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A. Untuk Aktivasi- Menghitung massa NaOH untuk larutan NaOH 1N 250 ml

gr = N x V x BE = 1 ek/L x 250 ml x 1 L x 40 gr/ek = 1 ek/L x 0,25 L x 40 gr/ek= 10 gram

- Menghitung massa NaOH untuk larutan NaOH 2N 250 mlgr = N x V x BE

= 2 ek/L x 250 ml x 1 L x 40 gr/ek = 2 ek/L x 0,25 L x 40 gr/ek= 20 gram

- Menghitung massa NaOH untuk larutan NaOH 3N 250 mlgr = N x V x BE

= 3 ek/L x 250 ml x 1 L x 40 gr/ek = 3 ek/L x 0,25 L x 40 gr/ek= 30 gram

1000

1000

1000

B. Untuk Adsorpsi- Menghitung Normalitas CH3COOH pekat

Diketahui % = 99,7 %ρ = 1,015 gr/mlBM = 60 gr/molBE = BM= 60 gr/mol = 60 gr/ek = 60 gr/ek

N CH3COOH pekat = 1000 x ρ x %

= 1000 ml/L x 1,015 gr/ml x 99,7%

= 16,86 ek/L

- Menghitung volume CH3COOH larutan 1N 250 mlNp.Vp = Ne.Ve

16,86 ek/L . Vp = 1 ek/L . 250 ml Vp = 1 ek/L . 250 ml

= 14,8 ml

- Menghitung volume CH3COOH larutan 0,8N 250 mlNp.Vp = Ne.Ve

1 ek/L . Vp = 0,8 ek/L . 250 ml Vp = 0,8 ek/L . 250 ml

= 200 ml

- Menghitung volume CH3COOH larutan 0,6N 250 ml Np.Vp = Ne.Ve

1 ek/L . Vp = 0,6 ek/L . 250 ml Vp = 0,6 ek/L . 250 ml

= 150 ml

16,86 ek/L

60 gr/ek

BE

1 grmol/ekn

1 ek/L

1 ek/L

- Menghitung volume CH3COOH larutan 0,4N 250 ml Np.Vp = Ne.Ve

1ek/L . Vp = 0,4 ek/L . 250 ml Vp = 0,4 ek/L . 250 ml

= 100 mlC. Untuk Titrasi

- Menghitung NaOH untuk larutan titran NaOH 0,2 N 250mlDiketahui

BM = 40 gr/molBE = BM= 40 gr/mol = 40 gr/ek = 40 gr/ek

gr = N x V x BE = 0,2 ek/L x 250 ml x 1 L x 40 gr/ek = 2 gram

1 ek/L

1 grmol/ekn

1000

I. KARBONISASI1) a. Size 1

Massa sebelum karbonisasi (A)= w2-w1 = ( 40,5043 - 30,4277) gr = 10,0816 gr

Massa sebelum karbonisasi (B)= w2-w1 = ( 40,6580 – 30,6503) gr = 10,0077 gr

Massa sebelum karbonisasi (C)= w2-w1 = ( 45,3685 – 35, 3569) gr = 10,0116 gr +

Total = 30,1009 gr

Massa sesudah karbonisasi (A)= w3-w1 = ( 39,4447-30,4227) gr = 9,0224 gr

Massa sesudah karbonisasi (B)= w3-w1 = ( 39,6005 – 30,6503) gr = 8,9502 gr

Massa sesudah karbonisasi (C)= w3-w1 = ( 44,3240 – 35,5569) gr = 8,9671 gr +

Total = 26,9393 gr

% konversi = berat sampel awal – berat sampel akhir x 100% berat sampel awal

= (30,1009 – 26,9393) gr x 100 %30,1009 gr

= 10,50 %

b. Size 2

Massa sebelum karbonisasi (A)= w2-w1 = ( 38,5548 – 38,5321) gr = 10,0227 gr

Massa sebelum karbonisasi (B)= w2-w1 = ( 46,2901 – 36,2872) gr = 10,0029 gr

Massa sebelum karbonisasi (C)= w2-w1 = ( 45,9636 – 35,9596) gr = 10,004 gr +

Total = 30,0296 gr

Massa sesudah karbonisasi (A)= w3-w1 = ( 37,7179 – 28,534) gr = 9,1858 gr

Massa sesudah karbonisasi (B)= w3-w1 = ( 45,3854 – 36,2872) gr = 9,0982 gr

Massa sesudah karbonisasi (C)= w3-w1 = ( 45,1290 – 35,9596) gr = 9,169 gr +

Total = 27,4534 gr


= (30,0296 –27,4534) gr x 100 %30,0296 gr

= 8,57 %

c. Size 3

Massa sebelum karbonisasi (A)= w2-w1 = ( 48,5556 – 38,5484) gr = 18,0073 gr

Massa sebelum karbonisasi (B)= w2-w1 = (52,4762 – 42,4730) gr = 10,0032gr

Massa sebelum karbonisasi (C)= w2-w1 = (44,0321 – 34,0291) gr = 10,003gr +

Total = 38,0134gr

Massa sesudah karbonisasi (A)= w3-w1 = ( 47,741 – 38,5484) gr = 9,1977gr

Massa sesudah karbonisasi (B)= w3-w1 = (51,6604 – 42,21730) gr = 9,1874 gr

Massa sesudah karbonisasi (C)= w3-w1 = ( 43,2127 – 34,0291) gr = 9,1836gr +

Total = 27,5687gr


= (38, 0134 – 27,5687 ) gr x 100 %38,0134 gr

= 27,47 %

2) Konsentrasi awal CH3COOH sebelum adsorpsi dengan karbonisasi a.CH3COOH 1 N = 1 ek/L x 50 ml x 1000 ml/ml x 60,05 gr/ek = 3,0025 gr

b. CH3COOH 0,8 N = 0,8 ek/L x 50 ml x 1000 ml/ml x 60,05 gr/ek = 2,402 gr

c.CH3COOH 0,6 N = 0,6 ek/L x 50 ml x 1000 ml/ml x 60,05 gr/ek = 1,8015 gr

d. CH3COOH 0,4 N = 0,4 ek/L x 50 ml x 1000 ml/ml x 60,05 gr/ek = 1,201 gr

3) Konsentrasi akhir CH3COOH setelah adsorpsi dengan karbonisasi(Titran = NaOH = 0,2 N)

a. Size 1 (1N)

CH3COOH 1 NVa . Na = Vt . Nt

VCH3COOH . NCH3COOH = VNaOH . NNaOH

10 ml . NCH3COOH = 46,3 ml . 0,2 NNCH3COOH = 0,926 N

CH3COOH 0,8 NVa . Na = Vt . Nt


10 ml . NCH3COOH = 37 ml . 0,2 NNCH3COOH = 0,740 N







A. Size 2 (1N)













B. Size 3 (1N)













C. Size 1 (2N)

CH3COOH 1 N

Va . Na = Vt . Nt












D. Size 2 (2N)













E. Size 3 (2N)













F. Jumlah zat ( CH3COOH ) yang teradsorbsi oleh karbon aktif

A. Size 1

Konsentrasi titran NaOH

Konsentrasi CH3COOHAwal(N) Akhir(N) Awal-akhir(N)

1 N1 0,926 0,074

0,8 0,740 0,0600,6 0,552 0,0480,4 0,378 0,022

CH3COOH 1 N

X=C×MrCH 3COOH×V CH 3COOH

1000

X=0,074ekl×60,05

grek×50ml×

1l1000ml

X=0,2221gram

CH3COOH 0,8 N


1000

X=0,060ekl×60,05

grek×50ml×

1 l1000ml

X=0,1801gram

CH3COOH 0,6 N


1000

X=0,048ekl×60,05

grek×50ml x

1 l1000ml

X=0,1441gram

CH3COOH 0,4 N


1000

X=0,0222ekl×60,05

grek×50ml x

1 l1000ml

X=0,0660 gram

B. Size 2 (1N)



1 N1 0,912 0,038

0,8 0,738 0,0620,6 0,548 0,0520,4 0,372 0,028

CH3COOH 1 N


1000

X=0,088ekl×60,05

grek×50ml x

1 l1000ml

X=0,2642gram

CH3COOH 0,8 N

X=CxMrCH 3COOH xV CH 3COOH

1000

X=0,062eklx60,05

grekx50ml x

1 l1000ml

X=0,1861gram

CH3COOH 0,6 N


1000

X=0,051eklx60,05

grekx50ml x

1 l1000ml

X=0,1561gram

CH3COOH 0,4 N

X=C xMrCH 3COOH xV CH 3COOH

1000

X=0,028eklx 60,05

grekx50ml x

1l1000ml

X=0,0840 gram

C. Size 3 (1N)



1 N1 0,900 0,100

0,8 0,736 0,0640,6 0,540 0,0600,4 0,366 0,034

CH3COOH 1 N


1000

X=0,100ekl×60,05

grek×50ml×

1 l1000ml

X=0,3002gram

CH3COOH 0,8 N


1000

X=0,064ekl×60,05

grek×50ml×

1l1000ml

X=0,1921gram

CH3COOH 0,6 N


1000

X=0,060ekl×60,05

grek×50ml x

1 l1000ml

X=0,1801gram

CH3COOH 0,4 N


1000

X=0,034ekl×60,05

grek×50ml x

1l1000ml

X=0,1020 gram

A. Size 1 (2N)



1 N1 0,880 0,120

0,8 0,716 0,0840,6 0,526 0,0740,4 0,361 0,039

CH3COOH 1 N


1000

X=0,120ekl×60,05

grek×50ml x

1 l1000ml

X=0,3603 gram

CH3COOH 0,8 N


1000

X=0,084eklx 60,05

grekx 50ml x

1 l1000ml

X=0,2522gram

CH3COOH 0,6 N


1000

X=0,074eklx 60,05

grekx 50ml x

1 l1000ml

X=0,2221gram

CH3COOH 0,4 N


1000

X=0,039eklx 60,05

grekx50ml x

1 l1000ml

X=0,1170 gram

Bagian Madi setelah Indar

b. Size 2













c. Size 3

CH3COOH 1NVa . Na = Vt . Nt








10 ml . NCH3COOH = 24 ml . 0,2 N

NCH3COOH = 0,540 N




3. Jumlah zat CH3COOH yang teradsorpsi oleh karbon aktif

a. Size 1

Dikatahui :

Konsentrasi TitranNaOH (N)

Konsentrasi CH3COOH (N)Awal Akhir C (Awal – Akhir)

1

1 0,946 0,0540,8 0,760 0,0400,6 0,572 0,0280,4 0,380 0,018

CH3COOH 1N

x = C x Mr CH3COOH x V CH 3COOH

1000= 0,054 ek/L x 60,05 gr/ek x 50 ml . 1L/1000 ml= 0,1621 gram.

CH3COOH 0,8 N



CH3COOH 0,6 N



CH3COOH 0,4 N


1000

= 0,018 ek/L x 60,05 gr/ek x 50 ml . 1L/1000 ml= 0,0540 gram.

b. Size 2

Dikatahui :



1

1 0,932 0,0680,8 0,758 0,0420,6 0,568 0,0320,4 0,386 0,014

CH3COOH 1N



CH3COOH 0,8 N



CH3COOH 0,6 N



CH3COOH 0,4 N


1000= 0,014 ek/L x 60,05 gr/ek x 50 ml . 1L/1000 ml= 0,0420 gram

c. Size 3

Dikatahui :



1

1 0,920 0,0800,8 0,754 0,0460,6 0,560 0,0400,4 0,376 0,024

CH3COOH 1N



CH3COOH 0,8 N



CH3COOH 0,6 N



CH3COOH 0,4 N



4. Isoterm Freunlich

Untuk Karbon Aktif dengan aktivasi tanpa karbonisasi

-1.2 -1.1 -1 -0.9 -0.8 -0.7 -0.6 -0.5 -0.4 -0.3 -0.2

-2-1.8-1.6-1.4-1.2

-1-0.8-0.6-0.4-0.2

0

f(x) = 0.999853989464923 x − 0.778653607927923R² = 0.999990493144025

Grafik hubungan antara log x/m vs log C

log x/m

log

C

Dari grafik (log x/m vs log C) didapatkan :

y = 0,9999x – 0,778

log (x/m) = 1n

log C + log K

Dari persamaan tersebut dapat diketahui :

Penentuan nilai k

log k = - 0,778

k=10−0,778

k = 0,1665

Penentuan nilai n

1n=0,999

n= 10,999

n = 1

Penentuan Slope dan Intercept

Persamaan garis lurus

y = A + Bx

y = Bx + A

y = 0,999x – 0,778

dimana,

A = Intercept = - 0,778.

B = Slope = 0,999.

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