assignemt XSTK

8/6/2019 assignemt XSTK

1/13

Trng i hc Bch Khoa TPHCM--- ---

BI TP LN XC XUT THNG K

Tn :Phm Thanh TngMSSV :50802688Lp :MT08KH05 Tit 1-3 ,th 2

Nhm : 7

TPHCM Ngay 30 thang 05 nm 2011

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2/13

Bi 1 : Mt cuc iu tra x hi hc c tin hnh 5 thnh ph A, B, C, D, Eyu cu nhng ngi c hi din t mc tha mn ca mnh i vi thnh

ph m h ang sng. Kt qu nh sau :

Thnh ph Mc tha mnRt tha mn Tng i KhngA 220 121 63B 130 207 75C 84 54 24D 156 95 43E 122 164 73

Vi mc ngha =5%, kim nh xem mc tha mn cuc sng c phn bging nhau trong 5 thnh ph trn hay khng ?

Dng bi :

- So snh cc phn s

Li gii :

D liu trong Excel :

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3/13

Tnh cc tng s : Tng hng :Chn E3 v nhp biu thc = SUM(B3:D3). Dng con tr

ko nt t in t E3 n E7. Tng ct: Chn B8 v nhp biu thc = SUM(B3:B7). Dng con tr

ko nt t in t B8 n D8 . Tng cng :Chn E8 v nhp biu thc = SUM(E3:E7).

Tnh cc tn s l thuyt :Tn s l thuyt = ( tng hng * tng ct ) / tng cng- Trng thi rt tha mn ca TP A: Chn B10 v nhp biu thc = E3*B8/E8.

- Trng thi tng i ca TP A: Chn C10 v nhp biu thc = E3*C8/E8.

- Trng thi khng ca TP A: Chn D10 v nhp biu thc = E3*D8/E8.

- Trng thi rt tha mn ca TP B: Chn B11 v nhp biu thc = E4*B8/E8.

- Trng thi tng i ca TP B: Chn C11 v nhp biu thc = E4*C8/E8.

- Trng thi khng ca TP B: Chn D11 v nhp biu thc = E4*D8/E8.

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4/13

- Trng thi rt tha mn ca TP C: Chn B12 v nhp biu thc = E5*B8/E8.

- Trng thi tng i ca TP C: Chn C12 v nhp biu thc = E5*C8/E8.

- Trng thi khng ca TP C: Chn D12 v nhp biu thc = E5*D8/E8.

- Trng thi rt tha mn ca TP D: Chn B13 v nhp biu thc = E6*B8/E8.

- Trng thi tng i ca TP D: Chn C13 v nhp biu thc = E6*C8/E8.

- Trng thi khng ca TP D: Chn D13 v nhp biu thc = E6*D8/E8.

- Trng thi rt tha mn ca TP E: Chn B14 v nhp biu thc = E7*B8/E8.

- Trng thi tng i ca TP E: Chn C14 v nhp biu thc = E7*C8/E8.

- Trng thi khng ca TP E: Chn D14 v nhp biu thc = E7*D8/E8.

p dng hm s CHITEST trong Excel :Tnh xc xut P(X > x2) bng cch chn B15 v nhp biu thc nh sau:

=CHITEST(B3:D7,B10:D14)Kt qu : P(X > x2) = 3.5299E-13 < =0.05 bc b gi thit H0Vy mc tha mn cuc sng c phn b Khc nhau trong 5 thnh ph trn

Bi 2 : mt bnh vin ln, s ca cp cu trong 5 ngy chn ngu nhin c ghi

li nh sau:Bui sng 44 53 56 49 38Bui chiu 33 42 15 30 45

Bui ti 39 24 30 27 30Vi mc ngha 5%, c th cho rng s ca cp cu trung bnh trong 3 buisng, chiu, ti l nh nhau c khng?

Dng bi :- Phn tch phng sai mt nhn t

Li gii :

Nhp d liu vo Excel :

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5/13

A B C D E F1 Ngy2 Bui 1 2 3 4 53 Bui sng 44 53 56 49 38

4 Bui chiu 33 42 15 30 455 Bui ti 39 24 30 27 30

Dng phn mm Anova: Single Factor:a. Nhp ln lt n lnh Tools v lnh Data Analysis.(i vi office 2003,

cn i vi office 2007 th Nhp ln lt n lnh Data v lnh DataAnalysis )

b. Chn chng trnh Anova: Single Factor trong hp thoi Data Analysis rinhp nt OK .

c. Trong hp thoi Anova: Single Factor ln lt n nh :

Phm vi u vo (Input Rangle) .

Cch sp xp theo hng hay ct (Group By) .

Nhn d liu (Label in First / Column).

Ngng tin cy (Alpha) .

Chn u ra (Output Option) .

Hnh nh cch lm nh sau (trong office 2007) :

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6/13

Kt qu trong Excel :

Anova: SingleFactorSUMMARYGroups Count Sum Average VarianceBui sng 5 240 48 51.5Bui chiu 5 165 33 139.5Bui ti 5 150 30 31.5

ANOVASource ofVariation SS df MS F P-value F crit

Between Groups 930 2 4656.26966292

10.01367450

8 3.885293

Within Groups 890 1274.1666666

7

Total 1820 14

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7/13

Bin lun :F = 6.269 > F0.05 = 3.885 bc b gi thit H0 .

Vy s ca cp cu trung bnh trong 3 bui sng, chiu, ti l khc nhau.Bi 3 :Mt nghin cu c tin hnh M xc nh mi quan h gia chiu caoca mt ngi v c giy ca h. Nh nghin cu thu c s liu sau:

X 66 63

67

71

62

Y 9 7 8 10

6

X 66 63 67 71 62Y 6 8 5 12 5Trong X l chiu cao (n v inches) cn Y l c giy. Tnh t s tng

quan h s tng quan v h s xc nh ca Y i vi X. Vi mc ngha = 5%,c kt lun g v mi tng quan gia X, Y( phi tuyn hay tuyn tnh) ? Tm nghi quy ca Y i vi X. Tnh sai s tiu chun ca ng hi quy.

Dng bi :

- Xc nh mi tng quan gia X, Y.

- Tm ng hi quy v sai s tiu chun.

Li gii :

xy

62 63 66 67 71

6 7 9 8 105 8 6 5 12

in 2 2 2 2 2 n = 10

iT11 15 15 13 22 T=76

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8/13

x =2.62+2.63+2.66+2.67+2.71 = 658

y = =76

2x = 66

2+632+672+712+622+662+632+672+712+622 = 43398

2

y =92 + 72 + 82 + 102 + 62 + 62 + 82 + 52 + 122 + 52 = 624

xy = 5050

H s tng quan r (1) :

r = 2 2 2 2( ) ( )( )

( ) ( )

n xy x y

n x x n y y

r=0.7166

H s xc nh :

r2 =0.5135

Tng bnh phng chung SST =2

2

ij

Ty

n

SST=46,4

Tng bnh phng do nhn t SSF =

2 2

1

ki

i i

T T

n n=

SSF=34,4

T s tng quan :$

/Y Xn = SSF/SST

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9/13

=0.7414 Vi = 5%, ta dng test thng k sau :

( ) ( )( ) ( )

$ 2

$1 2

r n kF

k

=

F=1.4687

Tra bng phn phi Fisher vi bc t do (3,5) ta c c=5.14.

F sY.X = 1.6798

sY.X chnh l sai s tiu chun ca ng hi quy

9

2 2

( ) ( ) (

( ) ( )

N xy x

N x x

y a x

N

2 ( )

2

y a x y

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10/13

Bi 4 :Hy phn tch vai tr ngnh ngh (chnh, ph) trong hot ng kinh t cacc h gia nh vng nng thn trn c s bng s liu v thu nhp trung bnh

ca mt h tng ng vi cc ngnh ngh ni trn nh sau (mc ngha 5%) :

Ngh chnh Ngh ph(1) (2) (3) (4)

Trng la(1) 3.5 7.4 8.0 3.5Trng cy n qu(2) 5.6 4.1 6.1 9.6Chn nui(3) 4.1 2.5 1.8 2.1Dch v(4) 7.2 3.2 2.2 1.5

Dng bi :

- Phn tch phng sai hai nhn t (khng lp)

Li gii :

S dng phn mm excel gii:

Nhp bng gi tr: nh hnh v

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11/13

a. To bng anova:

- Nhp ln lt n lnh Data v lnh Data Analysis (i vi Office 2007, cni vi Office 2003 th Nhp ln lt n lnh Tools v lnh Data Analysis).

- Chn chng trnh Anova: Two-Factor Without Replication trong hp thoiData Analysis ri nhp nt OK .

- Trong hp thoi Anova: Two-Factor Without Replication ln lt n nh ccchi tit:

Phm vi u vo (Input Rangle).

Nhn d liu (Labels in First Row / Column).

Ngng tin cy (Alpha).

Chn u ra (Output Option)in thng tin mong mun hoc checknewWorksheet Ply.

Nhp OK.

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12/13

b. Bng inova sau khi hon thnh

Kt qu v bin lun :

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13/13

F(rows) = 1,99661 chp nhn gi thit H0 (cc nghchnh to ra thu nhp trung bnh nh nhau.)

F(columns) = 0,110573 < F crit => chp nhn gi thit H0 ( cc ngh ph tora thu nhp trung bnh nh nhau.)

Ti liu tham kho :

Phn tch phng sai Nguyn nh Huy

Ph lc s dng excel SGK .

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