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contoh soal
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Adnan Kusuma Putra
1306369415
Mekanika Tanah
Hitung P yang bekerja pada dinding penahan berikut ini:
w = 10 kN/m2
2 eff = 19.2 10 = 9.2 kN/m2
3 eff = 20 10 = 10 kN/m2
Soil Type K0 = 1 - sin Ka = tan2(45 - -
) Kp = 1/Ka
Clay 0.66 0.49 2.04
Sand 1 0.43 0.27 3.69
Sand 2 0.4 0.25 4
1.2 m
3 m
3 m
= 19.2 kN/m2
2 = 35o , c2 = 0
1 = 16.5 kN/m2
1 = 20o , c1 = 20 kN/m2
3 = 20 kN/m2
3 = 37o , c3 = 0 kN/m2
Tekanan Vertikal (Effective active lateral pressure) v = .h Soil Type Kedalaman (m) Tekanan (kN/m2)
Clay 0 0
1.2 16.5 x 1.2 = 19.8
Sand 1 1.2 19.8 + 0 = 19.8
4.2 19.8 + (9.2 x 3) = 47.4
Sand 2 4.2 47.4 + 0 = 47.4
7.2 47.4 + (10 x 3) = 77.4
Tekanan Horizontal h-o = vKo Soil Type Kedalaman (m) Tekanan (kN/m2) Clay 0 0
1.2 19.8 x 0.66 = 13.07
Sand 1 1.2 19.8 x 0.43 = 8.51
4.2 47.4 x 0.43 = 20.38
Sand 2 4.2 47.4 x 0.4 = 18.96
7.2 77.4 x 0.4 = 30.96
Tekanan Aktif h-a = vKa 2c Soil Type Kedalaman (m) Tekanan (kN/m2) Clay 0 0 2x20 = -28
1.2 19.8x0.49 2x20 = -18.3
Sand 1 1.2 19.8 x 0.27 = 5.35
4.2 47.4 x 0.27 = 12.8
Sand 2 4.2 47.4 x 0.25 = 11.85
7.2 77.4 x 0.25 = 19.35
Tekanan Pasif h-p = vKp + 2c Soil Type Kedalaman (m) Tekanan (kN/m2) Clay 0 0 + 2x20 = 57.13
1.2 19.8x2.04 + 2x20 = 97.52
Sand 1 1.2 19.8 x 3.69 = 73.06
4.2 47.4 x 3.69 = 174.91
Sand 2 4.2 47.4 x 4 = 189.6
7.2 77.4 x 4 = 309.6
Tekanan Hidrostatik u Soil Type Kedalaman (m) Tekanan (kN/m2) Clay 0 0
1.2 0
Sand 1 1.2 0
4.2 10 x 3 = 30
Sand 2 4.2 10 x 3 = 30
7.2 10 x 6 = 60
1.2 1.2 1.2
1.2 1.2 1.2
1.2 1.2 1.2
4.2 4.2 4.2
4.2 4.2 4.2
4.2 4.2 4.2
7.2 7.2 7.2
7.2 7.2 7.2
7.2 7.2 7.2
19.8
47.4
77.4 30.96
20.38
13.07
18.96
8.57
30
60
30
60
30
60
5.35
42.8
79.35
41.85
-18.3
-28
5.35
12.8
19.35
-28
57.13
1.2 73.06
189.6 174.91
309.6
-18.3
11.85
57.13
97.52 95.06
204.91
219.6
369.6
Diagram:
Nilai P = Luas total diagram
Pa = -1/2 (28+18.3)(1.2) + 1/2 (5.35+42.8)(3) + 1/2 (41.85+79.35)(3) = 226.25 kN/m
Pp = 1/2 (57.1+97.52)(1.2) + 1/2 (73.06+204.91)(3) + 1/2 (219.6+369.6)(3) = 1393.55 kN/m