Perencanaan Batang Tarik Tekan

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  • 7/25/2019 Perencanaan Batang Tarik Tekan

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    a. Perencanaan Batang Tarik

    1) Spesifikasi:

    - Pu = 1610,391

    - Tarik = 0,9

    - Fraktur = 0,7

    - F! = "0 #Pa

    - Fu = $10 #Pa

    - % &aut =

    Per'itungan &e&an sen(iri

    a) Berat sen(iri ="0010*

    ="0010+

    ="0 kg= "0kg + Tinggi rata-rata

    = "0+10

    = "00 g

    &) Be&an per /int =25

    30 = 0,3 k2

    = 0,3 k2+ a!a &atang S106

    = 0,3+1,9$

    =1,6 k2

    Per'itungan &erat sa&ungan

    a) Sa&ungan = 104 + &erat sen(iri= 104 + "

    = ", k2

    &) Be&an per /int =2,5

    30 = 0,03

    c) Se'ingga ni5ai Pu = 1610,3911,60,03

    = 161",1"$ k2

    Preliminary design

    Pu Pn

    Pu = +F!+g

    g=1612,124103

    0,9250 = 716 "

    = 71,6 c"

    Dipilih profil IWF 400.400.15.15

    Spesifikasi prfi5:

    = $00

    B = $00

    t8 = 1

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    tf = 1

    r = ""

    = 17, c" = 17.0 "Berat = 1$0 kg = 0,1$ kg

    = $9.000 c$ = $90.000.000 $

    ! = 16.300 c$ = 163.000.000 $

    i = 16,6 c = 166

    i! = 9,$ c = 9,$

    ; = "."0 c3 = "."0.000 3

    ;! = 09 c3 =09.000 3

    f! = "0 #pa

    fu = $10 #pa

    ") "$0

    =

    L

    rmin =5000

    95,4 = ",$1 ? "$0 OK !!!

    3) Sa&ungan Baut

    @kuran 5u&ang AS2 03-17"9-"00", pasa5 17.3.6)

    ( = 3,1

    ( "$

    ( 3 = $1,1

    n = g C An ( t)

    n = 17.0 C A" $1,1 30) = 1.3$ mm2

    ntr5 5uas 5u&ang A'arus > 14)

    *uas 5u&ang = g C n = 17.0 C 1.3$ = "$66mm

    2

    Persentase 5uas 5u&ang =Luas lubang

    Ag 1004

    =2.466

    17.850 1004 = 13.14 > 14 D

    OK !!

    $) #eng'itung uat Eencana

    2n = 0,7 e fu

    = 0,7 1.3$ $10 = $.730.0 2 = $.730, k2

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    3/4

    2n = 0,90 g f!

    = 0,90 17.0 "0 = $.016."0 2 = $.016," k2

    D 2n !ang (ipakai se&agai kuat rencana a(a5a' !ang terkeci5Dipilih Nn = 4.016,25 kN

    )

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    i = 1, c = 1

    i! = 10,7 c = 107

    ; = .170 c3 = .170.000 3;! = ".900 c3 =".900.000 3

    f! = "0 #pa

    fu = $10 #pa

    )