John Bowne High School...2013/04/11 · Ni2+(aq) + 2e-. Ni(s), E reed = —0.28 V, cathode Fe2+(aq)...
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John Bowne High School...2013/04/11 · Ni2+(aq) + 2e-. Ni(s), E reed = —0.28 V, cathode Fe2+(aq) + 2e- E = —0.44 V, anode red Ni2+(aq) has the larger E red, so it will be reduced