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Lecture 10: Fixed Points ad Infinitum. M.C. Escher, Moebius Ants. David Evans http://www.cs.virginia.edu/~evans. CS655: Programming Languages University of Virginia Computer Science. Goal: Understand the Least Fixed Point Theorem. - PowerPoint PPT Presentation
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David Evanshttp://www.cs.virginia.edu/~evans
CS655: Programming LanguagesUniversity of VirginiaComputer Science
Lecture 10: Fixed Points ad Infinitum
M.C. Escher, Moebius Ants
20 Feb 2000 University of Virginia CS 655 2
Goal: Understand theLeast Fixed Point TheoremIf D is a pointed complete partial order, then a continuous function f: D D has a least fixed point (fixD f) defined by
D { (fn D ) | n 0 }
20 Feb 2000 University of Virginia CS 655 3
Last Time
• A domain is a structured set of values
• A function domain is constructed from two primitive domains, D1 D2 by associating an element of D2 with each element of D1.
• A fixed point of a function f: D1 D2 is
an element d D such that f d = d.
20 Feb 2000 University of Virginia CS 655 4
Last Time, cont.
• Any recursive definition can be encoded with a (non-recursive) generating function by abstracting out the thing that is defined.
• A fixed point of a generating function is a solution of its associated recursive definition.
20 Feb 2000 University of Virginia CS 655 5
Last Time, cont.
• (D, ) is a partial order if is:– reflexive: – transitive: – anti-symmetric:
• (D, ) is a pointed partial order if it has a
bottom element u D such that u d for all
elements d D.
a b and b a imply a = b
a aa b and b c imply a c
20 Feb 2000 University of Virginia CS 655 6
Ordered Product Domains
If <D, D > and <E, E > is are POs, <D x E , D x E > is a partial order, ordered by:
<d1, e1> D x E <d2, e2>
if d1 D d2 and e1 E e2
20 Feb 2000 University of Virginia CS 655 7
Ordered Product Example
• What is << Nat, > x < Nat, >>?
<0, 0>
<0, 1> <1, 0>
<0, 2> <2, 0>
<1, 73><3, 3>
(Hasse diagram)
20 Feb 2000 University of Virginia CS 655 8
Ordered Function Domains
If <D, D > and <E, E > is are POs, <D E , D E > is a partial order, ordered by: f D E
f1 D E f2
if for all d D,(f1 d) E (f2 d)
20 Feb 2000 University of Virginia CS 655 9
Ordered Function Example
< Bool, > = { false, true }
false true true false
What is << Bool, > < Bool, >>?
<{false, false}, {true, false}>
<{false, false}, {true, true}> <{false, true}, {true, false}>
<{false, true}, {true, true}>
20 Feb 2000 University of Virginia CS 655 10
T-Shirt Exercise
• What is the order of the domain:
<<Bool, > x < Bool, > < Bool, >>
(includes xor, and, or, implies, ...)
20 Feb 2000 University of Virginia CS 655 11
The Domain Nat
Nat
0 1 2 3 4 ...
20 Feb 2000 University of Virginia CS 655 12
Ordered Function Bottom• What is the bottom of
<Nat, > <Nat, > ?
{ <0, >, <1, >, <2, >, ... }
= { <x, > }
= { }
If a function map has no entry for x,
it maps x to .
20 Feb 2000 University of Virginia CS 655 13
Least Upper Bounds
• The least upper bound of a subset X of a domain D is the weakest element of X that is at least as strong as every other element of X. l X = D X
if for every x X, x l
and for every m X such that x m x X, l m
20 Feb 2000 University of Virginia CS 655 14
Least Upper Bounds in Nat
Nat
0 1 2 3 4 ...
Nat{ 0, 2, 4, 6, ... } =
Nat{Nat, 3, 17} =
any element of { 0, 2, 4, 6, ... }
3 or 17
20 Feb 2000 University of Virginia CS 655 15
Complete Partial Orders• A partial order D is complete if every
chain in D has a least upper bound in D. – Any upward chain through a Hasse diagram
converges to a limit– All finite partial orders are complete
– Most sensible partial orders (including Nat) are complete (see Gifford’s notes for some incomplete POs.)
20 Feb 2000 University of Virginia CS 655 16
Monotonic Functions• f D E is monotonic if d1 D d2
implies (f d1) E (f d2).
• Is not over << Bool, > < Bool, >> monotonic?
• Is { <x, x * 2>} over << Nat, > < Nat, >> monotonic?
• What functions are monotonic over Nat Nat?
20 Feb 2000 University of Virginia CS 655 17
Continuous Functions• f D E is continuous if, for all chains
C in D, f applied to the least element of the chain over D is the least element of (f c) for cC over E.
• Continuity is like monotonicity, but it works for limits of infinite chains also.
• If the CPO is finite, monotonicity implies continuity.
• Continuity always implies monotonicity
20 Feb 2000 University of Virginia CS 655 18
Monotonic/Continuous Functions in Domain Nat
Nat
0 1 2 3 4 ...
What is a monotonic function in Nat?
What is a continuous function in Nat?
20 Feb 2000 University of Virginia CS 655 19
Least Fixed Point Theorem
• If D is a pointed complete partial order, then a continuous function f: D D has a least fixed point (fixD f) defined by
D { (fn D ) | n 0 }
The least upper bound of applying f any number of times, starting with D.
20 Feb 2000 University of Virginia CS 655 20
Sanity Check
g: (Nat Nat) (Nat Nat) = f. n. if (n = 0) then 1
else (n * ( f (n - 1)))
What is (fixNat Nat g)?
In
20 Feb 2000 University of Virginia CS 655 21
Sanity Check
g: (Nat Nat) (Nat Nat) = f. n. if (n = 0) then 1
else (n * ( f (n - 1)))
What is (fixNat Nat g)?
20 Feb 2000 University of Virginia CS 655 22
What is the bottom of
Nat Nat?
{ <x, > | x Nat }
20 Feb 2000 University of Virginia CS 655 23
What is (g { <x, > | x Nat })?
g = f. n. if (n = 0) then 1
else (n * ( f (n - 1)))
g { <x, > | x Nat } =
{<0, 1>, <x, > | x > 0 and x Nat }
20 Feb 2000 University of Virginia CS 655 24
What is (g (g { <x, > | x Nat }))?
g = f. n. if (n = 0) then 1
else (n * ( f (n - 1)))
g { <0, 1>, <x, > | x > 0 and x Nat } =
{ <0, 1>, <1, 1>,
<x, > | x > 1 and x Nat }
20 Feb 2000 University of Virginia CS 655 25
What is LUB (gn { <x, > | x Nat }))?
g = f. n. if (n = 0) then 1
else (n * ( f (n - 1)))
g { <0, 1>, <x, > | x > 0 and x Nat } =
{ <0, 1>, <1, 1>, <2, 2>, <3, 6>, ...}
= {<x, x!> | x Nat }
20 Feb 2000 University of Virginia CS 655 26
• Think of bottom as the element with the least information, or the “worst” possible approximation.
• To find the least fixed point in a function domain, start with the bottom of the function domain and iterate...
Getting to the of things
20 Feb 2000 University of Virginia CS 655 27
Fixed Point Theorem
• Do all -calculus terms have a fixed point?
• (Smullyan: Is there a Sage bird?)
20 Feb 2000 University of Virginia CS 655 28
Finding the Sage Bird
F , X such that FX = X
• Proof:Let W = x.F(xx) and X = WW.
X = WW = ( x.F(xx))W
F (WW) = FX
20 Feb 2000 University of Virginia CS 655 29
Why of Y?
• Y is f. WW:Y f. (( x.f (xx)) ( x. f (xx)))
• Y calculates a fixed point (but not necessarily the least fixed point) of any lambda term!
• If you’re not convinced, try calculating ((Y fact) n). (PS1, 1e)
20 Feb 2000 University of Virginia CS 655 30
Still Uncomfortable?
20 Feb 2000 University of Virginia CS 655 31
Remember the problem reducing Y
• Different reduction orders produce different results
• Reduction may never terminate• Normal Form means no more ß-reductions
can be done– There are no subterms of the form (x. M)N
• Not all -terms can be written in normal form
20 Feb 2000 University of Virginia CS 655 32
Church-Rosser Theorem• If a -term has a normal form, any reduction
sequence that produces a normal form always the same normal form– Computation is deterministic– Some orders of evaluation might not terminate
though
• Evaluating leftmost first finds the normal form if there is one.
• Proof by trust the theory people, but don’t become one.
20 Feb 2000 University of Virginia CS 655 33
Charge• PS2 is due Thursday
• Domains are like types in programming languages, we will see them again soon...
• Next time: Intro to Language Design