De Kiem Tra Va Dap an Hoc Ki 1 Mon Toan Lop 11

7/30/2019 De Kiem Tra Va Dap an Hoc Ki 1 Mon Toan Lop 11

1/3

9S gd - t hi phngTrng thpt: l qu n

=====&&&=====

kim tra hc k i khi 11nm hc 2010 - 2011

Thi gian lm bi: 90 pht

I: Phn chung cho tt c cc ban( 8 im)

Bi 1(4.0 im):1/ Tm tt c cc s t nhin n tho mn phng trnh :

1 24P P Pn n n= +

2/ Cho khai trin nh thc :2

121

xx

+ . Tm s hng khng cha x trong khai

trin.3/ T cc ch s 1;2;3;4;5;6. Hi c th lp c bao nhiu s t nhinc 4 ch s khc nhau v tnh tng ca tt c cc s.

Bi 2(4.0 im): Cho hnh chp S.ABCD, c y ABCD l hnh thang vi y lnAB v AB = 2CD. Gi E l trung im ca AB.

1/ Xc nh giao tuyn ca hai mt phng (SAD) v (SCD)2/ Chng minh rng: AD song song vi mt phng (SCE).3/ M l mt im di ng trn cnh AD(M khng trng A v D), mt phng ()i qua M song song vi SA v CD, ct BC ti N ct SC ti P, ct SD ti Q

a) Xc nh thit din ca hnh chp S.ABCD ct bi mt phng (),thit din l hnh g?

b) Gi I l giao im ca MQ v NP. Chng minh rng: im I chy trn mtng thng cnh.

II: Phn dnh ring cho tng ban(2 im)

A: Ban khoa hc t nhin.

Bi 3a (2.0 im):Gii cc phng trnh lng gic sau

1/sin 3cos 2x x = 2/ sin 2 cos2 sin cos 1 0x x x x+ + + + =

B: Ban c bn A D

Bi 3b (2.0 im):Gii cc phng trnh lng gic sau

1/ 3sin cos 1x x+ = 2/ sin 2 cos 0x x+ =

Ht


2/3

p n v biu im bi kim tra hc k I khi 11 nm 2001

Bi/ Ni dung cn t im

K:3

n

n

0.25

PT ! ( 1)! 4( 2)! ( 1) ( 1) 4n n n n n n = + = + 2 2 3 0n n = 0.5

3 (t/m )

1( )

n

n loai

=

=

K 0.5

1/1.5

KL: n = 3 0.25

C:12 1212 12

12

12 122 2 20 0

1 1 kk k kk k

k k

xx C x C

x x x

= =

+ = =

0.25

+S hng TQ th k+1l:12

12 2

kk

k

xC

x

khng cha x 12 k = 2k k = 40. 5

2/1

=> s khng cha x l s hng th 5 : 412C =495 0.25

+Mi mt b sp th t 4 ch s ly t 6 ch s cho th lp c mt s

cng l mt chnh hp chp 4 ca 60.5

=> c tt c l 46 360A = s 0.5

+Mi mt ch s 1,2,3,4,5,6 ng mi v tr hng nghn, hng trm,hng chc, hng n v xut hin trong 35 60A = s

0.25

1

3/1.5

s lp c dng: 1000 100 10abcd a b c d = + + + vi a,b,c,d {1,2,3,4,5,6}=>Tng cc s l:

[ ]601000(1 2 3 4 5 6) 100(1 2 3 4 5 6) 10(1 2 3 4 5 6) (1 2 3 4 5 6)S= + + + + + + + + + + + + + + + + + + + + + + +

60.21.(1000 100 10 1) 60.21.1111S= + + + = =1399860

0.25

+V hnh ng cho phn 1 1.0

+( ) ( )

( ) ( )

D SAD SBC

S SAD SBC

0.5

1/1.0

( ) ( )SD SAD SBC = 0.5+ / /AE CD= 0.5Q

P

I

N

H

C

EA B

D

S

M

2/

1.0

/ // /( )

( )

AD CEAD SCE

CE SCE

0.5

a)+MN//CD,MQ//SA,PQ//CD 0.25

CM c thit din MNPQ l hnh thang 0.25

b)+( )

( ) ( )( )

I MQ SADI MQ NP I SAD SBC

I NP SBC

=

0.25

2

3/1.0

( ) ( ),I SH SAD SBC H AD BC = = cnh 0.25

+pt1 3 2

s inx cos2 2 2

x = 0.253a1/

12

sin( )3 2

x

= 0.25


3/3

72 2

3 4 12;

3 132 2

3 4 12

x k x k

k

x k x k

= + = +

= + = +

0.5

+pt 22sin .cos 2cos sin cos 0 (sin cos )(2cos 1) 0x x x x x x x x + + + = + + = 0.5

sin cos 0

2cos 1

x x

x

+ =

+ 0.25

2/

14

;2

23

x k

k

x k

= +

= +

0.25

+pt3 1 1

s inx+ cos2 2 2

x = 0.25

1os( )

3 2c x

= 025

11

2223 3 ;3

223 3

x kx k k

x kx k

= +

= + = = +

0.5

+pt 2sin .cos cos 0 (2sin 1)cos 0x x x x x + = + = 0.5

cos 0

1s

2

x

inx

= =

0.25

3b

2

12

2 ;6

72

6

x k

x k k

x k

= +

= + = +

0.25

Ch : +hc sinh lm bi cch khc ng vn cho im ti a+ i vi nghim ca cc pt lng gic khng cn nu k l s nguyn

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De Kiem Tra Va Dap an Hoc Ki 1 Mon Toan Lop 11