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DATA HASIL PRAKTIKUM

• Panjang sungai yang diamati

= 5 m atau 500 cm

•

Lebar sungai yang diamati= !0 cm

• Keda"aman sungai

Segmen # = $% cm& ! cm& ' cm

Segmen ( = ' cm& $ cm& $! cm

Segmen $ = $! cm& $% cm& $) cm

Segmen = $) cm& $! cm& $! cm

Segmen 5 = $! cm& # cm& ( cm

Segmen ) = ( cm& # cm& $! cm

• Kece*atan A"iran +,e"-sitas. mengguna/an urrent meter 

Segmen # = 0100( m2s

Segmen ( = 01#$ m2sSegmen $ = 01($ m2s

Segmen = 01$ m2s

Segmen 5 = 01$$ m2s

Segmen ) = 01(0 m2s

• Data 3a/tu a"iran mengguna/an met-de *e"am*ung

Keda"aman = )0 cm

Panjang = #0 m

Lebar +titi/ tenga4. = 1) m

U"angan /e 6a/tu +sec-nd.

Tenga4# ($

( (0

$ #%

#)

5 #%

Ratarata #!1)

• Data 3a/tu untu/ met-de *e"am*ung +5 u"angan.

Tenga47 #% deti/& #) deti/& #% deti/& (0 deti/& ($ deti/&A8 Luas *enam*ang +A. mengguna/an urrent meter 

a8 Segmen #

Tra* I = +37+48

2. 9 0 = (80 cm(

Tra* II = +48+49

2. 9 0 = #8'0 cm(

Luas *enam*ang segmen # = (80 cm( : #8'0 cm( = 8$!0 cm(

  = 01$! m(

 b8 Segmen (

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Tra* I = +49+43

2. 9 0 = #8!0 cm(

 Tra* II = +43+38

2. 9 0 = #8)(0 cm(

Luas *enam*ang segmen ( = #8!0 cm( : #8)(0 cm( = $8)0 cm(

  = 01$) m(

c8 Segmen $

Tra* I = +38+37

2. 9 0 = #8500 cm(

Tra* II = +37+36

2. 9 0 = #8)0 cm(

Luas *enam*ang segmen $ = #8500 cm( : #8)0 cm( = (8')0 cm(

  = 01(') m(

d8 Segmen

Tra* I = +36+38

2. 9 0 = #8!0 cm(

Tra* II = +38+38

2. 9 0 = #85(0 cm(

Luas *enam*ang segmen = #8!0 cm( : #85(0 cm( = $8000 cm(

  = 01$ m(

e8 Segmen 5

Tra* I = +38+41

2. 9 0 = #85!0 cm(

Tra* II = +41+42

2. 9 0 = #8))0 cm(

Luas *enam*ang segmen 5 = #8 5!0 cm( : #8))0 cm( = $8(0 cm(

  = 01$( m(

;8 Segmen )

Tra* I = +42+41

2. 9 0 = #8))0 cm(

Tra* II = +

41+38

2 . 9 0 = #85!0 cm(

Luas *enam*ang segmen ) = #8))0 cm( : #85!0 cm( = $8(0 cm(

  = 01$( m(

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c8 Segmen $

= 01($ 9 01(')

  = 010)!0! m$2s

d8 Segmen

= 01$ 9 01$  = 01#0( m$2s

e8 Segmen 5

= 01$$ 9 01$(

  = 01#0)'( m$2s

;8 Segmen )

= 01(0 9 01$(

  = 010)! m$2s

8 Luas *enam*ang +A. met-de *e"am*ung

• Tenga4 sungai

A = L segmen $ : L segmen

  = 01(') m( : 01$ m(

  = 015') m(

D8 Kece*atan a"iran +>e"-sitas. met-de *e"am*ung

Panjang ta"i ra;ia = 5 m

U"angan

/e

Kece*atan +m2s.Tenga4

# 01((

( 01(5

$ 01('

01$#

5 01('

Ratarata 01(%

?8 Debit +. mengguna/an met-de *e"am*ung = , 9 A

• Tenga4 sungai

= 01(% 9 015')

  = 01#) m$2s