TUGAS 2 BETON PRATEKAN

8/18/2019 TUGAS 2 BETON PRATEKAN

1/16

Nama : Ade Irma Yuliana

NIM : 130523606351

Mata Kuliah : Struktur Beton Pratekan

1. iketahui :!am"ar:

imen#i Penam$an%:


2/16

iameter tendon & 20 mm2

'e%an%an "a(a & 1200 N) mm2

*tt & *t+ & , 1-6 N) mm2

*t & *+ & 1/ N) mm2

2. itun% :

a. Bata#,"ata# tendon $ada tum$uan1

8 -1

4 dan1

2 "entan%.

". umlah tendon

. 'ulan%an %e#er

3. Penele#aian :


3/16

a. Menentukan "ata#,"ata# tendon

Menghitung Inersia

ua# Setia$ Ban%un

A1=300 x150=45 x 103

mm2

A2=12 x50 x 200=5 x103 mm2

A3=

1

2 x 50 x 200=5 x103mm2

A4=200 x1400=280 x 103mm

2

A5=

1

2 x 200 x 400=40 x103mm2

A6=

1

2

x 200 x 400=40 x103mm2

A7=600 x 300=180 x103mm

2

4

Σ A=595 x103 mm2

arak 'itik Berat 'erhada$ Sum"u Y7

Y 1=1775mm

Y 2=1633.33 mm

Y

3=1633.33 mm

Y 4=1000mm

Y 5=433.33mm

Y 6=433.33mm

Y 7=150mm

Menentukan Ya dan Y"

Y" &( A1. Y 1 )+( A2 . Y 2 )+ ( A3 .Y 3 )+ ( A4 . Y 4 )+( A5 . Y 5 )+( A6. Y 6 )+( A7. Y 7 )

Σ A

&

(79875 x 103 )+(8166,6 x103)+ (8166,6 x103 )+(280000 x 103 )+¿ (17333,3 x103 )+(17333,3 x103

595 x 103

&437875 x10

3

595 x 103


4/16

& 735,924mm

Ya & htotal−Y b

& 1850mm−735,924 mm ¿1114,075mm

Menentukan nilai aa1=Y a−( 12 .150)

¿1114,075−(75)

¿1039,075mm

a2=Y a−(150+ 13 .200) ¿1114,075−(216,67 )

¿897,4089 mm

a3=Y a−(150+ 13 .200)

¿1114,075−(216,67 )

¿897,4089 mm

a4=Y a−(150+( 12 × (200+800+400)))

¿1114,075−(850)

¿264,075 mm

a5=Y b−(300+(13 .400))

¿735,9243697−(433,33 )

¿302,59mm

a6=Y b−

(300+(

1

3

.400)

)


5/16

¿735,9243697−(433,33 )

¿302,5910364mm

a7=Y b−( 12 .300)

¿735,9243697−(150 )

¿585,924mm

Menentukan Iner#ia Penam$an%

I total=(( 112 . (300 ) (150 )3)+ (45 x 103. (1039,075 )2 ))+(( 136 . (50) (200 )3)+(5 x 103. (897,4089 )2 ))+(( 136 . (5 I total=193186283263.31mm4

Menentukan Momen Tahan (Z)

Z a= I total

Ya

¿193186283263.31mm

3

1114,075mm

¿173404998,7 mm2

Z b= I total

Yb

¿193186283263.31mm

3

765,48mm

¿262508338.1mm2

Menghitung Eksentrisitas (e)

e & Y" 8 100

& 935-2;8 100

& 635-2; mm

Tegangan-tegangan:

*tt & *t+ & , 1-6 N) mm2

*t & *+ & 1/ N) mm2

Berat (eni# "eton & 2;00 k%)m3 & 2; kNm

< & 0-/5


6/16

Berat Sendiri (g)

% & ua# total = te"al = B Beton

& 0-55 m = 1 = 2; kNm

& 1;-2/ kN)m

M% &

1

8 = % = 2

&1

8 = 1;-2/ kNm = 302

& 1606-5 kNm

Beban Kerja (q)

> & ;0 kNm

M> &1

8 = > = 2

&18 = ;0 kNm = 30

2

& ;500 kNm

Menghitung Gaa !rategang (!)

Sarat,#arat "ata# te%an%an:

a. P

A (1+ e . y bi2 )−(− Mg

Zb ) & 1/ N)mm2- dan

". P

A (1+ e . y bi2 )−( Mg+ Mq

Zb ) & 0

"ila-

e & 635-2; mm

i2 & I

A &193186283263.31

595 x 103 & 32;6/2./2

" & 935.2 mm

maka-

P

A (1+ e . ybi2 )−(− Mg+ MqZb ) & 0


7/16

P

595×103 (1+ 635,924×735,92324682.829 )−( 1606500000+4500000000262508338,1 ) & 0

P

595×103 (1+ 467992,241324682,829 )−(

6106500000

262508338,1 ) & 0 P

595×103 (1+1,441 )−(23,262 )¿ & 0

P

595×103((2,441)−(23,262 )) & 0

;-103 = 10,6 P 8 23-262 & 0

;-103 = 10,6 P & 23-262

P &23,262

4,103×10−6

P & 566-31 kN

Batas-batas tendon (kabe")

1

2 Bentang

iten%ah 8 ten%ah Bentan%

e ?

[Zb×fct

P −

Zb

A +

Mmin

P

]? [262508338,1×185669311.845 −262508338,1595000 + 16065000005669311,845 ]? [ 47251500865669311,845−441,19+283,367]? [833,46−441,19+283,367 ]

? 695-63/mm

Md & M> 4 M%

& ;500000000 4 1606500000

& 6106500000 Nmm

e # [ Zb×ftwƞ× P − Zb A + Mdƞ× P ]


8/16

# [262508338,1×−1,60,85×5669311,845 −262508338,1595000 + 61065000000,85×5669311,845 ]

#

[

−420013340,9

4818915,068

−441,19+ 6106500000

4818915,068

]# [−87,159−441,19+1267,19 ]

# 93/-/; mm

iata# tum$uan

e ?

[Zb×fct

P −

Zb

A +0

]? [262508338,1×185669311,845 −262508338,1595000 +0]? [ 47251500865669311,845−441,19+0]? [833,46−441,19+0 ]

? 32-29 mm

e # [ Zb×ftwƞ× P − Zb A + 0]

# [262508338,1×−1,60,85×5669311,845 −262508338,1595000 +0]

# [−420013340,94818915,068 −441,19+0]# [−87,159−441,19+0 ]

# −528,349mm

1

4 Bentang


9/16

&1

4× L

&1

4×30 m

& 7,5 m

Be"an #endiri %7 & 14,28 m

@ A %7 &1

2× g × L

&1

2×14,28×30

& 21;-2 kN

M% & ( R A (g )× X )−1

2× g × x

2

& (214,2×7,5)−1

2×14,28×56,25

& 1606,50−401,625

& 1204,88 kNm M% & Mmin

Be"an ker(a >7 & ;0 kN)m

@ A >7 &1

2× q × L

&1

2×40×30

& 600 kN


10/16

M> & ( R A (q ) × x )−1

2× q × x

2

& (600×7,25 )−1

2×40×56,25

& 4500−1125

& 3375 kNm M>

Md & M% 4 M>

& 1204,88 4 3375

& ;59-// kNm

Bata# 8 "ata# tendon


e ? [ Zb×fct P − Zb A + Mmin P ]

? [262508338,1×185669311.845 −262508338,1595000 + 12048750005669311,845 ]

? [ 47251500865669311,845−441,19+212,525]

? [833,46−441,19+212,525]

? 60;-96 mm

Md & M> 4 M%


11/16

& 3395 4 120;-//

& ;59-/95 kNm


# [262508338,1×−1,60,85×5669311,845 −262508338,1595000 + 45798750000,85×5669311,845 ]

# [−420013340,94818915,068 −441,19+ 45798750004818915,068 ]# [−87,15−441,19+950,395]

# 56-36; mm

1

8 Bentang

&1

8× L

&1

8×30 m

& 3,75 m

Be"an #endiri %7 & 14,28 m

@ A %7 &1

2× g × L

&1

2×14,28×30

& 21;-2 kN


12/16

M% & ( R A (g )× x )−1

2× g × x

2

& (214,2×3,75 )−12×14,28×14,0625

& /03.25 −100,4

& 702,84 kNm M% & Mmin

Be"an ker(a >7 & ;0 kN)m

@ A >7 &1

2× q × L

&1

2×40×30

& 600 kN

M> & ( R A (q ) × x )−1

2× q × x

2

& (600×3,75 )−1

2×40×14,0625

& 2250−281,25

& 1968,75 kNm M>

Md & M% 4 M>

&

902./; 41968,75

& 2691-5 kNm


13/16

Bata# 8 "ata# tendon


e ? [Zb×fct

P − Zb

A + Mmin

P ]

? [262508338,1×185669311.845 −262508338,1595000 + 7028437505669311,845 ]

? [ 47251500865669311,845−441,19+123,97 ]

? [833,46−441,19+123,97 ]

? 516-2; mm

Md & M> 4 M%

& 16/-95 4 902-/;

& 2691-5 kNm


# [262508338,1×−1,60,85×5669311,845 −262508338,1595000 + 26715937500,85×5669311,845 ]

# [−420013340,94818915,068 −441,19+ 26715937504818915,068 ]# −87,15−441,19+554,39

# 26-0;95 m

!am"ar Bentan%1

2 L


14/16

". Menentukan (umlah tendon

iameter tendon & 20 mm

'e%an%an a+al "a(a & 1200 N)mm2

ua# tendon A tendon7 &1

4 × π × d2

&1

4×3,14×20

2

& 31; mm2

Maka- (umlah tendon n7 & P

A tendon ×eg . awal ba!a

&5669311.845 "

314×1200

& 15.0;5 # 16 "atan%

. Menentukan tulan%an %e#er

iketahui data,data #e"a%ai "erikut:

& /00 kN

k & ;0 N)mm2

& 250 N)mm2

$ & 5 N)mm2

"+ & 200 mm Karena "alok "er"entuk I- maka le"ar ru#uk "7 & "+7

& 1/50 mm

ika- dC & 50 mm- maka

t & 8 dC

& 1/50 8 50

& 1/00 mm

*t &0,24

×√

fc$


15/16

& 0,24×√ 40

& 1-519

Men%hitun% tulan%an %e#er den%an rekomenda#i IS7

%c=%co=0,67× b w × & √ (ft 2+0,8×fc'×ft )

%c=%co=0,67×200×1850√ (1,522+0,8×5×1,517 )

%c=%co=717437,038 "

%c=%co=717,437 $"

% −%c=800−717,437

% −%c=82,56 $"

io"a men%%unakan #en%kan% den%an & 10 mm

A()=2×0,25×π×&2

A()=2×0,25×3,14×102

A()=157mm

*)=[ A() ×0,87×fy×dt % −%c ]

*)=[157×0,87×250×1900800000−717437,038 ]*)=744,468

arak mak#imum #en%kan% an% di%unakan & ; "+

& ; 200

& /00 mm


16/16

adi- di$a#an% #en%kan% 10 8 /00 mm.

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TUGAS 2 BETON PRATEKAN