Bao Cao ĐỒ ÁN TRANG BỊ ĐIỆN

n Chuyn Ngnh

1 inh Hu Giang - 20111449

n Chuyn Ngnh


n Chuyn Ngnh


LI NI U

Ngy nay trong cc lnh vc sn xut ca nn kinh t quc dn, c kh ha c lin quan cht ch n in kh ha v t ng ha. Hai yu t sau cho php n gin kt cu c kh ca my sn xut, tng nng sut lao ng, nng cao cht lng k thut ca qu trnh sn xut v gim nh cng lao ng.

Vic tng nng sut my v gim gi thnh thit b in cu my l hai yu cu ch yu i vi h thng truyn ng in v t ng ha nhng chng mu thun nhau. Mt bn i hi s dng cc h thng phc tp, mt bn li yu cu hn ch s lng thit b chung trn my v s thit b cao cp. Vy vic la chn mt h thng truyn ng in v t ng ha thch hp cho my l mt bi ton kh.

Qua thi gian hc tp v tm hiu, em thc hin mt ti nh: Thit k h truyn ng bin tn ng c khng ng b c cu quay chi tit my mi trn di s hng dn tn tnh ca ThS. Nguyn Th Lin Anh, b mn T ng ha Cng nghip, Vin in, trng i hc Bch Khoa H Ni.

Trong mt thi gian tng i ngn do vy n ny chc chn khng trnh khi nhng thiu st, vi s n lc ca bn thn, em rt mong nhn c kin ng gp ca cc thy c bn n ny hon thin hn!

H Ni, ngy 06 thng 06 nm 2015.

Sinh vin thc hin:

inh Hu Giang

n Chuyn Ngnh


CHNG I:

YU CU CNG NGH V TRUYN NG

1.1.TNG QUAN V MY MI.

Trong sn xut c kh cng nh trong cc lnh vc sn xut khc sn phm to ra giai on cui cng ca mt qu trnh sn xut, tuy nhin to ra sn phm cui cng cn phi tin hnh qua rt nhiu khu, t ch l nguyn vt liu cho n sn phm thng c tin hnh lin tc theo mt quy trnh cng ngh no hnh thnh mt h thng gi l dy chuyn sn xut, ty theo mc phc tp ca sn phm m dy chuyn sn xut cng c phc tp tng ng. Trong sn xut c kh th mi thuc giai on gia cng chi tit to ra mt sn phm c b mt t yu cu v k thut. My mi gia cng tinh vi lng d b, b mt trc khi mi c gia cng th hoc tinh trn cc my khc ( nh my tin, phay, bo... ) cng nh cc loi my chuyn mi th dng trong phn xng chun b phi vi lng d hng mm ( mi cc phi thp c, v hp gang c... ).

Trn my mi ta c th mi c cc mt tr ngoi, trong, mt cn, mt nh hnh, mi rng, ren, mi sc. Mi ng vai tr quan trng trong gia cng ln cui nn c dng rng ri trong cc nh my v phn xng c kh.

Hin nay my mi c hai loi chnh : My mi trn v my mi phng. Ngoi ra cn c cc my khc nhau : my mi v tm, my mi rnh, my mi ct, my mi rang v.v. Thng trn my mi c chi tit hoc bn, trn kp chi tit v mi, trn c trc chnh vi mi. C hai u t trn b my. S sau cho ta mt m hnh tng quan v my mi.

My mi cng nghip

My mi phng

My mi bng

bin

My mi mt u

My mi trn

My mi trn

ngoi

My mi trn trong

Cc loi khc

My mi v tm

My mi rnh

My mi ct

My mi rng

n Chuyn Ngnh


S biu din cng ngh mi c gii thiu hnh 1.1.

Hnh 1.1. S gia cng chi tit trn my mi Gii thch k hiu:

a) My mi trn ngoi. b) My mi trn trong. c) My mi mt phng bng bin . d) My mi mt phng bng mt u (bn ch nht). e) My mi mt phng bng mt u (bn trn). 1. Chi tit gia cng. 2. mi. 3. Chuyn ng chnh. 4. Chuyn ng n dao dc. 5. Chuyn ng n dao ngang.

My mi trn c hai loi : my mi trn ngoi ( hnh 1-1a) v my mi trn trong ( hnh 1-1b). Trn my mi trn chuyn ng chnh l chuyn ng quay ca mi ; chuyn ng n dao l di chuyn tnh tin ca dc trc (n do dc trc) hoc di chuyn tnh tin theo hng ngang trc (n dao ngang) hoc chuyn ng quay ca chi tit (n dao vng). Chuyn ng ph l di chuyn nhanh hoc chi tit v.v

My mi phng c hai loi : mi bng bin ( hnh 1-1c) v mt u ( hnh 1-1d). Chi tit c kp trn bn trn hoc ch nht. my mi bng bin , mi quay trn v chuyn ng tnh tin ngang so vi chi tit, bn my mang chi tit chuyn ng tnh tin qua li. Chuyn ng quay ca l chuyn ng chnh, chuyn ng n dao l di chuyn ca ( n dao ngang ) hoc chuyn ng ca chi tit ( n dao dc ). my

n Chuyn Ngnh


mi bng mt u , bn c th l trn hoc ch nht, chuyn ng quay ca l chuyn ng chnh, chuyn ng n dao l di chuyn ngang ca ( n dao ngang ) hoc chuyn ng tnh tin qua li ca bn mang chi tit ( n dao dc ). Mt tham s quan trng ca ch mi l tc ct (m/s) :

30,5 . .10dv d

[m/s]

Trong : d - ng knh mi, mm .

d - tc quay ca mi, rad/s.

Thng thng v = 30 50 m/s.

Ngoi ra ra cng cn ch ti yu t nh hng ti cht lng mi: Chn mi: m bo cht lng sn phm v nng cao nng sut khi chn

mi ra cn ch ti cc iu sau:

Vt liu mi.

Cht kt dnh mi.

cng mi.

Kt cu ... Nhng iu trn quy nh trong cng ngh ct.

Chn ch ct: Chn ch mi l chn ch quay ca , tc quay ca chi tit lng chy dao ngang v chiu su ct. V d:

Tc quay qu chm s tng lc ct chng mn . Nu tc qu cao lc li tm ln s gy gy trc v ...

Tc vt mi ph thuc vo yu cu k thut bng b mt gia cng. Mi tinh hay mi th ty thuc vo lng chy dao c tc mi hp l.

1.2. C IM TRUYN NG CA MY MI.

Mt c im quan trng trong h thng my mi l h thng thc hin nhiu truyn ng cng mt lc v c hai loi chuyn ng ch yu : Chuyn ng c bn v chuyn ng ph.

Chuyn ng c bn l s di chuyn tng i ca dao ct so vi phi m bo qu trnh ct gt. Chuyn ng ny li chia ra : chuyn ng chnh v chuyn ng n dao. - Chuyn ng chnh ( chuyn ng lm vic ) l chuyn ng a dao ct n

vo chi tit. - Chuyn ng n dao l chuyn ng x dch ca li dao hoc phi to ra

mt lp phoi mi.

Chuyn ng ph l nhng chuyn ng khng lin quan trc tip n qu trnh ct gt, chng cn thit khi chun b gia cng, hiu chnh my, v.v V d : di chuyn thanh dao hoc phi

Cc chuyn ng chnh, n dao c th l chuyn ng quay hoc chuyn ng tnh tin ca dao hoc phi.

n Chuyn Ngnh


1.2.1. Truyn ng chnh.

Trn my mi trn truyn ng chnh l truyn ng quay ca mi, vi vn tc c tnh theo biu thc:

. .

60.1000

d dD nv

(m/s)

Trong : dD - ng knh ca mi.

dn - s vng quay trc chnh mang (vng/pht).

Trong cc truyn ng ca mi th truyn ng quay mi c yu cu phi m bo mt tc tng i n nh, do vy trong cc thit k ngi ta thng s dng ng c khng ng b r to lng sc. Tuy nhin cc my mi c nng, duy tr tc ct l khng i khi mn hay kch thc chi tit gia cng thay i, thng s dng truyn ng ng c c phm vi iu chnh tc l D = 2 4/1 vi cng sut khng i. my mi trung bnh v nh v = 50 80 m/s nn mi c ng knh ln th tc quay khong 1000 vg/ph. nhng my c ng knh nh, tc rt cao. ng c truyn ng l cc ng c c bit, mi gn trn trc ng c, ng c c tc ( 24000 48000 vg/ph), hoc c th ln ti ( 150000 200000 vg/ph). Ngun ng c l cc b bin tn. c th l cc my pht tn s cao ( BBT quay), hoc l cc b bin tn tnh (BBT bng thyristor). M men cn tnh trn trc ng c thng l 15 20% momen nh mc. Momen qun tnh ca v c cu truyn lc li ln : 500 600% momen qun tnh ca ng c, do cn hm cng bc ng c quay . Khng yu cu o chiu quay ng c quay .

1.2.2. Truyn ng n dao.

a) My mi trn : my c nh, truyn ng quay chi tit dng ng c khng ng b nhiu cp tc (iu chnh s i cc p) vi D = (2 4) /1 . cc my ln th

dng h thng b bin i ng c in mt chiu ( BBD DM), h KDT DM c D = 10/1 vi iu chnh in p phn ng. Truyn ng n dao dc ca bn my trn c ln thc hin theo h BBD DM vi D = (20 25) /1

Truyn ng n dao ngang s dng thy lc.

b) My mi phng : Truyn ng n dao ca thc hin lp li nhiu chu k, s dng thy lc. Truyn ng n dao tnh tin qua li ca bn dng h truyn ng mt chiu vi D = (8 10) /1

1.2.3. Truyn ng ph.

Truyn ng ph trong my mi v truyn ng di chuyn nhanh u mi, bm du ca h thng bi trn, bm nc lm mt thng dng h truyn ng xoay chiu vi ng c khng ng b roto lng sc.

n Chuyn Ngnh


1.2.4. Truyn ng quay chi tit my mi.

- Phm vi iu chnh tc 8050/1. - M my c ti momen m my t 150 200% Mm. - Momen qun tnh c th ln gp 7 8 ln momen qun tnh trc ng c.

Do nhng c im trn i vi my mi c nng ngi ta dng ng c in 1 chiu (F-D hoc T-D). Cn i vi nhng my mi c nh ngi ta dng ng c lng sc nhiu cp tc .

n Chuyn Ngnh


CHNG II:

TNH CHN NG C V LA CHN BIN TN

2.1.THNG S K THUT.

Theo nhng yu cu k thut ca bi ta phi thit k h truyn ng vi ng c c cc thng s k thut nh sau:

- Mmen cc i 48 [Nm]

- Tc quay chi tit (n) 33 330 [Vng/pht]

- T s truyn (i) 3

- Hiu sut () 0,9

- Mmen qun tnh c cu (J) 0,009 [kg/s2]

2.2.TNH CHN NG C.

Trong mt h thng truyn ng th thnh phn quan trng nht l ng c truyn ng, n l ngun ng lc cho h thng, cht lng lm vic ca h thng c v mt kinh t c k thut ph thuc rt mnh m vo ng c c chn truyn ng v nhiu khi n cn nh hng n s hot ng chung ca cc h thng khc. ng c c chn phi yu cu p ng c cc ch tiu k thut sau:

- ng c phi c cng sut c th thc hin c yu cu ca truyn ng. - C tc , phm vi iu chnh tc ph hp yu cu vi mt phng n truyn

ng tng ng. - Tha mn cc yu cu v m my v hm ng c.

Ngoi ra cn mt s yu cu khc nh ph hp vi ngun in nng tiu th cng nh thch hp vi iu kin lm vic, tnh gn nh trong s dng v.v...

Theo s liu u bi ta c:

- Tc ln nht ca chi tit l:

max max

max

2 33034,555( / )

60 9,55 9,55

ct ctct

n nrad s

- Tc ln nht ca chi tit l:

min minmin

2 333,455( / )

60 9,55 9,55

ct ctct

n nrad s

- Cng sut ln nht ca c cu l:

max. 48.34,555 1,658( )ct ct ctP M kW

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10 inh Hu Giang - 20111449

- Tc ln nht ca ng c cho php (vi t s truyn i = 3) l:

max ct max. 3.34,55 103,665( / )i rad s hay max 990( / )n vong phut

- Tc nh nht ca ng c cho php (vi t s truyn i = 3) l:

min ct min. 3.3,455 10,366( / )i rad s hay min 99( / )n vong phut

- Di iu chnh tc :

max max

min min

99010 :1

99

nD

n

- Cng sut tnh ton ca ng c l:

1,658

1,842( )0,9

ctdc

P kWP kW

- Cng sut nh mc ca ng c l:

(1,1 1,3).dm ttP P

y ta chn

1,2. 1,2.1,842 2,2( )dm ttP P kW

thc hin truyn ng ta s dng ng c khng ng b rotor lng sc, do ng c c chn phi c cng sut p ng c yu cu truyn ng vi cng sut 2,2 kW. Cn c vo s liu ta chn c ng c ca Siemens (vi s hiu l 1LA7113-64A) c cc thng s nh sau:

- Cng sut ng c: 2,2( )dmP kW .

- Tc quay: n = 940 vng/pht. - Hiu sut: = 78%. - H s cng sut: cos = 0,78. - Dng in stato: Is = 5,2 A. - Momen ng c: Mc = 22 N.m. - S i cc: p = 3. - in tr roto: Rr = 2,5385 .

- in tr stato: Rs = 4,7398 .

- in khng ngn mch: 6,028 .L

- in cm t ha: 0,0954mL H .

- in cm tn ca stato: 0,0096sL H .

- in cm tn ca rotor: 0,0096rL H .

- Sut in ng pha stato: 181,7 .SE V

- Momen qun tnh: 20,011( . )J kg m .

2.3. LA CHN B BIN TN.

T cc thng s ca ng c 1LA7113-64A chn nh trn ta la chn b bin tn ph hp vi tiu ch:

- Cp cng sut cho ng c. - Chu c dng in stato ca ng c.

n Chuyn Ngnh

11 inh Hu Giang - 20111449

Ta la chn loi bin tn ca Siemens vi cc thng s sau:

- Tn bin tn: MM 440 vi m hiu 6SE6440-2UD22-2BA1. - Cng sut ca bin tn: 2,2P kW .

- Dng in u ra: 5,9 .rI A

- Dng in u vo: 7,5 .vI A

n Chuyn Ngnh

12 inh Hu Giang - 20111449

CHNG III:

NGUYN L IU KHIN V B BIN TN CA H THNG

3.1.NGUYN L IU KHIN.

3.1.1.Vector khng gian cc i lng ba pha.

Xy dng vector khng gian.

ng c khng ng b (CKB) ba pha c ba ( hay bi s ca ba) cun dy stator b tr trong khng gian nh hnh v sau:

Hnh 3.1. B tr cc cun dy trong stator ca CKB ba pha.

Hnh 3.2. S u dy v in p stator ca CKB ba pha.

(Ba trc ca ba cun dy lch nhau mt gc 1200 trong khng gian

Ba in p cp cho ba u dy ca ng c t li ba pha hay t b nghch lu, bin tn; ba in p ny tha mn phng trnh:

( ) ( ) ( ) 0sa sb scu t u t u t

n Chuyn Ngnh

13 inh Hu Giang - 20111449

Trong :

0

0

( ) | | cos( )

( ) | | cos( 120 )

( ) | | cos( 120 )

sa s s

sb s s

sc s s

u t u t

u t u t

u t u t

Vi 2s sf ; sf l tn s ca mch stator; | |su l bin ca in p pha, c th thay

i.

Trn mt phng c hc ng c khng ng b c 3 cun dy t lch nhau mt gc 120

0, nu trn mt phng ta thit lp mt h ta phc vi trc thc i qua cun dy A ca ng c, ta c th xy dng vector khng gian cho in p stator

0 0120 120

2[ ( ) ( ) ( )]

3

2[ ( ) ( )e ( )e ]

3

s sa sb sc

j js sa sb sc

u u t u t u t

u u t u t u t

Theo cng thc trn, vector su l vector c modul khng i, quay trn mt phng

phc vi tc 2s sf , v to vi trc thc (cun dy pha A) 1 gc pha .s t .

Vic xy dng c m t nh hnh di:

Hnh 3.3. Vector trn mt phng c hc

Theo hnh v trn, in p ca tng pha chnh l hnh chiu ca vector in p

stator su ln trc ca cun dy tng ng. i vi cc i lng khc ca ng c: dng

in stator, dng rotor, t thng stator v t thng rotor u c th xy dng cc vector khng gian tng ng nh i vi in p stator trn.

n Chuyn Ngnh

14 inh Hu Giang - 20111449

3.1.2. Chuyn h ta vector khng gian.

a. H ta c nh stator ( H ta -).

Vector khng gian in p stator l mt vector c modul xc nh ( | |su ) quay trn

mt phng phc vi tc gc s v to vi trc thc (trng vi cun dy pha A) mt

gc .s t . t tn cho trc thc l v trc o l , vector khng gian (in p stator)

c th c m t thng qua hai gi tr thc ( su ) v o ( su ) l hai thnh phn ca

vector. H ta ny l h ta stator c nh, gi tt l h ta .

Hnh 3.4. H ta -.

Bng cch chiu vector khng gian in p stator us ln hai trc ta (,) ta c th tnh c thnh phn theo 2 trc ta bng phng php hnh hc. Xt thnh phn vector in p trong h ta (,):

1 3

2 2

1 3

2 2

sa s

sb s s

sc s s s s

u u

u u u

u u u u u

Suy ra:

1 1( 2 ) ( )

3 3

s sa

s sa sb sa sc

u u

u u u u u

Theo phng trnh trn ch cn xc nh 2 thnh phn in p A v B th ta c th xc nh vector in p khng gian, v y l in p 3 pha cn bng, in p pha C sn trong phng trnh : s s su u ju

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15 inh Hu Giang - 20111449

Bng cch tng t nh i vi vector khng gian in p stator, cc vector khng gian dng in stator, dng in rotor, t thng stator v t thng rotor u c th c biu din trong h ta stator c nh (H ta -) nh sau:

s s s

s s s

r r r

s s s

r r r

u u ju

i i ji

i i ji

j

j

b. H ta t thng rotor ( H ta d-q).

Trc ht ta quy c nh sau: f (thay cho field coordinates hoc ta dq) v s

(thay cho stator coorfinates hoc ta ). V d:

iss : vector dng stator quan st trn h ta . ifs : vector dng stator quan st trn h ta dq.

T ta c:

ss s si i ji (3.1a)

fs sd sqi i ji (3.1b)

Trong mt phng ca h ta (,) ta xt thm mt h ta th hai, c trc honh l trc d, trc tung l trc q. H ta ny c chung im gc v nm lch i mt

gc s so vi h ta stator. Khi tn ti hai h ta v mt vector khng gian c

th biu din trn 2 h ta ny.

aad

dt

quay trn quanh gc ta chung, vi gc 0a a at

Hnh v di y m t mi lin h ca hai ta ny.

Hnh 3.5. H ta d-q

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16 inh Hu Giang - 20111449

Quan h gia 2 h ta

cos sin

sin cos

s sd s sq s

s sd s sq s

u u u

u u u

V

s s s

dqs sd sq

u u ju

u u ju

Bin i 2 h phng trnh trn ta c:

cos sin

sin cos

sd s s s s

sq s s s s

u u u

u u u

Cc h phng trnh trn c tc dng chuyn i t h ta (-) sang h ta (d-q) cho in o stator, cng ng cho cc thnh phn khc ca ng c. Khi xt h (d-q), ta cho trc d trng vi trc t thng rotor v quay vi tc bng tc gc ca vector t thng rotor.

Hnh 3.6. Tng hp h - v d-q

Trong h ta ta t thng rotor, cc vector dng stator v cc vector t thng rotor quay cng vi h ta (d-q), do cc phn t ca vector dng rotor l i lng 1 chiu, trong ch xc lp cc gi tr ny gn nh khng i, trong qu trnh qu , cc ai lng ny bin thin theo 1 lut ton nh trc.

Thnh phn t thng rotor trn trc q c gi tr l 0 do trc d trng vi vector t thng rotor, do t thng rotor ch c thnh phn d v i lng mt chiu

n Chuyn Ngnh

17 inh Hu Giang - 20111449

Mt cch tng t nh i vi vector dng stator, ta c th biu din tt c cc vector cn li trn h ta dq.

fs sd squ u ju (3.2a)

fr rd rqi i ji (3.2b)

fr rd rqj (3.2c)

fs sd sqj (3.2d)

Ta d dng nhn thy trong phng trnh (3.2c) c rq = 0 do trc q ng vung gc vi bn thn vector r .

Cc cun day ca ng c c cc in cm sau y:

Lm : h cm gia rotor v stator

Ls : in cm tiu tn pha cun dy stator

Lr : in cm tiu tn pha cun dy rotor ( quy i v stator)

T cc in cm ta nh ngha thm cc tham s sau:

Ls = Lm + Ls : in cm stator

Lr = Lm + Lr : in cm rotor

Ts = Ls/Rs : hng s thi gian stator

Tr = Lr/Rr : hng s thi gian rotor

2

1 m

s r

L

L L : h s tiu tn tng

Vi cc tham s mi c nh ngha ta c thm cc phng trnh ca t thng stator v t thng rotor sau y:

s s s r mi L i L (3.3a)

r s m r ri L i L (3.3b)

Ta c phng trnh in p stator v rotor trn h ta dq

.if

f f fss s s s s

du R j

dt

(3.4)

0 .if

f frr r r r

dR j

dt

(3.5)

3.1.3. Nguyn l lm vic ca h truyn ng iu khin bng phng php iu khin vector gin tip.

Nguyn l iu khin vector ta t thng rotor

Phng php iu khin c bin v v tr pha ca vecto dng in (in p) gip to c h thng iu chnh t thng hon ho m khng cn s dng cm bin t thng ng c. Trong ch xc lp vecto t thng roto quay ng b vi t trng quay stato, nu ta chn vecto ny trng vi trc d ca h thng ta quay ng b th ta c hnh sau:

n Chuyn Ngnh

18 inh Hu Giang - 20111449

Hnh 3.7. Nguyn l iu khin vector ta t thng rotor

Trong hnh trn, ch xc lp th v tt c cc vecto u quay ng b vi h trc ta nn gc l hng s v do cc thnh phn ca dng in chiu ln h trc cng l 1 chiu (bin thin rt chm). y l mt li th rt ln ca phng php ny c th d dng tng hp cc b iu chnh kiu v hng theo hnh chiu ca vecto dng in.

T cc phng trnh (3.1a,b),(3.2a,b),(3.2c,d) v (3.3a,b),(3.4),(3.5).

.if

f f fss s s s s

du R j

dt

(3.6a)

0 .if

f frr r r r

dR j

dt

(3.6b)

f f f

s s s r mi L i L (3.6c)

f f f

r s m r ri L i L (3.6d)

Cc i lng khng cn thit nh vector dng in rotor ifr , vector t thng stator fs b

trit tiu ra khi h. T hai phng trnh (3.6c) v (3.6d) c th rt ra c hai vector .

1

( )f f fr r s mr

i i LL

(3.7a)

( )f f f fms s s r s mr

Li L i L

L (3.7b)

Thay ifr v

fs vo (3.6a) v (3.6b) ta s thu c h phng trnh (3.8) sau mt vi bin

i.

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19 inh Hu Giang - 20111449

1 1 1 1 1( )i

rqsd rdsd s sq s sd

s r r m m s

dii u

dt T T T L L L

(3.8a)

1 1 1 1 1( )i

sq rqrdsq s sd s sq

s r m r m s

dii u

dt T T L T L L

(3.8b)

1rd msd rd sl rq

r r

d Li

dt T T

(3.8c)

1rq msq rq sl rd

r r

d Li

dt T T

(3.8d)

Vi trc d trng vi vecto t thng roto nn:

; 0rd rqr

cosssdi i cng trng vi vector r

do ta ni isd l thnh phn dng in sinh t thng roto

sinssqi i

Ta c cng thc momen ca ng c:

3 3. { . } . { . }

2 2

3 3. ( . . ) . .

2 2

mm r s m r s

r

m mrd sq rq sd rd sq

r r

LM p I i p I i

L

L Lp i i p i

L L

2

3. .

2

msd sq

r

LM p I I

L

Nu ta gi c bin vecto t thng roto khng i (bng cc b iu chnh cn thit) th momen ng c s t l thun vi thnh phn dng in stato chiu ln trc q: isq do ta gi thnh phn dng in ny l thnh phn dng in sinh momen.

Nn phng php ny c gi l phng php iu khin ta t thng roto.

C chin lc iu khin ging ng c 1 chiu: gi isd khng i (tng ng vi khng i), sau iu khin isq (tng ng vi iu khin I)

| |sd r

sq

i

i M

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20 inh Hu Giang - 20111449

3.1.4. iu khin vector gin tip.

Hnh 3.8. S h thng iu khin vector ta t thng rotor gin tip.

Vi phng php ny, gc s c tnh theo chui cc phng trnh sau:

.

s s

s slip

sqslip

r sd

rr

r

dt

I

T I

LT

R

3.2. B BIN TN BN DN.

3.2.1. Cu trc b bin tn bn dn.

B bin tn (BBT) l thit b bin i nng lng in t tn s cng nghip (50Hz) sang ngun c tn s thay i cung cp cho ng c xoay chiu. B bin tn chia lm hai loi: bin tn trc tip ( cycloconverter) v bin tn gin tip ( c khu trung gian mt chiu).

B bin tn trc tip c s dng h thng cng sut cao. B bin tn gin tip c s khi nh hnh 3.9.

Id

+ u1 f1

uI fI Ud

-

Hnh 3.9. S khi b bin tn gin tip.

CL Lc NL C

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21 inh Hu Giang - 20111449

in p xoay chiu tn s cng nghip (50Hz) c chnh lu thnh ngun mt chiu nh b chnh lu (CL) khng iu khin hoc b chnh lu iu khin, sau c lc v b nghch lu (NL) s bin i thnh ngun in p xoay chiu ba pha c tn s bin i cung cp cho ng c. B bin tn phi tha mn cc yu cu sau:

C kh nng iu chnh tn s theo gi tr tc t mong mun.

C kh nng iu chnh in p theo tn s duy tr t thng khe h khng i trong vng iu chnh momen khng i.

C kh nng cung cp dng in nh mc mi tn s.

B bin tn bn dn c th chia lm ba loi chnh ty thuc vo b chnh lu v nghch lu nh s hnh 3.1

(a)

(b)

(c)

Hnh 3.10. S khi cc bin tn gin tip: a. Bin tn nghch lu ngun p dng PWM v b chnh lu diot. b. Bin tn nghch lu ngun p dng xung vung v b chnh lu iu khin. c. Bin tn nghch lu ngun dng vi b chnh lu iu khin.

1. B bin tn vi nghch lu ngun p iu bin rng xung vi b chnh lu dng diot (3.10a).

in p mt chiu t b chnh lu khng iu khin (dng diot) c tr s khng i c lc nh t in c tr s kh ln. in p v tn s c iu chnh nh b nghch lu iu bin rng xung (Pulse Modulation Width PWM). Cc mch nghch

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22 inh Hu Giang - 20111449

lu bng cc tranzito (BJT, MOSFEST, IGBT) c iu khin theo nguyn l PWM m bo cung cp in p ng c c dng gn sinh nht.

2. B bin tn nghch lu ngun p dng xung vung v b chnh lu iu khin (3.10b).

in p iu chnh nh b chnh lu c iu khin (thng thng bng tiristo hoc tranzito). B nghch lu c chc nng iu chnh tn s ng c. Dng in p ra c dng hnh xung vung.

3. B bin tn vi nghch lu dng in v chnh lu iu khin dng tiristo (3.10c).

Ngun mt chiu cung cp cho nghch lu l ngun dng vi b lc l cun khng ln.

3.2.2. Mch chnh lu.

i vi ngun cp cho mch nghch lu th tnh cht ngun in l bng phng hn ch s nhp nh in p c th lm hng van khi van c bm vi tn s ln. V th chng ta phi la chn mch chnh lu sao cho dng in p ra cng bng phng th cng tt. Khi chng ta thc hin iu ch rng xung PWM vi tn s cao nn c th iu khin ng c chy trn v m rng vng tc iu chnh.

3.2.3. Mch nghch lu.

Xt mt mch nghch lu mt pha c s khi hnh 3.11a; in p uo c lc sao cho c dng hnh sin. Ti ca nghch lu l ng c, mang tnh cm khng, nn dng in io s chm pha so vi in p uo nh hnh 3.11b. Trong khong 1, in p uo v dng in io u mang du dng, trong khi khong 3, chng u c du m; nn cng sut tc thi s c truyn t mch mt chiu ti mch xoay chiu, tng ng vi ch nghch lu ca b bin i. Ngc li, khong 2,4 in p uo ngc du vi dng in io, dng cng sut s truyn t mch xoay chiu v mch mt chiu, tng ng vi ch chnh lu. Nh vy mch nghch lu hnh 3.11a s phi c kh nng lm vic bn gc phn t trn mt phng (io0uo) trong mt chu k in p li nh minh ha trn hnh 3.11c.

Hai dng mch nghch lu l:

Nghch lu iu bin rng xung (PWM) vi in p mt chiu l hng s, in p v tn s ra c iu chnh nh iu khin chuyn mch nghch lu.

Nghch lu dng xung vung (square wave pulse) l trng hp c bit ca nghch lu PWM.

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23 inh Hu Giang - 20111449

(a)

(b)

(c)

Hnh 3.11. Nguyn tc ca nghch lu mt pha:

a. S mch in. b. Dng in p v dng in. c. Cc ch lm vic trong mt phng.

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3.3. GII THIU V CI T B BIN TN (BBT) MM440 CHO NG C

1LA7113-64A.

3.3.1. Ci t mc nh. B bin tn MICROMASTER 440 c ci t mc nh kh xut xng sao cho

c th vn hnh m khng cn ci t thm bt k thng s no na. t c iu ny, cc thng s ca ng c c kt ni vi bin tn phi c thng s nh mc ph hp vi thng s ci t mc nh ( P0304, P0305, P0307, P0310) tng ng vi ng c 1LA7 4 cc ca Siemens. Cc thng s mc nh khc: Cc ngun lnh P0700 = 2 (u vo s). Ngun im t P1000 = 2 (u vo tng t). Ch lm mt ng c P0335 = 0. Gii hn dng in P0640 = 150%. Tn s nh nht P1080 = 0 Hz. Tn s ln nht P1082 = 50 Hz. Thi gian tng tc P1120 = 10 s. Thi gian gim tc P1121 = 10 s. Ch iu khin P1300 = 0.

a.Kha chuyn i DIP 50/60 HZ.

Tn s nh mc mc nh cho ng c ca b bin tn MICROMASTER l 50 Hz. i vi ng c c thit k chy tn s nh mc 60 Hz, cc b bin tn c th c t tn s ny nh s dng kha chuyn DIP 50/60 Hz. V tr OFF: Cc thng s mc nh ca Chu u (tn s nh mc ca ng c =

50Hz, cng sut tnh theo kW...) V tr ON: Cc thng s mc nh ca Bc M (tn s nh mc ca ng c = 60

Hz, cng sut tnh theo hp...).

3.3.2. Ci t thng s. 3.3.2.1. Ci t thng s nhanh. B bin tn tng thch vi ng c nh s dng chc nng ci t thng s nhanh, v cc thng s k thut quan trng s c ci t. Ci t nhanh khng cn c thc hin nu thng s nh mc ca ng c ghi trong b bin tn FU ( v d ng c tiu chun 1LA 4 cc ca Siemens) thch hp vi thng s nh mc ghi trn nhn ca ng c ang ni vo bin tn.

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Mc truy nhp ca ngi dng. 1 Mc c bn: Cho php truy nhp ti nhng thng s thng dng nht.

Lc thng s. 0 Tt c cc thng s.

Ci t thng s. 1 Ci t nhanh Ch .

P0010 nn c 1 ci t thng s nh mc trn nhn ca ng c

Tiu chun Chu u/Bc M. 0 Chu u [KW], tn s mc nh 50Hz.

Ch i vi P0100 = 0 hoc 1, gi tr P0100 c xc nh khi ci t kha chuyn DIP 50/60

OFF = kW, 50 Hz

ON = hp, 60 Hz

Chn kiu ng c. 1 ng c khng ng b ( hay ng c d b)

in p nh mc ng c in p nh mc [V] ghi trn nhn ng c l 220V

Dng in nh mc ng c. Dng in nh mc [A] ghi trn nhn ca ng c l 5,2A.

Cng sut nh mc ng c. Cng sut nh mc [kW] ghi trn nhn ng c l 2,2kW.

H s Cos nh mc ng c. H s cng sut nh mc (cos) ca ng c l 0,78.

Bt u

P0003 = 1

P0004 = 0

P0010 = 1

P0100 = 0

P0300 = 0

P0304 = 220

P0305 = 5,2

P0307 = 2,2

P0308 = 0,78

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26 inh Hu Giang - 20111449

Hiu sut nh mc ng c. Hiu sut nh mc ng c theo [%] c ghi trn nhn l 78%.

Tn s nh mc ng c. Tn s nh mc ng c tnh theo [Hz] ghi trn nhn l 50Hz.

Tc nh mc ng c. Tc nh mc ng c tnh theo [v/ph] ghi trn nhn l 940 v/ph.

Dng t ha ng c. Dng t ha ng c c tnh ton s dng P0340=1 hoc s dng P3900 = 1-3 (kt thc qu trnh ci t nhanh) v hin th trong thng s r0331.

Ch lm mt ng c. 0 Lm mt t nhin: S dng trc g qut c gn vi ng c.

H s qu ti ng c. Thng s ny chn gi tr max l 150% i vi momen khng i chn

Chn ngun lnh (nhp ngun lnh) 2 u ni

La chn im t tn s 2 im t tng t

Tn s nh nht. t tn s ng c nh nht ti ng c s chy m khng tnh n tn s im t. Gi tr c ci t y c tc dng cho c quay thun v quay ngc

P0309 = 78

P0310 = 50

P0311 = 940

P0320 = 0.0

P0335 = 0

P0640 = 150%

P0700 = 2

P1000 = 2

P1080 = 0.00

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27 inh Hu Giang - 20111449

Tn s ln nht. t tn s ng c ln nht ti ng c s chy m m khng tnh n tn s im t. Gi tr c ci t y c tc dng cho c quay thun v quay ngc

Thi gian tng tc. Thi gian tng tc l thi gian ng c tng tc t im dng n im c tn s ln nht (P1082) khi khng dng cch tng tc c dng ng cong. Nu thi gian tng tc c ci t qu nh, iu ny c th lm xut hin cnh bo A0501 (gi tr gii hn dng) hoc lm cho b bin tn ca h truyn ng b dng vi li F0001 (qu dng).

Thi gian gim tc. Thi gian gim tc l thi gian ng c gim tc t im ln nht (P1082) n im dng khi khng dng cch gim tc c dng ng cong. Nu thi gian gim tc c ci t qu nh, iu ny c th lm xut hin cnh bo A0501 (gi tr gii hn dng), A0502 (gi tr gii hn qu p) hoc lm cho b bin tn ca h truyn ng b dng vi li F0001 (qu dng) hoc F0002 (qu p).

OFF3 Thi gian gim tc. Nu t thng s thi gian gim tc qu thp s lm xut hin cnh bo A0501 (gi tr gii hn dng), A0502 (gi tr gii hn qu p) hoc lm cho b bin tn ca h truyn ng b dng vi li F0001 (qu dng) hoc F0002 (qu p).

Mode iu khin. 21 Ch iu khin vector c sensor

Chn im t momen xon. 0 Khng c im chnh

Chn d liu cho ng c 0 Khng hot ng

Ti u ha thit b iu khin tc . 0 Hm

P1082 = 50.00

P1120 = 10.00

P1121 = 10.00

P1135 = 5.00

P1300 = 21

P1500 = 0

P1910 = 0

P1960 = 0

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28 inh Hu Giang - 20111449

Kt thc qu trnh ci t nhanh thng s. 0 Khng ch ci t nhanh thng s (khng c qu trnh tnh ton motor)

Kt thc ci t nhanh.

3.3.2.2. Dng t ha. Gi tr ca dng t ha r0331/ P0320 c nh hng ln ti cht lng iu khin

vng kn. Khng th o c gi tr ny trng thi dng. iu ny c ngha l gi tr ny c c tnh cho chun ng c 4 cc 1LA7 theo tiu chun Siemens thng qua qu trnh t ng t thng s P0340 = 1 (P0320 = 0;kt qu r0331).

Nu lch ca dng t ha qu cao, th cc gi tr in khng v cc gi tr in tr ca ng c s khng th xc nh mt cch chnh xc c.

c bit i vi cc loi ng c ca nh cung cp th ba, vic kim tra k lng dng t ha c xc nh l rt quan trng v nu cn thit th phi iu k=chnh cho hp l.

3.3.2.3. Ci t ng dng. Ci t ng dng iu chnh/ ti u ha s kt hp gia b bin tn v ng c cho mt ng dng c th. B bin tn c nhiu tnh nng nhng khng phi tt c cc tnh nng u cn thit cho mt ng dng c th. C th b qua cc tnh nng ny khi ci t ng dng.

a. Bo v nhit ng c. Ngoi vic bo v qu nhit ng c, nhit ng c cng c tnh ton trong qu trnh hiu chnh d liu s mch tng ng ca ng c. c bit i vi ng c mang ti ln nhit cao, s hiu chnh ny c nh hng ng k ln n nh ca iu khin vng kn. i vi MM440, nhit ca ng c ch o c nh s dng b sensor KTY84. i vi gi tr thng s P0601 = 0,1, nhit ca ng c c tnh ton hoc c lng nh s dng m hnh nhit ng c. Nu bin tn lun lun c cp in p ngoi l 24 V, th nhit ng c cng c theo di/hiu chnh nh hng s thi gian nhit ca ng c, ngay c khi khi in p li tt. i vi phng php iu khin vng kn trong trng hp ng c ti ln nhit cao v khi ngun in li phi thng xuyn ng/ngt, th:

- Cn dng mt sensor KTY84 hoc - Cn ni mt ngun in p ngoi 24V.

b. iu khin vector c encoder (VC). Bc 1: Ci t thng s cho b encoder. Khi ci t ch iu khin vector c phn hi encoder (VC), u tin nn t h

truyn ng ch V/f ( xem thng s P1300). Cho chy h truyn ng v so snh r0061 vi r0021. Chng phi ging nhau v:

- Du.

P3900 = 0

Kt thc

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29 inh Hu Giang - 20111449

- Bin (vi sai lch nh ch bng vi %). Ch khi p ng hai iu kin trn, thay i P1300 v chn VC (P1300 = 21/23).

Khng c kch hot chc nng d tm mt tn hiu encoder (P0492 = 0) nu momen ti b gii hn bn ngoi, v d nh:

- iu khin vng kn my qun dy. - Ti chy ngang hoc di chuyn n im dng c nh. - Khi s dng phanh c kh ca ng c.

Gi tr im t momen b sung ch iu khin vector c/ khng c encoder, b iu khin tc c th ph

thuc vo lng momen b sung khng i hoc bin i. Gi tr im t b sung c th c dng h tr c cu nng h trong trng

hp ma st thc t ca h thp khi khi ng theo chiu thng ng. Gi tr b sung momen phi lun lun h tr hng nng ln (xin hy quan st du!). Nh c khi h xung, ch trt c thit lp v lm n nh thm ch iu khin vng kn (ti khng b tt nhiu).

Khi xc nh du ca gi tr im t momen b sung, phi ch cn thn v xem xt n tt c cc quy tc an ton lin quan. C th xc nh du ca gi tr im t momen b sung trong khu ci t nh sau: Nng ti c trng lng ti thiu s dng c cu nng v ghi li du t thng s r0079 (du ca r0079 tng ng vi du ca im t momen b sung).

Gi tr thc nghim ca momen b sung bng xp x 40% gi tr momen nh mc ng c r0333 m bo hot ng tt cho c cu nng (hy quan st du cn thn).

c.Phanh hm c kh ca ng c. Ci t cho cc ti nguy him. - H ti xung t. - Khi thay b bin tn, khng b bin tn thc hin chc nng iu khin phanh

hm c kh. - m bo an ton cho ti trng hoc dng hn vic iu khin ch hm ng c

( hm khng b iu khin), ri sau mi thc hin ci t nhanh v / hoc ti thng s xung nh cng c trn PC (v d nh phn mm STARTER hay AOP)

Ci t thng s cn bng trng lng i vi cc ng dng nng h - Thi gian t ha P0346 ln hn 0. - Tn s nh nht P1080 nn gn bng tn s trt ca ng c r0330 (

1080 0330P r ).

- Hiu chnh in p b tng theo ti. a)V/f ( P1300 = 0...3 ): P1310, P1311

b)SLVC ( P1300 = 20 ): P1610, P1611

Khng nu ch chn tn hiu trng thi r0052 bit 12 phanh hm ng c c kch hot gn cho P0731 P0733. Ngoi ra kch hot phanh hm ng c, thng s P1215 phi c t 1.

Khng c php dng phanh hm ng c lm phanh hot ng thng xuyn. V phanh ny thng thng ch c thit k cho mt s lng gii hn s ln phanh khn cp.

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Thi gian ng / m phanh c th c ly t ti liu th nghim ph hp. Cc gi tr in hnh di y c ly t ti liu th nghim Motor Catalog M11 2003/2004, trang 2/51:

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CHNG IV. M HNH TNH TON H THNG TRUYN NG IN.

4.1.M HNH TON HC NG C TRN H TA (d,q)

T h phng trnh (3.8) ta c:

1 1 1 1 1( )i

1 1 1 1 1( )i

(3.8)1

.

1

rqsd rdsd s sq s sd

s r r m m s

sq rqrdsq s sd s sq

s r m r m s

rd msd rd sl rq

r r

rq msq rq sl rd

r r

dii u

dt T T T L L L

dii u

dt T T L T L L

d Li

dt T T

d Li

dt T T

Ta ly Laplace h phng trnh trn ta thu c h phng trnh (5.1):

1 1 1 1 1( )

1 1 1 1 1( )

(5.1)1

1

rqrdsd sd s sq s sd

s r r m m s

rqrdsq sq s sd s sq

s r m r m s

mrd sd rd sl rq

r r

mrq sq rq sl rd

r r

pI I I UT T T L L L

pI I I UT T L T L L

Lp I

T T

Lp I

T T

Suy ra

1 1 1( 1)

1 1 1( 1)

1

0

rdsd sd s sq sd

sd r m s

rdsq sq s sd s sq

sq m s

mrd sd rd

r r

msq sl rd

r

T p I I UT T L L

T p I I UT L L

Lp I

T T

LI

T

vi 0rq

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32 inh Hu Giang - 20111449

Ta c h phng trnh (5.2)

1 1 1( 1)

1 1 1( 1)

(5.2)

1

( 1)

.

rdsd sd s sq sd

sd r m s

rdsq sq s sd s sq

sq m s

mrd sd

r

sq rsl

r sd

T p I I UT T L L

T p I I UT L L

LI

T p

I T p

T I

Trong : 1

1 1sd sq

s r

T T

T T

H s t tn tng: 2

1 m

s r

L

L L

Hng s thi gian stator: sss

LT

R

Hng s thi gian rotor: rrr

LT

R

Tuyn tnh ha quanh im lm vic

Ti im lm vic xc lp c: in p trn stator Usdo v Usqo, dng in Isqo v Isdo

tc quay so, t thng rotor rdo

Bin thin nh ca cc i lng trn tng ng l: Usd, Usq, Isq, Isd, s,

rd.

T h phng trnh (5.2) ta thu c h phng trnh (5.3) sau:

1 1 1( 1)

1 1 1( 1) ( ) (5.3)

1

rdsd sd so sq sqo s sd

sd r m s

sq sq so sd sdo s so rd rdo s sqsq m s

mrd sd

r

T p I I I UT T L L

T p I I I UT L L

LI

T p

Ta c phng trnh Momen nh sau: 3

2

mp rd sq

r

LM p I

L

Tuyn tnh ha quanh im lm vic ta c: 3

( . . )2

mp sqo rd rdo sq

r

LM p I I

L

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33 inh Hu Giang - 20111449

Phng trnh c tnh theo knh d: ( n gin ta loi b cc bin thin nh trn trc q:

Isq):

1 1 1

( 1).

sd sd sd sqo s rdsd s r m

T p I U IT L T L

(5.4a)

Phng trnh c tnh theo knh q: ( n gin ta loi b cc bin thin nh trn trc d:

Isd v rd):

1 1 1

( 1) ( )sq sq sq sdo rdo ssq s m

T p I U IT L L

(5.4b)

T 2 phng trnh (5.4a,b) v 1

mrd sd

r

LI

T p

ta xy dng c s cu trc ca

h thng nh sau:

Vi 1

L sdo rdom

K IL

Hnh 4.1.M hnh ton hc ng c trn h ta (d,q).

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CHNG V: XY DNG CU HNH HAI MCH VNG IU KHIN

5.1.MCH VNG IU KHIN DNG IN. a. Mch vng iu khin dng in Isd.

Mch vng iu khin dng in Isd nh hnh 5.1

*isdU Uisd Isd

(-)

Hnh 5.1.M hnh mch vng iu khin dng in Isd

i tng iu khin c hm truyn t:

( . . ) / ( )W

(1 . )(1 .p)(1 T . )

bd sd id sdt

bd sd i

K T K L

T p T p

Trong :

*

3

38038

10

101,6496( / )

6,0619

1 10,000125( )

2 2.4.10

0.001( )

dbd

Iid

sddm

bdx

i

UK

U

UK V A

I

T sf

T s

Risd

X

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35 inh Hu Giang - 20111449

Tnh ton Tsd

2 2

2

0,0954 0,0096 0,105( )

0,09541 1 0,1745

0,105

0,1050,0221( )

4,7498

0,1050,04136( )

2,5385

1 10,00267( )

1 1 1 1 0,1745

0,1745.0,0221 0,1745.0,04136

s r m s

m

s r

ss

s

rr

r

sd sq

s r

L L L L H

L

L L

LT s

R

LT s

R

T T s

T T

L

0,1745.0,105 0,0183s

Vi hng s thi gian Tbd rt nh so vi Tsd Hm truyn ca i tng tr thnh:

( . . ) / ( ) 38.0,00267.1,6496 / 0,0183W

(1 .p)(1 T . ) (1 0,00267.p)(1 0,001

9,

. ) (1 0,00267.p)(1

1458

0,001. )

bd sd id sdt

sd i

K T K L

T p p p

Nh vy s s c dng nh sau

*isdU Isd

(-)

Hnh 5.2. M hnh ti gin mch vng iu khin dng in Isd

Tng hp theo tiu chun ti u modun th hm chun:

2 2

1

1 2 .p 2 .pchF

Trong = min(Tsd, Ti) = Ti = 0.001(s).

Suy ra hm truyn b iu khin dng in Isd:

.p 1

.p

a

sd

b

TRi

T

Khu t l tch phn PI

Ta c 2 2

1

1 2 .p 2 .pchF

T T

Risd X

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Hm truyn t h ca mch vng dng in Isd l:

1 . ( . . ) / ( )

. .. (1 . )(1 . )

a bd sd i s

h i

b sd i

T p K T K LF R P

T p T p T p

Chn Ta = Tsd b hng s thi gian ln ( . . ) / ( )1 1

. .. (1 . ) . (1 )

bd sd i s

h

b i b s

K T K L KF

T p T p T p pT

vi ( . . ) / ( 9,1458)bd sd i sK K T K L

Suy ra: 2

1

11 .p .p

h

k

b b sdh

FF

T T TF

K K

Fk = Fch ta chn Tb/K = 2. v Tb.Tsd/K = 22

Chn = Ti = 0,001 => Tb/K=2.0,001=0,002

Tb = 0,002.9,1458= 0,01829

Ta = Tsd = 0,00267

B iu khin dng in Isd : .p 1 0,00267. 1

.p 0,01829.i

b

Ta pR

T p

b. Mch vng iu khin dng in Isq

Mch vng iu khin dng in Isq

*isqU Uisq Isq

(-)

Hnh 5.3. M hnh mch vng iu khin dng in Isq

i tng iu khin c hm truyn t:

( . . ) / ( )

W(1 . )(1 .p)(1 T . )

bd sq iq sdt

bd sq i

K T K L

T p T p

Risq

X

n Chuyn Ngnh

37 inh Hu Giang - 20111449

Trong :

*

max

3

38038

10

101,201( / )

4,1633.2

1 10,000125( )

2 2.4.10

0.001( )

dbd

Iiq

sq

bdx

i

UK

U

UK V A

I

T sf

T s

Nh cc tnh ton mch vng dng in Isd ta c:

0,00267

0,0183

sq

s

T

L

Vi hng s thi gian Tbd rt nh so vi Tsq Hm truyn ca i tng tr thnh:

( . . ) / ( ) 38.0,00267.1,201/ 0,0183

(1 .p)(1 T . ) (1 0,00267.p)(1 0,001. ) (1 0,00267.p)(

6,658

1 0,0 1. )

6

0

bd sq iq sdt

sq i

K T K LW

T p p p

Nh vy s s c dng nh sau

*isqU Isq

(-)

Hnh 5.4. M hnh ti gin mch vng iu khin dng in Isq

Tng hp theo tiu chun ti u modun th hm chun:

2 2

1

1 2 .p 2 .pchF

Trong = min(Tsd, Ti) = Ti = 0.001(s).

Suy ra hm truyn b iu khin dng in Isq :

.p 1

.p

a

sq

b

TRi

T

Khu t l tch phn PI

Ta c 2 2

1

1 2 .p 2 .pchF

T T

Risq

X

n Chuyn Ngnh

38 inh Hu Giang - 20111449

Hm truyn t h ca mch vng dng in l:

( . . ) / ( )1 .

. .. (1 . )(1 . )

bd sq iq sa

h i

b sq i

K T K LT pF R P

T p T p T p

Chn Ta = Tsq b hng s thi gian ln ( . . ) / ( )1 1

. .. (1 . ) . (1 )

bd sq iq s

h

b i b s

K T K L KF

T p T p T p pT

vi ( . . ) / ( 6,6586)bd sq iq sK K T K L

Suy ra: 2

1

11 .p .p

h

k

b sqh b

FF

T TF T

K K

Fk = Fch ta chn Tb/K = 2. v Tb.Tsq/K = 22

Chn = Ti = 0,001 => Tb/K=2.0,001=0,002

Tb = 0,002.6,6586 = 0,01332

Ta = Tsq = 0,00267

B iu khin dng in Isq : .p 1 0,00267. 1

.p 0,01332.i

b

Ta pR

T p

n Chuyn Ngnh

39 inh Hu Giang - 20111449

5.2. MCH VNG IU KHIN TC . Vi gi thit chng IV khi tng hp vng iu khin theo knh q: ( n gin

ta loi b cc bin thin nh trn trc d: Isd v rd).

Khi :

23 3

.2 2

m mp rdo sq p sq sdo

r r

L LM p I p I I

L L

vi vic b qua ,sqo rdI v . 0,0954.6,0619 0,5783.0 1

mrdo sdo m sdo

r

LI L I

T

Ta c s mch vng iu khin tc nh sau:

Hnh 5.5.M hnh mch vng iu khin tc

Hm truyn tng ng ca mch vng dng in Isq:

2 2

1

1 2 .p 2 .pRisq

i i

FT T

vi Ti2 = 0.001

2 = 1.e

-6 rt nh => c th b qua

Suy ra: 1 1 1

1 2 .p 1 2.0,001.p 1 0,002Risq

i

FT p

M hnh ha cm bin tc :

nm = 940 rpm => 2 940

98,4366( / )60 9,55 9,55

n nrad s

10

98,43660,1016( / ( / ))dk

dm

UV radK s

chn Udk = 10 V.

Chn T = 0.005(s)

n Chuyn Ngnh

40 inh Hu Giang - 20111449

Hm truyn i tng iu khin

2 2

2

2

2

1 3 1 3 1 1 1W . . . . . . . . . . .

2 p 1 .p 2 p(1 2T p)(1 p)

3 1 1 1. . . . .

2 p[1 (2 )p 2 p ]

3 1 1 1. . . . . .

2 p[1 (2 )p]

m mdt Risq p sdo p sdo

i r r i i

mp sdo

r i i i

mp sdo

r i i

L K LF p I p I K

K L J T L K J T

Lp I K

L K J T T T T

Lp I K

L K J T T

Vi 2.Ti.T = 0,002.0,005=0,00001 rt nh => c th b qua

Hay Wp(1 . )

dt

K

p T

Vi 2 23 1 1 3 0,0954 1 1

. . . . .3. .6,0619. .0,1016. 18,18392 2 0,105 1,201 0,011

m

p sdo

r i

LK p I K

L K J

Trong : 3 3 0.0954

. .3. 4,088572 2 0.105

mp

r

Lp

L

V 2 0,002 0,005 0,007( )iT T T s

Ta c: 18,1839

Wp(1 0,007 )

dtp

l i tng cn iu khin l khu tch phn qun tnh bc 1

Chn hm chun: 2 2 3 3

1 4 .p

1 4 .p 8 .p 8 .pch

TF

T T T

Theo phng p ti u i xng.

Do qun tnh c ca mch vng iu chnh tc l rt ln nn trong trng hp ny ly

T = Tc l hng s thi gian c hc.

B iu khin: R, i tng iu khin Wdt

Hm truyn h kn l:

R .W

1 R .W

dt

k

dt

F

Suy ra 2 2 3 3

2 2 3 3

2 2 3 3

4 . 1

1 4 .p 8 .p 8 .p (4 . 1)1.

1 W 4 . 1 .(8 .p 8 .p )W . 1.( 1)1 4 .p 8 .p 8 .p

c

k c c c c

k dt cc cdt

c c c

T p

F T T T T pR

KF T p T Tp TpT T T

Suy ra 3 2 2 2

(4 . 1).( 1) 1 (4 ).p

.(8 .p 8 .p) 8 . .p

c c

c c c

T p Tp T TR

K T T K T

n Chuyn Ngnh

41 inh Hu Giang - 20111449

Chn Tc = 0,2 ta c b iu khin 21 (4.0,2 0,007).p 1 0,807.

5,8188.8.18,1839.0,2 .p

pR

p

5.3.TNG HP CU TRC IU KHIN HON CHNH. Theo kt qu mc 5.2.a ta c:

4,1633

0,0954

0,1745

0,04136( )

0,00267

0,0183

. 0,0954.6,0619 0,5783

sqo

m

r

sd sq

s

rdo m sdo

I

L

T s

T T

L

L I

Tnh ton cc thng s c trong s cu trc:

2

1

1 1 0,1745

. . 0,1745.0,04136.0,091198.927

0,0954

. 1 0,04136. 1

54

m

r

r m

G

L

T p p

L

G

T

34.

3 3 0.0954. .3. 4,08857

2 2 0.105

1 1 0,17456,0619 .0,5783

0,1745.0,7

09384(

54)

mp

r

L sdo rdom

Lp

L

K IL

A

Thut ton tnh ton tc quay trong h ta (d,q):

s slip

ch xc lp th:

S khi tnh ton s

Hnh 5.6. S khi tnh ton s

sqslip

r sd

I

T I

n Chuyn Ngnh

42 inh Hu Giang - 20111449

CHNG VI:

M PHNG H THNG TRN MATLAB SIMULINK

6.1. MCH VNG IU KHIN TNG HP.

Sau khi m phng ta thm khu Ramp vo sau gi tr t v hiu chnh li b iu

khin R vi thnh phn I gim i 10 ln. Thu c kt qu nh sau:

Hnh 6.1. Mch vng tng hp.

Khu tnh ton s c cu trc nh sau:

Hnh 6.2.Khu tnh ton s

n Chuyn Ngnh

43 inh Hu Giang - 20111449

p ng khi c ti: Mc = 50%Mdm ng vo giy th 5 sau khi khi ng.

Hnh 6.3.p ng tc (c ti)

Hnh 6.4.p ng dng in Isq (c ti)

n Chuyn Ngnh

44 inh Hu Giang - 20111449

Hnh 6.5.p ng Momen (c ti)

Hnh 6.6.p ng dng in Isd (c ti)

n Chuyn Ngnh

45 inh Hu Giang - 20111449

KT LUN

Qua chng minh l thuyt v m phng trn Matlab Simulink em chng minh c cc kt qu l thuyt v phng php m phng ng.

Tuy nhin, b iu khin em tm ra vn cn nhng hn ch vi nhng yu cu cng ngh cn thi gian p ng ca h nhanh hn, nhng qua y cng gip em tng hp c nhng kin thc trn lp mnh c ging dy.

n Chuyn Ngnh

46 inh Hu Giang - 20111449

TI LIU THAM KHO

[1] Bi Quc Khnh & Nguyn Vn Lin, C s Truyn ng in, NXB khoa hc k thut 1994.

[2] Bi Quc Khnh, Nguyn Vn Lin, Phm Quc Hi & Dng Vn Ngh, iu chnh t ng truyn ng in, NXB khoa hc l thut 2008.

[3] Nguyn Don Phc, L thuyt iu khin tuyn tnh, NXB khoa hc k thut.

[4] Nguyn Phng Quang, iu khin t ng truyn ng in xoay chiu ba pha, NXB Gio Dc 1998.

[5] Nguyn Phng Quang, Matlab & Simulink dnh cho k s iu khin t ng, NXB Khoa hc l thut 2005.

[6] Trn Trng Minh, V Hong Phng, Bi ging Thit k cho cc b bin i in t cng sut.

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