biến tần siemens MM440

MICROMASTER 4400,12 kW 250 kWHng dn vn hnh Thng 07/05

Ti liu cho ngi lp my

Cnh bo, Lu v Ch

Thng 7/05

Cnh bo, lu v ch Cc cnh bo, lu v ch c a ra m bo an ton cho ngi s dng v trnh h hi cho sn phm hoc cc b phn ca thit b c ni. Cc cnh bo, lu v ch c th p dng cho tng hot ng c lit k phn u ca cc chng lin quan v c nhc li hoc b sung ti cc im quan trng trong cc phn ny. Hy c thng tin cn thn, v n gip bo v an ton cho bn thn ngi s dng v cng s gip ko di tui th ca b bin tn MICROMASTER 440 v cc thit b i km. CNH BO Thit b ny c mc in p nguy him v iu khin cc b phn c kh quay c nguy him cao. Nu khng tun theo cc cnh bo hoc khng thc hin theo cc hng dn trong ti liu ny th s nh hng n tui th ca my, gy nguy him cho ngi s dng hoc thit hi ln v ti sn. Ch ngi no c trnh chuyn mn ph hp mi c vn hnh thit b ny, v ch sau khi nm c tt c cc ch an ton, cc quy trnh ci t, vn hnh v bo dng trong ti liu ny. vn hnh c thit b tt v an ton ph thuc vo vic thao tc, lp t, vn hnh v bo dng hp l. T trn mch lc vn cn in trong vng 5 pht sau khi tt ngun nn khng c php m thit b trong khong thi gian ny. Cc t in t phng in trong khong thi gian ny. Thit b ny c kh nng bo v qu ti ng c theo UL508C phn 42. Theo thng s P0610 v P0335, i2t c bt theo mc nh. Cng c th bo v qu ti ng c bng PTC hoc KTY84 bn ngoi (khng kch hot theo mc nh bng thng s P0601). Thit b ny dng ph hp trong mch c dng khng qu 10000 A, in p ln nht 230 V / 460V / 575V khi c bo v bi cc cu ch loi H, J, K, p-t-mt hoc b iu khin ng c c bo v. Ch dng dy ng Loi 1 60/75 oC c tit din c ghi c th trong ti liu hng dn vn hnh. Cc u vo chnh, DC v cc u ni ng c c th c in p nguy him ngay c khi bin tn khng hot ng. Lun lun ch 5 pht thit b phng ht in sau khi tt ngun trc khi thc hin bt k ci t no. CH Hy c cc hng dn an ton, cc cnh bo v tt c cc nhn cnh bo gn trn thit b cn thn trc khi thc hin lp t v ci t. Hy gi tt c cc nhn cnh bo cn thn c th d dng c c v hy thay cc nhn b mt hoc b hng. Nhit mi trng xung quanh cho php ln nht l: - C v A-F: 500C mmen khng i (CT) v dng in ra cho php 100%. 400C mmen thay i (VT) v dng in ra cho php 100%. - C v FX v GX: 400C vi dng in ra cho php 100%.

2

Mc lc

Thng 7/05

Mc lc1 1.1 1.2 2 2.1 2.2 2.3 2.4 3 3.1 4 4.1 4.2 4.3 5 5.1 5.2 6 6.1 6.2 6.3 6.4 6.4.1 6.4.2 6.4.3 6.4.4 6.4.5 6.4.6 6.4.7 6.4.8 6.4.9 6.4.10 6.4.11 6.4.12 6.4.13 6.4.14 6.4.15 6.4.16 6.4.17 6.4.17.1 6.4.17.2 6.4.18 6.4.18.1 6.4.18.2 6.4.18.3 6.4.18.4 Lp t c kh........................................................................................................................... 5 Khong cch lp t ...................................................................................................................5 Kch thc lp t.......................................................................................................................5 Lp t phn in .................................................................................................................... 6 Cc thng s k thut ..................................................................................................................6 Cc u ni mch lc .............................................................................................................. 13 Cc u dy iu khin............................................................................................................ 21 S nguyn l ....................................................................................................................... 22 Ci t mc nh .................................................................................................................... 23 Kho chuyn i DIP 50/60 HZ ............................................................................................... 23 Truyn thng .......................................................................................................................... 24 Thit lp truyn thng MICROMASTER 440 Phn mm STARTER .................................. 24 Thit lp truyn thng MICROMASTER 440 AOP.............................................................. 24 Giao din BUS (CB) ................................................................................................................. 25 BOP/AOP (Tu chn) ............................................................................................................. 26 Cc nt v cc chc nng ....................................................................................................... 26 Thay i cc thng s .............................................................................................................. 27 Ci t thng s ..................................................................................................................... 28 Ci t thng s nhanh ............................................................................................................ 28 Nhn dng ng c ................................................................................................................. 32 Dng t ho ............................................................................................................................. 32 Ci t ng dng ..................................................................................................................... 34 Giao din ni tip ..................................................................................................................... 34 Chn ngun lnh...................................................................................................................... 34 u vo s (DIN) ..................................................................................................................... 35 Cc u ra s (DOUT) ............................................................................................................. 36 Chn gi tr im t tn s ..................................................................................................... 37 u vo tng t (ADC).......................................................................................................... 38 u ra tng t (DAC) ............................................................................................................ 39 Chit p xung (MOP) ............................................................................................................... 40 Tn s c nh (FF).................................................................................................................. 41 Chy nhp................................................................................................................................ 42 B pht hm to dc (RFG)................................................................................................ 43 Cc tn s quy chiu / gii hn ............................................................................................... 44 Bo v b bin tn ................................................................................................................... 45 Bo v nhit ng c ............................................................................................................... 45 Encoder .................................................................................................................................... 47 iu khin V/f........................................................................................................................... 48 iu khin nh hng trng (FCC)...................................................................................... 50 iu khin vect khng sensor (SLVC)................................................................................... 51 iu khin vect c encoder (VC)........................................................................................... 53 Cc chc nng c th ca bin tn ......................................................................................... 55 Khi ng bm......................................................................................................................... 55 T khi ng............................................................................................................................ 55 Phanh hm c kh ca ng c............................................................................................... 56 Hm mt chiu (DC) ................................................................................................................ 58

MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

3

Thng 7/05 6.4.18.5 6.4.18.6 6.4.18.7 6.4.18.8 6.4.18.9 6.4.19 6.4.20 6.5 6.6 7 7.1 7.2 8

Mc lc Hm hn hp ........................................................................................................................... 59 Hm ng nng........................................................................................................................ 60 B iu khin Vdc .................................................................................................................... 60 B iu khin PID .................................................................................................................... 61 Cc khi chc nng t do (FFB) ............................................................................................. 62 Tp d liu lnh v truyn ng .............................................................................................. 63 Thng s chn on ................................................................................................................ 66 Ci t ni tip ......................................................................................................................... 67 Ci t li cc thng s mc nh ............................................................................................ 67 Cc ch hin th v cnh bo .......................................................................................... 68 Hin th trng thi LED ............................................................................................................. 68 Cc thng bo li v cnh bo ................................................................................................ 69 Danh mc Thut ng vit tt ................................................................................................ 70

4


1 Lp t c kh

Thng 7/05

1 Lp t c kh1.1 Khong cch lp tCc b bin tn c th c lp st nhau. Trong t iu khin, khi lp cc b bin tn thnh cc hng theo chiu thng ng, cc iu kin mi trng khng c vt qu gii hn cho php. Ngoi ra cng cn phi lu cc khong cch ti thiu thng gi: C v A, B, C khong cch pha trn v pha di ti thiu:100mm C v D khong cch pha trn v pha di ti thiu:300mm C v F khong cch pha trn v pha di ti thiu:350mm C v FX, GX khong cch ti thiu pha trn: 250mm pha di: 150mm pha trc:40mm (FX), 50mm (GX)

1.2 Kch thc lp tKch thc l khoan H W mm (Inch) mm (Inch) 160 (6.30) 174 (6.85) 138 (5.43) 204 (8.03) 174 (6.85) 486 (19.13) 235 (9.25) 616,4 (24.27) 235 (9.25) 810 (31.89) 300 (11.81) 1375,5 (54.14) 1508,5 (59.38) 250 (9.84) 250 (9.84) Mmen xit Bulng Nm (ibf.in) 2xM4 2,5 (22.12) 4xM4 4xM5 4xM8 4xM8 4xM8 6xM8 6xM8

C v A B C D E F FX GX

3,0 (26.54)

13,0 (115,02) 13,0 (115,02)

Hnh 1-1 Cc kch thc lp t


5

Thng 7/05

2 Lp t phn in

2 Lp t phn in2.1 Cc thng s k thutDi in p u vo 1 AC 200 V- 240 V, 10% (Khng c b lc v c km b lc cp A) M hiu t hng6SE64402AB 2UC 11 2AA1 12 5AA1 13 7AA1 15 5AA1 17 5AA1 21 1BA1 21 5BA1 22 2BA1 23 0CA1

C v Cng sut nh mc CT Cng sut u ra Dng in vo CT -1 Dng in ra CT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng (khi km b lc cp A) Trng lng (khi khng c b lc) Mmen xit cho cc u mch lc

[kW] [kVA] [A] [A] [A] 3NA

0,12 0,4 0,9 3803 * 2,5 1,0 2,5 1,3 1,3

0,25 0,7 1,7 3803 * 2,5 1,0 2,5 1,3 1,3 1,1

A 0,37 1,0 4,6 2,3 3803 * 2,5 1,0 2,5 1,3 1,3

0,55 1,3 6,2 3,0 3805 * 16 2,5 1,0 2,5 1,3 1,3

0,75 1,7 8,2 3,9 3805 * 16 2,5 1,0 2,5 1,3 1,3 1,5

1,1 2,4 11,0 5,5 3807 * 14 6,0 1,0 6,0 3,4 3,3

B 1,5 3,2 14,4 7,4 3807 * 14 6,0 1,0 6,0 3,4 3,3

2,2 4,6 20,2 10,4 3812 * 12 6,0 1,0 6,0 3,4 3,3 2,25

C 3,0 6,0 35,5 13,6 3817 * 10 10,0 1,5 10,0 5,7 5,5

[mm2] [mm2] [mm2] [kg] [kg] [Nm]

1) Cc iu kin th cp: Dng in ti im hot ng nh mc p dng cho ngun c in p ngn mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 240V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 55% n 70%.

6


2 Lp t phn in

Thng 7/05

Di in p u vo (c km b lc cp A) M hiu t hng

3 AC 200 V- 240 V, 10%

6SE6440-

2AC230CA1

2AC240CA1

2AC255CA1

C v Cng sut nh mc CT Cng sut u ra Dng in vo CT- 1 Dng in ra CT Dng in vo VT -1 Dng in ra VT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc

[kW] [kVA] [A] [A] [A] [A] [A] 3NA * [mm2] [mm2] [mm2] [mm2] [kg] [Nm]

3,0 6,0 15,6 13,6 25 3810 * 2,5 10,0 1,5 10,0 5,7

C 4,0 7,7 19,7 17,5 28,3 22,0 32 3812 * 4,0 10,0 4,0 10,0 5,7 2,25

5,5 9,6 26,5 22,0 34,2 28,0 35 3814 4,0 10,0 4,0 10,0 5,7



7

Thng 7/05

2 Lp t phn in

Di in p u vo M hiu t hng C v Cng sut nh mc CT Cng sut u ra Dng in vo CT- 1 Dng in ra CT Cu ch Khuyn co loi Theo chun UL

3 AC 200 V - 240 V, 10%6SE6440-

(Khng c b lc )

2UC11 2UC12 2UC13 2UC15 2UC17 2UC21 2UC21 2UC22 2UC23 -2AA1 -5AA1 -7AA1 -5AA1 -5AA1 -1BA1 -5BA1 -2BA1 -0CA1 A B C

[kW] [kVA] [A] [A] [A] 3NA

0,12 0,4 1,1 0,9 10 3803 * 1,0 2,5 1,0 2,5 1,3

0,25 0,7 1,9 1,7 10 3803 * 1,0 2,5 1,0 2,5 1,3 1,1

0,37 1,0 2,7 2,3 10 3803 * 1,0 2,5 1,0 2,5 1,3

0,55 1,3 3,6 3,0 16 3805 * 1,5 2,5 1,0 2,5 1,3

0,75 1,7 4,7 3,9 16 3805 * 1,5 2,5 1,0 2,5 1,3 1,5

1,1 2,4 6,4 5,5 20 3807 * 2,5 6,0 1,0 6,0 3,3

1,5 3,2 8,3 7,4 20 3807 * 2,5 6,0 1,0 6,0 3,3

2,2 4,6 11,7 10,4 25 3810 * 2,5 6,0 1,0 6,0 3,3 2,25

3,0 6,0 15,6 13,6 25 3810 * 4,0 10,0 1,5 10,0 5,5

Tit din cp u vo min [mm2] Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng Mmen xit cho cc u mch lc [mm2] [mm2] [mm2] [kg] [Nm]

M hiu t hng C v Cng sut nh mc CT Cng sut u ra Dng in vo CT-1 Dng in ra CT Dng in vo VT- 1 Dng in ra VT- 1 Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit dn cp u ra max Trng lng Mmen xit cho cc u mch lc

6SE6440

2UC24 2UC25 2UC27 2UC31 2UC31 2UC31 2UC32 2UC33 2UC33 2UC34 -0CA1 -5CA1 -5DA1 -1DA1 -5DA1 -8EA1 -2EA1 -0FA1 -7FA1 -5FA1

C [kW] [kVA] [A] [A] [A] [A] [A] 3NA SNP [mm ] [mm2] [mm2] [kg] [Nm]2

4,0 7,7 19,7 17,5 28,3 22,0 32 3812 * 4,0 10,0 4,0 10,0 5,5

5,5 9,6 26,5 22,0 34,2 28,0 35 3814 * 4,0 10,0 4,0 10,0 5,5

7,5 12,3 34,2 28,0 38,0 42,0 50 3820

D 11,0 18,4 38,0 42,0 50,0 54,0 80 3824

E 15,0 23,7 50,0 54,0 62,0 68,0 80 3824 18,5 29,8 62,0 68,0 71,0 80,0 100 3830 22,0 35,1 71,0 80,0 96,0 104,0 125 3032 30,0 45,6 96,0 104,0 114,0 130,0 200 3140

F 37,0 57,0 114,0 130,0 135,0 154,0 200 3142

45,0 67,5 135,0 154,0 164,0 250 3144

1817 - 1820 - 1820 - 1021 - 1022 - 1225 - 1225 - 12270 0 0 0 0 0 0 0

10,0 35,0 10,0 35,0 17,0

16,0 35,0 16,0 35,0 16,0

16,0 35,0 16,0 35,0 16,0 10

25,0 35,0 25,0 35,0 20,0

25,0 70,0 70,0 95,0 35,0 150,0 150,0 150,0 25,0 50,0 70,0 95,0 35,0 150,0 150,0 150,0 20,0 55,0 55,0 55,0 50

2,25


8


2 Lp t phn in

Thng 7/05

Di in p u vo (c km b lc cp A) M hiu t hng C v Cng sut nh mc CT Cng sut u ra Dng in vo CT- 1 Dng in ra CT Dng in vo VT- 1 Dng in ra VT- 1 Cu ch Khuyn co loi

3 AC 380 V- 480 V, 10%

6SE6440- 2AD22- 2AD23- 2AD24- 2AD25- 2AD27- 2AD31- 2AD312BA1 0BA1 0BA1 5CA1 5CA1 1CA1 5DA1

B [kW] [kVA] [A] [A] [A] [A] [A] 3NA 3NE [mm2] [mm2] [mm2] [kg] [Nm] 2,2 4,5 7,5 5,9 16 3805 * 1,5 6,0 1,0 6,0 3,4 3,0 5,9 10,0 7,7 16 3805 * 1,5 6,0 1,0 6,0 3,4 1,1 4,0 7,8 12,8 10,2 20 3807 * 2,5 6,0 1,0 6,0 3,4 5,5 10,1 15,6 13,2 17,3 20,2 20 3807 * 2,5 10,0 2,5 10,0 5,7

C 7,5 14,0 22,0 18,4 23,1 29,0 32 3812 * 4,0 10,0 4,0 10,0 5,7 1,5 11,0 19,8 23,1 26,0 33,8 39,0 35 3814 * 6,0 10,0 6,0 10,0 5,7

D 15,0 24,4 33,8 32,0 37,0 45,2 50 3820 1817-0 10,0 35,0 10,0 35,0 17,0 2,25

Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng Mmen xit cho cc u mch lc M hiu t hng C v Cng sut nh mc CT Cng sut u ra Dng in vo CT- 1 Dng in ra CT Dng in vo VT- 1 Dng in ra VT- 1 Cu ch Khuyn co loi Theo chun UL Tit din u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng Mmen xit cho cc u mch lc

6SE6440- 2AD31- 2AD32- 2AD33- 2AD33- 2AD34- 2AD35- 2AD378DA1 2DA1 0EA1 7EA1 5FA1 5FA1 5FA1

D [kW] [kVA] [A] [A] [A] [A] [A] 3NA 3NE [mm2] [mm2] [mm2] [mm2] [kg] [Nm] 18,5 29,0 37,0 38,0 43,0 45,0 63 3822 10,0 35,0 10,0 35,0 17,0 22,0 34,3 43,0 45,0 59,0 62,0 80 3824 16,0 35,0 16,0 35,0 17,0 10 30,0 47,3 59,0 62,0 72,0 75,0 100 3830 25,0 35,0 25,0 35,0 22,0

E 37,0 57,2 72,0 75,0 87,0 90,0 125 3832 25,0 35,0 25,0 35,0 22,0 45,0 68,6 87,0 90,0 104,0 110,0 160 3836 35,0 150,0 50,0 150,0 75,0

F 55,0 83,8 104,0 110,0 139,0 145,0 200 3140 70,0 150,0 70,0 150,0 75,0 50 75,0 110,5 139,0 145,0 169,0 178,0 250 3144 95,0 150,0 95,0 150,0 75,0

1818-0 1820-0 1021-0 1022-0 1224-0 1225-0 1227-0

1) Cc iu kin th cp: Dng in ti im hot ng nh mc p dng cho ngun c in p ngn mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 400V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 70% n 80%. MICROMASTER 440 Hng dn vn hnh (Bn rt gn) 9

Thng 7/05

2 Lp t phn in

M hiu t hng

6SE6440-

2UD13 2UD15 2UD17 2UD21 2UD21 2UD22 2UD23 2UD24 2UD25 2UD27 -7AA1 -5AA1 -5AA1 -1AA1 -5AA1 -2BA1 -0BA1 -0BA1 -5CA1 -5CA1

C v Cng sut ra nh mc CT Cng sut ra nh mc Dng in vo CT- 1 Dng in ra CT Dng in vo VT 1) Dng in ra VT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc Di in p u vo M hiu t hng C v Cng sut ra nh mc CT Cng sut ra nh mc Dng in vo CT 1) Dng in ra CT Dng in vo VT 1) Dng in ra VT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc

A [kW] [kVA] 0,37 0,9 0,55 1,2 0,75 1,6 1,1 2,3 1,5 3,0

B 2,2 4,5 3,0 5,9 4,0 7,8

C 5,5 10,1 7,5 14,0

[A] 2,2 [A] 1,3 [A] [A] [A] 10 [3NA] 3803 [3NE] * 2 [mm ] 1,0 [mm2] [mm ] [mm2] [kg] [Nm]2

2,8 3,7 4,9 1,7 2,2 3,1 10 10 10 3803 3803 3803 * * * 1,0 2,5 1,0 2,5 1,3 1,0 2,5 1,0 2,5 1,3 1,1 1,0 2,5 1,0 2,5 1,3

5,9 7,5 10,0 4,1 5,9 7,7 10 16 16 3803 3805 3805 * * * 1,0 2,5 1,0 2,5 1,3 1,5 6,0 1,0 6,0 3,3 1,5 6,0 1,0 6,0 3,3 1,5

12,8 15,6 22,0 10,2 13,2 19,0 17,3 23,1 19,0 26,0 20 20 32 3807 3807 3812 * * * 2,5 6,0 1,0 6,0 3,3 2,5 10,0 2,5 10,0 5,5 4,0 10,0 4,0 10,0 5,5

2,5 1,0 2,5 1,3

2,25

3 AC 380 V- 480 V, 10%6SE6440-

(khng km b lc)

2UD31- 2UD31- 2UD31- 2UD32- 2UD33- 2UD33- 2UD34- 2UD35- 2UD371CA1 5DA1 8DA1 2DA1 0EA1 7EA1 5FA1 5FA1 5FA1

[kW] [kVA] [A] [A] [A] [A] [A] [3NA] [3NE] [mm2] [mm2] [mm2] [mm2] [kg] [Nm]

C D E F 11,0 15,0 18,5 22,0 30,0 37,0 45,0 55,0 75,0 19,8 24,4 29,0 34,3 47,3 57,2 68,6 83,8 110,5 23,1 33,8 37,0 43,0 59,0 72,0 87,0 104,0 139,0 26,0 32,0 38,0 45,0 62,0 75,0 90,0 110,0 145,0 33,8 37,0 43,0 59,0 72,0 87,0 104,0 139,0 169,0 32,0 38,0 45,0 62,0 75,0 90,0 110,0 145,0 178,0 35 50 63 80 100 125 160 200 250 3814 3820 3822 3824 3830 3832 8036 3140 3144 * 1817-0 1818-0 1820-0 1321-0 1022-0 1224-0 1225-0 1227-0 6,0 10,0 10,0 16,0 25,0 25,0 35,0 70,0 95,0 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0 6,0 10,0 10,0 16,0 25,0 25,0 35,0 70,0 95,0 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0 5,5 16,0 16,0 16,0 20,0 20,0 56,0 56,0 56,0 2,25 10 50

1) Cc iu kin th cp:Dng in ti im hot ng nh mc p dng cho ngun c in p ngn mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 400V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 55% n 70%. 10 MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

2 Lp t phn in

Thng 7/05

Di in p u vo M hiu t hng

3 AC 380 V- 480 V, 10%6SE64402UD38 -8FA1 2UD41 -1FA1

(khng km b lc)2UD413GA1 2UD416GA1 2UD420GA1

C v Cng sut ra nh mc ( CT) Cng sut ra nh mc Dng in vo CT 1) Dng in ra CT Dng in vo VT 1) Dng in ra VT Cu ch Khuyn co loi Hp cp theo chun DIN 46235 Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc

[kW] [kVA] [A] [A] [A] [A] [A] [3NA] [mm] [mm2] [mm ] [mm ] [mm ] [kg] [Nm]2 2 2

FX GX 90 110 132 160 145,4 180 214,8 263,2 169 200 245 297 178 205 250 302 200 245 297 354 205 250 302 370 250 315 400 450 1227-0 1230-0 1332-0 1333-0 10 10 10 10 1x95 hoc 1x150 hoc 1x185 hoc 1x240 hoc 2x35 2x50 2x70 2x70 1x185 hoc 1x185 hoc 2x240 2x240 2x120 2x120 1x95 hoc 1x150 hoc 1x185 hoc 1x240 hoc 2x35 2x50 2x70 2x70 1x185 hoc 1x185 hoc 2x240 2x240 2x120 2x120 110 110 170 170 25

200 339,4 354 370 442 477 560 1435-0 10 2x95 2x240 2x95 2x240 170

1) Cc iu kin th cp:Dng in ti im hot ng nh mc p dng cho ngun c in p ngn mch Vk 2,33 % l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 400V trong trng hp khng c cun khng chuyn mch.


11

Thng 7/05

2 Lp t phn in

Di in p u vo M hiu t hng C v Cng sut ra nh mc ( CT) Cng sut ra nh mc Dng in vo CT 1) Dng in ra CT Dng in vo VT 1) Dng in ra VT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc M hiu t hng C v Cng sut ra nh mc CT Cng sut ra nh mc Dng in vo CT- 1 Dng in ra CT Dng in vo VT- 1 Dng in ra VT Cu ch Khuyn co loi Theo chun UL Tit din cp u vo min Tit din cp u vo max Tit din cp u ra min Tit din cp u ra max Trng lng M men xit cho cc u mch lc

3 AC 500 V- 600 V, 10%

(khng km b lc)

6SE6440- 2UE17- 2UE21- 2UE22- 2UE24- 2UE25- 2UE27- 2UE31- 2UE315CA1 5CA1 2CA1 0CA1 5CA1 5CA1 1CA1 5DA1 [kW] [kVA] [A] [A] [A] [A] [A] [3NA] [3NE] [mm2] [mm2] [mm2] [mm2] [kg] [Nm]

C 0,75 1,5 2,2 4,0 5,5 1,3 2,6 3,7 5,8 8,6 2,0 3,7 5,3 8,1 11,1 1,4 2,7 3,9 6,1 9,0 3,2 4,4 6,9 9,4 12,6 2,7 3,9 6,1 9,0 11,0 10 10 10 16 16 3803-6 3803-6 3803-6 3805-6 3805-6 * 1,0 10,0 1,0 10,0 5,5 * 1,0 10,0 1,0 10,0 5,5 * 1,0 10,0 1,0 10,0 5,5 * 1,5 10,0 1,0 10,0 5,5 2,25 * 1,5 10,0 1,0 10,0 5,5

D 7,5 11,0 15,0 10,5 16,2 21,0 14,4 21,5 24,9 11,0 17,0 22,0 18,1 24,9 30,0 17,0 22,0 27,0 25 32 35 3810-6 3812-6 3814-6 * 2,5 10,0 2,5 10,0 5,5 * 4,0 10,0 4,0 10,0 5,5 1803-0 6,0 35,0 4,0 35,0 16,0 10

6SE6440-

2UE31- 2UE32- 2UE33- 2UE33- 2UE34- 2UE35- 2UE378DA1 2DA1 0EA1 7EA1 5FA1 5FA1 5FA1 D E F

[kW] [kVA] [A] [A] [A] [A] [A] [3NA] [3NE] [mm2] [mm2] [mm2] [mm ] [kg] [Nm]2

18,5

22,0

30,0

37,0

45,0

55,0

75,0

25,7 30,5 39,1 49,5 59,1 73,4 94,3 30 35,0 48,0 58,0 69,0 83,0 113,0 27,0 32,0 41,0 52,0 62,0 77,0 99,0 35,0 48 58,0 69,0 83,0 113,0 138,0 32,0 41,0 52,0 62,0 77,0 99,0 125,0 50 63 80 80 125 160 160 3820-6 3822-6 3824-6 3824-6 3132-6 3136-6 3136-6 1817-0 1818-0 1820-0 1820-0 1022-0 1024-0 1224-0 10,0 10,0 16,0 25,0 25,0 50,0 50,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0 6,0 10,0 16,0 16,0 25,0 35,0 50,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0 16,0 16,0 20,0 20,0 56,0 56,0 56,0 10 50

1) Cc iu kin th cp:Dng in ti im hot ng nh mc p dng cho ngun c in p ngn mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn trong h truyn ng v in p li 500V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 80% n 90%.

12


2 Lp t phn in

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2.2 Cc u ni mch lcC th tip cn vi cc u ni ngun in vo v cc u ni ca ng c bng cch tho cc phn v my pha trc. C v A ( Hnh 2-1) C v B v C ( Hnh 2-2) C v D v E ( Hnh 2-3) C v F ( Hnh 2-4) C v FX v GX ( Hnh 2-5) Cc u ni ca c v A F ( Hnh 2-6) Tng quan v cch ni i vi c v FX (Hnh 2-7) Tng quan v cch ni i vi c v GX (Hnh 2-8)

C v A

Hnh 2-1 Tho phn mt trc v my (C v A)


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2 Lp t phn in

C v B v C

Hnh 2-2 Tho v phn trc v my (C v B v C)

14


2 Lp t phn in C c D v E

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Hnh 2-3 Tho phn trc v my ( C v D v E)


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2 Lp t phn in

C v F

Hnh 2-4 Tho phn trc v my (C v F) 16 MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

2 Lp t phn in

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C v FX v GX

Hnh 2-5 Tho phn trc v my (C v FX v GX)


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2 Lp t phn in

C th tip xc vi cc u ni ngun vo v cc u ni ng c bng cch tho cc phn v my pha trc.

C v A

C v B v C

C v D v E

C v F Hnh 2-6 Cc u ni cho cc c v t A F.

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2 Lp t phn in

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Cc l treo u ni mt cp u vo ngun lc PE Cc l cho cc cp mch lc U1/L1, V1/L2, W1/L3 i qua

Cc l cho cp DCPA, DCNA ni vi b hm ngoi i qua Cc u cp mch lc pha U1/L1, V1/L2, W1/L3u ni tu Y

Cc u ni cp DCPA, DCNA vi b hm ngoi

Thanh ray iu chnh pha trn ai c hm pha trn Cc u ni vi b lc dv/dt DCPS, DCNS

Bng hin th trng thi Hp cha mch iu khin Thanh ray iu chnh pha di ai c hm pha di Cc ai c qut Qut Tip a cc u dy iu khin

Cc cu ch qut Bin p qut Cp pha ng c U2, V2, W2 u ni mt cp ng c PE

Hnh 2-7 Hnh v tm lc cc u ni b bin tn c v FX


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2 Lp t phn in

Cc l treo

u ni mt cp u vo ngun lc PE Cc l cho cc cp mch lc U1/L1, V1/L2, W1/L3 i qua

Cc l cho cp DCPA, DCNA ni vi b hm ngoi i qua Cc u cp mch lc pha U1/L1, V1/L2, W1/L3 u ni t Y

Cc u ni cp DCPA, DCNA vi b hm ngoi Thanh ray iu chnh pha trn ai c hm pha trn Cc u ni vi b lc dv/dt DCPS, DCNS Bng hin th trng thi Hp cha mch iu khin Thanh ray iu chnh pha di ai c hm pha di Cc ai c qut Qut Tip a cc u dy iu khin Cc cu ch qut Bin p qut Cp pha ng c U2, V2, W2 u ni mt cp ng c PE

Hnh 2- 8 : Hnh v tm lc cc u ni b bin tn c v GX 20 MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

2 Lp t phn in

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2.3 Cc u dy iu khinu dy 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 K hiu ADC1+ ADC1DIN1 DIN2 DIN3 DIN4 ADC2+ ADC2DAC1+ DAC1PTCA PTCB DIN5 DIN6 DOUT1/NC DOUT1/NO DOUT1/COM DOUT2/NO DOUT2/COM DOUT3/NC DOUT3/NO DOUT3/COM DAC2+ DAC2P+ NChc nng u ngun ra +10V u ngun ra 0V u vo tng t s1(+) u vo tng t s 1(-) u vo s s 1 u vo s s 2 u vo s s 3 u vo s s 4 u ra cch ly +24V/max. 100 mA u vo tng t s 2 (+) u vo tng t s 2 (-) u ra tng t s 1 (+) u ra tng t s 1 (-) u dy ni cho PTC / KTY 84 u dy ni cho PTC / KTY 84 u vo s s 5 u vo s s 6 u ra s s 1/ tip im NC u ra s s 1/ tip im NO u ra s s 1/ chn chung u ra s s 2/ tip im NO u ra s s 2/ chn chung u ra s s 3/ tip im NC u ra s s 3/ tip im NO u ra s s 3/ chn chung u ra tng t s 2 (+) u ra tng t s 2 (-) u ra cch ly 0 V/max. 100 mA Cng RS485 Cng RS485

Hnh 2-9 Cc u dy iu khin ca MICROMASTER 440


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2 Lp t phn in

2.4 S nguyn l

Ngun ngoi 24V

Cch ly quang

C v t A n F

hoc

u ra +24V max.100mA (cch ly)u ra 0V max. 100mA (cch ly)

C v FX v GX

Bo v nhit ng c

Ni ti khi phanh in tr ngoi Ni ti b lc dv/dt

BKha DIP (trn bng iu khin)

30 V DC/ 5A (ti thun tr) 250 V AC/ 2 A (ti cm)

Dng in 020 mA in p 0-10 V

Kho chuyn tn s DIP (trn bng I/O)

t ng

Hnh 2-10 S nguyn l

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3 Ci t mc nh

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3 Ci t mc nhB bin tn MCROMASTER 440 c ci t mc nh khi xut xng sao cho c th vn hnh c m khng cn ci t thm bt k thng s no na. t c iu ny, cc thng s ca ng c c kt ni vi bin tn phi c thng s nh mc ph hp vi thng s ci t mc nh (P0304, P0305, P0307, P0310) tng ng vi ng c 1LA7 4 cc ca Siemens (hy xem cc thng s nh mc ghi trn nhn). Cc thng s mc nh khc: Cc ngun lnh P0700 = 2 (u vo s, xem hnh 3-1) Ngun im t P1000 = 2 (u vo tng t, xem hnh 3-1) Ch lm mt ng c P0335 = 0 Gii hn dng in P0640 = 150% u ra Tn s nh nht tng t P1080 = 0 Hz Tn s ln nht P1082 = 50 Hz Thi gian tng tc P1120 = 10 s Thi gian gim tc P1121 = 10 s Ch iu khin P1300 = 0 Hnh 3-1 Cc u vo gn mc nh u vo/ u ra u vo s 1 u vo s 2 u vo s 3 u vo s 4 u vo s 5 u vo s 6 u vo s 7 u vo s 8 Cc u ni 5 6 7 8 16 17 thng qua u tng t s 1 thng qua u tng t s 2 Thng s P0701 = 1 P0702 = 12 P0703 = 9 P0704 = 15 P0705 = 15 P0706 = 15 P0707 = 0 P0708 = 0 Chc nng ON/OFF1

(I/O)

o chiu Xa li im t c nh (trc tip) im t c nh (trc tip) im t c nh (trc tip) Khng s dng Khng s dng

3.1 Kho chuyn i DIP 50/60 HZTn s nh mc mc nh cho ng c ca b bin tn MICROMASTER l 50 Hz. i vi ng c c thit k chy tn s nh mc 60Hz, cc b bin tn c th c t tn s ny nh s dng kho chuyn DIP 50/60 Hz. V tr OFF: cc thng s mc nh ca Chu u (tn s nh mc ca ng c = 50 Hz, cng sut tnh theo kW) V tr ON: Cc thng s mc nh ca Bc M (tn s nh mc ca ng c = 60 Hz, cng sut tnh theo hp.).


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4 Truyn thng

4 Truyn thng4.1 Thit lp truyn thng MICROMASTER 440 Phn mm STARTER thit lp cc truyn thng gia phn mm STARTER v MICROMASTER 440, cn c thm cc b phn tu chn di y: B kt ni gia b bin tn vi PC BOP nu nh cc gi tr chun USS ca b bin tn MICROMASTER 440 thay i (xem phn 6.4.1 Giao din ni tip (USS)). B kt ni gia bin tn v PC MICROMASTER 440 Cc ch ci t USS, xem phn 6.4.1 Giao din ni tip (USS) Phn mm STARTER Vo Menu, chn Option chn Ci t Giao din PG/PC Chn Cng PC COM (USS) Vo Properties chn giao din COM1, chn tc baud (n v tc truyn d liu)

CH : Cc thng s ci t USS trong b bin tn MICROMASTER 440 phi ph hp vi ch ci t ca phn mm STARTER.

4.2

Thit lp truyn thng MICROMASTER 440 AOPTruyn thng gia AOP v MM440 da trn giao thc USS, tng t nh STARTER v MM440. Khc vi BOP, cc thng s truyn thng thch hp phi c ci t cho c MM440 v AOP nu nh qu trnh t ng d tm giao din khng thc hin c (xem bng 4-1). S dng cc thnh phn tu chn, AOP c th c kt ni vi cc giao din truyn thng khc nhau (xem bng 4-1). Bng 4-1 AOP ti ng truyn BOP Cc thng s MM440 - tc baud - a ch bus Cc thng s AOP - tc baud - a ch bus Tu chn - kt ni trc tip - kt ni gin tip P2010[1] P8553 Khng cn thit c tu chn Ph kin gn cnh t BOP/AOP (6SE6400-0PM00-0AA0) AOP ti ng truyn COM P2010[0] P2011 P8553 P8552 Khng th Ph kin gn cnh t BOP/AOP (6SE6400-0MD00-0AA0)

24


4 Truyn thng Khi AOP hot ng nh mt b iu khin Thng s/ u dy Ngun lnh P0700 P1000 P1035 P1036 im t tn s (MOP) AOP trn ng truyn BOP 4 1 2032.13 (2032.D) 2032.14 (2032.E)

Thng 7/05

AOP trn ng truyn COM 5 2036.13 (2036.D) 2036.14 (2036E)

Tng tn s t MOP Gim tn s t MOP Xa li P2104 2032.7 2036.7

Li c th c gii tr thng qua AOP m khng ph thuc vo P0700 hoc P1000

4.3 Giao din BUS (CB)Giao din BUS (CB)

M un DeviceNet P0918

M un CANopen P0918

M un PROFIBUS P0918*)Tc baud c b bin tn xc nh t ng

P2040 P2041 P2051

P2040 P2041 P2051

P2040 P2041 P2051

* Cn quan st kho chuyn mch DIP dng xc nh phn cng M un DeviceNet Chiu di PZD Gi tr trng thi/ thc Chiu di PZD iu khin/ im t Tc P2041[2] P2041[3] P2041[4] 0:125 kbaud 1:250 kbaud 2:500 kbaud M un CANopen Kiu truyn d liu t T_PD0_1, T_PD0_5 Kiu truyn d liu T_PD0_6 R_PD0_1 R_PD0_5 R_PD0_6 Xc nh ng truyn CANopen MM4 Xc nh ng truyn CANopen MM4 - pht hin cc li truyn thng - tc baud M un PROFIBUS

P2041[0] P2041[1]

-Khng cn ci t (tr cc trng hp c bit). Hy xem cc hng dn vn hnh m un tu chn PROFIBUS

Chn on -


25

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5 BOP/AOP (Tu chn)

5 BOP/AOP (Tu chn)5.1 Cc nt v cc chc nngBng iu khin/ Nt Chc nng Hin th trng thi ngha Mn hnh LCD hin th cc ch ci t hin hnh ca b bin tn. n nt ny lm cho b bin tn khi ng. Nt ny khng tc dng mc nh Kch hot nt: BOP: P0700 = 1 hoc P0719 = 1016 AOP: P0700 = 4 hoc P0719 = 4046 trn ng truyn BOP P0700 = 5 hoc P0719 = 5056 trn ng truyn COM OFF1

Khi ng b bin tn

n nt ny khin ng c dng theo c tnh gim tc c chn. Kch hot nt: hy xem nt Khi ng b bin tn. Dng b OFF2 n nt ny hai ln (hoc n mt ln v gi mt khong thi gian) bin tn khin ng c dng t do. BOP: Nt ny lun lun c tc dng (khng ph thuc vo thng s P0700 hoc P0719) n nt ny lm ng c o chiu quay. o chiu c hin th bng du o chiu (-) hoc im chm nhy. Nt ny khng tc dng mc nh Kch hot nt: hy xem nt Khi ng b bin tn. trng thi sn sng chy, khi n nt ny, ng c khi ng v quay vi Chy nhp tn s chy nhp c ci t trc. ng c dng khi th nt ny ra. n ng c nt khi ng c ang lm vic khng c tc ng g. Nt ny c th dng xem thm thng tin Khi ta n v gi khong 2 giy nt ny hin th cc thng tin sau, bt u t bt k thng s no trong qu trnh vn hnh: 1. in p mt chiu trn mch DC (hin th bng d- n v V). 2. Dng in ra (A). 3. Tn s ra (Hz). 4. in p ra (hin th bng o- n v V). 5. Gi tr c chn trong thng s P0005 (Nu nh P0005 c ci t hin th bt k gi tr no trong s cc gi tr t1-4 th gi tr ny khng Nt chc c hin th li). nng n thm s lm quay vng cc gi tr trn bng hin th. n gi trong khong 2 giy quay v ch hin th thng thng. Chc nng nhy T bt k thng s no (v d rxxxx hoc Pxxxx), n nhanh nt Fn s ngay lp tc nhy n r0000, sau ngi s dng c th thay i thng s khc, nu cn thit. Nh tnh nng quay tr v r0000, n nt Fn s cho php ngi s dng quay tr v im ban u. Gii tr Nu xut hin cc cnh bo v cc thng bo li, th cc thng tin ny c th c gii tr bng cch n nt Fn. Truy nhp n nt ny cho php ngi s dng truy nhp ti cc thng s. thng s Tng gi tr n nt ny lm tng gi tr c hin th. Gim gi tr Trnh n AOP n nt ny lm gim gi tr c hin th. Gi trnh n AOP ngay lp tc (chc nng ny ch c AOP).

26


5 BOP/AOP (Tu chn)

Thng 7/05

5.2 Thay i cc thng sV d thng s P0004- b lc thng s Bc 1 2 3 4 5 6 n n n n n truy nhp thng s n khi P0004 c hin th ti cc mc gi tr thng s hoc t gi tr mong mun Kt qu hin th

xc nhn gi tr v lu li gi tr

Ngi s dng ch c th nhn thy cc thng s v lnh (bt u bng 7)


27

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6 Ci t thng s

6 Ci t thng s6.1 Ci t thng s nhanhB bin tn tng thch vi ng c nh s dng chc nng ci t thng s nhanh, v cc thng s k thut quan trng s c ci t. Ci t nhanh khng cn c thc hin nu thng s nh mc ca ng c ghi trong b bin tn FU (v d ng c tiu chun 1LA 4 cc ca Siemens) thch hp vi thng s nh mc ghi trn nhn ca ng c ang ni vo bin tn. Cc thng s c k hiu * c kh nng ci t nhiu hn cc kh nng c lit k di y. Hy xem danh sch thng s bit thm cc kh nng ci t khc.Bt u P0003 =3

Gi tr mc nh 1 Mc truy nhp ca ngi dng* 1 Mc c bn: Cho php truy nhp ti nhng thng s thng dng nht 2 M rng: V d truy nhp n cc cc chc nng I/O 3 Chuyn gia (ch dnh cho chuyn gia) Lc thng s * 0 Tt c cc thng s 2 Bin tn 3 ng c 4 Cm bin tc Ci t thng s * 0 Sn sng 1 Ci t nhanh 0

P0004 = 0

P0010 = 1

0

P0100 =

30 Ci t ti nh my Ch P0010 nn c 1 ci t thng s nh mc trn nhn ca ng c 0 Tiu chun Chu u/ Bc M 0 Chu u [KW], tn s mc nh 50Hz 1 Bc M [hp], tn s mc nh 60Hz 2 Bc M [kW], tn s mc nh 60Hz Ch i vi P0100 = 0 hoc 1, gi tr P0100 c xc nh khi ci t kho chuyn DIP 50/60 OFF = kW, 50 Hz ON = hp, 60Hz ng dng b bin tn (nhp vo kiu mmen yu cu) 0 0 Mmen khng i (v d thang my, my nn, my gia cng) 1 Mmen bin i (v d bm, qut) Ch Thng s ny ch c tc dng i vi b bin tn trong h truyn ng 5.5 kW / 400V 1 Chn kiu ng c 1 ng c khng ng b (hay ng c d b) 2 ng c ng b Ch i vi P0300 = 2 (ng c ng b), ch c php iu khin kiu V/f (P1300< 20)

P0205 = P0100 = 1,2

P0205 = P0100 = 0 P0300 =

P0300 =

28


6 Ci t thng s

Thng 7/05

P0304 =

P0304 =

P0305 =

P0305 =

P0307 =

P0307 =

P0308 = ...

P0308 =...

P0309 =

P0309 =

P0310 =

P0311 =

P0320 =

P0335 =

P0640 =

P0700 =

thng s FU in p nh mc ng c in p nh mc [V] ghi trn nhn ca ng c in p nh mc ghi trn nhn phi c kim tra, t bit c cu hnh mch Y/ m bo ph hp vi cch ni mch trn bng u ni ca ng c Dng in nh mc ng c thng s FU Dng in nh mc [A] ghi trn nhn ca ng c Cng sut nh mc ng c thng s FU Cng sut nh mc [kW/hp] ghi trn nhn ca ng c Nu P0100 = 0 hoc 2, gi tr tnh theo n V d mt loi nhn ghi thng s nh mc ca ng c in hnh (thng v kW Nu P0100 = 1, gi tr tnh theo n v hp s cho cu hnh mch ) thng s FU H s Cos nh mc ng c H s cng sut nh mc (cos) ghi trn nhn Nu nh ci t l 0, gi tr c t ng tnh ton Nu P0100 = 1,2 th P0309 khng c ngha nn khng cn nhp thng s FU Hiu sut nh mc ng c Hiu sut nh mc ca ng c theo [%] c ghi trn nhn Ci t l 0, gi tr c tnh bn trong Nu P0100 = 0 th P0309 khng c ngha, khng cn nhp 50.00Hz Tn s nh mc ng c Tn s nh mc ca ng c tnh theo [Hz] ghi trn nhn S i cc c t ng tnh ton li nu thng s thay i thng s FU Tc nh mc ng c Tc nh mc ca ng c tnh theo [v/ph] ghi trn nhn Ci t l 0, gi tr c tnh bn trong Ch : Cn phi nhp thng s trong trng hp iu khin vect mch kn, iu khin V/f vi FCC v b trt 0.0 Dng t ho ng c (Dng ny c nhp theo % ca P0305) Dng in t ho ng c tnh theo % P0305 (dng in nh mc ng c). Vi P0320 = 0, dng t ho ng c c tnh ton s dng P0340 = 1 hoc s dng P3900 = 1-3 (kt thc qu trnh ci t nhanh)- v c hin th trong thng s r0331. 0 Ch lm mt ng c (Chn h thng lm mt ng c) 0 Lm mt t nhin: S dng trc g qut c gn vi ng c 1 Lm mt cng bc: S dng qut lm mt cp ngun ring 2 Lm mt t nhin v qut bn trong 3 Lm mt cng bc v qut bn trong 150% H s qu ti ng c (H s qu ti ca ng c tnh theo [%] tng ng vi P0305) H s ny xc inh gii hn dng in vo ln nht bng % dng in nh mc ca ng c (P0305). Bng vic s dng P0205, thng s ny c ci t ti 150% i vi mmen khng i v ti 110% i vi mmen thay i Chn ngun lnh (nhp ngun lnh) 2 0 Ci t mc nh 1 BOP (bn phm) 2 u ni 4 USS trn ng chuyn BOP 5 USS trn ng chuyn COM (cc u ni 29 v 30) 6 CB trn ng chuyn COM (CB = mun truyn thng)


29

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6 Ci t thng s

BOP Cc u ni USS BOP link USS COM link CB COM link P1000 = Knh im t iu khin ng c P0700 = 2 iu khin tun t

La chn im t tn s * (nhp vo ngun im t tn s) 1 im t MOP 2 im t tng t 3 Tn s c nh 4 USS trn ng chuyn BOP 5 USS trn ng chuyn COM ( cc u dy iu khin 29 v 30) 6 CB trn ng chuyn COM ( CB l mun truyn thng) 10 Khng c im t chnh + im t MOP 11 im t MOP + im t MOP 12 im t tng t + im t MOP 76 CB trn ng chuyn COM + im t tng t 2 77 im t tng t 2 + im t tng t 2MOP ADC FF USS BOP link USS COM link CB COM link ADC2 im t b sung im t chnh Knh im t iu khin ng c iu khin tun t

2

P1080 =

P1082 =

P1120 =

P1121 =

0.00 Hz Tn s nh nht ( nhp tn s nh nht cho ng c, n v Hz) t tn s ng c nh nht ti ng c s chy m khng tnh n tn s im t. Gi tr c ci t y c tc dng cho c quay thun v quay ngc 50.00 Hz Tn s ln nht ( nhp tn s ln nht cho ng c, n v Hz) t tn s ng c ln nht ti ng c s chy m khng tnh n tn s im t. Gi tr c ci t y c tc dng cho c quay thun v quay ngc 10.00 s Thi gian tng tc ( nhp thi gian tng tc, n v s) Thi gian tng tc l thi gian ng c tng tc t im dng n im c tn s ln nht (P1082) khi khng dng cch tng tc c dng ng cong. Nu thi gian tng tc c ci t qu nh, iu ny c th lm xut hin cnh bo A0501 ( gi tr gii hn dng) hoc lm cho b bin tn ca h truyn ng b dng vi li F0001 (qu dng). 10.00 s Thi gian gim tc ( nhp thi gian gim tc, n v s) Thi gian gim tc l thi gian ng c gim tc t im c tn s ln nht (P1082) n im dng khi khng dng cch gim tc c dng ng cong. Nu thi gian tng tc c ci t qu nh, iu ny c th lm xut hin cc cnh bo A0501 ( gi tr gii hn dng), A0502 (gi tr gii hn qu p) hoc lm cho b bin tn ca h truyn ng b dng vi cc li F0001 (qu dng) hoc F0002 (qu p). MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

30

6 Ci t thng s

Thng 7/05

P1135 =

P1300 =

P1500 =

P1910 = P 1960 =

P 3900 =

5.00 s OFF3 Thi gian gim tc ( nhp thi gian gim tc dng nhanh bng s) V d nhp thi gian ng c gim t tn s ln nht P1082 xung trng thi dng hn thc hin lnh OFF3 (dng nhanh). Nu t thng s thi gian gim tc qu thp th s xut hin n bo A0501 (gi tr dng in gii hn), A0502 (gi tr in p vt qu gi tr cho php) hoc khng hot ng c do b li F0001 (qu dng) hoc F0002 (qu in p). 0 Mode iu khin ( Nhp mode iu khin theo yu cu) 0 V/f kiu tuyn tnh 1 V/f FCC 2 V/f kiu ng parabol 3 V/f kiu c th lp trnh c 5 V/f cho cc ng dng kiu my dt 6 V/f kiu FCC cho cc ng dng kiu my dt 19 V/f ch iu khin qua im t hiu in th c lp 20 Ch iu khin vect khng sensor 21 Ch diu khin vector c sensor 22 iu khin mmen xon vector khng sensor 23 iu khin mmen xon vector c sensor 0 Chn im t mmen xon* (nhp ngun cho im t mmen xon) 0 Khng c im t chnh 2 im t kiu tng t 4 USS trn ng truyn BOP 5 USS trn ng truyn COM ( Cc u iu khin 29 v 30) 6 CB trn ng truyn COM (CB: mun truyn thng) 7 im t kiu tng t 2 0 Chn d liu cho ng c* 0 Khng hot ng 0 Ti u ho thit b iu khin tc 0 Hm ti u ho thit b iu khin tc , phi bt ch iu khin vect vng kn (P1300=20 hoc 21). Sau khi chn xong ch ti u ho (P1960 =1), th n bo A0542 khng hin th. 0 Kt thc qu trnh ci t nhanh thng s ( bt u qu trnh tnh ton ng c) 0 Khng ch ci t nhanh thng s (khng c qu trnh tnh ton mt) Qu trnh tnh ton cc thng s ca ng c v t li tt c cc thng s khc theo 1 ch ca nh my, nhng thng s khng c trong qu trnh ci t nhanh (gn "QC"= 0) Qu trnh tnh ton cc thng s mt v ci t li ch I/O theo ch nh 2 mc 3 Ch tnh ton cc thng s ca mt. Khng ci t lai cc thng s khcCH

Vi P3900= 1,2,3 Kt thc

P0340 t t ti 1 v cc d liu ph hp c tnh ton.

Kt thc ci t nhanh Nu mun thc hin thm cc chc nng khc ca b bin tn, hy s dng phn Ci t ng dng (xem mc 6.4). Khch hng nn p dng cch ny i vi cc h truyn ng yu cu nhiu tnh nng hot ng cao.


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6 Ci t thng s

6.2 Nhn dng ng cKHI NG P0625 = ? |Nhit ng c -P0625 5C Khng

Cho php lm mt

20o C Nhit mi trng xung quanh ng c (c nhp theo n o v C) Nhit mi trng xung quanh ng c c nhp vi gi tr ng thi m d liu ca ng c ang c xc nh (gi tr mc nh l : 20o C) S chnh lch gia nhit ca ng c v nhit mi trng xung quanh ng c P0625 phi nm trong khong dung sai xp x 5 o C. Nu chnh lch trn khng nm trong khong dung sai ny th chu trnh xc nh d liu cho ng c ch din ra sau khi ng c ngui i.

P1910 = 1

A0541 ON

Qu trnh nhn dng ng c vi P1910=1 P1910=1: Nhn dng ng c v thay i thng s tng ng. Cc thng s ny c b iu khin chp nhn v thc hin.

0

Khi P1910=1 c chn, xut hin cnh bo A0541 (cho bit qu trnh xc nh d liu cho ng c ang c thc hin) v thng s P0340 t t l 3. Bt u qu trnh nhn dng ng c vi P1910=1 Qu trnh o cc gi tr c bt u vi lnh ON lin tc (trng thi n nh). ng c t chnh v tr rotor v dng in c chy qua. C th xem dng bng thng s r0069 (CO: Dng pha). Sau khi hon tt chu trnh xc nh d liu cho ng c, th thng s P1910 c t li (P1910=0, tc l ngng chu trnh xc nh d liu) v cnh bo A0541khng hin th na. chuyn b bin tn sang trng thi mi, phi thc hin lnh OFF1 trc khi chuyn sang bc tip theo. 0 Nhn dng ng c vi P1910=3 P1910=3: Xc nh c tnh bo ho ng c v thay i cc thng s tng ng. Khi P 1910=3 c chn, xut hin cnh bo A0541 (cho bit qu trnh xc nh d liu cho ng c ang c thc hin) v thng s P0340 t t l 2. Bt u qu trnh nhn dng ng c vi P1910=3 Qu trnh o cc thng s c bt u vi lnh ON ln tip. Sau khi hon tt chu trnh xc nh d liu cho ng c, th thng s P1910 c t li (P1910=0, tc l ngng chu trnh xc nh d liu) v cnh bo A0541khng hin th na. chuyn b bin tn sang trng thi mi, phi thc hin lnh OFF1 trc khi chuyn sang bc tip theo.

OFF1 P1910 =3 A0541 ON

OFF1KT THC

6.3

Dng t ho

Gi tr ca dng t ho r0331/ P0320 c nh hng ln ti cht lng iu khin vng kn. Khng th o c gi tr ny trng thi dng. iu ny c ngha l gi tr ny c c tnh cho chun ng c 4 cc 1LA7 theo tiu chun ca Siemens thng qua qu trnh t ng t thng s P0340 = 1 (P0320 = 0; kt qu r0331). Nu lch ca dng t ho qu cao, th cc gi tr in khng v cc gi tr in tr ca ng c s khng th xc nh mt cch chnh xc c. c bit i vi cc loi ng c ca nh cung cp th ba, vic kim tra k dng t ho c xc nh l rt quan trng v nu cn thit th phi iu chnh cho hp l. Cch thc xc nh dng t ho bng th cng v tnh ton li d liu s mch tng ng khi h truyn ng c iu khin theo phng php vect vng kn (P1300 = 20/21) c minh ho theo bng di y. 32 MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

6 Ci t thng s

Thng 7/05

Khi ng

Ci t nhanh

Nhn dng ng c

Chu trnh ci t nhanh Nh c qu trnh ci t nhanh, b bin tn hiu v iu chnh thng s ph hp vi ng c. Cc thng s cng ngh cng c ci t. Nhn dng ng c Nh c qu trnh nhn dng ng c, d liu s mch in ng c tng tng (m phng trong bin tn) c xc nh bng k thut o. Xc nh dng t ho xc nh dng t ho (P0320/r0331), cn tng tc ng c ti tc c gi tr gn bng 80% tc nh mc trong iu kin khng ti. Trong qu trnh ny, cc iu kin sau phi c duy tr cn thn: - Phng php iu khin vect phi hot ng, P1300=20/21 - Khng c vn hnh thiu t thng (r0056,8 = 0) - im t t thng, r1598= 100% - Khng c lm vic ch ti u ho hiu sut, P1580 =0% Ch hot ng khng ti c ngha l ng c ang hot ng khng ti (trc ng c khng c ni vi ti). Trong iu kin trng thi n nh, dng in r0027 t c xp x tng ng vi dng t ho nh mc r0331. (Dng in ny lun lun thp hn dng khng ti cho ch iu khin n thun V/f).

Hot ng trong iu khin khng ti

Tho mn cc iu kin khng?

Qu trnh tnh ton mi cc d liu s mch tng ng ca ng c lin quan n vic o v nhp dng in t ho l mt qu trnh lp.Qu trnh ny phi lp i lp li t nht 2-3 ln cho ti khi t c cc tiu chun sau : - Gi tr dng t ho c nhp vo cng chnh xc th im t t thng (r1598 =100%) cng ph hp hn vi gi tr thc ca t thng (r0084 = 96..104%) ly t m hnh b quan st. Gi tr hiu chnh u ra Xm (r1787) ca m hnh quan st nn cng thp cng tt. Cc gi tr ph hp nm trong khong 1-5%. Gi tr hiu chnh Xh m b quan st phi thc hin cng t th nhy ca cc thng s ng c sau s c mt in cng gim. CH hin th r0084 trn BOP/AOP, b lc thng s phi m ti cp 4 v thng s phc v P3950 = 46. 0 Tnh ton P0320 Lc ny, gi tr mi c th dc nhp theo P0320 t phn t dng in sinh t thng c xc nh r0029 bng thng thc sau. P0320 = r 0029*100 / P0305 0 Tnh ton cc thng s ng c Cc gi tr d liu ca s mch tng ng c tnh ton t d liu nh mc ghi trn nhn c nhp.Ngoi ra cc thng s ca cc ch iu khin c t t trc, (do c ti u ho) (P0340 =3).

C

Khng

P0320 =

P0340 =

Kt thc


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6 Ci t thng s

6.4 Ci t ng dngCi t ng dng iu chnh/ ti u ho s kt hp gia b bin tn v ng c cho mt ng dng c th. B bin tn c nhiu tnh nng nhng khng phi tt c cc tnh nng u cn thit cho mt ng dng c th. C th b qua cc tnh nng ny khi ci t ng dng. Phn ln cc tnh nng c th c m t y; hy xem danh sch cc thng s cho cc tnh nng ph. Cc thng s c nh du * th c nhiu ch ci t hn cc ch c lit k ra y. Hy xem danh sch thng s khi mun ci t thm cc ch khc.

Khi

ng 1 Mc truy nhp ca ngi s dng* 1 Cp c bn: cho php truy cp ti cc thng s hay s dng nht 2 Cp m rng: cho php m rng kh nng truy cp, v d ti chc nng I/O ca b bin tn. 3 Cp chuyn gia: ( ch dnh cho cc chuyn gia s dng )

P0003 = 3

6.4.1 Giao din ni tipP2010 =

Tc baud USS Ci t tc baud cho truyn thng USS. a ch USS Ci t a ch duy nht cho b bin tn. Chiu di PZD USS Xc nh s t c di 16 bit PZD trong mt ln truyn d liu theo kiu USS. Chiu di PKW USS Xc nh s t c di 16 bit PKW trong mt ln truyn d liu theo kiu USS.

6

P2011 =

0

P2012 =

2

Cc ch ci t c th 4 2400 Baud 5 4800 Baud 6 9600 Baud 7 19200 Baud 8 38400 Baud 9 57600 Baud 10 76800 Baud 11 12 93750 Baud 115200 Baud

P2013 =

127

6.4.2 Chn ngun lnhP0700 =

Chn ngun lnh Chn ngun lnh s 0 Ch ci t li khi xut xng 1 BOP (bn phm) 2 u ni 4 USS trn ng truyn BOP 5 USS trn ng truyn COM 6 CB trn ng truyn COM

2

BOP Cc u ni USS BOP link USS COM link CB COM linkP0700 = 2

iu khin tun t

Knh im t

iu khin ng c

34


6 Ci t thng s

Thng 7/05

6.4.3 u vo s (DIN)P0701 =...

Chc nng u vo s s 1 u ni s 5 1 ON/OFF1 Chc nng u vo s s 2 u ni s 6 12 o chiu

1

P0702 =...

12

P0703 =...

P0704 =...

P0705 =...

P0706 =...

P0707 = 0

P0708 = 0

9 Chc nng u vo s s 3 u ni s 7 9 Nhn bit li 15 Chc nng u vo s s 4 u ni s 8 15 im t c nh ( chn trc tip) 15 Chc nng u vo s s 5 u ni s 16 15 im t c nh ( chn trc tip) 15 Chc nng u vo s s 6 u ni s 17 15 im t c nh ( chn trc tip) 0 Chc nng u vo s s 7 Qua u vo tng t, u ni s 3 0 u vo s khng hot ng 0 Chc nng u vo s s 8 Qua u vo tng t, u ni s 10 0 u vo s khng hot ng

Cc ch ci t c th 0 u vo s khng hot ng 1 ON/OF1 2 ON + o chiu/OFF1 3 OFF2- Dng t do 4 OFF3- Gim tc nhanh 9 Nhn bit li 10 Chy nhp, bn phi 11 Chy nhp, bn tri 12 o chiu 13 Tng MOP (Tng tn s) 14 Gim MOP (Gim tn s) 15 im t c nh (chn trc tip) 16 im t c nh (chn trc tip+ ON) 17 im t c nh (chn m nh phn + ON) 21 Ti ch/ T xa 25 Kch hot hm DC 29 Li h thng bn ngoi 33 Khng cho php im t tn s b sung 99 Cho php ci t thng s BICO

P0724 =...

Thi gian tr i vi cc u vo s Xc nh thi gian tr (thi gian lc) dng cho u vo s 0 1 2 3 Khng c thi gian tr Thi gian tr 2.5 ms Thi gian tr 8.2 ms Thi gian tr 12.3 ms

P0725 =...

u vo s PNP/NPN Chuyn i gia trng thi tch cc cao (PNP) v tich cc thp (NPN). Qu trnh ny p dng vi tt c cc u vo s cng mt lc. 0 Ch NPN ==> Tch cc thp 1 Ch PNP ==> Tch cc caoKnh DIN

Thi gian tr: DIN


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6 Ci t thng s

6.4.4 Cc u ra s (DOUT)P0731=

BI: Chc nng ca u ra s s 1 52.3 Cc ch ci t thng thng Xc nh ngun ca u ra s s 1. 52.0 B truyn ng sn sng BI: Chc nng ca u ra s s 2 52.7 52.1 B truyn ng sn sng hot ng Xc nh ngun ca u ra s s 2. 52.2 B truyn ng ang hot ng BI: Chc nng ca u ra s s 3* 0.0 52.3 Kch hot ch pht hin li ca b truyn ng Xc nh ngun ca u ra s s 3. 52.4 OFF2 hot ng 52.5 OFF3 hot ng 0 52.6 Ch hm hot ng o u ra s Xc nh trng thi cao v thp ca rle 52.7 Ch cnh bo ca b truyn cho mt chc nng nht nh. ng hot ng 52.8 chnh lch gia gi tr im t v gi tr thc t 52.9 iu khin t PLC ( iu khin PZD) 52.A Tn s ln nht t c 52.B Cnh bo: Dng in ca ng c ang ti gi tr gii hn 52.C Ch hm c kh (MHB) hot ng 52.D ng c qu ti 52.E Chiu quay ca ng c, theo chiu kim ng h 52.F B bin tn qu ti 53.0 Kch hot hm DC

0 0 0 0 1 1 0 0 1 0 0 1 0 1 0 1 0

P0732=

P0733=

P0731=

Knh DOUT

R le:

Thi gian ng / m ln nht

36


6 Ci t thng s

Thng 7/05

6.4.5 Chn gi tr im t tn sP1000 =

Chn Gi tr t tn s 0 Khng c Gi tr t chnh 1 Gi tr t MOP 2 Gi tr t tng t 3 Tn s c nh 4 USS trn ng truyn BOP 5 USS trn ng truyn COM 6 CB trn ng truyn COM 7 Gi tr t tng t 2 10 Khng c Gi tr t chnh 11 Gi tr t MOP 12 Gi tr t tng t...

2

+ + +

Gi tr t MOP Gi tr t MOP Gi tr t MOP

76 CB trn ng truyn COM + Gi tr t tng t 2 77 Gi tr t tng t 2 + Gi tr t tng t 2 CH Ngoi Gi tr t chnh, c th nhp mt Gi tr t ph bng P1000 V d P1000=12:P1070 r0755 P1075 P1000=12P1075=1050 r1050 P1000=12P1070=755MOP iu khin tun t ADC P1000 = 12 FF USS BOP link USS COM link CB COM link ADC2 P 1000 = 12 Gi tr t chnh Gi tr t ph Knh im t iu khin ng c

CI: CO: CI: CO:

Gi tr t chnh ADC thc t sau khi ly thang t l [4000h] Gi tr t ph Tn s u ra thc t ca MOP

P1074 = BI: Gi tr t ph khng hot ng P1075 = CI: Gi tr t ph

0:0 0:0

Xc nh ngun ca Gi tr t ph (c thm vo Gi tr t chnh ) Cc ch ci t thng thng 755 Gi tr t u vo tng t 1024 Gi tr t tn s c nh 1050 Gi tr t MOPP1076 = CI: nh thang gi tr t b sung

1:0

Xc nh ngun chia cho Gi tr t ph. Cc ch ci t thng thng 1 nh thang bng 1.0 (100%) 755 Gi tr t u vo tng t 1024 Gi tr t tn s c nh 1050 Gi tr t MOP


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6 Ci t thng s

6.4.6 u vo tng t (ADC)P0756 =

0 Kiu ADC Xc nh kiu u vo tng t v kch hot chc nng theo di ca u vo tng t 0 u vo in p n cc (t 0 n +10 V) 1 u vo in p n cc vi chc nng theo di (t 0 n 10 V) 2 u vo dng in n cc (t 0 n 20mA) 3 u vo dng in n cc vi chc nng theo di (t 0 n 20mA) 4 u vo in p lng cc (t -10 ti +10 V) CH T P0756 n P0760, th p dng cc ch s sau: Ch s 0: u vo tng t s 1 (ADC1), u ni 3,4 Ch s 1: u vo tng t s 2 (ADC2), u ni 10, 11

P0757 = P0758 =

Gi tr x 1 ca nh thang ADC

0V

P0759 = P0760 =

0.0% Gi tr y1 ca nh thang ADC Thng s ny biu th gi tr x1 bng a% ca P2000.(Tn s quy chiu). 10 V Gi tr x2 ca nh thang ADC 100.0% Gi tr y2 ca nh thang ADC Thng s ny biu th gi tr x2 bng a% ca P2000.(Tn s quy chiu). 0V Chiu rng ca di cht ADC Xc nh chiu rng ca di tn hiu cht trn u vo tng t. 10 ms Thi gian tr, mt tn hiu ADC Xc nh thi gian tr t thi im mt tn hiu im t tng t n khi xut hin thng bo li F0080 .Knh ADC Kho chuyn mch DIP Kiu ADC nh thang ADC Vng cht ADC im t

P0761 =

P0762 =

Cm bin li t dy

Chc nng

38


6 Ci t thng s

Thng 7/05

6.4.7 u ra tng t (DAC)P0771 =

CI: DAC Xc nh chc nng ca u ra tng t t 0 n 20 mA 21 CO: Tn s u ra (c ly thang t l theo P2000) 24 CO: Tn s u ra ca b bin tn (c ly thang t l theo P 2000) 25 CO: in p u ra (c ly thang t l theo P2001) 26 CO: in p ng trung gian DC (c ly thang t l theo P2001) 27 CO: Dng in u ra (c ly thang t l theo P2002) CH i vi P0771 n P0781, th p dng cc ch s sau: Ch s 0 : u ra tng t s 1 (DAC1), u ni 12, 13 Ch s 1 : u ra tng t s 2 (DAC1), u ni 26, 27

21

2ms Xc nh thi gian lc [ms]cho tn hiu u ra tng t.Thng s ny cho php lc DAC nh b lc PT1. P0776 = Kiu DAC 0 Xc nh kiu u ra tng t 0 Dng in u ra 1 in p u ra CH P0776 thay i t l ca r0774 (t 0-20mA n 0-10 V) Cc thng s t l P0778, P 0780 v vng cht tlun c nhp trong khong 0-20mA DAC l in p u ra th phi ng cc u ra DAC bng mt in tr 500.P0773 = Hng s thi gian lc DAC

0.0% Xc nh gi tr u ra x1 l a%. Thng s ny biu th gi tr tng t nh nht l a% ca P200x (ph thuc vo ch ci t P0771). P0778 = Gi tr y1 ca thang t l DAC 0 Thng s ny biu th gi tr cho x1 theo n v mA. P0779 = Gi tr x2 ca thang t l DAC 100.0% Xc nh gi tr c tnh u ra x2 l a%. Thng s ny biu th gi tr tng t nh nht l a% ca P200x (ph thuc vo ch ci t P0771). P0780 = Gi tr y2 ca thang t l DAC Thng s ny biu th gi tr x2 theo mA.P0777 = Gi tr x1 ca thang t l DAC P0781 = Chiu rng ca di cht DAC

20

0

t chiu rng ca di cht theo n v [mA] cho u ra tng t.Knh DAC

Chc nng

nh thang DAC

Vng cht DAC


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6 Ci t thng s

6.4.8 Chit p xung (MOP)P1031 =

P1032 =

P1040 =

0 B nh im t ca MOP Lu li im t ca chit p xung (MOP) hot ng trc khi ra lnh OFF hoc ngt in. 0 im t MOP s khng c lu li. 1 im t MOP s c lu li. (Gi tr P1040 c cp nht) 1 Khng cho php cc im t MOP m 0 Cho php t MOP c gi tr m 1 Khng cho php im t MOP c gi tr m. 5.00 Hz im t MOP Xc nh im t cho chit p xung. Thi gian tng tc v thi gian gim tc MOP c xc nh bng thng s P1120 v P1121. Cc ch ci t c th khi chn MOP: Tng MOP Ch la chn Gim MOP P0719=0, P0700=2, DIN P0702=13 (DIN2) P0703=14 (DIN3) P1000=1, hoc P0719=1, P0700=2 P0719=0, P0700=1, Nt UP Nt DOWN BOP P1000=1, hoc P0719=11 P0719=0, US trn ng P0700=4, T iu khin USS T iu khin truyn BOP P1000=1, hoc r2032 Bit 13 USS r2032 Bit 14 P0719=41 P0719=0, US trn ng P0700=5, T iu khin USS T iu khin truyn COM r2036 Bit 13 USS r2036 Bit 14 P1000=1, hoc P0719=51 P0719=0, T iu khin CB T iu khin P0700=6, CB r2090 Bit 13 CB r2090 Bit 14 P1000=1, hoc P0719=61

40


6 Ci t thng s

Thng 7/05

6.4.9 Tn s c nh (FF)0.00 Hz Tn s c nh s 1 C th c chn trc tip qua DIN1 (P0701=15,16) P1002 = Tn s c nh s 2 5.00 Hz C th c chn trc tip qua DIN2 (P0702=15,16) P1003 = Tn s c nh s 3 10.00 Hz C th c chn trc tip qua DIN3 (P0703=15,16)P1001 = P1004 =

Khi xc nh chc nng ca cc u vo s (P0701 ti P0706), c th la chn ba kiu khc nhau cho cc tn s c nh: 15 = Chn trc tip (P0701-P0706 =15) ch c bit ny, mi u vo s lun chn tn s c nh tng ng, v d: u vo s s 3 s chn tn s c nh s 3 Nu nhiu u vo hot ng cng mt lc th cc gi tr c cng li. Mt lnh ON cn c b sung. Vd. FF1+FF2+FF3+FF4+FF5+FF6 16 = Chn trc tip + lnh ON (P0701P0706=16) ch ny, cc tn s c nh c chn ging nh cho 15, tuy nhin cc tn s ny c kt hp vi mt lnh ON. Vd. FF1+FF2+FF3+FF4+FF5+FF6

15.00 Hz Tn s c nh s 4 C th c chn trc tip qua DIN4 (P0704=15,16)

P1005 =

20.00 Hz Tn s c nh s 5 C th c chn trc tip qua DIN5 (P0705 =15,16)

25.00 Hz 17= Chn ch m nh phn + Lnh ON Tn s c nh s 6 ( c m BCD + ON/OFF1) C th c chn trc tip qua DIN6 C th chn 16 tc c nh ch ny. (P0706 =15,16) P1007 = Tn s c nh s 7 30.00 Hz .P1006 = P1008 = P1009 = P1010 = P1011 = P1012 = P1013 = P1014 = P1015 = P1016 =

Tn s c nh s 8 Tn s c nh s 9 Tn s c nh s 10 Tn s c nh s 11 Tn s c nh s 12 Tn s c nh s 13 Tn s c nh s 14 Tn s c nh s 15

35.00 Hz 40.00 Hz 45.00 Hz 50.00 Hz 55.00 Hz 60.00 Hz 65.00 Hz 65.00 Hz 1 2 3 Chn trc tip Chn trc tip + Lnh ON Chn ch m ho nh phn+ lnh ON

M tn s c nh - Bit 0 1 Xc nh phng php la chn cc tn s P1017 = M tn s c nh - Bit 1 1P1018 = P1019 = P1025 = P1027 =

M tn s c nh - Bit 2 M tn s c nh - Bit 3 M tn s c nh - Bit 4 M tn s c nh - Bit 5

1 1 1 1

CH i vi cc ch ci t 2 v 3, tt c cc thng s t P1016 n P1019 phi c t ti gi tr chn b bin tn chp nhn lnh . 1 2 Chn trc tip Chn trc tip + Lnh ON


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6 Ci t thng s

6.4.10 Chy nhpP1058 =

P1059 =

5.00Hz Tn s chy nhp bn phi Tn s c o bng n v Hz khi ng c quay theo chiu kim ng h ch chy nhp. 5.00Hz Tn s chy nhp bn tri Tn s c o bng n v Hz khi ng c quay ngc chiu kim ng h ch chy nhp. 10.00s Thi gian tng tc chy nhp Thi gian tng tc (n v s) t l khong thi gian tn s tng t 0 n gi tr ln nht (P1082). Thi gian tng tc khi chy nhp c gii hn bi P1058 hoc P1059. 10.00s Thi gian gim tc chy nhp Thi gian gim tc (n v s) l khong thi gian tn s gim t gi tr ln nht (P1082) xung 0.

P1060 =

P1061 =

42


6 Ci t thng s

Thng 7/05

6.4.11 B pht hm to dc (RFG)P1091 =

P1092 =

0.00Hz Tn s nhy 1 (n v Hz) Xc nh tn s nhy 1 trnh cc nh hng ca hin tng cng hng c hc v kh cc tn s trong khong P1101 (di tn s nhy) 0.00Hz Tn s nhy 2

P1093 =

Tn s nhy 3

0.00Hz

P1094 = P1101 =

Tn s nhy 4 Di tn s nhy (n v Hz)

0.00Hz 2.00 Hz Tn s nhy

Di tn s nhy

P1120 =

Thi gian tng tc (n v s)

10.00 s

P1121 =

Thi gian gim tc (n v s)

10.00 s

P1130 =

P1131 =

Thi gian tng tc ban u theo phng php ng cong (n v tnh theo s) Thi gian tng tc cui cng theo phng php ng cong (n v tnh theo s) Thi gian gim tc ban u theo phng php ng cong (n v tnh theo s)

00.0 s Cc thi gian tng/ gim tc theo phng php ng cong nn s dng v c th trnh c cc phn ng t ngt, nh gim c ng sut v 00.0 s h hng cho phn c. Thi gian tng tc v thi gian gim tc c ko di nh phng php tng/ gim on c tuyn 00.0 s ng cong.

P1132 =

P1133 =

Thi gian gim tc cui cng 00.0 s theo phng php ng cong (n v tnh theo s) 0 Phng php ng cong 0 Lin tc 1 Gin on 5.00s Thi gian gim tc theo lnh OFF3 Xc nh thi gian gim tc t im c tn s ln nht n im dng i vi lnh OFF3

P1134 =

P1135 =


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6.4.12 Cc tn s quy chiu / gii hnP1080 =

P1082 =

P2000=

P2001 =

Tn s nh nht (n v Hz) 0.00 Hz t tn s nh nht cho ng c [Hz], ti ng c s chy m khng ph thuc vo gi tr t tn s. Nu im t c gi tr nh hn gi tr ca thng s P1080, th tn s u ra c t P1080 v o du. Tn s ln nht (n v Hz) 50.00 Hz t tn s ln nht cho ng c [Hz], ti ng c s chy m khng ph thuc vo gi tr t tn s. Nu im t vt qu gi tr ca thng s P1082, th tn s u ra c gii hn. Gi tr t y c tc dng cho c hai trng hp ng c quay thun v ngc. Tn s quy chiu (n v Hz) 50.00 Hz Tn s quy chiu (n v Hz) tng ng vi gi tr 100%. Nn thay i ch ci t khi tn s ln nht cn c gi tr ln hn 50Hz. Ch ny c t ng thay i n gi tr 60Hz nu tn s chun 60Hz c chn nh thng s P0100. Ch : Tn s quy chiu c nh hng n tn s im t v cc im t tn s thng qua giao thc USS v mun PROFIBUS (FB100) (4000H hex 100% P2000) u c lin quan n gi tr ny. in p quy chiu (n v V) 1000V in p quy chiu theo n v V (in p ra) tng ng vi gi tr 100%. Ch Ch nn thay i ch ci t ny nu cn a ra in p theo mt thang t l khc. Dng in quy chiu (n v A) 0.10 A Dng in quy chiu tnh theo n v A (dng in ra) tng ng vi gi tr 100%. im t mc nh = 200% dng in nh mc ca ng c (P0305). Ch Ch ci t ny ch nn c thay i nu dng in ra cn thit tnh theo mt thang t l khc. Mmen quy chiu (n v A) 0.12 Mn Mmen quy chiu tnh theo n v Nm tng ng vi gi tr 100%. Ch ci t mc nh = 200% mmen inh mc ca ng c chy mmen khng i c xc nh t d liu tng ng ca ng c. Ch Ch nn thay i ch ci t nu mmen u ra cn thit tnh theo mt thang t l khc.

P2002=

P2003 =

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6.4.13 Bo v b bin tnP0290 =

Ch phn ng qu ti ca b bin tn Chn ch phn ng cho b bin tn i vi hin tng qu nhit bn trong. 0 Gim tn s u ra 1 Dng (F0004/ F0005) 2 Gim tn s xung v tn s u ra 3 Gim tn s xung sau dng (F0004)Theo di b bin tnr0036

0

Phn ng qu ti b bin tn P0290 iu khin i_max (U/f) iu khin dng (SLVC,VC)

i2t P0294 Nhit trong b tn nhit P0292 Nhit IGBT P0292

A0504 A0505 A0506

r0037

iu khin xung f

F0004 F0005

P0292 =

15oC Ch cnh bo nhit ca b bin tn o Xc nh s chnh lch nhit (n v C) gia ngng tc ng qu nhit v ngng cnh bo ca bin tn. Ngng cnh bo c b bin tn lu gi bn trong v ngi s dng khng th thay i c. Ngng cnh bo nhit ca b bin tn: T_warm Twarn = Ttrip - P0292 Ngng tc ng do nhit ca bin tn T_trip Nhit MM440, C v A-C D-F F FX GX600V 95kW 110kW 132kW 160kW 200kW

CT B tn nhit IGBT B chnh lu vo Khng kh lm mt Bng iu khinP0295 = Thi gian tr tt qut 110oC 140oC 95oC 145oC 80oC 145oC 88oC 150oC 75oC 55oC 65oC

CT91oC 150oC 75oC 55oC 65oC




0s Thng s ny xc nh thi gian tr tnh bng giy t thi im tt ngun bin tn n thi im tt ngun qut. Nu t bng 0 th qut s tt ngay lp tc khi tt ngun.

6.4.14 Bo v nhit ng cNgoi vic bo v qu nhit ng c, nhit ng c cng c tnh ton trong qu trnh hiu chnh d liu s mch tng ng ca ng c. c bit i vi ng c mang ti ln nhit cao, s hiu chnh ny c nh hng ng k ln n nh ca iu khin vng kn. i vi MM440, nhit ca ng c ch o c nh s dng b sensor KTY84. i vi gi tr thng s P0601 = 0,1, nhit ca ng c c tnh ton hoc c lng nh s dng m hnh nhit ng c. Nu bin tn lun lun c cp in p ngoi l 24 V, th nhit ng c cng c theo di/hiu chnh nh hng s thi gian nhit ca ng c, ngay c khi khi in p li tt. i vi phng php iu khin vng kn trong trng hp ng c ti ln nhit cao v khi ngun in li phi thng xuyn ng/ngt, th: MICROMASTER 440 Hng dn vn hnh (Bn rt gn) 45

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6 Ci t thng s

-cn dng mt sensor KTY84 hoc - cn ni mt ngun in p ngoi 24V.P0335 =

P0601 =

Ch lm mt ng c (chn h thng lm mt cho ng c) 0 0 Lm mt t nhin: S dng qut c gn trn trc ca ng c 1 Lm mt cng bc: S dng qut lm mt c cp ngun ring 2 Lm mt t nhin v s dng qut bn trong 3 Lm mt cng bc v s dng qut bn trong 0 Sensor nhit cho ng c Chn sensor nhit cho ng c 0 Khng c sensor 1 Nhit in tr PTC 2 KTY84 Khi chn ch "Khng c sensor" hoc "ch nhit in tr PTC" , nhit ca ng c c xc nh da trn gi tr c c lng bi m hnh nhit ng cLi F0015

pht hin mt tn hiu

Khng sensor

Tc ng theo nhit

D liu mch tng ng Tn tht in nng Pv,mot

M hnh nhit ng c

P0604 =

130 oC Ngng cnh bo v qu nhit ca ng c Xc nh ngng cnh bo bo v ng c khi qu nhit . Ngng cnh bo ny lun lun c gi tr thp hn 10% so vi ngng m ti hoc ch tc ng hoc ch gim Imax c khi ng (P0610). trip = 1,1 warm = 1,1 P0604 warm : ngng cnh bo (P0604) trip : ngng tc ng (nhit ln nht c th) Ngng cnh bo nn c t mc ln hn nhit xung quanh P0625 t nht l 40oC. P0604 P0625 + 40 oC. 2 Tc ng theo nhit ca bin tn Xc nh ch tc ng khi nhit ca ng c ti ngng cnh bo 0 Khng tc ng, ch cnh bo 1 Cnh bo v gim Imax (dn n tn s u ra thp hn) 2 Cnh bo v tc ng (F0011) 150,0% H s qu ti ca ng c [%] Xc nh gii hn dng qu ti cho ng c, n v [%], tng ng vi P0305 (dng in nh mc ca ng c). Gi tr gii hn c ly l gi tr thp hn trong hai gi tr sau: hoc dng in ln nht ca bin tn hoc 400% dng in nh mc ca ng c (P0305).

P0610 =

P0640 =

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6.4.15 EncoderP0400 = 0 Chn kiu encoder Chn kit encoder 0 Khng dng 1 B encoder mt ng xung 2 B encoder hai ng xung Bng bn cho thy gi tr ca P0400 l hm ca s cc dng ng xung Thng s u dy Dng ng xung u ra Encoder P0400 = 1 A Dng n A Dng i AN P0400 = 2 A Dng n B A Dng i AN B BN m bo hot ng tt, cc kho chuyn mch DIP trn mun encoder phi c t da vo kiu encoder (TTL, HTL) v u ra encoder nh sau: Kiu Ngun u ra Encoder Dng n Dng i TTL (v d 1xP8001-2) 5V 111111 010101 HTL(v d 1xP8001-1) 24V 101010 000000 1024 S xung encoder trn mt vng quay Xc nh s lng xung encoder pht ra khi trc ng c quay mt vng. 0 Tc ng khi mt tn hiu tc Xc nh phng php tnh tc sau khi mt tn hiu encoder 0 Khng chuyn sang SLVC 1 Chuyn sang ch SLVC 10.00Hz Sai lch tc cho php Thng s P0942 xc nh ngng sai lch tn s khi tn hiu encoder b mt (bo li F0090) Ch : 'Vi P0492 = 0, H thng khng theo di hin tng mt tn hiu encoder. 10ms Thi gian tr tc ng khi mt tn hiu tc P0492 c dng d tm tn hiu encoder b mt cc tn s thp. Nu tc ca ng c nh hn gi tr ca thng s P0492, th hin tng mt tn hiu encoder c xc nh nh dng thut ton thch hp. P0494 xc nh thi gian tr tnh t thi im d tm tn hiu tc b mt n lc bt u c tc ng tng ng. Ch P0494 = 0 ( khng c chc nng theo di): Vi P0492 = 0, mt tn hiu encoder cc tn s thp khng c kch hot. Do , cc tn s ny, mt tn hiu encoder khng c d tm (mt tn hiu encoder tn s cao vn c kch hot min l P0492 > 0).

P0408 = P0491 =

P0492 =

P0494 =


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6.4.16 iu khin V/fP1300 =

Ch iu khin V/f

0

P1310 =

Dng thng s ny chn ch iu khin. i vi ch iu khin "c tnh V/f", t s gia in p ra ca bin tn vi tn s ra ca bin tn c xc nh. 0 V/f tuyn tnh 1 V/f FCC 2 V/f vi c tnh parabol (xem thm trong danh sch cc thng s) 50, 00% B tng lin tc (n v %) Tng in p theo % tng ng vi P0305 (dng in nh mc ca ng c) v P0350 (in tr stato) cc tn s ra thp duy tr t thng ca ng c v cc gi tr in tr c tc dng ca cun dy khng th b qua. B tng in p c tnh tuyn tnh V/f Di gi tr

B tng in p

in p raV_tng thc

V/f thng thng (P1300 = 0)

P1310 kch hot

P1311 =

B tng gia tc (n v %) 0, 0% Tng in p tng tc hm theo % tng ng vi P0305 v P0350. P1311 ch lm tng in p khi tng tc/ gim tc v lm tng thm mmen tng tc/ hm. Nu nh thng s P1312 ch c tc dng cho qu trnh tng tc u tin sau lnh ON, th thng s P1311 c tc dng sau mi thi im m h truyn ng tng tc hoc hm. B tng in p c tnh tuyn tnh V/f Di gi tr

B tng in p

V/f thng thng (P1300 = 0)

P1310 kch hot

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P1312 =

P1320 =

P1321 = P1322 = P1323 = P1324 = P1325 =

B tng khi khi ng (n v %) 0.0% Tng in p khi khi ng (sau lnh ON) theo % tng ng vi P0305 (dng in nh mc ng c) hoc P0350 (in tr stato), khi s dng c tnh V/f tuyn tnh hoc bnh phng. in p tng n khi 1) t n im t ln u tin 2) im t gim n gi tr nh hn u ra b pht hm to dc tc thi. To tn s th nht ca lut 0.0Hz V/f c th lp trnh c t cc to V/f (t P1320/1321 n P1324/1325 xc nh c tnh V/f. To in p th nht ca lut 0.0Hz V/f c th lp trnh c To in p th hai ca lut 0.0Hz V/f c th lp trnh c To in p th hai ca lut 0.0Hz V/f c th lp trnh c To tn s th ba ca lut V/f 0.0Hz c th lp trnh c 0.0Hz To in p th ba ca lut V/f c th lp trnh c

P1333 =

10,0% Tn s khi khi ng cho FCC ( n v %) Xc nh tn s khi khi ng FCC nh l hm ca tn s nh mc ca ng c (P0310).

chuyn mch

Ch Mc b in p khng i P1310 s gim dn khi chuyn sang ch FCC.P1335 =

B trt (tnh theo %) 0,0% iu chnh ng tn s ra ca bin tn sao cho tc ng c khng i khi ti ng c thay i

Di b trt:

P1338 =

H s suy gim cng hng V/f H s suy gim cng hng V/f

0,00


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6.4.17 iu khin nh hng trng (FCC)Cc gii hnP0640 =

150,0% H s qu ti ng c [%] Gii hn dng in qu ti ng c tnh theo % ca P0305 (dng in nh mc ng c). Gi tr gii hn c ly l gi tr thp hn trong hai gi tr sau: hoc dng in ln nht ca bin tn hoc 400% dng in nh mc ca ng c (P0305).

P1520 =

P1521 =

FC-spec. CO: Mmen gii hn trn Xc nh gi tr c nh cho mmen gii hn trn. P1520 def = 1,5x r0333 P1520max = 4x r0333 FC-spec. CO: Mmen gii hn di Nhp gi tr c nh cho mmen gii hn di. P1521 def = - 1,5x r0333 P1521 max = 4x r0333

Gii hn mmen t c Gii hn cng sut Gii hn Gii hn dng dng

Gii hn mmen

f_thc t Mmen khng i Cng sut khng if_dng

Cng sut dng

P1530 =

P1531 =

FC-spec. Gii hn cng sut ch ng c Xc nh gi tr c nh cho cng sut tc dng cho php ln nht ch ng c P1530 def = 2,5xP0307 P1530 max = 3 x P0307 FC-spec. Gii hn cng sut ch my pht Nhp gi tr c nh cho cng sut pht tc dng cho php ln nht ch my pht. P1531 def = -2,5x P0307 P1531 max = -3x P0307

Gii hn cng sut ch ng c my pht

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6.4.17.1 iu khin vect khng sensor (SLVC)P1300 =20

0 Ch iu khin 20 iu khin tc vect vng kn khng c encoder SLVC c th rt c hiu qu trong cc ng dng sau: Cc ng dng yu cu mmen ln Cc ng dng yu cu p ng nhanh khi ti thay i t ngt Cc ng dng yu cu duy tr mmen khi qua tn s 0 Hz Cc ng dng yu cu duy tr tc chnh xc cao Cc ng dng yu cu bo v trc ng c khng b trt. P1452 = Hng s thi gian b lc cho tn s thc (SLVC) 4ms t hng s thi gian ca b lc PT1 dng cn du sai s ca khu iu khin tc khi lm vic ch vect khng sensor (SLVC). Vic gim gi tr ny lm tng cht lng ng ca qu trnh iu chnh tc . Nu t gi tr thp hoc gi tr cao th s gy ra s mt n nh. C th t P1452 =2 trong hu ht cc ng dng. P1470 = H s khuch i ca khu iu khin tc (SLVC) 3.0 Nhp h s khuch i ca khu iu khin tc trong ch iu khin vect khng sensor (SLVC). P1472 = Hng s thi gian tch phn ca khu iu khin tc (SLVC) 400ms Nhp hng s thi gian tch phn ca khu iu khin tc trong ch iu khin khng sensor (SLVC).

San ti

Khu tin iu khin

Tn s t Mmen t

Tn s thc t m hnh tnh ton

*) ch c tc dng nu c khu tin iu khin (P1469 >0)

P1610 =

P1611 =

50.0% B tng mmen lin tc (SLVC) t tng mmen di tn s thp hn SLVC (iu khin vect khng sensor). Nhp gi tr ny theo % ca mmen nh mc ca ng c r0333. P1610 ch c tc dng ch iu khin vng h t 0Hz n xp x p1755. 0.0% B tng mmen khi tng tc (SLVC)ttt t tng mmen di tn s thp hn SLVC (iu khin vect khng sensor). Nhp gi tr ny theo % ca mmen nh mc ca ng c r0333. P1611 ch c tc dng ch iu khin vng h t 0Hz n xp x p1755. Khc vi P1610 tng mmen P1611 ch c tc dng khi tng/gim tc.


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P1750 =

1 T iu khin ca m hnh ng c Thng s ny iu khin hot ng ca ch iu khin vect khng sensor (SLVC) cc tn s rt thp. Do , thng s ny c cc iu kin sau: Bit00 Start SLVC open loop 0 NO 1 YES (Hot ng trc tip sau khi c lnh ON) Bit01 Zero Crossing SLVC open loop 0 NO 1 YES (vng tc i qua 0)Khi khi ng Vng tc qua im 0 Vng kn Vng kn P1755 Vng h Vng h

P1755

Trong hu ht cc ng dng, gi tr ci t ca thng s P2750 = 0 c kt qu tt nht tn s thpP1755 =

5.0Hz Tn s khi ng ca m hnh ng c (SLVC) Nhp tn s khi ng ca ch iu khin vect khng sensor (SLVC), do SLVC chuyn t vng h sang vng kn ti tn s .Khu tin iu khin B iu khin tc P1750/ P1755 P1425 P1470 P1472

Gii hn mmen

im t tn s

Vng h/ kn

im t t thng cho vng kn im t t thng cho vng h

B iu khin dng

in p ra thc

Xc nh dng Gc thc

Tn s thc

Tn s ra thc

Tn s trt

M hnh tnh ton cho vng kn

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6.4.17.2 iu khin vect c encoder (VC)Bc 1: Ci t thng s cho b encoder (xem phn 6.4.15) Khi ci t ch iu khin vect c phn hi encoder (VC), u tin nn t h truyn ng ch V/f (xem thng s P1300). Cho chy h truyn ng v so snh r0061 vi r0021. Chng phi ging nhau v: - du - bin (vi sai lch nh ch bng vi %) Ch khi p ng hai iu kin trn, thay i P1300 v chn VC (P1300 = 21/23). Khng c kch hot chc nng d tm mt tn hiu encoder (P0492 = 0) nu mmen ti b gii hn bn ngoi., v d nh: - iu khin vng kn my qun dy - ti chy ngang hoc di chuyn n im dng c nh - khi s dng phanh c kh ca ng cP1300 =21 Ch iu khin 0

21 iu khin vect c sensor P1442 = Hng s thi gian lc cho tc thc 4ms t hng s thi gian lc ca b lc PT1 lc tc cho b iu khin tc . Vic gim gi tr ny lm tng cht lng ng ca qu trnh iu chnh tc . Nu t gi tr thp th s gy ra s mt n nh. C th t P1422 =2 trong hu ht cc ng dng. P1460 = H s khuch i ca b iu khin tc 3.0 Nhp h s khuch i ca b iu khin tc P1462 = Thi gian tch phn ca b iu khin tc 400ms Nhp thi gian tch phn ca b iu khin tc

San ti

Khu tin iu khin

Tn s t Mmen t

Tn s thc t encoder

ch c tc dng nu c khu tin iu khin


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Gi tr im t mmen b sung ch iu khin vect c/ khng c encoder, b iu khin tc c th ph thuc vo lng mmen b sung khng i hoc bin i. Gi tr im t b sung c th c dng h tr c cu nng h trong trng hp ma st thc t ca h thp khi khi ng theo chiu thng ng. Gi tr b sung m-men phi lun lun h tr hng nng ln (xin hy quan st du!). Nh c khi h xung, ch trt c thit lp v lm n nh thm ch iu khin vng kn (ti khng b tt nhiu). Khi xc nh du ca gi tr im t mmen b sung, phi ch cn thn v xem xt n tt c cc quy tc an ton lin quan. C th xc nh du ca gi tr im t mmen b sung trong khu ci t nh sau: Nng ti c trng lng ti thiu s dng c cu nng v ghi li du t thng s r0079 (du ca r0079 tng ng vi du ca im t mmen b sung. Gi tr thc nghim ca m-men b sung bng xp x 40% gi tr mmen nh mc ng c r0333 m bo hot ng tt cho c cu nng (hy quan st du cn thn).P1511 =

CI: Gi tr im t M-men b sung

0.0

Cc gi tr im t 2889 2890 755.0 755.1 2015.2 2018.2 2050.2 im t c nh 1 theo % im t c nh 2 theo % u vo tng t s 1 u vo tng t s 2 USS (ng truyn BOP) USS (ng truyn COM) CB (v d mun PROFIBUS)

Chn ngun gi tr im t mmen b sung.

San ti Khu tin iu khin

Tn s t

B iu khin tc PI Mmen t

Tn s thc CI : im t mmen thc

*) Ch c tc dng nu c tin iu khin (P1496 > 0)

SLVC: VC:

Ti P1452 P1442

Kp P1470 P1460

Tn P1472 P1462

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6.4.18 Cc chc nng c th ca bin tn6.4.18.1 Khi ng bm0 Khi ng b bin tn khi ng c ang quay bng cch thay i nhanh chng tn s ra ca b bin tn cho n khi xc nh c tc thc ca ng c. 0 Ch FS khng c kch hot 1 Ch FS lun lun c kch hot, khi ng theo chiu im t 2 Ch FS c kch hot, nu trong trng hp c cp ngun tr li, gii tr li, OFF2 th khi ng theo chiu im t 3 Ch FS c kch hot, nu trong trng hp gii tr li, OFF2 th khi ng theo chiu im t 4 Ch FS lun lun c kch hot, ch theo chiu im t 5 Ch FS c kch hot, nu trong trng hp c cp ngun tr li, gii tr li, OFF2 th ch khi ng theo chiu im t 6 Ch FS c kch hot, nu trong trng hp gii tr li, OFF2 th ch khi ng theo chiu im t P1202 = Dng ng c trong ch khi ng bm (tnh theo %) 100% Xc nh dng in tm kim cho ch khi ng khi ng c ang quay. P1203 =? Di tm kim trong ch khi ng bm (tnh theo %) 100% t h s tn s ra thay i theo trong ch khi ng khi ng c ang quay ng b vi ng c ang quay.P1200 = Khi ng bm (Flying start - FS)

6.4.18.2 T khi ngP1210 =

T khi ng t cu hnh chc nng t khi ng 0 Khng tc dng 1 Li c gii tr sau khi cp ngun tr li 2 Khi ng li sau s c mt ngun 3 Khi ng li sau s c thp p li hoc cc li khc 4 Khi ng li sau s c thp p li 5 Khi ng li sau s c mt ngun v cc li khc 6 Khi ng li sau s c thp p/ mt ngun hoc li khc

1


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6 Ci t thng s

6.4.18.3 Phanh hm c kh ca ng cCi t cho cc ti nguy him - H ti xung t - Khi thay b bin tn, khng b bin tn thc hin chc nng iu khin phanh hm ng c - m bo an ton cho ti trng hoc dng hn vic iu khin ch hm ng c ( b hm khng b iu khin), ri sau mi thc hin ci t nhanh v/hoc ti thng s xung nh cng c trn PC (v d nh phn mm STARTER hay AOP) Ci t thng s cn bng trng lng i vi cc ng dng nng h - Thi gian t ho P0346 ln hn 0. - Tn s nh nht P1080 nn gn bng tn s trt ca ng c r0330 (P1080 r0330). - Hiu chnh in p b tng theo ti. a) V/f (P1300 = 03): P1310, P1311 b) SLVC (P1300 = 20): P1610, P 1611 Khng nu ch chn tn hiu trng thi r0052 bit 12 phanh hm ng c c kch hot gn cho P0731- P0733. Ngoi ra kch hot phanh hm ng c, thng s P1215 phi c t 1. Khng c php dng phanh hm ng c lm phanh hot ng thng xuyn. V phanh ny thng thng ch c thit k cho mt s lng gii hn s ln phanh khn cp. Thi gian ng/m phanh c th c ly t ti liu th nghim ph hp. Cc gi tr in hnh di y c ly t ti liu th nghim Motor Catalog M11 2003/2004, trang 2/51: C ng c 63 71 80 90 100 112 132 160 180 200 225P1215 =

Kiu phanh 2LM8 005-1NAxx 2LM8 005-2NAxx 2LM8 010-3NAxx 2LM8 020-4NAxx 2LM8 040-5NAxx 2LM8 060-6NAxx 2LM8 100-7NAxx 2LM8 260-8NAxx 2LM8 315-0NAxx 2LM8 400-0NAxx

Thi gian m [ms] 25 25 26 37 43 60 50 165 152 230

Thi gian ng [ms] 56 56 70 90 140 210 270 340 410 390

0 BI: Kch hot phanh hm ngoi 0 Phanh hm ng c hot ng 1 Phanh hm khng hot ng CH Mun iu khin phanh hm bng u ra r le s th:P0731 = 52.C (=52.12) (hy xem phn 6.4.4 "Cc u ra s (DOUT)").

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P0731=52.C

P0748 = 0

BI: Chc nng u ra s s 1 52.3 Cc ch ci t thng thng Xc nh ngun ca u ra s s 1 52.0 Sn sng cp ngun CH 52.1 Sn sng chy Cng c th iu khin rle phanh 52.2 H truyn ng ang chy t u ra s khc (nu c). Tng 52.3 Kch hot ch pht hin li t nh DOUT1, nn m bo rng 52.4 Phm OFF2 hot ng I/Os c iu khin bng bit trng 52.5 Phm OFF3 hot ng thi "MHB c kch hot" 52.6 Kho chuyn mch khng c hot ng 52.7 Ch cnh bo hot ng 52.8 chnh lch gia gi tr im t v gi tr thc t 52.9 iu khin PLC/PZD 0 52.A Tn s ln nht t dc o cc u ra s Thng s ny cho php o cc tn 52.B Cnh bo: Gii hn dng in ca hiu ra ng c 52.C Phanh hm ng c hot ng 52.D ng c qu ti 52.E Chiu quay ca ng c, cng chiu kim ng h 52.F Qu ti bin tn 53.0 Mun hm DC hot ng 53.1 Tn s thc f_act > P2167 (f_off) : Knh DOUT Bin i DOUTs Thi gian tr nh phanh (n v s) 1.0sCO/BO: DOUTs trng thi

0 0 0 0 1 1 0 0 1 0 0 1 0 1 0 1 0 0

ng ng ng ng ng ng ng ng ng ng ng ng ng ng ng ng ng ng

Chc nng xxxx.y

Rle:

- thi gian ng / m ln nht

P1216 =

P1217 =

Thi gian tr nh phanh (n v s) Xc nh khong thi gian m b bin tn chy vi tn s nh nht P1080 sau khi t ho v trc khi bt u tng tc. P1216 thi gian m phanh + thi gian m rle Thi gian hm sau khi gim tc (n v s) Xc nh thi gian b bin tn chy tn s nh nht (P1080) sau khi gim tc P1217 thi gian ng phanh + thi gian ng rle

1.0s

1.0s


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6 Ci t thng s

6.4.18.4 Hm mt chiu (DC)P1230 =

BI: Kch hot hm DC Thng s ny cho php hm DC hot ng s dng tn hiu ly t ngun ngoi. Chc nng ny c duy tr vi iu kin tn hiu bn ngoi c kch hot. Hm DC lm cho ng c dng nhanh bng cch bm dng DC vo ng cBI: Kch hot hm DC

f_tHm DC

f_thc

Hm DC hot ng

P1232 =

P1233 =

Ch : C th dng hm DC khi bin tn cc trng thi r0002 = 1,4,5 100% Dng hm DC (theo %) Xc nh mc dng hm DC theo % tng ng vi dng in nh mc ca ng c (P0305). 0s Thi gian hm DC Xc nh khong thi gian m hm bng dng DC c kch hot sau lnh OFF1 hoc OFF3.

Hm DC

Hm DC hot ng

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dc OFF Phanh DC

Phanh DC hot ng

P1234 =

Tn s bt u phanh DC (n v Hz) t tn s bt u phanh DC.

650Hz

6.4.18.5 Hm hn hpP1236 =

Dng in cho hm hn hp (theo %) 0% Xc nh mc dng in DC t ln trn sng AC sau khi vt qu ngng in p DC t cho hm hn hp. Gi tr dng nhp theo [%] tng ng vi dng in nh mc ca ng c (P0305). (hy xem phn 6.4.12). Nu P1254 = 0 : Ngng in p t cho hm hn hp Hoc: Ngng in p t cho hm hn hp P1236 = 0 Khng c hm hn hpf_t f_t

UDC_Comp = 1,13 x

2 Vmains = 1,13 2 P0210

UDC_Comp = 0,98.r1242 P1236 > 0 C hm hn hp

f_thc t

f_thc t


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6.4.18.6 Hm ng nngP1237 =

0 Hm ng nng Ch hm ng nng c kch hot nh thng s P1237- xc nh chu k lm vic nh mc cng nh thi gian ng ca in tr hm. 0 Khng lm vic 1 Chu k hm c ti 5% 2 Chu k hm c ti 10% 3 Chu k hm c ti 20% 4 Chu k hm c ti 50% 5 Chu k hm c ti 100% Khi s dng hm ng nng, nng lng phn hi ch my pht c chuyn cho in tr hm ngoi thng qua b hm c iu khin, nng lng c chuyn thnh nhit nng trong in tr ny. Ch hm ng nng cho php kim sot c qu trnh hm ca b truyn ng.Chc nng ny khng tch hp sn i vi bin tn c v FX v GX.in tr hm ngoi

B hm c iu khin

6.4.18.7 B iu khin VdcP1240 =...

P1254 =...

Cu hnh ca b iu khin Vdc Kch hot/ khng kch hot b iu khin Vdc. 0 B iu khin Vdc khng hot ng 1 Kch hot b iu khin Vdc-max T ng pht hin cc mc lm vic Vdc Kch hot/ khng kch hot ch t pht hin cc mc lm vic cho b iu khin Vdc cc chc nng khc nhau. 0 Khng c kch hot 1 c kch hot

1

VDC r1242

1

Kch hot b iu khin Vdc-max

A0911

fthc t fthc t

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6.4.18.8 B iu khin PIDP2200 =...

P2253 =... P2254 =...

P2257 =... P2258 =... P2264 =... P2267 =... P2268 =... P2280 =... P2285 =... P2291 =... P2292 =...

0.0 BI: Kch hot b iu khin PID Ch PID cho php ngi s dng kch hot/ khng kch hot b iu khin PID. Ch ci t ti gi tr 1 s kch hot b iu khin PID v s t ng loi b thi gian tng tc/gim tc c t trc P1120 v P1121 cng im t tn s thng thng. 0.0 CI: im t PID Xc nh ngun im t cho u vo PID 0.0 CI: Ngun PID b tr Chn ngun b tr cho im t PID. Tn hiu ny c nhn vi h s b tr v cng vo vi gi tr im t PID. 1.00s Thi gian tng tc cho im t PID t thi gian tng tc cho im t PID 1.00s Thi gian gim tc cho im t PID t thi gian gim tc cho im t PID 755.0 CI: Tn hiu phn hi PID Chn ngun cho tn hiu phn hi PID. 100.00% Gi tr tn hiu phn hi PID ln nht t gii hn trn cho gi tr tn hiu phn hi theo [%] 0.00% Gi tr tn hiu phn hi PID nh nht t gii hn di cho gi tr tn hiu phn hi theo [%] 3.000 H s t l ca b iu khin PID Cho php ngi s dng ci t h s t l cho b iu khin PID 0.000s Hng s thi gian tch phn PID Ci t hng s thi gian tch phn cho b iu khin PID 100.00% Gii hn trn ca u ra PID t gii hn trn cho u ra ca b iu khin PID theo [%] 0.00% Gii hn di ca u ra PID t gii hn di cho u ra ca b iu khin PID theo [%]

iu khin ng c

PIDra

V d:

Thng s P2200 P2253 P 2264 P 2267 P2268 P2280 P2285 P2291 P2292

Thng s dng vn bn BI: kch hot b iu khin PID CI: im t PID CI: Gi tr phn hi PID Gi tr phn hi PID ln nht Gi tr phn hi PID nh nht H s t l ca b iu khin PID Hng s thi gian tch phn PID Gii hn trn ca u ra PID Gii hn di ca u ra PID

V d P2200 = 1.0 P2253=2224 P2264=755 P2267 P2268 P2280 P2285 P2291 P2292

Thng s B iu khin PID hot ng PID-FF1 ADC Hiu chnh cho ng dng Hiu chnh cho ng dng Xc nh bi qu trnh ti u ho Xc nh bi qu trnh ti u ho Hiu chnh cho ng dng Hiu chnh cho ng dng 61


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6.4.18.9 Cc khi chc nng t do (FFB)P2800 =

P2801 =

P2802 =

0 Cho php dng FFBs Thng s P2800 c dng cho php s dng tt c cc khi chc nng. Cng theo thng s P2801 v P2802 s cho php kch hot cc khi chc nng tng ng Cc ch ci t c th: 0 Khng cho php 1 Cho php 0.0 Kch hot FFBs Thng s P2801 c dng kch hot tng khi chc nng t do t P2801[ 0] n P2801[16] ( P2801 [x] >0) Cc ch ci t c th: 0 Khng hot ng 1 Mc 1 2 Mc 2 3 Mc 3 Kch hot FFBs Thng s P2802 c dng kch hot tng khi chc nng t do t P2802 [0] n P2802 [13] ( P2802[x]>0) Cc ch ci t c th: 0 Khng hot ng 1 Mc 1 2 Mc 2 3 Mc 3 Hn na, cc thng s P2801 v P2802 c dng xc nh cc tun t thi gian ca tt c cc khi chc nng. Bng di y cho thy s u tin tng t tri qua phi v t trn xung di. V d: P2801[3] = 2, P2801[4] =2, P2802[3] =3, P2802 [4] = 2 FFBs c tnh theo tun t sau: P2802[3], P 2801[3] , P2801[4], P2802[4] (Timer 4, OR1, OR2, ADD1) Cc khi chc nng hot ng c tnh ton 132 ms mt ln.thp u tin 2 cao u tin 1

Mc 3 Mc 2 Mc 1 Mc 0

M

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6.4.19 Tp d liu lnh v truyn ngP0810 =

B d liu lnh CDS bit 0 (ti ch/ t xa) Chn ngun lnh m trong bit 0 c c ra chn b d liu lnh (CDS). Chn CDS

0

CDS hot ng

Thi gian chuyn i

Thi gian chuyn i

B d liu hin ang hot ng (CDS) c hin th nh thng s r0050 Chn CDS CDS hot ng r0055 bit r0054 bit r0050 15 15 1. CDS 0 0 0 2. CDS 0 1 1 3. CDS 1 0 2 3. CDS 1 1 2 Cc ch ci t thng dng nht 722.0 = u vo s s 1 (P 0701 phi c t ti 99, BICO) 722.1 = u vo s s 2 (P 0702 phi c t ti 99, BICO) 722.2 = u vo s s 3 (P 0703 phi c t ti 99, BICO) 722.3 = u vo s s 4 (P 0704 phi c t ti 99, BICO) 722.4 = u vo s s 5 (P 0705 phi c t ti 99, BICO) 722.5 = u vo s s 6 (P 0706 phi c t ti 99, BICO) 722.6 = u vo s s 7 (thng qua u vo tng t s 1, P 0707 phi c t ti 99) 722.7 = u vo s s 8 (thng qua u vo tng t s 2, P 0708 phi c t ti 99) V d v chuyn i CDS CDS1: Ngun lnh thng qua cc u ni v ngun im t thng qua u vo tng t (ADC) CDS2: Ngun lnh thng qua BOP v ngun im t qua MOP S chuyn i CDS c thc hin nh u vo s s 4 (DIN4) Cc bc: 1. Thc hin qu trnh ci t CDS1 (P0700[0] =2 v P1000[0] =2) 2. Ni P0810 (P0811 nu cn) vi ngun chuyn i CDS (P0704[0] = 99, P0810 = 722.3) 3. Sao chp t CDS1 ti CDS2 (P0809 [0]=0, P0809[1]=1, P0809 [2]=2 4. Hiu chnh thng s CDS2 (P0700 [1]=1 v P1000 [1] =1)


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iu khin tun t.

Knh im t

iu khin ng c

P0820=...

0 BI: B d liu truyn ng (DDS) bit 0 Chn ngun lnh m t bit 0 c c ra chn mt b d liu cho b truyn ng.Ch vn hnh Ch sn sng Chn

Thi gian chuyn i

Thi gian chuyn i

DDC hot ng

B d liu hin ang hot ng (CDS) c hin th nh thng s r0051[1] DDS hot Chn DDS ng r0055 bit r0054 bit r0051[0] r0051[1] 05 04 1. DDS 0 0 0 0 2. DDS 0 1 1 1 3. DDS 1 0 2 2 3. DDS 1 1 2 2 Cc ch ci t thng dng nht 722.0 = u vo s s 1 (P0701 phi c t ti 99, BICO) 722.1 = u vo s s 2 (P0702 phi c t ti 99, BICO) 722.2 = u vo s s 3 (P0703 phi c t ti 99, BICO) 722.3 = u vo s s 4 (P0704 phi c t ti 99, BICO) 722.4 = u vo s s 5 (P0705 phi c t ti 99, BICO) 722.5 = u vo s s 6 (P0706 phi c t ti 99, BICO) 722.6 = u vo s s 7 (thng qua u vo tng t s 1, P0707 phi c t ti 99) 722.7 = u vo s s 8 (thng qua u vo tng t s 2, P0708 phi c t ti 99)

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V d 1 Cc bc ci t cho mt ng c -Tin hnh ci t ti DDS1 -Ni P0820 (P0821 nu cn) vi ngun chuyn i DDS (v d s dng DIN 4: P0704[0]=99, P0820=722.3) -Sao chp DDS1 ti DDS2 ( P0819[0]=0, P0819[1] =1, P0819[2] = 2 -Hiu chnh cc thng s DDS2 ( v d thi gian tng tc, thi gian gim tc P1120[1] v P1121[1])iu khin tun t B iu khin cc cng iu khin ng c

SUM im t

2

Cc bc ci t i vi trng hp c 2 ng c (ng c 1, ng c 2) - Ci t thng s cho ng c 1; hiu chnh cc thng s DDS1 cn li - Ni P0820 (P0821 nu cn) vi ngun chuyn i DDS (v d qua DIN 4: P0704[0]=99, P0820=722.3) - Chuyn ti DDS2 (kim tra nh thng s r0051). - Ci t thng s cho ng c 2; hiu chnh cc thng s DDS2 cn ling c 1

ng c 2


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6 Ci t thng s

6.4.20 Thng s chn onr0035 r0036 CO: Nhit ng c Hin th nhit ca ng c c o theo n v oC CO:Mc tn dng bin tn Hin th mc tn dng bin tn theo % tng ng vi kh nng qu ti. lm c iu ny, gi tr ny c tnh ton bng m hnh I2t Gi tr thc t I2t tng ng vi gi tr I2t ln nht c th t c cho bit mc tn dng ca b bin tn CO/BO: T hin th trng thi s 1 Hin th t trng thi u tin (ZSW) ca bin tn (theo nh dng bit) v c th c dng chun on trng thi b bin tn. CO/BO: T iu khin s 1 Hin th t iu khin u tin (STW) ca bin tn (theo nh dng bit) v c th c dng hin th cc lnh ang thc hin. CO: Tn s thc t Hin th tn s thc t theo n v Hz.Gi tr thc ca tc c lc Gi tr thc ca tn s c lc

r0052

r0054

r0063

Cc gi tr tn s thc t

M hnh tnh ton

Gi tr tn s thc

Tn s xung encoder gi tr tn s thc

r0079

r1114

CO: im t tn s c chn Hin th gi tr t tn s c chn. Cc gi tr im t tn s sau c hin th: r1078 Gi tr t tng (HSW+ZUSW) P1058 Tn s chy nhp, theo chiu kim ng h. P1059 Tn s chy nhp, ngc chiu kim ng h. CO: im t tn s sau khi iu khin chiu quay ca ng c. Hin th gi tr t tn s (tn s chun) theo n v Hz sau khi chc nng o chiu quay ng c.

r1170

CO: im t tn s sau b pht hm to dc Hin th gi tr t tn s tng ( gi tr chun) theo n v Hz sau b pht hm to dc.

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