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Calculos de velocidades y aceleraciones

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Calculo de velocidades y aceleraciones para el mecanismo caja negra

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Page 1: Calculos de velocidades y aceleraciones

CΓ‘lculos para Ι΅=0.

VELOCIDADES

VA = Ο‰2 βˆ— rA

VA = 200 mm s

VB = VA + VB/A

100 π‘šπ‘šπ‘ 

sin 94.54=

𝑉𝐡

sin 75.11

𝑉𝐡 = 96.95 π‘šπ‘šπ‘ 

𝑉𝐡𝐴

= 100 π‘šπ‘šπ‘  2 + (96.95 π‘šπ‘š

𝑠 )2 βˆ’ 2 100 π‘šπ‘šπ‘  96.95 π‘šπ‘š

𝑠 βˆ— cos 10. 35

𝑉 𝐡𝐴 = 18.02 π‘šπ‘š

𝑠

πœ”4 =𝑉𝐡

π‘Ÿπ΅

πœ”4 = 1.43 π‘Ÿπ‘Žπ‘‘π‘ 

πœ”3 =𝑉 𝐡

𝐴

π‘Ÿ 𝐡𝐴

πœ”3 = 0.277 π‘Ÿπ‘Žπ‘‘ 𝑠

𝑉𝐷 = πœ”4 βˆ— π‘Ÿπ·

𝑉𝐷 = 1.43 βˆ— 115

𝑉𝐷 = 164.45 π‘šπ‘šπ‘ 

VE = VD + VE/D

164.45 π‘šπ‘šπ‘ 

sin 17.6=

𝑉𝐸

sin 90

𝑉𝐸 = 543.87 π‘šπ‘šπ‘ 

543.87 π‘šπ‘šπ‘ 

sin 17.6=

𝑉𝐸/𝐷

sin 72.4

Page 2: Calculos de velocidades y aceleraciones

𝑉𝐸/𝐷 = 518.87 π‘šπ‘šπ‘ 

πœ”5 =𝑉𝐸/𝐷

π‘ŸπΈ/𝐷

πœ”5 = 4.5 π‘Ÿπ‘Žπ‘‘π‘ 

πœ”6 =𝑉𝐸

π‘ŸπΈ

πœ”6 = 2.6 π‘Ÿπ‘Žπ‘‘ 𝑠

ACELERACIONES

π‘Žπ΄ = π‘Žπ΄π‘›+ π‘Žπ΄π‘‘

Como Ο‰2 es constante, entonces Ξ±2 es 0 y por ende aceleraciΓ³n tangencial de A es cero.

π‘Žπ΄ = π‘Žπ΄π‘›= πœ”2

2π‘Ÿπ΄ = 22 βˆ— 50 = 200 π‘šπ‘šπ‘ 2

π‘Žπ΅π‘›+ π‘Žπ΅π‘‘

= π‘Žπ΄π‘›+ π‘Žπ΅/𝐴𝑛

+ π‘Žπ΅/𝐴𝑑

π‘Žπ΅π‘›=πœ”4 𝑋 πœ”4 𝑋 π‘Ÿπ΅

π‘Žπ΅π‘›= 1.43 π‘˜ 𝑋 (1.43 𝐾 𝑋(66.7 𝑖 βˆ’ 12.18 𝑗)

π‘Žπ΅π‘›= βˆ’136.39 𝑖 + 26.18 𝑗

π‘Žπ΅π‘‘= 𝛼4 𝑋 π‘Ÿπ΅ = 𝛼4π‘˜ 𝑋 66.7 𝑖 βˆ’ 12.18 𝑗

π‘Žπ΅π‘‘= 66.70 βˆ— 𝛼4𝑖 + 12.18 βˆ— 𝛼4 𝑗

π‘Žπ΅/𝐴𝑛=πœ”3 𝑋 πœ”3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅/𝐴𝑛= 0.277 π‘˜ 𝑋 4.62 𝑗 βˆ’ 17.39 𝑖 = βˆ’1.27 𝑖 βˆ’ 4.81𝑗

π‘Žπ΅/𝐴𝑑= 𝛼3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅π΄π‘‘

= βˆ’π›Ό3 βˆ— 62.81 𝑗 + 𝛼3 βˆ— 16.702 𝑖

𝑖 β†’ 𝛼4 βˆ— 12.18 + 𝛼362.81 = βˆ’64.88

𝑗 β†’ 𝛼4 βˆ— 66.70 βˆ’ 𝛼3 βˆ— 16.702 = βˆ’31.69

𝛼4 = βˆ’0.0699 π‘Ÿπ‘Žπ‘‘π‘ 2

Page 3: Calculos de velocidades y aceleraciones

𝛼3 = 1.01 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘Žπ΅ = 139.01 π‘šπ‘šπ‘ 2

π‘Žπ·π‘›= 42.24 𝑗 βˆ’ 231.23 𝑖

π‘Žπ·π‘‘= 1.46 𝑖 + 8.005 𝑗

π‘Žπ· = 235.9 π‘šπ‘š 𝑠2

π‘ŽπΈπ‘›+ π‘ŽπΈπ‘‘

= π‘Žπ·π‘›+ π‘Žπ·π‘‘

+ π‘ŽπΈ/𝐷𝑛+ π‘ŽπΈ/𝐷𝑑

π‘ŽπΈπ‘› =πœ”6 𝑋 πœ”6 𝑋 π‘ŸπΈ

π‘ŽπΈπ‘›= βˆ’2.6 π‘˜ 𝑋 (βˆ’2.6 𝐾 𝑋(βˆ’63.5 𝑖 βˆ’ 200.17 𝑗)

π‘ŽπΈπ‘›= βˆ’429.26 𝑖 βˆ’ 1353.15 𝑗

π‘ŽπΈπ‘‘= 𝛼6 𝑋 π‘ŸπΈ = 𝛼6 𝑋 βˆ’63.5 𝑖 + 200.17 𝑗

π‘ŽπΈπ‘‘= βˆ’200.17 βˆ— 𝛼6𝑖 βˆ’ 63.5 βˆ— 𝛼6 𝑗

π‘ŽπΈ/𝐷𝑛 =πœ”5 𝑋 πœ”5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑛= βˆ’4.6 π‘˜ 𝑋 84.18 𝑗 + 522.19 𝑖 = 387.22 𝑖 βˆ’ 2402.047𝑗

π‘ŽπΈ/𝐷𝑑= 𝛼5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑑= βˆ’π›Ό5 βˆ— 18.37 𝑗 + 𝛼5 βˆ— 113.52 𝑖

𝑖 β†’ βˆ’π›Ό6 βˆ— 200.77 βˆ’ 𝛼5113.5 = βˆ’273.27

𝑗 β†’ βˆ’π›Ό6 βˆ— 63.5 βˆ’ 𝛼5 βˆ— 18.37 = βˆ’3712.97

𝛼6 = βˆ’38.67 π‘Ÿπ‘Žπ‘‘π‘ 2

𝛼5 = 70.81 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘ŽπΈ = 8266.85 π‘šπ‘šπ‘ 2

Page 4: Calculos de velocidades y aceleraciones

CΓ‘lculos para Ι΅=45

VELOCIDADES

𝑉𝐴 = πœ”2 𝑋 π‘Ÿπ‘Ž

𝑉𝐴 = βˆ’2π‘˜ 𝑋 35.36 𝑖 + 35.36 𝑗 = βˆ’70.72 𝑗 + 70.72 𝑖 = 100 π‘šπ‘šπ‘ 2

VB = VA + VB/A

𝑉𝐡 = πœ”4 𝑋 π‘Ÿπ΅

𝑉𝐡 = πœ”4π‘˜ 𝑋 65.37 𝑖 + 18 𝑗 = πœ”4 βˆ— 65.3 𝑗 βˆ’ πœ”4 βˆ— 18 𝑖

𝑉𝐡𝐴

= πœ”3 𝑋 π‘Ÿπ΅/𝐴

𝑉𝐡𝐴

= πœ”3π‘˜ 𝑋 30.02 𝑖 + 57.65 𝑗 = πœ”3 βˆ— 30.02 𝑗 βˆ’ πœ”3 βˆ— 57.65 𝑖

𝑖 β†’ βˆ’πœ”3 βˆ— 57.65 + πœ”4 βˆ— 18 = 70.72

𝑗 β†’ πœ”3 βˆ— 30.02 βˆ’ πœ”4 βˆ— 65.37 = βˆ’70.72

πœ”3 = βˆ’1.82 π‘Ÿπ‘Žπ‘‘ 𝑠

πœ”4 = βˆ’1.91 π‘Ÿπ‘Žπ‘‘ 𝑠

𝑉𝐡 = 129.50 π‘šπ‘šπ‘ 

𝑉𝐷 = πœ”4 𝑋 π‘Ÿπ·

𝑉𝐷 = βˆ’1.92 𝐾 𝑋 110.8 𝑖 + 30.53 𝑗 = βˆ’212.73 𝑗 + 58.61 𝑖 = 220.65 π‘šπ‘šπ‘ 

VE = VD + VE/D

VE = Ο‰6 X rE

𝑉𝐸 = πœ”6 π‘˜ 𝑋 5.46 𝑖 + 209.9 𝑗 = πœ”6 βˆ— 5.46 𝑗 βˆ’ πœ”6 βˆ— 209,9 𝑖

𝑉𝐸/𝐷 = πœ”5 𝑋 π‘ŸπΈ/𝐷

𝑉𝐸/𝐷 = πœ”5 π‘˜ 𝑋 89.59𝑖 + 72.09 𝑗 = πœ”5 βˆ— 85.59 𝑗 βˆ’ πœ”5 βˆ— 72.09 𝑖

𝑖 β†’ βˆ’πœ”6 βˆ— 209.9 + πœ”5 βˆ— 72.09 = 55.56

𝑗 β†’ πœ”6 βˆ— 5.46 βˆ’ πœ”5 βˆ— 89.59 = βˆ’201.65

πœ”6 = βˆ’1.05 π‘Ÿπ‘Žπ‘‘ 𝑠

πœ”5 = βˆ’2.28 π‘Ÿπ‘Žπ‘‘ 𝑠

Page 5: Calculos de velocidades y aceleraciones

𝑉𝐸 = 220.46 π‘šπ‘šπ‘ 

ACELERACIONES

π‘Žπ΄ = π‘Žπ΄π‘›+ π‘Žπ΄π‘‘

Como Ο‰2 es constante, entonces Ξ±2 es 0 y por ende aceleraciΓ³n tangencial de A es cero.

π‘Žπ΄π‘› = πœ”2 𝑋(πœ”2 𝑋 π‘Ÿπ΄)

π‘Žπ΄π‘› = βˆ’2π‘˜ 𝑋 βˆ’70.72 𝑗 + 70.72 𝑖 = βˆ’141.44 𝑖 βˆ’ 141.44 𝑗 = 200 π‘šπ‘šs2

π‘Žπ΅π‘›+ π‘Žπ΅π‘‘

= π‘Žπ΄π‘›+ π‘Žπ΅/𝐴𝑛

+ π‘Žπ΅/𝐴𝑑

π‘Žπ΅π‘›=πœ”4 𝑋 πœ”4 𝑋 π‘Ÿπ΅

π‘Žπ΅π‘›= βˆ’1.91 π‘˜ 𝑋 (βˆ’124.85 𝑗 + 34.81 𝑖)

π‘Žπ΅π‘›βˆ’ 238.46 𝑖 βˆ’ 65.66 𝑗

π‘Žπ΅π‘‘= 𝛼4 𝑋 π‘Ÿπ΅ = 𝛼4 π‘˜ 𝑋 65.37 𝑖 + 18 𝑗

π‘Žπ΅π‘‘= βˆ’18 βˆ— 𝛼4𝑖 + 65.37 βˆ— 𝛼4 𝑗

π‘Žπ΅/𝐴𝑛=πœ”3 𝑋 πœ”3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅/𝐴𝑛= βˆ’1.82 π‘˜ 𝑋 βˆ’54.63 𝑗 + 104.9 𝑖 = βˆ’99.4 𝑖 βˆ’ 190.9𝑗

π‘Žπ΅/𝐴𝑑= 𝛼3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅/𝐴 𝑑 = 𝛼3 βˆ— 30.02 𝑗 βˆ’ 𝛼3 βˆ— 57.65 𝑖

𝑖 β†’ βˆ’π›Ό4 βˆ— 18 + 𝛼3 βˆ— 57.65 = βˆ’2.28

𝑗 β†’ 𝛼4 βˆ— 65.37 βˆ’ 𝛼3 βˆ— 30.02 = βˆ’266.68

𝛼4 = βˆ’4.76 π‘Ÿπ‘Žπ‘‘π‘ 2

𝛼3 = βˆ’1.53 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘Žπ΅ = 400.61 π‘šπ‘šπ‘ 2

π‘Žπ· = π‘Žπ·π‘›+ π‘Žπ·π‘‘

π‘Žπ·π‘› = πœ”4 𝑋 πœ”4 𝑋 π‘Ÿπ΅ = βˆ’1.92 π‘˜ 𝑋 βˆ’212.73 𝑗 + 58.61 𝑖 = βˆ’408.44 𝑖 βˆ’ 112.53 𝑗

π‘Žπ·π‘‘= 𝛼4 𝑋 π‘Ÿπ΅ = βˆ’4.76 π‘˜ 𝑋 110.8 𝑖 + 30.53 𝑗 = βˆ’527.408 𝑖 βˆ’ 639, .93 𝑗

π‘Žπ· = 691.91 π‘šπ‘šπ‘ 2

Page 6: Calculos de velocidades y aceleraciones

π‘ŽπΈπ‘›+ π‘ŽπΈπ‘‘

= π‘Žπ·π‘›+ π‘Žπ·π‘‘

+ π‘ŽπΈ/𝐷𝑛+ π‘ŽπΈ/𝐷𝑑

π‘ŽπΈπ‘› =πœ”6 𝑋 πœ”6 𝑋 π‘ŸπΈ

π‘ŽπΈπ‘›βˆ’ 1.05 π‘˜ 𝑋 (βˆ’5.73 𝑗 + 220.39 𝑖)

π‘ŽπΈπ‘›= βˆ’ βˆ’ 6.01 𝑖 βˆ’ 231.4 𝑗

π‘ŽπΈπ‘‘= 𝛼6 𝑋 π‘ŸπΈ = 𝛼6π‘˜ 𝑋 5.46 𝑖 + 209.9 𝑗

π‘ŽπΈπ‘‘= βˆ’209.9 βˆ— 𝛼6𝑖 + 5.46 βˆ— 𝛼6 𝑗

π‘ŽπΈ/𝐷𝑛 =πœ”5 𝑋 πœ”5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑛= βˆ’2.28π‘˜ 𝑋 βˆ’204.2 𝑗 + 164.36 𝑖 = βˆ’465.71 𝑖 βˆ’ 374.74 𝑗

π‘ŽπΈ/𝐷𝑑= 𝛼5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑑= 𝛼5 βˆ— 89.59 𝑗 βˆ’ 𝛼5 βˆ— 72.09 𝑖

𝑖 β†’ βˆ’π›Ό6 βˆ— 209.9 + 𝛼572.09 = βˆ’722.82

𝑗 β†’ 𝛼6 βˆ— 5.46 βˆ’ 𝛼5 βˆ— 81.59 = βˆ’783.27

𝛼6 = βˆ’3.6 π‘Ÿπ‘Žπ‘‘π‘ 2

𝛼5 = 0.45 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘ŽπΈ = 6770.24 π‘šπ‘šπ‘ 2

Page 7: Calculos de velocidades y aceleraciones

CΓ‘lculos para Ι΅=105

VELOCIDADES

𝑉𝐴 = πœ”2 𝑋 π‘Ÿπ‘Ž

𝑉𝐴 = βˆ’2π‘˜ 𝑋 12.94 𝑖 + 98.29 𝑗 = βˆ’25.88 𝑗 + 96.59 𝑖 = 100 π‘šπ‘šπ‘ 2

VB = VA + VB/A

𝑉𝐡 = πœ”4 𝑋 π‘Ÿπ΅

𝑉𝐡 = πœ”4π‘˜ 𝑋 48.77 𝑖 βˆ’ 47.11 𝑗 = πœ”4 βˆ— 48.77 𝑗 + πœ”4 βˆ— 47.11 𝑖

𝑉𝐡𝐴

= πœ”3 𝑋 π‘Ÿπ΅/𝐴

𝑉𝐡𝐴

= πœ”3π‘˜ 𝑋 61.71 𝑖 βˆ’ 20.40 𝑗 = πœ”3 βˆ— 61.71 𝑗 + πœ”3 βˆ— 20.40 𝑖

𝑖 β†’ βˆ’πœ”3 βˆ— 20.9 + πœ”4 βˆ— 47.11 = 96.59

𝑗 β†’ βˆ’πœ”3 βˆ— 61.71 + πœ”4 βˆ— 48.77 = βˆ’25.88

πœ”3 = 3.13 π‘Ÿπ‘Žπ‘‘ 𝑠

πœ”4 = 3.44 π‘Ÿπ‘Žπ‘‘ 𝑠

𝑉𝐡 = 233.25 π‘šπ‘šπ‘ 

𝑉𝐷 = πœ”4 𝑋 π‘Ÿπ·

𝑉𝐷 = 3.44𝐾 𝑋 82.71 𝑖 βˆ’ 79.9 𝑗 = 284.52 𝑗 + 274.85 𝑖 = 295.544 π‘šπ‘šπ‘ 

VE = VD + VE/D

VE = Ο‰6 X rE

𝑉𝐸 = πœ”6 π‘˜ 𝑋 βˆ’165.39 𝑖 + 129.4𝑗 = βˆ’πœ”6 βˆ— 165.39 𝑗 βˆ’ πœ”6 βˆ— 129.4 𝑖

𝑉𝐸/𝐷 = πœ”5 𝑋 π‘ŸπΈ/𝐷

𝑉𝐸/𝐷 = πœ”5 π‘˜ 𝑋 βˆ’102 𝑖 βˆ’ 53.1 𝑗 = βˆ’πœ”5 βˆ— 102 𝑗 + πœ”5 βˆ— 53.1 𝑖

𝑖 β†’ βˆ’πœ”6 βˆ— 129.4 βˆ’ πœ”5 βˆ— 53.1 = 274.85

𝑗 β†’ βˆ’πœ”6 βˆ— 165.39 + πœ”5 βˆ— 102 = 284.85

πœ”6 = βˆ’1.96 π‘Ÿπ‘Žπ‘‘ 𝑠

πœ”5 = βˆ’0.39 π‘Ÿπ‘Žπ‘‘ 𝑠

Page 8: Calculos de velocidades y aceleraciones

𝑉𝐸 = 411.59 π‘šπ‘šπ‘ 

ACELERACIONES

π‘Žπ΄ = π‘Žπ΄π‘›+ π‘Žπ΄π‘‘

Como Ο‰2 es constante, entonces Ξ±2 es 0 y por ende aceleraciΓ³n tangencial de A es cero.

π‘Žπ΄π‘› = πœ”2 𝑋(πœ”2 𝑋 π‘Ÿπ΄)

π‘Žπ΄π‘› = βˆ’2π‘˜ 𝑋 βˆ’25.88 𝑗 + 70.72 𝑖 = βˆ’51.76 𝑖 βˆ’ 193.18 𝑗 = 200 π‘šπ‘šs2

π‘Žπ΅π‘›+ π‘Žπ΅π‘‘

= π‘Žπ΄π‘›+ π‘Žπ΅/𝐴𝑛

+ π‘Žπ΅/𝐴𝑑

π‘Žπ΅π‘›=πœ”4 𝑋 πœ”4 𝑋 π‘Ÿπ΅

π‘Žπ΅π‘›= 3.44 π‘˜ 𝑋 (167.76 𝑗 + 162.05 𝑖)

π‘Žπ΅π‘›βˆ’ 577.09 𝑖 + 557.45 𝑗

π‘Žπ΅π‘‘= 𝛼4 𝑋 π‘Ÿπ΅ = 𝛼4 π‘˜ 𝑋 48.77 𝑖 βˆ’ 47.11 𝑗

π‘Žπ΅π‘‘= 48.77 βˆ— 𝛼4𝑖 + 47.11 βˆ— 𝛼4 𝑗

π‘Žπ΅/𝐴𝑛=πœ”3 𝑋 πœ”3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅/𝐴𝑛= 3.13 π‘˜ 𝑋 193.1 𝑗 + 63.85 𝑖 = βˆ’604.4 𝑖 + 199.85𝑗

π‘Žπ΅/𝐴𝑑= 𝛼3 𝑋 π‘Ÿπ΅/𝐴

π‘Žπ΅/𝐴 𝑑 = 𝛼3 βˆ— 61.71 𝑗 βˆ’ 𝛼3 βˆ— 20.4 𝑖

𝑖 β†’ βˆ’π›Ό4 βˆ— 18 + 𝛼3 βˆ— 57.65 = βˆ’2.28

𝑗 β†’ 𝛼4 βˆ— 65.37 βˆ’ 𝛼3 βˆ— 30.02 = βˆ’266.68

𝛼4 = 11.90 π‘Ÿπ‘Žπ‘‘π‘ 2

𝛼3 = 31.36 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘Žπ΅ = 580.36 π‘šπ‘šπ‘ 2

π‘Žπ· = π‘Žπ·π‘›+ π‘Žπ·π‘‘

π‘Žπ·π‘› = πœ”4 𝑋 πœ”4 𝑋 π‘Ÿπ΅ = 3.44 π‘˜ 𝑋 284.5 𝑗 + 274.85 𝑖 = βˆ’978.68 𝑖 + 945.48 𝑗

π‘Žπ·π‘‘= 𝛼4 𝑋 π‘Ÿπ΅ = 11.90 π‘˜ 𝑋 82.71 𝑖 βˆ’ 79.9 𝑗 = 984.24 𝑗 + 950.81 𝑖

π‘Žπ· = 1929.92 π‘šπ‘šπ‘ 2

Page 9: Calculos de velocidades y aceleraciones

π‘ŽπΈπ‘›+ π‘ŽπΈπ‘‘

= π‘Žπ·π‘›+ π‘Žπ·π‘‘

+ π‘ŽπΈ/𝐷𝑛+ π‘ŽπΈ/𝐷𝑑

π‘ŽπΈπ‘› =πœ”6 𝑋 πœ”6 𝑋 π‘ŸπΈ

π‘ŽπΈπ‘›= βˆ’1.96 π‘˜ 𝑋 (324.16 𝑗 + 253.62 𝑖)

π‘ŽπΈπ‘›= 635.35 𝑖 βˆ’ 497.09 𝑗

π‘ŽπΈπ‘‘= 𝛼6 𝑋 π‘ŸπΈ = 𝛼6π‘˜ 𝑋 βˆ’165.39 𝑖 + 129.4 𝑗

π‘ŽπΈπ‘‘= βˆ’165.39 βˆ— 𝛼6𝑖 βˆ’ 129.4 βˆ— 𝛼6 𝑗

π‘ŽπΈ/𝐷𝑛 =πœ”5 𝑋 πœ”5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑛= βˆ’0.39π‘˜ 𝑋 39.78 𝑗 βˆ’ 20.7 𝑖 = 15.51 𝑖 + 8.073 𝑗

π‘ŽπΈ/𝐷𝑑= 𝛼5 𝑋 π‘ŸπΈ/𝐷

π‘ŽπΈ/𝐷𝑑= βˆ’π›Ό5 βˆ— 102 𝑗 + 𝛼5 βˆ— 53.1 𝑖

𝑖 β†’ βˆ’π›Ό6 βˆ— 129.4 βˆ’ 𝛼5 βˆ— 53.1 = βˆ’147.71

𝑗 β†’ βˆ’π›Ό6 βˆ— 165.39 + 𝛼5 βˆ— 102 = 2068.737

𝛼6 = βˆ’4.31 π‘Ÿπ‘Žπ‘‘π‘ 2

𝛼5 = 13.28 π‘Ÿπ‘Žπ‘‘π‘ 2

π‘ŽπΈ = 2902.97 π‘šπ‘šπ‘ 2