теория вероятностей учебное пособие

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  • ..

    , 2006

    Copyright & A K-C

  • .

    12 .

    , , . .

    , -

    , . , .

    .

    .

    .

    1. .. . - .: , 1988.

    2. .. . - .: , 1986.

    3. .., .. . - .: ,

    1982.

    4. .. . - .: , 1987.

    5. .., .. . - .: , 1988.

    6. .., .., .. . - .: , 1980.

    7. .., .. . - .: , 1986.

    8. .., .. . .: , 1983.

    9. .., .. . . - .:

    - , 1962.

    10. .., .. . - .: , 1969.

    .

    1 .

    2 .

    3 .

    4 , .

    5 .

    6 . .

    7 .

    8 .

    9 , .

    10 , .

    11 , .

    12 , .

    .

    Copyright & A K-C

  • 1

    .

    m

    n , .. P(A)=mn . -

    .

    1.1. , 3 -1,0,1.

    . , 1, -

    ?

    :

    1.

    3 :

    1) -1

    2) 0

    3) 1

    n=3. (m=1)

    P()= mn =

    13

    1.2. .

    , .

    :

    n=18 ( ).

    m=9

    () = mn =

    918 =

    12

    1.3. , 0 1. 0 1 -

    .

    0?

    :

    : 01, 10, 11, 00.

    n=4,

    m=3

    P(A)=mn =

    34 .

    1.4. . : 6 -

    , , , 3 ?

    :

    , , , , , . N=6. -

    , 3 , 2 . , ()=16 , P(B)=

    36 =

    12 ,

    P()=26 =

    13

    Copyright & A K-C

  • 1.5. 2 , ,

    5.

    :

    - 5.

    n=36.

    4

    1 2 3 4

    1- 1 2 3 4 , .. m = 4

    2- 4 3 2 1

    P(A)=mn =

    436 =

    19 .

    1.6. 5- . : ) -

    , ( : 15451); ) ; )

    .

    :

    ) n=99999-9999=90000 ( 1 99999 1

    9999). 9 : 1, 2,,9,

    10 : 0, 1, 2,,9, , , ..

    m=9101011=900.

    ()=mn =

    90090000 =

    1100 .

    ) 9: 1, 2, 3,9, , 10: 0, 1, 2,,9;

    : 5, 0. ( 5), .. m=91010102=18000, ()=mn =

    1800090000 =

    15 .

    ) 5 5 : 1, 3, 5, 7, 9

    m=55555=3125

    P(A)=mn =

    312590000 =

    5144 .

    1.7. 10 4 . , -

    ?

    :

    10. , -

    n=210

    m=C24

    ()=mn = 2222

    2222

    10

    4

    C

    =

    215

    1.8. 8 2, 4, 6, 8, 12, 7, 11, 13. 2

    . , .

    :

    Copyright & A K-C

  • 2 8. , -

    28

    8 : 2, 4, 6, 8, 12.

    , 25

    8=5+3

    2=2+0 -

    (A)=C25

    C28 =

    514

    1.9. , 5 7

    . 5 . -

    : , : 1

    , 2 2 ; ; D

    .

    :

    5 15 (3+5+7).

    , n=C515

    15=7+8

    A: 5=5+0 mA = C57

    P(A)=mAn =

    C57

    C515 =

    1143

    15=3+5+7

    B: 5=1+2+2 mB = C13 C

    25 C

    27

    P(B)= mBn =

    C31

    52

    72

    155

    C C C

    =30143

    15=3+12

    C: 5=3+2 mC = C33 C

    212 =1C

    212 = C

    212

    P(C)=C212

    C215 =

    291

    15=5+10

    D:5=0+5 mD = C510

    P(D)=mDn =

    C510

    C515 =

    12143

    1.10. ,,,, (6 49) 6 .

    , : ) 6 ; ) 5 6; ) 3 ?

    :

    6 49. ,

    649 =49!

    6! 43! =13.983.816.

    49=6+43

    6 : 6=6+0

    5 : 6=5+1

    4 : 6=4+2

    Copyright & A K-C

  • 3 : 6=3+3

    (m1=1),

    1+56 143 =1+

    6!435! =259 (m2=259) ,

    1+258+46C 243+C

    36C

    343=1 + 258 + 13545 + 246820 = 260624

    :

    (A)=m1 n =

    1C 649

    =1

    13.983.816 0,00000007

    (B)=m2 n =

    1+C56 C 143

    C 649 =

    25913.983.816 =0,0000185

    (C)=m3 n =

    1+C56 C 143 +C

    46 C

    243 +C

    36 C

    343

    C 649 =

    260.62413.983.816 0,0186

    1.11. , 3 , , ,

    . , .

    :

    10 (0,1,

    ... ,9) 3.

    n= 310 = 10!7! =720. m=1.

    P(A)=mn =

    1720 .

    1.12. -

    30 . . -

    , , ?

    :

    30 5, -

    n = 530 = 3029282726=17100720.

    , , m=1.

    (A)= mn =

    1A530

    = 1

    17100720 .

    1.13. , n , m .

    . , -

    .

    :

    m n ,

    m , nm =mn.

    , - m ( 1 , 2- ..

    m-).

    Copyright & A K-C

  • P(A)= m

    Anm =

    mmn =

    1mn-1 .

    1.14. 10 , . -

    , , 10 . -

    , . :

    10 10,

    , 1010 =1010

    , m=1010 =P10=10!

    (A)= mn =

    P10A1010

    = 10!1010 0,00036

    1.15. , 24 ?

    ( , 29 .)

    :

    365 24,

    , A 24365 =36524.

    , m=A 24365 A 24365

    P(A)= A 24365 - A

    24365

    A 24365 =1 -

    A 24365

    A 24365 =1 -

    365!341! 36524

    1.16. 1,2,3,4,5 . ) -

    . , ; ) -

    3 , . , -

    .

    :

    ) 5 , .. n=P5

    =5!

    :

    1) 2, 4 4 .

    2) - 4, 4 4 , m=P4+P4=4!+4!

    P(A)= P4+P4

    P5 =

    4!+4!5! =

    24!5! =

    25

    ) 5 3, .. n=A35 =543=60

    :

    1) - 2, 2 4 ,

    2) - 4, 2 4 , ..

    m=A24 +A24 =43+43=24

    P(B)= A24 +A

    24

    A35 =

    2460 =

    25

    1.17. 10 . , 3

    .

    Copyright & A K-C

  • :

    n=P10=10!

    , ,

    , , 10, 8 ; 3

    P3 , m=P3P8=3!8!

    P(A) = mn =

    P3P8P10

    = 3! 8!10! =

    115

    1.18. 5 , , , , . , ,

    ,

    :

    3 (, , )

    n = P(2, 2, 1) = (2+2+1)!2! 2! 1! =

    5!22 = 30 m = 1

    P(A) = 1

    P(2,2,1) = 130

    1.19. . ,

    7 , , :

    ; ;

    5; D 5, 1 2.

    :

    7 10 (0, 1, 2, 3, , 9). -

    . n = A710 =107.

    , 4 ( 10 ), 3

    10 3. mA=310

    10111=10310=104.

    () = mAn =

    A310 10 A710

    = 104

    107 = 0,001

    , 7 , .. m=710 , ()=

    mBn

    = 710

    710 =

    10!3!107 0,0605.

    , 5, 6

    10 6.

    mC=610 ,

    ()= mCn =

    610 710

    = 106

    107 =0,1.

    D , 5, 1 2,

    3, 2, 2.

    mD=(3, 2, 2)= (3+2+2)!3! 2! 2! =210

    (D)= mDn =

    210107 =2,110

    -5=0,000021

    Copyright & A K-C

  • 1.20. 2 . : 7

    8 ?

    : P1=636 >P2=

    536

    1.21. , , 14 : , , , , , -

    , , , , ,

    .

    : 413

    1.22. , 5 ?

    : P = 37 , : 7 : 1 , 1 1

    .

    1.23. , 900 60 , -

    , 180 ,

    , 150 , 20

    , . -

    : - , - ,

    , - , ?

    : 115 ,

    56 ,

    29 .

    1.24. , . ,

    :

    ) , ) , .

    : 190 ,

    181 .

    1.25. , 20 25 2 ,

    25. , : ) ; ) ; )

    .

    : ) C220

    C225 =

    1930 , )

    C120 C15

    C225 =

    13 , )

    C25

    C225 =

    130 .

    1.26. 40 , 10 . 2 .

    , 5 ?

    : C510 C

    1530

    C2040 =

    139365040

    1.27. 10 5 . 3 .

    ?

    : , = C 210 C

    15

    C 315 0,494

    1.28. 5 , 3 3 2 5 .

    3 . , : ) ; ) 2

    ; ) 7 .

    Copyright & A K-C

  • : ) 15 C

    13 C

    12

    C310 =

    14 , )

    C 310 - C15 C

    13 C

    12

    C310 =

    34 , )

    C15 C23 +C

    25 C

    12

    C310 =

    724

    1.29. 10 2. , 5 -

    : ) 1 ; ) ; ) .

    : ) 12 C

    48

    C510 =

    59 ) C510

    38C =

    29 )

    C58

    C510 =

    29

    1.30. ,

    ?

    : 1

    A46 =

    1360

    1.31. 6 .

    . : = {

    5 }; = { }; = { -

    }.

    : ) 6

    A56 =

    11296 )

    A56 - 6A56

    = 12951296 )

    6P5A56

    = 554

    1.32. 10 , ,

    8 , , -

    . : 1 2 -

    . . .

    : ()= 8810

    = 145 , ()=

    38810

    = 115 .

    : 3 : 1 8, 2 9 3 10.

    1.33. () -

    , 4.

    ,

    .

    : 1

    42 =

    116 .

    1.34. 6 , , , , , . ,

    , ?

    : 1

    (3, 2,1) =

    160 .

    Copyright & A K-C

  • 2

    ()=()(/)=()(/), (/)

    , .. ,

    . ,

    ()=()()

    (+)=()+()-()

    , (+)=()+()

    2.1. 15% . , 5

    ?

    :

    : i i- ( 5,1=i ); i - . -

    5 .

    ()=(12345)=(1)(2)(3)(4)(5)=(,85)5,44.

    2.2. , -

    . , , -

    0,3; 0,4; 0,6.

    , ?

    :

    i-(i=1,2,3) , , i ; i - .

    .

    ) ()=(123)=(1)(2)(3)=(1-(1)).

    (1-(2))(1-(3))=(1-0,3)(1-0,4)(1-0,6)0,168.

    ) (1)=1.

    () = (1 2 3) = (1) (2) (3) = 1 (1- (2)) (1- (3)) = 1 (1-0,4) (1-0,6) =

    0,24.

    2.3. 96% ( ); -

    75 ( ). ,

    , .

    :

    ( ), , , , ,

    ( ) ( ).

    ()=0,96, (/)=0,75.

    ()=()(/)=0,960,75=0,72.

    2.4. , 20 25 2 , -

    25. , .

    :

    :

    i i- (i=1,2)

    Copyright & A K-C

  • .

    ()=(12)=(1)(2/1)=2025

    1924 = 30

    19.

    2.5. 6 , .

    , . ,

    .

    :

    :

    1 P,

    2 ,

    3 - ,

    4 - ,

    5 - ,

    6 - , i- , i =1 6, .

    .

    ()=(123456)=(1)(2/1)(3/12).

    (4/123)(5/1234)(6/12345)=16

    25

    14

    13

    12 1=

    1360 .

    2.6. 100 .

    .

    , 5% .

    :

    , ,

    . . =12345 , ={ -

    } =15, .

    ()=(1)(2/1)(3/12)(4/123)(5/1234)=95100

    9499

    9398

    9297

    9196 0,77

    ()=1-P(A)1-0,770,23.

    2.7. 20 , 4 ( 5 -

    ). 4. : ={ -

    }, ={ }.

    :

    :

    1 ( 4 );

    A2 , ;

    3 , ;

    4 , , .

    ()=(1234)=(1)(2/1)(3/12)(4/123)=

    2020

    1519

    1018

    517 0,13

    i= i- , 1- (i=2,3,4)

    Copyright & A K-C

  • ()=(1234)=(1)(2/1) (3/12) (4/123)=

    2020

    419

    318

    217 0,004.

    2.8. , 5 10 , 5 3 . -

    , .

    :

    :

    i i- (i=1,5).

    - 5 .

    ()=(12345)=(1)(2/1)(3/12)(4/123)

    (5/1234)

    15=5+10

    1:3=1+2

    1 n1=315

    m1=C15 C

    210

    (1)=m1n1

    =C15 C

    210

    C315

    12=4+8

    (A2/A1): 3=1+2 n2=C312 , m2=C

    14 C

    28

    P(A2/A1)=m2n2

    =C14 C

    28

    C312

    9=3+6

    (A3/A1A2): 3=1+2 P(A3/A1A2)=C13 C

    27

    C39

    6=2+4

    (A4/A1A2A3): 3=1+2 P(A4/A1A2A3) = C12 C

    25

    C63

    3= 1+2

    (A5/ A1A2A3A4): 3= 1+2 P(A5/ A1A2A3A4) = 1

    P(A) = C15 C

    210

    C315

    C14 C28

    C312

    C13 C26

    C39

    C12 C24

    C36 10,08

    2.9. .

    ,

    0,01. , 0,01; - 1=0,08; 2=0,12; -

    - 3=0,1. :

    :

    :

    - , .. 0,01.

    - , .. 0,01.

    Copyright & A K-C

  • i- i- 0,01 (i=1,2,3)

    1- -, 2- - , 3- - .

    ()=1-()=1-(123)=1-(1)(2)(3)=1-(1-(1))(1-(2))(1-(3))=1-(1-0,08)(1-0,12)(1-

    0,1)=1-0,920,880,90,27.

    2.10. , ,

    0,7 ?

    :

    :

    ;

    ;

    i i- , i=1,2,3

    ()=1-()=1-(123)=1-(1)(2)(3)=1-(1-(1))(1-(2))(1-(3))=1-(1-,7)3=1-

    ,33=0,973.

    2.11. .

    , 3 . , , -

    ?

    :

    - 3 .

    - 3 .

    i - i- (i=1,2,3).

    ()=1-()=1-(123)=1-(1)(2/1)(3/12)=1-910

    89

    78 =0,3.

    - 3 , , .

    ()=1-(1)(2/1)(3/12)=1-45

    34

    23 =0,6.

    2.12. , 30 24. ,

    ?

    :

    - .

    - 1-, 2- .

    i - i- (i=1,2)

    ()=1-()=1-(12)=1-(1)(2/1)=1-630

    529 =1-

    129 =

    2829 0,97.

    2.13. . , -

    , 0,95?

    :

    n .

    n .

    i i- i =1,n .

    ()=1-()=1-(12n)=1-(1)(2)(n)=1-(12 )

    n.

    Copyright & A K-C

  • 1-(12 )

    n>0,95, (12 )

    n20 n>log220 , n>lg20lg2 , n>

    lg2+1lg2 (lg20,3)

    n>4,3 .. n5.

    2.14. , 100 , 5 , -

    , -

    50.

    :

    - .

    - .

    - .

    - .

    100=5+95 n= 50100

    B:50=0+50C:50=1+49 m1=

    5095 , m2=

    4995

    15 .

    ()=(+)=()+()=m1n +

    m2n =

    C5095

    50100 +4995

    15

    50100 0,18.

    2.15. 20 25 . , -

    , 3 4 . , ?

    :

    - , .. 3 4 .

    - 3 .

    - 4 .

    25=20+5 n =425 =12650, m1=C320

    15 =5700

    : 4 = 3+1 m2=C420 =4845

    : 4 =4+0

    ()=(+)=()+()=m1n +

    m2n =

    C320 15 +

    420

    425 0,45+0,380,83.

    2.16. , , 5 ,

    11 , 8 , 10,8 6. .

    , .

    :

    D

    i i-

    i i-

    Di i- , i=1,2.

    ()=(++D)=()+()+(D)=(12)+(12)+(D1D2)=(1)(2)+(1)(2)+(D1)(D2)= 524

    1024 +

    1124

    824 +

    824

    624 =

    186576 0,32.

    Copyright & A K-C

  • 2.17. -6

    6 . : ) ; ) -

    - .

    - , .. 3 6

    i - i- 3

    i - i- 4

    i - i- 5

    Di - i- 6 , i=1,2

    F - - .

    Fi - i- - .

    49=6+43 n=649

    i: 6=3+ 3 m1=36

    343

    Bi: 6=4+2 m2 =46

    243

    Ci: 6=5+1 m3 =C56 C

    143

    Di: 6=6+0 m4= C66 =1

    ()=(12)=(1)(2)=m1n

    m1n =

    C

    36 C

    343

    C649

    2

    0,0003115

    (F)=P(F1F2)=P(F1)P(F2)=P(A1+B1+C1+D1)

    P(A2+B2+C2+D2)=(P(A1)+P(B1)+P(C1)+P(D1))

    (P(A2)+P(B2)+P(C2)+P(D2))=2)2( 431

    n

    m

    n

    m

    n

    m

    n

    m++++++++++++ =

    C

    36 C

    343 +C

    46 C

    243 +C

    56 C

    143 +1

    C649

    2

    0,0003473

    2.18. 10 20 ., 5 15 . 2 10 . 6

    . , ?

    :

    6 .

    6 .

    6 20 . (=1,20)

    5 20 . 15 . (=1,15)

    D 5 20 10 . (=1,10)

    4 20 . 2 15 . (=1,10)

    F 4 20 , 10 15 .(=1,05)

    G 3 20 . 3 15 . (=1,05)

    20 . 15 . 10 .

    17 = 10 + 5 + 2

    : 6 = 6 + 0 + 0

    : 6 = 5 + 1 + 0

    D: 6 = 5 + 0 + 1

    E: 6 = 4 + 2 + 0

    F: 6 = 4 + 1 + 1

    G: 6 = 3 + 3 + 0

    Copyright & A K-C

  • ()=1-()=1-(()+()+P(D)+P(E)+P(F)+P(G))=1-1

    C617 (C610 +C

    510 C

    15 +C

    510 C

    12 +C

    410 C

    25 +C

    410 C

    15 C

    12 +C

    310 C

    35 )0,4.

    2.19. 2 , 3 .

    : - - , - , - , D -

    .

    :

    Ei i- .

    P(A)=P(E1E2)=P(E1)P(E2)=26

    36 =

    16

    P(B)=P(E1E2+E1E2)=P(E1)P( 2E )+P(E1)P(E2)=26 6

    3+

    46

    36 =

    12

    P(C)=P(E1E2)=P(E1)P(E2)=46

    36 =

    13

    P(D)=1-P(D)=1-P(E1E2)=1-46

    36 =

    23

    2.20. . , -

    , , 0,6; 0,7; 0,8. -

    :

    - 3-

    -

    C

    D - 2-

    - , 2-

    :

    i i- , i=1,2,3.

    P(A)=P(A1A2A3)=P(A1)P(A2)P(A3)=0,60,70,8=0,336

    P(B)=1-P(B)=1-P(A1A2A3)=1-P(A1)P(A2)P(A3)=1-0,40,30,2=0,976.

    P(D)=P(A1A2A3+A1A2A3+A1A2A3)=P(A1)P(A2)P(A3)+P(A1)P(A2)P(A3)+P(A1)P(A2)P(A3)=0,60,70,2

    +0,60,30,8+0,40,70,8=0,452.

    P(C)=P(A1A2A3+A1A2A3+A1A2A3)=P(A1)P(A2)P(A3)+P(A1)

    P(A2)P(A3)+P(A1)P(A2)P(A3)=0,40,30,8+0,40,70,2+0,60,30,2=0,188.

    P(E)=P(D+A)=P(D)+P(A)=0,452+0,336=0,788.

    2.21. 2 30

    36 . . -

    : - ; - , ; - .

    :

    Di i-

    Ei i- , i=1,2.

    P(A)=P(D1E1)=P(D1)P(E1/D1)=3066

    2965 =

    29143

    P(B)=P(D1E2+D2E1)=P(D1)P(E2/D1)+P(D2)P(E1/D2)=3066

    3665 +

    3666

    3065 =

    72143

    Copyright & A K-C

  • P(C)=1-P(C)=1-P(A)=1-143

    29=

    143

    114

    2.22. . 3-

    . 2. 5 -

    , .

    . , ?

    :

    , .. 2 3.

    2

    3

    Di i-; i=1, 2, 3

    P(A)=P(B+C)=P(B)+P(C)=P(D1D2D3+D1D2D3+D1D2D3)+P(D1D2D3)=

    P(D1)P(D2)P(D3)+P(D1)P(D2)P(D3)+P(D1)P(D2)P(D3)+P(D1)P(D2)P(D3)=15

    15

    45 +

    15

    45

    15 +

    45

    15

    15 +

    15

    15

    15

    =34125 +

    1125 =

    13125 =0,104.

    2.23. , -

    , p=0,05525.

    , : ) -

    ; ) .

    :

    , .

    , -

    .

    Di i- , i=1, 2.

    P(A)=P(D1+D2)=P(D1)+P(D2)=2p=0,1105

    P(B)=P(D1+D2)=P(D1)+P(D2)-P(D1D2)=P(D1)+P(D2)-P(D1)P(D2)=p+p-pp=2p-p2=0,1075.

    2.24. - 1

    2, .

    , .

    - 1 2

    1 2. , ?

    :

    i i-

    i i- ; i=1,2

    P(A)=P(BC)=P(B)P(C)=P(B1+B2)P(C1+C2)=((P(B1)+P(B2)-P(B1B2))-(P(C1)+P(C2)-P(C1C2))=(P(B1)+P(B2)-

    P(B1)P(B2))(P(C1)+P(C2)-P(C1)P(C2))=(p1+p2-p1p2)2

    1' 2' 1" 2"

    Copyright & A K-C

  • 2.25. k1, k2, k3, k4,

    q1, q2, q3, q4 (pi=1-qi, i=1 4, ). , ?

    30

    A) k2 k1 k3 k4

    B) k1 k3 k2 k4

    :

    i i- , i=1 4,

    ) k2, k3, k4, .. k2,k3,k4.

    P(A)=P(A1B)=P(A1)P(B)=P(A1)(1-P(B))=P(A1)(1-P(A2A3A4))=P(A1)

    (1-P(A2)P(A3)P(A4))=p1(1-q2q3q4)

    ) 1 k1 k2, 2 k3 k4.

    1) P(A)=P(C1C2)=P(C1)P(C2)=P(A1+A2)P(A3+A4)=(P(A1)+P(A2)-P(A1A2))(P(A3)+P(A4)-

    P(A3A4))=(P(A1)+P(A2)-P(A1)P(A2))(P(A3)+P(A4)-P(A3)P(A4))=(p1+p2-p1p2)(p3+p4-p3p4).

    2)P(A)=P(C1)P(C2)=(1-P(C1))(1-P(C2))=(1-P(A1)P(A2))(1-P(A3)P(A4))=

    (1-q1q2)(1-q3q4).

    2.26. ) ) 2 ) - , - . -

    , 0,7; -

    .

    A) 2 1 3 2' 1' 3'

    B) 2' 1' 2 1 3 3'

    :

    .

    i i , i=1 3,

    Bi i i=1 3,

    D 2 3

    .

    P(C)=P(A1D)=P(A1)P(D)=P(A1)(1-P(D))=P(A1)(1-P(A2A3))=P(A1)(1-P(A2)P(A3))=0,7(1-0,32)=0,673.

    A ( ))

    1 1, 2, 3.

    Copyright & A K-C

  • 2 1, 2, 3

    D2 2 3.

    P(A)=1-P(A)=1-P(E1E2)=1-P(E1)P(E2)=1-(1-P(E1))(1-P(E2))=1-(1-P(A1D))(1-P(B1D2))=1-(1-

    P(A1)P(D))(1-P(B1)P(D2))

    P(D1)=1-P(D1)=1-P(A2A3)=1-P(A2)P(A3)=1-0,30,3=1-0,32

    P(D2)=1-P(D2)=1-P(B2B3)=1-P(B2)P(B3)=1-0,32

    P(A)=1- (1-0,7(1-0,32))2=0,868.

    B ( )

    F1 1, 1

    F2 2, 2, 3, 3.

    P(B)=P(F1F2)=P(F1)P(F2)=(1-P(F1))(1-P(F2))=(1-P(A1B1)

    (1-P(A2A3B2B3))=(1-0,32)(1-0,34)=0,907.

    P(A)P(C) =

    0,8680,637 1,36,

    P(B)P(C) =

    0,9070,637 1,41.

    %.

    P(A)-P(C)P(C) 100=36%

    P(B)-P(C)P(C) 100=43%

    ) .

    2.27. N .

    - , :

    1 2 L1 L2 L3

    0,6 0,5 0,4 0,7 0,9

    L1 M K2 L2 K2 N L3 .

    :

    i (i=1,2) , i, - -

    i, - Lj (j=1, 2, 3). -

    =P(A+B)=P(A)+P(B)-P(A)P(B) ..

    P(A)=P(A1)+P(A2)-P(A1)P(A2)=0,6+0,5-0,60,5=0,8.

    P(B)=P(L1)(L2)(L3)=0,40,70,9=0,252,

    p=0,8+0,252-0,80,252=0,85.

    Copyright & A K-C

  • 2.28. -

    . ) , -

    ; ) - -

    ; ) - ; )

    - .

    : ) (1-)(1-) ) ) (1-) ) (1-)

    2.29. ,

    (1)=0,8, (0)=0,2. 3- .

    : P(000)=0,23 P(001)=P(100)=P(010)=0,80,22

    P(110)=P(101)=P(011)=0,20,82 P(111)=0,83

    2.30. , 3 1, 2, 3, -

    . -

    12 (1-) -

    . , .

    , 111, 123.

    : p12 (1-p)

    12 (1-p).

    2.31. , 1, 0, 0, 0, -

    1000.

    : 14 111=

    14 .

    2.32. ,

    .

    : 16

    15

    14

    13 =

    1360 .

    2.33. 5 , , , , . ,

    .

    : 25

    24

    13

    12 =

    130

    2.34. 6. ,

    1 2 .

    : 2531

    2430 =

    2031 .

    2.35. 7 3 . 3 .

    , .

    : 710

    69

    58 =

    724 .

    2.36. , : 0 1. 0 1 -

    . , 0?

    : 1-12

    12 =

    34 .

    Copyright & A K-C

  • 2.37. 3 . 1-

    0,15. 2- =0,1, 3- - 0,12. , ,

    , .

    : 1-0,850,90,88=0,37.

    2.38. , 4 , 0,9 ( ).

    , .

    : 1-0,14=0,9999.

    2.39. 0,9984. -

    , .

    : =0,8.

    2.40. 0,5.

    , 0,9.

    : n4 (1-0,5n0,9).

    2.41. , , 0,2. -

    , 0,99 ,

    .

    : n3 (1-0,2n>0,99), lg 50,7.

    2.42. , 12 -

    . , : ) ; ) 6-, 2-; )

    1- ; ) .

    : ) 112

    112 =

    1144 , )2

    112 12

    1=

    72

    1

    )1112

    1112 =

    121144 , )1-

    121144 =

    23144 .

    2.43. 0,01; 0,006; 0,002 -

    . , .

    : 0,01+0,006+0,002=0,018.

    2.44. . , , , 0,8.

    , .

    : 0,80,2+0,80,2=0,32.

    2.45. , , , 2 :

    . .

    - 1 1 1=0,9 0 1-

    1=0,1, 0 0 q1=0,8 1 1-q1=0,2. -

    - p2=0,7; 1-p2=0,3; q2=0,6; 1-q2=0,4. -

    :

    10, ,

    10, 2 .

    :

    P(A)=P(T11)P(T00)=[p1p2+(1-p1)(1-q2)][q1q2+(1-q1)(1-p2)]0,36.

    P(B)=P(T11)P(T01)+P(T10)P(T00)=[p1p2+(1-p1)(1-q2)][q1(1-q2)+p2(1-q1)]+[p1(1-p2)+(1-p1)q2][q1q2+(1-q1)(1-

    p2)]0,49.

    Copyright & A K-C

  • 2.46. 10 : , , -

    , 2 - 5 - . : )

    ; ) ; )

    : , , ; )

    : , , .

    : ) 0,3; 0,2;0,5

    ) 0,3+0,2=0,5.

    ) P(AB)=310

    29 =

    115 P(CA)=

    510

    39 =

    16 P(CB)=

    510

    29 =

    19

    ) P(ABC)=310

    29

    58 =

    124 P(CAB)=

    510

    39

    28 =

    124 P(CBA)=

    510

    29

    38 =

    124

    2.47. . ,

    0,9, - 0,8. , ,

    : ) ; ) .

    : ) 0,90,90,8=0,648,

    ) 1-(0,90,10,2+0,10,90,2+0,10,10,8+0,10,10,2)=0,954.

    2.48. . 2, 42, 44,

    42, 44. . , : )

    42; ) 42; ) .

    : ) 13

    12 =

    16 , )

    13 +

    12 -

    13

    12 =

    23 , )

    13

    12 +

    13

    12 =

    13 .

    2.49. . -

    , , 0,5, - 0,9.

    , , ?

    : 0,5+0,9+0,90,5=0,95.

    2.50. , . -

    , . -

    k k - ( qk=1-pk - ). -

    , .

    .

    a) 1 b) 1 2 3 c) 2 1 4 2 4 5 6 3 3 : ) 1-q1q2q3

    b) 1-(1-p1p2p3)(1-p4p5p6) ) p1p4(p2+p3-p2p3)=p1p4(1-q2q3).

    Copyright & A K-C

  • 3 . , -

    kH () ),1( nk = . -

    = =

    ==n

    k

    n

    kkkk HPHAPHPAP

    1 1

    1)(),/()()(

    )(),...(),( 21 HnPHPHP , - , "" , ..

    )/( AHP K , ,)(

    )/()()/(

    AP

    HAPHPAHP KKK

    =

    nk ,1= 3.1 ,

    1f 2f , 1f 2f

    . 1f 0,3; 1f -0,6. , ?

    :

    kH - ;kf =1,2.

    kH .

    2

    1)()( 21 == HPHP ( 1f 2f ).

    ={ }; 6,0)/(;3,0)/( 21 == HAPHAP ;

    =

    =+==2

    1

    45,06,02

    13,0

    2

    1)/()()(

    kkk HAPHPAP

    3.2 "1" () 5

    1 "0"

    ( ) 5

    4. ,

    "1", "1" "0" 0,1; "0" "1" -0,3. :

    : 1H - "1"

    2H - "0" = { "1"}

    5

    1)( 1 =HP 9,0)/( 1 =HAP ("1" "0")

    5

    4)( 2 =HP 3,0)/( 2 =HAP ("0" "1")

    =

    ==+==2

    1

    42,050

    213,0

    5

    49,0

    5

    1)/()()(

    kkk HAPHPAP

    3.3 , . , - 2:3:5. , 0,05; 0,1; 0,2. . , .

    :

    : kH - - , -1, 2, 3. = { } .. 2:3:5

    10

    2)( 1 =HP

    Copyright & A K-C

  • 95,005,01)/( 1 ==HAP

    10

    3)( 2 =HP 9,01,01)/( 2 ==HAP

    10

    5)( 3 =HP 8,02,01)/( 3 ==HAP

    =

    =++==3

    1

    86,08,05,09,03,095,02,0)/()()(k

    kk HAPHPAP

    3.4 12 10 , . , , , -. , , .

    : : 1- ; 2- ;

    12

    1)( 1 =HP 12

    11)( 2 =HP

    -

    11

    2)/( 1 =HAP ( 10 , 1 , 1 )

    11

    1)/( 2 =HAP ( 10 , 1 , )

    =

    =+==2

    1 132

    13

    11

    1

    12

    11

    11

    2

    12

    1)/()()(

    kKK HAPHPAP

    3.4 15 , . -

    25 . , , - 2 1 ?

    :

    KH (=0,1,2), .

    KH .

    k

    k n

    m =)( 230Cnk =

    ( 30 25) 30=25+5

    0H : 2=0+2 250 Cm =

    1H : 2=1+1 15

    1251 CCm =

    2H : 2=2+0 2252 Cm =

    29

    20

    !30!23!2

    !28!2!25)(

    87

    25

    !30

    !28!2525525)(

    87

    2

    !30!3!2

    !28!2!5)(

    230

    225

    2

    230

    230

    15

    125

    1

    230

    25

    0

    ===

    ===

    =

    ===

    C

    CHP

    CC

    CCHP

    C

    CHP

    = { } 0)/( 0 =HAP 1)/( 2 =HAP

    7

    6

    28

    24)/( 1 ==HAP ( 28 , 24 ).

    53,0609

    3251

    87

    25

    7

    6

    87

    250

    87

    2)/()()(

    2

    0

    =++== =k

    kk HAPHPAP

    Copyright & A K-C

  • 3.6 0,8 , 0,2 - . , - 0,7; - 0,3. , - -. , .

    :

    : 1- , 2- . = { - }.

    8,0)( 1 =HP 7,0)/( 1 =HAP 2,0)( 2 =HP 3,0)/( 2 =HAP

    :

    903,031

    28

    3,02,07,08,0

    7,08,0

    )/()(

    )/()()/(

    2

    1

    111 =+

    =

    =

    =kkk HAPHP

    HAPHPAHP

    3.7 60% - , 80% 75% . - - . , .

    : : 1- -

    2 -- (1)=0,6 (60% 100% -) (2)=0,4 = { } P(A/H1)=0,8 (80% ) P(A/H2)=0,75 (75% ) :

    13

    8

    75,04,08,06,0

    8,06,0

    )/()(

    )/()()/(

    2

    1

    111 =+

    =

    =

    =k

    kk HAPHP

    HAPHPAHP =0.62

    3.8 "" "."

    , 5

    2"" "".

    , "" "" 5:3. - , , : ) ""; ) "".

    : - "", - "". : H1- "", H2- "". P(H1) : P(H2)=5;3, , P(H1)+P(H2)=1 P(H1)=5/8; P(H2).=3/8 P(A/H1)=3/5; P(A/H2)=1/3; P(B/H1)=2/5; P(B/H2)=2/3.

    ====

    ====++++========2

    1 2

    1

    3

    1

    8

    3

    5

    3

    8

    5)/()()(

    lii HAPHPAP

    ====

    ====++++========2

    1 2

    1

    3

    2

    8

    3

    5

    2

    8

    5)/()()(

    lii HBPHPBP

    4

    3

    2

    15

    3

    8

    3

    )(

    )/()()/( 111 =

    ==

    AP

    HAPHPAHP

    Copyright & A K-C

  • 2

    1

    2

    13

    2

    8

    3

    )(

    )2/()2()/( 2 =

    =

    =

    BP

    HBPHPBHP

    3.9 25 , , 10 , 7 , 5- 3 . 25 , - 20, -15 10 . . :

    1S = { }; 2S = { }; 3S = {-

    }. :

    : H1- H2 - H3 - H4 - . P(H1)=10/25, P(H2)=7/25,P(H3)=5/25, P(H4)=3/25 = { }. P(A/H1)=1, B k - - , -1,2.

    30

    19

    24

    19

    25

    20)/()()()/( 121212 ==== BBPBPBBPHAP

    20

    7

    24

    14

    25

    15)/()()()/( 121213 ==== BBPBPBBPHAP

    20

    3

    24

    9

    25

    10)()/( 214 === BBPHAP

    :

    6,0499

    300

    20

    3

    25

    3

    20

    7

    25

    5

    30

    19

    25

    71

    25

    10

    125

    10

    )/()(

    )/()()/(

    4

    1

    111

    =

    +++

    =

    =

    =kkk HAPHP

    HAPHPAHP

    03,0998

    27

    750

    49920

    3

    25

    3

    )(

    )/()()/()(

    11,0998

    105

    750

    49920

    7

    25

    5

    )(

    )/()()/()(

    87,0)/()/()(

    27,0499

    133

    750

    49930

    19

    25

    7

    )(

    )/()()/(

    )750

    499)/()())((

    4443

    3332

    211

    222

    4

    1

    =

    =

    ==

    =

    =

    ==

    +=

    =

    =

    =

    == =

    AP

    HAPHPAHPSP

    AP

    HAPHPAHPSP

    AHPAHPSP

    AP

    HAPHPAHP

    HAPHPAPk

    kk

    3.10 . , 1- 2- , , - .3,0;4,0;2,0 321 === ppp

    : : 1H -3-

    Copyright & A K-C

  • 2H -3- .

    7,0)(;3,0)( 21 == HPHP = { }, = {- } =1,2

    .08,04,02,0)()()()/(

    44,06,02,04,08,0

    )()()()()()/(

    21212

    212121211

    ====

    =+=+=+=

    BPBPBBPHAP

    BPBPBPBPBBBBPHAP

    47

    14

    188,0

    056,0

    08,07,044,03,0

    08,07,0

    )/()(

    )/()()/(

    2

    1

    222 ==+

    =

    =

    =k

    kk HAPHP

    HAPHPAHP

    3.11 , , , 10 , - - . ) , ? ) , - , .

    :

    : 1H -

    2H 3H

    10

    2)(,

    10

    5)(,

    10

    3)( 321 === HPHPHP

    = { }

    3

    2)/( 1 =HCP ( 3 , 2 )

    2

    1)/( 2 =HCP 3

    1)/( 3 =HCP

    ) =

    =++==3

    1 60

    31

    3

    1

    10

    2

    2

    1

    10

    5

    3

    2

    10

    3)/()()(

    kkk HCPHPCP

    )31

    15

    60

    312

    1

    10

    5

    )(

    )/()()/( 2

    22 =

    =

    =

    CP

    HCPHPCHP

    3.12 . - 5 3 , 4 4 . - . ) , ? ) , ?

    :

    : kH - , =1,2,3 3

    1)( =kHP

    ={ }

    2

    1

    8

    4)/(

    8

    5)/()/(

    3

    21

    ==

    ==

    HAP

    HAPHAP

    12

    7

    2

    1

    3

    1

    8

    5

    3

    1

    8

    5

    3

    1)/()()(

    3

    1

    =++== =k

    kk HAPHPAP

    Copyright & A K-C

  • 14

    5

    12

    78

    5

    3

    1

    )(

    )/()()/()/( 1121 =

    =

    ==

    AP

    HAPHPAHPAHP

    -

    7

    5

    14

    5

    14

    5)/()/()( 21 =+=+= AHPAHPBP

    3.13 : , , . , 0,3:0,4:0,3. 0,6. , , 0,2. , . - , , .

    : : 1H -

    2H -

    3H -

    .3,0)(;4,0)(;3,0)( 321 === HPHPHP

    D={ }, -- 4,1=k

    .0048,02,06,02,02,0)()/(

    0048,02,02,06,02,0)()/(

    0144,06,02,02,06,0

    )()()()()()/(

    43213

    43212

    432143211

    ===

    ===

    =====

    EEEEPHDP

    EEEEPHDP

    EPEPEPEPEEEEPHDP

    16

    9

    0048,03,00048,04,00144,03,0

    0144,03,0

    )/()(

    )/()()/(

    3

    1

    111

    =++

    =

    =

    =

    =k

    kk HDPHP

    HDPHPDHP

    3.14 ,

    25,0;5,0;25,0 321 === . , , 0,1;0,2 0,4 . , . : 0,225. 3.15 3 . 20% , -10% - 5%. , - 30 % , 20% - 50% . : 0, 895. 3.16 , -, . 0,06, - 0,03. ? : 0,05. 3.17 5 4 . , . , ( ). : 5/9. 3.18 24 5 . , -, 0,9. 0,65. - . , ? : 90/337.

    Copyright & A K-C

  • 3.19 (), () () . - , 40% . 60% . , 0,02. - 0,03 0,04. , , -. , ? : 8/29. 3.20 , . , 1- , 1-, 2- 3- - 0,4; 0,3; 0,5. : 20/29. 3.21 3 4/5, 3/4, 2/3 . 3 - 2 ( ). - , . : 6/13. 3.22 , , , 1, - 2. 1 3 1 . 2 1 3 . ) , ? ) , 1- , ? : ) 1/2; ) 3/4.

    3.23 , (), (), (), 3:2:5. , 0,8; 0,9; 0,9. ) , ? ) , . : ) 0,87; ) 18/87. 3.24 , -. - 0,8, -0,7, - 0,5. ) - . ) . , . : ) 0,47; ) 12/47.

    Copyright & A K-C

  • 4 , .

    ,

    , .

    ()

    .

    .

    ix - ip .

    1X 2X nX

    1p 2p np

    11

    ==

    n

    iip

    ( ) F(x) , -

    P (X

  • m x px kk

    n

    k= =

    1

    , -

    ( )m x f x dxx =

    +

    .

    , , , .

    X :

    ( )[ ] [ ] [ ]( )D M X m M X M Xx x= = 2 2 2

    ( ) ( )D x m p x p mx k xk

    n

    k k k xk

    n

    = = = =

    1

    22

    1

    2

    ( ) ( ) ( ) ( )x x xD x m f x dx x f x dx m= =

    +

    +

    2 2 2

    C X x xD= .

    0 . -

    0 ,

    .

    ,

    :

    ( ) ( )P X M P X Me e< = > . 4.1 X

    , , .

    :

    C X 0, 1 2 .

    Bk ={ k- } k=1 ,2 .

    ( ) ( ) ( ) ( )P X P B B P B P B= = = = =0 0 5 0 5 0 251 2 1 2 , , , ( ) ( ) ( ) ( ) ( ) ( )

    ( ) ( ) ( ) ( )

    P X P B B B B P B P B P B P B

    P X P B B P B P B

    = = + = + = + =

    = = = = =

    10 5 0 5 0 5 0 5 0 5

    2 0 5 0 5 0 25

    1 2 1 2 1 2 1 2

    1 2 1 2

    , , , , ,

    , , ,

    X 0 1 2 P 0,25 0,5 0,25

    ( )F x

    x

    x

    x

    x

    =

    < < >

    0 00 25 0 10 75 1 21 2

    ,

    , ,

    , ,

    ,

    4.2 . ,

    , 0,9. ,

    Copyright & A K-C

  • . : ) -

    X , ; ) -

    K0 .

    :

    Bk ={ k } k=1,2,3, ...

    ( ) ( )( ) ( ) ( ) ( )( ) ( )

    ( ) ( )

    P X P B

    P X P B B P B P B

    P X P B B B

    P X k P B B B Bk kk

    = = = =

    = = = = =

    = = = =

    = = =

    1 1 0 9 0 1

    2 0 9 0 1 0 09

    3 0 9 0 1 0 081

    0 9 0 1

    1

    1 2 1 2

    1 2 32

    1 2 11

    , ,

    , , ,

    , , ,

    .................................................................

    ... , ,

    X 1 2 3 ... k .... k - 1 P 0,1 0,09 0,081 .... 0,9 - 0,1 k0 = 1 ( ) .

    4.3 4 . 0,5 -

    , . -

    X - , .

    :

    Bk ={k- } k=1,2,3,4.

    X 0 1 2 3 4 P 0,5 0,25 0,125 0,0625 0,0625

    4.4 3 .

    0,1 . -

    X , ,

    , . -

    , X , ( )F x , - : m Dx x x, , .

    :

    X , . X :

    X 0 1 2 3 P 0,729 0,243 0,027 0,001

    Copyright & A K-C

  • ( ) ( ) ( ) ( ) ( )f x x x x x= + + + 0 729 0 243 1 0 027 2 0 001 3, , , , .

    ( ) ( )F x P X x

    x

    x

    x

    x

    x

    = < =

    < < <

    >

    0 0

    0 279 0 1

    0 972 1 2

    0 999 2 3

    1 3

    ,

    , ,

    , ,

    , ,

    ,

    4.5 7 , 4 , . -

    3 . X .

    X { X 2 } :

    ( )( )( )( )

    7 4 3

    0 3 0 3

    1 3 1 2

    2 3 2 1

    3 3 3 0

    = += = +

    = = +

    = = +

    = = +

    X

    X

    X

    X

    :

    :

    :

    :

    ( )P X k mn

    n C k

    m C

    m C C C

    m C C C

    m C

    k= = = =

    = =

    = =

    = =

    =

    , , ,73

    0 33

    1 41

    32

    32

    2 42

    31

    42

    3 43

    0 3

    1

    4

    3

    ( )

    ( )

    ( )

    P P XC

    P P XC

    C

    P P XC

    C

    0

    73

    132

    73

    242

    73

    01 3 4

    7

    1

    35

    14 4 3 3 4

    2 7

    12

    35

    23 3 4 3 4

    2 2 7

    18

    35

    = = = = =

    = = =

    =

    =

    = = =

    =

    =

    ! !

    !

    ! ! !

    ! !

    ! ! !

    ! ! !.

    Copyright & A K-C

  • 4.6 10 2 . 3 . X 3 . - F(x) f(x) , mx Dx . :

    ( )( )( )

    10 2 8

    0 3 0 3

    1 3 1 2

    2 3 2 1

    = += = +

    = = +

    = = +

    X

    X

    X

    :

    :

    :

    ( )

    n C

    P X km

    n

    m C m C C C

    m C C

    k

    =

    = =

    = = =

    = =

    103

    0 83

    1 21

    82

    82

    2 22

    81

    2

    8

    ,

    .

    X 0 1 2

    P C

    C83

    103

    7

    15=

    C C

    C82

    21

    103

    7

    15

    =

    C C

    C81

    22

    103

    1

    15

    =

    ( )F x

    x

    x

    x

    x

    =

    <

    <

    >

    0 0

    7

    150 1

    14

    151 2

    1 2

    ,

    ,

    ,

    ,

    ( ) ( ) ( ) ( )f x x x x= + + 715

    7

    151

    1

    152

    m x px k kk

    = = + + ==

    0

    2

    07

    151

    7

    152

    1

    15

    3

    5

    4.7 5 , .

    X, ,

    . .

    :

    Bk = { k }, k = 1 5,

    X 1 2 3 4 5 P 0,2 0,2 0,2 0,2 0,2

    Copyright & A K-C

  • ( )F x

    x

    x

    x

    x

    x

    x

    =

    < < < <

    >

    0 1

    0 2 1 2

    0 4 2 3

    0 6 3 4

    0 8 4 5

    1 5

    ,

    , ,

    , ,

    , ,

    , ,

    ,

    ( ) ( ) ( ) ( ) ( ) ( )( )f x x x x x x= + + + + 0 2 1 2 3 4 5, . 4.8 4 1 4 .

    63

    2 . X .

    X , ( )F x , f(x) -: m Dx x x, , .

    :

    1 2 3 4 5 6

    1 1 1 2 2 3

    2 3 4 3 4 4

    3 4 5 5 6 7

    ( ) ( ) ( ) ( )

    ( )

    P Xm

    nP X P X P X

    P X

    = = = = = = = = = =

    = =

    31

    64

    1

    65

    2

    6

    1

    36

    1

    6

    71

    6

    , , ,

    .

    X 3 4 5 6 7

    P

    ( ) ( ) ( ) ( ) ( ) ( )

    ( )

    f x x x x x x

    m x p

    D x p m

    D

    x k kk

    x k k xk

    x x

    = + + + +

    = = + + + + = =

    = = + + + + =

    = =

    =

    =

    1

    63

    1

    64

    1

    35

    1

    66

    1

    67

    31

    64

    1

    65

    1

    36

    1

    67

    1

    6

    30

    65

    91

    616

    1

    625

    1

    336

    1

    649

    1

    625

    5

    3

    5

    3

    1

    5

    2 2

    1

    5

    16

    16

    13

    16

    16

    Copyright & A K-C

  • 4.9 X 3 x1 =4 p1

    =0,5 ; x2 =6 p2 =0,3 x3 c p3. x3 p3 mx =8.

    :

    .. pkk= =

    1

    3

    1 ,

    m x p x

    x

    x k kk

    = = + +

    ==

    1

    3

    3

    3

    8 4 0 5 6 0 3 0 2

    21

    , , , ,

    .

    4.10 ( ) 1,2,3,4 5 0,07 ; 0,21 ; 0,55 ; 0,16 ; 0,01. - 30 . C ?

    : X X 1 2 3 4 5 P 0,07 0,21 0,55 0,16 0,01

    ( )

    m x p

    D x p

    x k kk

    x k kk

    = = + + + + =

    = = + + + +

    + = =

    =

    =

    1

    5

    2

    1

    52 2 2 2

    2 2

    1 0 07 2 0 21 3 0 55 4 0 16 5 0 01 2 83

    1 0 07 2 0 21 3 0 55 4 0 16

    5 0 01 2 83 8 67 8 0089 0 6611

    , , , , , ,

    , , , ,

    , , , , ,

    ( ) ( )

    x x

    x x

    D

    n m

    = =

    = + = + =

    0 82

    30 2 83 0 82 30 109 5 110

    ,

    , , ,

    . 4.11 C 3 I , II , III .

    P I P II P III

    1 0,5 0,3 0,2

    2 0,4 0,4 0,2

    3 0,4 0,5 0,1

    , I 5 , II 3 , III 1.

    :

    C Xk k k = 1,2,3 .

    X1 1 3 5 P 0,2 0,3 0,5

    X2 1 3 5

    P 0,2 0,4 0,4

    X3 1 3 5

    P 0,1 0,5 0,4

    1 3 , .. [ ] [ ] X X3 1< . 2 1 ,

    [ ][ ][ ]

    M X

    D X

    X

    1

    12

    1

    3 6

    15 4 3 6 2 44

    1 56

    =

    = =

    =

    ,

    , , ,

    ,

    [ ][ ][ ]

    M X

    D X

    X

    2

    2

    2

    3 4

    2

    1 41

    =

    =

    =

    ,

    ,

    [ ][ ][ ]

    M X

    D X

    X

    3

    32

    3

    3 6

    14 6 3 6 1 64

    1 28

    =

    = =

    =

    ,

    , , ,

    ,

    Copyright & A K-C

  • 3 2 , .. [ ] [ ] [ ]M X M X M X2 1 33 4= < =, 4.12 F1(x) F2(x) X1 X2 c, a1

    a2 , 1 . ,

    ( ) ( ) ( )F x a F x a F x= +1 1 2 2 X . :

    1) F1(x) F2(x) , a1 a2 0 ;

    a1F1(x) a2 F2(x) , .

    ) ( ) ( ) ( )( ) ( ) ( )

    2 0 0 0

    1 1 1

    1 1 2 2 1 2

    1 1 2 2 1 2

    lim lim lim

    lim lim limx x x

    x x x

    F x a F x a F x a a

    F x a F x a F x a a

    + + +

    = + = + =

    = + = + =3) -

    x ( ) ( ) ( ) ( ) ( ) ( )F x a F x a F x a F x a F x F x = + = + =0 0 01 1 2 2 1 1 2 2 .

    3 , .. ( )F x .

    4.13 X .

    ( )F x A B arctgxa

    x= + < < , ( ) , A B const .

    a) , ( )f x . :

    ( )lim lim ,x x

    F x A Barctgx

    aA

    BA

    B

    = +

    = =

    2 2

    0

    ( )lim lim ,x x

    F x A Barctgx

    aA

    BA

    B

    AB

    A

    AB

    B

    + += +

    = + + =

    = =

    + = =

    2 21

    20

    1

    2

    21

    1

    ( )F x arctg xa

    = +12

    1

    .

    ( ) ( ) ( )f x F x xa

    a

    a

    a x= =

    + =

    +1 1

    1

    12

    2

    2 2 .

    4.14 X

    ( )F x

    x

    x x

    x

    =

    <

    >

    06

    36 3

    13

    ,

    cos ,

    ,

    ( )f x ,

    (((( )))) .4

    ,4

    ,0,4

    0

  • : (((( )))) (((( ))))

    >>>>

  • 2

    3)2(1

    2

    1

    2

    3)2(

    2

    112

    3)2(102

    3

    0 1

    0 1

    2)2(2

    322

    30)(,21)3

    0

    0 2

    32

    2

    30)(,10)2

    00)(,0)1

    .)()(

    2

    3,1

    3

    2

    0 1

    0

    2

    1 2 3

    202)2(20)(

    xxxtt

    xdttdttdtxFx

    x xdttdtxFx

    xdtxFx

    xdttfxF

    aa

    x adxdxxadxaxdxdxxf

    =+==

    =

    ++=>>>

    ++++====++++++++====>

  • ++

    ++=

    =+=+=

    ===+=

    ==

    >>>

    >>>>

    >>>>

  • 7.31. (X,Y),

    f x yx y

    ( , )( )

    =+ +

    2

    12 2 3 :

    0== yx mm

    =

    5,00

    05,0k

    Copyright & A K-C

  • 8. .

    , (X,Y) , -

    +

    =

    2

    2

    2

    2

    2

    2

    )())((2)(

    )1(2

    1exp

    12

    1),(

    y

    y

    yx

    yxxy

    x

    x

    xy

    xyyx

    mymymxrmx

    r

    ryxf

    ),( yx mm - , yx , - X,Y, xyr - . : (X,Y) -

    ( xyr =0), . X Y f(x,y)

    f x yt

    E Et

    x m

    E

    y m

    Ex y

    x

    x

    y

    y

    ( , ) exp( ) ( )

    =

    +

    22

    2

    2

    2

    2,

    2xx tE = , 2yy tE = (t0,4769...) - X Y . , , , :

    =

    y

    y

    y

    y

    x

    x

    x

    x

    mm

    mmYXP

    ),(

    ,

    ()- , , :

    137

    ( ) ( )( ) ( )x m r x m y m y mkx

    x

    xy x y

    x y

    y

    y

    +

    =

    2

    2

    2

    22

    2

    xyr =0 (X,Y) D

    yx kbka == , 22

    1)),((k

    eDYXP

    =

    == yx , . 0== yx mm R (X,Y) ( ) :

    f rr

    e r

    r

    r

    ( ) ,

    ,

    = >

    >>>

  • 9.15. X

    X -1 0 1 2 P 0,2 0,1 0,3 0,4

    Y X= 2 . :

    m P X x

    D P X x m

    yx

    kk

    yx

    kk y

    k

    k

    = = = + + + =

    = = = + +

    + + =

    =

    =

    2 2 0 2 2 01 2 0 3 2 0 4 2 4

    2 2 0 2 2 01

    2 0 3 2 0 4 2 4 1 99

    1 0 1 2

    1

    4

    2

    1

    42 1 2 0 2

    1 2 2 2 2

    ( ) , , . , ,

    ( ) ( ) ( ) ( ) , ( ) ,

    ( ) , ( ) , ( , ) ,

    9.16. X - 6 . - Y X= +2 1.

    : .. X - 6 3 . :

    P X k C p q n pnk k n k( ) , , , .= = = = q =

    56

    316

    X 0 1 2 3 P 1 2 5

    2 1 6

    75

    216

    15

    216

    1

    216

    P X c p q

    P X c p q

    P X c p q P X c p q

    m x P X xy k k

    ( )

    ( ) .

    ( ) , ( )

    .

    ( ) ( ) ( )

    = = =

    =

    = = =

    =

    = = =

    = = = =

    =

    =

    = + = = +

    05

    6

    125

    216

    1 31

    6

    5

    6

    75

    216

    2 31

    6

    5

    6

    15

    2163

    1

    6

    1

    216

    2 1 2 0 1

    30 0 3

    3

    31 1 2

    2

    32 2 1

    2

    33 3 0

    3

    + + +

    + + + + =

    = + = = + +

    + + + + + + =

    =

    =

    125

    2162 1 1

    75

    216

    2 2 115

    2162 3 1

    1

    2162

    2 1 2 0 1125

    216

    2 1 175

    2162 2 1

    15

    2162 3 1

    1

    2164

    5

    108

    1

    4

    2 2 2

    1

    4

    2 2 2

    ( )

    ( ) ( ) .

    ( ) ( ) ( ) ( )

    ( ) ( ) ( ) .

    k

    y k k yk

    D x P X x m

    9.17. X

    f xx x

    x( )

    exp( ), ( )

    ,=

    > >

    0 0

    0 0.

    eY ==== .

    Copyright & A K-C

  • :

    22

    2

    2

    2)2(

    0

    2222

    )1)(2()1(2)1(0

    2

    1)()()(

    ++++++++====

    ++++

    ++++====

    ++++

    ++++

    ++++====

    ====

    ++++========

    ++++

    ++++

    ++++

    x

    xxy

    xy

    e

    dxeemdxxfeD

    9.18. r 2 , . . :

    .. , , - (r;0). , , OX --, .

    0 2 ,

    f ( )

    , ( , )

    , ( , )

    =

    0 0 2

    1

    20 2

    Sr

    =2

    2sin ;

    M S S f dr

    dr

    d[ ] ( ) ( ) sin sin= = = =

    +

    2

    0

    2 2

    02

    1

    2 42

    = =r r2 2

    2 0

    cos

    9.19. , R .

    : .. , , - (R,0). , , -

    OX.

    2

    2

    ,

    f ( ),

    ,

    ==

    +

    1 1

    0

    22 2 2

    2 2 2

    Y 1 4 P 0,6 0,4

    X 1 3 P 0,3 0,7

    Copyright & A K-C

  • m x y f x y dx dy x yR

    dx dy

    Rd d

    R

    Rd R

    D x y f x y dx dy m x yR

    dx dy

    RR

    d d

    ZD

    R

    Z ZD

    R

    = = + =

    = = =

    = = +

    =

    +

    +

    ( , ) ( , )

    .

    ( , ) ( , ) ( ) ( )

    2 22

    22

    2

    3

    0

    2

    00

    2

    2 2 2 22

    22

    3

    0

    1

    1 1

    3

    2

    3

    1

    4

    9

    1

    4

    9 2

    4

    9 182

    2 2 2

    0

    2

    RR R R

    = = .

    9.23. 2 X Y. X

    f x ex

    1

    2

    181

    3 2

    2

    ( ) .( )

    =

    Y (1;5). :

    M X Y M X Y M X Y M X M Y

    M X Y M X Y D X Y D X Y

    D X Y D X Y

    [ ], [ ], [ ], [ ], [ ],

    [ ], [ ], [ ], [ ],

    [ ], [ ].

    + + + +

    2 3 4

    2 3 3 2 1

    2 6

    2 2

    2 2

    : m Dx x= =2 9, . Y:

    m Dy y=+

    = =

    =1 5

    23

    5 1

    12

    4

    3

    2

    ,( )

    .

    ,

    .3

    295923

    3

    4223

    4922][ ====++++++++====++++++++==== xDymyDxmyDxDYXD

    9.24. X Y, Y X= +5 3. - X : m Dx x= =2 1, .

    : ) Y; ) X Y. :

    Copyright & A K-C

  • a M Y M X m

    D Y D X D X

    x) [ ] [ ]

    [ ] [ ] [ ]

    = + = + = + =

    = + = = =

    3 5 3 5 3 5 2 13

    3 5 5 25 1 252

    k M X Y M X M Y M X X

    m M X D X M X

    xy

    x

    ) [ ] [ ] [ ] [ ]

    [ ] ( [ ] [ ])

    ( ) .

    = = + =

    = + = + + == + =

    3 5 2 13

    3 5 26 6 5 26

    5 1 4 20 5

    2

    2 2

    9.25. X f x ex

    ( ) =1

    2

    2

    22

    .

    Y X X= +1 3 42 3 . :

    m Dx x= =02, .

    M X x f x dx X X[ ] ( ) ( ) , ( )3 3= =

    +

    M X x f x dx x e dxx

    [ ] ( )3 3 3 21

    20

    2

    2= = =

    +

    +

    ( )

    M Y M X X M M X M X

    D X M X M X

    [ ] [ ] [ ] [ ] [ ]

    ( [ ] [ ]) [ ] ( )

    .

    = + = + =

    = + + = + + =

    =

    1 3 4 1 3 4

    1 3 4 1 3 0 4 0

    1 3

    2 3 2 3

    2 3 2

    2

    9.26. X Y:

    X Y . M X Y[ ],3 2 4+ M X Y[ ], D X Y[ ].3 2 5 +

    : -

    f x

    xx

    xf y

    y y

    y1 28

    0 4

    0 0 4

    1

    18

    1

    30 6

    0 0 6( )

    , [ ; ]

    , [ ; ], ( )

    , [ ; ]

    , [ ; ]=

    =

    +

    .. X Y:

    m x f x dx xx

    dxx

    D x f x dx m xx

    dx

    x

    x x

    = = = =

    = = =

    +

    +

    1

    3

    0

    4

    21

    2 2

    0

    4

    8 24

    4

    0

    8

    3

    8

    64

    9

    ( )

    ( ) ( )

    = =x4

    32

    4

    0

    64

    9

    8

    9

    f x1 ( )

    1

    2

    x 4

    f y2 ( )

    13

    y 6

    Copyright & A K-C

  • m y f y dy y y dyy y

    D y f y dy m y y dy

    y y

    y

    y y

    = = +

    = +

    =

    =

    = = +

    =

    = +

    =

    +

    +

    2

    3 2

    0

    6

    22

    2 2

    0

    6

    4 3

    1

    18

    1

    3 54 6

    6

    0

    2

    1

    18

    1

    34

    72 9

    6

    0

    4 2

    ( )

    ( ) ( )

    M X Y m mx y[ ] .3 2 4 3 2 4 38

    32 2 4 8+ = + = + =

    M X Y m mX Y

    kx y xy[ ]

    ( = = = =

    8

    32

    16

    3 0)

    , -

    D X Y D Dx y[ ] ( ) .3 2 5 3 2 98

    94 2 162 2 + = + = + =

    172 9.27. , 2 3 , . -

    Y X X= +2 12 , X- , . :

    .. X. X 0 1 2 P 0,3 0,6 0,1

    P XC

    CP X

    C C

    CP X

    C

    C( ) , ; ( ) , ; ( ) ,= = = = =

    = = = =0 0 3 1 0 6 2 013

    2

    52

    21

    31

    52

    22

    52

    m x p

    D x p m

    M Y M X X M X M X D M X

    x k kk

    x k k xk

    X

    = = + + =

    = = + + =

    = + = + = +

    + = + + =

    =

    =

    0 0 3 1 0 6 2 01 0 8

    0 0 3 1 0 6 2 01 0 8 0 36

    2 1 2 1 2

    0 8 1 2 0 36 0 8 0 8 1 2

    1

    3

    2 2

    1

    32 2 2 2

    2 2 2

    2

    , , , ,

    ( ) , , , , ,

    [ ] [ ] [ ] [ ] ( [ ])

    , ( , , ) , ,2

    9.28. 3 . , 3

    n . Y X X= + 2 3 22 , X - .

    :

    A, P A C p q( ) = 32 2 1, p =

    1

    2, q =

    1

    2.

    P A p( ) =

    = =3

    1

    2

    1

    2

    3

    8

    2

    .. X- A n , A

    p . .. X.

    Copyright & A K-C

  • = + 27

    64

    93

    6422n n .

    9.29. (X,Y) :

    m m rx y x y xy= = = = =1 1 2 3 0 5, , , , , . Z X Y= ( )2 .

    Z.

    :

    M Z M X Y XY M X M Y M XY

    D X M X D Y M Y M X M Y

    rxy x y

    [ ] [ ] [ ] [ ] [ ]

    ( [ ] ( ]) ( [ ] [ ]) ( [ ] [ ]

    )

    = + = + =

    = + + + ++ =

    2 2 2 2

    2 2

    2 2

    2

    11

    , , k rxy xy x y= . 9.30. X Y [ ; ]01 ,

    . - .

    :

    R Y X= ,

    { }M R M Y X[ ] .= ( )X Y, XOY, - f x y( , ) = 1 1.

    y 1

    D 2

    D 1

    x 0 1 174

    D X Y Y X X Y1 : > = ; D X Y X Y X2 : Y > = .

    M R x y dxdy y x dxdy

    dx x y dy dy y x dx

    DD

    x y

    [ ] ( ) ( )

    ( ) ( ) .

    = + =

    = + =

    1 1

    1

    3

    21

    0

    1

    00

    1

    0

    M R M Y X M Y XY X

    M Y M X M Y M X D Y

    M Y M X M Y D X M X

    [ ] [ ] [ ]

    [ ] [ ] [ ] [ ] ( [ ]

    [ ]) [ ] [ ] ( [ ] [ ])

    2 2 2 2

    2 2

    2 2

    2

    2

    2

    1

    12

    1

    42

    1

    2

    1

    2

    1

    12

    1

    4

    1

    6

    = = + =

    + = +

    + + + =

    = +

    + +

    =

    R x 0 X Y 1

    Copyright & A K-C

  • M X M Ya b

    D X D Yb a

    [ ] [ ] , [ ] [ ]( )

    ( )

    = =+

    =+

    = = =

    =

    =

    =

    2

    0 1

    2

    1

    2 121 0

    121

    12

    2

    2

    9.31. (X,Y) ( ; )11 3 2

    2 4

    . Z X Y= +2 4 3.

    : Dx = 3 , D y = 4 , kxy = 2 , mx = 1, my = 1.

    D Z D X Y D X Y D X D Y

    kxy

    [ ] [ ] [ ] [ ] ( ) [ ]

    ( ) ( ) .

    = + = = + ++ = + =

    2 4 3 2 4 2 4

    2 2 4 4 3 16 4 16 2 108

    2 2

    9.32. 2 , 4. - 3. 3 . - .

    : m mx y= = 0 , D Dx y= = 4, kxy = 3. Z X1 3= , Z Y2 3= . k M Z Z M Z M Z M X Y M X M Y

    M X Y M X M Y M X Y M X M Y k

    Z Z

    xy

    1 2 1 2 1 29 3 3

    9 9 9 9

    9 3 27

    = = =

    = = = == =

    [ ] [ ] [ ] [ ] [ ] [ ]

    [ ] [ ] [ ] ( [ ] [ ] [ ])

    .D Z D X D X D Z[ ] [ ] [ ] [ ]1

    223 3 9 4 36= = = = =

    rk

    Z Z

    Z Z

    Z Z1 2

    1 2

    1 2

    27

    36 36

    27

    36

    3

    4=

    =

    = =

    .

    9.33. [1,2] (), -, [10,12] (). , - .

    : .. X - , X:

    ma b

    x =+

    =+

    =2

    1 2

    2

    3

    2.

    Db a

    x =

    =

    =( ) ( )2 2

    12

    2 1

    12

    1

    12.

    .. Y- , .. Y: my =+

    =10 12

    211.

    .. Z- Z X Y= 2 m M X Y M X M YZ = = =[ ] [ ] [ ]

    2 2

    X Y

    = + = +

    =( [ ] [ ]) [ ]D X M X M Y2

    1

    12

    9

    411

    77

    3.

    9.34. X Y: f xx

    x10 5 0 2

    0 0 2( )

    , , [ ; ]

    , [ ; ]=

    ;

    f ye y

    y

    y

    2

    0

    0 0( )

    ,

    ,=

    >

    ======== xe

    xtxFtm

    xx

    10.16. ( )X t

    f x x t t ex t x t

    2 1 2 1 22

    1

    2

    1 12

    2 22

    ( , , , )( sin ) ( sin )

    =

    + + +

    . , -

    .

    : m t t D t k t tt t

    t tx x x( ) sin , ( ) , ( , )

    ,

    ,= = =

    =

    1

    0

    11 21 2

    1 2

    .

    10.17. f x x t t ex t x t

    2 1 2 1 22

    12

    1 12

    2 22

    ( , , , )( ) ( )

    =

    . , .

    : m t t D t k t tt t

    t tx x x( ) , ( ) , ( , )

    ,

    ,= = =

    =

    1

    0

    11 21 2

    1 2

    .

    V 0 1 2 P 0,5 0,2 0,3

    Copyright & A K-C

  • 11 , .

    X(t), Y(t) Z(t) - , (t) , : 1. Z(t)=X(t)+Y(t) , M[Z(t)]=M[X(t)]+M[Y(t)]

    kz(t1,t2) = kxy(t1,t2) + kyx(t1,t2) + ky(t1,t2) + kx(t1,t2), kxy(t1,t2) -

    X(t) Y(t). ( ) ( ) ( )

    = 2121 tYtXMt,tk xy

    , kxy(t1,t2) = kyx(t2,t1), kz(t1,t2) = kx(t1,t2) + ky(t1,t2) + kxy(t1,t2) + kxy(t2,t1)

    X(t) Y(t) - , kz(t1,t2) = kx(t1,t2) + ky(t1,t2) 2. Y(t)= X(t)+(t) ( X(t) (t) ) , [Y(t)] =

    M[X(t)]+ (t), ky(t1,t2) = kx(t1,t2) 3. Z(t) = (t)X(t) ( X(t) (t) ) , [Z(t)] = (t)M[X(t)], kz(t1,t2) = (t1)(t2)kx(t1,t2)

    4. dt

    )t(dX)t(Y = ,

    dt

    )]t(X[dM)]t(Y[M = ,

    21

    2121

    ),(2),(

    tt

    ttkxttk y =

    5. =t

    0d)(X)t(Y ,

    =t

    0d)](X[M)]t(Y[M , = d),(kxd)t,t(k 2

    2t

    021

    1t

    0121y

    11.1 mx(t), Dx(t) kx (t1,t2) X(t) = Ucos2t U- M[U] = 5, D[U] = 6.

    : mx(t) = M[u cos2t] = cos2t M[u] = 5cos2t kx(t1,t2) = M[( X(t1) - mx(t1) ) ( X(t2) - mx(t2) )] = = M[(u cos2t1 5 cos2t1) (u cos2t2 - 5 cos2t2) = M[cos2t1 cos2t2(u 5)

    2] = =cos2t1cos2t2 M[(u 5)2]=cos2t1cos2t2

    M[(u mu)2] =cos2t1 cos2t2 Du = 6cos2t1 cos2t2

    Dx(t) = kx(t,t) = 6cos22t

    11.2 mx(t), Dx(t) kx(t1,t2) X(t) =U(3t+1)-5t+4 U - M[U]=3 , D[U]=2 : mx(t) = M[u(3t + 1) 5t +4] = (3t +1)M[u] 5t + 4 = (3t + 1) 3 5t + 4 = 4t + 7 kx(t1,t2) = M[(u (3t1 + 1) 5t1 + 4 4t1 7) (u(3t2 +1) 5t2 + 4 - 4t2 7)] = M[(u(3t1 + 1) - 3(3t1 + 1)) (u(3t2 +1) - 3(3t2 +1))]= M[(3t1 + 1)(3t2 +1)(u 3)

    2] = =(3t1 + 1) (3t2 +1) M[(u 3)2] = (3t1 + 1) (3t2 +1) M[(u mu)

    2] = = (3t1 + 1) (3t2 +1) Du = 2(3t1 + 1) (3t2 +1) Dx(t) = kx(t,t) = 2(3t + 1)

    2 11.3 X(t) =Vt , V- , [1;4]. mx(t), Dx(t) kx(t1,t2). X(t).

    : V

    2

    5

    2

    41

    2

    bamv =

    +=

    += ,

    4

    3

    12

    1)(4 2

    12

    a)(b 2Dv =

    =

    =

    [ ] [ ] [ ] t2

    5VMttVMX(t)M ===

    k x ( t 1 , t 2 ) = M [ ( X ( t 1 ) - mx ( t 1 ) ) ( X ( t 2 ) - mx ( t 2 ) ) ] =

    [ ]

    tkD

    tttt

    ttt

    VDVMttttVttVM

    xx2

    2121

    2

    212211

    4

    3),()(

    4

    3

    2

    5

    2

    5

    2

    5

    ==

    ==

    =

    =

    X(t) 1 1V = , 2 2V = , 3 4V = :

    t11

    X3(t)=4t

    X2(t)=2t

    X1(t)=t

    X(t)

    2

    4

    Copyright & A K-C

  • ( ) ( ) 4yy t25t,tktD ==

    11.4 X(t) ( ) ( ) 2121xx ttt,t k,4ttm =+= . ( ) ( ) ( )21 t,tyk tyD ,tym , 2tXt5tY )()( += . : X(t) : 5t 2.

    ( ) 220252452M[X(t)]5t]2X(t)[5t(t)y ++=++=+=+= ttttMm ,t25t)t,(tk5t5t)t,(tk 22

    2121x2121y ==

    11.5 X(t) 4tt

    21x2

    x

    22

    21

    e)t,(tk 5t,t(t)m+

    =+= .

    8.X(t)t

    3Y(t)

    2=

    :

    5t

    1585t)(t

    38(t)m

    38X(t)

    3M(t) 2

    2x22y=+==

    =ttt

    m

    ( )

    ( ) 2t

    4yy

    4

    tt

    2221x2221y

    2

    22

    21

    2111

    et

    9t,tk(t)D

    ett

    9t,tk

    t

    3

    t

    3)t,(tk

    +

    ==

    ==

    11.6 Z(t) -

    X(t) Y(t) :

    .ett)t,(tk

    ,tt)t,(tk t,(t)m t,(t)m)t(t

    2121y

    2121xyx

    21+=

    ===

    : Z(t)=X(t)+Y(t), ( ) ( ) ( ) 0tttmtmtm yxz ==+=

    ( )[ ]21 tt212,1y2,1x2,1z e1tt)tt(k)tt(k)tt(k ++=+= 11.7 2 X(t) Y(t) : ,t(t)m 2x =

    )(2,1

    tte)tt(k 211

    = , ,1)t(my =

    2122 )(

    2,1ytte)tt(k

    =

    , X(t),Y(t) -

    tte)tt(k 122,1xy=

    : 0)t,t(k 21xy = , tt2t)t(mt)t(m)t(m 22yxz +=++=

    ( ) ( ) ,,

    )()()(

    1221

    2)12(221

    )21(12,1212,12,1

    tmettk

    e

    ztt

    xy

    yxztttt ttettkttttkttk

    +

    =

    +=+=

    tte)tt(ttetttte)t,t(kt

    )t,t(kt)t,t(ktt)t,t(k)t,t(k

    122

    12221121

    )(21

    )(12xy1

    21xy221y2121x21z

    + +++=+

    +++=

    11.8

    tt3)t(m 2x += , )).tt(21(e4)t,t(k 21)tt(221x 21 += - . :

    ( ) ( ) ( ) 2ttYttXtZ ++=

    Copyright & A K-C

  • [ ] [ ] ( )

    )1t2t2(tte16t

    )t,t(k

    t)t,t(k

    )tt(tte16t

    )t,t(k

    tt

    )t,t(kt,tk ;1t6)tt3(dt

    )t(XdM)t(YM ;

    dt

    )t(dX)t(Y

    21)(2

    1

    21x

    221y

    21)(2

    1

    21x

    21

    21x2

    21y2

    21

    21

    =

    =

    =

    =+=+===

    11.9 , dt

    )t(dX)t(Y = X(t)

    tsin2)t(mx = 2

    12 )tt(521x e3)t,t(k = .

    . :

    )2)12(101()(530

    1

    )2,1(

    2)2,1(

    )12()(530

    1

    )2,1(21

    )2,1(2

    )2,1(

    cos2)sin2())(()(

    212

    212

    ttet

    ttk xt

    ttk y

    ttet

    ttk x

    tt

    ttk xttk y

    tttmxtmy

    tt

    tt

    ====

    ====

    ====

    ====

    ============

    11.10 X(t) 2

    21 )tt(21x

    2x e2)t,t(k ,1t)t(m == .

    .)t1(dt

    )t(dXt2)t(Z ,1t)t(Xt)t(Y 22 +=++=

    : 195

    [ ] [ ]

    )))(21(16),(

    4),(

    )(4),(

    ),(22),(

    125)1(4)1()1(2)1())((2)(

    2),(),(

    11)1(1)(1)()(

    221

    2)21(21

    2

    21

    22121

    21

    2)21(

    1

    21

    21

    212

    2121

    222222

    2)21(21212121

    232222

    ttttt

    ttkt

    ttttk

    ttt

    ttktt

    ttkttttk

    mm

    ttttkttttk

    m

    tte

    tte

    ttttttttttt

    tte

    ttttttttXtMttXtMt

    xz

    x

    xz

    xz

    xy

    y

    =

    =

    =

    =

    +=+=+=+=

    ==

    ++=++=++=++=

    11.11 X(t) 5t4)t(mx += 2121x tcostcos)t,t(k = . . :

    ( ) ( )

    ( ) tsint,tk)t(Dtsintsindt cost dcosd)t ,(kt d)t,t(k

    t5t2d)54(dmtm;d)(X)t(Y

    2yy

    2120 20 120 21x0 121y

    t0

    2t0 xy

    t0

    2121

    ==

    = = =

    +=+ == =

    11.12

    ( ) ( ) +=t

    tdXt

    tY0

    2

    3

    2 . X(t)

    .ett)t,t(k ,e2)t(m 21 tt2121xtx +== . :

    ( ) ( ) ( ) +=+=+= t0

    t

    0

    2t22xy t1e

    t3

    4tde2

    t3

    2tdm

    t3

    2tm

    ( ) = = + 2t

    0

    t

    0211

    2121y ded

    t3

    2

    t3

    2t,tk 21

    1 2

    Copyright & A K-C

  • ( )( )( ) ( )2tt

    2yy

    tt2

    tt1

    21

    1etet9

    4t,tk)t(D

    1eet1eettt9

    42211

    +==

    ++=

    11.13 X(t) c

    ( ) 2121x2x tt5t,tk 3t)t(m =+=

    ( ) 3t

    0tdX)t(Y + =

    Y(t): )t(my )t,t(k 21y

    : Z(t)=t X(t),

    11.14 t2cosVe)t(X t3 = , V- , M[V]=5, D[V]=1. -

    , X(t) =t

    0d)(X)t(Y .

    : X(t)

    [ ] [ ][ ]

    [ ] [ ]

    ==

    =

    ===

    ==

    ===

    +

    ++

    d2cose5d)(m)t(m

    t2cost2costte

    VDt2cost2costte)5V(Mt2cost2costte

    )t2coste5t2costVe)(t2coste5t2costVe(M)t,t(k

    t2cose5VtM2coset2cosVeM)t(m

    3t

    0

    t

    0xy

    21)(3

    21)(32

    2133

    23

    23

    13

    13

    21x

    t3t3t3x

    21

    2121

    2211

    ,

    3tt2sinU)t(X += , U- , M[U]=2, D[U]=4

    : ( ) 3tt2sin2tmx += ; )t,t(k 21x =4 ,t2sint2sin 21 =)t(Dx t2sin4 2

    11.16 X(t): 2

    12 )tt(21x

    2x e2)t,t(k ,1t2t3)t(m =++= .

    3)(2

    1)(,1

    )()( 2 ++++====++++++++==== ttX

    ttZt

    dt

    tdXttY

    : ( ) ,2t2

    1t

    2

    5tmz +=

    212 )(

    2121z

    ttett2

    1)t,t(k

    =

    11.17 X(t) 22

    21 tt21x

    3x e)t,t(k ,t3t)t(m =+= .

    22 t3dt

    )t(dXt)t(Y = .

    ( ) ( ) ( )( ) ( )

    ( ) ( ) tdZtYtt5t,tkttt,tk

    t3t3tttm ttm

    3t

    0

    2221x2121z

    32xz

    21

    + =

    ==

    +=+==

    ( ) ( ) ( )

    ( ) ( ) 33222

    0

    21

    01221

    2

    0

    1

    0121

    324

    3

    0

    33

    0

    2121 9

    5 5,,

    2

    3

    43

    ttdddkdttk

    ttt

    tdtdmtm

    ttt

    z

    t

    y

    tt

    zy

    ===

    ++=++=+=

    ( )

    ( ) ( ) ( )13

    152cos32sin2

    13

    53cos32sin2

    13

    5

    2cos32sin213

    2cos

    30

    3

    33

    +=+=

    ++=

    tteetm

    ctte

    tdte

    tty

    tt

    Copyright & A K-C

  • ( ) ( ) 2121xx tcostcos9t,tk ,tcos2tm: ==

    : ,3)( 4ttmy =2

    22

    1 ttett4)t,t(k 323

    121y=

    11.18 , =t

    0d)(X)t(Y , X(t) -

    , X(t) c 198

    2121x tcostcos4)t,t(k =

    tsin1)t(m 2x += . .

    : ,t2sin4

    1t

    3

    2)t(my

    = tsintsin4

    )t,t(k 21221y =

    11.19 X(t): 22212121xx t2ttt)t,t(k,3)t(m ++==

    H +=t

    01t3d)(X)3t()t(Y

    : ,1t6t3)t(m 2y =

    ( )( )

    ++= 3122232121y 2211 tt32

    tt4

    1tt

    3

    13t3t)t,t(k

    11.20 X(t) X(t)=Vcost, V- - mv=2, v=3. X(t): )t(mx , )t,t(k 21x , xD t( ) . -

    Y(t)=X(t)+dt

    )t(dX , -

    Copyright & A K-C

  • 12 C , .

    ( , ) X(t) - , , , ..

    ),(k)t,t(k,const)t(m x21xx == tt 12 = , ))(k)(k( xx =

    const)0(k)t,t(kD xxx === X(t) , )(Sx , ),( + - ( ) , --:

    ( ) ( ) ==++

    dcosk2

    )(S ;dcosS)(k0

    xx0

    xx

    )(Sx , - , , ))(S)(S( xx = -

    ( ) ( )

    ( ) )(S2

    1)(S ,d ek

    2

    1)(S

    d eSd eS2

    1)(k

    xx i

    xx

    ix

    ixx

    ==

    = =

    +

    +

    +

    )(Sx , )(Sx - , , )(Sx (0; ).

    ( ) ( ) ===+

    +d S

    2

    1d S)0(kD x

    0xxx

    )(x )0(k)(k

    D

    )(k)(x

    x

    x

    xx

    ==

    -

    ( ) ( )

    xx

    x SS

    S max2

    d )(max

    1 2x== +

    = =++

    d)(k 2

    d)(20

    x2x0

    x

    1)0(x = ,

    )(x , );;( + -

    )(Smax x

    , )(Sx ,

    );( +

    12.1 X(t) 1t2)t(mx += .e)t,t(k2

    12 )tt(21x

    =

    12.2 dt

    )t(dX)t(Y = ?

    :

    ttkxtte

    ttet

    etttt

    ttkxttky

    constttmxtmy

    tt

    tttt

    12),()2)12(21(

    )(2

    )12)(2())((

    2))((

    1221

    )2,1(2

    )2,1(

    2)12())(()(

    212

    212

    212

    ============

    ====

    ++++====

    ====

    ====

    ====++++========

    Y(t)- 12.2 X(t)

    Copyright & A K-C

  • .e)t,t(k,1)t(m )tt(21xx 21== X(t) Y(t),

    Y(t)=t 1dt

    )t(dX + ?

    : X(t) -

    ( ) )(kttett)(ttetttttetttdt

    )tt(ktt)tt(k

    111t1))t(m(t1dt

    )t(dXtM)t(m

    y)(

    212)(

    21)(

    2121

    2,1x2

    212,1y

    xy

    21212

    21 ==

    =

    =

    =+=+=

    +=

    Y(t) , .. )t,t(k 21y

    = 2 1t t , t1 t2 12.3 X(t)

    ,0)t(mx = 221

    21x)tt(1

    1)t,t(k

    += =

    t

    0.d)(X)t(Y

    X(t),Y(t)? : X(t)- ,

    Y(t) , ,

    ,arctgtt2)t1(n)t,t(kD 2yy ++== l .. t 12.4 X(t)=A cos (t+ ) , A - , - , [0;2]. , X(t) - :.. [0;2] ,

    f( )= [ ]

    [ ]

    2;0;0

    2;0;2

    1

    , Y=cos Z=sin

    M[Y]=M[cos ]= ( ) +

    Y f ( )d = 0sin

    2

    1d

    2

    1cos

    2

    0

    2

    0=

    =

    M[Z]=M[sin ]= ( ) +

    Z ( )d = 0cos

    2

    1d

    2

    1sin

    2

    0

    2

    0=

    =

    += tcos(A[M)t(mx )]= costcosA[M -A

    sin t sin ]= =AcostM[cos ]-AsintM[sin ]= 0 0 =0 Y=cos2 Z=sin2

    ( ) ( )

    ( )( )

    ( )

    ( )( ) ( )

    ( ) ( ) ( )( )( )

    1122

    212

    22

    1221

    11

    21

    1

    11

    212

    112

    1

    1

    0112

    2

    01

    1

    0

    20122

    21

    21

    0121

    0

    1

    11

    2

    1

    V ;

    1 ;

    ;

    ;

    1 );(

    1,

    0

    211

    arctgttarctgtt

    tt

    ttnttarctgtt

    ddV

    dduarctgu

    VddV

    t

    dduttarctgu

    darctgtarctg

    darctgd

    dttk

    dmtm

    t

    t tt

    t

    y

    t

    xy

    ++

    ++

    ++=

    ==+

    ==

    ==+

    ===+=

    ==+

    =

    ==

    l

    Copyright & A K-C

  • M[Y]=M[cos2 ]= ( ) +

    Y f( )d = 0d

    2

    12cos

    2

    0=

    [ ] [ ] ( ) ( ) 0d2

    12sind f Z2sinMZM

    2

    0=

    = ==

    +

    ( ) =+++=++= )tt(cos)2)tt(cos(2

    A)tcos(A)tcos(A)t(X)t(X 2121

    2

    2121

    ( )[ ]

    [ ]

    [ ]

    2

    A)tt(k)t(D

    )tt(cos2

    A)tt(cos00

    2

    A

    )]tt(cos2sinM)tt(sin]2[cosM)tt([cos2

    A

    )]tt(cos2sin)tt(sin2cos)tt([cosM2

    A

    )]t(X)t(X[(M))t(m)t(X))(t(m)t(X(M)t,t(k

    )tt(cos2sin)tt(sin2cos)tt(cos2

    A

    2

    ,xx

    21

    2

    21

    2

    212121

    2

    212121

    2

    212x21x121x

    212121

    2

    ==

    =+

    =+++=

    =+++=

    ===

    +++=

    12.5 X(t) )1(e4

    b)(k 2x +

    = (b>0,

    >0).

    dt

    )t(dX)t(Y = .

    : ,

    =

    =

    =

    =

    ==

    =

    2

    x

    1

    2

    x

    121

    x2

    21

    21x2

    21yy

    2

    x2

    y

    td

    )(dk

    t

    t

    )(k

    ttt

    )(k

    tt

    )t,t(k)t,t(k)(k

    d

    )(kd)(k

    ,1t

    )tt(

    t 1

    t

    )tt(

    t 1

    12

    12

    12

    2

    =

    =

    =

    =

    2x

    2

    12x

    2x

    1y

    d

    )(kd

    td

    )(kd

    d

    )(kd

    t)(k

    =

    =

    =

    >+=

    0),1(e4

    b

    0),1(e4

    b

    )(k

    2

    2

    x

    )1(e4

    b

    0),1(e4

    b

    0),1(e4

    b

    ))(k()(k xy =

    +

    >==

    4

    b)0(k)t(D yy ==

    ( )( )( )( )

    ( )( )

    =

    >=++=

    0,e4

    b1e

    4

    b

    0,e4

    b1e

    4

    b

    k

    2

    2

    x

    ( )( )( ) ( )

    ( ) ( )

    =+

    >+=

    =

    0, 1e4

    b1e

    4

    b

    0, 1e4

    b1e

    4

    b

    k x

    Copyright & A K-C

  • ( )

    >

  • 12.10 -

    >

  • ( ) ( ) ( )( )

    ( ) ( ) ( ) ( )

    ( ) ( ) )(S)(S)(S2

    1)(S)(S

    2

    1

    d cosk2

    d cosk2

    2

    1

    dcoscos2

    1k

    2

    0x0x0x0x0x

    00

    x00

    x

    000

    x

    =+=++=

    =

    ++

    =

    =++=

    ++

    +

    .. )(Sx )(S)(S 0x0x =+ 12.13. )(Sx ,

    >

    =

    1 ,0

    1 ),1()(k

    2

    x

    :

    ( ) ( ) ( )

    =

    +=

    ==

    ===

    ====

    +

    1

    0

    10

    2

    1

    0

    21

    0

    2

    0

    sin1

    sin1

    )1(2

    sin1

    V d cosdV

    -du 1

    d cos12

    d cos12

    d cos2

    )(

    du

    kxxS

    ( )2

    22

    2

    2102

    2

    2

    sin4cos1

    2cos

    2

    ===

    12.14 )(Sx , 22)( = ekx

    :

    ( ) === +

    +

    deedek iixxS22*

    2

    1

    2

    1)( ( ) ( ) =

    +=

    ++

    dede2

    a

    0

    i20

    i22

    ( ) ( )

    22

    2

    22

    2

    2

    0

    i20i22

    4

    a2

    4

    4

    2

    a

    i2

    1

    i2

    1

    2

    ae

    i2

    1e

    i2

    1

    2

    a

    +=

    +

    =

    =

    ++

    =

    +

    =

    ++

    12.15 , -

    = eD)(k xx )0( >

    : ( ) ( ) ( ) ( ) =

    +

    =

    +=

    ==

    =

    ++

    +

    ++

    +

    +

    0

    i0ix

    0

    i0

    ix

    ix

    ix

    *x

    ei

    1e

    i

    1

    2

    Ddede

    2

    D

    eeD2

    1de)(k

    2

    1)(S

    )(

    D

    i

    1

    i

    1

    2

    D22

    xx

    +=

    ++

    =

    .)(

    D2)(S2)(S

    22

    x*xx

    +==

    =

    +==

    = D2

    )0(D2

    )0(S

    D2

    )(Smax

    D2

    x

    2x

    x

    x

    x

    x

    ( )

    =

    = == =+

    +

    + + 2e2

    de2deDD

    2d k

    D

    2000

    xx0

    xx

    .2=

    Copyright & A K-C

  • 12.16. X(t) 5)t(mx =

    )1(

    8)(S 2

    *x +

    = X(t)

    :

    , = eD)(k xx

    )(

    D)(S 22x*

    x +=

    , 1 ,8D 2x ==

    8D 1, x == = e8)(kx 12.17 , -

    , 0 ,0b,)(

    b)(S 22x >>+

    =

    :

    )(2

    b)(S

    2

    1)(S 22x

    *x +

    ==

    ;2

    bD , ;

    2

    bD x

    22x ==

    = = e2

    b)(k x

    ( )

    =

    =

    == =

    =

    ==

    =

    +++

    2

    2e

    2de

    2

    b

    b

    4d k

    D

    2

    b

    b

    )0(S

    b

    )(SmaxD2

    000x

    x

    2

    xx

    x

    12.18. )(Sx X(t) ,

    = coseDk xx :

    ( )

    ( ) =+=

    ===

    +

    +

    +

    deeee

    deeDdek

    iiix

    ix

    ixx

    D

    S

    2

    1

    2

    cos2

    1

    2

    1)(*

    ( )

    ( ) ( )

    ( ) ( ) ( )

    ( ) ( ) ( ) ( )

    =

    ++

    ++

    =

    =

    +++

    +

    ++

    +=

    =

    +++

    +=

    ++

    ++=

    +

    ++

    ++

    2222x

    x

    0

    ii

    0

    ii0

    ii

    0iixiii

    0

    iii0

    x

    )(

    2

    )(

    2

    4D

    i

    1

    i

    1

    i

    1

    i

    1

    4D

    dedede

    de4

    Ddeeee

    deeee4D

    ))()()((

    )(D2222

    222x

    +++++=

    Copyright & A K-C

  • )(S*x )(S*x

    -2 2 = = =2, =1 =2, =3 )(S*x 12.19. X(t) 8)t(mx =

    42

    2*x

    625

    520)(S

    +++

    =

    X(t) : ,

    = coseD)(k xx :

    4222222

    222x

    2222

    222x*

    x

    )(2)(D

    ))()()((D)(S

    +++++

    =

    =+++

    ++

    =

    4222222432223

    222222222222

    222222

    22222

    )(2)(2)(2

    42)()()2)(()(

    )2))((2)((

    ))()()((

    +++=++++

    ++++++++=

    =+++++=

    =+++

    3

    20D

    5

    22

    x

    22

    =

    ==+

    =

    =+

    3

    522

    22

    2

    82 2

    ==

    =D

    x20 , 0> , .. = 2

    = 1 , Dx

    =20

    10

    =

    , ( ) = cose10k 2x

    12.20. )(Sx X(t),

    )sin(cose)(k 2x += ( )0, >

    : (((( )))) (((( ))))++++

    ++++

    ====

    ++++========

    dieediekxSx sincos

    22

    1

    2

    1*

    Copyright & A K-C

  • (((( )))) (((( )))) (((( ))))

    ++++

    ++++

    ++++====

    ====

    ++++++++++++

    ++++

    ++++

    ++++

    ====

    diiei

    diiediie

    dieieiei

    ieiee

    dieieieieiee

    000

    4

    20 2

    )(2

    1

    22

    1(

    0

    2

    2

    (((( )))) (((( )))) (((( ))))

    (((( )))) (((( )))) ====

    ++++

    ++++++++++++

    ++++++++

    ++++

    ++++++++

    ++++

    ++++

    dei

    dei

    dededei

    iiii

    iiiiii

    00

    00

    0

    ( )( )

    =

    +

    +

    ++++

    +++

    +=

    =

    ++

    +

    +++

    +

    ++

    ++

    ++

    +=

    ))((

    )(2

    ))((

    )(2

    )(

    2

    )(

    2

    4

    ))(())(()(

    1

    )(

    1

    ))(()(

    1

    )(

    1

    4

    22222222

    2

    2

    i

    i

    i

    i

    iiiiii

    iiiiii

    +

    ++

    +

    =

    =

    +

    +++

    ++

    +++

    +=

    2222

    2

    22222222

    2

    )(

    2

    )(

    2

    2

    ))(())(()(

    1

    )(

    1

    2

    12.21. ,

    X(t) )0(eD)(k22

    xx >= :

    ( = +

    2due 2u2

    )

    , 22

    4x*x e

    2

    D)(S

    = , 2

    2

    4x*xx e

    D)(S2)(S

    ==

    )(Sx

    (((( )))) (((( ))))

    ====

    ====

    ====++++====

    ++++

    ====

    ++++

    ++++

    ====

    ====++++

    ++++

    ++++++++

    ====++++

    ++++

    ====

    ====++++

    ====

    ++++

    ====

    2

    2222

    422

    4422

    2

    1

    2

    1

    2

    22

    22

    2

    22

    4

    22

    222

    222

    22

    dud

    uiu

    i

    de

    i

    exD

    d

    iii

    exD

    d

    i

    exD

    diexDdiexkxS

    22

    24

    2

    24

    2

    2

    2

    4

    2

    22

    2222

    +

    === eD

    eDdu

    eeD xx

    ux

    Copyright & A K-C

  • =

    24x

    x4

    2eD))(S(

    2

    2

    , =0 ))(S( x

    + - =0 - max., 0

    ( ) ( ) ==

    =

    = 2

    D

    D2

    Smax

    2D ;

    D0S

    x

    x

    x

    xxx

    ( )

    ===

    ==

    =====

    +

    ++

    2

    22

    22

    2

    dud

    2

    u 2

    22

    0

    2

    2

    22

    00

    due

    u

    deDD

    dkD

    u

    xx

    xx

    Copyright & A K-C