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九九九九九九九九九九九九九九九九九九九九九 1 Solution of biharmonic problem s with circular boundaries usi ng null-field integral equatio ns Name: Chia-Chun Hsiao Date: 2005/9/2 Place: NCKU

Solution of biharmonic problems with circular boundaries using null-field integral equations

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Solution of biharmonic problems with circular boundaries using null-field integral equations. Name: Chia-Chun Hsiao Date: 2005/9/2 Place: NCKU. Outlines. Introduction Formulation Numerical examples Conclusions. Outlines. Introduction Formulation Numerical examples Conclusions. - PowerPoint PPT Presentation

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Page 1: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

1

Solution of biharmonic problems with circular boundaries using null-field integral equations

Name: Chia-Chun HsiaoDate: 2005/9/2Place: NCKU

Page 2: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

2

Outlines

Introduction Formulation Numerical examples Conclusions

Page 3: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

3

Outlines

Introduction Formulation Numerical examples Conclusions

Page 4: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

4

Engineering problems with arbitrary boundaries

Circular boundary

Circular boundary

Degenerate boundary

Straight boundary

Degenerate boundary

(Legendre polynomials)

(Chebyshev polynomials)

(Fourier series)

Elliptic boundary(Mathieu

function)

Page 5: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

5

MotivationBEM/BIEM

Improper integral

Contour Fictitious boundary method

: collocation point

B BB

C

C

Direct Indirect (Interior)

Singular Desingular (Regular)

Limiting process

xxB B

Null-field approach

Fictitious boundary

Page 6: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

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MotivationBEM/BIEM

Improper integral

CPV & HPV

Contour Fictitious boundary method

B BB CC

ill-posed

Direct Indirect (Exterior)

Singular Desingular (Regular)

Limiting process

xxB B

Degenerate kernel

( , )IK s x

C ( , )EK s x

Field point

Present approach

: collocation point

Null-field

Fictitious boundary

Page 7: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

7

Literature review

Engineering

problems

Laplace problems

Helmholtz problems

Biharmonic problems

Torsion bar with circular holesSteady state heat conduction of tube

Electromagnetic wave

Membrane vibration

Water wave and Acoustic problems

Plane elasticity : Airy stress functionSolid mechanics : plate problemFluid mechanics : Stokes flow

2 0u

2 2( ) 0k u

4 0u

Page 8: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Literature review1. Plane elasticity:

3. Viscous flow (Stokes Flow):

2. Solid mechanics (Plate problem):

4 0, :u u Airy stress function

4 0, :u u stream function

ntdisplacemelateraluu :,04

Jeffery (1921), Howland and Knight (1939),Green (1940) and Ling (1948)

Kamal (1966), DiPrima and Stuart (1972), Mills (1977) and Ingham and Kelmanson (1984)

Bird and Steele (1991)

Page 9: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Purpose

A semi-analytical approach in conjunction with Fourier series, degenerate kernels and adaptive observer system is applied to biharmonic problems.

Advantages : 1. Mesh free. 2. Accurate. 3. Free of CPV and HPV.

Page 10: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Outlines

Introduction Formulation Numerical examples Conclusions

Page 11: Solution of biharmonic problems with circular boundaries using null-field integral equations

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11

Problem statement

Governing equation:

Essential boundary condition:

4 ( ) 0,u x x ( ), ( ),u x x x B

:lateral displacement,( )u x ( )x

Bu

u

:slope

Natural boundary condition:( ), ( ),m x v x x B( )m x ( )v x: moment, : shear

force

v

m

Page 12: Solution of biharmonic problems with circular boundaries using null-field integral equations

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12

Boundary integral equations

BIEs are derived from the Rayleigh-Green identity :

8 ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),B

u x U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

xW

x

Interior problem

BCW

BIE for the domain point

Null-field integral equation

Page 13: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Boundary integral equation for the domain point

8 ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),B

u x U s x v s s x m s M s x s V s x u s dB s x

8 ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),B

x U s x v s s x m s M s x s V s x u s dB s x

8 ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),m m m m

B

m x U s x v s s x m s M s x s V s x u s dB s x

8 ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),v v v v

B

v x U s x v s s x m s M s x s V s x u s dB s x : Poisson ratio

,

( )( )x

x

u xK

n

22

, 2

( )( ) ( ) (1 )m x

x

u xK u x

n

2

,

( ) ( )( ) (1 )v x

x x x x

u x u xK

n t n t

Displacement

Slope

Displacement

Moment

Displacement

Shear force

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Null-field integral equation

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), Cm m m m

B

U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), Cv v v v

B

U s x v s s x m s M s x s V s x u s dB s x : Poisson ratio

,

( )( )x

x

u xK

n

22

, 2

( )( ) ( ) (1 )m x

x

u xK u x

n

2

,

( ) ( )( ) (1 )v x

x x x x

u x u xK

n t n t

Displacement

Slope

Displacement

Moment

Displacement

Shear force

Page 15: Solution of biharmonic problems with circular boundaries using null-field integral equations

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is the fundamental solution, which satisfies

Relation among the kernels

( , ) ( , ) ( , ) ( , )

( , ) ( , ) ( , ) ( , )

( , ) ( , ) ( , ) ( , )

( , ) ( , ) ( , ) ( , )

m m m m

v v v v

U s x s x M s x V s x

U s x s x M s x V s x

U s x s x M s x V s x

U s x s x M s x V s x

, ( )m sK , ( )v sK , ( )sK

, ( )xK

, ( )m xK

, ( )v xK

2( , ) lnU s x r r 4 ( , ) 8 ( )U s x s x

Continuous (Separable form of degenerate kernel)

Page 16: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Degenerate kernels

( , )x r

( , )s R

32 2

2

222

32 2

2

22

1( , ) (1 ln ) ln [ (1 2ln ) ]cos( )

2

1 1[ ]cos[ ( )],

( 1) ( 1)( , ) ln

1( , ) (1 ln ) ln [ (1 2ln ) ]cos( )

2

1 1[ ]co

( 1) ( 1)

I

m m

m mm

E

m m

m mm

U s x R R R R RR

m Rm m R m m R

U s x r rR

U s x R R

R R

m m m m

s[ ( )],m R

R

EUO

IU

q f

s

r

xx

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Fourier series

01

( ) ( cos sin ),M

n nn

u s g g n h n s B

01

( ) ( cos sin ),M

n nn

s c c n d n s B

01

( ) ( cos sin ),M

n nn

m s a a n b n s B

01

( ) ( cos sin ),M

n nn

v s p p n q n s B

The boundary densities are expanded in terms of Fourier series:

M: truncating terms of Fourier series

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Adaptive observer system

ja

22R

1R

1O2O

3O

1B

2B3B

: Collocation point

: Radius of the jth circle

: Origin of the jth circle

: Boundary of the jth circle

( , )x

jR

jO

jB

1

33R

1x

2x

3x

2 1Mx

2Mx

kx

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Vector decomposition for normal derivative

i j j

e

ie

iB

jOjB

j

iiO

je

Tangential direction

True normal direction

Radial direction

( , ) ( , )( , ) cos( ) cos( )

2nx x

U s x U s xU s x

n t

: normal derivative

xt xn

( , ) ( , )( , ) cos( ) cos( )

2nx x

s x s xs x

n t

( , ) ( , )( , ) cos( ) cos( )

2nx x

M s x M s xM s x

n t

( , ) ( , )

( , ) cos( ) cos( )2n

x x

V s x V s xV s x

n t

: tangential derivative

x( , )x

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Linear algebraic system

Null-field integral equations for and formulations( )u x ( )xq

1

1

2

2

11 11 12 12 1 1

11 11 12 12 1 1

21 21 22 22 2 2

21 21 22 22 2 2

1 1 2 2

1 1 2 2H

H

H H

H H

H H

H H

H H H H HH HH

H H H H HH HH

θ θ θ θ θ θ

θ θ θ θ θ θ

θ θ θ θ θ θ

U Θ U Θ U Θ v

U Θ U Θ U Θ m

U Θ U Θ U Θ v

U Θ U Θ U Θ m

U Θ U Θ U Θ v

U Θ U Θ U Θ m

1

1

2

2

11 11 12 12 1 1

11 11 12 12 1 1

21 21 22 22 2 2

21 21 22 22 2 2

1 1 2 2

1 1 2 2H

H

H H

H H

H H

H H

H H H H HH HH

H H H H HH HH

θ θ θ θ θ θ

θ θ θ θ θ θ

θ θ θ θ θ θ

M V M V M V θ

M V M V M V u

M V M V M V θ

= M V M V M V u

M V M V M V θ

M V M V M V u

1

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),j

HC

j j j j jj B

U s x v s s x m s M s x s V s x u s dB s x

1

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ),j

HC

j j j j jj B

U s x v s s x m s M s x s V s x u s dB s x

H: number of circular boundaries

Collocation circle index

Routing circle index

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Numerical

Analytical

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

Linear algebraic system

Potential

Flowchart of the present method

Degenerate kernels

Fourier series

Fourier coefficients

BIE for domain point

Adaptive observer system

Collocation method

Matching B.C.

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Stokes flow problems (Eccentric case)

2R

e1B

2B

1R

1

1 1 1 1,u c R

2 20, 0u

Governing equation:

Essential boundary condition:

4 ( ) 0,u x x

on

on

1B

2B

u

: stream function

: normal derivative of stream function

/u n

(Stationary)

Page 23: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Linear algebraic system

1 1

1 1

2 2

2 2

11 11 12 12 11 11 12 12

11 11 12 12 11 11 12 12

21 21 22 22 21 21 22 22

21 21 22 22 21 21 22 22

θ θ θ θ θ θ θ θ

θ θ θ θ θ θ θ θ

U Θ U Θ M V M Vv θ

U Θ U Θ M V M Vm u=

U Θ U Θ M V M Vv θ

U Θ U Θ M V M Vm u

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( ) ( , ) ( ) ( , ) ( ) ( ), C

B

U s x v s s x m s M s x s V s x u s dB s x

Unknown constant

Given

Unknown

c

Page 24: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Constraint equation

2 21

2 2

2

, ,1

1, ,

{ [ ( , ) ( ) ( , ) ( )

( , ) ( ) ( , ) ( )] ( )} ( ) 0,

jj jn nB B

j

j j jn n

U s x v s s x m s

M s x s V s x u s dB s dB x x

1 11 1 0nB B

dB dBn

2 2

2 2

2

1

1( ) { [ ( , ) ( ) ( , ) ( )

8

( , ) ( ) ( , ) ( )] ( )},

jj jB

j

j j j

x U s x v s s x m s

M s x s V s x u s dB s x

2( ) ( )x u x

x

1B

2B

e

Vorticity:

Constraint:

Page 25: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Inner circle

Trapezoid integral

2

01

2( ) ( )

N

kk

f d fN

2 21

2 2

2

, ,1

1, ,

{ [ ( , ) ( ) ( , ) ( )

( , ) ( ) ( , ) ( )] ( )} ( ) 0

jj jn nB B

j

j j jn n

U s x v s s x m s

M s x s V s x u s dB s dB x

( 2)j

Analytical

Numerical

( 1)j

x

1B2B

eSeries sum Trapezoid integral

1 11 1( , ) ( ) ( )

B Bf s x dB s dB x 1 2

2 1( , ) ( ) ( )B B

f s x dB s dB xVector

decomposition

Outer circle

Page 26: Solution of biharmonic problems with circular boundaries using null-field integral equations

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26

Linear algebraic augmented system

1

1

1 12

2

1

11 11 12 12 11 11

11 11 12 12 11 11

21 21 22 22 21 21

21 21 22 22 21 21

11 11 12 12 11 11

R

u

θ θ θ θ θ θ

θ θ θ θ θ θ

U Θ U Θ V Mv

U Θ U Θ V Mm

U Θ U Θ V Mv

U Θ U Θ V Mm

U Θ U Θ V M2 2 2 2 2 2,n ,n ,n ,n ,n ,n

Unknown

Page 27: Solution of biharmonic problems with circular boundaries using null-field integral equations

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27

Outlines

Introduction Formulation Numerical examples Conclusions

Page 28: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Plate problems

1B

4B

3B

2B1O

4O

3O

2O

Geometric data:

1 20;R 2 5;R

( ) 0u s 1B( ) 0s

1 (0,0),O 2 ( 14,0),O

3 (5,3),O 4 (5,10),O 3 2;R 4 4.R

( ) sinu s

( ) 1u s

( ) 1u s

( ) 0s

( ) 0s

( ) 0s

2B

3B

4B

and

and

and

and

on

on

on

on

Essential boundary conditions:

(Bird & Steele, 1991)

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Contour plot of displacement

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

Present method (N=21)

Present method (N=61)

Present method (N=41)

Present method (N=81)

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Contour plot of displacement

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

-20 -15 -10 -5 0 5 10 15 20-20

-15

-10

-5

0

5

10

15

20

Present method (N=101)

Bird and Steele (1991)

FEM (ABAQUS)FEM mesh

(No. of nodes=3,462, No. of elements=6,606)

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Parseval sum for convergence ( )

0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

0.4

0.8

1.2

1.6

Pa

rse

val s

um

0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

0.2

0.4

0.6

0.8

1

Pa

rse

val s

um

1v1m

0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

2

4

6

8

Pa

rse

val s

um

0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

1

2

3

4

Pa

rse

val s

um

2v2m

2 2 2 2 200

1

( ) 2 ( )n nn

f d a a b

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0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

200

400

600

Pa

rse

val s

um

0 10 20 30 40Te rm s o f Fo u rie r se rie s

40

60

80

100

120

140

Pa

rse

val s

um

3v3m

0 10 20 30 40Te rm s o f Fo u rie r se rie s

0

50

100

150

200

250

Pa

rse

val s

um

0 10 20 30 40Te rm s o f Fo u rie r se rie s

10

20

30

40

50

60

70

Pa

rse

val s

um

4v4m

Parseval sum for convergence

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Stokes flow problems

1

2 1R

e

1 0.5R

1B

Governing equation:

4 ( ) 0,u x x

Boundary conditions:

1( )u s u and ( ) 0.5s on 1B

( ) 0u s and ( ) 0s on 2B

2 1( )

e

R R

Eccentricity:

Angular velocity:

1 1

2B

(Stationary)

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Comparison of stream function

Kelmanson & Ingham (BIE)Analytical solution

Present method

n=80 n=160 n=320Limitn→∞

0.0 0.1066 0.1062 0.1061 0.1061 0.1060 0.1060 (N=5)

0.1 0.1052 0.1048 0.1047 0.1047 0.1046 0.1046 (N=7)

0.2 0.1011 0.1006 0.1005 0.1005 0.1005 0.1005 (N=7)

0.3 0.0944 0.0939 0.0938 0.0938 0.0938 0.0938 (N=7)

0.4 0.0854 0.0850 0.0848 0.0846 0.0848 0.0848 (N=9)

0.5 0.0748 0.0740 0.0739 0.0739 0.0738 0.0738 (N=11)

0.6 0.0622 0.0615 0.0613 0.0612 0.0611 0.0611 (N=17)

0.7 0.0484 0.0477 0.0474 0.0472 0.0472 0.0472 (N=17)

0.8 0.0347 0.0332 0.0326 0.0322 0.0322 0.0322 (N=21)

0.9 0.0191 0.0175 0.0168 0.0163 0.0164 0.0164 (N=31)

n: number of boundary nodes

1u

N: number of collocation points

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0 80 160 240 320 400 480 560 640

0.0736

0.074

0.0744

0.0748

0 80 160 240 320

Comparison for 0.5

DOF of BIE (Kelmanson)

DOF of present method

BIE (Kelmanson) Present method Analytical solution

(160)

(320)

(640)

u1

(28)

(36)

(44)(∞)

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36

Contour plot of Streamline for

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=81)

Kelmanson (Q=0.0740, n=160)

Kamal (Q=0.0738)

e

Q/2

Q

Q/5

Q/20-Q/90

-Q/30

0.5

0

Q/2

Q

Q/5

Q/20-Q/90

-Q/30

0

Page 37: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

37

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=21)

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=81)

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=41)

Contour plot of Streamline for 0.8

Kelmanson (Q=0.0740, n=160)

Page 38: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

38

Contour plot of vorticity for

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=21) Present method (N=41)

Kelmanson (n=160)

0.5

Page 39: Solution of biharmonic problems with circular boundaries using null-field integral equations

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39

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Present method (N=21) Present method (N=41)

Contour plot of vorticity for 0.8

Kelmanson (n=160)

Page 40: Solution of biharmonic problems with circular boundaries using null-field integral equations

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Outlines

Introduction Formulation Numerical examples Conclusions

Page 41: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

41

Conclusions

Successful applied to biharmonic problems with circular boundaries by using the present method.

Good agreement was obtained after compared with previous results, exact solution and ABAQUS data.

Stream function and vorticity were found to be independent of Poisson ratio as we predicted.

Once engineering problems satisfy the biharmonic equation with circular boundaries, our present method can be used.

Page 42: Solution of biharmonic problems with circular boundaries using null-field integral equations

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42

Thank you for your kind attention!

The end

Page 43: Solution of biharmonic problems with circular boundaries using null-field integral equations

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43

Direct BIEM Indirect BIEM

8 ( ) ( , ) ( ) ( , ) ( )

( , ) ( ) ( , ) ( ) ( ),B

u x U s x v s s x m s

M s x s V s x u s dB s x

0 ( , ) ( ) ( , ) ( )

( , ) ( ) ( , ) ( ) ( ),

B

C

U s x v s s x m s

M s x s V s x u s dB s x

( ) ( , ) ( ) ( , ) ( )} ( )

,B

u x U s x s s x s dB s

x

( ) ( , ) ( ) ( , ) ( )} ( )

,

B

C

u x U s x s s x s dB s

x

Conclusions

Null-field integral equation available?

Null-field ! No !

Page 44: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

44

?Further research

Viewpoint Finished Further research

Direct BIEM

& formulation & formulation

Indirect BIEM

Single & double layer potentials

Triple & Quadruple layer potentials

Post processin

gLateral displacement

Stress or moment diagram

Boundary condition

Essential boundary condition

Natural boundary condition...etc.

( )u x ( )x ( )m x ( )v x

Page 45: Solution of biharmonic problems with circular boundaries using null-field integral equations

九十四年電子計算機於土木水利工程應用研討會

45

?Further research

Viewpoint Finished Further research

Degenerate scale

Simply-connected problem had finished by Wu (2004)

Doubly-connected & multiply-connected problems

Shape of domain

Circular domain Arbitrary domain

Page 46: Solution of biharmonic problems with circular boundaries using null-field integral equations

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46

uniform pressure

a

B

w=constant

0)(,0)( xxu

: flexure rigidity

: deflection of the circular plate

: uniform distributed load

: domain of interest

)(xu

D

)(xw

Governing equation: xD

xwxu ,

)()(4

Boundary condition: 0)(,0)( xxu

Splitting method

xxu ,0)(*4Governing equation:

Boundary condition:D

wax

D

waxu

16)(,

64)(

3*

4*

General form

Governing equation: xxu ,0)(*4

Boundary condition: )()(),()(**** xxxuxu