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Pertemuan 25 Uji Kesamaan Proporsi. Matakuliah: I0134 – Metoda Statistika Tahun: 2005 Versi: Revisi. Learning Outcomes. Pada akhir pertemuan ini, diharapkan mahasiswa akan mampu : Mahasiswa dapat menghasilkan uji khi-kuadrat untuk uji kesamaan proporsi. - PowerPoint PPT Presentation
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Pertemuan 25Uji Kesamaan Proporsi
Matakuliah : I0134 – Metoda Statistika
Tahun : 2005
Versi : Revisi
2
Learning Outcomes
Pada akhir pertemuan ini, diharapkan mahasiswa
akan mampu :
• Mahasiswa dapat menghasilkan uji khi-kuadrat untuk uji kesamaan proporsi.
3
Outline Materi
• Hasil pengamatan
• Statistik uji khi-kuadrat
• Pengambilan keputusan
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Uji Proporsi
• Goodness of Fit Test: A Multinomial Population
• Tests of Independence: Contingency Tables
• Goodness of Fit Test: Poisson and Normal Distributions
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A Multinomial Population
1. Set up the null and alternative hypotheses.
2. Select a random sample and record the observed
frequency, fi , for each of the k categories.
3. Assuming H0 is true, compute the expected frequency, ei , in each category by multiplying the category probability by the sample size.
continued
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A Multinomial Population
4. Compute the value of the test statistic.
5. Reject H0 if
(where is the significance level and there are k - 1 degrees of freedom).
22
1
( )f ee
i i
ii
k2
2
1
( )f ee
i i
ii
k
2 2 2 2
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Test of Independence: Contingency Test of Independence: Contingency TablesTables
1. 1. Set up the null and alternative Set up the null and alternative hypotheses.hypotheses.
2. Select a random sample and record 2. Select a random sample and record the observedthe observed
frequency, frequency, ffij ij , for each cell of the , for each cell of the contingency table.contingency table.
3. Compute the expected frequency, 3. Compute the expected frequency, eeij ij , , for each cell. for each cell. e
i jij
(Row Total )(Column Total ) Sample Size
ei j
ij (Row Total )(Column Total )
Sample Size
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Test of Independence: Contingency Tables
4. Compute the test statistic.
5. Reject H0 if (where is the significance level and with n rows and m columns there are
(n - 1)(m - 1) degrees of freedom).
22
( )f e
eij ij
ijji2
2
( )f e
eij ij
ijji
2 2 2 2
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Contoh Soal : Finger Lakes Homes (B)
• Contingency Table (Independence) Test
Price Colonial Ranch Split-Level A-Frame < $65,000 18 6 19 12 > $65,000 12 14 16 3
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Contingency Table (Independence) TestContingency Table (Independence) Test
• HypothesesHypotheses
HH00: Price of the home : Price of the home isis independent of independent of the style the style of the home that is purchased of the home that is purchased
HHaa: Price of the home : Price of the home is notis not independent of theindependent of the
style of the home that is purchasedstyle of the home that is purchased
• Expected FrequenciesExpected Frequencies
PricePrice Colonial Ranch Split-Level A-Frame Colonial Ranch Split-Level A-Frame Total Total
<< $99K 18 $99K 18 6 19 12 6 19 12 55 55
> $99K 12 14 16 > $99K 12 14 16 3 45 3 45
Total 30 20 35 Total 30 20 35 15 10015 100
Contoh Soal : Finger Lakes Contoh Soal : Finger Lakes HomesHomes
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• Contingency Table (Independence) Test– Test Statistic
= .1364 + 2.2727 + . . . + 2.0833 = 9.1486– Rejection Rule
With = .05 and (2 - 1)(4 - 1) = 3 d.f.,
Reject H0 if 2 > 7.81
– Conclusion
We reject H0, the assumption that the price of the home is independent of the style of the home
that is purchased.
22 2 218 16 5
16 56 11
113 6 75
6 75 ( . )
.( )
. .( . )
. . 2
2 2 218 16 516 5
6 1111
3 6 756 75
( . ).
( ). .
( . ).
.
. .052 7 81. .052 7 81
Contoh Soal : Finger Lakes Homes
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• Selamat Belajar Semoga Sukses.