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alfa = 2 Xa Ya 0 0 0.1 0.181818 0.2 0.333333 0.3 0.461538 0.4 0.571429 0.5 0.666667 0.6 0.75 0.7 0.823529 0.8 0.888889 0.9 0.947368 1 1 0 0.2 0.4 0.6 0.8 1 1.2 0 0.2 0.4 0.6 0.8 1 2

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Page 1: materi destilasi

alfa = 2

Xa Ya0 0

0.1 0.1818180.2 0.3333330.3 0.4615380.4 0.5714290.5 0.6666670.6 0.750.7 0.8235290.8 0.8888890.9 0.947368

1 1

0 0.2 0.4 0.6 0.8 1 1.20

0.10.20.30.40.50.60.70.80.9

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Page 2: materi destilasi

0 01 1

Page 3: materi destilasi

alfa = 3

Xa Ya0 0 0 0

0.1 0.25 1 10.2 0.4285710.3 0.56250.4 0.6666670.5 0.750.6 0.8181820.7 0.8750.8 0.9230770.9 0.964286

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Page 4: materi destilasi

alfa = 4

Xa Ya0 0 0 0

0.1 0.307692 1 10.2 0.50.3 0.6315790.4 0.7272730.5 0.80.6 0.8571430.7 0.9032260.8 0.9411760.9 0.972973

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Page 6: materi destilasi

Xbenzen Ytoluena1 1

0.897 0.957 0 00.773 0.907 1 10.659 0.8310.555 0.7570.459 0.678

0.37 0.5910.288 0.4960.211 0.3930.141 0.2810.075 0.1610.013 0.031

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Page 9: materi destilasi

campuran biner A dan B dengan αAB = 3F = 100 mol/jamXf = 0.4hasil distilasi bag. atas = 0.9 A + 0.1 B

bawah = 0.1 A + 0.9 Bfeed berupa camp 0.4 uap

0.6 cair F, Xfa. Jika R= 2 berapa rate atas dan bawah

berapa jumlah rate teoritisb. Jika jumlah plate teoritis = 12

berapa rate kembali ke kolom atas

JAWABF = D + W

100 =

NM Komponen AF.Xf = D. Xd + W. Xw

40 =

Distilasi

Page 10: materi destilasi

D, Xd

W, Xw

Distilasi

C

R

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α = 3

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α = 2

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Benzena - Toluena

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α = 2

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α = 4

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Benzena - Toluena

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Page 18: materi destilasi

Xf0.40.4

Xd0.90.9

Xw0.10.1

goa0

0.9

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01

01

01

0.30.9

30.960.54042

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