tng cao th chi ph xy dng mng in cng ln v gi thnh thit b cng tng. V vy phi chn in p nh mc nh th no cho ph hp v kinh t v k thut.

Chn in p ti u theo cng thc kinh nghim:

Ui = 4,34. ( kW, km, MW).Trong :

Ui - in p ng dy th i (kV).

li - khong cch t ngun n ph ti th i ( km).

Pi - cng sut ln nht trn ng dy th i(MW).Ta c bng s liu:Ph tiSmax(MVA)Pmax(MW)li

(km)Ui

(kV)U m

(kV)

135,7+j22,2635,7045,35107,76110

225,5+j15,925,5079,3295,81

336,55+j22,7936,5544,00108,83

441,65+j25,9741,6546,67115,89

539,1+j24,3839,1045,35112,42

631,45+j19,6131,4549,19102,00

T bng s liu trn ta thy rng in p ti in trong khong (95,81115,89) chn in p nh mc cho mng in l Um = 110kV.

2.2 D kin cc phng n ni dy.

Mng in thit k gm 1 ngun in v 6 ph ti, trong c 5 ph ti loi I, 1 ph ti loi III. Cc phng n ni dy d vo cc yu t sau:

+ V tr ngun v ph ti.

+ m bo cht lng in nng, kinh t.

+ m bo vn hnh an ton, tin cy v linh hot.

Ta c th a ra cc phng n nh sau:Phng n I:

6N

5

1

4

3

2

Phng n II:

6N

5

1

4

3

2Phng n III:

N

65

1

4

3

2

Phng n IV:

N

65

1

4

3

2Phng n V:

N

6

5

1

4

3

22.3 Tnh ton chn tit din dy dn

Do mng in thit k c Um =110kV. Tit din dy dn thng c chn theo phng php mt kinh t ca dng in Jkt.

Fkt =. (*)

Vi Imax l dng in cc i trn ng dy trong ch lm vic bnh thng, c xc nh theo cng thc:

Imax = =

Trong :

Jkt - mt kinh t ca dng in.

Um - in p nh mc ca dng in. (kV)

Smaxi - cng sut trn ng dy th i khi ph ti cc i.(MVA) n - s l ng dy.

Ta s dng dy nhm li thp truyn ti vi thi gian s dng cng sut cc i ca ph ti l 5000h. Jkt c tra theo bng trang 295_Thit k cc mng v h thng in_NXB khoa hc k thut 2008, ta c mt kinh t ca dng in Jkt = 1,1 A/mm2 .

Da vo tit din dy dn tnh theo cng thc (*), tit hnh chn tit din tiu chun gn nht v kim tra cc iu kin v s to thnh vng quang. bn c v ng dy v iu kin php nng ca dy dn.

* Kim tra iu kin vng quang.

Theo iu kin, tit din dy dn khng c nh hn tr s cho php i vi mi cp in p.

Vi cp in p 110kV, khng xut hin vng quang tit din dy dn ti thiu c php l 70mm2 .

* Kim tra pht nng dy dn.

Theo iu kin:

Isc max < k. Icp.Trong :

Icp - dng in cho php ca dy dn, n ph thuc vo bn cht v tit din ca dy.

k - h s quy i theo nhit Khc = 0.8 ng vi nhit l 25oc.

i vi ng dy kp : Isc max = 2.Ibt max < 0.8 Icp.

i vi ng dy n khi c s c s dn n mt in.

2.4 Tiu chun tn tht in p

Cc mng in 1 cp in p t tiu chun k thut nu trong ch ph ti cc i cc tn tht in p ln nht trong ch lm vic bnh thng v ch s c nm trong khong sau y:

i vi nhng mng in phc tp (mng in kn), c th chp nhn tn tht in p ln nht trong ch ph ti cc i v ch s c nm trong khong:

Trong (Ubt Max , (Usc Max l tn tht in p lc bnh thng v lc s c nng n nht.

Ta tnh tn tht theo cng thc:

(Ui (%) = %

Pi ,Qi l cng sut tc dng v cng sut phn khng trn ng dy th i (MW, MVAr).

Ri, Xi l in tr tc dng v in khng ca ng dy th i().2.5 Tnh ton c th tng phng nPhng n I1. S :

N

65

1

4

3

22. La chn tit din dy dna - on ng dy N-1

Chn tit din dy dn.

Imax N-1 = = .103= 110,22 (A)

Fkt = = = 100,2Chn dy dn loi AC- 95,c tit din chun l 95mm2 v dng in cho php Icp=330A.

- Kim tra theo iu kin vng quang: dy dn chn c:

Ftc=95mm2 70 mm2 ( tha mn iu kin).

- Kim tra theo iu kin pht nng: v on N-1 l ng dy kp nn khi hng mt l th l cn li vn phi lm vic bnh thng.Do dng in trong ch s c phi nh hn h s k nhn vi dng in cho php ca dy dn:

Isc = 2.Ibt max = 2.110,22 = 220,44 (A)

Isc < 0,8.Icp = 330A ( tha mn iu kin ).

Kim tra tn tht in p trn ng dy.

Vi loi ng dy AC- 95 ta c: ro=0.33/km, xo=0.429/km

in tr v in khng ng dy :

R=ro.l =0,33.45,35=7,48 ().

X =xo .l =0,429.45,35=9,73().

- Tn tht in p ch bnh thng :

(U1bt % = =

EMBED Equation.3 4 %

- Tn tht in p ch s c:

(U1sc % =2. (U1bt % = 2. 4 % = 8 %b - on ng dy N-6 Chn tit din dy dn:

Imax = =.103 =194,2(A)

Fkt = = 176,55

Chn dy dn loi AC-185 c tit din chun l 185mm2 v dng in cho php Icp= 510 A.


Ftc=185mm2 > 70 mm2 ( tha mn iu kin).

- Kim tra theo iu kin pht nng : v on N-6 l ng dy n nn khi xy ra s c s dn n mt in, khng tnh n Isc.


Vi loi ng dy AC- 185 ta c: ro=0.17/km, xo=0.409/km


R=ro.l =1.0,17.49,19=8,36 ().

X =xo .l =.0,409.49,19=20,12()..

- Tn tht in p ch bnh thng

(U1bt % = =

EMBED Equation.3 4,39% Khng tnh n tn tht in p ch s c. Cc on dy cn li tnh tng t, ta c cc bng s liu tnh ton.Bng chn tit din dy dnonng dy s ll(km)Smax(MVA)Imax

(A)FktLoi dyro

()xo

()

N-1245,3535,7+j22,26110,22100,2AC-950,330,429

N-2270,3225,5+j15,978,7371,57AC-700,450,44

N-324436,55+j22,79112,85102,59AC-950,330,429

N-4246,6741,65+j25,97128,59116,9AC-1200,270,423

N-5245,3539,1+j24,38120,72109,75AC-1200,270,423

N-6149,1931,45+j19,61194,2176,55AC-1850,170,409

Bng kim tra iu kin pht nng ca dy dnon ng dyImaxIsck,Icp(A)

N-1110,2220,4264

N-278,73157,5212

N-3112,9225,7264

N-4128,6257,2304

N-5120,7241,4304

N-6194,2408

Theo s liu tnh ton bng trn,cc dy dn chn tha mn iu kin pht nng.Bng tnh tn tht in pon ngdyR()X()(Ubt%(Usc%

N-17,489,7348

N-217,8517,456,0512,1

N-37,269,443,977,94

N-46,309,874,298,57

N-56,129,593,917,82

N-68,3620,125,43

Theo bng trn ta thy:

(Ubt max%= 6.05 < 10%

(Uscmax% = 12.1 < 20% (tha mn iu kin)

Vy phng n I t yu cu k thut.

Phng n II

1. S :

N

6

5

1

43

2

2-La chn tit din dy dna- on ng dy 5-4 Chn tit din dy dn.

5-4 = 4= 41,65+ j25,97 (MVA).

Imax 5-4 = = =128,59 (A)

Fkt = . = = 116,9Chn dy dn loi AC- 120 ,c tit din chun l 120mm2 v dng in cho php Icp=380A.

- Kim tra theo iu kin vng quang: dy dn chn c :


- Kim tra theo iu kin pht nng : on 5-4 l ng dy kp nn khi hng mt l th l cn li vn phi lm vic bnh thng .

Isc = 2.Ibt max = 2.128,59 = 257,18 (A)

Isc < 0,8.Icp = 304 A ( tha mn iu kin ) Kim tra tn tht in p trn ng dy.Vi loi ng dy AC- 120 ta c: ro=0,27/km, xo=0.423/kmin tr v in khng ng dy :

R=ro.l =.0,27.45,35=6,12 ().

X =xo .l =.0,423.45,35=9,59().


(U5-4 bt % = =

EMBED Equation.3 4,11%


(U5-4sc % 2. (U5-4bt % = 2. 4,11% = 8,22%.

b- on ng dy N-5 Chn tit din dy dn.

N-5=5+4 =(39.1+j24.38)+(41.65+j25.97)=80.75+j50.35 (MVA).

Imax N-5 = = 249,31 (A)

Fkt = . = = 26,65Chn dy dn loi AC- 240 ,c tit din chun l 240mm2 v dng in cho php Icp=610A.


Ftc=240mm2 70 mm2 ( tha mn iu kin).

Kim tra theo iu kin pht nng :

Isc = 2.Ibt max = 2.249,31 = 498,62 (A)

Isc > 0,8.Icp =488 A (khng tha mn iu kin ).

Chn li dy dn loi AC-300 ,tit din chun 300 mm2 v dng in cho php l 690A



- Kim tra theo iu kin pht nng:

Isc = 2.Ibt max = 2.249,31 = 498,62 (A)

Isc < 0,8.Icp =552 A(tha mn iu kin) Tnh tn tht in p trn ng dy.

Vi loi ng dy AC-300 ta c: ro=0,108/km, xo=0,392/km


R=ro.l =.0,108.45,35=2,45 ().

X =xo .l =.0,392.45,35=8,89().


(UN-5 bt % = =



(UN-5sc % 2. (UN-5bt % = 2.2,58% =5,16%.

Cc on ng dy cn li tnh phng n I, ta c cc bng s liu:Bng chn tit din dy dnonng dy s ll(km)Smax(MVA)Imax

(A)FktLoi dyro

()xo

()

N-1245,3535,7+j22,26110,22100,2AC-950,330,429

N-2270,3225,5+j15,978,7371,57AC-700,450,44

N-324436,55+j22,79112,85102,59AC-950,330,429

5-4245,3541,65+j25,97128,59116,9AC-1200,270,423

N-5245,3539,1+j24,38120,72109,75AC-1200,270,423

N-6149,1931,45+j19,61194,2176,55AC-1850,170,409


N-1110,22220,44264

N-278,73157,46212

N-3112,85225,7264

5-4128,59257,18304

N-5249,31498,62552

N-6194,2408

Theo s liu tnh ton bng trn ,cc dy dn chn tha mn iu kin pht nng.

Bng tnh tn tht in p

on ng dyR()X()(Ubt %(Usc%

N-17,489,7348

N-217,8517,456,0512,1

N-37,269,443,977,94

5-46,129,594,168,32

N-52,458,872,585,16

N-68,3620,125,43

Theo bng trn ta tht tn tht in p ln nht trn on ng dy lin thng N-5-4:

(Ubt max%= 4,16+2,58 = 6,74 < 10%

(Usc max% = 8,32+5,16=13,48 < 20% (tha mn iu kin)

Vy phng n II t yu cu k thut.Phng n III

1. S

N

65

1

4

3

22. La chn tit din dy dna - on ng dy 3-2 Chn tit din dy dn.

3-2 =2 =25,5+j15,9 (MVA).

Imax 3-2 = =

EMBED Equation.3 = 78,73 (A)

Fkt = = = 71,57

Chn dy dn loi AC- 70, c tit din chun l 70mm2 v dng in cho php Icp=265A.


Ftc=70mm2 ( tha mn iu kin).

- Kim tra theo iu kin pht nng :

Isc = 2.Ibt max = 2.78,73 = 157,46 (A)

Isc < 0,8.Icp = 265A ( tha mn iu kin ). Kim tra tn tht in p trn ng dy.

Vi loi ng dy AC-70 ta c: ro=0,45/km, xo=0.44/km


R=ro.l =0,45.49,19=11,07().

X =xo .l =0,44.49.19= 10,82().


(U3-2bt % = =3,75% Tn tht in p ch s c:

(U1sc % 2. (U1bt % = 2. 3,75 % = 7,51 %b - on ng dy N-3 Chn tit din dy dn:

N-3 =3 +2 =(36,55+j22,79)+(25,5+j15,9)=62,05+j38,69 (MVA)

Imax = =

EMBED Equation.3 =191,58(A)

Fkt = = 174,16





Isc = 2.Ibt max = 2.191,58 = 383,16 (A)

Isc < 0,8.Icp = 510 (tha mn iu kin).


Vi loi ng dy AC- 185 ta c: ro=0,17/km, xo=0,409/km


R=ro.l = 0,17.44=3,74().

X =xo .l = 0,409.44=9()..


(UN-3bt % = =



(UN-3sc % 2. (UN-3bt % = 2. 4,8 % = 9,59 %.

Cn li cc on ng dy N-1,N-6 tnh phng n I,cc on ng dy N-5,5-4 c tnh phng n II. Ta c cc bng s liu sau:Bng chn tit din dy dnon ngdys ll

(km)Smax

(MVA)Imax

(A)FktLoi dyro

()xo

()

N-1249,1935,7+j22,26110,22100,20AC-950,330,429

3-2249,1925,5+j15,978,7371,57AC-700,450,44

N-324462,05+j38,69191,58174,16AC-1850,170,409

5-4245,3541,65+j25,97128,59116,90AC-1200,270,423

N-5245,3580,75+j50,35249,31226,65AC-3000,1080,391

N-6145,3531,45+j19,61194,2176,55AC-1850,170,409


N-1110,22220,44264

3-278,73157,46212

N-3191,58383,16408

5-4128,59257,18304

N-5249,31498,62552

N-6194,2408


Bng tnh tn tht in p

on ng dyR()X()(Ubt %(Usc%

N-17,489,734,007,99

3-211,0710,823,757,51

N-33,749,004,809,59

5-46,129,594,178,33

N-52,458,875,3210,65

N-68,3620,125,43

Ta c tn tht in p ng dy lin thng N-3-2:

(Ubt %= 3,75+4,8=8,55%

(U sc% =7,51+9,59=17,46

Tn tht in p ng dy lin thng N-5-4:

(Ubt % = 6,74%

(Usc % =13,48%

Vy tn tht in p ln nht l :

(Ubt max%= 8,55 < 10%

(Umax sc% = 17,46 < 20% (tha mn iu kin)

Vy phng n III t yu cu k thut.

Phng n IV

1. S

N

6

5

1

4

3

22. La chn tit din dy dna - on ng dy1-2 Chn tit din dy dn.

1-2= 2=25,5+j15,9 (MVA).

Imax 1-2 = =


Fkt = . = = 71,57

Chn dy dn loi AC- 70 ,c tit din chun l 70mm2 v dng in cho php Icp=265A.


Ftc=70mm2 ( tha mn iu kin).


Isc = 2.Ibt max = 2.78,73 = 157,46 (A)

Isc < 0,8.Icp = 265A ( tha mn iu kin ).


Vi loi ng dy AC-70 ta c: ro=0,45/km, xo=0.44/km


R=ro.l =0,45.55=12,38().

X =xo .l =0,44.55= 12,1().


(U1-2bt % = =



(U1-2sc % =2.U1-2bt % = 2. 4,2 % = 8,4 % b - on ng dy N-1 Chn tit din dy dn:

N-1=1+2 =(35,5+j22,26)+ (25,5+j15,9)=61+j38,16(MVA)

Imax = =


Fkt = = 171,77




Kim tra theo iu kin pht nng:

Isc = 2.Ibt max = 2.188,95 = 311,9 (A)

Isc < 0,8.Icp = 510 (tha mn iu kin).

- Kim tra tn tht in p trn ng dy.



R=ro.l = 0,17.45,35=3,85().

X =xo .l = 0,409.45,35=9,27()..


(UN-1bt % = =


-Tn tht in p ch s c:

(UN-3sc % =2.(UN-3bt % = 2. 4,87 % = 9,74 %. c -on ng dy 4-3 Chn tit din dy dn.

4-3 =3= 36,55+j22,79 (MVA).Imax 4-3 = =


Fkt = . = = 102,59

Chn dy dn loi AC- 95 ,c tit din chun l 95mm2 v dng in cho php Icp=330A.


Ftc = 95mm2 > 70mm2 ( tha mn iu kin).


Isc = 2.Ibt max = 2.112,85 = 225,7 (A)

Isc < 0,8.Icp = 330 A ( tha mn iu kin ).


Vi loi ng dy AC- 95 ta c: ro=0,33/km, xo=0.429/km


R=ro.l =0,33.34,79=5,74().

X =xo .l =0,429. 34,79 =7,46().


(U4-3bt % = =



(U1sc % =2. (U1bt % = 2. 3,14% = 6,28 % d - on ng dy N-4 Chn tit din dy dn:

N-4 =4 +3 =(41,65+j25,97)+(36,55+j22,79)=78,2+j48,76(MVA)

Imax = =


Fkt = = 219,49


- Kim tra theo iu kin vng quang: dy dn chn c



Isc = 2.Ibt max = 2.241,44=482,88 (A)

Isc < 0,8.Icp = 671(tha mn iu kin). kim tra tn tht in p trn ng dy.



R=ro.l = 0,131. 46,67=3,06().

X =xo .l = 0,401. 46,67= 9,36()..


(UN-4bt % = =

EMBED Equation.3 5.75%

-Tn tht in p ch s c:

(UN-4sc % 2. (UN-4bt % = 2. 5.75% = 11,5 %.

Cn li cc on ng dy N-5,N-6 tnh phng n I, ta c cc bng s liu sau:Bng chn tit din dy dnon ngdys ll

(km)Smax

(MVA)Imax

(A)FktLoi dyro

()xo

()

N-1249,1961+j38,16188,95171,77AC-1850,170,409

1-225525,5+j15,978,7371,57AC-700,450,44

4-3234,7936,55+j22,79112,85102,59AC-950,330,423

N-4246,6778,2+j48,76241,44219,49AC-2400,1310,401

N-5245,3539,1+24,38120,72109,75AC-1200,270,429

N-6149,1931,45+j19,61194,2176,55AC-1850,170,409


N-1188,95377,9408

1-2 78,73157,46212

4-3112,85225,7264

N-4241,44482,88488

N-5120,72241,44304

N-6194,2408

Theo s liu tnh ton bng trn ,cc dy dn chn tha mn iu kin pht nng.Bng tnh tn tht in pon ng dyR()X()(Ubt %(Usc%

N-13,859,274,879,75

1-2 12,3812,104,208,40

4-35,747,463,146,28

N-43,069,365,7511,5

N-56,129,593,917,82

N-68,3620,125,43

Ta thy tn tht in p ng dy lin thng N-1-2:

(Ubt % = 4,87+4,2=9,07%

(Usc % =9,75+8,4=18,15%

Tn tht in p ng dy lin thng N-4-3

(Ubt % = 3,14+5,75=8,89 %

(Usc % =6,28+11,4=17,68 %

Tn tht in p ln nht l :

(Ubt max%= 9,07 < 10%

(Umax sc% = 18,15 < 20% (tha mn iu kin)

Vy phng n IV t yu cu k thut.

Phng n V

1. S

N

6

5

1

4

3

2

2. La chn tit din dy dn

phng n ny cc ph ti 3 v 4 ni vi nhau thnh mch kn. Cc

ph ti cn li c tnh ging phng n I.

Ta ch tnh ton on mch kn N-3-4-N.

* Tnh phn cng sut trn on ng dy.

Gi s cc ng dy c cng tit din, mch in ng nht ,ta c :

- Cng sut trn on N-4.

N-4=

= 38,98+j24,3 (MVA).

Cng sut trn on N-3.

N-3 = 4+ 3 - N-4

= (41,65+j25,97)+(36,55+j22,79)-(38,98+j24,3) = 39,22+j24,46 (MVA).

Cng sut trn on 3-4. 3-4 = N-3 3 = (39,22+j24,46) (36,55+j22,79) = 2,67+j1,67 (MVA).

Vy im ph ti 4 l im phn cng sut.

a - on ng dyN-4 Chn tit din dy dn.

Imax = =

EMBED Equation.3 = .103=241,09 (A)

Fkt = . = = 219,17Chn dy dn loi AC- 240 ,c tit din chun l 240mm2 v dng in cho php Icp=610A.- Kim tra theo iu kin vng quang: dy dn chn c:

Ftc=240mm2 > 70 mm2 ( tha mn iu kin).- Kim tra theo iu kin pht nng : i vi ng dy N-4 c 2 trng hp vn hnh s c :

+ trng hp s c on 4-3

+ trng hp s c on N-3

Ta thy rng trng hp s c on N-3 nguy him hn v phi ti mt lng cng sut ti ph ti 3.Khi c s c on N-3,cng sut chy trn on cn li l

= =(36,55+j22,79)+(41,65+j25,97)=78,2+j48,76 (MVA)

IscN-4 = ==482,87 A

Isc N-4= 482,87A < 0,8Icp(tha mn iu kin)b- on ng dy N-3

Imax ==242,87 A

Fkt = . = =220,79

Chn dy dn AC-240, Icp=610A


Ftc=240mm2 >70 mm2 ( tha mn iu kin).

- Kim tra theo iu kin pht nng : i vi ng dy N-3 c 2 trng hp vn hnh s c :

+ trng hp s c on 4-3


Cng ging nh ng dy N-4,s c nguy him nht l on N-4 .Khi c s c on N-4,cng sut chy trn on cn li l = =78,2+j48,76 (MVA)

IscN-3 = IscN-4 =482,87 A

Isc N-3= 482,87A < 0,8 Icp(tha mn iu kin)

c- on ng dy 3-4

Imax ==16,53 A

Fkt = . = =15,03

Tit din ti thiu cho cp in p 110 kV l 70 mm2 .Chn dy dn AC-70 tha mn iu kin vng quang vi Icp=610A

Kim tra theo iu kin pht nng : vi ng dy ny c 2 TH vn hnh s c



S c ng dy N-4 nguy him hn do ph ti ca n ln hn

Isc = =257,62A >0,8Icp

Chn li tit din AC-95 vi Icp =330, Isc < 0,8Icp(tha mn).Cc on ng dy cn li c chn phng n I , ta c bng s liu sauon ngdys ll(km)Smax

(MVA)Imax

(A)FktLoi dyro

()xo

()

N-1245,3535,7+j22,26110,22100,2AC-950,330,429

N-2270,3225,5+j15,978,7371,57AC-700,450,44

N-314436,55+j22,79242,6220,55AC-2400,1310,401

N-4146,6741,65+j25,97241,09219,7AC-2400,1310,401

3-4134,792,67+j1,6716,5315,03AC-950,330,429

N-5245,3539,1+j24,38120,72109,75AC-1200,270,423

N-6149,1931,45+j19,61194,2176,55AC-1850,170,409


N-1110,2220,4264

N-278,73157,5212

N-3242,6482,87488

N-4241,09482,87488

4-316,53257,18265

N-5120,7241,44304

N-6194,2408


Kim tra tn tht in p trn ng dyTnh tn tht in p trn on ng dy kn N-3-4-N

Loi AC-240 c ro=0,131/km, xo=0,401/km

- in tr in khng ng dy N-3

R=ro.l = 1. 0,131. 44=5,76().

X =xo .l =1. 0,401. 44= 17,64()..

- in tr in khng ng dy N-4

R=ro.l = 1.0,131. 46,67=6,11().

X =xo .l =1. 0,401. 46,67= 18,72().

Loi AC-95 c ro=0,33/km, xo=0.429/km

- in tr in khng ng dy 3-4

R=ro.l = 1.0,33. 34,79=11,48().

X =xo .l =1. 0,429.34,79= 14,93().

* Tn tht in p lc bnh thng:Xt on N-3:(UbtN-3% =

=

Trn on N-4:

(UbtN-4% =

=

Xt on 3-4

(Ubt3-4% =

==0,47%* Ch lm vic s c ch lm vic s c ch xt trng hp nng l nht , l s c on ng dy t ngun n im phn b cng sutTrng hp s c trn on N-3 :(UscN-4-3% =

=

=14,72%Trng hp s c trn on N-4 :(UscN-3-4% =

=

=17,9%Bng tnh tn tht in pon ng dyR()X()(Ubt %(Usc%

N-13,859,274,879,75

N-212,3812,14,28,4

N-35,7617,642,2214,72

3-411,4814,930,47

N-46,1118,715,7317,9

N-56,129,593,917,82

N-68,3620,125,43

Theo bng trn ta tht tn tht in p ln nht trn on ng dy kn N-3-4

(Ubt max%=5,73 < 10%

(Usc max% =17,9 < 20% (tha mn iu kin)

Vy phng n 5 t yu cu k thut.Bng tng kt tn tht in p ca 5 phng nPhng

n(Ubt %(Usc%

16,0512,1

26,7413,48

38,5517,46

49,0718,15

55,7317,9

Theo bng s liu trn,ta chn 2 phng n c tn tht nh nht tnh ton v mt kinh t l :

Phng n 1 vi :(Ubt max%= 6,05 %

(Uscmax% = 12,1 %

Phng n 2 vi : (Ubt max%= 6,74 %

(Usc max% = 13,48 %2.6 Tnh ton so snh cc phng n v kinh t

Khi tnh ton, thit k mng li in cn phi m bo yu cu v kinh t v k thut.Mc d trn thc t hai yu cu kinh t v k thut thng mu thun nhau, mt li in c ch tiu k thut tt, vn u t v chi ph vn hnh cao. Ngc li, li in c vn u t, chi ph vn hnh nh th tn tht cao, cu trc li in phc tp, vn hnh km linh hot, an ton thp.V vy vic nh gi tnh ton ch tiu kinh t ,k thut ca mt li in s m bo cho vic t ch tiu v k thut, hp l v kinh t.

so snh v mt kinh t ta s dng hm chi ph tinh ton hng nm:

Z = (atc + avh).K + (A.C

(1)Trong :

Z: l hm chi ph tn tht hng nm (ng).atc : h s thu hi vn tiu chun, =

= 0,125

Ttc: thi gian tiu chun thu hi vn u t

avh: h s khu hao hao mn thit b , y ly avh = 4% =0,04K: vn u t xy dng ng dy

K = x.(K0i.li = (Ki

K0i: chi ph cho 1 ng dy nhnh th i, tit din Fi.

li: chiu di chuyn ti th i ,(km)Vi ng dy n x= 1, ng dy kp x=1,6

(A: tn tht in nng , (kWh)(A = ((Pmax.( =(

(P: tn tht cng sut ton h thng khi ph ti cc i, (kW)(: thi gian tn tht ln nht ph thuc vo ph ti v tnh cht ca ph ti c tnh bng cng thc:( = (0,124 + Tmax.10-4)2.8760 (h)

Vi Tmax: thi gian s dng ph ti ln nht v ly bng Tmax = 5000 h

( = (0,124 + 5000.10-4)2.8760 = 3411 (h)C: gi in nng tn tht, C = 500/1kWh.Gi dy dn:

Loi dy AC-70AC-95AC-120AC-150AC-185AC-240AC-300

Gi

(106 / km)208283354403441500600

Tnh ton c th nh sau:

a. Phng n 1ng dyS lli(km)Loi dyxKoi(106)Ki(106 )Pi

(MV)Qi

(MVr)Ri

()(Pi(MV)

N-1245,35AC-951,628320534,4835,722,267,481,0942

N-2279,32AC-701,620826397,725,515,917,851,3322

N-3244AC-951,628319923,236,5522,797,261,1132

N-4245,35AC-1201,635425686,2441,6525,976,121,2185

N-5245,35AC-1201,635425686,2439,124,382,450,4299

N-6149,19AC-185144121692,7931,4519,618,360,9491

Tng139920,66,1370

T phng php tnh trn ta lp c bng s liu sau:

Tng vn u t xy dng ng dy :(Ki = 139920,6 .106()

Tng tn tht cng sut ton h thng : ((Pmax =6,1370 (MW)

Tng tn tht in nng :

(A =((Pmax . ( = 6,1370. 3411 =20933,07(MWh)

Theo cng thc (1) hm chi ph tnh ton:

Z=(0,125+0,04). 139920,6.106 +20933,07.500.103 =3,36.1010()b. Phng n 2bng s liu tnh tonng dyS lli(km)Loi dyxKoi(106)Ki(106 )Pi

(MV)Qi

(MVr)Ri

()(Pi(MV)

N-1245,35AC-951,628520679,661,238,167,483,216

N-2279,32AC-701,620826397,725,515,917,851,332

N-3244AC-951,628319923,236,5522,797,261,113

4-5245,35AC-1201,635425686,2441,6525,976,121,219

N-5245,35AC-3001,66004353680,7550,352,451,834

N-6149,19AC-185144121692,7931,4519,618,360,949

Tng157915,59,662

Tng vn u t xy dng ng dy (Ki = 157915,5.106 ()Tng tn tht cng sut ton h thng : ((Pmax =9,6621(MW)Tng tn tht in nng: (A =((Pmax . ( = 9,6621. 3411 =32957,42(MWh)Theo cng thc (1) hm chi ph tnh ton: Z=(0,125+0,04). 157915,5.106+32957,42.500.103 =4,25.1010().Bng tng kt tnh ton cc ch tiu kinh t, k thut ca cc phng n Phng n(Ubt%(Usc%K

(106 )Z

(1010)

I6,0512,1139920,63,36

II6,7413,48157915,54,25

Kt lun: phng n I l phng n ti u nht m bo v kinh t v k thut.mt khc phng n l phng n n gin c v s ni dy cng nh v b tr thit b bo v rle,my bin p, my ctcc ph ti khng lin quan n nhau,nn khi c s c mt ph ti s khng nh hng n cc ph ti khc,V vy phng n I l phng n ti u nht.CHNG III : TNH TON LA CHN MY BIN P

B TR KH C V THIT B TRN S NI IN CHNH*********

3.1 Tnh ton chn cng sut, s lng ,loi my bin p

Trm bin p l mt phn t rt quan trng ca h thng in, n c nhim v tip nhn in nng t h thng, bin i t cp in p ny sang cp in p khc v phn phi cho cc mng in tng ng.v vy vic la chn cc my bin p cn m bo tnh cht cung cp in lin tc v yu cu v kinh t ,k thut.3.1.1 Tnh ton chn cng sut nh mc, s lng my bin p cho ph ti

Tt c cc ph ti trong h thng bao gm h loi I v h loi III v vy m bo cung cp in cho cc ph ti ny ta cn t 2 my bin p i vi h loi I v 1 my bin p i vi h loi III .Trong n phng n ti u c chn phn trn gm 5 ph ti loi I (1,2,3,4,5) v 1 ph ti loi III(6).Nh vy cng sut ca my bin p trong trm c th xc nh theo cng thc sau:i vi ph ti loi III, TBA(trm bin p) c 1 MBA(my bin p)SmB SmaxPh ti loi I, TBA c 2 MBA lm vic song songSmB

EMBED Equation.3

Vi k: h s qu ti s c, ly k =1,4.a- Ph ti 1Ta c : P1= 35,7 (MW) , cos(1= 0,85

S1max= = 42 (MVA)

S1B( = 30 (MVA)

( Chn 2 MBA c cng sut nh mc l Sm =32(MVA).b- Ph ti 6

P1= 31,45 (MW) , cos(1= 0,85

S1max= = 37 (MVA)

S1B( 37 (MVA)

( Chn 1 MBA c cng sut nh mc l Sm =40(MVA).

Cc ph ti 2,3,4,5 tnh v chn tng t nh ph ti 1,ta c bng s liu sau

Ph tiThuc h loiSimax(MW)cos(Simax(MVA)SimB(MVA)

1I35,700,8542,0032

2I25,500,8530,0025

3I36,550,8543,0032

4I41,650,8549,0040

5I39,100,8546,0040

6III31,450,8537,0040

3.1.2 Chn loi MBATa chn MBA cho tng ph ti ,nu ph ti yu cu iu chnh in p thng th chn MBA 3 pha c u phn p c nh. Nu ph ti yu cu iu chnh in p khc thng th chon MBA c b iu chnh in p di ti .

Trong n c 2 ph ti yu cu iu chnh in p T (ph ti 1 v 6).cn li l ph ti yu cu iu chnh in p KT.Ta c bng thng s MBA chn:ph tis lLoi myBin pS liu k thutS liu tnh ton

Um (kV)Un (%)(Pn (kW)(P0 (kW)I0 (%)RX(Qo

CaoH()()kVAr

12TPD 32000/1101152210,5145350,751,8743,5240

22TPDH 25000/1101152210,5120290,82,5455,9200

32TPDH 32000/1101152210,5145350751,8743,5240

42TPDH 40000/1101152210,5175420,71,4434,8280

52TPDH 40000/1101152210,5175420,71,4434,8280

61TPD 40000/1101152210,5175420,71,4434,8280

3.2 B tr thit b v kh c in trn s ni in chnh.Do a phn ph ti l cc h tiu th loi I nn m bo cung cp in an ton v lin tc ta s dng s h thng hai thanh gp l vic song song.Khi vn hnh mt thanh gp vn hnh cn mt thanh gp d tr.

S h thng 2 thanh gp

i vi cc trm cui ta c 2 trng hp:

- Ph ti loi III : Ta dng s b ng dy-my bin

S b ng dy my bin p

- Ph ti loi I :ta dng s cu

S cu trong S cu ngoiTa c th chn s cu theo 2 k sau:- Chn theo cng sut ca MBA,tnh cng sut gii hn thay i 2 sang 1 MBA lm vic :Sgh = SmB .

EMBED Equation.3 = SmB . .

Nu Spt min Sgh s dng s cu ngoi.

Nu Spt min > Sgh s dng s cu trong.- Chn theo ng dy,s cu thng c phi hp vi ng dy:

S cu ngoi phi hp vi ng dy c l < 70 km

S cu trong phi hp vi ng dy c l 70 km.Do thao tc bn MBA quan trng hn ng dy,nn ta chn s cu trong, ngoi theo Sgh.

a- Ph ti 1L ph ti loi I , ta dng s cu:Sgh1= SmB1 . = 32.=22,234(MVA)

Spt min= 21< Sgh1 ( ta chn s cu ngoi.b- Ph ti 6L ph ti loi III nn ta dng s b ng dy-my bin p.Cc ph ti cn li l ph ti loi I tnh tng t nh ph ti 1

bng chn s cu:

Ph tiSm min(MVA)SmB(MVA)Pn(kW)Po(kW)Sgh(MVA)Chn

121321453522,234s cu ngoi

220251202917,381s cu trong

330321453522,234s cu trong

424401754227,713s cu ngoi

528401754227,713s cu trong

6------

Theo bng s liu tnh ph ti 1 v 4 ta dng s cu ngoi,ph ti 2,3,5 ta dng s cu trong .CHNG IV : TNH TON CH XC LP CA LI IN .

*********

Vic tnh ton ch xc lp ca mng in c ngha ht sc quan trng i vi vic tnh ton , thit k v vn hnh mng in. chng ny ta xc nh thng s ch xc lp trong cc trng thi ph ti cc i , cc tiu, v sau s c khi ph ti cc i. Khi xc nh cc dng cng sut v cc tn tht cng sut, ta ly in p tt c cc nt trong mng in bng in p nh mc l Ui = Um = 110 kV.4.1 Ch ph ti cc i.

a. on N-1:* S nguyn l :

=35.7+j22.26*S thay th:

*Tnh thng s:

+Dy dn:

Dy dn AC-95 c ro=0,33/km, xo=0,429/km,bo=2,65.10S.

RN-1=ro.lN-1 =0,33.45,35=7,48 ().

XN-1 =xo .lN-1 =0,429.45,35=9,73().

BN-1 = n.Bo.lN-1 = 2. 2,65.10.45,35 = 2,404. 10-4 (S).+TBA:

MBA- 32000/110 c UN%= 10,5% (Pn = 145 kW(P0 =35 kW

Io% = 0,75%UC m=115 kV Sm = 32 MVA

UH m = 22 kV.

in tr, in khng ca MBA:

R1B =

=

=1,872 ().

X1B = =

=43,395 ().

Z1B =.( R1B +jX1B) =.(1,872+j43,395) =0,936+j21,7().+Ph ti:

1 =35.7+j22.26(MVA).

*Tnh ch xc lp:

Ta c UN = 1,1.Um= 121 kV.- Cng sut sau tng tr ca MBA

= 1 = 35.7+j22.26(MVA)

- Tn tht cng sut trn tng tr TBA

= .Z1B = .(0,936+j21,698) =0,137 + j3,174(MVA).- Cng sut trc tng tr TBA

=+ = (35,7+22,26) + (0,137 + j3,174) = 35,837 +j25,434(MVA).- Tn tht cng sut lc khng ti

= n( +j) =2.(35.10-3+j)= 0,07+j0,48 (MVA).

- Cng sut trn thanh gp cao p ca MBA

B1 = + = (35,837 +j25,434) +(0,07+j0,48) = 35,907+j25,914(MVA).

- Cng sut phn khng do dung dn ca ng dy N-1 sinh ra

jQcc = jUm2.N-1=j.1102.2,404.10-4 = j1,454( MVAr)- Cng sut sau tng tr ng dy

=B1 - jQcc =(35,907+j25,914)- j1,454 =35,907 +24,46 (MVA) - Tn tht cng sut trn tng tr ng dy :

=.ZN-1 = .(7,48+j9,73) =1,167 + j1,518(MVA). - Cng sut trc tng tr dy dn :

=(35,907 +24,46)+ (1,167 + j1,518)= 37,074+j25,978(MVA).

- Cng sut phn khng do dung dn u ng dy sinh rajQcc = jUN2.N-1=j.1212.2,404.10-4 = j1,76( MVAr)

- Cng sut u ngun

N-1 = S - jQcc =(37,074+j25,978)- j1,76 = 37,074 +j24,218(MVA).-Tn tht in p trn ng dy N-1

UN-1 = = =4,381(kV)

- in p ti nt 1U1 = UN - UN-1 = 121-4,381 =116,619 (kV)- Tn tht in p trn MBA

UB1 = =

EMBED Equation.3 =5,020 (kV)

in p nt quy i v pha cao p

U2 = U1- UB1 = 116,619- 5,020 = 111,599 (kV)

in p thc nt 2

U2 == U2 .= 111,599. =21,349 (kV).- Tn tht in nng trn ng dy:

(AN-1 = (PN-1.( = 35,7.3411.10-3 = 121,772 (MWh)- Tn tht in nng trn trm bin p: (AB1 = n.(P0.t + = (2.35.8670+3411). 10-3 =1032,909(MWh)- Tng tn tht in nng:

(AN-1 = (AN-1 + (Ab1 = 121,772 + 1032,909= 1154,681 (MWh)b. on N-6.

* S nguyn l :

N6

49,19 kmS6 =31,45+j 19,61

TPD-40000/110*S thay th:

*Tnh thng s:

+Dy dn:

Dy dn AC-185 c ro=0,17/km, xo=0,409/km,bo=2,82.10S.

RN-6=ro.lN-6 =0,17.49,19=7,48 ().

XN-1 =xo .lN-1 =0,409. 49,19=9,73().

BN-1 = n.Bo.lN-1 = 2,65.10.49,19= 1,39. 10-4 (S).

+TBA:

MBA- 40000/110 c UN%= 10,5% (Pn = 175 kW(P0 =42kW

Io% = 0,7%

UC m=115 kV Sm = 40 MVA

UH m =22kV.

in tr, in khng ca MBA:

R6B =

=

=1,446 ().

X6B = =

=34,72 ().

Z1B =.( R1B +jX1B) =1,446+j34,72().

+Ph ti:

1 =31,45+j19,61(MVA).

* Tnh ch xc lp:

Ta c UN = 1,1.Um= 121 kV.

- Cng sut sau tng tr ca MBA

= 6 = 31,45+j19,61 (MVA) - Tn tht cng sut trn tng tr TBA

= .Z6B = .(1,446+j34,72) =0,164 + j3,942(MVA).

- Cng sut trc tng tr TBA

=+ = (31,45+j19,61) + (0,164 + j3,942)= 31,614 +j23,552(MVA).- Tn tht cng sut lc khng ti

= n( +j) =(42.10-3+j)= 0,042+j0,28 (MVA).

- Cng sut trn thanh gp cao p ca MBA

B6 = + = (31,614 +j23,552)+(0,042+j0,28) = 31,656+j23,832(MVA).

- Cng sut phn khng do dung dn ca ng dy N-1 sinh ra

jQcc = jUm2.N-6=j1102. 1,39.10-4 = j0,841( MVAr)

- Cng sut sau tng tr ng dy

=B6 - jQcc =(31,656+j23,832)- j0,841=31,656+j23,005(MVA)- Tn tht cng sut trn tng tr ng dy : =.ZN-6 = .(7,48+9,73 ) =1,058 + j2,545(MVA). - Cng sut trc tng tr dy dn : =(31,656+j23,832)+( 1,058 +j2,545)=32,714+26,377(MVA).- Cng sut phn khng do dung dn u ng dy sinh rajQcc = jUN2.N-6=j.1212.1,39.10-4 = j1,015( MVAr)

- Cng sut u ngun

N-6 = S - jQcc =(32,714+26,377)- j1,015= 32.714+j24.522 (MVA).-Tn tht in p trn ng dy N-1

UN-6 = = =6,507(kV)

- in p ti nt 1U1 = UN - UN-1 = 121-3,994 =114,493 (kV)- Tn tht in p trn MBA

UB6 = =

EMBED Equation.3 =3,77 (kV)\ in p nt quy i v pha cao p

U2 = U6- UB6 = 116,619- 5,020 = 110,723 (kV)

in p thc nt 2

U2 == U2 .= 111,599. =21,182 (kV)

- Tn tht in nng trn ng dy:

(AN-6 = (PN-6.( = 31,45.3411.10-3 = 107,276 (MWh)

- Tn tht in nng trn trm bin p:

(AB1=(P0.t+=(42.8670+175.3411). 10-3 =961,065(MWh)

- Tng tn tht in nng:

(AN-6 = (AN-6 + (Ab6 = 107,276 + 961,065= 1068,341 (MWh)

Ta c bng thng s ng dyPh til(km)Pmax(MW)Qmax(MVAr)ro

()xo

()

bo106(S)R()X()B/2106(S)

145,3535,722,260,330,4292,657,489,73120,18

279,3225,515,90,450,442,5817,8517,45409,29

34436,5522,790,330,4292,657,269,44233,20

446,6741,6525,970,270,4232,696,309,87251,08

545,3539,124,380,270,4232,696,129,59243,98

649,1931,4519,610,170,4092,828,3620,1269,36

Thng s my bin p c ly bng muc 3.1.2 phn chn my bin p.Bng tnh ton in p cc nt (kV) v tn tht in p

Ph tiUNUiUBU'2U2

14,381116,6195,020111,59921,349

26,076114,9244,626110,29821,101

34,246116,7545,148111,60621,351

44,611116,3894,648111,74121,376

54,165116,8354,317112,51721,525

66,507114,4933,770110,72321,182

Bng tnh ton ch xc lp

Ph ti123456

S''B35,7+j22,2625,5+j15,936,55+j22,7941,65+j25,9739,1+j24,3831,45+j19,61

SBi0,137+j3,1740,095+j2,0730,144+j3,3270,144+j3,4560,127+j3,0460,164+j3,941

S'Bi35,837+j25,43425,595+j17,97336,694+j26,11741,794+j29,42639,227+j27,42631,614+j23,551

S0i

0,07+j0,480,058+j0,40,07+j0,480,084+j0,560,084+j0,560,042+j0,28

SBi

35,907+j25,92425,653+j18,37336,764+j26,59741,878+j29,98639,311+j27,98631,656+j23,831

jQ''i

j1,454j4,952j2,822j3,038j2,952j0,83

S''Ni35,907+j24,4625,653+j13,4236,764+j23,77541,878+j26,94839,311+j25,0331,656+j24,034

SNi

1,167+j1,5171,236+j1,2091,15+j1,4951,291+j2,0231,099+j1,7221,058+j2,545

S'Ni

37,074+j25,97726,889+j14,62937,914+j25,2743,169+j28,97140,41+j26,75532,714+j24,522

jQ'ij1,76j5,992j3,414j3,676j3,572j1,015

SNi37,074+j24,21826,889+j8,63737,914+j21,85643,169+j25,29540,41+j23,18332,714+j23,507

Ph tiSSmmax(PiSmB(PN

(P0(AB(Add(A

MBA(MVA)(MV)(MVA)(kW)(kW)(MWh)

(MWh)

(MWh)

12421,094232145351039,2093732,3164771,525

22301,33222512029802,7904544,1345346,925

32431,113232145351059,7363797,1254856,861

42491,218540175421183,7204156,3045340,024

52460,429940175421130,5571466,3892596,946

61370,94914017542878,6643237,3804116,044

Tng6,1376094,67620933,64827028,324

Bng tnh ton tn tht in nng

4.2 Ch ph ti cc tiu.

Ch ph ti cc tiu tnh tng t nh ch ph ti cc i

vn hnh kinh t cc TBA, ti cc trm gim p c 2 MBA vn hnh song song ,trong ch cc tiu ta c th ct bt 1 MBA nu tha mn iu kin :

S < Sgh = Sm .

Vi Sgh c tnh phn 3.2 ,bng tnh ton sau:

Ph ti SMin (MVA)Sgh (MVA)Nhn xtMBA

12122,234Ct 1 MBA1 32000/110

22017,381Khng ct225000/110

33022,234Khng ct232000/110

42427,713Ct 1 MBA140000/110

52827,713Khng ct2 40000/110

62227,713Khng ct1 40000/110

Theo bng tnh ton trn ta thy ph ti 1 v 4 ct 1 MBA, cn li khng ct MBAKhi tnh ton ch xc lp ta ly: UN= 105%. 110 = 115,5(kV).Bng tnh ton ch xc lpph ti123456

S''Bi

17,85+j11,1325,5+j15,936,55+j22,7920,4+j12,7223,8+j14,8418,7+j11,66

SBi0,068+j1,5870,042+j0,9210,07+j1,6190,069+j1,6580,047+j1,1280,058+j1,393

S'Bi

17,918+j12,71717,042+j11,52125,570+j17,51920,469+j14,37823,847+j15,96818,758+j13,053

Soi

0,035+j0,240,058+j0,40,07+j0,480,042+j0,280,084+j0,560,042+j0,28

SBi

17,953+j12,95717,1+j11,92125,64+j17,99920,511+j14,65823,931+j16,52818,8+j13,333

jQ''

j1,454j4,952j2,822j3,038j2,952j0,83

S''Ni

17,953+j11,50317,1+j6,96925,64+j15,17820,511+j11,6223,931+j13,57618,8+j12,494

SNi

0,281+j0,3660,503+j0,4920,533+j0,6920,289+j0,4530,383+j0,60,352+j0,847

S'Ni

18,235+j11,86817,603+j7,46126,173+j15,8720,8+j12,07324,314+j14,17619,152+j13,341

jQ'i

j1,76j5,992j3,414j3,676j3,572j1,015

Sni

18,235+j10,10917,6+j1,46826,173+j12,45610,8+j8,39724,314+j10,60419,152+j12,326

Bng tnh ton in p cc nt v tn tht in p

Ph ti UN

(kV)Ui

(kV)UB

(kV)U'2

(kV)U2

(kV)

12,181113,3195,166108,15320,690

23,847111,6533,060108,59320,774

32,942112,5583,590108,96820,846

42,166113,3344,665108,66820,789

52,466113,0342,605110,42921,126

63,711111,7894,296107,49320,564

CHNG V : TNH TON IU CHNH IN P

*********Cc ph ti ca mng in thit k l cc h tiu th loi I (ph ti 1,2,3,4,5), h ph ti loi III (ph ti 6).C yu cu iu chnh in p thng (ph ti 1,6)v khc thng (ph ti 2,3,4,5). iu chnh in p trong HT ta c th c nhiu bin php. i vi MBA c th ca bng cch thay i u phn p ca MBA nh thay i t s bin i in p,thay i thng s ng dy,thay i dng cng sut phn khng ph ti trong mng inCc ph ti c yu cu iu chnh in p khc thng , ta s dng MBA c b iu chnh di ti v tin hnh chn u phn p cho cc ph ti vi phm vi iu chnh :

Upatc = 115 9.1,78%.115.

Cc ph ti c yu cu iu chnh in p thng ta s dng MBA c u phn p c nh vi phm vi iu chnh l:

Upatc= 115 2.2,5%.115.

Yu cu iu chnh cht lng in p bao gm :

+ Yu cu iu chnh in p khc thng, lch in p cho php Trong ch ph ti cc tiu :dU1% = 0 %

Trong ch ph ti cc i : dU2% = +5 %

+ Yu cu iu chnh in p thng

Ch ph ti cc tiu :dU1% ( +7.5%

Ch ph ti cc i:dU2% +2.5%

Quy c:

K hiu 1 dng cho ch ph ti min.

K hiu 2 dng cho ch ph ti max

Phng php chn nh sau:

in p yu cu trn thanh ci h p ca trm c xc nh theo cng thc

Uyc = UHm + dU%.UHm

Trong UHm l in p nh mc ca mng in h p

+ Vi h iu chnh in p khc thng: i vi mng in ny UHm = 22 kV. V vy in p yu cu trn thanh ci h p ca trm khi ph ti cc tiu ,cc i l:Uyc1 = UHm + dU1%. UHm = 22 +0 %.22 = 22 (kV).Uyc2 = UHm + dU1%. UHm = 22 +5 %.22 = 23,1 (kV).

+ Vi h iu chnh in p thng:

Uyc1 = UHm + du1%. UHm = 22 +7.5 %.22 = 23,65(kV).

Uyc2 = UHm + du1%. UHm = 22 +2.5 %.22 = 22,55(kV). T s bin i in p ca MBA k ==

Vi Upa gi tr in p tng ng vi u phn p c chn

Ukt gi tr in p khng ti pha h p. Ukt =1,1.UHm =1,1.22= 24,2 (kV) gi tr in p trn thanh ci h p quy i v pha cao p

UH = k UH =(UC - UB).

+ MBA c b iu chnh in p di ti(Vi h iu chnh in p khc thng).

mi ch ph ti c mt u phn p tng ng

Upa1=(UC1 - UB1).

Upa2 =(UC2 - UB2).

in p ca u iu chnh tiu chun l :

Upatc = 115 9.1,78%.115.Upa1 chn Upatc1Upa2 chn Upatc2Tnh li gi tr in p thc trn thanh ci h p ca MBA

UH1 =(UC1 - UB1).

UH2 =(UC2 - UB2).

Kim tra iu kin :

dU1%= .100% = 0%

dU2%= .100% = 5%

+ MBA c u phn p c nh (dng cho yu cu iu chnh in p thng).

c hai ch ph ti min v ph ti max ch dng chung mt u phn p tiu chun :

Upatb = eq \s\don1(\f(1,2)) (U1pa+U2 pa)

(chn u phn p tiu chun gn nht vi gi tri Upatc) in p ca u iu chnh tiu chun l :

Tnh li gi tr in p thc trn thanh ci h p ca MBA

UH1 =(UC1 - UB1).

UH2 =(UC2 - UB2).

Kim tra iu kin:

dU1%= .100% 7,5%

dU2%= .100% 2,5%.Bng s liu in p trn thanh ci h p quy i v pha cao pTrm bin p123456

U2 max (kV)111.599110.298111.606111.741112.517110.723

U2 min (kV)108.153108.593108.968108.668110.429107.493

Bng s liu cc u phn p tiu chun i vi MBA c yu cu ca khc thngNc-9-8-7-6-5-4-3-2-10

Upatc (kV)96,57798,624100,671102,718104,765106,812108,859110,906112,953115

Nc0123456789

Upatc (kV)115117,047119,094121,141123,188125,235127,282129,329131,376133,423

Bng s liu cc u phn p tiu chun i vi MBA yu cu ca thngNc-2-1012

Upatc (kV)109,25112,125115117,875120,75

5.1 Chn u phn p cho MBA trm 1.

in p trn thanh ci h p quy i v pha cao p

U= 108,153kV

U= 111,599 kVy l h loi I, yu cu iu chnh in p thng nn ta c cc

gi tr in p yu cu trn thanh ci ca TBA :Uyc1 = Um + du1%.Um = 22 +7.5 %.22 = 23,65(kV).

Uyc2 = Um + du1%.Um = 22 +2.5 %.22 = 22,55(kV).

Tnh u iu chnh trong MBA khi ph ti cc tiu v cc i:

Vi Ukt = 24,2(kV) Upa1 = U. = 108,153. = 110,668 (kV)

Upa2 = U. = 111,599. = 119,765 (kV) c hai ch ph ti min v ph ti max ch dng chung mt u phn p

tiu chun : Upatb = eq \s\don1(\f(1,2)) (U1pa+U2 pa) = eq \s\don1(\f(1,2)) (110,668+119,765) =115,217 (kV)Da vo bng ta chn Upatc =115kV ng vi n=0

Tnh li gi tr in p thc trn thanh ci h p ca MBA :

UH1 =(UC1 - UB1). = 108,153.= 22,759 (kV)UH2 =(UC2 - UB2). =111,599.=23,484 (kV)

Kim tra iu kin:

dU1%= .100% = 3,45% 7,5%

dU2%= .100% = 6,745% 2,5% (tha mn iu kin)5.2 Chn u phn p cho MBA trm 2.

in p trn thanh ci h p quy i v pha cao p

U = 108,593 (kV)

U= 110,298 (kV)y l h loi I, yu cu iu chnh in p khc thng nn ta c cc

gi tr in p yu cu trn thanh ci ca TBA :Uyc1 = UHm + dU1%. UHm = 22 +0 %.22 = 22 (kV)

Uyc2 = UHm + dU1%. UHm = 22 +5 %.22 = 23,1 (kV)

Tnh u iu chnh trong MBA khi ph ti cc tiu v cc i:

Upa1 = U. =108,593. = 119,452(kV)

Upatc1 =119,094 ng vi n=2Upa2 = U. =110,298. = 115,55(kV)

Upatc2=115 ng vi n =0

Tnh li gi tr in p thc trn thanh ci h p ca MBA :

UH1 =(UC1 - UB1). = 108,593 .= 22,066 (kV)

UH2 =(UC2 - UB2). =110,298.=23,211(kV)

Kim tra iu kin:

dU1%= .100% = 0%

dU2%= .100% = 5,5% (tha mn iu kin)5.3 Cc MBA ca cc trm cn li

i vi MBA ca trm 6 chn tng t nh trm 1, MBA trm 3,4,5 chn tng t nh trm 2, ta c bng thng s chnTrm bin p

Nc chn

Ch

MinCh

Max

100

220

321

421

531

600

CHNG VI: B CNG SUT PHN KHNG TRONG LI IN.*********

Gim tn tht cng sut v in nng trong cc mng in l mt trong nhng bin php quan trng tit kim nhin liu v tng ngun in cho ph ti. Mt trong nhng bin php thng c p dng gim tn tht cng sut v in nng trong h thng in l b cng sut phn khng trong li in .

Phng php b cng sut phn khng trong li in :

Da vo hm chi ph tnh ton ti u ha dung lng thit b b bao gm:

Vn u t cho thit b b. Tn tht in nng do thit b b gy ra.

Tn tht in nng trn li in sau khi t thit b b.

Xt cho mt ph ti ta c hm chi ph tnh ton l :

Z = Z1 + Z2 + Z3()Z1 :l vn u t v chi ph lp t thit b b: Z1 = k0.Qb()

k0 :sut u t cho thit b b (/ kVAr) ,k0= 150 106 / MVArQb:tng dung lng bZ2 :chi ph tn tht in nng do thit b b gy ra : Z2 = (P0. Qb.C.t ()(P0 :tn tht cng sut tc dng ca thit b b ,(kW/kVAr) (P0=0,005 MW/MVArC :gi tin 1 n v tn tht in nngt :thi gian vn hnh thit b b, t= 8760 hZ3 : tn tht in nng trong li in sau khi lp t thit b b

Z3 =(A.C = (Pmax ..C

Vi

(MW)

Trong

C :gi tin 1 n v tn tht in nng, C = 500.103/1MWh.

:thi gian tn tht cng sut ln nht, = 3411 h

xc nh dung lng b kinh t ca cc h tiu th,chng ta o hm hm ch ph theo cng thc :

Zmin

EMBED Equation.3

Trong qu trnh tnh ton b phn khng chng ta phi gi thit rng:

- in p ti cc nt trong mng in bng in p danh nh ca mng in .

- Khng xt nh hng ca cc thit b b n ch in p.

- Co ly c nh.

- gi ca cc thit b b c ly t l thun vi cng sut ca chng.

Tnh ton b cho 1 ph ti in hnh theo hm chi ph tnh ton (Z):

a - on ng dy N-1.

* S thay th:

0 1

Q1- Qb

Rd1

Rb1 Qb1

Vi Rd1=7,48 ().

Rb1=1,87 ().Hm chi ph tnh ton hng nm:

Z = (ko+ (P0 .C.t )Qb1+

Ta c : Zmin

EMBED Equation.3

Qb= Q1- .( ko+ (P0 .C.t)

= 22,26 - .(150.106+ 0,005 .500.103 .8760)

=-42,958 (MVAr).Vy Qb=0 khng phi b.Cc ph ti cn li tnh tng t, ta c bng tng kt sauon ng dyRdi()Rb1()Qi(MVAr)Qb

(MVAr)nhn xt

N-17,481,8722,26-42,958khng phi b

N-217,852,5415,9-14,006khng phi b

N-37,261,8722,79-44,000khng phi b

N-46,31,4425,97-52,814khng phi b

N-56,121,4424,38-56,280khng phi b

N-68,361,4419,61-42,613khng phi b

Theo bng s liu tnh ton ta thy,khng cn b phn khng i vi tt c cc h tiu th.CHNG VII : TNH TON GI THNH TI IN*********

Gi thnh truyn ti in ca li in c xc nh theo cng thc

(/kWh)

Trong :

Y : chi ph vn hnh hng nm trong mng in () Att : tng in nng m cc ph ti in nhn c, (MWh) .1. Tnh tng in nng ph ti nhn c Att c tnh theo ch ph ti cc i vi Tmax = 5000h.

Ta c : Att = P(i.Tmax =209,95.5000 = 1049,75.103 (MWh) .2. Chi ph vn hnh hng nm Y .

Y = avhd.kd + avht.kt + ((A.C ()

Trong

avhd : h s vn hnh ng y , avhd= 0,04.avht : h s vn hnh thit b trong TBA , avht= 0,1.

kd :vn u t xy dng ng y.

kt : vn u t xy dng TBA.((A :tng tn tht in nng (bao gm tn tht in nng trn ng y v MBA) , (MWh)C : gi in 1kWh ,C = 500/1kWh.a. Vn u t xy dng ng y: kd = 139920,6 .106 ()b. Vn u t xy dng TBA :

Vi trm c 2 MBA, gi s bng 1,8 ln trm c 1 MBA2 trm c 2 MBA cng sut 40 MVA,2 trm c 2 MBA cng sut 32 MVA,1 trm c 2 MBA cng sut 25 MVA

V 1 trm c 1 my bin p cng sut 40 MVA.Bng gi MBA 110/220 (106/MBA)

Sm (MVA)162532406380

Kt(106 )130001900022000250003500042000

Ta c vn u t xy dng TBA l:

kt=1,8.(2.25000.106+2.22000.106+ 19000. 106 )+25000.106 =2,284. 1011() Tng tn tht in nng trn ng dy ( tnh chng II).(Ad=20933,07(MWh) Tng tn tht in nng trn MBA( tnh chng II).

(AB = 6094,676 (MWh)

((A =((Ad+((AB =20933,07 + 6094,676 = 27027,746 (MWh)

Tn tht in nng tnh theo % in nng ca ph ti:

(A% == =2,575%Chi ph vn hnh hng nm l:

Y = avhd.kd + avht.kt + ((A.C

= 0,04. 139920,6 .106+ 0,1. 2,284. 1011+27027,746.500.103 = 4,195. 1010 ()

* Vy gi thnh ti in : = = 39,963 (/kWh).* Gi thnh xy dng mng in cho 1 MW cng sut ph ti:

k = = = 775,235.106 /MW.Bng tng kt ch tiu kinh t- k thut ca mng inTTCc ch tiuTr sn v

1Utb6,05%

2Usc12,1%

3 di ng yL n49,19km

L kp241,69km

Tng290,88km

4Tng cng sut TBA998MVA

5Vn u tng dy1,3991011

Trm bin p2,2841011

Tng vn u t3,1951011

6Tng cng sut ph ti max209,95MW

7in nng ti hng nm1049,75103 MWh

8Tng tn tht cng sut6,1370MW

9Tng tn tht in nng27027,746MWh

10Tng tn tht in nng2,575%

11Chi ph vn hnh hng nm4,1951010

12Gi thnh ti in39,963/ kWh

13Gi thnh xy dng cho 1 MW 775,235106 MW

TI LIU THAM KHO1. Nguyn Vn m. Mng li in. Nh xut bn Khoa hc v K thut H Ni , 2001.

2. Nguyn Vn m. Mng li in.( Tnh ch xc lp ca cc mng in v h thng phc tp). Nh xut bn Khoa Hc va K thut H Ni, 2000.

3. Nguyn Vn m. Thit k cc mng v h thng in. Nh xut bn Khoa hc v K thut H Ni, 2008.MC LCLi m uChng 1. Phn tch ngun v ph tiI.S a l1

1.1. Nhng s liu ngun cung cp2

1.2. Nhng s liu ph ti2

II. Phn tch ngun v ph ti3

2.1. Ngun in3

2.2. Ph ti 4

III. Cn bng cng sut trong h thng in4

Chng 2. D kin cc phng n, tnh ton s b la chn phng n2.1. Chn in p nh mc cho li in5

2.2. D kin cc phng n ni dy6

2.3. Tnh ton chn tit din dy dn8

2.4. Tiu chun tn tht in p9

2.5. Tnh ton c th tng phng n10

2.6. Tnh ton so snh cc phng n v kinh t33

Chng 3. Tnh ton la chn my bin p, b tr kh c v thit b trn s ni in chnh

3.1. Tnh ton chn cng sut, s lng, loi my bin p37

3.1.1 Tnh ton chn cng sut nh mc, s lng my bin p cho ph ti37

3.1.2 Chn my bin p38

3.2. B tr thit b v kh c in trn s ni in chnh39

Chng 4. Tnh ton ch xc lp ca li in

4.1. Ch ph ti cc i42

4.2. Ch ph ti cc tiu50

Chng 5. Tnh ton iu chnh in p

5.1. Chn u phn p cho my bin p trm 156

5.2. Chn u phn p cho my bin p trm 257

5.3. Chn u phn p cho my bin p trm cn li58

Chng 6. B cng sut phn khng trong li in

Chng 7. Tnh ton gi thnh ti in

Ti liu tham kho

65

Mc lc

66C1

-jQ

S'

N-1

S

N

2

1

N

45,35 km

2TPD-32000/110

2xAC-95

N-1

Z

N-1

S''

N-1

-jQ

C1

S

B1

S

B1

S

01

Z

B

S

1

1

SB1 22

S

B6

S

B6

S

ZN-6

C6

N

1

C6

-jQ

N-6

S''

N-1

S'

-jQ

N-6

S

06

Z

B-6

66

SB6 22

65

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