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8/18/2019 ESP REDA SLB_VSD
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REDA ProductionSystem Variable SpeedDrive
Introduction
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204/19/1
!pon completion o" t#is section$ you s#ouldbe able to%
E&plain t#e t#ree basic steps o" VSD operation!nderstand #o' drive proves bene(cial to
certain applications)
Variable Speed Drive
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*
State o" t#e Art
+ec#nolo,y$
-i,# Per"ormance$
Reliable$
Variable Speed Drive
SpeedStar 2000 .lu& Vector
VSD
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4
Variable Speed Drive bectives
3#at is t#e "unction o" a VSD
earn #o' t#e system 'or5s
.eatures 6 7ene(ts
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8
3#at does t#e VSD do "or us
Provides constant torue t#rou,# t#eentire speed ran,e)
:an be used manually to set t#e V/-;
ratio "or speci(c applications
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3#y use a VSD in your
application>.le&ibility to t#e system% Provide li,#tnin, protection "or t#e do'n#oleeuipment)
Eliminate t#e need "or c#o5es in t#e system)
Provide in#erent so"t start no inrus# currents)
Protect t#e do'n#ole euipment "rom pumpo?)
Enable remote operation/automation) Enable smoot# response to torue c#an,es)
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@
Slo' acceleration ramp ultimately reducespump 'ear$ prevents sand in(ltration$ andt#us increases run li"e
Reduces do'ntime and maintenance
AND!!!
can catc# a bac5spinnin, motor)
can provide +rac5in, underload)
3#y use a VSD in your
application>
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VSDs add value to t#e
application Every application can bene(t "rom variable
speedB
ESPs are no e&ception
C E&tend your euipment li"e
C mprove your system eciency
C Enable optimi;ation as 'ell conditions c#an,e
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9
VSD
Disconnect
Step-Up
Transformer
J Box
Step-Down
Transformer
Bank
VSD Application
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10
VSD utput to Fotor
controls t#e output VoltageVoltage and FreqencFreqenc to t#e motor by%
:#an,in, t#e input A: si,nal to D: si,nal$
:#oppin, t#e resultin, D: si,nal$ and
(nally$Varyin, t#e output volta,e and "reuency
to t#e motor)
7y varyin, t#e volta,e and "reuency to t#e
motor$ 'e are c#an,in, '#at is called t#eV/-ert; ratio)
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" #$ases A%
Fixe& Voltage' Fixe& FreqencFixe& Voltage' Fixe& Freqenc Varia(le Voltage' Varia(le FreqencVaria(le Voltage' Varia(le Freqenc
)* Dio&es %on+erter
,* D% ink %apacitors"* ./BTs .n+erter
)* Dio&es %on+erter
,* D% ink %apacitors
"* ./BTs .n+erter
12
3
7asic VSD Electrical dia,ram
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1204/19/1
3#y use VSD>
As 'e #ave seen$ a VSD is simply a device"or ta5in, a (&ed "reuency po'er supplyG
and c#an,in, it to a variable "reuency todrive t#e do'n#ole euipment)
+#ere is not#in, Hma,icH about a VSD) As
t#e "reuency increases$ so does t#e motorspeed as 'ell as its #orsepo'er capability)
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Fedium Volta,e vs) o' Volta,eVSDs
Medium Voltage VSD
Motor
Input Transformer -
Internal
Controller 4.16 V ! " 4.16 V
Step-Do#nTransformer
Step-$pTransformer
%o# Voltage VSD
Motor
Controller
&il-filled Transformer
&utdoor $se
&il-filled Transformer
&utdoor $se
4.16 V416! V
3'!(4'! (
6!! V
!-input
V
Sid( )nclosure
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1404/19/1
+#e increased speed causes t#e pump to putout more #ead and Io'G and$ in an e?ort toobey t#e la's o" p#ysics$ t#e bra5e#orsepo'er reuired to do t#is tas5 also
increases)
3e can predict t#e c#an,e in pumpper"ormance 'it# anity la's)
Si;in, a VSD application is t#en a matter o"matc#in, t#e pump and motor at t#e speedo" interest)
3#y use VSD>
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1804/19/1
+#ere is anot#er point "or discussion '#ic#may be re,arded a specialityG but could uite
possible come in #andy on some occasions)
3e s#ould probably call t#is Ht'ea5in,H t#eapplication)
Summary
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104/19/1
+#e 'ell system curve is simply a reIectiono" t#e total ener,y available and lost in t#e
'ell system 'it# t#e e&ception o" t#e pump)
n our application$ 'e try to matc# t#e pumpper"ormance curve to t#e 'ell system curveG
and '#ere t#ey meet is '#ere t#e 'ells#ould produce)
Summary
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1@04/19/1
.or t#e sa5e o" t#is discussion letJs assumeour 'ell system curve is a strai,#t line and'e 5no' t#e end points)
Assume 'e 'ant to use a KL800 andproduce 1*80 "eet o" +D- at 00 bpd and'e 'ant to produce only 200 "eet o" +D- at*400 bpd
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3e could use a 80 sta,e KL800 and ,et t#edesired 1*80 "eet o" +D- at @0 -; but loo5
'#at #appens to t#e *400 7PD point) 3ecould not possibly run t#e unit t#is slo'ly)
Summary
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1904/19/1
0 )000
,000
"000 1000%apacit - Barrels per Da
2000 3000 4000 5000 6000 )0000
7ea&Feet
7#8otoroa&
)0
,0
"0
10
20
30
,900
)900
"900
:e&a Single Stage #mp #erformance %r+e/N2300 210 Series #mp - Varia(le Freqenc
7 e a & % a p a c i t !
#mp ;nl ! -oa&
4 0 7
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2004/19/1
Ac#ievin, t#e lo'er point o" 200 "eet at *400bpd may cause us to drop to a lo'er
"reuency t#an 'e really 'ant to use)
s t#ere anyt#in, 'e could do>
Summary
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2104/19/1
Mes t#ere is)
3e are dividin, t#e 'ell system curve by t#enumber o" sta,es in t#e pump in order to
display it on our sin,le sta,e pumpper"ormance curve)
" 'e divide t#e 'ell system curve by a
lar,er number o" sta,es say 100 "ore&le$ it tends to become HIatterH)
Summary
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2204/19/1
0 )000
,000
"000 1000%apacit - Barrels per Da
2000 3000 4000 5000 6000 )0000
7ea&Feet
7#8otoroa&
)0
,0
"0
10
20
30
,900
)900
"900
:e&a Single Stage #mp #erformance %r+e/N2300 210 Series #mp - Varia(le Freqenc
7 e a & % a p a c i t !
#mp ;nl ! -oa&
4 0 7
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2*04/19/1
7y usin, more sta,es in t#e pump$ 'e canma5e t#e 'ell system curve Iatter and ,et a
muc# 'ider Io' ran,e covera,e 'it# t#epump) +#e only problem is t#at more sta,esare ,ivin, us too muc# Io' and ta5in, us tot#e ri,#t o" t#e operatin, ran,e)
s t#ere anyt#in, 'e can do to counteractt#is>
Summary
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2404/19/1
+#e +D- reuired is essentially a sum o" t#evertical li"t reuired$ t#e tubin, "riction and
t#e 'ell#ead pressure)
+#e vertical li"t is determined by t#e 'ellproductivity and is beyond our sp#ere o"
inIuence)
3e could possibly increase "riction 'it#smaller tubin,)
Summary
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2804/19/1
+#e easiest t#in, "or us to do is increase t#e'ell#ead pressure)
+#is 'ill #ave t#e e?ect o" raisin, t#e 'ellsystem curve vertically 'it#out c#an,in, t#eslope)
Summary
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204/19/1
0 )000
,000
"000 1000%apacit - Barrels per Da
2000 3000 4000 5000 6000 )0000
7ea&Feet
7#8otoroa&
)0
,0
"0
10
20
30
,900
)900
"900
:e&a Single Stage #mp #erformance %r+e/N2300 2)" Series #mp - Varia(le Freqenc
7 e a & % a p a c i t !
#mp ;nl ! -oa&
4 0 7
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2@04/19/1
7y raisin, t#e 'ell#ead pressure$ 'e canraise t#e 'ell system curve bac5 up to 'it#in
t#e ran,e o" t#e pump)
bviously increasin, t#e 'ell#ead pressurearbitrarily 'ill cause additional po'er loss
but t#ere are occasions '#ere t#e overridin,consideration is strictly a matter o"ma&imi;in, t#e total Io' ran,e)
Summary
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204/19/1
7y increasin, t#e number o" sta,es$ 'e canIatten out t#e 'ell system curve 'it#
respect to t#e pump per"ormance curve andac#ieve a ,reater ran,e)
Summary
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Flow HZ Flow60= ×60
HZ
Head60HeadHZ = ×HZ
60
2
BHP60BHP HZ = ×60
HZ 3
MHP60MHPHZ = ×60
HZ
" 'e 5no' t#e pump per"ormance at 0 -;$ 'e can correct it toanot#er "reuency by t#e anity la's%
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*004/19/1
60MHP ×= 60BHPHZ
60
2
×=HZ 60
60MHP
60BHP
Usefl?qations" 'e 5no' t#e pump 7-P at 0 -; and 'e 5no' '#at is t#e
ma&imum "reuency 'e desire to run at$ 'e can determinet#e minimum permissible 0 -; motor -P ratin, as%
" 'e 5no' t#e pump 7-P at 0 -; and 'e 5no' '#at ourmotor si;e is at 0 -;$ 'e can calculate t#e ma&imumallo'able "reuency be"ore overloadin, t#e motor as%
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*104/19/1
% Load =
BHP60
MHP60 × 60
HZ 2
×= VoltsVoltsHz
60
Usefl?qations" 'e 5no' t#e volta,e at 0 -;$ 'e can calculate it at anot#er
"reuency as%
" 'e 5no' t#e pump 7-P at 0 -; and t#e motor rated -p at0 -;$ 'e can determine t#e motor load at any "reuency as%
60
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*204/19/1
=Volts
x KVA
Amps x
1.32100
0
!"#$e &tp&t KVA = KVA x
'''V
()0V
!se"ul EuationsAt any "reuency$ i" 'e 5no' t#e volts and amps$ 'e cancalculate t#e NVA as%
()0
" 'e 5no' t#e drive NVA ratin, at one input volta,e$ 'e canconvert it to anot#er input volta,e as%
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**04/19/1
×Hp L#m#t =Hz HP L#m#t Hz
6
0
60
×=HZ 6
0
60*HP
60BHP
!se"ul Euations
" 'e 5no' t#e pump s#a"t -P ratin, at 0 -;$ 'e can convert itto anot#er "reuency as%
" 'e 5no' t#e pump s#a"t -P ratin, at 0 -; and t#e pump 7-Preuirement at 0 -;$ 'e can determine t#e ma&imum"reuency allo'able be"ore 'e e&ceed t#e s#a"t capability as%