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NAMA : ELSAGITA SIAGIAN NIM : 03111003038 15.4. The heat required when 1 kmol of MgSO 4 .7H 2 O is absorbed isothermally at 291 K in a large mass of water is 13.3 MJ. What is the heat of crystallization per unit mass of the salt? Panas keseluruhan = 13,3 MJ Berat Molekul MgSO 4 .7H 2 O adalah 246 kg/kmol Maka, panas yang dibutuhkan tiap bagian dari garam itu adalah Panaskeseluruhan Beratmolekul = 13,3 x 1000 kJ / kmol 246 kg / kmol =54,065 kJ / kg 15.6. A batch of 1500 kg of saturated potassium chloride solution is cooled from 360 K to 290 K in an unagitated tank. If the solubilities of KCl are 53 and 34 kg/100 kg water at 360 K and 290 K respectively and water losses due to evaporation may be neglected, what is the yield of crystals? Konsentrasi mula-mula larutan adalah 53 100 =0,53 kg kg air Atau c 1 = 0,53 ( 1+0,53) =0,346 kg kg larutan Massa awal KCl = 1500 kg x 0,346 kg = 520 kg Massa air mula-mula (w 1 ) = 1500 kg – 520 kg = 980 kg Konsentrasi KCl pada larutan akhir c 2 = 34 100 =0,34 kg kg air

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NAMA : ELSAGITA SIAGIANNIM : 03111003038

15.4. The heat required when 1 kmol of MgSO4.7H2O is absorbed isothermally at 291 K in a large mass of water is 13.3 MJ. What is the heat of crystallization per unit mass of the salt?

Panas keseluruhan = 13,3 MJ

Berat Molekul MgSO4.7H2O adalah 246 kg/kmol

Maka, panas yang dibutuhkan tiap bagian dari garam itu adalah

Panas keseluruhanBeratmolekul

=13,3x 1000kJ /kmol246kg /kmol

=54,065kJ /kg

15.6. A batch of 1500 kg of saturated potassium chloride solution is cooled from 360 K to 290 K in an unagitated tank. If the solubilities of KCl are 53 and 34 kg/100 kg water at 360 K and 290 K respectively and water losses due to evaporation may be neglected, what is the yield of crystals?

Konsentrasi mula-mula larutan adalah 53

100=0,53

kgkgair

Atau c1=0,53

(1+0,53)=0,346

kgkg larutan

Massa awal KCl = 1500 kg x 0,346 kg = 520 kg

Massa air mula-mula (w1) = 1500 kg – 520 kg = 980 kg

Konsentrasi KCl pada larutan akhir

c2=34

100=0,34

kgkg air

Karena tidak ada ikatan hydrogen dan evaporasi diabaikan maka R = 1 dan E = 0

Yield = Rwc1−c2(1−E)1−c2(R−1)

=(1 x980 kg )[ 0,53−0,34 (1−0)1−0,34 (1−1) ]=186kg