MATE CASO 2

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  • 7/24/2019 MATE CASO 2

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    Comprobemos:

    yn=C1 ex+C2x e

    x

    yp=

    1 (x ) ex+

    2 (x )x ex

    exxe

    x

    W e

    2x+xe2xe2xx=e2x

    exex+xex

    1 xex

    W1 2x e

    2x

    2exex+xex

    ex0

    W2 2e

    2x

    ex2e

    x

    1=2 xe2x

    e2xdx

    1=2

    x2

    2

    1=x2

  • 7/24/2019 MATE CASO 2

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    2=2 e

    2x

    e2xdx

    2=2x

    x2 ex+2x2 ex

    x2ex

    1 ex+2e

    4x

    exe4x

    W 4 e3x

    +e3x

    =5e3x

    ex 4e4x

    1 e4x

    W1 30e

    5x

    30ex4e

    4x

    ex0

    W2

    30

    ex30ex

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    1=

    30e

    5x

    5e3x

    dx

    2=

    30

    5e3x

    dx

    1=6 e2xdx 2= 6 e

    3xdx

    2x=

    3x=

    2dx=d

    3dx=d

    dx=d

    2 dx=

    d

    3

    1=6

    2 ed 2=

    6

    3 ed

    1=3e2x

    2=2e

    3x

    yp=3x+(2ex)

    yp=5ex