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7/23/2019 PETR 3321 HW 2 Solutions
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PETR 3321
PRESSURE TRANSIENT TESTING
HOMEWORK 2 SOLUTIONS
2.1. c.
Given,
We use Eq. 2.1 from the textbook,
=
= 1 = 2.54 = 3 = 7.62
= 5.95 = 0.00595
= 2.5 = 2.514.696 = 0.1701
=
4 Using the values for the rest of the properties as provided,
we get,
=0.00396
2.2. c.
Given,
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7/23/2019 PETR 3321 HW 2 Solutions
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We use Eq. 2.1 from the textbook,
=
= 1.25 = 3.175 = 5 = 12.7
= 14 = 0.014
=
4 Using the values for the rest of the properties as provided
and rearranging Eq. 2.1 to solve for pressure
drop, we get,
= 0.1565 = 0.1565 14.696 = 2.3
2.3. c.
Given,
We use Eq. 2.1 from the textbook,
=
= 1.1 = 2.794 = 2.7 = 6.858
= 8.5 = 8.514.696 = 0.5784
= 4
Using the values for the rest of the properties as provided and
rearranging Eq. 2.1 to solve for
permeability, we get,
= 0.098 = 98
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2.4. a.
Given,
We use Eq. 2.4 from the textbook,
= 10.001127
Using the values for all of the properties as provided, we
get,
= 265
2.5. a.
Given,
We use Eq. 2.4 from the textbook,
= 1
0.001127
Using the values for all of the properties as provided and
rearranging Eq. 2.4 to solve for flow rate, we
get,
= 935
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2.6. a.
Given,
We use Eq. 2.11 from the textbook,
= 141.2 ()
Using the values for all of the properties as provided, we
get,
= 143
2.7. a.
Given,
We use Eq. 2.11 from the textbook,
= 141.2 ()
Using the values for all of the properties as provided and
rearranging Eq. 2.11 to solve for flow rate, we
get,
= 555
