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7/31/2019 Tut 4 Graphing Techniques
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Jurong Junior CollegeJC1 Mathematics H2 (9740)
Tutorial 4: Graphing Techniques Solution Section A : Basic Questions
1(a) 121
y x
= +
Vertical Asymptotes: 1 x = Horizontal Asymptote: 2 y =
1(b)2 3 1 3
12 2
x x y x
x x
+ = = + + +
Vertical Asymptotes: 2 x = Oblique Asymptote: 1 y x= +
1(c) 2 0 ( 2)( 24 x x
y x x x
= = ++ )
Vertical Asymptotes: 2 and 2 x x= =Horizontal Asymptote: 0 y =
1(d)1
y x x
=
Vertical Asymptotes: 0 x =Oblique Asymptote: y x=
1(e) 2 21 1
04 4
y x x
= = ++ +
Vertical Asymptotes: 2[Note: Thers is no real root for whichNIL 4 0.] x + =Horizontal Asymptote: 0 y =
1(f) 1 e x y = +
Vertical Asymptotes: Note: is defined for all real vaNIL lues of ].[ xe x
[Note: As , 0, so 1.
Horizon
tal Asy
As , , s
mptote: 1
o .]
x
x
x e y
x e
y
y
+
+ +
=
1
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2(a) 3 2 3 y x x= + y
( 0.816, 4.09)
3
(0.816, 1.91) x
1.89
y
2(b) 2e x y =
1
0 y =
x
y2(c) ln( 2) y x= +
ln 2
x1
2 x =
2
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2(d) 2 1 y x=
y
x1
2(e)4 1 9
2 1 2 2(2 1) x x
x y
= =
+ +
2(f) ,ln y x x= 0 x >
y
x
12
y =
4
4
12
x =
y
x1
(0.368, 0.368)
3
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2(g)2 2 8
23 3
x x y x
x x
+= = + +
y
2(h)2 4 1 2
31 1
x x y x
x x
+ += = + + +
(0.172, 0.657)
2 y x= +
3 x
(5.83, 10.7)
23
=
22 x
1 x =
y y 3
3
3 x
x= +
3.73
1
0.268
4
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2(i)6 24
13 3
y x x
= + +
y
3(a)2 2
14 9
x y+ = - An ellipse 3(b)2 2
14 4
x y+ = - A circle
3(c)2 2
14 9
x y = - A hyperbola 3(e)2
2( 2) 125
x y
+ = - An ellipse
3(d) 2 2( 1) 16 4( 3) x y = + +
2 2
2 2
( 1) 4( 3) 16
( x 1) ( 3)1 - A
16 4
x y
y
+ =+
=
6
y x+ =
hyperbola
3(f) 2 2 2 6 x y x y+ + =
2 2
2 2 2 2
2 2
2 6 6
( 1) 1 ( 3) 3 6
( 1) ( 3) 16 - A circle
x x y y
x y
x y
+ + = + + = + + =
4(a) 2 24 162 2
14 16
x y + =
x(9, 0)
(1, 8)
1 y
=
3 x = 3 x =
9
x
y
4
4
22
5
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4(b)2 2
125 4 x y =
4(c) 2 2( 2) ( 1) 5= x y +
4(d)2
2( 1)9
y x =1
x55
y
25
y x=
25
y x=
x
y
(2, 1)
5
2
4
3
0
y 3( 1) y x=
x
3( 1) y x
3 2
(1, 0)
(1, 3)
=
3 2
3 (1, -3)
6
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5(a) 5(b)
5(c) 5(d)
5(e)
6(a) f ( ) f 2 x
y x y
= = Geometrical transformation: A stretch parallel to the x -axis with a scale factor of 2.
6(b) g( ) g( 2) y x y x= = +Geometrical transformation: A translation of 2 units in the direction of the x -axis .
6(c) h( ) 2h( ) y x y= = x
x
e
Geometrical transformation: A stretch parallel to the y-axis with a scale factor of 2.
6(d) k( ) k( ) 2 y x y x= = +Geometrical transformation: A translation of 2 units in the direction of the y-axis
6(e) m( ) m( ) y x y= = Geometrical transformation: A reflection about the x -axis.
6(f) 2 4 2 4 2 4e e e x x x y y+ = = = +
Geometrical transformation: A stretch parallel to the y-axis with a scale factor of 4e .
OR [Replace x by ( x 2).]2 4 2 2( 2) 4e e e x x y y+= = = x +
Geometrical transformation: A translation of 2 units in the direction of the x -axis.
7
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6(g) [Replace x by ( x).]ln(2 ) ln( 2) y x y x= = +
Geometrical transformation: A reflection about the y-axis.
6(h)2 2
1 2(
x x y y
x x
+ += =+ +1)
Geometrical transformation: A stretch parallel to the y-axis with a scale factor of 1
.2
.
7(a) f ( ) f ( 1) 2 y x y x= = + (i) A translation of 1 units in the direction of the x -axis.(ii) A translation of 2 units in the direction of the y-axis.
7(b) f ( ) f (2 1) y x y x= = +(i) A translation of 1 units in the direction of the x -axis.(ii) A stretch parallel to the x -axis with a scale factor of 1/2.
7(c) 1f ( ) f ( )2
y x y x= =
(i) A stretch parallel to the x -axis with a scale factor of 2.(ii) A reflection about the y-axis.
7(d) .f ( ) 1 f ( 1) y x y x= = +(i) A translation of 1 unit in the direction of the x -axis.(ii) A reflection about the x -axis.(iii) A translation of 1 unit in the direction of the y-axis.
.8(a) The equation of the resulting graph is f ( 2) y x
8(b) The equation of the resulting graph is f 2 x
y .
8(c) The equation of the resulting graph is 2f ( ). y x 8(d) The equation of the resulting graph is f ( ). y x 8(e) The equation of the resulting graph is f ( ) 1. y x
9(i) y( )2,3
( 4, 2) ( )3 y f x = +
x
( )1,0( )5,0 ( )3,0
8
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y9(ii)
9iii)
9(iv)
9(v)
1( , 2
3 )
x
1,3
3
( )3 y f x=
( )0,0 2 ,03
2,0
3
y( 1, 3)
( )1, 2( ) y f x
=
x
( )0,0 ( )2,0( )2,0
( 1, 2)
y
x
( )1, 1
( ) 4 y f x=
( )0, 4
y( )1,12
( 1, 8) ( )4 y f x=
x
( )0,0 ( )2,0( )2,0
9
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9(vi) y
9(vii)
9(viii)
9(ix)
( 1, 2)
x
( )1, 3
( ) y f x=
( )0,0 ( )2,0( )2,0
( 1, 3) y
( )1,3
( x
) y f x=
( )0,0 ( )2,0( )2,0
( 1, 2)
y( )1,3
( ) y f x=
x
( )0,0 ( )2,0( )2,0
y( )1, 3
( 1, 2) ( )2 y f x=
x
( )0,0 ( )2,0( )2,0
( )1, 3 ( 1, 2) y
10
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9(x)
11,
2
10(i)
x1
1,3
( )
1 y f x
=
2 x =
0 y =
0 x 2 x = =
y
( )2 y f x=
x
2 x =
3 y =
( )1,0
3 y =
11
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10(ii) y
11(i) The graph of could be mapped onto the graph of x y 3= 13 += x y by a stretch parallel tothe y-axis by a scale factor of 3ORa translation parallel to the x-axis in the negative direction of 1 unit.
(ii)ln 5
5 3ln 3
x px p= = .
The graph of 3 x y = could be mapped onto the graph of 5 x y = by a stretch parallel
to the x-axis by a scale factor of ln 3ln 5
.
x
1 x =
13 y =
( )1
y f x
=
( )2,0
(0, -2)
12
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Standard Questions:12. f ( ) (2 )(4 ) x x x x= (i) 2 f ( ) y x=
x0 2 4
y
(ii) f ( ) y x= (iii) f ( ) y x=
(iv)1
f ( )
y
x
=
y
(0.845, 3.08)(0.845, 1.75)
x20 4
(0.845,-1.75)
(3.15, -3.08)
y
x2 40
x
y
2
(0.845, 3.08) (3.15, 3.08)
(-0.845, 3.08) (0.845, 3.08)
404 2
x
y (-3.15, -3.08) (3.15, -3.08)
(0.845, 0.325)
(3.15, -0.325)
2 x = 4 x =
13
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13.
(0.368, 0.368) is the minimum point.
x
y
1
(0.368, 0.368)
(i) 2 ln= y x x . (ii) 1ln
y x x
=
x
y
1
x
y
1( )0.368, 2.72
14.
x
y
(4, 4.69)
4 x y x e =
0 y =
(0, 0) is the minimum point and is the maximum point.(4, 4.69)
x
14
y
(4, 2.17)
2 4 x y x e =
0 y =
(4, 2.17)
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14(ii)
x
y
( 4, 4.67)
4 x y x e=
0 y =
x
y
(4, 0.213)
4 x y x e=
0 y = 0 x =
14(iii)
15. (i) 2( 2) 4 y x= + +
(ii)
2 2
4 42 4 x x
y
= + = +
Step 1: Stretch parallel to the x-axis by a scale factor of 1
2
Step 2: Translation parallel to the y-axis in the positive direction of 2 unitsStep 3: Reflection about the x-axis
OR
Step 1: Stretch parallel to the y-axis by a scale factor of 2Step 2: Translation parallel to the y-axis in the negative direction of 2 unitsStep 3: Reflection about the x-axis
16. Let 2f ( ) x y x= = .
After A: 2f ( 3) ( 3) y x x= =
After B: 22f ( 3) 2( 3) y x x= =
After C : 22f ( 3) 5 2( 3) 5 y x x= + = +
The equation of the resulting curve is 22( 3) 5 y x= + .
15
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2
2
2
2f ( 3) 5
5f ( 3)
2
( 3) 5f ( ) 2
x x
x x
x x
+ =
=
+ =
The equation of the resulting curve is2 6 4
2 x x
y+ += .
17 (i) f (2 2 )= y x y
17 (ii)
(2, 2)
x 5
( , 0)2
(1, 0)
1 y
( )2 2 y f x= =
3 x =
y
x
( 2, 5)
(0,1)
4 y =
( )1 3 y f x=
4 x =
16
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y 17(iii)
x
2 y = ( )2 y f x=
17(iv) 17(v) y
y ( 2, 2)
( 2, 2)
17(vi)
3
( ) y f x= x 3
x
( ) y f x=
( )3,0
y
( )2 y 1= y f x=
x
1 y =
4 x =
17
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y 17(vii)
1( 2, )
2
18(i) )(f x y =f ( 2) f ( 2 2) f( ) y x x y x [ 2 units in the direction of x-axis]
( , ) ( 2, ) x y x y
1 x =
02
1
x
y
= y
( 1, 5)
3 x =
( )4,0
1 y
=
( )
x
1 y
f x=
0 x =
18
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(ii) )2
1(f x
y =
f( ) f(1 ) f(1 ) f (1 )2 2
x x y x y x y y= = + = + =
n o p
[ translation -1 units in the direction of x-axis.stretch // x-axis, factor 2 ; Reflection in y-axis. ]
( , ) ( 1, ) (2( 1), ) ( 2( 1), ) ( 2 2, x y x y x y x y x ) y
( , ) (2 2 , )
(0, 0) (2, 0)
( 2, 0) (6, 0)
( 1, 5) (4, 5)
x y x
y
y
0 x =
1 0 x x= =
19(a) .f ( ) y x=
(b) .f ( ) when 0
f (| |)f ( ) when 0
x x y x
x x
= =
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20.2 7
22( 2) 3
23
22
A = 2, B = 3
x y
x x
y x
y x
+=+
+ += +
= ++
1 1 3 32
2 2 x x x x +
+ + 2+
Following the formula for composite transformations, y = d + cf(b x + a)
( ) ( )( ) ( 2) 3 2 2 3 2 f x f x f x f x + + + +
Sequence of transformations will be1) Translation of -2 units along the x - axis2) Scaling of 3 along the y - axis3) Translation of 2 units along the y - axis
-2
2
7/2
y
x-7/2
20