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INSTITUTE OF TECHNOLOGY Subject – Control System Engineering (2150909) Branch – Electrical Topic – Root Locus Name Enrollment No. Abhishek Chokshi 140120109005 Himal Desai 140120109008 Harsh Dedakia 140120109012 Kaveesh Raval 140120109016 Guided By – Prof. Abhishek Ha

Root locus

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Page 1: Root locus

GANDHINAGAR INSTITUTE OF TECHNOLOGY

Subject – Control System Engineering (2150909)Branch – Electrical Topic – Root Locus Name Enrollment No. Abhishek Chokshi 140120109005 Himal Desai 140120109008Harsh Dedakia 140120109012Kaveesh Raval 140120109016

Guided By – Prof. Abhishek Harit

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CONTENT Introduction Angle and Magnitude Condition Construction of Root Locus Examples

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INTRODUCTIONWhat is Root Locus ?•Root locus is a graphical representation of the closed-loop poles as a system parameter is varied.•It can be used to describe qualitatively the performance of a system as various parameters are changed.•It gives graphic representation of a system’s transient response and also stability.•We can see the range of stability, instability, and the conditions that cause a system to break into oscillation.

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ANGLE AND MAGNITUDE CONDITION:

05 exp 9.fig

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CONSTRUCTION OF ROOT LOCUSRule 1: Symmetrical about real axisRule 2: Number of Root Locus branches =

Number of Open Loop Poles and Open Loop Zeros

Rule 3: Real axis LociA point on Real axis lies on Root Locus if the sum of poles and zeros to the Right Hand Side of that point must be odd number. Root Locus Point will move on Root Locus path.

To left of an odd

numbers

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Note:Starting and Ending point:

The root locus starts at open loop pole witk K = 0 and terminates at open loop zeros with K = ∞

Ending

Starting

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Rule 6: Break Away PointIt is a point on Root Locus where two poles meet. Once the two pole meet , they split i.e they break away from real axis.

Procedure to calculate Break Away Point:

1.Write the Characteristic Equation i.e 1 + G(S)H(S) = 0

2.Arrange Characteristic Equation in such a way that K = f(s)

3.Differentiate K w.r.t S and equate it to zero, this will give valid and invalid break away point.

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Break Away Point S = -1.45

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Rule 7: Intersection with Imaginary axisThis rule gives us point on the imaginary axis which the root locus will cut while moving to the Right half of the s plane.Intersection of Imaginary axis can be found by using Routh-Hurwitz criterion.Procedure to calculate Intersection with Imaginary axis :

1.Write the Characteristic Equation i.e 1 + G(S)H(S) = 02.Construct the Routh array3.Determine K 4.Get the Auxiliary Equation5.Compute the roots of Auxiliary Equation. These will be the

intersecting point with the imaginary axis.

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+j1.59K = 9.65

-j1.59K = 9.65

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-6 -5 -4 -3 -2 -1 0

-4

-3

-2

-1

0

1

2

3

4

Real Axis

Imag Axis

-2 + j2.45

-2 - j2.45

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MATLAB

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MATLAB

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Q- USE MATLAB TO DRAW THE ROOT LOCUS FOR THE FEEDBACK SYSTEM WHOSE OPEN LOOP TF IS A(S)=

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