C S K THUT IN 2Gio vin: TS. Nguyn Vit SnB mn: K thut o v Tin hc
cng nghipC1 - 108 - i hc Bch Khoa H NiEmail: [email protected]
2010 -C s k thut in 22C S K THUT IN 2Ni dung chng trnh:Chng 1: Khi
nim v mch phi tuyn.I. Khi nim v mch phi tuyn.II. Tnh cht mch phi
tuyn.III. Tuyn tnh ha - Qun tnh ha phn t phi tuyn.IV. Phng php xt
mch phi tuyn.Chng 2: Ch xc lp hng trong mch phi tuyn.I. Khi nim
chung.II. Phng php th.III. Phng php d.IV. Phng php lpC s k thut in
23C S K THUT IN 2Ni dung chng trnh:Chng 3: Ch xc lp dao ng trong
mch phi tuynI. Khi nim chung.II. Phng php th vi gi tr tc thi.III.
Phng php cn bng iu ha.IV. Phng php iu ha tng ng.V. Phng php d.VI.
Phng php tuyn tnh ha quanh im lm vic.Chng 4: Qu trnh qu trong mch
phi tuyn.I. Khi nim chung.II. Phng php tham s b (nhiu lon).III.
Phng php sai phn lin tip.IV. Phng php bin pha bin thin chm (h s tch
phn).C s k thut in 24C S K THUT IN 2Ni dung chng trnh:Chng 5: L
thuyt v mch c thng s di - ng dy di u tuyn tnh.I. M hnh ng dy di
u.II. Ch xc lp iu ha trn ng dy di.III. Qu trnh qu trn ng dy di khng
tiu tn.C s k thut in 25C S K THUT IN 2Ti liu thamkho:1. C s k thut
in 1 & 2 - Nguyn Bnh Thnh - Nguyn Trn Qun - Phm KhcChng -
1971.2. C s k thut in - Quyn 1 - B mn K thut o v Tin hc cng nghip -
20043. Gio trnh l thuyt mch in - PGS - TS. L Vn Bng - 2005.4.
Fundamentals of electric circuits - David A.Bell - Prentice Hall
InternationalEdition - 1990.5. Electric circuits - Norman Blabanian
- Mc Graw Hill - 1994.6. Methodes detudes des circuit electriques -
Fancois Mesa - Eyrolles - 1987.7. An introduction to circuit
analysis a system approach - Donald E.Scott - McGraw Hill -
1994.http://www.mica.edu.vn/perso/Nguyen-Viet-Son/Ly-Thuyet-Mach/C
s k thut in 26C S K THUT IN 2Chng 1: Khi nimv mch phi tuynI. Khi
nimv mch phi tuyn.II. Tuyn tnh ha - Qun tnh ha phn t phi tuyn.III.
Tnh cht mch phi tuyn. IV. Phng php xt mch phi tuyn.Bi tp: 1 - 4, 6,
7, 8 - 13.C s k thut in 27C S K THUT IN 2Chng 1: Khi nimv mch phi
tuynI. Khi nim v mch phi tuyn.I.1. Mch v h phng trnh mch phi
tuyn.I.2. Phn t mch phi tuyn.I.3. Hm c tnh ca phn t phi tuyn.II.
Tuyn tnh ha - Qun tnh ha phn t phi tuyn.III. Tnh cht mch phi tuyn.
IV. Phng php xt mch phi tuyn.C s k thut in 28Chng 1: Khi nim v mch
phi tuynI.1. Mch v h phng trnh mch phi tuyn.S mchLut6000( ) =
=ckmfE(x, y, z, t), H(x,y,z,t) Thit b inMch haM hnh trng M hnh h
thngu(t), i(t), p(t) M hnh mch(nng lng) KirchoffM hnh mch tn hiuH
phng trnh ton hc gtb>> gmoi truong Hu hn cc trng thi. l 15V2
0.2 2.5 0.25 0.45 3.6 6.1 1.53 1.98 14V < 15V3 0.25 2.6 0.26
0.51 4.08 6.68 1.67 2.18 15.4VEBAR1R5R2R3R4Cch 1: D trc tip t s
mchCCho I5U5544UIR=3 4 5I I I = +3 3 3U I R =3 5 ACU U U =
+22ACUIR=1 2 3I I I = +1 1 tnh ACE R I U = +Sai s:15.4 15% 100% 2,
67%15c= =I1I4I5I2I3C s k thut in 2Chng 2: Ch xc lp hng trong mch
phi tuynIII.Phng php d34V d 2: Cho mch in: R1 = R2 = 4, R3 = 8, R4
= 10, E = 15V.Tnh dng I5 theo phng php d.AV4 3 2
100.80.60.40.2U5(I5) Kt qu d:n I5U5Etnh1 0.4A 3V 5V > 3.75V2
0.2A 2.5V 3.5V < 3.75V3 0.25A 2.6V 3.85V > 3.75VEhRvR5Cch 2:(
)4 1 2 3/ / / /vR R R R R = +( 5vR = O43 43.75hAE R VR R = =+1 2 3
4 11 1 16.75A AEVR R R R R | |+ + = = |+\ . Lp phng trnh:5 5( )h vE
R I U I = +Tra U5(I5)Cho I5U55 5 5( )tnh vE R I U I = + Bin i mch
theo s Thevenil: Sai s:3.85 3.75% 100% 2, 67%3.75c= =C s k thut in
2Chng 2: Ch xc lp hng trong mch phi tuynIII.Phng php d35V d 3: Cho
mch in bit J = 12A (1 chiu), E =20V (1 chiu), R = 30. Mng 2 ca thun
tr c bs: A11 = 1.1 ; A12 = 20 ; A21 = 0.5 ; A22 = 10. Phn tphi tuyn
c c tnh cho theo bng:Gii:JAI1AU1AI2AU2AREU(I)I(A) 0 0.5 1 1.5 2
2.2U(V) 0 7 10 14 20 25Tnhdngchyquaintrphituyn. Bin i mng 2 ca +
ngun dng s Thevenil12 222 21010200.5AvaoAIU ARI A== = = = O21 1221
2101224( )0.5th hoII JE U VA A== = = = =EthREU(I)Rvao24 2020 3022,
4( )1 1 1 120 30thvaoTDvaoE ER RE VR R++= = =+ +. 20.301220
30thTDthR RRR R= = = O+ +C s k thut in 2Chng 2: Ch xc lp hng trong
mch phi tuynIII.Phng php d36 Phng trnh d:EthREU(I)Rvao. ( )TD TDE R
I UI = +I(A) 0 0.5 1 1.5 2 2.2U(V) 0 7 10 14 20 25I(A) RTD.I Etnh=
RTD.I + U(I)0.5 6 13V < 22.4V1 12 22 < 22.4V1.5 18 32 >
22.4V22, 4( )TDE V =12TDR = O p dng cng thc ni suy tuyn tnh:1.5
11.5 (22.4 32). 1.02( )32 22I A= + = Vy dng in chy qua in tr phi
tuyn l: I = 1.02(A)C s k thut in 237C S K THUT IN 2Chng 2: Ch xc lp
hng trong mch phi tuyn.I. Khi nimchung.II. Phng php th.III. Phng
php d.IV. Phng php lp.C s k thut in 2Chng 2: Ch xc lp hng trong mch
phi tuynIII.Phng php lp38 Ni dung phng php:Biu din qu trnh mch
Kirhoff theo phng trnh phi tuyn dng:x = (x)Cho mt gi tr ca x0tnh gi
tr x1 = (x0)Thay gi tr x1 tnh gi tr x2 = (x1)Qu trnh tnh lp dng khi
xn- xn-1nh hn sai s cho trc.C s k thut in 2Chng 2: Ch xc lp hng
trong mch phi tuynIII.Phng php lp39 Ni dung phng php:yx0yx0yx0y =
(x)yx0y = (x)x = (x)Nghim l honh giao im:ng thng y = xng cong y =
(x)iu kin hi t : Trong min ccgi tr lp xk, tr tuyt i dcngy=(x)
nhhndcng y = x.|(x)| < 1C s k thut in 2Chng 2: Ch xc lp hng
trong mch phi tuynIII.Phng php lp40 Thut ton: u, nhc im:Cn kim tra
iu kin hi t ca php lp.Tnh nhanh, cho php tnh n sai s nh ty .C th lp
trnh cho my tnh tnh nghim t ng.Cho xkTnhxk+1= (xk)Nghimx =
xk+1ngSai1.( ) ( )( )k ky ckx xx c c+= sxk= xk+1C s k thut in 2Chng
2: Ch xc lp hng trong mch phi tuynIII.Phng php lp41V d: Cho mch in
gm in dn tuyn tnh g = 0.2(Si) mc ni tip vi phn tphi tuyn c c tnh
u(i) = 2i2. Ngun cung cp mt chiu E = 10V. Dng phngphp lp tnh cc gi
tr dng p trong mch. Chn bin lp i: u = Ri + 2i210 = 5i + 2i2i = -
0.4i2+ 2Gii: Lp phng trnh mch: u = u(i) + ug Kt qu lp:k ikik+1 = 2
0,4.ik2|ik| = |ik+1 - ik|0 1(A) 1,6(A) 0,6(A)1 1,6(A) 0,976(A)
0,624(A)2 0,976(A) 1,619(A) 0,643(A)3 1,619(A) 0,952(A) 0,667(A)4
0,952(A) Khng hi t iu kin hi t:0,8 1didx =
