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Will The Circle Be Unbroken arr: Bob Wolford TablEdited By Bob A Wolford [email protected] Dec 2008 Page 1 / 3 F # T A B 4 4 melody Q U 0 U 0 U 0 U 1 V 3 G(GBD) V 3 U U 1 U 1 U 0 V 3 V 1 V G7(GBD/F) U 1 U 0 V 3 . C(CEG) U 0 F # T A B 7 V 3 . U 1 C 0 G(GBD) V U 0 U 1 V 3 V 3 V U 1 U 3 V 3 V 1 F # T A B 13 V Em(EgB) U 3 U 0 V 1 . G(GBD) U 3 V 0 D(DF # A) U 1 U 0 C 3 G(GBD) double stops V U 0 U 0 U 1 U 0 V 3 V 0 V 3 V 0

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  • Will The Circle Be Unbroken arr: Bob Wolford TablEdited By Bob A Wolford

    [email protected] Dec 2008

    Page 1 / 3

    T A B

    melody

    0

    0

    0

    1

    3

    G(GBD)

    3

    1

    1

    0

    3

    1

    G7(GBD/F)

    1

    0

    3

    C(CEG)

    0

    T A B

    7

    3

    1

    0

    G(GBD)

    0

    1

    3

    3

    1

    3

    3

    1

    T A B

    13

    Em(EgB)

    3

    0

    1

    G(GBD)

    3

    0

    D(DF A)

    1

    0

    3

    G(GBD)

    double stops

    0

    0

    1

    0

    3

    0

    3

    0

  • Will The Circle Be Unbroken - arr: Bob Wolford

    Page 2 / 3

    T A B

    19

    1

    0

    1

    0

    0

    3

    1

    3

    G7(GBD/F)

    1

    0

    2L

    3

    C(CEG)

    0

    2L

    3

    1

    0

    0

    G(GBD)

    T A B

    25

    0

    1

    3

    0

    3

    0

    1

    3

    0

    3

    0

    1

    0

    Em(EgB)

    3

    0

    1

    3

    G(GBD)

    3

    T A B

    31

    0

    2

    D(DF A)

    1

    0

    3

    G(GBD)

    1

    0

    2

    1

    3

    backup

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    T A B

    37

    G7(GBD/F)

    1

    2L

    1

    2L

    C(CEG)

    2L

    1

    2L

    1

    2L

    1

    2L

    1

    G(GBD)

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

  • Will The Circle Be Unbroken - arr: Bob Wolford

    Page 3 / 3

    T A B

    43

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    1

    3

    D(DF A)

    3

    2

    3

    2

    G(GBD)

    T A B

    49

    embellishments

    0

    0

    0

    0

    0

    0

    1

    0

    2

    H

    0

    3

    3

    0

    1L

    0

    1

    3

    0

    1

    0

    0

    0

    3

    2

    H

    0

    3

    1L

    0

    1

    G7(GBD/F)

    1

    0

    1L

    0

    1

    1L

    0

    0

    1

    0

    C(CEG)

    1

    3

    2L

    T A B

    55

    2

    0

    3

    0

    3

    0

    1L

    0

    1

    0

    0

    G(GBD)

    1

    Po

    0

    0

    0

    0

    0

    1

    0

    2

    H

    0

    3

    3

    0

    1L

    0

    1

    3

    0

    1

    0

    0

    0

    3

    0

    0

    0

    1L

    0

    1

    3

    2L

    3

    T A B

    61

    3

    Em(EgB)

    3

    0

    1

    G(GBD)

    2L

    0

    3Po

    0

    1

    0

    0

    D(DF A)

    0

    0

    1

    H

    0

    2L

    1

    0

    0

    0

    2

    H

    3

    0

    G(GBD)

    1

    0

    0

    0

    3

    0

    1

    0

    0

    0

    1

    H

    2

    0