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Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Ch. 3. The Smith Chart
Mapping of the reflection
coefficient in the complex
domain
ljir
L
L ejZZ
ZZ 000
0
00
d
d = l 0
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Normalized impedance
irdj jed 2
0
Generalized reflection coefficient:
ir
irin
in
j
j
d
djxrz
Z
dZ
1
1
1
1
0
Normalized impedance:
2
2
2
22
22
1
1
1
1
1
rr
r
r
ir
ir
ir
Real part: Imaginary part:
22
2
22
111
1
2
xx
x
ir
ir
i
d
d = l 0
Γ(d)
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Representation of normalized resistance
2
2
2
1
1
1
rr
rir
01
2
1
2
11
10
22
2
2
2
22
ir
ir
ir
r
r
r
Examples:
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Representation of normalized reactance
01
1111
00
1111
01
22
22
22
22
ir
ir
i
ir
ir
x
x
x
x
x
Examples:
22
2 111
xxir
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Combined diagram: Smith Chart
1
1
jxr
jxrjxrz
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Repetition
Reflection coefficient:
ljir
L
L ejZZ
ZZ 000
0
00
Generalized reflection coefficient:
irdj jed 2
0
ir
irin
in
j
j
d
djxrz
Z
dZ
1
1
1
1
0
Normalized impedance:
22
22
1
1
ir
irr
221
2
ir
ix
Normalized
resistance:
Normalized
reactance:
d
d = l 0
Γ(d)
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
How to use the Smith Chart
• Normalize load impedance: ZL zL
• find reflection coefficient: zL Γ0
• rotate reflection coefficient: Γ0 Γ(d)
• find normalized input impedance: zin(d)
• de-normalize input impedance: zin(d) Zin(d)
Example: determine
input impedance Zin(d)d
d = l 0
Γ(d)
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Impedance transformation using
Smith chart
1) Normalize load impedance:
ZL zL = ZL/Z0
2) Find reflection coefficient:
zL Γ0 = (zL-1)/(zL+1)
3) Rotate reflection coefficient:
Γ0 Γ(d) = Γ0 exp(-j2βd)
4) Find normalized input impedance:
Γ(d) zin(d) = (1+ Γ(d))/(1- Γ(d))
5) De-normalize input impedance:
zin(d) Zin(d) = Z0 zin(d)
zL=0.6+j1.2 Γ0 =0.2+j0.6
zin=0.3-j0.53
Γ=-0.32-j0.55
ZL=30+j60 Ω
Z0=50 Ω
d=l=2cm
f=2GHz vp=c/2
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Generalized standing wave ratio
1
1)(
)(1
)(1)(
)( 20
SWR
SWRd
d
ddSWR
ed dj
Can determine SRW for a
given Γ(d) by drawing circle
with center at Γ = 0 through
Γ(d) in the Smith chart.
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Open circuit TL as a reactive element
djdjZZ
djZZz
L
Lin
cot
tan
tan
0
0
Note: ZL = corresponds to r = 0
(outer circle of Smith chart)
Upper half-circle: inductive
Lower half-circle: capacitive
Example: zin = jx = 1/jωCZ0
n
CZd
0
1 1cot
1
f = 3GHz
β = 81.6m-1
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Short circuit TL as a reactive element
djdjZZ
djZZz
L
Lin
tan
tan
tan
0
0
Note: ZL = 0 also corresponds to
r = 0 (outer circle of Smith chart)
Upper half-circle: inductive
Lower half-circle: capacitive
Example: zin = jx = jωL/Z0
n
Z
Ld
0
1tan1
f = 3GHz
β = 81.6m-1
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Admittance transformation
)(1
)(1
)(1
)(11
)(1
)(111
0
de
de
d
d
zy
d
d
ZZY
j
j
in
in
in
in
e-jπ Γ(d) corresponds to 180º
rotation of Γ(d) in Smith chart.
This converts impedance to
admittance
Alternatively: Rotate Smith chart
by 180º : Admittance Smith chart
zin = 1+j
yin = 0.5-j0.5
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Admittance Smith chart
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
ZY Smith chart
2222,
11
xr
xb
xr
rg
jxrzjbgy
in
in
Use original Smith chart
to display impedances
and rotated chart to
display admittances.
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Frequency dependence: parallel R and L
L
Zj
R
Zjbgy oo
in
Example:
Z0 = 50 Ω, L = 10 nH
g = 0.3, 0.5, 0.7, 1
f = 500 MHz to 4 GHz
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Frequency dependence: parallel R and C
CjZR
Zjbgy o
oin
Example:
Z0 = 50 Ω, C = 1 pF
g = 0.3, 0.5, 0.7, 1
f = 500 MHz to 4 GHz
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Frequency dependence: series connections
CZ
j
Z
Lj
Z
R
jxrz
ooo
in
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
A
B
C
D
E
A: gA = Z0/RL = 1.6
B: yB = gA + jZ0ωCL = 1.6 + j1.2
zB = 0.4 - j0.3
C: zC = zB + jωL1/Z0 = 0.4 + j0.8
yC = 0.5 – j1.0
D: yD = yC + jZ0ωC = 0.5 + j0.5
zD = 1 – j1
E: zE = zD + jωL2/Z0 = 1
Z0 = 50 Ω f = 2 GHz
Zin = Z0 = 50 Ω : Match at 2 GHz
Example: T-type network
Institutt for InformatikkIFI5480: RF kretser, teori og design
Tor A Fjeldly
Simulation of Zin for T-network
CAD simulation of Zin for
frequences 0.5 – 4 GHz
Note that C behaves as a short
at the highest frequencies and
the network will be dominated
by L2 (purely inductive)