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8/3/2019 De + DA HKI toan 9
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H v tn: Lp: 9S bo danh:Phng thi:
K THI HT HC K INm hc 2010 2011MN THI: TON 9(Thi gian: 90 pht)
im bi thiBng s Bng ch
bi.I. Phn trc nghim:(3 im)
Dng bt ch t m vo trn ng trc p n ng trong cc cu sau
Cu 1: Php tnh no sau y chnh xc:A) 2 8 10+ = B) a. b : a.b 1=
C) ( )2
2 3 2 3 = D) ( )2
2A A 0 =
Cu 2: ng thng y = 5x + 6 song song vi ng thng no sau y:A) y = 6x + 5 B) y = 5x 25 C) y = - 5x + 6 D) y 5x = 6
Cu 3: T im A ngoi ng trn (O; 5cm) k tip tuyn AM vi ng trn (M l tip im). di AM l bao nhiu bit AO = 13cm?A) 8cm B) 18cm C) 12cm D) 10cm
Cu 4: iu kin biu thc A =7
x 2c gi tr xc nh l:
A) x 0 v x 2 B) x 0 v x 4 C) x 0 D) x 2
Cu 5: Cp s no sau y l nghim ca h phng trnh:3x y 3
7x 2y 20
=
+ =A) (2; 3) B) (1; 0) C) (4; -4) D) (1; 1)
Cu 6: Hai ng trn (O, 5cm) v (O, 8cm) c v tr tng i vi nhau nh th no bit OO = 12cmA) Tip xc trong B) Khng giao nhau
C) Tip xc ngoi D) Ct nhau
II. Phn t lun: (7 im)Bi 1. (1,5 im) Rt gn cc biu thc saua) 2505).5225( +
b) 9 4 5 9 4 5 +c)
5 1 5 1
5 1 5 1
+ +
+Bi 2. (1,5 im) Cho hai ng thng: (d1): y = 2x v (d2): y = - x + 3.
a) V hai ng thng trn cng mt mt phng ta .b) Xc nh ta giao im ca hai ng thng trn.Bi 3. (4 im) Cho hai ng trn (O) v (O) tip xc ngoi ti A. K tip tuyn chung ngoi BC, B (O); C (O). Tip tuyn chung trong ti A ct tip tuyn chung ngoi BC ti I.
a) Chng minh rng 0BAC 90=b) Trn tia i ca tia IA ly im D sao cho IA = ID. T gic ABDC l hnh g? V sao?c) Tnh di BC trong trng hp OA = 7,2cm v OA = 3,2cmd) Gi giao im ca OI v AB l M; giao im ca OI v AC l N.
Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3 1000B Trn Hng o Tp Quy Nhn
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Chng minh rng:3
3
OM OI
O'N O'I=
p n Biu im: Mn ton 9I. Phn trc nghim: 3 im: Mi cu ng cho 0,5 im.
Cu 1 Cu 2 Cu 3 Cu 4 Cu 5 Cu 6
C B C A A DII. Phn t lun: 7 imBi 1: 1,5 im, mi cu ng cho 0,5 im
a) (5 2 2 5). 5 250 5 10 10 5 10 10+ = + =
b) ( ) ( )2 2
9 4 5 9 4 5 5 2 5 2 5 2 5 2 4 + = + = =
c)( ) ( )
( ) ( )
2 2
5 1 5 15 1 5 1 123
45 1 5 1 5 1 5 1
+ + + + = = =
+ +
Bi 2: 1,5 im:a): V ng chnh xc th hai hm s cho 1 im:
b) 0,5 imPhng trnh honh giao im ca hai ng thng l: 2x = - 3x + 3Gii phng trnh ta tm c x = 1Thay x vo 1 trong hai hm s ta tm c y = 2Vy giao im ca hai ng thng l (1; 2)Bi 3: V hnh chnh xc cho 0,5 ima) 1 im: Theo tnh cht tip tuyn ct nhau ta cIA = IB = IC A ng trn (I) ng knh BC
do : 0BAC 90=b) 1 im: T gic ABDC c hai ng cho ct nhau titrung im mi ng nn l hnh bnh hnh;
mt khc 0BAC 90= nn l hnh ch nht.c) 1 im: Theo h thc lng trong tam gic vung ta c: IA2 = OA.OA IA = 4,8cmDo BC = 2IA = 9,6cm
Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3 1000B Trn Hng o Tp Quy Nhn
4
3
2
1
-1
-2 2 4y
x
O
y=-3x
+3
y=2x
N
M
I
O'O
D
C
B
A
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d) 0,5 im: Ta c OI2 = OA.OO; OI2 = OA.OO (h thc lng trong tam gic vung) 2
2
OI OA
O'I O'A= ; Mt khc OMA ANO
OA MA
O'A O'N=
2
2
OI MA
O'I O'N= (1)
Theo h qu nh l Ta let ta c:OI OM
O'I MA= (2); T (1) v (2) ta c:
3
3
OM OI
O'N O'I=
Trung tm bi dng kin thc vn ha cho hc sinh cp 2 + 3 1000B Trn Hng o Tp Quy Nhn
s
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