Dynamic of Soil-structur Interaction[Www.icivil.ir]

Embed Size (px)

DESCRIPTION

structur Interaction

Citation preview

  • ri.livici.www

  • S H A R I F O F U N I V E R S I T Y O F

    T H E C N O L O G Y

    D Y N A M I C O F S O I L - S T R U C T U R

    I N T E R A C T I O N

    P R O J E C T T E R M

    K E S H A V A R Z . M O H A M M A D R E Z A - M O H A M M A D P O U R

    P O U Y A

    R O O M N U M B E R

    Lecture's name:

    Professor M.Ali.Ghannad

    2014- winter- February

  • 2 | P a g e

    Problem define:

    Two stories shear building with embedment square (10*10) m^2 foundation

    Using CONAN software to plot the soil dynamic stiffness coefficients variations and

    foundation input motion to dimensionless frequency (0

  • 3 | P a g e

    0.00

    2.00

    4.00

    6.00

    8.00

    10.00

    12.00

    14.00

    16.00

    18.00

    0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

    kh,c

    h

    a0

    Sway dynamic stiffness coefficients kh ch

    0.00

    5.00

    10.00

    15.00

    20.00

    0 1 2 3 4 5

    kh,c

    h

    a0

    Sway DOF for surface foundationkh Embedment foundation:

    For a0 more than 1.23 leads to ch

    approximate equal to 1.22 and kh

    values for a0 more than 0.95 are

    less than 1 and converge to zero.

    Surface foundation:

    For a0 more than 0.45 leads to ch

    approximate equal to less than1

    and kh values are going converge

    to zero but with lower speed than

    the embedment foundation.

    Static stiffness (horizontal) = 2.0831e+09

    Static stiffness = 1.2130e+09 (surface foundation)

    Using excel to plot the data as this way:

    This graph express the variation of dynamic coefficients for sway DOF (horizontal) for different

    values of dimensionless frequency (a0=.r

    ).as it's shown for lower values of a0, the dynamic

    damping coefficient is very frequency dependent. And for excitation frequency till 25 rad/sec stiffness

    coefficient kh=1. If compare this model of building with the surface foundation case we see that

    there is some different and it's about that in this case we see, the ch is effected by soil-structure

    interaction less than the embedment case.

  • 4 | P a g e

    0.00

    2.00

    4.00

    6.00

    8.00

    10.00

    12.00

    14.00

    16.00

    18.00

    0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

    kr,c

    r

    a0

    Rocking dynamic stiffness coefficient kr cr

    Static stiffness (rocking) = 9.4319e+10

    -0.60

    -0.40

    -0.20

    0.00

    0.20

    0.40

    0.60

    0.80

    1.00

    1.20

    0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

    ugh

    /uc

    a0

    Sway FIM Re(ugh/uc) Im(ugh/uc)

    This graph express the variation of dynamic coefficients for rocking DOF for different values of

    dimensionless frequency (a0=.r

    ).

    Conclusion:

    The embedment foundations are more effected by increasing in damping ratio of soil-structure

    system, in other hands by increasing embedment ratio (

    ), soil-structure systems affected in

    damping ratio more than stiffness.

    We run Conan again by input txt file and for foundation input motion plot graph like this:

  • 5 | P a g e

    -0.03

    -0.02

    -0.01

    0.00

    0.01

    0.02

    0.03

    0.04

    0.05

    0.06

    0.07

    0.08

    0 0.5 1 1.5 2 2.5 3 3.5 4 4.5

    ugr

    /uc

    a0

    Rocking FIM Re(ugr/uc) Im(ugr/uc)

    -0.40

    -0.30

    -0.20

    -0.10

    0.00

    0.10

    0.20

    0.30

    0.40

    -10 0 10 20 30 40 50

    acce

    lera

    tio

    n (

    g)

    Time (sec)

    Free Field Motion (FFM)

    These graphs express how is the

    For excitation data as *.txt file plot the dynamic stiffness coefficients variations and foundation

    input motion to dimensionless frequency.

    For determine the dynamic stiffness coefficients variations and FIM along the specific

    earthquake, it should be in frequency domain, so we have to choose the suitable software to

    change earthquake data from time domain to frequency domain.

    We could us of Microsoft office excel or SIESMO SIGNAL or Matlab.

    Now we have frequency domain data:

  • 6 | P a g e

    -0.05

    0

    0.05

    0.1

    0.15

    0.2

    0.25

    0.3

    0 10 20 30 40 50 60

    FFT

    mag

    f (Hz)

    Fourier amplitude of FFM

    Free field motion in frequency domain:

    Foundation input motion for excitation in control point motion as a specific time-history data:

  • 7 | P a g e

  • 8 | P a g e

    Matlab code that is used for plot these graphs:

    clc;

    clear all;

    load FFM.txt;

    load h.txt;

    load r.txt;

    dt=input('please enter time step of inserted record> ');

    a_surf=FFM';

    H=h';

    R=r';

    n=length(a_surf);

    F=zeros(2,n+1);

    for index=1:n+1

    F(1,index)=H(1,index)+1i*H(2,index);

    F(2,index)=R(1,index)+1i*R(2,index);

    end

    b=a_surf(2,:);

    acc=[0,b];

    df=1/(n*dt);

    t=0:dt:n*dt;

    f=0:df:n*df;

    a_fft=fft(acc)/n;

    A_time=zeros(2,n+1);

    for j=1:2

    a_freq=a_fft.*F(j,:);

    a_time=n*real(ifft(a_freq));

    figure(j);

    hold on;

    if j==1

    title('Horizontal FIM');

    xlabel('Time (sec.)');

    ylabel('ugh (m)');

    else

    title('Rocking FIM');

    xlabel('Time (sec.)');

    ylabel('ugr (Rad)');

    end;

    plot(t,a_time);

    hold off;

    figure(2+j);

    hold on;

    if j==1

    title('Horizontal FIM');

    xlabel('Frequency (Hz)');

    ylabel('ugh (m)');

    else

    title('Rocking FIM');

    xlabel('Frequency (Hz)');

    ylabel('ugr (Rad)');

    end;

    plot(f,n*a_freq);

    hold off;

    end;

  • 9 | P a g e

    ~

    ~ ~

    ~

    ~

    Using Cone model concept for specific frequency to determine dynamic stiffness

    coefficients, to simplify use the approximate formula in ATC3-06 for compute the period of

    soil-structure system.

    Page56 on ATC3-06:

    Ta=CT.hn3/4 where for concrete frames: CT= 0.025

    Ta=0.025*(22.965879)3/4=0.26sec

    Page387 on ATC3-06:

    For embedment foundation:

    ky=8

    2 1 +

    2

    3

    =842.75(106)5.64

    20.41 +

    2

    3

    4

    5.64= 1775.55E06 (N/m)

    k=8^3

    3(1) 1 + 2

    =842.75(106)5.71^3

    3(10.4)1 + 2

    4

    5.71= 84930.42E06 (N/m)

    Page65 on ATC3-06:

    W= 0.7*(280ton) = 196 ton, K=42

    ^2=42

    196

    0.26^2=114.46405E06 (N/m), h=0.7*7=4.9m

    T=T1 +

    ky(1 +

    ky.2

    k)=0.26*1 + 114.46405E06

    1775.55E06(N/m)(1 +

    1775.55E06(N/m).(4.9m)2

    84930.42E06(N/m))=0.

    27 sec

    T

    T=0.27

    0.26=1.038,

    H

    =5.8

    5.675=1.02

    graph on page 71

    0=0.025

    = 0+0.05

    (1.04)^3=0.07

    So =2

    T=23.27rad/sec ao=

    .r

    = (23.27*5.675)/150=0.88 dimensionless

    frequency

    a0 kh ch kr Cr

    0.88 9.05E-01 1.28E+00 8.43E-01 3.77E-01

    Static stiffness (horizontal) = 2.0831e+09, Static stiffness (rocking) = 9.4319e+10

  • 10 | P a g e

    S (a0=0.88) = (2.0831e+09)*( 9.05E-01+i*0.88*1.28E+00)= 1.8852e+09 +2.3464e+09i for sway DOF

    S (a0=0.88) = (9.4319e+10)*( 8.43E-01+i*0.88*3.77E-01)= 7.9511e+10 +3.1291e+10i for rocking DOF

    Modeling for standard software to analysis soil-structure interaction we should use above

    coefficients for setting dashpot and spring for sway and rocking like this figure:

    ky=1.8852e+09 (N/m)

    cy=2.3464e+09(N.s/m)

    kt= 7.9511e+10 (N/m)

    ct= 10 +3.1291e+10(N.s/m)

    Using reference [2] and compute the damping ratio and stiffness of soil-structure system for

    first mod.

    At the first we must write the mass and stiffness matrices:

    m=[90 00 90

    ] , K=[2

    ],

  • 11 | P a g e

    ~

    ~

    A=k-2.m=103[430 215215 215

    ]=0, 1=x110^3

    90=30.21rad/sec

    fix=30.21rad/sec Tfix=0.207sec, ao=1.14

    a0 kh ch kr cr

    1.14 8.71E-01 1.24E+00 7.97E-01 3.74E-01

    With assumption that the lateral force act to each story related by weight of itself, we have:

    1=(12.5648.374

    ) mStr=173.1 ton, H=5.8 m,

    =0.578,

    =

    =

    (.)(+.)

    (.+)(. +..+)(+.)=

    0.0215 - 0.0399i=

    =

    .^2=(.+)(. +..)(+.)

    (.)(.)(+.)=

    13.7795 + 8.4522i=

    =1+ + * + * * =15.7787 + 7.8703i

    =fix2

    +24(1+)= 29.1051 + 0.9915i

    d=Real

    () =29.1051 T= 0.22 sec and =

    ()

    ()=0.0340

    T

    T=0.22

    0.207=1.063, 0=0.034

  • 12 | P a g e

    ~

    ~

    ~

    Using ATC3-06 to compute reduction of base shear for this building.

    For no interaction effect:

    A=0.3 for high relative hazard, B=2.75 from standard spectrum, I=1 for

    building with intermediate importance factor, R=7 for intermediate concert moment frame

    Cs(T, )=

    =0.32.751

    7=0.1179

    V= Cs.W=0.1179*180ton=21.21ton For interaction effect:

    = [Cs(T, ) Cs(T, ) (

    ) ^0.4]

    Cs(T, )=0.1179

    = [0.1179 0.1179 (0.05

    0.07) ^0.4]

    =2.6 Conclusion

    For this specific building if use ATC guideline for SSI we reduce base shear

    about 10% and if compare it with damping ratio that come from modal

    simplified method, can see the increasing in damping ratio computed by

    ATC approach it's not real and for this case SSI it's not so important and if

    we want done with SSI, the more exact approaches is required.