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Lecture 15: Expectation for Multivariate Distributions
Probability Theory and Applications
Fall 2008
Those who ignore Statistics are condemned to reinvent it.Brad Efron
Outline
• Correlation
• Expectations of Functions of R.V.
• Covariance
• Covariance and Independence
• Algebra of Covariance
Correlation Intuition
• Covariance is a measure of how much RV vary together.
Wife’s Age and Husband’s Age
Correlation .97
Example from http://cnx.org/content/m10950/latest/
Guess Covariance???Positive, Negative, 0
• Crime Rate, Housing Price
• SAT Scores, GPA Freshman Year
• Weight and SAT Score
• Average Daily Temperature, Housing Price
• GDP, Infant Mortality
• Life Expectancy, Infant Mortality
Expectations of Functions of R.V.
( ( , )) ( , ) ( , )
( ) ( ) ( , )
( , ) ( , )
( ) ( ) ( ) ( )x y
E g x y g x y f x y dydx
E X Y x y f x y dxdy
x f x y dy dx y f x y dx dy
xf x dx yf y dy E X E Y
NOTE substitute appropriate summation for discrete
Variance and Covariance
Univariate becomes variance
Multivariate becomes covariance
Note:
2 2var( ) ( ) ( ) ( )X X Xx
X E X x f x
,
cov( , ) ( )( )
( )( ) ( , )
X Y
X Yx y
X Y E X y
x y f x y
NOTE substitute appropriate integral for continuous
var( ) cov( , )X X X
Calculating Covariance
Can simplify
,
, ,
cov( , ) ( )( )
( , )
( , ) ( , )
( )
( ) ( ) ( )
X Y
X Y X Yx y
X Y X Yx y x y
X Y X Y X Y
X Y E X Y
xy y x f x y
xy f x y y x f x y
E XY
E XY E X E Y
Correlation of X and Y
Definition
The correlation always falls in [ -1, 1]
It a measure of the linear relation between X and Y
cov( , )( , )
X Y
X YX Y
Extreme Cases
If X=Y then ρ=1.
If X=-Y then ρ=-1.
If X and Y independent, then ρ=0.
If X=-2Y then ρ=?.
Example
Joint is
Find correlation of X and Y
2 0, 0, 1( , )
0 . .
x y x yf x y
o w
1
0
1
0
12 2
0
( ) 2 2(1 ) 0 1
( ) 2 (1 ) 1/ 3
( ) 2 (1 ) 1/ 6
var( ) 1/ 6 1/ 9 1/18
y
Yf y dx y y
E Y y y dy
E Y y y dy
Y
1
0
1
0
12 2
0
( ) 2 2(1 ) 0 1
( ) 2 (1 ) 1/ 3
( ) 2 (1 ) 1/ 6
var( ) 1/ 6 1/ 9 1/18
x
Xf x dy x x
E X x x dx
E X x x dx
X
Example
Joint is
Find correlation of X and Y
2 0, 0, 1( , )
0 . .
x y x yf x y
o w
11 12
0 0 0
( , ) 2 (1 ) 1/12
cov( , ) 1/12 1/ 9 1/ 36
cov( , ) 1/ 36( , ) 1/ 2
1/18 1/18
y
X Y
E X Y xydxdy y y dy
X Y
X YX Y
Properties of Covariance
a)
b) cov(aX+bY)=ab[cov(X,Y)]
var( ) cov( , )X X X
( ) ( )
( ) ( ) ( ) ( )
cov( ) ( ) ( ) ( )
[ ( , ) ( ) ( )] cov( , )
E aXbY abE XY
E aX aE X E bY bE Y
aX bY E aXbY E aX E bY
ab E X Y E X E Y ab X Y
Properties of Covariance
c)
d)
2var( ) var( )aX a X
cov( , )( ) ( , )
| | | |
( , ) ( * ) ( , )| || |
X
ab X YaX bY X Y
a b Y
abX Y sign a b X Y
a b
( ) ( * ) ( , )aX bY sign a b X Y
Properties of Covariance
e) If X and Y are independent
Proof:( , ) ( ) ( )
( ) ( ) ( ) ( )
x y
x Y
E X Y xyf x f y dxdy
xf x dx yf y dy E X E Y
cov( , ) 0 ( , ) 0X Y correl X Y
cov( , ) ( ) ( ) ( ) 0X Y E XY E X E Y
Note
Cov(X,Y)=0 does not imply independence of X and Y
Independence of X and Y implies cov(X,Y)=0
In this case Y=X2 so the variables are definitely not independent but their covariance is 0 because they have no linear relation.
Algebra of variance/covariance/correlation
Given:
Calculate mean of Z=2X-3Y+5
variance of Z=2X-3Y+5
2 2
( ) ( )
var( ) var( )
cov( , )
Y Y
X Y
XY
E X E Y
X Y
X Y
Long steps
2 2 2
2
( ) 2 3 5
( ) 2( ) 3( )
[ ( )] 4( ) 3( ) 12( )( )
[ ( )] 4 var( ) 8var( ) 12cov( , )
X Y
X Y
X Y X Y
E X
Z E Z X Y
Z E Z X Y X Y
E Z E Z X Y X Y
Working Rules for linear combinations
Write formula
Discard Constants
Square it
Replace squared R.V
with var and crossterms
with cov
2 2
2 3 5
2 3
4 9 12
4var( ) 9 var( ) 12cov( , )
Z X Y
X Y
X Y XY
X Y X Y