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7/24/2019 MATE CASO 2
1/3
Comprobemos:
yn=C1 ex+C2x e
x
yp=
1 (x ) ex+
2 (x )x ex
exxe
x
W e
2x+xe2xe2xx=e2x
exex+xex
1 xex
W1 2x e
2x
2exex+xex
ex0
W2 2e
2x
ex2e
x
1=2 xe2x
e2xdx
1=2
x2
2
1=x2
7/24/2019 MATE CASO 2
2/3
2=2 e
2x
e2xdx
2=2x
x2 ex+2x2 ex
x2ex
1 ex+2e
4x
exe4x
W 4 e3x
+e3x
=5e3x
ex 4e4x
1 e4x
W1 30e
5x
30ex4e
4x
ex0
W2
30
ex30ex
7/24/2019 MATE CASO 2
3/3
1=
30e
5x
5e3x
dx
2=
30
5e3x
dx
1=6 e2xdx 2= 6 e
3xdx
2x=
3x=
2dx=d
3dx=d
dx=d
2 dx=
d
3
1=6
2 ed 2=
6
3 ed
1=3e2x
2=2e
3x
yp=3x+(2ex)
yp=5ex