tán sắc - giao thoa ánh sáng toàn tập vật lý 12

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  • 7/31/2019 tn sc - giao thoa nh sng ton tp vt l 12

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    Bi tp 12 luyn thi i hc - Trn Th An ([email protected] 09.3556.4557) Trang 1

    TN SC GIAO THOA NH SNGA. L THUYT

    TN SC NH SNG* S tn sc nh sng

    Tn sc nh sng l s phn tch mt chm sng phc tp thnhcc chm sng n sc.

    * nh sng n sc, nh sng trngnh sng n sc l nh sng khng b tn sc khi i qua lngknh. Mi nh sng n sc c mt mu nht nh gi l mu n sc.

    Mi mu n sc trong mi mi trng c mt bc sng xcnh. Ch rng mu sc c qui nh bi tn s sng nh sng vkhng i khi truyn i trong cc mi trng khc nhau.

    Khi truyn qua cc mi trng trong sut khc nhau vn tc ca nh sng thay i, bc sng canh sng thay i cn tn s ca nh sng th khng thay i.

    nh sng trng l tp hp ca v s nh sng n sc khc nhau c mu bin thin lin tc t ntm.

    Di c mu nh cu vng c c v s mu nhng c chia thnh 7 nhm mu chnh (m mt ngi cth phn bit c) l , cam, vng, lc, lam, chm, tm, cn gi l quang ph ca nh sng trng.

    Chit sut ca cc cht lng trong sut i vi cc nh sng n sc khc nhau l khc nhau, chit sutbin thin theo mu sc ca nh sng v tng dn t mu n mu tm: n < ncam vcam >. . . . > vtm.

    Tnh cht ny l tnh cht chung cho mi mi trng trong sut . Khi nh sng trng truyn qua cc mitrng trong sut nh lng cht phng ,bn mt song song , thu knh , lng knh . . . u xy ra hin tng tnsc nhng th hin r nht khi truyn qua lng knh. Hin tng tn sc xy ra ng thi vi hin tng khc xnh sng .

    * ng dng ca s tn sc nh sngHin tng tn sc nh sng c dng trong my quang ph phn tch mt chm sng a sc, do cc

    vt sng pht ra, thnh cc thnh phn n sc.Nhiu hin tng quang hc trong kh quyn, nh cu vng chng hn xy ra do s tn sc nh sng. l

    v trc khi ti mt ta, cc tia sng Mt Tri b khc x v phn x trong cc git nc.Hin tng tn sc lm cho nh ca mt vt trong nh sng trng qua thu knh khng r nt m b nhe,

    li b vin mu sc (gi l hin tng sc sai).

    NHIU X NH SNGHin tng nhiu x l hin tng nh sng khng tun theo nh lut truyn thng .Hin tng nhiu x quan st c khi nh sng truyn qua l nh, hoc gn mp ca nhng vt trong sut

    hay khng trong sut .Hin tng nhiu x gii thch c khi coi nh sng c tnh cht sng. Mi l nh hoc khe hp khi c nh

    sng truyn qua s tr thnh mt ngun pht sng nh sng th cp.Mi chm nh sng n sc l mt chm sng c bc sng v tn s xc nh:

    - Trong chn khng , bc sng xc nh bi cng thc :)(

    )/(10.3)(

    8

    Hzf

    sm

    f

    cm == .

    - Trong mi trng trong sut c chit sut n:nfn

    c

    f

    v ===

    .' .

    GIAO THOA NH SNG GIAO THOA NH SNG TRNG* Hin tng giao thoa nh sng

    Hai chm sng kt hp l hai chm pht ra nh sng c cng tn s v cng pha hoc c lch phakhng i theo thi gian.

    Khi hai chm sng kt hp gp nhau chng s giao thoa vi nhau: Nhng ch 2 sng gp nhau m cngpha vi nhau, chng tng cng ln nhau to thnh cc vn sng. Nhng ch hai sng gp nhau m ngc phavi nhau, chng trit tiu nhau to thnh cc vn ti. Nu hai ngun cng pha th vn trung tm l vn sng.

    tm

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    Bi tp 12 luyn thi i hc - Trn Th An ([email protected] 09.3556.4557) Trang 2

    Nu chm sng ti gm nhiu bc x th tr mn thu c l cc h thng vn xen k nhau vi cckhong vn khc nhau. Ti vn trung tm c s chng chp ca cc h thng vn v c mu l tng hp ca cc

    bc x. Ti mt s im trn mn cng c hin tng chng chp ny g l s trng vn. Khong cch gia haivn gn nht c mu ging mu vn trung tm gi l khong trng vn.

    Nu dng nh sng trng th h thng vn giao thoa ca cc nh sng n sc khc nhau s khng trngkht vi nhau: chnh gia, vn sng ca cc nh sng n sc khc nhau nm trng vi nhau cho mt vn sngtrng gi l vn trng chnh gia. hai bn vn trng chnh gia, cc vn sng khc ca cc sng nh sng nsc khc nhau khng trng vi nhau na, chng nm k st bn nhau v cho nhng quang ph c mu nh

    cu vng.Hin tng giao thoa nh sng l bng chng thc nghim quan trng khng nh nh sng c tnh chtsng.

    * V tr vn, khong vn

    + V tr vn sng: xs = ka

    D; vi k Z.

    + V tr vn ti: xt = (2k + 1)a

    D

    2

    ; vi k Z.

    + Khong vn l khong cch gia 2 vn sng (hoc 2 vn ti) lin tip:

    i =a

    D. Gia n vn sng lin tip c (n 1) khong vn.

    MY QUANG PH - CC LOI QUANG PHMy quang ph:nh ngha:My quang ph l dng c dng phn tch chm sng c nhiu thnh phnthnhnhng thnh phn n sc khc nhau .

    Nguyn tc hot ng: Da vo hin tng tn sc nh sng .Cu to: Cu to gm 3 b phn chnh: ng chun trc, h tn sc v bung nh

    ng chun trc: ng chun trc l b phn c dng mt ci ng, gm mt thu knh hi t (L 1) gn mtu ng, u cn li c mt khe hp, tiu im (F) nm tiu din ca thu knh. ng chun trc c tc dngto ra chm tia l sau thu knh L1 l chm sng song song.

    H tn sc:H tn sc gm mt hoc vi thu knh (P), c tc dng tn sc chm sng phc tp truyn tng chun trc ti lng knh.

    Bung nh:Bung nh l mt hp kn gm mt thu knh hi t (L2 ) v mt tm knh m hoc knh nh

    (E) t ti tu din ca thu knh. Bung nh c tc dng ghi li quang ph ca ngun sng. Quang ph lin tc:

    nh ngha:Quang ph lin tc l quang ph gm nhiu di mu t n tm , ni lin nhau mt cchlien tc .

    Ngun pht sinh quang ph lin tc: Cc cht rn , cht lng , cht kh p sut ln khi b nung nng spht ra quang ph lien tc .

    Tnh cht:- Quang ph lin tc khng ph thuc vo bn cht ca vt pht sng .- Quang ph lin tc ph thuc vo nhit ca vt pht sng . Khi nhit tng dn th cng bc x

    cng mnh v mim quang ph lan dn t bc x c bc sng di sang bc x c bc sng ngn.Quang ph vch pht x:

    L1 P

    L2

    E

    F2

    F1

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    nh ngha:Quang ph gm cc vch mu ring l , ngn cch nhau bng nhng khong ti, c gi lquang ph vch pht x .

    Ngun pht ra quang ph vch pht x: Cc cht kh hay hi p sut thp pht ra khi b kch thch phtsng .

    Tnh cht :- Mi nguyn t ho hc khi b kch thch , pht ra cc bc x c bc sng xc nh v cho mt quang

    ph vch pht x ring , c trng cho nguyn t y .- Cc nguyn t khc nhau , pht ra quang ph vch khc hn nhau v : s lng cc vch , mu sc

    cc vch, v tr (tc l bc sng)ca cc vch v v cng sng ca cc vch .Quang ph vch hp th:nh ngha:Quang ph lin tc thiu mt s vch mu do b cht kh (hay hi kim loi) hp th, c gi

    l quang ph vch hp th. (Nh vy: Quang ph vch hp th l nhng vch ti trn nn ca quang ph lintc)

    Ngun pht ra quang ph vch hp th: Chiu nh sng t mt ngun qua khi kh hay hi b nung nngri chiu qua my quang ph, ta s thu c quang ph vch hp th .

    iu kin c quang ph vch hp th l: nhit ca ngun sng phi ln hn nhit ca m kh.Tnh cht:- Quang ph vch hp th ph thuc vo bn cht ca kh hp th. Mi cht kh hp th c mt quang ph

    vch hp th c trng.- Trong quang ph vch c s o sc nh sau: mi nguyn t ho hc ch hp th nhng bc x no m

    n c kh nng pht x, v ngc li, n ch pht bc x no m n c kh nng hp th.Phn tch quang ph :- Phn tch quang ph l g ?Phn tch quang ph l phng php vt l dng xc nh thnh phn ho hc ca mt hp cht, da vo

    vic nghin cu quang ph ca nh sng do cht pht x hoc hp th .- Php phn tch quang ph c u im nh th no ?o Cho kt qu nhanh, cng mt lc xc nh c s c mt ca nhiu nguyn t.o nhy rt cao, cho php pht hin c hm lng rt nh c trong mu nghin cu.o Cho php nghin cu t xa, nh pht hin thnh phn cu to ca mt tri , cc ngi sao. . . .

    TIA HNG NGOI TIA T NGOI TIA XTia hng ngoi Tia t ngoi.* Pht hin tia hng ngoi v t ngoi

    ngoi quang ph nh sng nhn thy c, c hai u v tm, cn c nhng bc x m mt khngnhn thy, nhng nh mi hn ca cp nhit in (hng ngoi v t ngoi) v bt hunh quang (t ngoi) m ta

    pht hin c. Cc bc x gi l tia hng ngoi v tia t ngoi.Tia hng ngoi v tia t ngoi c cng bn cht vi nh sng.Tia hng ngoi v tia t ngoi cng tun theo cc nh lut: truyn thng, phn x, khc x, v cng gy

    c hin tng nhiu x, giao thoa nh nh sng thng thng.* Tia hng ngoi+ Cc bc x khng nhn thy c bc sng di hn 0,76 m n khong vi milimt c gi l tia hng

    ngoi.+ Mi vt c nhit cao hn nhit mi trng u pht ra tia hng ngoi. C th ngi pht ra tia hng

    ngoi c bc sng t 9 m tr ln. Ngun pht tia hng ngoi thng dng l l than, l in, n in dy tc.+ Tnh cht:- Tnh cht ni bt nht ca tia hng ngoi l tc dng nhit: vt hp th tia hng ngoi s nng ln.- Tia hng ngoi c kh nng gy ra mt s phn ng ha hc, c th tc dng ln mt s loi phim nh,

    nh loi phim hng ngoi dng chp nh ban m.- Tia hng ngoi c th iu bin c nh sng in t cao tn.- Tia hng ngoi c th gy ra hiu ng quang in trong mt s cht bn dn.+ ng dng:- Tia hng ngoi dng sy kh, si m.- S dng tia hng ngoi chp nh b mt Tri t t v tinh.- Tia hng ngoi c dng trong cc b iu khin t xa iu khin hot ng ca tivi, thit b nghe,

    nhn,

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    - Tia hng ngoi c nhiu ng dng a dng trong lnh vc qun s: Tn la t ng tm mc tiu da votia hng ngoi do mc tiu pht ra; camera hng ngoi dng chp nh, quay phim ban m; ng nhm hngngoi quan st ban m.

    * Tia t ngoi+ Cc bc x khng nhn thy c bc sng ngn hn 0,38 m n c vi nanmt c gi l tia t ngoi.+ Ngun pht: Nhng vt c nung nng n nhit cao (trn 20000C) u pht tia t ngoi. Ngun pht

    tia t ngoi ph bin hn c l n hi thy ngn v h quang in.+ Tnh cht:

    - Tc dng mnh ln phim nh, lm ion ha khng kh v nhiu cht kh khc.- Kch thch s pht quang ca nhiu cht, c th gy mt s phn ng quang ha v phn ng ha hc.- C mt s tc dng sinh l: hy dit t bo da, lm da rm nng, lm hi mt, dit khun, dit nm mc, - C th gy ra hin tng quang in.- B nc, thy tinh hp th rt mnh nhng li c th truyn qua c thch anh.+ S hp th tia t ngoi:

    Thy tinh hp th mnh cc tia t ngoi. Thch anh, nc v khng kh u trong sut vi cc tia cbc sng trn 200 nm, v hp th mnh cc tia c bc sng ngn hn.

    Tng zn hp th hu ht cc tia c bc sng di 300 nm v l tm o gip bo v cho ngi vsinh vt trn mt t khi tc dng hy dit ca cc tia t ngoi ca Mt Tri.

    + ng dng: Thng dng kh trng nc, thc phm v dng c y t, dng cha bnh (nh bnh cixng), tm vt nt trn b mt kim loi,

    Tia X Thang sng in t.* Tia X: Tia X l nhng sng in t c bc sng t 10 -11 m n 10-8 m.* Cch to ra tia X: Cho mt chm tia catt tc l mt chm electron c nng lng ln p vo mt

    vt rn th vt pht ra tia X.C th dng ng Rn-ghen hoc ng Cu-lt-d to ra tia X.

    * Tnh cht ca tia X:+ Tnh cht ng ch ca tia X l kh nng m xuyn. Tia X xuyn qua c giy, vi, g, thm ch c

    kim loi na. Tia X d dng i xuyn qua tm nhm dy vi cm, nhng li b lp ch vi mm chn li. Do ngi ta thng dng ch lm cc mn chn tia X. Tia X c bc sng cng ngn th kh nng m xuyncng ln; ta ni n cng cng.

    + Tia X c tc dng mnh ln phim nh, lm ion ha khng kh.+ Tia X c tc dng lm pht quang nhiu cht.+ Tia X c th gy ra hin tng quang in hu ht kim loi.+ Tia X c tc dng sinh l mnh: hy dit t bo, dit vi khun, * Cng dng ca tia X:

    Tia X c s dng nhiu nht chiu in, chp in, chn on hoc tm ch xng gy, mnhkim loi trong ngi, cha bnh (cha ung th). N cn c dng trong cng nghip kim tra chtlng cc vt c, tm cc vt nt, cc bt kh bn trong cc vt bng kim loi; kim tra hnh l ca hnhkhch i my bay, nghin cu cu trc vt rn...

    * Thang sng in t:Gi thuyt ca Mc xoen: nh sng l sng in t c bc sng rt ngn so vi sng v tuyn , lan

    truyn trong khng gian ( Tc l nh c bn cht sng )

    Mi lin h gia tnh cht in t vi tnh cht quang ca mi trng: =

    v

    chay =n

    Trong : l hng s in mi, ph thuc vo tn s f ca nh sng; l t thm .- Sng v tuyn, tia hng ngoi, nh sng nhn thy, tia t ngoi, tia X, tia gamma u c bn cht l sng

    in t. Chng c cch thu, pht khc nhau, c nhng tnh cht rt khc nhau v gia chng khng c ranh giir rt.

    - Nhng sng in t c bc sng di th d quan st hin tng giao thoa, bc sng cng ngn th tnhm xuyn cng mnh .

    - Thang sng in t c sp xp v phn loi theo th t bc sng gim dn t tri qua phi

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    Min sng in t Bc sng (m) Tn s (Hz)

    Sng v tuyn in 4 43.10 10 4 1210 3.10 Tia hng ngoai 3 710 7,6.10 11 143.10 4.10

    nh sng nhn thy 7 77, 6.10 3,8.10 14 144.10 8.10 Tia t ngoi 7 93,8.10 10 14 178.10 3.10 Tia X 8 1110 10 16 193.10 3.10 Tia gamma Di 10-11 Trn 3.1019

    41 0 21 0 1 21 0 41 0 61 0 81 0 1 01 0 1 21 0 1 41 0 ( m )

    P h n g p h a p v o t u y e nP h n g p h a p c h u p a n h

    P h n g p h a p q u a n g i e n

    P h n g p h a p n h i e t i e n

    P h n g p h a p i o n h o aT h a n g s o n g i e n t v a c a c h t h u , p h a t

    Songvotuyenien

    M a y p h a tv o t u y e n i e n

    Tiahongngoai

    0

    V a tn o n gd i

    5 0 0 C

    Anhsangnhnthay

    C a cn g u o ns a n g

    Tiatngoai

    0

    V a tn o n gt r e n

    2 0 0 0 C

    TiaX

    O n gt i aX

    Tiagamma

    S p h a n

    r a p h o n g x a

    T h u

    P h a t

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    CH V PHNG PHP GIgI TON

    Phn 1: Tn sc nh sn

    Ch 1: Tn sc nh sng qua lng knh- Tnh gc lch gia tia - tia tm trong tn sc nh sng qua lng knh.- Tnh b rng quang ph thu c trn mn.Phng php gii- Khc x nh sng:ni .sini = nr.sinr.

    - Phn x ton phn: sinigh =1

    2

    n

    n; vi n1 > n2.

    - Cc cng thc lng knh:- sini1 = n sinr1- sini2 = n sinr2- A = r1 + r2- D = i1 + i2 A+ Trng hp i v A nh: i1 = nr1; i2 = nr2: D = (n 1)A

    + Gc lch cc tiu:

    Dmin1 2

    min 1

    1 2

    22

    Ar r

    D i Ai i

    = = =

    =

    - Tnh gc lch gia tia - tia tm trong tn sc nh sng qua lng knh.Nu gc chit quang A b (A < 100), ta c: D = (n 1)A; Dt = (nt 1)A D = Dt D = (nt n)ANu gc ln (A > 100, i1, i2 ln) ta tnh D theo cng thc D = i1 + i2 A cho tng bc x ri tnh gc lch.- Tnh b rng quang ph thu c trn mn.+ Cch 1: p dng cng thc gn ng: tan D = x/L x+ Cch 2: tan D = x/L x, tan Dt = xt/L xt. x = xt x.Ch : Chit sut ca khi cht trong sut i vi cc nh sng n sc khc nhau l khc nhau v ln

    nht i vi tia tm, nh nht i vi tia . Tch s gia .n = hng s = c.TCh 2: Tn sc nh sng qua mt nc, bn mt song song- Tnh gc lch gia tia - tia tm trong tn sc nh sng qua mt nc.- Tnh b rng quang ph thu c trn y b.

    Phng php gii-p dng nh lut khc x nh sng: sini = n r.sinr cho tia v tia

    tm, ta c:sini = n.sinr rsini = nt.sinrt rt

    Gc lch: D = r rt-B rng quang ph thu c trn y b:

    tanr = x/h; tanrt = xt/h x = x xt.

    - Nu tia ti vung gc vi b mt phn cch th khng c hintng tn sc .

    Ch 3: Tn sc nh sng qua thu knh- Xc nh v tr tiu im ca tia , tia tm, .- Tnh khong cch t tiu im tia n tiu im tia tm khi cho chm sng trng qua thu knh

    Phng php gii

    - p dng cng thc thu knh:D = =f

    1(n -1)

    +

    21

    11

    RR. (n l chit sut ca cht lm thu knh

    i vi mi trng t thu knh v R1, R2 l bn knh cc mt cong vi qui c mt li R > 0, lmR < 0, phng R = 0 ).

    L

    Tm

    DDtD

    x

    x

    xt

    D

    i

    r

    rt

    tm

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    nh sng tr ng

    Quang trc chnh FO Ft tm

    ft

    xf

    - Nu bit n ta c th tnh c f tng ng v tm c khong cch t tiu im tia n tiu imtia tm nh yu cu bi ton.

    i vi mu :

    +=

    21

    11)1(

    1

    RRn

    f

    i vi mu tm :

    +=

    21

    11)1(1RR

    nf tt

    => Khong cch gia hai tiu im v tm l: tt ffFFx ==

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    Phn 2: Giao thoa nh sn

    Ch 1: Kho st hin tng giao thoa.- Kho st hin tng giao thoa vi hai khe Young.- Thit lp biu thc xc nh v tr vn sng, vn ti. Tnh khong vn.- t h vn trong mi trng chit sut n. Tnh khong vn mi.

    Phng php gii- Gi khong cch t khe S nhai khe S1, S2 ln lt l d1 v d2.

    - Chiu qua khe sng S nh sngn sc. Hai khe S1, S2 nhn sng tkhe S gi n nn tha mn iu kinkt hp. Kt qu l trn mn E cnhng im m hai sng nh sngcng pha, tng cng ln nhau v tothnh vn sng, nhng im hai sngnh sng ngc pha trit tiu ln nhauv to thnh vn ti.

    - kho st tnh cht ca mt im M bt k trn mn, ta xt hiu ng i (cn gi l quang trnh) catia sng theo hai ng i SS1M v SS2M:

    ( ) ( )/ /2 2 1 1 2 1d d d d d d = + + =

    Ta c: ( ) ( )

    22 22

    2 22 1 2 1 2 12

    2 21

    ad D x

    2d d 2xa d d d d 2xa

    ad D x

    2

    = + +

    = + = = +

    Nu x rt b so vi D (x thng c tnh c mm cn D c tnh c m), ta c th tnh gn ng:

    2 1d d 2D+ = 2 1xa

    d d

    D

    = =

    - Nu M l vn sng: 2 1 Sxa Dd d k x k kiD a

    = = = = = vi i l khong vn:D

    ia

    = .

    o Vi k = 0 x = 0: Vn trung tm l vn sng.o Vi k = 1, 2, l cc vn sng bc 1, bc 2,

    - Nu M l vn ti: 2 1 Txa 1 1 D 1d d k x k k iD 2 2 a 2 = = = + = + = +

    o Vi k = 0; -1: vn ti bc 1 (vn ti th nht cnh vn trung tm): xT1 = 0,5i.o Vi k = 1, -2: vn ti bc 2: xT2 = 1,5i.

    - Nu t c h vn trong mi trng chit sut n, vi a v D khng i th bc sng v khong vn gim

    i n ln so vi bc sng v khong vn trong chn khng , tc l:

    n

    =' ;

    n

    ii =' .

    M2M

    S1 d1 xd2

    S a I OD

    S2E

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    Ch 2: Giao thoa vi nh sng trng.- M t hin tng giao thoa vi nh sng trng.- Xc nh b rng quang ph bc 1, bc 2, , bc n.- Xc nh phn giao nhau ca cc quang ph bc 2, 3; rng khe en gia quang ph bc 1 2.- Xc nh s bc x v bc sng ca tng bc x cho vn sng, vn ti ti M ta x.

    Phng php gii- M t hin tng: Nu thay nh sng n sc trong th nghim Young bng nh sng trng th trn mn

    ta thu c vn trung tm l vn sng trng, hai bn l di sng ging nh cu vng, mu tm trong , mu

    ngoi. Hin tng trn c gii thch l do trong nh sng trng c v s cc bc x n sc, mi bcx cho mt h vn giao thoa ring. S chng chp ca cc h vn hnh thnh nn cc di mu quang ph.- B rng quang ph bc 1 c tnh t xT1 n xDD1, tng t nh th cho b rng quang ph bc 2, 3,

    o B rng quang ph bc 1: ( )d t1 d1 t1 d tDx x x i ia

    = = =

    o B rng quang ph bc 2: ( )d t2 d2 t2 1Dx x x 2 2xa = = = o B rng quang ph bc 3: ( )d t3 d3 t3 1Dx x x 3 3xa

    = = =

    o rng khe en gia vn sng trng trung tm vi QPB1: x t1 = ito rng khe en gia QPB1 vi QPB2: ( )t d1 t2 d1 2 Dx x x a

    = =

    o Phn giao nhau gia QPB2 v QPB3: ( )d t2 d2 t3 2 3 Dx x x a

    = =

    - Ti mt im M c ta x trn mn.o Nhng bc x cho vn sng ti M tha mn iu kin:

    Dx k a

    = vi

    [ ]0,38 m 0,76 m (ty bi ton c th cho khong ny khc nhau, nu khng choth mc nh l khong ny)

    Cch 1: Thay vo, ta c cc gi tr k tng ng. ng vi mi gi tr ca k th sc mt bc x cho vn sng M v tnh gi tr cc bc x :

    xak k

    D=

    Cch 2: Thay cc s nguyn lin tip k vo biu thc, k no cho thuc khong binthin ca n th nhn v nhn lun gi tr tng ng:

    xa

    kD =

    o Nhng bc x cho vn ti (b tt, b thiu) ti M tha mn iu kin: 1 Dx k2 a

    = +

    ri gii

    tng t trng hp trn tm .

    Ch 3: Cho b rng min giao thoa, xc inh s vn sng, vn ti trong min giao thoa.Phng php gii- Tng t trng hp giao thoa sng c khi hai ngun cng pha, ta c th tnh c s vn sng, vn ti

    trong min giao thoa khi bit b rng min giao thoa L:L

    k b2i

    = + viD

    ia

    =

    o Vn sng: 2k + 1 (1 y l k thm vn sng trung tm)o Vn ti: ( )

    ( )

    2k b 0,5

    2k 2 b 0,5

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    Ch 4: Bi ton dch chuyn khe S, m rng khe S.- Dch chuyn khe S theo phng song song vi mt phng cha hai khe. Hi h vn dch chuyn theo

    chiu no? Dch chuyn mt on bng bao nhiu?- M rng khe S sao cho h vn bin mt. Gii bi ton trong trng hp ch m rng v mt pha v m

    rng v c hai pha.

    Phng php gii- Dch chuyn khe S theo phng song song vi mt phng cha hai khe. Hi h vn dch chuyn theo

    chiu no? Dch chuyn mt on bng bao nhiu?- Khi dch chuyn khe S mt on y theo phng song song vi mt phng cha hai khe th h vn (vntrung tm O) dch chuyn ngc chiu vi chiu dch chuyn ca khe S sao cho S, I, O thng hng. dch

    chuyn c tnh theo cng thc:y x

    xd D

    =

    - Trc khi dch chuyn: ( ) ( )/ /2 2 1 1 2 1 xad d d d d d D = + + = = . Ti v tr vn trung tm, x = 0.- Sau khi dch chuyn, vn trung tm di n v tr mi (hay h vn dch chuyn mt on x).

    ( ) ( ) ( ) ( )/ / / /2 2 1 1 2 1 2 1xa ya

    ' d d d d d d d dD d

    = + + = + = +

    - Ti v tr mi ca vn trung tm: xa ya x y' 0D d D d

    = = = . Du tr chng t x v y ngc du

    hay h vn dch chuyn ngc chiu vi chiu dch chuyn ca ngun v t l theo h s tam gic ng dng.- Ch rng, khi ta dch chuyn khe S th vn sng trung tm dch chuyn t O n M sao cho S, I v O

    lun thng hng. Bi ton c th cho x dng h vn dch chuyn bao nhiu khong vn; vn sng chim chvn ti lin k, vn tung tm by gi l vn ti;

    - M rng khe S sao cho h vn bin mt. Gii bi ton trong trng hp ch m rng v mt pha v mrng v c hai pha.

    - Nu ta khng dch chuyn khe S m m rng khe S ra, th O vn l vn sng, ng thi rng cavn sng tng ln dn cho n M. Nu rng ny ln th n c th chim ch lun ca vn ti lin k vin, khi , trn mn c chiu sng hon ton v h vn bin mt. V vy, rng khe S nh nht khi mtvn sng c th chim ch mt vn ti lin k trc n hay x = 0,5i, t ta c th tnh c rng khe S.Cn ch thm rng, y ta tnh trong trng hp ny ch xt m rng v mt pha, nu m rng v hai pha(c trn c di) th mi pha nh nht cng phi bng y nn rng khe S trong trng hp ny l 2i.

    M2M

    S1 d1 xS d2

    y a I O

    d DS2

    E

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    Ch 5: t trc mt trong hai khe mt bn mt song song, hi h vn dch chuyn theo chiu no vdch chuyn mt on bng bao nhiu.

    Phng php giiKhi c bn mng (bn mt song song) b dy e

    v chit sut n trc khe S1, vn sng trung tm tiO s di n v tr O cng chiu vi khe c t bnmt nh hnh v bn. Vi di:

    a

    DenxOO

    .).1('

    0

    ==

    - Gi thi gian nh sng i trong bn mt songsong chit sut n l t (vn tc tng ng l v).

    t = e / v- Vi thi gian ny, nh sng i trong khng kh

    c qung ng tng ng: s = c.t = n.v.t = ne- xt v tr vn trung tm, ta xt hiu quang trnh trc v sau khi t bn mt song song.

    o Trc khi t bn mt song song: 2 1 xad d D = = .o Sau khi t bn mt song song: ( ) ( )/ /2 1 2 1 xa' d d d d e ne n 1 eD = = + = o V tr mi ca vn trung tm khi ( ) ( )n 1 eDxa' 0 n 1 e x

    D a = = =

    Ch 6: Bi ton trng vn.- Xc nh v tr trng vn trong trng hp giao thoa vi 2 bc x, 3 bc x. Xc nh bc v bc sng

    tng ng.- Tnh khong trng vn vi 2 bc x, 3 bc x.- Cho b rng min giao thoa. Xc nh s vn trng (c mu ging vi mu vn trung tm), s vn ng

    vi tng loi bc x, s vn khc mu, s vn (c cng mu v khc mu).

    Phng php gii- Nu chiu vo khe sng S ng

    thi cc bc x c bc sng 1, 2,... th trn mn s xut hin cc hthng vn ng vi cc bc x . Docc h thng vn xp xen nhau trnmn nn s c nhng v tr m cc hthng vn u cho vn sng (gingm nh vn trung tm) hoc vn ti,hin tng ny gi l s trng vn.

    - Ti v tr trng vn, xt cho vn sng ta c: x = k1i1 = k2i2 = k3i3 = ...o Xt cho hai bc x: x = k1i1 = k2i2 1 2 2

    2 1 1

    k i

    k i

    = =

    . Ta rt gn n ti gin phn s trn ta c

    th tm c cc gi tr tng ng ca k1 v k2. l bc ca cc bc x trng nhau. Khongtrng vn c xc nh bng khong cch gia hai vn trng lin tip hay khong cch tvn trng th nht n vn trung tm.

    o Xt cho ba bc x, ta tnh ring cho tng cp bc x ri tnh c v tr vn trng.

    x = k1i1 = k2i2 = k3i3

    1 2 2

    2 1 1

    3 32

    3 2 2

    k i

    k i

    ik '

    k ' i

    = =

    = =

    Ly bi chung nh nht ca k2 v k2 ri tm c k1, k3 ri tnh c khong trng vn.

    O(e,n) d1

    x0S1 d2a O

    S2 D

    M2M

    S1 d1 xd2

    S a I OD

    S2E

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    - Cho b rng min giao thoa l L, ta c th tnh c s vn trng nh cch tnh s vn sng, nhng thayv tnh cho khong vn th ta tnh cho khong trng vn:

    Lk b

    2 i= +

    vi i l khong trng vn.

    - Ch :Nu hi tnh s vn c mu khc nhau, s vn sng ca bc x mu no th nh ch ncc vn trng, khi tnh s vn sng chng ta s loi bt cc vn trng nhau.

    V d: Trong th nghim giao thoa nh sng bng khe Young. nh sng s dng gm 3 bc x , lc,lam c bc sng ln lt l: 1 = 0,64m, 2 = 0,54m, 3 = 0,48m.

    a. Vn sng u tin k t vn sng trung tm c cng mu vi vn sng trung tm ng vi vn sngbc my ca vn sng mu lc?

    b. Cho b rng min giao thoa l L = 8cm, D = 2m, a = 1mm. Tnh khong trng vn ca - lam; c ba bc x. Tnh s vn sng. S vn c mu ging mu vn trung tm S vn trng nhau ca - lam S vn mu

    Gii:

    - Ta c:

    11 2 2

    22 1 1

    23 32

    33 2 2

    k 27k i 0,54 27

    k 32k i 0,64 32

    k ' 8ik ' 0, 48 8

    k ' 9k ' i 0,54 9

    == = = = =

    =

    = = = = =

    Bi chung nh nht ca k2 v k2 l 32. T ta c th khng nh: Vn sng trng mu vi vn trung tm lvn bc 32 ca nh sng lc, bc 27 ca nh sng v bc 36 ca nh sng lam.- Khong trung vn - lam: Ta c vn th 3 ca nh sng trng vi th 4 ca nh sng lam nn

    i13 = 3i1 = 3.1,28 = 1,84mmi = 32i2 = 32.1,08 = 34,56mm

    - Tnh s vn sng trong na min giao thoaBc x : L/2i1 = 80/2.1,28 = 31,25 n1 = 31.Bc x lc: L/2i2 = 80/2.1,08 = 37,04 n2 = 37.Bc x lam: L/2i3 = 80/2.1,96 = 41,67 n3 = 41.

    - S vn trng cp 2 (trng nhau ca c ba bc x): L/2i = 80/2.34,56 = 1,56 n = 1- S vn trng cp 1 (trng nhau ca hai bc x):

    o - lc n12: L/2i12 = 80/2.34,56 = 1,56 n12 = 1 n12 = n12 n = 0o - lam n13: L/2i13 = 80/2.1,84 = 21,74 n13 = 21 n13 = n13 n = 20o Lc - lam n23: L/2i23 = 80/2.8,64 = 4,69 n23 = 4 n23 = n23 n = 3

    S vn sng trong na MGT: n = (n1 + n2 + n3 ) - (n1 + n2 + n3 ) 2.n = 84S vn sng trong c MGT: 2n + 1 = 169 vn

    - S vn sng c mu : 2(n1 n12 - n13 ) = 42- S vn sng c mu ging mu vn trung tm (k c vn trung tm): 2. n + 1 = 3

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    Ch 7: Giao thoa vi cc dng c khc: Tnh khong cch 2 nh a v b rng min giao thoa L- Lng gng phng.- Lng lng knh Fresnel.- Lng thu knh Billet.

    Phng php gii- Giao thoa bi lng lng knh Fresnel ( gc chit quang nh) :

    d d

    D

    - Giao thoa bi hai na thu knh hi t (bn thu knh Billet) :

    - Giao thoa bi lng gng phng .

    Cc i lng tng ng vigiao thoa bng 2 khe Y-ng vkin thc thng dng : a = S1S2 = 2d (n-1)A Gc lch gia tia ti v tia l:

    D = (n -1)A B rng ca min giao thoa:

    L = 2d(n-1)A

    EL1

    S1 M1 P1O1

    S O H IO

    O2

    S2 M2 P2L2D

    d dL

    Cc i lng tng ng vi giao thoa bng 2khe Y-ng v kin thc thng dng :

    a = S1S2 = 1.'O

    d

    dd+O2 .

    D = HO = L (d + d) = OO- d. trn mn E thu c h vn th mn phit cch thu knh mt khong ln hn OI, tc

    l D HI. Khi D = HI th trn mn ch c 1vn sng ti I . Cng thc thu knh dng xc nh d:

    '

    111

    ddf+=

    fd

    fdd

    =

    .'

    B rng ca min giao thoa:

    L = O1O2 (1+'d D

    d

    +)

    Cc i lng tng ng vi giao thoa

    bng 2 khe Y-ng v kin thc thng dng: a = S1S2 = 2.HS1= 2.SI sin() D = HO = HI + IO = IS.cos() + IO . Ngun sng S v cc nh S1 , S2 nmtrn ng trn bn knh IS .

    (IS =IS1=IS2)Khi lm bi cn s dng tam gic ng

    dng xc nh cc khong cchB rng min giao thoa:

    L = 2.IO.tan()

    G1 S M

    S12

    H OI

    S2

    G2 N

    D

    S1

    S2I

    M

    N

    OS

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    BI TP TN SC GIAO THOA NH SNG

    thi mn 12 Song anh sang - Tan sac tap 1(M 242)

    Cu 1 : Mt nh sng n sc c bc sng ca n trong khng kh l 0,7 .m v trong cht lng trong sut

    l 0,56 .m Chit sut ca cht lng i vi nh sng l:A. 1,5. B. 1,25. C. 2 . D. 3 .

    Cu 2 : Mt tia sng trng chiu vung gc ti mt bn ca mt lng knh c gc chit quang A = 6 0. Chitsut ca lng knh i vi tia v tm ln lt l n = 1,64; nt = 1,68. Sau lng knh t mt mn Msong song vi mt bn ca lng knh cch n L=1,2m. Chiu di quang ph thu c trn mn l:

    A. 5cm. B. 5mm. C. 12,6mm. D. 12,6cm.Cu 3 : Cho mt thu knh hi t c hai mt li ging nhau bn knh 10cm, chit sut ca thu tinh lm thu

    knh i vi tia v tia tm ln lt l 1,60 v 1,69. cho tiu im ng vi cc tia mu tm trngvi tiu im ng vi cc tia mu ngi ta ghp st vi thu knh hi t ni trn mt thu knh

    phn k c hai mt ging nhau v cng c bn knh l 10cm, nhng thu knh phn k ny lm bngmt loi thy tinh khc. H thc lin h gia chit sut ca thu knh phn k i vi nh sng tmv nh sng l :

    A. n = nt + 0,09 B. nt = n + 0,09 C. nt = n + 0,9 D. n = nt + 0,9Cu 4 : Mt lng knh c tit din thng l 1 tam gic u ABC. Chiu 1 chm tia sng trng hp vo mt

    bn AB i t y ln. Chit sut ca lng knh i vi nh sng l 2 v i vi nh sng tm

    l 3 Gi s lc u lng knh v tr m gc lch D ca tia tm l cc tiu, hi phi quay lng knh1 gc bng bao nhiu gc lch ca tia cc tiu?

    A. 450. B. 300. C. 150. D. 600.Cu 5 : Mt lng knh c gc chit quang l 600. Chit sut ca lng knh i vi nh sng l 1,5. Khi

    chiu tia ti lng knh vi gc ti 600 th gc lch ca tia qua lng knh l:A. Dd = 18,07 B. Dd = 48,59 C. Dd =38,88 D. Dd = 24,74

    Cu 6 : Mt sng nh sng n sc c t trng nht l:A. vn tc truyn B. chit sut lng knh vi nh sng .

    C. mu sc D. tn sCu 7 : Pht biu no sau y l ng?

    A. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c nhiu mu khi chiu xin v c mu trng khi chiu vung gc.

    B. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c nhiu mu d chiu xin hay chiu vung gc.

    C. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c mu trng d chiu xin hay chiu vung gc.

    D. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c nhiu mu khi chiu vung gc v c mu trng khi chiu xin.

    Cu 8 : nh sng lam c bc sng trong chn khng v trong nc ln lt l 0,4861 m v 0,3635m.Chit sut tuyt i ca nc i vi nh sng lam l:

    A. 1,3373 B. 1,3335 C. 1,3725 D. 1,3301Cu 9 : Chiu mt chm tia sng trng hp ti mt bn ca lng knh c gc chit quang A = 60 0. Bit chit

    sut ca lng knh i vi nh sng tm l 1,54. Gc lch cc tiu ca tia mu tm bng:A. 51,30 B. 49,460 C. 40,710 D. 30,430

    Cu 10 : nh sng trng qua lng knh thy tinh b tn sc, nh sng mu b lch t hn nh sng mu tm, l v:

    A. Chit sut ca thy tinh i vi nh sng nh hn nh sng tm.B. Vn tc nh sng trong thy tinh ln hn so vi nh sng tm.C. Tn s ca nh sng ln hn tn s ca nh sng tm.D. nh sng trng bao gm v s nh sng mu n sc c mt s tn s khc nhau v do chit sut

    ca thy tinh i vi sng nh sng c tn s nh th nh hn so vi sng nh sng c tn s ln

    hn.

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    Cu 11 : nh sng c bc sng trong chn khng l 0,6563m, chit sut ca nc i vi nh sng l 1,3311. Trong nc nh sng c bc sng:

    A. 0,4226m B. 0,4549m C. 0,4931m D. 0,4415mCu 12 : Mt bc x n sc c tn s f = 4,4.1014HZ khi truyn trong nc c bc sng 0,5m th chit

    sut ca nc i vi bc x trn l:A. n = 0,733 B. n = 1,32 C. n = 1,36 D. n = 1,43

    Cu 13 : Mt lng knh thy tinh c gc chit quang A = 50, chit sut i vi tia tm l nt = 1,6852. Chiuvo lng knh mt tia sng trng di gc ti nh, hai tia l tm v vng hp vi nhau 1 gc

    0,0030rad. Ly 1 = 3.10-4

    rad. Chit sut ca lng knh i vi tia vng:A. 1,6519 B. 1,5941 C. 1,4763 D. 1,6518

    Cu 14 : Pht biu no sau y l sai khi ni v nh sng trng v nh sng n sc ?A. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.B. Khi cc nh sng n sc i qua mt mi trng trong sut th chit sut ca mi trng i vi nh

    sng l nh nht, i vi nh sng tm l ln nht.C. nh sng trng l tp hp v s cc nh sng n sc khc nhau c mu bin thin lin tc t n

    tm.D. Chit sut ca cht lm lng knh l ging nhau i vi cc nh sng n sc khc nhau.

    Cu 15 : Chiu mt tia sng trng vo mt bn ca mt lng knh c tit din thng l tam gic u sao cho tia

    tm c gc lch cc tiu. Chit sut ca lng knh i vi tia tm l n t = 3 . cho tia c gc

    lch cc tiu th gc ti phi gim 15

    0

    . Chit sut ca lng knh i vi tia :A. 1,4142 B. 1,4355 C. 1,4792 D. 1,5361Cu 16 : Tm pht biu ng v nh sng n sc.

    A. i vi cc mi trng khc nhau , nh sng n sc lun c cng bc sngB. i vi nh sng n sc , gc lch ca tia sng i vi lng knh khc nhau u c cng gi tr.C. n sng n sc l nh sng khng b lch ng truyn khi i qua lng knh .D. nh sng n sc l nh sng khng b tch mu khi i qua lng knh.

    Cu 17 : Tm pht biu ng v nh sng n sc:A. nh sng n sc l nh sng khng b tch mu khi qua lng knh.B. i vi cc mi trng khc nhau, nh sng n sc lun c cng bc sng.C. i vi nh sng n sc, gc lch ca tia sng i vi cc lng knh khc nhau u c cng gi tr.D. nh sng n sc l nh sng khng b lch ng truyn khi i qua lng knh.

    Cu 18 : Mi lin h gia tnh cht in t v tnh cht quang ca mi trng c biu hin bng cng thcno sau y? Vi c l tc nh sng trong chn khng, v l tc nh sng trong mi trng chng s in mi v t thm .

    A.c

    v= B. =

    c

    v C.

    1c

    v = D.

    v

    c=

    Cu 19 : Trong mt th nghim o bc sng nh sng thu c mt kt qu = 0,526m. nh sng dngtrong th nghim l nh sng mu :

    A. B. vng C. tm D. lcCu 20 : Mt lng knh c gc chit quang A = 50, chiu mt chm tia ti song song hp mu lc vo cnh

    bn ca lng knh theo phng vung gc vi mt phn gic ca gc A sao cho mt phn ca chmtia sng khng i qua lng knh v mt phn qua lng knh. Bit chit sut ca lng knh i vi nh

    sng mu lc n = 1,55. Khi i, A b th gc lch D ca tia sng qua lng knh l:A. 3,090. B. 3,220 C. 2,750. D. 2,860.Cu 21 : Mt lng knh thu tinh c A = 450. Chiu chm tia sng hp a sc SI gm tp hp 4 tia , cam,

    lc, tm n gp mt bn AB theo phng vung gc, th c nhng tia no l ra khi mt AC?. Bit

    chit sut ca thu tinh i vi nh sng mu vng l 2 .A. , cam, lc B. C. , cam D. , cam, lc, tm

    Cu 22 : Nguyn nhn gy ra hin tng tn sc nh sng mt tri trong th nghim ca Niutn l:A. chit sut ca lng knh i vi cc nh sng n sc l khc nhau.B. chm nh sng mt tri b nhiu x khi i qua lng knh.C. gc chit quang ca lng knh trong th nghim cha ln.D. b mt ca lng knh trong th nghim khng nhn.

    Cu 23 : Khi mt chm nh sng n sc truyn t mi trng c chit sut n 1 = 1,6 vo mi trng c chit

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    sut n2 = 4/3 th:A. Tn s khng i, bc sng tng B. Tn s gim, bc sng tngC. Tn s khng i, bc sng gim D. Tn s tng, bc sng gim

    Cu 24 : Pht biu no sau y l ng?A. nh sng n sc l nh sng b tn sc khi i qua lng knh.B. nh sng trng l hn hp ca v s nh sng n sc c mu bin thin lin tc t n tm.C. Ch c nh sng trng mi b tn sc khi truyn qua lng knh.D. Tng hp nh sng n sc s lun c nh sng trng.

    Cu 25 : Pht biu no sau y l khng ng?A. Khi chiu mt chm nh sng mt tri i qua mt cp hai mi trng trong sut th tia tm b lch vpha mt phn cch hai mi trng nhiu hn tia .

    B. nh sng n sc khng b tn sc khi i qua lng knh.C. Chit sut ca cht lm lng knh i vi cc nh sng n sc l khc nhau.D. nh sng trng l tp hp ca v s cc nh sng n sc c mu bin i lin tc t n tm.

    Cu 26 : iu no sau y l sai khi ni v nh sng n sc ?A. i lng c trng cho sng nh sng n sc l tn sB. i lng c trng cho sng nh sng n sc l bc sng trong chn khngC. i lng c trng cho sng nh sng n sc l bc sngD. Vn tc ca sng nh sng n sc ph thuc chit sut ca mi trng trong sut nh sng truyn

    qua

    Cu 27 : Pht biu no sau y l sai khi ni v nh sng n sc?A. Trong cng mt mi trng truyn, vn tc nh sng tm nh hn vn tc nh sng .B. Chit sut ca mt mi trng trong sut i vi nh sng ln hn chit sut ca mi trng

    i vi nh sng tm.C. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.D. Trong chn khng, cc nh sng n sc khc nhau truyn i vi cng vn tc.

    Cu 28 : Chiu t nc ra khng kh mt chm tia sng song song rt hp (coi nh mt tia sng) gm 5 thnhphn n sc: tm, lam, , lc, vng. Tia l n sc mu lc i l l mt nc (st vi mt phncch gia hai mi trng). Khng k tia n sc mu lc, cc tia l ra ngoi khng kh l cc tia nsc mu:

    A. lam, tm. B. , vng. C. tm, lam, . D. , vng, lam.Cu 29 : Mt thu knh hi t c hai mt li c bn knh ging nhau 20cm. Chit sut ca nh sng v tm

    i vi thu knh l: nd = 1,5, nt = 1,54. Khi khong cch t tiu im i vi tia v tia tm l:A. 19,8cm B. 0,148cm. C. 1,48cm. D. 1,48m.

    Cu 30 : T khng kh ngi ta chiu xin ti mt nc nm ngang mt chm tia sng hp song song gmhai nh sng n sc: mu vng, mu chm. Khi chm tia khc x

    A. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chmmu vng nh hn gc khc x ca chm mu chm.

    B. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chmmu vng ln hn gc khc x ca chm mu chm.

    C. vn ch l mt chm tia sng hp song song.D. ch l chm tia mu vng cn chm tia mu chm b phn x ton phn.

    Cu 31 : nh sng n sc c tn s 5.1014 Hz truyn trong chn khng vi bc sng 600 nm. Chit sut

    tuyt i ca mt mi trng trong sut ng vi nh sng ny l 1,52. Tn s ca nh sng trn khitruyn trong mi trng trong sut nyA. ln hn 5.1014 Hz cn bc sng nh hn 600 nm.B. vn bng 5.1014 Hz cn bc sng nh hn 600 nm.C. nh hn 5.1014 Hz cn bc sng bng 600 nm.D. vn bng 5.1014 Hz cn bc sng ln hn 600 nm.

    Cu 32 : Trong cc pht biu sau y, pht biu no l sai?A. nh sng trng l tng hp (hn hp) ca nhiu nh sng n sc c mu bin thin lin tc t

    ti tm.B. nh sng do Mt Tri pht ra l nh sng n sc v n c mu trng.C. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.D. Hin tng chm sng trng, khi i qua mt lng knh, b tch ra thnh nhiu chm sng c mu sc

    khc nhau l hin tng tn sc nh sng.

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    Cu 33 : Tm pht biu sai v hin tng tn sc:A. Th nghim ca Newton v tn sc nh sng chng t lng knh l nguyn nhn ca hin tng tn

    sc.B. Tn sc l hin tng mt chm nh sng trng hp b tch thnh nhiu chm sng n sc khc

    nhau.C. Nguyn nhn ca hin tng tn sc l do chit sut ca cc mi trng i vi cc nh sng n

    sc khc nhau th khc nhau.D. Hin tng tn sc chng t nh sng trng l tp hp v s cc nh sng n sc khc nhau.

    Cu 34 : Chn cu sai trong cc cu sau:A. Mi nh sng n sc khc nhau c mu sc nht nh khc nhau.B. nh sng n sc l nh sng khng b tn sc khi qua lng knh.C. Lng knh c kh nng lm tn sc nh sng.D. nh sng trng l tp hp ca 7 nh sng n sc , cam, vng, lc, lam, chm, tm.

    Cu 35 : Chiu mt chm tia sng trng song song, hp vo mt bn ca mt lng knh c gc chit quang A= 60 theo phng vung gc vi mt phn gic ca gc chit quang. Chit sut ca lng knh i vitia l n = 1,50, i vi tia tm l nt = 1,54. Ly 1 = 3.10

    -4rad. Trn mn t song song v cchmt phn gic trn 1 on 2m, ta thu c gii mu rng:

    A. 8,64mm B. 8,46mm C. 6,36mm D. 5,45mmCu 36 : Trong cc yu t sau y: I. Bn cht mi trng truyn ; II. Mu sc nh sng; III. Cng nh

    sng. Nhng yu t no nh hng n vn tc truyn ca nh sng n sc ?

    A. II, III. B. I, II, III. C. I, III. D. I, II.Cu 37 : Mt thu knh hi t gm 2 mt cu li ging nhau bn knh R = 30cm. Chit sut ca thu knh i

    vi nh sng l 1,5 v i vi nh sng tm l 1,54. Khong cch gia tiu im i vi tia vtiu im i vi tia tm ca thu knh l:

    A. 30cm. B. 22,2cm. C. 2,22cm. D. 27,78cm.Cu 38 : Mt lng knh c gc chit quang A = 60. Chiu chm nh sng trng vo mt bn ca lng knh

    theo phng vung gc vi mt phng phn gic ca gc chit quang ti 1 im rt gn A. Chm tial c chiu vo 1 mn nh t song song vi mt phng phn gic ni trn v cch mt phng ny1 khong 2m. Chit sut ca lng knh i vi nh sng l 1,5 v i vi nh sng tm l 1,54. Brng quang ph trn mn l:

    A. 11,4mm B. 4mm C. 8,38mm D. 6,5mm.Cu 39 : Pht biu no sau y l sai khi ni v nh sng trng v nh sng n sc:

    A. nh sng trng l tp hp ca v s cc nh sng n sc khc nhau c mu bin thin lin tc t n tm.

    B. nh sng n sc l nh sng khng b tn sc khi i qua lng knhC. Khi cc nh sng n sc i qua mt mi trng trong sut th chit sut ca mi trng i vi nh sng

    l nh nht, i vi nh sng tm l ln nht.D. Chit sut ca cht lm lng knh l ging nhau i vi cc nh sng n sc khc nhau.

    Cu 40 : Chiu xin mt chm sng hp gm hai nh sng n sc l vng v lam t khng kh ti mt ncth

    A. chm sng b phn x ton phn.B. so vi phng tia ti, tia khc x vng b lch t hn tia khc x lam.C. tia khc x ch l nh sng vng, cn tia sng lam b phn x ton phn.

    D. so vi phng tia ti, tia khc x lam b lch t hn tia khc x vng.Cu 41 : Mt bc x n sc c tn s f = 4,4.1014HZ th khi truyn trong khng kh s c bc sng l:A. = 0,6818m. B. = 0,6818m. C. = 13,2m. D. = 0,6818. 10-7m

    Cu 42 : Trong mt th nghim ngi ta chiu mt chm nh sng n sc song song hp vo cnh ca mtlng knh c gc chit quang A = 80 theo phng vung gc vi mt phng phn gic ca gc chitquang. t mt mn nh E song song v cch mt phng phn gic ca gc chit quang 1m. Trnmn E ta thu c hai vt sng. S dng nh sng vng, chit sut ca lng knh l 1,65 th gc lchca tia sng l:

    A. 5,20 B. 7,80 C. 6,30 D. 4,00Cu 43 : Mt lng knh c gc chit quang A = 60. Chiu 1 tia sng trng ti mt bn ca lng knh vi gc

    ti nh. Chit sut ca lng knh i vi nh sng l 1,5 v i vi nh sng tm l 1,54. Gc hpbi tia l mu v mu tm l:

    A. 3,240

    . B. 30

    . C. 0,240

    . D. 6,240

    .

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    Cu 44 : Mt sng nh sng n sc c c trng nht l :A. vn tc truyn. B. mu sc.C. chit sut lng knh vi nh sng . D. tn s.

    Cu 45 : Chiu mt tia sng trng vo mt bn ca mt lng knh c gc chit quang A = 60 0 sao cho gc

    lch ca tia tm l cc tiu. Chit sut ca lng knh i vi tia tm l n t = 1,732 3 . Gc lch cctiu ca tia tm:

    A. 600 B. 1350 C. 1200 D. 750Cu 46 : Chn cu ng:Chiu mt chm tia sng hp qua mt lng knh. Chm tia sng s tch thnh chm

    tia sng c mu khc nhau. Hin tng ny gi l:A. Giao thoa nh sng B. Nhiu x nh sng.C. Khc x nh sng D. Tn sc nh sng

    Cu 47 : iu no sau y l ng khi ni v nh sng n sc ?A. Chit sut ca cht lm lng knh khng ph thuc tn s ca sng nh sng n scB. Chit sut ca cht lm lng knh i vi nh sng mu nh hn i vi nh sng mu lcC. Trong nc vn tc nh sng mu tm ln hn vn tc ca nh sng mu .D. Sng nh sng c tn s cng ln th vn tc truyn trong mi trng trong sut cng nh

    Cu 48 : Mt b nc su 1,2m. Mt chm nh sng mt tri chiu vo mt nc di gc ti i sao cho sini =0,8. Chit sut ca nc i vi nh sng l 1,331 v i vi nh sng tm l 1,343. B rng cadi quang ph di y b l:

    A. 2,5cm. B. 2cm. C. 1,25cm. D. 1,5cm.Cu 49 : Mt tia sng i qua lng knh l ra ch mt mu duy nht khng phi mu trng th l:

    A. Lng knh khng c kh nng tn sc. B. nh sng a sc.C. nh sng b tn sc D. nh sng n sc

    Cu 50 : Mt thu knh hi t mng, c 2 mt cu ging nhau bn knh 20cm. Chit sut ca thu knh ivi nh sng l n = 1,50; i vi nh sng tm l nt = 1,54. Khong cch gia tiu im i vitia v tiu im i vi tia tm:

    A. 1,481cm B. 1,482cm C. 1,96cm D. 1,50cmCu 51 : Chit sut ca mi trng th nht i vi mt nh sng n sc l n 1 = 1,4 v chit sut t i ca

    mi trng th hai i vi mi trng th nht l n21 = 1,5. Vn tc ca nh sng n sc trongmi trng th hai l:

    A. 2,14.108 m/s B. 1,43.108 m/s C. 2,68.108 m/s D. 4,29.108 m/s

    Cu 52 : iu no sau y l ng khi ni v nh sng n sc ?A. Vn tc ca nh sng n sc trong chn khng ph thuc bc sng nh sngB. Tn s ca nh sng n sc ph thuc mi trng truynC. Trong cng mt mi trng trong sut vn tc ca nh sng mu nh hn vn tc nh sng mu

    tmD. Vn tc ca nh sng n sc ph thuc vo mi trng truyn

    Cu 53 : Chn cu ng trong cc cu sau:A. Sng nh sng c phng dao ng dc theo phng truyn nh sng.B. Vn tc nh sng trong mi trng cng ln nu chit sut ca mi trng ln.C. ng vi mi nh sng n sc, bc sng khng ph thuc vo chit sut ca mi trng nh sng

    truyn quaD. ng vi mi nh sng n sc, sng nh sng c mt chu k nht nh.

    Cu 54 : Pht biu no sau y l sai khi ni v nh sng trng v nh sng n sc?A. Chit sut ca cht lm lng knh l ging nhau i vi cc nh sng n sc khc nhau.B. Khi cc nh sng n sc i qua mt mi trng trong sut th chit sut ca mi trng i vi nh

    sng l nh nht, i vi nh sng tm l ln nht.C. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.D. nh sng trng l tp hp ca v s cc nh sng n sc khc nhau c mu bin thin lin tc t

    n tm.Cu 55 : Mt thu knh mng hi t bng thy tinh c chit sut i vi tia l n = 1,5145, i vi tia tm

    l nt = 1,5318. T s gia tiu c ca thu i vi tia v tiu c i vi tia tm l:A. 1,0336 B. 1,0597 C. 1,1057 D. 1,2809

    Cu 56 : Mt lng knh thy tinh c gc chit quang A = 40, t trong khng kh. Chit sut ca lng knh ivi nh sng v tm ln lt l 1,643 v 1,685. Chiu mt chm tia sng song song, hp gm hai

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    bc x v tm vo mt bn ca lng knh theo phng vung gc vi mt ny. Gc to bi tia v tia tm sau khi l ra khi mt bn kia ca lng knh xp x bng

    A. 1,4160. B. 0,1680. C. 0,3360. D. 13,3120.Cu 57 : Chn cu sai:

    A. i lng t trng cho nh sng n sc l tn s.B. Chit sut ca cht lm lng knh i vi nh sng nh hn i vi nh sng mu lcC. Sng nh sng c tn s cng ln th vn tc truyn trong mi trng trong sut cng nh.D. Vn tc ca nh sng n sc khng ph thuc vo mi trng truyn.

    Cu 58 : Khi cho nh sng truyn t mi trng trong sut ny sang mi trng trong sut khc thA. tn s khng i v vn tc khng i B. tn s thay i v vn tc khng iC. tn s khng i v vn tc thay i D. tn s thay i v vn tc thay i

    Cu 59 : Th nghim vi nh sng n sc ca Niu-tn nhm chng minhA. lng knh khng lm thay i mu sc ca nh sng qua n.B. s tn ti ca nh sng n sc.C. nh sng Mt Tri khng phi l nh sng n sc.D. nh sng c bt k mu g, khi qua lng knh cng b lch v pha y.

    Cu 60 : Pht biu no sau y l khng ng?A. nh sng trng l tp hp ca v s cc nh sng n sc c mu bin thin i lin tc t n

    tm.B. Chit sut ca cht lm lng knh i vi cc nh sng n sc l khc nhau.

    C. nh sng n sc khng b tn sc khi i qua lng knh.D. Khi chiu mt chm nh sng mt tri i qua mt cp hai mi trng trong sut th tia tm b lch v pha

    mt phn cch hai mi trng nhiu hn tia .Cu 61 : Tim pht biu sai v hin tng tn sc:

    A. Tn sc l hin tng mt chm nh sng trng hp b tch thnh nhiu chm sng n sc khcnhau

    B. Hin tng tn sc chng t nh sng trng l tp hp v s cc nh sng n sc khc nhau.C. Th nghim ca Newton v tn sc nh sng chng t lng knh l nguyn nhn ca hin tng tn

    sc.D. Nguyn nhn ca hin tng tn sc l do chit sut ca cc mi trng i vi cc nh sng n

    sc khcCu 62 : Bc sng ca nh sng trong khng kh l 0,75 .m Bc sng ca n trong nc l bao nhiu?

    Bit chit sut ca nc i vi nh sng l 4/3.A. 0,632 .m B. 0,563 .m C. 0,445 .m D. 0,546 .m

    Cu 63 : Pht biu no sau y l khng ng? Cho cc chm nh sng sau: Trng, , vng, tm.A. Mi chm nh sng trn u c mt bc sng xc nh.B. Chiu nh sng trng vo my quang ph s thu c quang ph lin tc.C. nh sng trng b tn sc khi i qua lng knh.D. nh sng tm b lch v pha y lng knh nhiu nht nn chit sut ca lng knh i vi n ln

    nht.Cu 64 : Chiu nh sng trng do mt ngun nng sng pht ra vo khe hp F ca mt my quang ph lng

    knh th trn tm knh nh (hoc tm knh m) ca bung nh s thu cA. nh sng trng

    B. mt di t n tm ni lin nhau mt cch lin tc.C. cc vch mu sng, ti xen k nhau.D. by vch sng t n tm, ngn cch nhau bng nhng khong ti.

    Cu 65 : Chit sut ca mi trng l 1,65 khi nh sng chiu vo c bc sng 0,5 m. Vn tc truyn v tns ca sng nh sng l:

    A. v = 1,82.106m/s. f = 3,64.1012Hz. B. v = 1,28.108m/s. f = 3,46.1014Hz.C. v = 1,82.108m/s. f = 3,64.1014Hz. D. v = 1,28.106m/s. f = 3,46.1012Hz.

    Cu 66 : Mt lng knh c gc chit quang A = 60, chit sut ca lng knh i vi tia l n = 1,6444 v ivi tia tm l nt = 1,6852, Chiu tia sng trng ti mt bn ca lng knh di gc ti nh. Gc lchgia tia l mu v tia l mu tm:

    A. 0,0044 rad B. 0,0055 rad C. 0,0011 rad D. 0,0025 radCu 67 : Chiu mt chm sng trng song song hp, coi nh mt tia sng vo mt b nc di gc ti 60 0.

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    Chiu su ca b nc l 1m. Di y b c mt gng phng t song song vi mt nc. Chitsut ca nc i vi nh sng tm l 1,34 v i vi nh sng l 1,33. Chiu rng ca di muthu c chm sng l ra khi mt nc l:

    A. L 0,008m. B. L 0,009m. C. L 0,006m. D. L 0,09m.Cu 68 : Bc sng ca mt trong cc bc x mu lc l

    A. 0,55mm B. 0,40m C. 0,55m D. 0,75mCu 69 : Mt lng knh c gc chit quang A = 60 (coi l gc nh) c t trong khng kh. Chiu mt chm

    nh sng trng song song, hp vo mt bn ca lng knh theo phng vung gc vi mt phng

    phn gic ca gc chit quang, rt gn cnh ca lng knh. t mt mn E sau lng knh, vung gcvi phng ca chm tia ti v cch mt phng phn gic ca gc chit quang 1,2 m. Chit sut calng knh i vi nh sng l 1,642 v i vi nh sng tm l 1,685. rng t mu n mutm ca quang ph lin tc quan st c trn mn l

    A. 10,1mm. B. 5,4mm. C. 36,9mm. D. 4,5mm.Cu 70 : Mt lng knh c gc chit quang A= 60, chit sut ca lng knh i vi tia 6444,1=dn v i

    vi tia tm l 6852,1=tn . Chiu tia sng trng ti mt bn ca lng knh di gc ti nh. Gc lchgia tia l mu v tia l mu tm:

    A. 0,0011 rad B. 0,0025 rad C. 0,0043 rad D. 0,00152 rad

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    phiu soi - p n (Dnh cho gim kho)Mn : 12 Song anh sang - Tan sac tap 1

    M : 242

    01 { ) } ~ 28 { ) } ~ 55 ) | } ~

    02 { ) } ~ 29 { | ) ~ 56 { ) } ~

    03 { ) } ~ 30 { ) } ~ 57 { | } )

    04 { | ) ~ 31 { ) } ~ 58 { | ) ~

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    06 { | } ) 33 ) | } ~ 60 { | } )

    07 ) | } ~ 34 { | } ) 61 { | } )

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    09 { | ) ~ 36 { | } ) 63 ) | } ~

    10 { | } ) 37 { | ) ~ 64 { ) } ~

    11 { | ) ~ 38 { | ) ~ 65 { | ) ~

    12 { | ) ~ 39 { | } ) 66 ) | } ~

    13 ) | } ~ 40 { ) } ~ 67 { ) } ~14 { | } ) 41 { ) } ~ 68 { | ) ~

    15 ) | } ~ 42 ) | } ~ 69 { ) } ~

    16 { | } ) 43 { | ) ~ 70 { | ) ~

    17 ) | } ~ 44 { | } )

    18 { ) } ~ 45 ) | } ~

    19 { | } ) 46 { | } )

    20 { | ) ~ 47 { | } )

    21 { | ) ~ 48 { | ) ~

    22 ) | } ~ 49 { | } )

    23 ) | } ~ 50 ) | } ~24 { ) } ~ 51 { ) } ~

    25 ) | } ~ 52 { | } )

    26 { | ) ~ 53 { | } )

    27 { ) } ~ 54 ) | } ~

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    thi mn 12 Song anh sang - Tan sac tap 2(M 243)

    Cu 1 : Chiu mt chm tia sng hp qua mt lng knh. Chm tia l ra khi lng knh c nhiu mu sckhc nhau. Hin tng l:

    A. Tn sc nh sng B. Giao thoa nh sngC. Nhiu x nh sng D. Khc x nh sng

    Cu 2 : Bc sng ca bc x da cam trong chn khng l 600nm th tn s ca bc x lA. 5.1013Hz. B. 5.1015Hz. C. 5.1014Hz. D. 5.1012Hz.

    Cu 3 : Hy chn cu ng. Khi sng nh sng truyn t mt mi trng ny sang mt mi trng khc thA. c tn s v bc sng u khng i. B. c tn s ln bc sng u thay i.C. tn s khng i, nhng bc sng thay i. D. bc sng khng i, nhng tn s khng i.

    Cu 4 : Hin tng giao thoa nh sng ch quan st c khi hai ngun nh sng l hai ngun:

    A. Kt hp B. n sc C. Cng mu sc D.Cng cng sng.

    Cu 5 : T hin tng tn sc v giao thoa nh sng, kt lun no sau y l ng khi ni v chit sut camt mi trng?

    A. Chit sut ca mi trng ln i vi nhng nh sng c bc sng ngn.

    B. Chit sut ca mi trng ln i vi nhng nh sng c bc sng di.C. Chit sut ca mi trng nh khi mi trng c nhiu nh sng truyn qua.D. Chit sut ca mi trng nh nhau i vi mi nh sng n sc.

    Cu 6 : T khng kh ngi ta chiu xin ti mt nc nm ngang mt chm tia sng hp song song gmhai nh sng n sc: mu vng, mu chm. Khi chm tia khc x

    A. vn ch l mt chm tia sng hp song song.B. ch l chm tia mu vng cn chm tia mu chm b phn x ton phn.C. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chm

    mu vng nh hn gc khc x ca chm mu chm.D. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chm

    mu vng ln hn gc khc x ca chm mu chm.Cu 7 : Mt lng knh thu tinh c gc chit quang A = 80. Chit sut ca thu tinh lm lng knh i vi

    nh sng mu v nh sng mu tm ln lt l n = 1,6444 v nt = 1,6852. Chiu mt chm nhsng trng rt hp, coi nh mt tia sng, vo mt bn ca lnh knh theo phng vung gc vi mt. Gc to bi tia l mu v mu tm l

    A. 0,057rad. B. 0,0057rad. C. 0,57rad. D. 0,0075rad.Cu 8 : Chiu mt tia sng trng ti vung gc vi mt bn ca mt lng knh c gc chit quang A = 4 0.

    Chit sut ca lng knh i vi nh sng v nh sng tm ln lt l n = 1,643 v nt = 1,685.Gc gia cc tia l mu v mu tm l

    A. 1,66rad. B. 3,92.10-3rad. C. 2,93.103 rad. D. 2,93.10-3rad.Cu 9 : Hy chn cu ng. Khi mt chm sng n sc truyn t khng kh vo trong thu tinh th

    A. tn s tng, bc sng gim. B. tn s khng i, bc sng gim.C. tn s gim, bc sng tng. D. tn s khng i, bc sng tng.

    Cu 10 : Mt thu knh hi t c hai mt cu, bn knh cng bng 20cm. Chit sut ca thu knh i vi tia

    tm l 1,69 v i vi tia l 1,60, t thu knh trong khng kh. bin thin t ca thuknh i tia v tia tm l

    A. 0,46dp. B. 64,1dp. C. 46,1dp. D. 0,9dp.Cu 11 : Pht biu no sau y l ng khi ni v chit sut ca mt mi trng:

    A. Chit sut ca mt mi trng trong sut nht nh i vi mi nh sng n sc khc nhau l khcnhau

    B. Chit sut ca mt mi trng trong sut khc nhau i vi mt loi nh sng nht nh th c gi trnh nhau

    C. Chit sut ca mt mi trng trong sut nht nh i vi mi nh sng n sc l nh nhauD. Vi bc sng nh sng chiu qua mi trng trong sut cng di th chit sut ca mi trng cng

    lnCu 12 : iu no sau y l sai khi ni v nh sng n sc?

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    A. Cc nh sng n sc khc nhau c th c cng gi tr bc sngB. i lng c trng cho nh sng n sc l bc sngC. Cc nh sng n sc ch c cng vn tc trong chn khngD. i lng c trng cho nh sng n sc l tn s

    Cu 13 : Trong chm nh sng trng cA. by loi nh sng mu l: , cam, vng, lc, lam, chm, tm.B. ba loi nh sng n sc thuc mu , lc, lam.C. v s cc nh sng n sc khc nhau.

    D. mt loi nh sng mu trng duy nht.Cu 14 : Khi cho mt chm nh sng trng truyn ti mt thu knh theo phng song song vi trc chnh

    ca thu knh th sau thu knh, trn trc chnh, gn thu knh nht s l im hi t ca:A. nh sng mu tm B. nh sng c mu trung gian gia v tm.C. nh sng mu . D. nh sng mu trng.

    Cu 15 : Chn cu pht biu ng:A. Tiu c ca mt thu knh ph thuc vo mu sc nh sng chiu n thu knh .B. Chit sut ca mi trng trong sut nht nh i vi i vi mi nh sng n sc khc nhau c gi tr nh nhau.

    C. Khi nh sng i vo cc mi trng khc nhau th bc sng khc nhau nn c mu sc khc nhau.

    D. nh sng c bc sng cng di chiu qua mi trng trong sut th chit sut ca mi trng cng ln.Cu 16 : Ti sao khi i qua lp knh ca s, nh sng trng khng b tn sc thnh cc mu c bn ?

    A. V nh sng trng ngoi tri l nhng sng khng kt hp, nn chng khng b tn sc.B. V do kt qu ca tn sc, cc tia sng mu i qua lp knh v l ra ngoi di dng nhng chm tia

    chng cht ln nhau, tng hp tr li thnh nh sng trng.C. V knh ca s l loi thu tinh khng tn sc nh sng.D. V knh ca s khng phi l lng knh nn khng tn sc nh sng.

    Cu 17 : Chn cu pht biu khng ng:A. Chit sut ca mt mi trng trong sut c gi tr khc nhau i vi nh sng n sc khc nhau.B. Cc nh sng n sc khi i qua lng knh ch b lch phng truyn m khng b tn sc.C. nh sng mu b tn sc khi qua lng knh v bin thnh nh sng mu tm.D. Trong th nghim tn sc nh sng, chm nh sng mu tm b lch nhiu nht.

    Cu 18 : Chit sut ca nc i vi nh sng (d

    = 0,759 m ) l 1,239; i vi nh sng tm (t

    =

    0,405 m ) l 1,343. Chit sut ca nc i vi nh sng xanh( x = 0,500 m ) bngA. 1,236. B. 1,293. C. 1,336. D. 1,326.

    Cu 19 : Tn sc nh sng l hin tngA. c trng ca lng knh thu tinh.B. chung cho mi mi trng trong sut, tr chn khng.C. chung cho mi cht rn, cht lng trong sut.D. chung cho mi mi trng trong sut, k c chn khng.

    Cu 20 : Chiu mt chm tia sng mu vng vo mt bn ca mt lng knh c gc chit quang A= 9 0 digc ti nh. Tc ca tia mu vng trong lng knh l 1,85.10 8 m/s; tc nh sng trong chnkhng c= 3.108m/s. Gc lch ca tia l l:

    A. 5,5946rad B. 0,4116rad C. 0,2538rad D. 0,0976radCu 21 : Pht biu no sau y l sai khi ni v nh sng trng v nh sng n sc.

    A. Chit sut ca cht lm lng knh i vi nh sng n sc khc nhau c tr s nh nhau.B. Khi nh sng n sc i qua mt mi trng trong sut th chit sut ca mi trng i vi nh sng l

    nh nht, i vi nh sng tm l ln nht.C. nh sng trng l tp hp ca v s nh sng n sc c mu bin thin lin tc t n tm.D. nh sng n sc l nh sng khng b tn sc khi qua lng knh.

    Cu 22 : Pht biu no sau y l ng khi cho nh sng trng chiu vo my quang ph?A. Chm tia sng l ra khi lng knh cu my quang ph trc khi i qua thu knh ca bung nh gm

    nhiu chm tia sng song song.B. Chm tia sng l ra khi lng knh ca my quang ph trc khi i qua thu knh ca bung nh l mt

    chm tia sng mu song song.C. Chm tia sng l ra khi lng knh ca my quang ph trc khi i qua thu knh ca bung nh l mt

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    chm tia phn k mu trng.D. Chm tia sng l ra khi lng knh ca my quang ph trc khi i thu knh ca bung nh l mt chm

    tia phn k c nhiu mu khc nhau.Cu 23 : Chn cu sai:

    A. nh sng trng l tp hp gm 7 nh sng n sc:, cam, vng, lc, lam, chm, tmB. Vn tc ca nh sng ty thuc mi trng trong sut m nh sng truyn qua.C. nh sng n sc l nh sng khng b tn sc khi qua lng knh.D. Dy cu vng l quang ph ca nh sng trng.

    Cu 24 : Mt nh sng n sc c tn s dao ng l 5.1013

    Hz, khi truyn trong mt mi trng c bc sngl 600nm. Tc nh sng trong mi trng bngA. 3.108m/s. B. 3.106m/s. C. 3.107m/s. D. 3.105m/s.

    Cu 25 : Mt lng knh thy tinh c gc chit quang A = 70, chit sut ca lng knh i vi tia tm l nt =1,6042. Chiu vo lng knh mt tia sng trng di gc ti nh, gc lch gia tia l mu v tiatm l D = 0,0045rad. Chit sut ca lng knh i vi nh sng mu l:

    A. n = 1,5872 B. n = 1,6005 C. n = 1,5798 D. n = 1,5672Cu 26 : Mt tia sng trng chiu ti bn hai mt song song vi gc ti 60 0. Bit chit sut ca bn mt i

    vi tia tm l nt = 1,732; i vi tia l n = 1,700. B dy bn mt l e = 2cm. rng ca chmtia khi l ra khi bn mt bng

    A. 0,024cm. B. 0,014cm. C. 0,034cm. D. 0,044cm.Cu 27 : Mt sng in t n sc c tn s 60 GHz th c bc sng trong chn khng l

    A. 5cm. B. 50 m . C. 5mm. D. 500 m .Cu 28 : Hin tng tn sc xy ra khi cho chm nh sng trng hp i qua lng knh ch yu l v

    A. nh sng trng l tp hp ca nhiu nh sng khc nhau.B. chit sut ca thu tinh ph thuc vo mu sc ca nh sng.C. thu tinh nhum mu cho nh sng trng.D. xy ra hin tng giao thoa.

    Cu 29 : Pht biu no sau y l ng?A. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b nc

    to nn y b mt vt sng c nhiu mu khi chiu xin .B. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b nc

    to nn y b mt vt sng c mu trng d chiu xin hay chiu vung gc.

    C.Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c nhiu mu d chiu xin hay chiu vung gc.

    D. Mt chm nh sng mt tri c dng mt di sng mng, hp ri xung mt nc trong mt b ncto nn y b mt vt sng c nhiu mu khi chiu vung gc v c mu trng chiu xin.

    Cu 30 : Mt ngun sng S pht ra hai bc x m4,01 = v m6,02 = , ti trc chnh ca mt thu knh.Bit chit sut ca thu tinh lm thu knh thay i theo bc sng ca nh sng theo quy lut:

    2

    0096,055,1n

    += ( tnh ra m ). Vi bc x 1 th thu knh c tiu c f1 = 50cm. Tiu c ca

    thu knh ng vi bc sng 2 lA. 0,35m. B. 0,53m. C. 0,50m. D. 0,53cm.

    Cu 31 : Chn cu tr li khng ng:A. i lng c trng cho nh sng n sc l tn s.B. Tc ca nh sng n sc khng ph thuc mi trng truyn.C. Chit sut ca cht lm lng knh i vi nh sng nh hn i vi nh sng lc.D. Sng nh sng c tn s cng ln th tc truyn trong mi trng trong sut cng nh.

    Cu 32 : Hin tng tn sc nh sng xy raA. ch vi lng knh thu tinh.B. ch vi cc lng knh cht rn hoc cht lng.C. mt phn cch hai mi trng chit quang khc nhau.D. mt phn cch mt mi trng rn hoc lng, vi chn khng(hoc khng kh).

    Cu 33 : Chit sut tuyt i ca mi trng trong sut i vi mt tia sng:A. Thay i theo mu ca tia sng v tng dn t mu n mu tm.B. Khng ph thuc mu sc nh sng.

    C. Thay i theo mu ca tia sng, nhng c gi tr ln nht, nh nht i vi nhng tia sng mu g th

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    tu theo bn cht ca mi trng.D. Thay i theo mu ca tia sng v tng dn t mu tm n mu .

    Cu 34 : Mt thu knh thu tinh, c hai mt cu li ging nhau, bn knh mi mt bng 20cm. Chit sut cathu knh i vi tia l n = 1,50 v i vi tia tm l nt = 1,54. Khong cch gia tiu im ivi tia v tiu im i vi tia tm bng bao nhiu ?

    A. 1,60cm. B. 1,49cm. C. 1,25cm. D. 2,45cm.Cu 35 : Chn cu sai trong cc cu sau:

    A. Chit sut ca mt mi trng trong sut nht nh i vi nh sng c bc sng di th ln hn i vi nh

    sng c bc sng ngnB. Mu quang ph l mu ca nh sng n scC. nh sng n sc l nh sng c bc sng nht nhD. Chit sut ca mt mi trng trong sut nht nh ph thuc vo bc sng ca nh sng n sc

    Cu 36 : Trong mt th nghim ngi ta chiu mt chm nh sng n sc song song hp vo cnh ca mtlng knh c gc chit quang A=8o. t mt mn nh E song song v cch mt phng phn gic cagc chit quang 1 m. Trn mn E ta thu c hai vt sng. S dng nh sng vng, chit sut calng knh l 1,65 th gc lch ca tia sng l

    A. 5,20 B. 7,80 C. 4,00 D. 6,30Cu 37 : Gi D, f, Dt, ft ln lt l t v tiu c ca cng mt thu knh thu tinh i vi nh sng v

    nh sng tm, do n < nt nnA. D = Dt. B. D > Dt. C. f > ft. D. f < ft.

    Cu 38 : Trong mt th nghim o bc sng nh sng thu c mt kt qu m526,0 = . nh sng dngtrong th nghim l

    A. nh sng mu lc. B. nh sng mu tm.C. nh sng mu vng. D. nh sng mu .

    Cu 39 : Khi truyn qua lng knh, chm nh sng trng sA. b bin thnh nh sng mu . B. b lch phng truyn v tch ra thnh nhiu

    mu.C. ch b tch ra thnh nhiu mu. D. ch b lch phng truyn.

    Cu 40 : Khi chiu chm nh sng trng hp vo mt lng knh th chm sng mu tm b lch nhiu nht.Nguyn nhn l do

    A. nh sng tm l mu cui cng trong quang ph ca nh sng trng.B. nh sng tm b ht v ph y lng knh mnh hn so vi cc mu khc.C. chit sut ca cht lm lng knh i vi nh sng tm c gi tr ln nht.D. chit sut ca cht lm lng knh i vi nh sng tm c gi tr nh nht.

    Cu 41 : Chn cu sai trong cc cu sau:A. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.B. nh sng trng l tp hp ca 7 nh sng n sc: , cam, vng, lc, lam, chm, tm.C. Lng knh c kh nng lm tn sc nh sng.D. Mi nh sng n sc khc nhau c mu sc nht nh khc nhau.

    Cu 42 : Mt ci b su 1,5m cha y nc. Mt tia sng Mt Tri ri vo mt nc b di gc ti i, ctani = 4/3. Bit chit sut ca nc i vi nh sng v nh sng tm ln lt l n = 1,328 v nt =1,343. B rng ca quang ph do tia sng to ra y b bng:

    A. 14,64mm. B. 12,86mm. C. 16,99mm. D. 19,66mm.

    Cu 43 : Mt sng nh sng n sc c c trng nht lA. tc truyn nh sng. B. mu sc ca nh sng.C. tn s nh sng. D. chit sut lng knh i vi nh sng .

    Cu 44 : Mt loi thy tinh c chit sut i vi nh sng mu l 1,6444 v chit sut i vi nh sngmu tm l 1,6852. Chiu mt tia sng trng hp t khng kh vo khi thy tinh ny vi gc ti 800th gc khc x ca cc tia lch nhau ln nht mt gc bao nhiu?

    A. 1,030. B. 0,820. C. 0,560. D. 0,950.Cu 45 : T khng kh ngi ta chiu xin ti mt nc nm ngang mt chm tia sng hp song song gm

    hai nh sng n sc: mu vng, mu chm. Khi chm tia khc xA. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chm

    mu vng nh hn gc khc x ca chm mu chm.B. ch l chm tia mu vng cn chm tia mu chm b phn x ton phn.

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    C. vn ch l mt chm tia sng hp song song.D. gm hai chm tia sng hp l chm mu vng v chm mu chm, trong gc khc x ca chm

    mu vng ln hn gc khc x ca chm mu chm.Cu 46 : Gc chit quang ca lng knh bng 80. Chiu mt tia sng trng vo mt bn ca lng knh, theo

    phng vung gc vi mt phng phn gic ca gc chit quang. t mt mn quan st, sau lngknh, song song vi mt phng phn gic ca lng knh v cch mt phn gic ny mt on 1,5m.Chit sut ca lng knh i vi tia l n = 1,50 v i vi tia tm l nt = 1,54. rng ca quang

    ph lin tc trn mn quan st bng

    A. 7,0mm. B. 6,5mm. C. 9,3mm. D. 8,4mm.Cu 47 : Chiu mt chm sng trng song song, hp, coi nh mt tia sng vo mt b nc di gc ti 60 0.

    Chiu su ca b nc l 10cm. Di y b c mt gng phng, t song song vi mt nc.Chit sut ca nc i vi nh sng tm l 1,34 v i vi nh sng l 1,23. Chiu rng ca dimu m ta thu c chm sng l l

    A. 0,009cm. B. 0,009m. C. 0,09m. D. 0,0009m.Cu 48 : Pht biu no sau y l khng ng? Cho cc chm nh sng sau: trng, , vng, tm.

    A. Mi chm nh sng trn u c mt bc sng xc nh.B. nh sng trng b tn sc khi i qua lng knh.C. Chiu nh sng trng vo my vo my quang ph s thu c quang ph lin tc.D. nh sng tm b lch v pha y lng knh nhiu nht nn chit sut ca lng knh i vi n ln

    nht.

    Cu 49 : Mt lng knh c gc chit quang A= 60, chit sut ca lng knh i vi tia n = 1,6145 v ivi tia tm l nt= 1,6623. Thc hin th nghim tn sc vi nh sng trng th gc lch ca tia , gclch ca tia tm, gc lch ca tia mu v tia mu tm ln lt s l:

    A. D = 0,0464rad; Dt = 0,0964rad; D = 0,05rad.B. D = 0,0694rad; Dt = 0,0644rad; D = 0,005rad.C. D = 0,0964rad; Dt = 0,0464rad; D = 0,05rad.D. D = 0,0644rad; Dt = 0,0694rad; D = 0,005rad.

    Cu 50 : Hin tng tn sc nh sng thc cht l hin tngA. i mu ca cc tia sng.B. to thnh chm nh sng trng t s ho trn ca cc chm nh sng n sc.C. chm sng trng b tch thnh nhiu chm n sc khc nhau.D. chm sng trng b mt i mt s mu.

    Cu 51 : Chiu mt chm nh sng trng vo mt bn ca mt lng knh c gc chit quang A= 6 0 theophng vung gc mt phn gic gc chit quang. Trn mn quan st E t song song v cch mtphn gic ca lng knh mt on d= 1,5m ta thu c di mu c b rng l 6mm. Bit chit sutca lng knh i vi nh sng l n = 1,5015. Chit sut ca lng knh i vi nh sng tm s l:

    A. nt = 1,5264 B. nt = 1,5543 C. nt = 1,5168 D. nt = 1,5397Cu 52 : Trong mt th nghim ngi ta chiu mt chm nh sng n sc song song hp vo cnh ca mt

    lng knh c gc chit quang A = 80 theo phng vung gc vi mt phng phn gic ca gc chitquang. S dng nh sng vng, chit sut ca lng knh l 1,65 th gc lch ca tia sng l

    A. 7,80. B. 4,00. C. 6,30. D. 5,20.Cu 53 : Hin tng cu vng c gii thch da vo hin tng no sau y?

    A. Hin tng phn x ton phn. B. Hin tng tn sc nh sng.

    C. Hin tng giao thoa nh sng. D. Hin tng quang in.Cu 54 : Chiu xin mt chm sng hp gm hai nh sng n sc l vng v lam t khng kh ti mt ncth

    A. chm sng b phn x ton phn.B. tia khc x ch l nh sng vng, cn tia sng lam b phn x ton phn.C. so vi phng tia ti, tia khc x lam b lch t hn tia khc x vng.D. so vi phng tia ti, tia khc x vng b lch t hn tia khc x lam.

    Cu 55 : Bc sng ca mt nh sng n sc trong mi trng vt cht chit sut n = 1,6 l 600nm. Bcsng ca n trong nc chit sut n = 4/3 l

    A. 459nm. B. 500nm. C. 720nm. D. 760nm.Cu 56 : Hy chn cu ng. Mt nh sng Mt Tri hp ri xung mt nc trong mt b bi v to y

    b mt vt sng

    A. c mu trng d chiu xin hay chiu vung gc.

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    B. c nhiu mu d chiu xin hay chiu vung gc.C. c nhiu mu khi chiu xin v c mu trng khi chiu vung gc.D. khng c mu d chiu th no.

    Cu 57 : Chiu mt tia sng trng vo mt bn ca mt lng knh c tit din thng l mt tam gic u saocho tia vng t cc tiu. Chit sut ca lng knh i vi tia vng l n v= 1,62. cho tia tm c gclch cc tiu th gc ti phi tng 200. Chit sut ca lng knh i vi tia tm c gi tr bng:

    A. nt = 1,75 B. nt = 1,68 C. nt = 1,86 D. nt = 1,92Cu 58 : Chn cu tr li ng trong cc cu sau:

    A. Sng nh sng c phng dao ng dc theo phng truyn nh sng.B. Tc nh sng trong mi trng cng ln nu chit sut ca mi trng cng ln.C. ng vi mi nh sng n sc, sng nh sng c mt chu k nht nh.D. ng vi nh sng n sc, bc sng khng ph thuc vo chit sut ca mi trng nh sng

    truyn qua.Cu 59 : Hin tng tn sc nh sng, trong th nghim I ca Niu-tn, xy ra do nh sng trng l mt hn

    hp ca nhiu nh sng n sc khc nhau, v doA. lng knh khng t lch cc tiu.B. lng knh lm bng thu tinh.C. chit sut ca mi cht - trong c thu tinh - ph thuc bc sng ca nh sng.D. lng knh c gc chit quang qu ln.

    Cu 60 : S ph thuc ca chit sut vo bc sng

    A. l hin tng c trng ca thu tinh. B. ch xy ra vi cht rn v cht lng.C. xy ra vi mi cht rn, lng hoc kh. D. ch xy ra i vi cht rn.

    Cu 61 : Gi nc, nl, nL, nv ln lt l chit sut ca thu tinh i vi cc tia chm, lam, lc, vng. Sp xp tht no di y l ng ?

    A. nc > nL > nl > nv. B. nc > nl > nL > nv.C. nc < nl < nL < nv. D. nc < nL < nl < nv.

    Cu 62 : Lng knh c gc chit quang A= 600, chit sut ca lng knh i vi nh sng mu vng n v = 1,62;i vi nh sng mu n = 1,59. Khi chiu chm nh sng trng vo lng knh trn th lch catia sng mu v mu vng ng vi gc lch cc tiu ca chng c gi tr bng bao nhiu?

    A. D = 2020. B. D = 2045. C. D = 2038. D. D = 2053.Cu 63 : Pht biu no sau y l sai khi ni v nh sng n sc ?

    A. Trong chn khng, cc nh sng n sc khc nhau truyn i vi cng vn tc.B. nh sng n sc l nh sng khng b tn sc khi i qua lng knh.C. Trong cng mt mi trng truyn, vn tc nh sng tm nh hn vn tc nh sng .D. Chit sut ca mt mi trng trong sut i vi nh sng ln hn chit sut ca mi trng

    i vi nh sng tm.Cu 64 : Cho mt thu knh hi t c hai mt li ging nhau bn knh 10cm, chit sut ca thu tinh lm thu

    knh i vi tia v tia tm ln lt l 1,60 v 1,69. cho tiu im ng vi cc tia mu tm trngvi tiu im ng vi cc tia mu ngi ta ghp st vi thu knh hi t ni trn mt thu knh

    phn k c hai mt ging nhau v cng c bn knh l 20cm, nhng thu knh phn k ny lm bngmt loi thy tinh khc. H thc lin h gia chit sut ca thu knh phn k i vi nh sng tmv nh sng l :

    A. n = nt + 0,09 B. nt = n + 0,09 C. nt = n + 0,18 D. n = nt + 0,18

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    phiu soi - p n (Dnh cho gim kho)Mn : 12 Song anh sang - Tan sac tap 2

    M : 243

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    thi mn 12 Giao thoa Ly thuyet tap 1(M 244)

    Cu 1 : Bc x c bc sng = 0,3 mA. l tia t ngoi. B. thuc vng nh sng nhn thy.C. l tia hng ngoi. D. l tia X.

    Cu 2 : Tia hng ngoi c pht ra

    A. ch bi mi vt c nhit cao hn mi trng xung quanh.B. ch bi cc vt c nung nng(n nhit cao)C. bi cc vt c nhit ln hn 0(K).D. ch bi cc vt c nhit trn 00C.

    Cu 3 : Tia no sau y d quan st hin tng giao thoa nht?

    A.nh sng nhnthy. B.

    Tia hng ngoi. C. Tia X. D. Tia t ngoi.

    Cu 4 : Khi tng dn nhit ca mt dy tc n in, th quang ph ca nh sng do n pht ra thay inh th no sau y?

    A. Sng dn ln, nhng vn by mu cu vng.B. Ban u ch c mu , sau ln lt c thm mu cam, mu vng, cui cng khi nhit cao,

    mi c by mu, ch khng sng thm.

    C. Va sng dn thm, va tri rng dn, t mu , qua cc mu cam, vng, v cui cng, khi nhit cao, mi c by mu.D. Hon ton khng thay i g.

    Cu 5 : iu no sau y ng khi ni v quang ph lin tc ?A. Dng xc nh bc sng nh sng.B. Dng xc nh thnh phn cu to ca cc vt pht sng.C. xc nh nhit ca ngun sng.D. Quang ph lin tc ph thuc vo thnh phn cu to ca ngun sng.

    Cu 6 : Chn th nghim ng dng o bc sng ca nh sng:A. Th nghim giao thoa vi khe Ing. B. Th nghim v nh sng n sc.C. Th nghim tng hp nh sng trng. D. Th nghim tn sc ca Niutn.

    Cu 7 : Quang ph ca cc vt pht ra nh sng sau, quang ph no l quang ph lin tc?

    A. n dy tc nngsng. B.n hi thy ngn. C. n Natri. D. n Hir.

    Cu 8 : Chn cu sai. Tia t ngoiA. lm in ha khng kh. B. khng tc dng ln knh nh.C. gy ra nhng phn ng quang ha. D. kch thch mt s cht pht quang.

    Cu 9 : Chn cu tr li khng ng:A. Tia X khng b lch trong in trng v trong t trng.B. Tia X c pht hin bi nh Bc hc Rnghen.C. Tia X c nng lng ln v c bc sng ln.D. Tia X l sng in t.

    Cu 10 : iu no sau y l khng ng khi ni v quang ph lin lc ?A. Quang ph lin tc ph thuc vo nhit ca ngun sng.B. Quang ph lin tc l nhng vch mu ring bit trn mt nn ti.C. Quang ph lin tc khng ph thuc vo thnh phn cu to ca ngun sng.D. Quang ph lin tc do cc vt rn, nng hoc kh c t khi ln khi b nung nng pht ra.

    Cu 11 : Tia no sau y khng do cc vt b nung nng pht ra ?

    A.nh sng nhnthy.

    B. Tia X. C. Tia hng ngoi. D. Tia t ngoi.

    Cu 12 : Sp xp theo th t gim dn ca tn s cc sng in t sau:A. nh sng nhn thy, tia hng ngoi, tia t ngoi.B. Tia hng ngoi, tia t ngoi, nh sng thy c.C. Tia t ngoi, nh sng thy c, tia hng ngoi.D. nh sng thy c, tia t ngoi, tia hng ngoi.

    Cu 13 :

    C th nhn bit tia X bng

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    A. t bo quang in. B. cc cu trn u ng.C. mn hunh quang. D. chp nh.

    Cu 14 : C th ngi nhit 370C pht ra bc x no trong cc loi bc x sau ?A. Bc x nhn thy. B. Tia hng ngoi. C. Tia t ngoi. D. Tia X.

    Cu 15 : Vch quang ph thc cht lA. nhng vch sng, ti trn cc quang ph.B. thnh phn cu to ca my quang ph.C. bc x n sc, tch ra t nhng chm sng phc tp.

    D. nh tht ca khe my quang ph to bi nhng chm sng n sc.Cu 16 : Khi mt vt hp th nh sng pht ra t mt ngun, th nhit ca vt

    A. bng nhit ca ngun. B. cao hn nhit ca ngun.C. c th c gi tr bt k. D. thp hn nhit ca ngun.

    Cu 17 : Quang ph vch ca cht kh long c s lng vch v v tr cc vchA. ch ph thuc vo bn cht ca cht kh. B. ph thuc vo cch kch thch.C. ph thuc vo p sut. D. ph thuc vo nhit .

    Cu 18 : Bc x c bc sng trong khong t 10 -9m n 3,8.10-7m lA. tia t ngoi. B. tia X. C. tia hng ngoi. D. nh sng nhn thy.

    Cu 19 : Hin tng o sc ca vch quang ph (o vch quang ph) cho php kt lun rngA. trong cng mt iu kin v nhit v p sut, mi cht u hp th v bc x cc nh sng c

    cng bc sng.

    B. cc vch ti xut hin trn nn quang ph lin tc l do giao thoa nh sng.C. nhit xc nh, mt cht ch hp th nhng bc x no m n c kh nng pht x v ngc li,

    n ch pht nhng bc x m n c kh nng hp th.D. trong cng mt iu kin, mt cht ch hp th hoc ch bc x nh sng.

    Cu 20 : Di nh nng mt tri ri vo, mng du trn mt nc thng c mu sc sc s l do hin tng:A. giao thoa. B. khc x. C. nhiu x. D. tn sc.

    Cu 21 : Quang ph hng ngoi ca hi nc c mt vch mu bc sng l 2,8 m . Tn s dao ng casng ny l

    A. 1,7.1015Hz. B. 1,7.1014Hz. C. 1,07.1014Hz. D. 1,7.1013Hz.Cu 22 : Quang ph lin tc ca mt vt

    A. ph thuc c bn cht v nhit . B. khng ph thuc bn cht v nhit .

    C. ch ph thuc vo bn cht ca vt. D. ch ph thuc vo nhit ca vt.Cu 23 : Ngun sng no khng pht ra tia t ngoiA. Mt Tri. B. Cc than hng. C. H quang in. D. n thy ngn.

    Cu 24 : Quang ph lin lc pht ra bi hai vt khc nhau thA. hon ton khc nhau mi nhit . B. hon ton ging nhau mi nhit .C. ging nhau, nu mi vt c mt nhit ph

    hp.D. ging nhau, nu chng c cng nhit .

    Cu 25 : Tia Rnghen cA. cng bn cht vi sng m. B. bc sng ln hn bc sng ca tia hng

    ngoi.C. cng bn cht vi sng v tuyn. D. in tch m.

    Cu 26 : Pht biu no sau y l ng khi ni v quang ph ?

    A. thu c quang ph hp th th nhit ca m kh hay hi hp th phi cao hn nhit cangun sng pht ra quang ph lin tc.B. Quang ph lin tc ca ngun sng no th ph thuc thnh phn cu to ca ngun sng y.C. Quang ph hp th l quang ph ca nh sng do mt vt rn pht ra khi vt c nung nng.D. Mi nguyn t ha hc trng thi kh hay hi nng sng di p sut thp cho mt quang ph vch

    ring, c trng cho nguyn t .Cu 27 : Tia hng ngoi v tia t ngoi

    A. ch c tia hng ngoi lm en knh nh.B. ch c tia hng ngoi c tc dng nhit.C. khng c cc hin tng phn x, khc x, giao thoa.D. u l sng in t nhng c tn s khc nhau.

    Cu 28 : Quang ph do nh sng Mt Tri pht ra l

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    A. quang ph vch pht x. B. quang ph lin tc.C. quang ph vch hp th. D. quang ph vch.

    Cu 29 : Tia hng ngoi, nh sng nhn thy, tia t ngoi, tia X v tia gamma u lA. sng c hc, c bc sng khc nhau. B. sng v tuyn, c bc sng khc nhau.C. sng in t c tn s khc nhau. D. sng nh sng c bc sng ging nhau.

    Cu 30 : Bc x c bc sng trong khong t 10 -9m n 3,8.10-7m lA. tia X. B. nh sng nhn thy. C. tia hng ngoi. D. tia t ngoi.

    Cu 31 : Bc x c bc sng = 1,0 m

    A. l tia hng ngoi. B. l tia t ngoi.C. thuc vng nh sng nhn thy. D. l tia X.

    Cu 32 : Bc x c bc sng = 0,6 mA. thuc vng nh sng nhn thy. B. l tia hng ngoi.C. l tia t ngoi. D. l tia X.

    Cu 33 : Khi mt vt hp th nh sng pht ra t mt ngun, th nhit ca vtA. thp hn nhit ca ngun. B. c th c gi tr bt k.C. cao hn nhit ca ngun. D. bng nhit ca ngun.

    Cu 34 : Vch quang ph thc cht lA. bc x n sc, tch ra t nhng chm sng phc tp.B. nh tht ca khe my quang ph to bi nhng chm sng n sc.C. nhng vch sng, ti trn cc quang ph.D. thnh phn cu to ca my quang ph.

    Cu 35 : Quang ph lin tc ca mt vtA. ch ph thuc vo nhit ca vt. B. ch ph thuc vo bn cht ca vt.C. khng ph thuc bn cht v nhit . D. ph thuc c bn cht v nhit .

    Cu 36 : Tia Rnghen c pht ra trong ng Rnghen l doA. t trng ca dng eleectron chuyn ng t catt sang i catt b thay i mnh khi electron b

    hm t ngt bi i catt.B. pht x electron t i catt.C. i catt b nung nng mnh.D. cc electron nng lng cao xuyn su vo cc lp v bn trong ca nguyn t i catt, tng tc

    vi ht nhn v cc lp v ny.

    Cu 37 : Tc dng ni bt nht ca tia hng ngoi lA. tc dng sinh hc. B. tc dng nhit.C. lm pht quang mt s cht. D. lm in ha khng kh.

    Cu 38 : c im ca quang ph lin tc l:A. khng ph thuc vo thnh phn cu to ca ngun sng.B. c nhiu vch sng ti xen k.C. khng ph thuc vo nhit ngun sng.D. ph thuc vo thnh phn cu to ca ngun sng.

    Cu 39 : Quang ph do nh sng Mt Tri pht ra thu c trn Tri t lA. quang ph vch pht x. B. quang ph vch hp th.C. quang ph lin tc. D. quang ph m.

    Cu 40 : Hin tng o vch quang ph, nhit t ca m hi hp th phi ln c th pht x v so

    vi nhit t0 ca ngun sng trng th:A. t > t0. B. t c gi tr bt k. C. t < t0. D. t = t0.

    Cu 41 : Tia hng ngoi, nh sng nhn thy, tia t ngoi, tia X v tia gamma u lA. sng c hc, c bc sng khc nhau. B. sng nh sng c bc sng ging nhau.C. sng v tuyn, c bc sng khc nhau. D. sng in t c tn s khc nhau.

    Cu 42 : Pht biu no sau y l khng ng khi ni v quang ph vch pht x ?A. Quang ph vch pht x do cc cht kh hay hi p sut thp b kch thch pht sng.B. L mt h thng gm cc vch mu ring r trn mt nn ti.C. Quang ph vch pht x gm nhng vch mu lin tc nm trn nn ti.D. Mi nguyn t ho hc trng thi kh hay hi khi pht sng di p sut thp cho mt quang ph

    vch c trng cho nguyn t .Cu 43 : Bc x hng ngoi l bc x

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    A. c bc sng nh hn 0,4 m. B. n sc, c mu hng.

    C. c bc sng t 0,75 m n 10-3m. D. n sc, khng mu u ca quang ph.Cu 44 : ng nng ca electrn trong ng tia X khi n i catt phn ln

    A. b hp th bi kim loi lm catt. B. lm nng i catt.C. bin thnh nng lng tia X. D. b phn x tr li.

    Cu 45 : Hin tng giao thoa chng t rngA. nh sng c bn cht sng. B. nh sng l sng in t.C. nh sng c th b tn sc. D. nh sng l sng ngang.

    Cu 46 : mt nhit nht nh mt cht:A. bc x n sc, m n c th hp thu hay pht ra, ph thuc vo p sut.B. c th hp th mt bc x n sc no th khng th pht ra bc x n sc .C. bc x n sc, m n c th hp th hay pht ra, ph thuc vo nhit .D. c th hp th mt bc x n sc no th cng c th pht ra bc x n sc .

    Cu 47 : Pht biu no sau y l ng ?A. Cht kh hay hi p sut thp c kch thch bng nhit hay bng in cho quang ph lin tc.B. Cht kh hay hi c kch thch bng nhit hay bng in lun cho quang ph vch.C. Quang ph lin tc ca nguyn t no th c trng cho nguyn t y.D. Quang ph vch ca nguyn t no th c trng cho nguyn t y.

    Cu 48 : Tia Rnghen c pht ra trong ng Rnghen l doA. t trng ca dng eleectron chuyn ng t catt sang i catt b thay i mnh khi electron b

    hm t ngt bi i catt.B. pht x electron t i catt.C. cc electron nng lng cao xuyn su vo cc lp v bn trong ca nguyn t i catt, tng tc

    vi ht nhn v cc lp v ny.D. i catt b nung nng mnh.

    Cu 49 : Quang ph lin lc pht ra bi hai vt khc nhau thA. hon ton khc nhau mi nhit . B. ging nhau, nu chng c cng nhit .C. hon ton ging nhau mi nhit . D. ging nhau, nu mi vt c mt nhit ph

    hp.Cu 50 : Quang ph vch hp th l

    A. quang ph gm cc vch mu ring bit trn mt nn ti.

    B. quang ph gm nhng vch ti trn nn quang ph lin tc.C. quang ph gm nhng vch mu bin i lin tc.D. quang ph gm nhng vch ti trn nn sng.

    Cu 51 : Quang ph no sau y l quang ph vch pht xA. nh sng t chic nhn nung . B. nh sng t bt th in.C. nh sng ca Mt Tri thu c trn Tri t. D. nh sng t dy tc bng n nng sng.

    Cu 52 : mt nhit nht nh mt cht:A. bc x n sc, m n c th hp th hay pht ra, ph thuc vo nhit .B. c th hp th mt bc x n sc no th khng th pht ra bc x n sc .C. c th hp th mt bc x n sc no th cng c th pht ra bc x n sc .D. bc x n sc, m n c th hp thu hay pht ra, ph thuc vo p sut.

    Cu 53 : Bc x hng ngoi l bc x

    A. n sc, c mu hng. B. c bc sng nh hn 0,4 m.C. n sc, khng mu u ca quang ph. D. c bc sng t 0,75 m n 10-3m.

    Cu 54 : Tnh cht ni bt ca tia X lA. tc dng ln knh nh. B. kh nng m xuyn.C. lm pht quang mt s cht. D. lm in ha khng kh.

    Cu 55 : Quang ph gm mt di mu t n tm lA. c ba loi quang ph trn. B. quang ph vch hp th.C. quang ph vch pht x. D. quang ph lin tc.

    Cu 56 : Tia hng ngoi v tia t ngoiA. khng c cc hin tng phn x, khc x, giao thoa.B. u l sng in t nhng c tn s khc nhau.

    C. ch c tia hng ngoi lm en knh nh.

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    D. ch c tia hng ngoi c tc dng nhit.Cu 57 : Quang ph vch hp th l

    A. quang ph gm cc vch mu ring bit trn mt nn ti.B. quang ph gm nhng vch ti trn nn sng.C. quang ph gm nhng vch mu bin i lin tc.D. quang ph gm nhng vch ti trn nn quang ph lin tc.

    Cu 58 : Quang ph lin tcA. ph thuc vo bn cht v nhit ca ngun pht.

    B. ph thuc vo bn cht ca ngun pht m khng ph thuc vo nhit ca ngun pht.C. khng ph thuc vo bn cht v nhit ca ngun pht.D. ph thuc vo nhit ca ngun pht m khng ph thuc vo bn cht ca ngun pht.

    Cu 59 : Chn hin tng lin quan n hin tng giao thoa nh sng:A. Mu sc sc s ca bong bng x phng.B. Mu sc ca nh sng trng sau khi chiu qua lng knh.C. Bng n trn t giy khi dng mt chic thc nha chn chm tia sng chiu ti.D. Vt sng trn tng khi chiu nh sng t n pin.

    Cu 60 : Tia hng ngoi c pht ra mi trng xung quanhA. ch bi cc vt c nung nng(n nhit cao)B. ch bi cc vt c nhit trn 00C.C. ch bi mi vt c nhit cao hn mi trng xung quanh.

    D. bi cc vt c nhit ln hn 0(K).

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    phiu soi - p n (Dnh cho gim kho)Mn : 12 Giao thoa Ly thuyet tap 1

    M : 244

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    thi mn 12 Giao thoa Ly thuyet tap 2(M 245)

    Cu 1 : Quang ph vch pht x c pht ra doA. cc cht rn , lng hoc kh c t khi ln khi b nung nngB. chiu nh sng trng qua cht kh hay hi b nung nngC. cc cht kh hay hi p sut thp khi b kch thch pht sngD. cc cht rn , lng hoc kh khi b nung nng

    Cu 2 : Quang ph hng ngoi ca hi nc c mt vch mu bc sng l 2,8 m . Tn s dao ng casng ny l

    A. 1,07.1014Hz. B. 1,7.1013Hz. C. 1,7.1015Hz. D. 1,7.1014Hz.Cu 3 : C th nhn bit tia hng ngoi bng

    A. pin nhit in B. mn hunh quang C. mt ngi D. quang ph kCu 4 : Pht biu no sau y l khng ng?

    A. Tia hng ngoi c tc dng ln mi knh nh.B. Tia hng ngoi l sng in t c bc sng ln hn 0,76 m.C. Tia hng ngoi c tc dng nhit rt mnhD. Tia hng ngoi do cc vt b nung nng pht ra.

    Cu 5 : Tm pht biu sai v tc dng v cng dng ca tia t ngoi: Tia t ngoi

    A. c th gy ra cc hiu ng quang ho, quang hp.B. trong cng nghip c dng sy kh cc sn phm nng cng nghip.C. c tc dng sinh hc, hu dit t bo, kh trngD. c tc dng rt mnh ln knh nh.

    Cu 6 : Quang ph vch pht x ca hidro c 4 mu c trng l :A. , vng, lam, tm B. , lc, chm, tmC. , lam, chm, tm D. , cam, vng, tm

    Cu 7 : Tia hng ngoi v tia Rnghen u c bn cht l sng in t, c bc sng di ngn khc nhaunn

    A. chng b lch khc nhau trong t trng u.B. chng b lch khc nhau trong in trng u.C. c kh nng m xuyn khc nhau.

    D. chng u c s dng trong y t chp X-quang (chp in).Cu 8 : Tm pht biu sai v tia hng ngoi.

    A. Tia hng ngoi c bn cht l sng in t.B. Tia hng ngoi kch thch th gic lm cho ta nhn thy mu hng.C. Vt nung nng nhit thp ch pht ra tia hng ngoi. Nhit ca vt trn 500 oC mi bt u

    pht ra nh sng kh kin.D. Tia hng ngoi nm ngoi vng nh sng kh kin, bc sng ca tia hng ngoi di hn bc sng

    ca nh .Cu 9 : Nu sp xp cc tia hng ngoi, tia t ngoi, tia Rnghen v nh sng nhn thy c theo th t

    gim dn ca tn s th ta c dy sau:A. tia hng ngoi, nh sng thy c, tia t ngoi, tia RnghenB. tia hng ngoi, tia t ngoi, tia Rnghen, nh sng thy cC. tia Rnghen, tia t ngoi, nh sng thy c, tia hng ngoiD. tia t ngoi, tia hng ngoi, tia Rnghen, nh sng thy c

    Cu 10 : Php phn tch quang ph lA. Php o vn tc v bc sng ca nh sng t quang ph thu c.B. Php phn tch mt chm sng nh hin tng tn sc.C. Php o nhit ca mt vt da trn quang ph do vt pht ra.D. Php phn tch thnh phn cu to ca mt cht da trn vic nghin cu quang ph do n pht ra.

    Cu 11 : Pht biu no sau y sai ?A. Quang ph ca nh sng mt tri thu c trn tri t l quang ph lin tc.B. Quang ph vch pht x c nhng vch mu ring l nm trn nn ti.C. Quang ph vch pht x do cc kh hay hi p sut thp b kch thch pht ra.

    D. C hai loi quang ph vch: quang ph vch hp th v quang ph vch pht x.

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    Bi tp 12 luyn thi i hc - Trn Th An ([email protected] 09.3556.4557) Trang 36

    Cu 12 : Chn cu sai. Dng phng php ion ho c th pht hin ra bc x A. tia X mm B. tia t ngoi C. tia X cng D. Tia

    Cu 13 : Tm pht biu saiA. Cc h quang in vi nhit trn 4000oC thng c dng lm ngun tia t ngoi.B. Mt Tri ch pht ra nh sng nhn thy v tia hng ngoi nn ta trng thy sng v cm gic m p.C. n dy tc nng sng n 2000oC l ngun pht ra tia t ngoi.D. Thu tinh v nc l trong sut i vi tia t ngoi.

    Cu 14 : Cc tnh cht hoc tc dng no sau y khng phi ca tia t ngoi:

    A. C kh nng gy ra hin tng quang in B. C tc dng sinh hcC. C tc dng in ha cht kh D. B thch anh hp th rt mnhCu 15 : Pht biu no sau y l ng?

    A. Tia t ngoi khng c tc dng dit khun.B. Tia t ngoi l mt trong nhng bc x m mt ngi c th thy c.C. Tia t ngoi l bc x do vt c khi lng ring ln b kch thch pht ra.D. Tia t ngoi khng b thch anh hp th.

    Cu 16 : Quan st nhng ngi thi hn in, khi lm vic h thng dng mt n c tm knh tm chemt. H lm nh vy l :

    A. chng bc x nhit l hng da mt.B. trnh lm cho da tip xc trc tip vi tia t ngoi v chng la mt.C. chng hm lng ln tia hng ngoi ti mt, chng la mt.

    D. ngn chn tia X chiu ti mt l hng mt.Cu 17 : Quan st mt lp mng x phng trn mt nc ta thy c nhng di mu khc nhau (nh mu cu

    vng). l do:A. nh sng qua lp x phng b tn scB. Mng x phng c kh nng hp th v phn x khc nhau i vi cc nh sng n sc trong nh

    sng trngC. Mng x phng c b dy khng bng nhau, to ra nhng lng knh c tc dng lm cho nh sng b

    tn scD. Mi nh sng n sc trong nh sng trng sau khi phn x mt trn v mt di ca mng x phng giao

    thoa vi nhau to ra nhng vn mu n scCu 18 : Tm pht biu sai. Quang ph lin tc

    A. c hnh thnh do cc m hi nung nng.B. do cc vt rn b nung nng pht ra.C. do cc cht lng v kh c t khi ln khi b nung nng pht ra.D. l mt di sng c mu sc bin thin lin tc t n tm.

    Cu 19 : Pht biu no sau y l khng ng?A. Trong my quang ph, ng chun trc c tc dng to ra chm tia sng song song.B. Trong my quang ph, lng knh c tc dng phn tch chm nh sng phc tp song song thnh cc

    chm sng n sc song song.C. Trong my quang ph, bung nh nm pha sau lng knh.D. Trong my quang ph, quang ph ca mt chm sng thu c trong bung nh lun my l mt di

    sng c mu cu vng.Cu 20 : Quang ph lin tc ca mt ngun sng J

    A. ph thuc vo c thnh phn cu to v nhit ca ngun sng J.B. khng ph thuc vo c thnh phn cu to v nhit ca ngun sng J.C. khng ph thuc thnh phn cu to ca ngun sng J, m ch ph thuc vo nhit ca ngun

    sng .D. khng ph thuc vo nhit ca ngun sng J, m ch ph thuc thnh phn cu to ca ngun

    sng .Cu 21 : S sp xp no sau y l ng?

    A. fhng ngoi >