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Voltage regulator (VR) provides:
nearly constant dc output voltage that is essentially independent of the
input voltage
output load current
temperature
Chapter 5 (P#166)
DC-DC Converters
Input DC Constant output ?
DC VoltageConstant OR
Variable (Dynamic)
Load
Constant
OR
Variable Voltage
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DC Voltage
Regulator
Series Shunt Step-
Down
Linear Switching
Step-up Up & Down
(Negative)
Chopper
s
+ Positive - Negative
Dual
BuckBoost
Buck-boost
Regulated
Power Supply
-Low Efficiency (Disadvantage)
-Low Noise (Advantage)
-High Efficiency (Advantage)
-High Noise (Disadvantage)
In Power Electronics
We discuss only
Switching Power
supplies
In Power Electronics
Why not Linear PS?
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SMPS
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5.2(Page 166) PRINCIPLE OF STEP-DOWN OPERATION
VDC RloadVload
Iload+
VDC
t
VDC
t
Vload
VAV
Figure 5.1
offon
DConAV
tt
V.tV
T
V.tV
DCon
AV
T
ON Off
DCon
AV VT
tV K = Duty Cycle
)......(
k
R
RkV
V
I
V)cetansisReInput(R load
loadDC
DC
load
DCi 45
BJT
MOSFET
IGBT
Ri
DCAV VkV
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Figure 5-3(page 171) DC Converter with RL - Load
VDC
t
t
Vload
Figure 3-40
RL
Vload
Iload
VDC+
SCR
v1(t)D1
Free-wheelingdiode
Makes current
flow during tofftON=? T
ON Off
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1. Constant-frequency Operation (PWM) Page 168 (Self)
2. Variable-frequency Operation (FM) Page 168 (Self)
Which of the above method preferable ? Why?
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The duty cycle k can be generated by comparing a dc reference
signal vcrwith a saw-tooth carrier signal vr
Vg
0
Vr
0
V
Vcr
vrVcr
T
kT T
t
t
+5V
0
0
VcrVcr
T
kT T
t
t
)9.5....(tT
Vvr
r kTVv
crcr kt
T
VVr
cr M
VVk
r
cr
M = Modulation index
Vr= Maximum valueof saw tooth wave
vr= Instantaneous Value of
saw tooth wavettanConsV
V
VV cr
r
ino
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http://upload.wikimedia.org/wikipedia/commons/1/1f/PWM_3L.gif7/27/2019 DC_DC_1_PE_AU_06_11_08
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Section 5.3 to 5.7 (Page 171 to 185)
Will Refer When Required
NOW START
Section 5.8(Page 186)
Switching Mode Power Supply
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DC to DC: CHOPPER [Switching Mode Power Supply] (SMPS)
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V
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PRINCIPLE OF STEP-DOWN OPERATION
VDC RloadVload
Iload+
VDC
t
VDC
t
Vload
VAV
BJTMOSFETIGBT
Ri
VDC
t
VDC
t
t
Vload
t
Vload
Figure 3-40
RL
Vload
Iload
VDC
+
SCR
v1(t)D1
Figure 3-40
RL
Vload
Iload
VDC
+
SCR
v1(t)D1
T
ON Off
T
ON Off
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5.8 (Page#186) Switching-Mode Regulators
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BUCK
BOOST
BUCK-BOOST
This circuit is
different form
the circuit givenin the book (Fig
5.18). Find the
difference, why
this difference?
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5.8.1 (Page#186) Buck Regulator (Step Down)
Figure 5.15 (Similar); Elements of switching-mode regulators - Buck (Step Down)
l i
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1. A buck converter is supplied from a 50V battery
source. Given L=400uH, C=100uF, R=20 Ohm,f=20KHz and D=0.4.Calculate: (a) output voltage(b) maximum and minimum inductor current, (c)output voltage ripple.
2. Design a buck converter such that the outputvoltage is 28V when the input is 48V. The load is8Ohm. Design the converter such that it will be in
continuous current mode. The output voltageripple must not be more than 0.5%. Specify thefrequency and the values of each component.Suggest the power switch also.
Please Do it - Practice the following Problems
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Variable
PWM
Linear Mode
Vin
Vout
Switching Mode
Vin
Vout
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Variable
PWM
Square Voltage
(Ripples)
Variable
PWM
Variable
PWM
LPF(C)
Required to
remove DC
ripples
LPF (LC)
Required to
remove DC
ripplesL Remove?
C Remove?
5.8 (page#186) SMPS - Step Down (Buck) Regulator
Do we
Need PWM
in Linear
Power
Regulators
WHY?
Do we
Need LPFin Linear
Power
Regulators
WHY?
Fig 5 16 SMPS Step
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LPFVariable
PWMFree Wheeling:
Diode required to
pass energy trapped
in L&C during tOFF
Do we need Free
Wheeling Diode in
Linear Power
Regulators WHY?
CONTROL CIRCUIT
Fig 5.16 SMPS - Step
Down (Buck) Regulator
Vin
Vout ON ON
T=1/f
OFF
Continuous I and Discontinuous I in DC DC Converters
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Continuous IL and Discontinuous IL in DC-DC Converters
Continuous Inductance Current (IL)
ON
OFF
ON
OFF
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FIGURE 5 16 Buck regulator with continuous i
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Control
vc
eL
iL,ILis,Is
ic,Icio,Ia
IGBT
io,Iaic,Ic
is=iL
ON
Mode 1
io,Iaic,Ic
IL
OFF
Mode 2
FIGURE 5.16 Buck regulator with continuous iL
Mode 1-When transistor
is switched ON at t=0.
The current flows
through L, C & load
Mode 2-When transistor is
switched OFF at t=t1. Thecurrent flows through
Diode, C & loadt
ONMode
OFF
ModeON
t=0 t=t1
osL VVv oL Vv 0
i I
i I
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),.....(I
I
V
V
T
tkCycleDuty
)o(a
s
s
oon 49485
).....()VV(V
VLIT
fttperiodSwitching
asa
s
s
5051
21
).....(LfV
)VV(VIcurrentripplepeaktoPeak
s
asa 515
).....(C
TIVvoltageripplepeaktoPeak
c535
8
io,Iaic,Ic
is=iL
ON
Mode 1
io,Iaic,Ic
is=iL
ON
Mode 1
Control
vc
eL
iL,ILis,Is
ic,Icio,Ia
Control
vc
eL
iL,ILis,Is
ic,Icio,Ia
io,Iaic,Ic
IL
OFF
Mode 2
io,Iaic,Ic
IL
OFF
Mode 2Equation required for Designing
Buck Converter
http://www hills2 u net com/electron/smps htm#buck
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http://www.hills2.u-net.com/electron/smps.htm#buck
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V
t
VL=eL
Vs
LVV
dtdi osL
?dtdiL
LV
LV oo
0
kT T
ONON OFF
kT T
dt
diLe LL
VLCurrent in the inductor
will not change thedirection
Voltage in the inductor
will change the
direction (polarity)
osL VVv
oV
IL
IL
I1
I2
(1-k)T
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I
t
VL=eL
Vs
IC
kT T
ONON OFF
kT T
VC
Current in the Capacitor
changes its direction
I1-I
a
I2-Ia
(1-k)T
Voltage in the capacitor
will not change
direction (polarity)
Figure 5 16
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Figure 5.16
io,Iaic
,Ic
is=iL
ON
Mode 1
io,Iaic
,Ic
is=iL
ON
Mode 1
io,Iaic,Ic
IL
OFF
Mode 2
io,Iaic,Ic
IL
OFF
Mode 2
Please Read S it hi R l t
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Its percent voltage ripple is 100%.
The output voltage with such a high ripple content may be satisfactory forelectric heaters, light dimming circuits, etc., it is certainly not suitable for theoperation of amplifiers and other circuits requiring almost constant dcvoltage.
The high voltage ripple can be controlled by placing a capacitor across theload.
The capacitor is large enough so that its voltage does not have anynoticeable change during the time the switch is off.
Somewhat better circuit can be developed by including an inductor, which is
in series with the switch when the switch is on (closed), to limit the current inrush.
However, this creates another problem. Since the current in the inductorcannot change suddenly, we have to provide at least one more switch, sucha freewheeling diode, to provide a path for the inductor current when the
switch is off (open).
Please Read- Switching Regulator
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Please Read Switching Regulator Basic Design Procedure
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oCalculate D to obtain required output voltage.
o Select a particular switching frequency (f) and device
preferably f>20KHz for negligible acoustic noise
higher fs results in smaller L and C. But results in higher
losses.
Reduced efficiency, larger heat sink.
Possible devices: MOSFET, IGBT and BJT. Low power
MOSFET can reach MHz range.
Please Read- Switching Regulator Basic Design Procedure
Please Read Switching Regulator Basic Design Procedure
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oCalculate Lmin. Choose L>>10 LminoCalculate C for ripple factor requirement.
Capacitor ratings:
must withstand peak output voltage
must carry required RMS current. Note RMS current fortriangular w/f is Ip/3, where Ip is the peak capacitor
current given by iL/2.
oWire size consideration:
Normally rated in RMS. But iL is known as peak. RMS
value for iL is given as:
Please Read- Switching Regulator Basic Design Procedure
SMPS - Step UP (Boost) Regulator
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Variable
PWM
inout VD
V
1
1
p ( ) g
SMPSVoltage Inverter
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PWM
g
Configuration
Buck-Boost
little modified call Cuk
in_out VD1
D=V
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