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  • 67

    CHNG V: NG DNG B IU KHIN M T CHNH VO

    IU KHIN NHIT L IN TR.

    5.1 Gii thiu chung v l in tr

    L in tr l mt thit b bin in nng thnh nhit nng thng qua dy

    t (dy nung). T dy t nh bc x, i lu, dn nhit, nhit nng c

    a ti vt cn gia nhit

    5.1.1 c im

    - C kh nng to c nhit cao do nhit nng c tp trung trong

    mt th tch nh.

    - C tc nung ln, nng sut cao do nhit nng tp trung nhit

    cao.

    - Nung u v chnh xc nh vic d iu chnh v khng ch ch

    in v nhit .

    - L bo m c kn, c kh nng nung trong chn khng hoc

    trong mi trng c kh bo v, v vy chy hao kim loi nh.

    - C kh nng c kh ho, t ng ho cao.

    - m bo iu kin v sinh: khng c bi, khng c khi, t ting n.

    5.1.2 Nguyn l lm vic

    Theo nh lut Joule Lence, khi dng in chy qua vt dn c in tr

    R (vt rn hoc cht lng), n s to ra mt nhit lng. Nng lng nhit ny

    s t nng bn thn vt dn hoc gin tip t nng cc vt nung gn n:

    Q = R.I2.t

    Trong :

    Q: Nhit lng to ra trn dy dn (J)

    I: Cng dng in chy qua dy dn (A)

    R: in tr ca dy dn ( )

    t: Thi gian dng in chy qua (s)

  • 68

    5.1.3 Phn loi l in tr

    *) Theo phng php to nhit, chia thnh 2 nhm:

    - L in tr tc dng trc tip: l l in tr m vt nung c dun

    nng trc tip bng dng in chy qua n. Loi l ny t dng v ch

    c dng nung cc vt dng c hnh dng n gin.

    - L in tr tc dng gin tip: l l in tr m nhit c to ra

    dy in tr, ri dy in tr s truyn nhit cho vt nung bng bc x,

    i lu hoc dn nhit

    *) Theo nhit ca l, chia lm 3 loi:

    - L c nhit thp: Nhit lm vic nh hn 6000C

    - L c nhit trung bnh: Nhit lm vic t 6000C 12000C

    - L c nhit cao: Nhit trn 12000C

    5.1.4 Cu to l in tr

    *) Yu cu c bn i vi cu to l in tr

    - Hp l v mt cng ngh: c ngha l cu to l khng nhng ph hp

    vi qu trnh cng ngh yu cu m cn tnh n kh nng s dng n

    i vi qu trnh cng ngh khc nu nh khng lm tng phc tp

    trong thit k v gi c khng qu cao.

    - Hiu qu v k thut: l kh nng biu th hiu sut cc i ca kt

    cu khi cc thng s ca n xc nh (kch thc ngoi, cng sut,

    trng lng)

    - Chc chn khi lm vic: l mt trong nhng tiu ch quan trng nht

    ca cht lng kt cu ca cc l in. Nu trong khi lm vic, 1 b

    phn no khng lm vic s nh hng n qu trnh sn xut

    chung, gy thit hi cho sn xut.

    - Tin li khi s dng

    - R v n gin khi ch to

  • 69

    - Hnh dng b ngoi p

    *) Cu to l in tr

    L in tr thng thng gm 3 phn chnh: v l, lp lt, dy nung.

    - V l: V l in tr l mt khung cng vng, ch yu chu ti trong

    trong qu trnh lm vic ca l. Mt khc v l cng dng gi lp cch

    nhit v m bo s kn hon ton hay tng i ca l. Khung v l cn

    cng, vng chc chu c ti trng ca lp lt, ph ti l (vt nung) v

    cc chi tit c kh gn trn v l.

    V l c hai dng c bn:

    + V l ch nht: dng trong cc l ging, l lin tc, l y bc v l

    y rung

    + V l trn: dng trong cc l ging, l chp.

    V l trn chu c tc dng bn trong tt hn v l hnh ch nht khi

    cng mt lng kim loi lm v l. Khi lm v l trn ngi ta thng chn

    dy t tng ng ca tm thp so vi ng knh v l nh sau:

    ng knh v l (mm) 1000-2000 2500-4000 4500-65000

    dy tm thp (mm) 3-6 8-12 14-20

    - Lp lt:

    Lp lt l in tr thng gm 2 phn: vt liu chu la v cch nhit

    + Phn vt liu chu la c th xy dng bng gch tiu chun, gch hnh

    v gch hnh c bit tu theo hnh dng v kch thc cho ca bung l.

    Cng c khi ngi ta m bng cc loi bt chu la gi l khi m. Khi

    m c th tin hnh ngay trong l hay ngoi nh cc khun. Phn vt liu

    chu la phi t cc yu cu sau:

    Chu c nhit cc i ca l

    C bn nhit ln khi lm vic

  • 70

    C bn c hc khi xp vt nung v t thit b vn chuyn

    trong cc iu kin lm vic

    m bo kh nng gn dy nung bn v chc chn.

    C bn ho hc khi lm vic, chu c tc ng ca kh

    quyn l v nh hng ca vt nung

    m bo kh nng tch nhit cc tiu. iu ny c bit quan trng

    trong l lm vic c chu k.

    + Phn cch nhit thng nm gia v l v vt liu chu la. Mc ch

    ch yu ca phn ny l gim tn tht nhit. Cc yu cu c bn i vi phn

    cch nhit l:

    H s dn nhit cc tiu

    Kh nng tch nhit cc tiu

    n nh v tnh cht l, nhit trong iu kin lm vic xc nh.

    - Dy nung: Dy nung l b phn pht nhit ca l, thng c t

    trong bung l hoc bung pht nhit, chng lm vic nhit cao, v vy

    vt liu lm dy nung cn c yu cu sau:

    Kh nng chu nng tt, khng b oxi ho trong mi trng khng

    kh nhit cao.

    C bn nng cao, bn c hc tt

    C in tr sut ln

    C h s nhit in tr nh.

    Cc kch thc phi n nh

    Cc tnh cht in phi c nh

    D gia cng: ko dy, d hn, i vi vt liu phi kim cn p khun

    c.

    Ngi ta chia dy nung thnh 2 loi:

  • 71

    + Dy nung kim loi: c ch to bng cc hp kim Cr Al, Cr Ni v

    cc hp kim c in tr ln.

    + Dy nung phi kim loi: Dng b bin l SiC, graphit, than.

    5.2 Kho st v m phng c tnh ca l in tr ti phng th

    nghim o lng i Hc Bch Khoa H Ni

    5.2.1 Nhn dng l in tr

    Vi c tnh i tng cho trc nh hnh v:

    - Gii hn thang o: 0 10V (tng ng vi 00C 1000 C)

    - Tc my ghi: 10 mm/h (tng ng vi 1mm/6s)

    - p ng u vo 3V 5V

    - p ng u ra 47,50C 640C (tng ng vi 4,75V 6,4V)

    T th a v dng so chun ta xc nh c tr vn chuyn 0 = 12(s)

    5.2.2 Xc nh m hnh i tng ca h thng

    )(1 t )(1 th )(th

    Hnh 5.1: ng c tnh i tng l in tr ghi trn my Recorder

  • 72

    Hnh 5.2: M hnh i tng

    Hm truyn t: s

    1DT0e).s(W)s(W

    Ta c th xc nh )(W1 p t hm )(1 ty :

    Xc nh hm so chun t :

    Ta c h( ) = h 1( )

    T im 0,7 k song song vi trc t ct ng c tnh ti im A.

    - T im A k song song vi trc )(t ct trc t ti im 7t .

    - Chia 7t lm 3 phn bng nhau v ly im 3t .

    - T im 3t k song song vi trc )(t ct ng c tnh ti im B.

    - T B k song song vi trc t ct trc )(t ti )( 3t

    Hm so chun c xc nh :

    33,0)(y)t(y)t( 33

    Ta nhn thy rng 0,31< )( 3t .Vy i tng cho l khu qun tnh

    bc nht c tr.

    Hm truyn t ca i tng c dng :

    1s.T

    e.K)s(Ws.

    Xc nh cc thng s ca hm truyn t:

    Do h s khuch i: 82.0265.1

    yxK dt

    Xc nh tr dung lng v hng s thi gian T

    )(1 pW pe 0

  • 73

    i tng l khu bc nht c tr nn hm so chun c m t dng:

    T)t( 1

    e1)t(

    Chn hai im A v B trn th:

    A = 0,2 tA = 54(s)

    B = 0,8 tB = 276(s)

    Tt(

    B

    T)t(

    A

    )1B

    1A

    e1

    e1

    T)t()1ln(

    T)t()1ln(

    1BB

    1AA

    1B

    1A

    B

    A

    tt

    )1ln()1ln(

    )1ln(.)1ln(.t)1ln(.)1ln(.t B1BAA1AB

    Tt

    Tt)1ln()1ln( ABBA

    Thay vo hm )(t ta c:

    )s(160

    2,0ln8,0ln54276

    1ln1lnttT

    BA

    AB

    s188,0ln2,0ln

    8,0ln.2762,0ln.54)1ln()1ln(

    )1ln(.t)1ln(.t

    AB

    ABBA1

    Do hm truyn t ca khu qun tnh bc nht c tr l:

    1s.160

    e82,01s.T

    e.K)s(Ws18s

    dt1

    1

  • 74

    Hm truyn t ca i tng c xc nh bi:

    1s.160

    e.82,0e.sWWs.30

    s.1DT

    0

    Vy hm truyn t ca h thng l:

    1s160

    e82.0Ws30

    DT

    5.3 Phng php Ziegler Nichols xc nh tham s cho b iu

    khin PID truyn thng

    5.3.1 Phng php Ziegler Nichols I

    Lut Kp Ti TD P T/KL

    PI 0.9T/KL 10L/3

    PID 1.2T/KL 3L L/2

    Bng 5.1: Tham s b iu khin theo phng php Ziegler Nichols I

    i vi i tng l l in tr c hm truyn:

    1s160

    e82.0Ws30

    DT

    Th bng thng s cho cc b iu khin l:

    Lut Kp Ti TD P 6.5

    PI 5.8 100

    PID 7.8 90 15

    Bng 5.2: Tham s b iu khin theo phng php Ziegler Nichols I

    cho i tng l in tr

    5.3.2 Phng php Ziegler Nichols II

    Phng php ny tnh cc tham s ca b iu khin da trn Kth v Tth

    a) Xc nh Kth v Tth

  • 75

    >> Gh=tf(0.82,[160 1])

    Transfer function:

    0.82

    ---------

    160 s + 1

    >> Gh.inputdelay=30

    Transfer function:

    0.82

    exp(-30*s) * ---------

    160 s + 1

    >> Gh_app=pade(Gh,3)

    Transfer function:

    -0.82 s^3 + 0.328 s^2 - 0.05467 s + 0.003644

    --------------------------------------------------------------

    160 s^4 + 65 s^3 + 11.07 s^2 + 0.7778 s + 0.004444

    >> rlocus(Gh_app)

  • 76

    Hnh 5.1: Xc nh Kth

    Vy Kth ca hm xp x l: 11,9

    Sau khi xc nh c Kth ca hm xp x Gh_app, thay vo i tng

    hiu chnh li tham s Kth h kn ca i tng ch bin gii n nh

    tc l h(t) c dng dao ng iu ho:

    Hnh 5.2: S m phng khi Kth = 11

    Vi Kth = 11 th h kn c dng dao ng iu ho:

    Hnh 5.3: c tnh hng s ti hn

    T th tm c Tth = 110

    Lut tnh ton b tham s theo phng php Ziegler Nichols II

    Lut Kp Ti TD P 0.5Kth

  • 77

    PI 0.45Kth 0.85Tth

    PID 0.6Kth 0.5Tth 0.12Tth

    Bng 5.3: Tham s b iu khin theo phng php Ziegler Nichols II

    i vi i tng l l in tr c hm truyn:

    1s160

    e82.0Ws30

    DT

    Th bng thng s cho cc b iu khin l:

    Lut Kp Ti TD P 5.5

    PI 4.95 93

    PID 6.6 55 13

    Bng 5.4: Tham s b iu khin theo phng php Ziegler Nichols II

    cho i tng l in tr

    5.4 Kt qu m phng

    + Trong trng hp ny ta chn cc h s t l nh sau:

    Ge = 0.35

    eG = 20

    Gu = 0.33 (i vi b iu khin m t chnh)

    Gu = 0.11 (i vi b iu khin m truyn thng)

  • 78

    Hnh 5.4: p ng ca h thng l in tr cho FPIC (--); STFPIC (___)

    V b PID chn theo phng php Ziegler Nichols I

  • 79

    Hnh 5.5: p ng ca h thng l in tr cho FPIC (--); STFPIC (___)

    V b PID chn theo phng php Ziegler Nichols II

    *) Nhn xt

    Qua kt qu m phng ta thy p ng ca h thng m t chnh l tt

    hn so vi cc b iu khin PID truyn thng chn theo phng php Ziegler

    Nichols

  • 80