A ~~H.St""d ..Pro 1/8.0, FKAAS(Io)
STAAD-Pro is a comprehensive structural software that addresses all aspects ofstructural engineering especially for model development, analysis, design,visualization, verification and etc.
STAAD.Pro includes several new exciting features including integrated shear wall
and two-way slab design, a full backup manager, physical members and momentconnections for steel design and the ability to write macros inside of STAAD forfurther customization.
STAAD.Pro. is also capable to guide user through the processes of:
a. Creating an input file whether graphically or through a text editorb. Running STAAD.Pro to perform analysis and designc. Visualization and verification of the model graphically and numericallyd. Printing the output result as desired
Therefore, the following contents will be covered in this module by using STAAS.Prosoftware:
a. Two dimensional structure analysisb. Three dimensional structure analysisc. Structural analysis for plate member
EXERCISE TOPIC PAGE
Exercise 1:0 Simply Supported Beam 3Exercise 2.0 Frame and Truss Structures 6
Assignments 9Exercise 3.0 Truss 11Exercise 4.0 Rigid Frame 16
Assignments 20Exercise 5.0 Space Frame 22
Assignments 25Exercise 6.0 Slab 32Exercise 7.0 Retaining Wall 35
Assignments 39EXTRA Simply Supported Beam Design 40
1 Prepared by: Ahmad Fahmy Kotnarudin, January 20101st Edition r" Amendment
\
STAADPRO MAIN WINDOW, STMilJ'lo-Blank , - Dl x
1\0 Modeling u;
"- ""-.led""""@X-Y OX-X
eX-Z @y-y -0 -
OY-Z OZ'lGridQ;gin.,)
X
m 0 0 0-ldI: Rqt m 9u:w'
X ii-~ io-~ ,-- .----Y 051 1051-'- -0 -
""'"C1loa1 Coonhft
rJR.tComk Cj.•••"" kflwb.1&-d~) fuQ.
X ~ 151 'Iiiiiil!dJ[LJy!iat "51~[k)
TWO methods in modelling, analysis and design that can be used in STAAD PRO are:a. Graphic Method using available icons or functions from StaadPro interfaceb. Text Method writing commands in Staad Editor
FIVE main steps used in modelling work of a structure by using STAAD PRO program.
1. Modeling:To study the given structure that is going to be analyzedTo decide the coordinates, node numbers, connection between nodes and types of support.
2. Assigning the load:To assign loading either static or dynamic on desired elements or nodes on the structure
3. Properties:To assign material properties such as concrete, steel, aluminium etc.To assign others undefined material properties by its modulus of elasticity, Poison's ratio,density, dimension etc.
4. Analysis and design:To run the program based on the input data used in step (a), (b) and (c)To check/verify the input data either correct or not.
S. Result:To view/collect the outputs after analysis/design by running the model
2 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
St""d·Pro 118.0,
WEEK 1 (PLANE STRUCTUREl
EXERCISE1 dtllMode of AnalysisFile Name
: Plane: Exe 1 CONCRETE
f5.0kNTml·--··· . r·-········r··--····-··T-·····--T·-·-·-··r···--·····T--··· - ...-_.:..... _- ·-T--·....-.-r.--.-.-r.------
+ l ~ T ¥ * t W * 1~ 1-10m
OBJECTIVES:At the end of this lesson student should able to:
a. Create and apply nodes, members, supports, properties and loading using graphical methodcorrectly
b. Verify the values of reaction, maximum shear force and bending moment with fundamentalknowledge of static
c. Get familiar with the icons that always been used during modeling or analyzing works
GENERAL PROCEDURE:
1. Create folder and name it2. File -> Mode of analysis New Project .
a. Write file nameb. Allocate the created folderc. Select the metric unit
3. Create member by using: IIII' Ia. Snap/Beam icon I ~ap Node/Beam~
b. Provided table in creating node by filling the coordinates in x, y and t, while connectingtwo nodes in creating a member
->
4. Assign the property, loading and support by using General button on the left side of theStaadPro's window• General -> Property -> Define -> Rectangular: put beam size -> Assign to Selected Beam ->
Assign• General -> Support -> Create: choose suitable supports -> Assign to Selected Nodes -> Assign• General -> load -> Add load Cases -> New: go to load items and choose Member load ->
Assign to Selected Beam -> Assign
'5. Command -> Analyze-> Perform the Analysis the followed by16-.~-.m-.~-.'J-....-_ c-·.~-.!"-ma-.n-ds-A-n-alyz-...-e.l Post Analysis Print function and activate;
a. Support reactions functionb. Member forces functionc. Joint displacements function, under
6. View Outputs ~ in terms of data and graphical diagrams of shear force, bending moment
and displacement
b~ry Commands Analyze I
3 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
SAMPLES OF GRAPHICAL OUTPUT:
.000 kN
125.000 kN
~-'~~~J ~;±Nmr=rJ------1--------lLoad t : Bendinq Z
~
~-~---'----'.~~-------~--__..... . .__. . .....__...b.~:_~~_~~...._.._....-.._...__.~---..---..--..---.--··---··--,..·-·-_1_.,
~~i11iq--..L __ ..L__ L__ L__ .L..pH"REE!::::=t==:!:===±::::==b==h __ L_-.f.6.= 25.000 kN
= FREEX=FREE. = FREEl = FREE Postprocessing
CD C"D0 CDZ e
CD<b . C.t
litii.
Elit
m £50) nID
•......•
C0
15E~~~
'"t0CLti.II
y
\\\
4 Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, r" Amendment
St""d ..·..--
EXERCISE 2 d(jjLoading = O.75kN/m
= O.25kN/m= 10kN (at each frame's joints) and 20
joints)= 10kN
: a. Top chordb. Bottom chordc. Vertical load
Mode of AnalysisFile Name
d. Lateral load: Plate: Exe 2
. Top chord and verticalmembers of truss Section Matefia!
CH102X51UAJOX30X4UB178X102X19UC203X203X52
STEELSTEELSTEELSTEEL
Diagonal members of truss
IRoof beam
10kN
10kN!
10kN
0.25 kN/min global y /
-1.50m-·---3.00m
/release release
uc ucuc
6.00m
6.00m
OBJECTIVES:At the end of this lesson student should able to:
a. Apply end condition by using release functionb. Separate two analysis between frame and truss even in plate mode analysisc. Differentiate the output in terms of bending moment showed at truss member and frame
member
6 Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, r" Amendment
GENERALPROCEDURE:
1. Create folder and name it2. File -> Mode of analysis New Project
a. Write file nameb. Allocate the created folderc. Select the metric unit
3.. Create nodes by using Snap/Beam icon and use Insert Node ~ icon to split the member4. Use Specification icon to assign for truss member and end condition
->
I~ I·-> Beam -> Release: choose directions -> Add -> Assign to Selected Beam -> Assign
5. Assign the property, loading and support by using General button on the left side of theStaadPro's window
7. Command -> Perform the Analysis the followed byPost Analysis Print function and activate;d. Support reactions functione. Member forces functionf. Joint displacements function, under
Analyze->
6. View Outputs in terms of data and graphical diagrams of bending moment and displacement
SAMPLESOF GRAPHICAL OUTPUT:
s:t. bail 1 ~m'S!pl~~l1m~':!
~Load 1: BtHu!in!}1.
Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
7
St""d·Pro 1/8.0,
FEATURES EXPLORATION EXERCISES: ~
FILENAMETYPE OF MATERIALBEAM SIZE
: Explore 1
: Concrete
: 250 mm x 450 mm
~10.0kNI
t
(Pinned)
9
3m 3 3m(Roller)
HO.8U'
SHEAR FORCE DIAGRAM
Fy(kll) Fy(kll)
I t '1 ti I2 2
-5
BENDING MOMENT DIAGRAM
MZ(kllm) Im{kllrn)
w If10 - 10
~~:Prepared by: Ahmad Fahmy Kamarudin, January 2010
i" Edition, r" Amendment
STRUCTURE ElEMENT : Explore 2TYPE OF MATERIAL : ConcreteSIZE : 250 mm x 450 km
'-30.0 kN
c2D.Dk/I
"20'~ ~.• j .11~, , r , 20 n: f
(Fixed)
10
~ l IJ II ~
10 In
(Roller)d'i
(Roller)
1001 20 m
15.3 20.0
0.7
~ib
~
[
14.713.3
SHEAR FORCE DIAGRAM ( kN )200
57.8
31.1
:vV
/16.1
94.8
BENDING MOMENT DIAGRAM ( kNm )
Prepared by: Ahmad Fahmy Kamarudin, January 2010t" Edition, 2nd Amendment
WEEK 2 (TRUSS AND PLANE STRUCTURESl
EXERCISE 3 ...d~
Truss is used to support loading from roof and it is chosen based on the basis of the span, the slopeand the roof material.
'. 'r"D _ ....
Analysis of TrussesThe analysis of trusses is usually based on thefollowing simplifying assumptions:a. The centroidal axis of each member coincides
with the line connecting the centers of theadjacent members and the members only carryaxial force.
b. All members are connected only at their ends byfrictionless hinges in plane trusses.
c. All loads and support reactions are applied only atthe joints.
Pratt(o)
11
COmp(lUlldIm8~
c
sa¥tiOOlb(h)
bowstring(i)
three-hinged arch(ji
Prepared by: Ahmad Fahmy Kamarudin, January 2010s" Edition, 2nd Amendment
Staad·Prc; 118110,
EXERCISE4
: a. Top chord = 12.5 kNb. Lateral load = 5.0 kN
: Truss: Exe 3
Loading
Mode of analysisFile name-
STEELOBJECTIVE: STEEL
At the end of this lesson student should able to:a. Get familiar with Staad Editor command in modeling and analyzing the truss structure
}
f12.5 kN
~12.5kN
LOAD 1 POINT LOADJOINT LOAD \J1 TO WFY-12.5\ 1 FX 5
~ \ J
$TAAD EDITOR COMMANDS Command forassigning the loads
DEFINE MATERIAL STARTISOTROPIC STEELE 2.Q5e+008~Po/ISSON 0.3DENSITY 76.8195~LPHA 1.2e-005QAMF>0.03END DEFINE MATERIALMEMBER PROPERTYBRITISH1TO 22 TABLE ST ~H125X65X1523 TO 29 TABLE ST UA25X25X4
'='CONSTANTSMATERIAL STEELALL
STAAD TRUSSSTARTJOB INFORMATIONENGINEERDATE 05-Jul-09END JOB INFORMATIONINPUT WIDTf\79 r
(6VL 0 Command for creating nodes
JOJ~I~apqRl?t1 Nf-TES -=--=--=--=--=--=----=--------=--- -,------'¥ 0408 140.6 ~~ Node increment I
/ ~ d d d"f614 0 6lf I .
r Command for creating membersMEMBER INCIDENCES.-t~ oDIAGONAL AND HORIZONTAL MEMBERS
~_i~~~1 - Incremental of member's label
\r 89101411H\ tJ III !'vi
Command for assigning theproperties
* VERTICAL MEMBER1519221rn--JJ,t-l> II'\'""~-~
(*) Used for statement (if
necessary) membersPERFORM ANALYSISPRINT MEMBER FORCESALLPRINT JOINT DISPLACEMENTS ALLPRINT SUPPORT REACTION ALL
* BRACINGfV1 ~,.) h\~239229r (~ 11 t81 2 2
Command for assigning the support
FINISH
SUPPORT Roller: it restraints9 PINNED \ /' in y- direction
" IItFIXED BUr FX FZ MX MY MZ It'
12 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
Stttttd·Pro 1/8.0,
GENERAL PROCEDURE:
1. Create folder and name it2. File -> Mode of analysis -> New Project
a. Write file nameb. Allocate the created folderc. Select the metric unit
3. Each line of the command is written in Staad Editor for modeling and analyzing the structure.4. Finally run the model by using Analyze -> Run Analysis function5. View Outputs in terms of reactions data, internal forces and graphical diagrams of
displacement and compression-tension members
SAMPLES OF GRAPHICAL OUTPUT:
f12.5 k~l,
ilJ,
i[iliit~
f12.5 k~l
f12.5kN
~12.5 kll
~12.5 kN
6
/81 9
~12.5kN
"2.5 kNi
1fI2.5kN
'12.5 k~1
~12.5kN
I/ .(\s.544mm tf~ i/ '" V I
" "~" ax: 17.336 mm -, __ !
/\ ~ ••• ~~X:_'~~l," 7.·;·7F <. ~ ~.-lIIaX:2.383mm, , ,,/ /', »>: .-
~ »< / ...... --- -' '--,/ I /-,/ '.." " .J J" •• ~
~ax:15.553 mm' Ua,x:/17..286 mm :,tax: 16.056 mm _ .. ~ .~~ 11.533 mm
x: 12.830mm '12.5 kN
Lead 1 : [}j~pb.{.'ernenIDisplacement - mm
13 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
,,
Ii
51ikfi""'
~12.5 kN
;12.5kN
L12.5 kN
'12.5 ktl
~12.5 ktl
5
14
l.oad Case: IJ~rn.JN1J9N-!"h, " ..., ,~
Deflection Beam Forces Diagram
@Hatch t)R1IIf) Outline
loads~ !.Dads: Dired 11
Moment -.1~Show!.Dad /vrow
Mode ShapeMode Shape:
<BNone
6 Deflection •
@ Section Displacement
IUMode Shape aForces
r!jAxiai
tf.) Diagram
from To
i[) Intensity
Mrnnun: ~_~:~:]
MalOmum: :831817I
No of values: i16 11:9
alEJl!endingyya EJ8enClng22
aCaTaIEl Shearyy
IElShearzz
ICITorsioniDStress
f12.5 kN
Prepared by: Ahmad Fahmy Kamarudin, January 2010t" Edition, z" Amendment
bz__ --------~-----------------
Sttttld·P,o 118.
EXERCISE 4 dOLRigid frame structure consists of column and girder jointed by moment-resistant connection. Open
rectangular arrangement, which allows freedom of planning and easy fitting of doors and windows.
Normally this type of structure is economic up to 20 - 25 stories. It suits for RC building because of
inherent rigidity of RC joint
Loading : a. Top chord
b. Lateral load
: Plane
: Exe 4Mode of Analysis
File Name
STAAD EDITOR
STAAD PLANESTARTJOB INFORMATIONENGINEER DATE 05-Jul-09END JOB INFORMATIONINPUT WIDTH 79
X Y ZR 10 0 3.5 0R = repeat command10 = no. of repetition in x, y or z
direction
R-9 4 4
JOINT COORDINATES R = repeat commandf.,. @O 02~J 0 Q..tJ 9 = no. of repetition in single direction
R 10~) 1) ._ excluding existing member/ (4r member differentiation
MEMBER INCIDENCES (column 5 - column 1).- -- - - - /~ /:'""' ~= node of differentiation
*Col mn ~ \ ( . (node 5 - node 1)-\ ~~~, if
'1 R 9 4'\'='
I Incremental of member's label I*Bsam~ L- ~
~ ~ 5 ~@1(j)
R 9~ i/r-- --,
\., ~ I' Incremental of members line ISUPPORTS1 T04 FIXED
16
LOAD 1 LOADTYPE POINT LOADJOINT LOAD59 13 172125 29 33 37 FX 104-, fX C;;DEFINE MATERIAL STARTISOTROPIC CONCRETEE 2.17185e+007POISSON 0.17DENSITY 23.5616ALPHA 1e-005DAMP 0.05END DEFINE MATERIALMEMBER PROPERTY1 TO 40 PRISYD 0.45---------- -41 TO 70 RRISYD 0.4 ZD 0.25coNSTANTS-MATERIAL CONCRETE ALL
PERFORM ANALYSISPRINT MEMBER FORCESALLPRINT JOINT DISPLACEMENTS ALLPRINT SUPPORT REACTION ALL
FINISH
Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
St""d·P,o V8110,
Each BayStorey heightloading( X - Direction}
=6m=3.5m= 10 kN from (1st to 9th
floor}15 kN at uo'" floor}, __
i
I
III
3
IIf
0----6.OOm ":--6.00 ni c:----, .. .
I6.00mI
K3 [3 EJ3tl'Em
5.00m
68 69 70~7 ~8 9
65 , 66 67~3 ~4 5
62 63 64~9 [10 1 ~.
59 60 61!J5 6 7 ill
56 57 58)1 2 III b.
53 54 557 8 ~9 1;>1
50 51 523 4 ~5
47 48 499 r 0 ~1./ -144 45 46
I, \ , ~'i ,41 ,42 43,. .,. ~ ,
~ill !Zill [<Jill [<Jill
o
6
2
8
o
Determine:
6
2
a. Reactionsb. Displacement mode and maximum
displacement value
Beam Numbers
17 Prepared by: Ahmad Fahmy Kamorudin, January 2010i" Edition 2nd Amendment
OBJECTIVES:
At the end of this lesson student should able to:a. Get familiar with Staad Editor command in
modeling and analyzing the plane structure
. \
1 2 ~3/"
37 ps 139-
33 34 [35
9 30 ~1-
5 6 7.-
1 22 3 ~,
, 7 8 9 Cil
3 4 15
fJ 0 11
\P' 'p 8'
~ )\
<:(
flila l'l~ l'l'~ Jil1ll
4
o
6
2
8
4
o
6
2
Node Numbers
Stattd·Pro 118.
SAMPLES OF GRAPHICAL OUTPUT:
Reactions:
MzkUm
"ode
Horizontal Vertical Horizontal Moment
~ ~ ~ ~ ~ktl ktJ ktl ktlm
3
1 Lateral.Loa __""",,,,,,,,,,,,~?o.,:~J..,,,,,,,,,,,,,,.~s.,~,:~l.,,_,,,_,,,,,,,_gg,i_",,,..,,,,,,,,o.,.~?~_l.1.Lateral Loa. """"",_""",~,?,?,:~j"."__."",,,,,..,,,,,,~,:~.L,,,_,,,,,,_,,,_".,o.:~.l" ",,,,,,._g.~~~,L,,,,1 Lateral Loa: .",,,,,,,,,.,,,,,,~?~:~J,,_,,.,,,,,,,,,,,,~,~,:~j,_,,,,,,,,.,,,,,,_gg,l"",_"_""g:~~~l,,,,,,..1 Leteret Loa -20,5: 85.0 ~ 0.0: 0.000 ~
56,982...- - ---.-.
63:92963.701
.... - _ __ ..56.343
2
4
Displacement Mode:
18
How to cut section as frame above?
Cut section EJ-> Select to view ->OK ->Drag and hold right button mouse on requiredframe -> after completed, release the mousebutton
,-- - - - --- - --- ---- ------ -.---- -- -- --- -- - - - - --., ,: '
,~~ ~~ ~~ ~~,'------- ------- -- ---------- - - - --------- --- - -- - --'
But, how to view the whole structure back?
Use Display Whole Structure I[;]I icon
Horizontal Vertical Horizontal
tlode LfC X V Zmm mm mm
Max X 41 1 Lateral Loa 43.019 : 0,331 : 0,000
Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, r" Amendment
Staad·P,o 1/8,,0,
MODElUNG EXERCISE: ~
FILENAME : Modelling 1
6@3=18m
5m
2.5m 2.5m
I~nII
15m10m
10m
I{
20kN joE' ---+_----""
II
I~NOTE:
II
25m + 15m _I
~~2m
~/
35m"
80m••
30m
Question:Figure shows an offshore platform whichconsist of:
a. 4 legged jacketb. Flaire boomc. Top side moduled. Conductore. Drilling Derrickf. Hell port
\\120kN ioE:---------!--~
\\
\20kN +E--------f----3>+
20kN ;.<=-I -+--_~\I \I I
20kN------l ~ l
65m
Based on the 'Text Method', write acommand, by using the Staad Editor in orderto model the structure.
The above figure is not an actual offshore platform dimensions. The dimensions are created for learning purposes
20 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition r" Amendment
Staad-Pro 1111.0, 'K•••••(!.J
TRUSS EXERCISE:
.0 kN
FILENAMETYPE OF MATERIAL
: Truss 1: Steela. Diagonal element (Pipe)b. Top chord, bottom chord and
vertical element (Tube)
c) The output result for:i) Support reactionsii) Internal forces due to the real loads
for each element. Please specifywhether the element in tension orcompression
iii) The maximum displacement inglobal y-direction
Please give comments if the result indicatesinstability. Propose solution to overcomethis problem and resubmit the result of (a),(b) and (c)
QUESTION
Perform the analysis and produce:
a) STAAD EDITOR command
b) Graphici) 3D Viewii) Deflection mode of the structureHi) Reaction at Point 18 and 34
5.0 kN.0 kN
.0 kN.0 kN
5.0 kN.0 kN
5.0 ktl '\.0 ktl
(Pinned)
.0 kN5.0 kN
5.0 kN5.0 kN 5.0 kN 5.0 ktl
5.0 kH
Warren Truss Type (Roller)
Nodes
Elements
21 Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, 2nd Amendment
.0 kN
WEEK 3 (SPACE STRUCTURE}
EXERCISE 5 -AtllMode of AnalysisFile Name
: Space: Exe 5
St""d·Pro 1/8.0,
OBJECTIVES:At the end of this lesson student should able to:a. Create a three dimensional model by
using repeat all command correctly withsame application as repeat command
b. Apply wind loading to the structurebased on the input value of designedwind pressure
MaterialCONCRETECONCRETE
Ref 1 : for columnRef 2 : for beam
3D View
22
STAAD SPACE Rectangular Medium Rise StructureSTART JOB INFORMATIONENGINEER DATEEND JOB INFORMATIONINPUT WIDTH 79
Joint Coordinatesto 0 0 412 0 0 1R300-4RAS 03.S 0
Member Incidences * Column- 1117411
R344R A41616
* Beam in X-Direction8117188311R334RA41216
SUPPORTS1 TO 16 FIXED
* Beam in Z-Direction1411721144 11R244RA41216
DEFINE MATERIAL STARTISOTROPIC CONCRETEE 2.1718Se+007POISSON 0.17DENSITY 23.5616ALPHA le-OOSDAMP O.OSEND DEFINE MATERIALMEMBER PROPERTY1 TO 80 PRIS YD 0.4S81 TO 200 PRIS YD 0.6 ZD 0.2CONSTANTSMATERIAL CONCRETE ALL
DEFINE WIND LOAD *In x-directionTYPE 1INT 1.5 HEIG 1LOAD 1 Wind LoadWIND LOAD X 1 TYPE 1
PERFORM ANALYSISPRINT MEMBER FORCESALLPRINT JOINT DISPLACEMENTS ALLPRINT SUPPORT REACTION ALL
FINISH
Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, r" Amendment
(r ~~ 4.00m ---'[il~
~ !iifiiJ ElIJl El~
12.00m
~~Iil ~i1l ~i1l
I!I4
I!
1~ a ~ra 12.00m ~ra
Plan View
"12.00m
11.50m
,4.00m-i r
I!3j!
., ;>-[,] lilm ~ ~
Front Elevation
1f(AAS
.00111
.50m
How to assign wind loading?
General -> load -> load Cases Details: writewind load -> Add -> New -> Definitions ->Wind: double click -> Intensity: write fnt(kN/m2
) = 1-5 (calculated design windpressure taken from the code) and Height(m)= 1-> load Items -> Wind load: Selectwind direction -> Add
23 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition 2nd Amendment
Stttttd ..Pro-1I8110,
WIND LOAD PRACTICE: ~
FILE NAME : Space 1TYPE OF MATERIALS
MaterialCONCRETECONCRETE
Ref 1 : for columnRef 2 : for beam
Question;1. Complete the command given and determine the:
a. Maximum reactions in x,y,z and momentb. Maximum deflection
/
Plan View
2. Attach the deflected mode image of the orthogonaltower
3D View
Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, 2nd Amendment
17.50m
~~ I1lIiJ f1D fJliJ ram
Front Elevation
25
/Sttl"d ..Pro 1/8,,0,
STAAD SPACE Orthogonal Shape MRB
START JOB INFORMATION
ENGINEER DATE
END JOB INFORMATION
INPUT WIDTH 79
JOINT COORDINATES CYLINDRICAL REVERSE
18008803159400 1640315RA5 0 3.5 0
MEMBER INCIDENCES
* External Beams
11718711825261411RA41516RAOOO
* Internal Beams
7517258211RA4 816RAOOO
* Close
115"1724 ; 116 25 32RA 4 216*R AOOO',
* Column
200 1 i7 207 11RA4 816240925 247 11RA4 816
26
SUPPORTS
1 TO 16 FIXED
DEFINE MATERIAL START
DEFINE WIND LOAD
PERFORM ANALYSIS
PRINT MEMBER FORCES ALLPRINT JOINT DISPLACEMENTS ALL
PRINT SUPPORT REACTION ALL
FINISH
Prepared by: Ahmad Fahmy Komarudin, January 201015t Edition 2nd Amendment
Sttttld ..Pro vallo,
SPACE STRUCTURE EXERQSE: ~
Question:You are required to model a twin towers building according to the following dimensions, sizes,loading, support condition and materials. The following command is given for your reference .
.-I--l-I-
11 I--I-
Yl-I--I--I--I-
(.. .. .. . -i.. ..
I Skybridge I
20m
wi:J,3@ Material: Concrete~ Column: Diameter: 750mm11w~ Beam: 400mm x 600mm3
wi:J,3@ Material: Concrete~ Column: Diameter: 1000m"....•w
i:J, Beam: 600mm x 700mm3
~Ul3@ Material: Concrete~ Column: Diameter:"5:: 1500mm3
FixedSupport
3D VIEW
Load Case 1 : Wind Load in X Direction (Assume: 1.5kN/m2)
Load Case 2 : Wind Load in Z Direction (Assume: 1.5kN/m2)
Skybridge:
Horizontal and Vertical Elements: UB 838 x 292 x 176
27
The above high-rise structure dimensions are created for learning purposes
Sub.Store
Sub._21Storey
A·A
1st 30Storey
TOWER 1 TOWER 2
Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
/
Staad ..Pro
PLAN VIEW FRONT
!
\ \,
\
-I 1st 30 Storey
~
\" , ~
"\ ---5.00m~~- -1I.00m~--5.0on1
\ . !
\ /\ I\ /
\'--- /---- ~~-
SUb. 21 Storey
III
I-t-H-t-+--H--t+--j 105~'OOnl
I-H-H--+-++++---I!
1I
Iri173.5OmII
IIi
IiIII
I!
28 Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, 2nd Amendment
\)'fH<\r
St""d ..P,o 1/8.0, 1"AAS('~)
3850m
29
B.OOm
Sub. 11 Storey
Skybridge
Front View
Top View
\/
Prepared by: Ahmad Fahmy Kamarudin, January 2010r Edition, ZWAmendment
St"ad·Pro 1/8,,0,
3D View
A - A Cut Section
Please provide the following requirements in your report:
1. Staad-Editor used
2. Elevations as following:a. Front elevation and plan view together with I" load caseb. Side elevation and plan view together with 2nd load casec. Plan view only together with combine load cased. 3D-view [line)e. 3D-view (solid)
3. Deflection modes due to:a. Load case 1b. Load case 2c. Combine load cases
4. Maximum reaction value due to (please indicates the location):a. Load case 1b. Load case 2c. Combine load cases
5. Maximum moment value due to (please indicates the location):a. Load case 1b. Load case 2c. Combine load cases
Please give comments if the result indicates instability or warning.
30 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
St""d·Pro 1/8,,0,
STAAD PLANE High Rise StructureSTART JOB INFORMATIONENGINEER DATEEND JOB INFORMATIONINPUT WIDTH 79
JOINT COORDINATES CYLINDRICAL REVERSE11500815031599001690315174002040270RA300 3.5 0
6219 108.5 0 628 9 108.5 3156294 108.5 0 632 4 108.5 270RA200 3.5 0
873 4 182 0 876 4 182 270RA1003.5 a
MEMBER INCIDENCES
* COLUMN* 1ST 30 STOREY1121811992916111717372011RA29 37 20
* 2ND 20 STOREY2000 609 621 2007 112008629617201111RAOOO
2012 621 633 2019 112020 629 641 2023 11RA191212
* 3RD 10 STOREY2252 869 873 2255 1 1RAOOO2256 873 877 2259 11RA944RAOOO
* BEAM (INSIDE)* 1ST 30 STOREY30002129300711
31
32392937; 3240 3138; 3241 33 39; 3242 3540RA29 4 20RAOOO
* OUTSIDE335921223365113366 29 30 3372 113373 37 38 3375 11RA291720RAOOO
3869 21 28; 387029 36; 3871 40 37RA29 3 20
* CLOSE3959608616RAOOO* 2ND 20 STOREY (INSIDE)4000 621 629; 4001 623 630; 4002 625 631;4003627632RA20 412
* OUTSIDE4083 621 622 4089 11RA20 712
* M-ISS42298678684230867872RAOOO
4231629630; 4232 630631; 4233 631632RA20 312RAOOO
5000621 628; 5001 632 629RA20 212
* 3RD 10 STOREY6000873874; 6001 874875; 6002 875 876RA 1034RAOOO6033876873RA1014
FINISH
Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition r" Amendment
1/(AAS
WEEK 4 (PLATE STRUCTURE}
EXERCISE6 AOLPlate PressureMode of AnalysisFile Name
OBJECTIVES:At the end of this lesson student should able to:
a. Create a mesh model of slab and beams using translational repeat icon and generate surfacemeshing icon correctly
c. Verify the result of vertical reactions obtained with fundamental knowledge of staticd. Identify the location of maximum stress concentration on the structure through stress
contours
GENERAL PROCEDURE:
1. Create folder and name it2. File -> Mode of analysis New Project
d. Write file namee. Allocate the created folderf. Select the metric unit
3. Create nodes by using Snap/Beam icon then delete a" members and remain only the nodes4. Create meshing by using Senerate Surface Meshing icon I@ I
Generate Surface Meshing: select nodes in anticlockwise direction -» choose Quadrilateralmeshing -» Divisions: example A=4, B=5, C=4, D=5 -> Apply
->
5. Assign the property, loading and support by using general button on the left side of theStaadpro's window
6. Command -> Perform the analysis by activating thea. Support reactions functionb. Element forces/stress functionc. Joint displacement function, under
Post analysis print function
-> Analyze
Command -> Post Analysis Print -> Add -> Analysis/Print (located at left window) -> select
11··· ~ PRINT ELEMENT FORCE 1-> Assign to view
7. View Outputs in terms of data and graphical diagrams of displacement and stress
32 Prepared by: Ahmad Fahmy Kamarudin, January 20101st Edition, r" Amendment
SAMPLES OF GRAPHICAL OUTPUT:
\\..,
\
33 Prepared by: Ahmad Fahmy Komarudin, January 20101st Edition, r" Amendment
EXERCISE 7 -A.ftL
Stttad·P,o V8110,
Plate PressureHydrostatic PressureMode of AnalysisFile Name
: 20 kN/m2 (acting on slab): 0 kN/m2 to 20 kN/m2 (acting on wall): Space: Exe 7
Node 1: 0.25
Node 2: 0.25
Node 3: 0.25
Node 4: 0.25
~M_1!;Q~~1;<MtiJ
,2 00.45
...CONCRETE
~ HighIgtt Assigled Gecmetry
'1.;-,. -~&It-_.-.,c-·,,---", .. I .c.".~e,." •.., ..
Ir",,-"c.-Y~-....y-"'-iM"'---"· J L~Jl;l!~ 1 ..".".;Jl';!!1!L->-",
L. tta~,,- ...~ I I,,",~.- J .:,J~T*-,,:,
1
OBJECTIVES:At the end of this lesson student should able to:
a. Create a mesh model of slab and beam using translational repeat icon and generate surfacemeshing icon correctly
b. Verify the result of vertical reaction obtained with fundamental knowledge of staticc. Identify the location of maximum stress concentration on the structure through stress
contours
35 Prepared by: Ahmad Fahmy Kamarudin, January 2010t" Edition, 2nd Amendment
GENERAL PROCEDURE:
1. Create folder and name it2. File -> Mode of analysis New Project
a. Write file nameb. Allocate the created folderc. Select the metric unit
1. Create nodes by using Snap/Beam icon then delete all members and remain only the nodes2. Create meshing by using Generate Surface Meshing icon3. Assign the property, loading and support by using General button on the left side of the
Staadpro's window4. Command ->
->
Perform the analysis by activating the ->a. Support reactions functionb. Element forces/stress functionc. Joint displacement function, under
Post Analysis Print function5. View Outputs in terms of data and graphical diagrams of displacement and stress
Analyze
SAMPLES OF GRAPHICAL OUTPUT:
MLYH/mm2"0.0&
0.06
0."
0.02
0.02
0.1}4
0.06
0.0&53 53 63 68 n 13 83 88 93 98 116 115 ". 113
1.0.kJ!ilt",·'"
[:'~I!::-)
Name: UNEI
SbossType: MLY
_Nollv: 2
In Post processing mode:
Plate -> Cut by a line: make a cross section line then ended with perpendicular line -> Stress Type:
choose and click Update ->
36 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
MY(kx:aI)kNmIm
(= -58.2·-48II.-377
.-27.5
.-17.3
.-7.0911lI3.13El13.3
11lI23_6
11lI33
.8
!!I44054.2
11164_4
m747
1184.9
.951>=105
37
1
St""d·Pro 118.0,
!
1
Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
PLATE EXERCISE: ~
: Plate 1: a. Steel water tank thickness = 8mm
b. Concrete slab thickness = 125mmc. Beam size = 200 mm x 600 mm
: Restraint in y-direction: Plate water pressure on slab = 40kN/m2
Hydrostatic pressure on tank's wall = from 0 kN/m2 (top) to 40kN/m2 (bottom)
FILE NAMETYPE OF MATERIALS
TYPE OF SUPPORT-. LOADING
39 Prepared by: Ahmad Fahmy Kamorudtn, January 2010i" Edition, 2nd Amendment
Sttt~d·P,o 1/8.0,
EXTRA NOTE (CONCRETE DESIGN}
EXERCISES ASTAGE ASimply Supported Beam Concrete AnalysisBeam Size : 200mm x 600mmPerform Analysis -> Post Analysis Print ->
a. Member Forcesb. Support Reactionc. Joint Displacement
Analyze: Run Analysis
loading assumptions
r:'.llLl load Cases Details. E:i· IIJ 1: Dead Load
i '~UNI GY -35 kN.im[:31IJ 2: Uve toed. L ..~ UNlGY-20kNl'm .
[~).IQ 3: COMBINATION LOAD CASE 3:.IQ (1.4) x Load 1
s r ; -IQ (1.6)=< Load 2I ;.ILl load Envelopes
U
IIp-
I
L(x:-d 2; Shear YForce - kU 0.0 kN
SAMPLE OF ANALYSIS FINDINGS:
,'ax: GO.O k
L,XiU :2 ~ Sending 1.Mom~nt_ kNm
4.293mm
1.<;ud ') , n;~p:l!H:ern~m!Displacement - mm
40 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
\.i'fH.ir~~ ~
S t""d..P,o 118110,- IKAAS {%Itus,.\~o}
=0.0 kN= 60.0 kN=0.0 kNX= FREEy= FREE
= FREE
STAGEBply Supported Beam Concrete Design
er running the analysis, in modeling mode go to:
ode -> Interactive Design -> Concrete Design
On the left side of RC Designer window;
1. Click Envelopes: then click New Env. button and put your reference design environment narne->OK ,
2. Click Members button -> highlight all beams and click Auto Form Member icon I~I3. Click Groups/Briefs -> click New Briefs button: write Beam and choose BS8110 code followed by
OK. Any amendment of design parameters can be done by double clicking on the created beam'sname -> Click New Design Group button but make sure the beam members still highlighted.Then choose the created beam file of Design Brief -> '
4. Click Concrete Member ->make selection on required beam that need to be designed and clickOK
The beam layout, main reinforcement, shear layout, shear reinforcement, and detailing can beeasily viewed through the icons which still in the same function of Concrete Member
SAMPLE OF DESIGN FINDINGS:
1
I
#;
l'==". =.====r==--_~ .~~J ~.
layer 1 (Tap) Layer 2 (Top) l!'1yer '1(Bot) UI),lOt 2 (Bot)
SeriaJNo. 6arOia I ": !Slartng;,am::el fndin9~istanCe I~. .
••
12 15.4-
12 4.6
i.S0Q
1.500
4.500
4.5(JO
41 Prepared by: Ahmad Fahmy Kamarudin, January 2010t" Edition, 2nd Amendment
StlAad ..Pro 118110,
'"Q)o Mem Span Type Length H()g
c: m em'"a;CI) 1.11 Beam 6.000 3.00
~CD.ceCD::ICD
!••coU
-sR~.£:m::.:
~ Distance
c mii::I 0.000--I O.SOO
-SR HOO~ffi 1.500.,.c
2.000en- ~2.SOO
fi ~ 3.000t;;CI) 3.50-0s:U>
4.0000) , 4.500c~ ~,',l5 ,
5.000}.- ,5.5011
6.000 1(e)
SpanBottom Layers Top Layers
Moment AsReq. As'Req, Bars Area Bars Area
kNm mmz mmz mmz mmz
0.000 o 0 2T4{} 2513 0 io.10.000 o 0 2T40 2513 0 Oil0.000 0 0 2T-411 2513 0
0.000 n 0 2T40 2513 2T12 226
0.000 0 0 2T40 2513 2T12 226
0.000 0 0 2T40 2513 2T12 226
0.000 0 .0' 2T40 2513 2T12 226
O.{}OO {} 0 2T40 2513 2T12 226
0.000 0 0 2T40 2513 2T12 226
O.{}OO {} 0 2T4{} 2513 2T12 226
0.000 0 0 2T4{} 2513 0
0.000 {} 0 2T-40 2513 oo.oeo 0 0 2T4{} 2513 0
l(s)
! ~I
<-jIE
c!l ~ I
·1· ·1·
I
I I R10@StxM> RIO@125mm Im '. R1O@0C>nm .'.. I I; -.
I I~ i~ S I I
8 ~ Jf-- '" mM~ " -,,-_. m:mm m • , 21" . :tliAtt~~
~ I€ FyI·N)<; ~
.00 40<1
§ 243_ --200 200-_. ~i.
I.3 1 ..]2
j 2
-200 -200w
.. -- -243
I€ --<00<
--<••
! <.lJ
r r--,!;
.J-
'===Seeton at c=J m ~
42 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, r" Amendment
~>..m..5 EE.,; :3
m en0
0.000 l(s) 243.000 2.168 146c 131•.. Ol 202.500CI) U> 0.500 1 1.875 63D m
E DCI) 1.000 1 162.000 1.500 38::ICI) :5 1.500 121.500 1.125 42a; R... ..5 2.000 81.000 0.750 42~c0 c 2.500 1 40.500 0.375 420 1ii::a:
3.000 0.000 O.ODO 42.0
tim 3.500 1 40.500 0.375 42U>m c 4.000 '1 81.000 0.750 42~ 1iip ::a:c 4.500 1 121.500 1.125 2700
S 5.000 162.000 1.500 38m R
5..500 202.500 1.875.:z:: ..5 63OJ:3 m 6.000 He) 243.000 2.168<T 146x: m1:: x:m enill
~•..CDCI).s::en
1 IJ.001 1.515 2 lO 8.0 1570) []c
2 1.515 4.404 2 10~ 12.5 157<D.D. 3 4.404 5.999 2 10 8.0 157
I 19 RlO-OJ-8D 24 R1D-03-125 H 20 RIO-O'3-BO
B1 ~O2~
~ ~ IR..j ~
±J ~ ~Ol ~
.0202
0l0i O]Ol 0]0]
A-A ]-] c-c
(after exporting the raw detailing directly to dxf file)
Details report can be obtained from the following procedure:
File -> BS8110 Report Setup: make the selection of report required -> OK -> File -> Print Preview.
43 Prepared by: Ahmad Fahmy Kamarudin, January 2010i" Edition, 2nd Amendment
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