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TUGAS 2 KINEMATIKA DAN DINAMIKA Nama: Valianto NIM: 111234032 O 2 A = 4,75 in BC = 2 in O 4 B = 6,5 in CD = 14,5 in AB = 12 in W 2 = 10 rad / det → konstan AC = 13,25 in Ditanyakan : V D , a D , W 5 , α 5 ?

Tugas 2 Kinematika Dan Dinamika Valianto 2-TPKM.docx

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TUGAS 2 KINEMATIKA DAN DINAMIKANama: Valianto

NIM: 111234032

O2A = 4,75 in

BC = 2 inO4B = 6,5 in

CD = 14,5 inAB = 12 in

W2 = 10 rad/det konstanAC = 13,25 in

Ditanyakan :

VD , aD , W5 , 5 ?Penyelesaian : Tabel KecepatanBesaranHargaArahVektor

VAW2 O2A = 10 4,75 = 47,5 in/det O2Ao - a

VBW4 O4B = ? O4Bo - b

VBAW3 AB = ? ABa - b

VCW3 AC = ? ACa - c

VDW6 O4D = ?o - d

VDCW5 CD = ? CDc - d

Polygon KecepatanSkala 1 in = 3 in/deto - b = 12,32 ina - b = 25,07 in

a - c = 27,68 ino - d = 15,61 in VD = 15,61 3 = 46,83 in/detc - d = 9,63 in

VDC = 9,63 3 = 28,89 in/det

W5 = = = 1,99 in/det Tabel Percepatan

BesaranNormal

HargaArah

aAW22 O2A = 102 4,75 = 475 in/det2A O2 o - ao

aBW42 O4B = ?B O4o - bo

aBAW32 AB = ?B Aa - ba

aCBayang-bayang

aDW62 O4D = ?o - do

aDCW52 CD = 1,992 14,5 = 57,42 in/det2D Cc - dc

BesaranTangensial

HargaArahVektor

aA 2 O2A = ?A O2 ao - a

aB 4 O4B = ?B O4bo - b

aBA 3 AB = ?B Aba - b

aCBayang-bayango c

aD 6 O4D = ?do - d

aDC 5 CD = ?D Cdc - d

Polygon Percepatan

aD = 24,82 in

5 = = = 3,96 in/det2