Tuyen Tap de Thi Thu Suc Hk 1 Mon Toan 12

n tp THI HC K I- Mn Ton 12 Nm hc 2013- 2014

Gio vin: L B BO0935.785.115 T Ton THPT Phong in 1

PHN II: TUYN TP CC THI HC K I

S GIO DC V O TO TT- HU V MT S TRNG THPT TRC THUC



S Gio dc v o to kim tra hc k I - nm hc 2009-2010 Tha Thin Hu Mn: TON - Lp 12 Thi gian lm bi: 90 pht CHNH THC A- PHN CHUNG DNH CHO TT C CC TH SINH ( 7,0 im )

Cu 1: (4,0 im) Cho hm s 3 23 4y x x= + 1) Kho st s bin thin v v th (C) ca hm s . 2) Vit phng trnh tip tuyn ca th (C) ti im trn (C) c honh l nghim ca

phng trnh " 0y = . 3) Da vo th (C) hy bin lun theo m s nghim ca phng trnh:

3 23 0x x m + + = .

Cu 2: (2,0 im) 1) Gii phng trnh 29 4.3 243 0x x+ + = . 2) Tm gi tr ln nht v gi tr nh nht ca hm s ( )2 3 xy x e= trn on [ ]0; 2 .

Cu 3: (1,0 im). Cho hnh chp S.ABCD c y ABCD l hnh vung cnh a ; cc cnh bn u bng nhau v bng 2 .a

1) Tnh th tch khi chp S.ABCD. 2) Tnh th tch khi nn c nh trng vi nh ca hnh chp v y ca khi nn ni tip

trong y ca hnh chp S.ABCD.

B- PHN RING ( 3,0 im )

Th sinh ch c lm mt trong hai phn sau: ( phn 1 hoc phn 2 )

Phn 1: Theo chng trnh chun

Cu 4a: (1,0 im) Gii bt phng trnh: ( )2 18

log 2 2 6log 3 5x x .

Cu 5a: (2,0 im) Cho t din SABC c 2AB a= , 3AC a= , 060BAC = , cnh SA vung gc vi (ABC) v SA = a.

1) Tnh th tch khi chp S.ABC. 2) Tnh khong cch t A n mp(SBC). 3) Tnh th tch khi cu ngoi tip hnh chp S.ABC.

Phn 2: Theo chng trnh nng cao

Cu 4b: (1,0 im) Gii h phng trnh:

( )22 2 2log log 2log 3

9 .3 81x y

x y x

+ =

=

Cu 5b: (2,0 im) Cho hnh nn nh S c bn knh y bng a v ng cao 2SO a= . Mt mt phng i qua nh S, to vi y hnh nn mt gc 060 v ct hnh nn theo thit din l tam gic SAB.

1) Tnh din tch tam gic SAB theo a. 2) Tnh bn knh mt cu ngoi tip t din OSAB theo a.

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S Gio dc v o to kim tra hc k I - nm hc 2010-2011 Tha Thin Hu Mn: TON - Lp 12 Thi gian lm bi: 90 pht CHNH THC

Cu 1: (1,0 im) Cho hm s 3 212 36 3y x x x= + + . a) Tm cc khong n iu ca hm s. b) Tm cc im cc tr v cc gi tr cc tr ca hm s.

Cu 2: (0,5 im) Tm tim cn ng v tim cn ngang ca th hm s 2 3

1

xy

x

+=

.

Cu 3: (0,5 im) Tm tp xc nh ca hm s ( )2

2 52x x .

Cu 4: (0,5 im) Khng s dng my tnh, hy tnh:

a) 52log 8A = b) 9log 281B =

Cu 5: (0,5 im) Tnh theo a th tch ca khi t din u cnh a . Cu 6: (0,5 im) Khi cho tam gic vung ABC (vung ti A, 2 , AB b AC b= = ) quay quanh cnh AB

ta c hnh g ? Tnh theo b din tch xung quanh ca hnh . Cu 7: (2,5 im) Cho hm s 4 22 4 1y x x= + . a) Kho st s bin thin v v th (C) ca hm s. b) Da vo (C), tm m phng trnh 4 22 4 0x x m + = c 4 nghim phn bit. Cu 8: (1,5 im) Gii phng trnh v bt phng trnh sau : a) 2 13 8.3 3 0x x+ + = b) ( )1 1

3 3

log log 2 1 0x x+ + + >

Cu 9: (2,0 im) Cho hnh chp t gic u S.ABCD c cnh y bng a v cnh bn bng 2a . a) Tnh th tch khi chp S.ABCD theo a . b) Xc nh tm v tnh theo a bn knh ca mt cu ngoi tip hnh chp S.ABCD .

Cu 10: (0,5 im) Tm gi tr nh nht ca hm s 22

12

2y x x

x x= +

.

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S Gio dc v o to kim tra hc k I - nm hc 2011-2012 Tha Thin Hu Mn: TON - Lp 12 Thi gian lm bi: 90 pht CHNH THC

A. PHN CHUNG DNH CHO TT C CC TH SINH (7,0 im)

Cu 1: (3,0 im) Cho hm s 3 3 3y x x= . a) Kho st s bin thin v v th (C) ca hm s. b) Da vo th (C) hy bin lun theo m s nghim ca phng trnh 3 3 0x x m = . Cu 2: (2,0 im) : Gii cc phng trnh :

a) 2 8 1 32 4x x x + = b) ( ) ( )222 2log 2 3 2log 2 3 2x x+ + =

Cu 3: (1,0 im) Tm gi tr ln nht, gi tr nh nht ca hm s ( ) ( )21 12 32y f x x x= = + trn on [ ]2;2 .

Cu 4: (1,0 im) Cho tam gic ABC vung cn ti A, ng thng i qua A vung gc vi BC ti H,

2AH a= . Cho hnh tam gic ABC quay quanh ng thng c mt hnh trn xoay. Tnh din tch mt xung quanh v th tch ca khi trn xoay to thnh.

B. PHN RING (3,0 im) Th sinh ch c lm mt trong hai phn sau (phn 1 hoc phn 2): Phn 1: Theo chng trnh chun. Cu 5a: (2,0 im) Cho hnh chp S.ABCD, y l hnh thang vung ti A, B; 2 2 2 ,AD AB BC a= = =

4SC a= . SA (ABCD), M l trung im ca AD. 1) Tnh th tch ca khi chp S.CMD. 2) Xc nh tm I, tnh bn knh v din tch ca mt cu ngoi tip hnh chp S.ABCM.

Cu 6a: (1,0 im) Cho hm s 2

1

xy

x=

(C'). Tm cc im trn (C') sao cho khong cch t im

n ng tim cn ng bng hai ln khong cch t im n ng tim cn ngang ca (C'). Phn 2: Theo chng trnh nng cao. Cu 5b: (2,0 im) Cho hnh chp tam gic u S.ABC c cnh y bng a , mt bn hp vi y mt

gc 60 0 . 1) Tnh th tch khi chp S.ABC. 2) Xc nh tm I, tnh bn knh v din tch ca mt cu ngoi tip hnh chp S.ABC.

Cu 6b: (1,0 im) Xc nh m hm s 2 2

2

x x my

x

+ +=

+ t cc tiu ti 2x = .

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UBND TNH THA THIN HU S GIO DC V O TO

THI CHNH THC

KIM TRA HC K I- NM HC 2012- 2013 Mn: TON 12 THPT

Thi gian lm bi: 90 pht Khng k thi gian pht

I. PHN CHUNG CHO TT C TH SINH: (7,0 im) Cu 1: (1,0 im)

Tnh gi tr cc biu thc sau:

a) 0,752

0,53 127 25 .16

A

= +

b) 9 9 9log 15 log 18 log 10.B = +

Cu 2: (3,0 im) Cho hm s 2 1

1

=

x

yx

c th l (C).

a) Kho st v v th (C) ca hm s. b) Vit phng trnh tip tuyn ca th (C), bit rng tip tuyn vung gc vi

ng thng c phng trnh .y x= Cu 3: (3,0 im) Cho khi chp S.ABC c y ABC l tam gic u cnh a , mt bn SBC hp vi mt y mt

gc bng 060 , ( )SA ABC . Gi M v N ln lt l hnh chiu vung gc ca A trn cc cnh SB v SC.

a) Tnh th tch ca khi chp S.ABC theo a . b) Xc nh tm I, bn knh v tnh din tch mt cu mt cu ngoi tip khi chp S.ABC

theo a . c) Tnh th tch ca khi chp A.BCNM theo a .

II- PHN RING- PHN T CHN: (3,0 im) (Th sinh ch c lm mt trong hai phn) 1. Theo chng trnh Chun:

Cu 4a: (2,0 im) Gii cc phng trnh v bt phng trnh sau:

a) ( ) ( )12 2log 2 1 log 2 2 6x x+ = b) 12 2 3 0x x ++ < Cu 5a: (1,0 im)

Tm gi tr ln nht v gi tr nh nht ca hm s 2sin 3 sin 1y x x= + 2. Theo chng trnh Nng cao:

Cu 4b: (2,0 im)

a) Cho x l mt s thc m. Chng minh rng: ( )

( )

2

2

11 1 2 2 1 241 211 1 2 2

4

x xx

x

x x

+ +

=+

+ +

.

b) Cho , a b l di hai cnh gc vung, c l di cnh huyn ca mt tam gic vung, trong 1c b v 1c b+ . Chng minh rng: log log 2 log .log

c b c b c b c ba a a a+ + + =

Cu 5b: (1,0 im)

Tm gi tr ln nht v gi tr nh nht ca hm s 34 sin 2sin3

y x x= trn on 0; .

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S GD&T THA THIN HU TRNG THPT PHONG IN

THI HC K I (Nm hc: 2008-2009) Mn thi : Ton 12

Thi gian lm bi: 90 pht (khng k thi gian pht ) I. Phn chung cho c 2 ban: (8,0 im) Cu 1: (3,0 im)

1) Kho st v v th (C) ca hm s 3

1

xy

x

+=

+.

2) Vit phng trnh tip tuyn ca (C) ti im c tung 2.y = Cu 2: (1,5 im) Cho hm s ( )3 23 1y x m x m= + + + ( m l tham s)

Xc nh m hm s c cc i l 1x = . Cu 3: (1,5 im)

1) Gii phng trnh: 2.9 5.6 3.4 0x x x + = 2) Gii bt phng trnh: ( )21

2

log 3 2 1x x +

Cu 4: (2,0 im) Cho khi chp t gic u S.ABCD c cnh y bng a , cnh bn 2a .

1) Tnh th tch ca khi chp. 2) Xc nh tm v tnh bn knh mt cu ngoi tip khi chp trn. 3) Tnh din tch mt cu v th tch khi cu ngoi tip khi chp trn.

II. Phn dnh ring cho tng ban (2im) Hc sinh ban KHTN ch lm cu 5a; hc sinh ban c bn ch lm cu 5b.

Cu 5a: (2,0 im) 1) Gii h phng trnh :

( )3

2

log 3

2 12 .3 81xx y

y y y

+ =

+ =

2) Cho khi chp S.ABC c y l ABC vung ti B. Bit SA (ABC), gc BAC = 300, BC a= v SA a a= . Gi M l trung im ca SB. Tnh th tch khi t din MABC.

Cu 5b: (2,0 im) 1) Gii bt phng trnh ( ) ( )2 7 ln 1 0x x + > 2) Cho hnh chp S.ABC c y ABC l tam gic u cnh a , cnh bn SA vung gc vi y v SA bng a . Tnh th tch ca khi chp S.ABC theo a .

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TRNG THPT GIA HI KIM TRA HC K I (Nm hc: 2008 2009) T Ton-Tin Mn Ton-Khi 12. Chun-Nng cao. Thi gian : 90 pht (khng k thi gian pht ) PHN CHUNG:( 7 im)

Cu 1(3): Cho hm s : 1

2)(

==

x

xxfy (1)

1. Kho st v v th (C) ca hm s (1). 2. Chng minh rng ng thng d: y = 2x + m lun ct th (C) ti hai im M v N phn bit vi mi m. Xc nh m on thng MN ngn nht.

Cu 2(2):

1. Gii phng trnh: 1)69(log)63.4(log 22 =xx

.

2.Chng minh rng: nmnmnm

nmnm+=

+.

))(( 4 34 34 34 3;

vi , 0m n n > ; 0>m . Cu 3(2): Cho hnh chp S.ABC c ABC vung ti B c cmAB 3= , cmBC 4= , cnh bn

)(ABCSA v cmSA 4= . Gi (P) l mt phng qua A v vung gc vi SC; mt phng (P) ct SC v SB ln lt ti D v E.

1. Chng minh: )(SBCAE . 2. Tnh th tch khi chp S.ADE.

II. PHN RING ( 3 im )

A. Hc sinh hc chng trnh chun chn cu 4a.

Cu 4a

1. ( 1 ) Gii bt phng trnh sau: 3

2

1logx5

2

1log



S GD&T THA THIN HU THI HC K I NM HC 2008 - 2009 TRNG THPT HNG TR MN TON KHI 12 --------------------- Thi gian lm bi: 90 pht. (Khng k thi gian pht ) ----------------------------------------------- H v tn:..................................................................................... SBD:................................................................. Lp:................... ----------------------------------------------------------------------------------------------------- Cu 1. (3,5 im)

Cho hm s 3y x 3x 2= + a/. Kho st s bin thin v v th (C) ca hm s. b/. Vit phng trnh tip tuyn ca th (C) ti giao im ca n vi trc tung.

c/. Da vo th (C), Bin lun theo m s nghim ca phng trnh 3x 3x m 0 + = Cu 2. (1,5 im) Gii cc phng trnh sau:

a/. x 1 x3 5.3 8+ =

b/. ( ) ( )2 2log x 1 log x 5 2+ = Cu 3. (1 im)

Gii bt phng trnh sau: x x 2

x

1 x

9 3 279

3

+

+<

Cu 4. (1 im)

Tm gi tr ln nht v gi tr nh nht ca hm s 3 2y x 3x 9x 7= + + trn 2;2

Cu 5. (3 im) Cho hnh chp t gic S.ABCD c y ABCD l hnh vung, cnh bn SA vung gc vi mt phng y. Bit SB = 3a v SC = 5a. a/. Chng minh tam gic SBC vung ti B. b/. Tnh th tch ca khi chp S.ABCD. c/. Gi M, N, P, Q ln lt l trung im ca cc cnh SA, SB, SC, SD. Tnh th tch khi chp ct MNPQ.ABCD.

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Cn b coi thi khng gii thch g thm.



TRNG THPT THI HC K I NM HC 2008 2009 NGUYN NH CHIU MN TON KHI 12 T TON Thi gian lm bi : 90 pht ****** (Khng k thi gian giao ) ********** H v tn : ....................................... Lp : ................................................

A. PHN CHUNG ( Dnh cho tt c cc hc sinh ) Cu 1: (2,5 im) Cho hm s 3 2y x 3x 2= + c th (C).

a/ Kho st s bin thin v v th (C) ca hm s. b/ Tm m phng trnh 3 2x 3x m 0 + + = c 3 nghim phn bit.

Cu 2: (1 im) Rt gn biu thc sau: 21 1

2 21 2 :b b

A a ba a

= + , vi 0, 0,a b a b> > .

Cu 3: (2 im) Gii cc phng trnh :

a/ 2x 5x 6 x 12 4+ = ;

b/ 8 2212

2log x 3log x log x 1+ = .

Cu 4: (2,5 im) Cho hnh chp S.ABCD c y ABCD l hnh ch nht, SA (ABCD), , 2 , 7AB a AD a SC a= = = . a/. Tnh th tch khi chp S.ABCD. b/. Xc nh tm v tnh bn knh mt cu ngoi tip khi chp S.ABCD.Tnh th tch khi cu.

B. PHN T CHN (Dnh ring cho hc sinh tng ban) Hc sinh hc Ban no chn phn dnh ring cho Ban hc

I. Dnh cho hc sinh Ban nng cao. Cu 5A : (1 im) Tm gi tr ln nht v nh nht ca hm s sau: y = sin3x cos2x + sin x + 2 Cu 6A : (1 im) Bin lun s nghim ca phng trnh sau theo tham s m . (m -3).9x +2(m +1) .3 x m - 1 = 0 .

II. Dnh cho hc sinh Ban c bn. Cu 5B : (1 im) Gii bt phng trnh : 2 32 2log log 4 0x x+ Cu 6B : (1 im) Tm gi tr ln nht v nh nht ca hm s sau: y = | x2 4x 5 |

trn [ ]2;6

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S GD-T TT Hu KIM TRA HC K I (2008 - 2009) Trng THPT Phan ng Lu Mn Ton - Lp 12 Thi gian: 90 pht

A. Phn chung

Bi 1(3 im): Cho hm s y = x3 - 3x - 1 1. Kho st v v th (C) ca hm s.

2. Vit phng trnh tip tuyn ca (C) ti im x = 2 . 3. Tm tt c gi tr ca m phng trnh x3 - 3x + m - 2 = 0 c 3 nghim phn bit.

Bi 2 (2 im): 1. Cho hm s y = f(x) = 2xex - ln(cosx). Tnh f (0).

2. Gii phng trnh 3log 43 13 .3 3 3x x x + = . Bi 3 (2 im): Cho hnh chp tam gic u S.ABC, cnh y a, gc gia cnh bn v mt y bng 600. 1. Tnh chiu cao SH, th tch ca hnh chp. 2. Tnh bn knh mt cu ngoi tip hnh chp.

B. Phn ring

Phn dnh cho hc sinh hc chng trnh CHUN

Bi 4 (2 im):

1. Tm gi tr ln nht v gi tr nh nht ca hm s 26y x x= trn on [0; 5].

2. Gii bt phng trnh ( ) ( )2 4log 5 log 2 1x x + . Bi 5 (1 im): Mt hnh nn c chiu cao 10 cm. Thit din qua trc l mt tam gic u. Tnh t s din tch xung quanh ca hnh nn v din tch mt cu ni tip hnh nn.

Phn dnh cho hc sinh hc chng trnh NNG CAO

Bi 4 (2 im):

1. Gii phng trnh 3 32 24

log log3

x x+ = .

2. Tm m phng trnh sau c nghim: ( )2 s inx+ cos sin 2 1x x m = . Bi 5 (1 im): Cho hai na ng thng Ax, By cho nhau v vung gc vi nhau, c AB l ng vung gc chung, AB = a. Gi M, N ln lt l cc im trn Ax v By vi AM = x, BN = y. a. Chng minh cc mt ca t din ABMN l cc tam gic vung. b. Tnh din tch ton phn v th tch t din ABMN theo a, x, y.

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Trng THPT Vinh Xun KIM TRA HC K I - NM HC 2008-2009 T Ton Tin MN TON LP 12 (Thi gian 90 pht ) ----------- CHNH THC A-PHN CHUNG BT BUC: ( 7 im ) Cu 1: (4 im)

Cho hm s 2 1

1

xy

x

+=

a) Kho st s bin thin v v th (C) ca hm s. b) Vit phng trnh tip tuyn ca th (C) ti giao im ca th (C) v trc tung . c) Tm m ng thng d c phng trnh ( )2 2y m x= + + ct th (C) ti hai im phn bit. Cu 2: (3 im) Cho hnh chp S.ABCD, y l hnh ch nht ABCD c , 3AD a AB a= = , cnh bn SA vung gc vi mt y (ABCD), cnh bn SB to vi mt y (ABCD) mt gc bng

030 . Gi H l hnh chiu vung gc ca A trn SD. a) Chng minh rng DC vung gc vi AH. b) Xc nh tm v tnh bn knh mt cu ngoi tip hnh chp S.ABCD . c) Tnh th tch khi chp H.ABC . B-PHN DNH CHO HC SINH TNG BAN: ( 3 im )

* Hc sinh Ban C bn lm cc cu 3a, 4a, 5a: Cu 3a: (1im) Gii phng trnh: 15 3.5 8 0x x+ = . Cu 4a: (1im) Gii bt phng trnh: ( ) ( )22 2log 2 3 1 log 3 1x x x+ + + . Cu 5a: (1im) Cho tam gic ABC vung gc ti A, , AC b AB c= = quay quanh cnh huyn BC. Tnh th tch khi trn xoay c to thnh.

* Hc sinh Ban Nng cao lm cc cu 3b, 4b, 5b: Cu 3b: (1im) Gii h phng trnh:

( )

( ) ( )2 2

41

55

log log 5

x yx y

x y x y

=

+ + =

Cu 4b: (1im) Gii phng trnh: ( ) ( )2 23 2log 2 1 log 2x x x x+ + = + . Cu 5b: (1im) Hnh tr c bn knh y R v trc 2OO R = . Hai im A, B ln lt thuc hai ng trn y (O) v (O) sao cho gc gia AB v trc OO bng . Tnh khong cch gia AB v OO theo R v .

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TRNG THPT NGUYN HU THI HC K I NM HC 2008 - 2009 T TON LP 12 ( Thi gian 90 pht ) PHN CHUNG CHO TT C TH SINH

Bi 1: (3 im) Cho hm s 223 += xxxy

1) Kho st s bin thin v v th hm s. 2) Bin lun theo m s nghim ca phng trnh:

0223 =++ mxxx Bi 2: (2 im) Gii cc phng trnh sau

1) 0424.2 1 = +xx 2) 01log2log3 9

29 = xx

Bi 3: (2 im) Cho hnh chp tam gic u S.ABC c cnh y l a v cnh bn l 2a. 1) Chng minh SA vung gc vi BC. 2) Tnh din tch mt cu ngoi tip hnh chp S.ABC.

PHN RING CHO TH SINH THEO MI BAN A. Theo chng trnh ban Khoa hc t nhin (cc lp t 12A1 n 12A7)

Bi 4A: (1 im) Tm gi tr ln nht v gi tr nh nht ca hm s

xxy 2cos.sin= trn on ];0[ Bi 5A: (1 im) Tm tt c cc gi tr ca tham s m phng trnh sau c 4

nghim phn bit: 0loglog2 323 =+ mxx

Bi 6A: (1 im) Cho mt hnh tr c trc l OO' , mt mt phng (P) bt k song song vi trc OO' ct hnh tr theo thit din l hnh ch nht ABCD. Gi I l tm hnh ch nht ABCD, bit rng bn knh ng trn ngoi tip hnh ch nht ABCD bng bn knh ng trn y ca hnh tr. Chng minh I thuc mt cu ng knh OO'

B. Theo chng trnh ban C bn v ban Khoa hc x hi (cc lp t 12B1 n 12B10 v 12C)

Bi 4B: (1 im) Cho hm s xey sin= , chng minh rng:

0''cos'.sin. =+ yxyxy

(vi 'y v ''y ln lt l o hm cp mt v o hm cp hai ca ca hm s) Bi 5B: (1 im) Tm gi tr ln nht v gi tr nh nht ca hm s

xe

xy 2).

4

1

2( = trn an [-1;1]

Bi 6B: (1 im) Cho mt hnh tr c trc l OO' v c chiu cao bng bn knh y v bng 50cm. Mt on thng AB di 100cm vi A thuc ng trn (O) v B thuc ng trn ( O' ), tnh khong cch gia AB v OO'.

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TRNG THPT NG HUY TR KIM TRA HC K I NM HC 2008-2009 CHNH THC Mn TON LP 12

Thi gian: 90 pht, k c thi gian giao . -------------------------------------------

A. PHN CHUNG: (7,0 im) Phn dnh cho tt c hc sinh hc chng trnh chun v chng trnh nng cao.

Cu I: (3,0 im) Cho hm s 3y = x - 3x - 1 (1)

1) Kho st v v th (C) ca hm s (1). 2) Da vo th (C), bin lun theo tham s m s nghim ca phng trnh:

3- x + 3x +1+ m = 0 . 3) Vit phng trnh tip tuyn ca th (C) ti tip im c honh x0 = 2 .

Cu II: (3,0 im)

1) Rt gn biu thc: A = 2+ 7

2+ 7 1+ 7

14

2 7.

2) Gii cc phng trnh sau:

a) x x9 -10.3 + 9 = 0 b) 1 44

1log (x -3) = 1+ log

x

Cu III: (1,0 im) Cho hnh chp S.ABC c y ABC l tam gic vung ti C, cnh SA vung gc vi

y, gc ABC bng 060 , BC = a v SA = a 3 . Tnh th tch ca khi chp . B. PHN RING: (3,0 im)

Hc sinh hc chng trnh no ch c lm phn dnh ring cho chng trnh . I. Dnh cho hc sinh hc chng trnh chun:

Cu IVa : (3,0 im) 1) Tm gi tr ln nht v gi tr nh nht ca hm s 1

2

y = log (x +1) trn on [1 ; 3].

2) Cho hnh nn c nh S, mt y l hnh trn tm O, ng knh AB = 2R v tam gic SAB vung.

a) Tnh th tch khi nn gii hn bi hnh nn .

b) Gi s M l mt im thuc ng trn y sao cho 0BAM 30= . Tnh din tch thit din ca hnh nn to bi mt phng (SAM). II. Dnh cho hc sinh hc chng trnh nng cao:

Cu IVb: (3,0 im)

1) Tm gi tr ln nht v gi tr nh nht ca hm s 3 21 1 12 2 2

1y = log x + log x - 3log x +1

3 trn

on 1

;44

.

2) Cho mt cu tm O, bn knh bng R. Xt mt hnh nn ni tip mt cu c bn knh y bng r. Tnh din tch xung quanh hnh nn.

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S GD&T Tha Thin Hu KIM TRA HC K I Trng THPT Hng Vinh Nm hc 2008-2009 MN TON LP 12

Thi gian lm bi: 90' Cu 1: (2,5) Cho hm s: 3 23 1= +y x x 1/ Kho st v v th (C) ca hm s 2/ Vit phng trnh tip tuyn vi (C) ti im c honh l nghim ca phng trnh " 0y =

Cu 2: (1)

Tm gi tr ln nht v nh nht ca hm s: 3 21

2 3 13

y x x x= + + trn on [-1;2]

Cu 3: (1)

Gii phng trnh: 344 21

2

1

=+ xx

Cu 4: (2,5) Cho hnh chp t gic u S.ABCD c cnh y bng 2a, cnh bn hp vi y mt gc a/ (1,25) Tnh th tch ca khi chp S.ABCD

b/ (1,25) Xc nh tm v bn knh ca mt cu ngoi tip hnh chp S.ABCD

PHN T CHN: HC SINH CHN 1 TRONG HAI CU 5A HOC 5B Cu 5A: ( DNH CHO HC SINH BAN A)

1/ (1) Tm cc tim cn ca th hm s: = + 2 1y x x

2/ (1) Gii bt phng trnh + >2

3 93

5log 18 log log

3 2

xx x

3/ (1) Ct mt xung quanh ca mt hnh nn theo mt ng sinh, ri tri ra trn mt mt phng, ta c mt na hnh trn c ng knh bng 10cm. Tnh th tch ca khi nn gii hn bi hnh nn . Cu 5B: ( DNH CHO HC SINH BAN C BN)

1/ (1) Tm cc tim cn ca th hm s +

=

2 1

(1 )

xy

x x

2/ (1) Gii bt phng trnh: +

PHN II: Hc sinh thuc ban no ch lm phn dnh ring cho ban (3) A. Ban KHTN:

Cu 52: Trn mt phng (P) c gc vung xOy, on SO=a vung gc vi (P). Cc im M, N chuyn ng trn Ox, Oy sao cho ta lun c OM+ON=a

a. Xc nh v tr ca M, N th tch ca t din S.OMN ln nht. b. Khi t din S.OMN c th tch ln nht , xc nh tm v tnh bn knh mt cu ngoi

tip t din S.OMN. Cu 61: Gii h phng trnh:

2 2 25log log log 2

22

x y

xy

= =

B. Ban KHXH-NV v Ban C Bn: Cu 51: Gii bt phng trnh:

22 35 6

6 5

x x

Cu 62: Cho hnh chp S.ABCD c y l hnh vung cnh a, cnh bn SA vung gc vi mt phng y, cnh bn SB= 3a

a. Tnh th tch ca hnh chp S.ABCD b. Xc nh tm, bn knh ca mt cu ngoi tip hnh chp S.ABCD

-----------------------------Ht------------------------------------



S GD - T THA THIN HU TRNG THPT HO CHU

KIM TRA HC K I NM HC : 2008 - 2009

MN: TON - KHI 12 Thi gian : 90 pht

( khng tnh thi gian giao ) ......................................................

I .PHN DNH CHUNG CHO C HAI BAN ( 7. 0 im )

Cu 1: (3.0 im) : Cho hm s 1

23

+=

x

xy c th ( )C

a. Kho st v v thi ( )C . b.Tm cc im trn th ( )C ca hm s c ta l nhng s nguyn. c. Chng minh rng trn th ( )C khng tn ti im no m ti tip tuyn vi th i qua

giao im ca hai tim cn . Cu 2: (2.0 im) : Gii cc phng trnh sau

a. 22x+1 9.2x + 4 = 0 b. 03log23log2 3 =+ xx

Cu 3: (2.0 im) : Trong khng gian cho tam gic ABC vung ti A., c cnh BC = 2a; 2aAB = . Tnh din tch xung quanh ca hnh nn trn xoay khi quay ng gp khc CBA xung quanh trc l ng thng cha cnh AB. Tnh gc nh ca hnh nn . II. PHN DNH RING CHO TNG BAN ( 3. 0 im )

A. Phn dnh ring cho ban c bn:

Cu 1: (1,50 im) : Cho hnh chp S.ABC c y l tam gic vung ti A, BC = 2a ; cc cnh bn SA =

SB = SC = 3a . Xc nh tm v tnh din tch mt cu ngoi tip hnh chp.

Cu 2: (1,50 im) : Cho hm s ( ) ( )3

1231

3

1 23 += xmxmmxy . Vi gi tr no ca m th hm s c

cc i v cc tiu, ng thi honh cc im cc i v cc tiu 1x , 12x tha mn iu kin

12 21 =+ xx .

B. Phn dnh ring cho ban KHTN: ( 3. 0 im )

Cu 1: (1,50 im) : Cho hnh chp S.ABCD c ABCD l hnh vung cnh a. SAB l tam gic u v vung gc vi y. Xc nh tm v tnh din tch mt cu ngoi tip hnh chp.

Cu 2: (1,50 im) : Cho hm s ( )

mx

mmxmxy

+

++++=

432 22 . Tm tt c cc gi tr ca tham s m

hm s c hai cc tr v hai gi tr ny tri du.

-----------------------------------Ht-----------------------------------



TRNG THPT NGUYN CH THANH THI HC K I T TON MN TON LP 12 NM HC 2008-2009

(Thi gian lm bi : 90 pht , khng k thi gian giao ).

I/PHN CHUNG CHO TT C HC SINH(7 im) : BI 1: Cho hm s 396 23 ++= xxxy c th (C). 1.(2im) Kho st s bin thin v v th (C) ca hm s. 2.(1.25im) Gi A l im thuc th (C) c honh bng 4 , vit phng trnh tip tuyn vi th (C) ti im A. Tip tuyn ny ct li th (C) ti im B (B khc A) , tm ta im B.

BI 2.(1im) Tm gi tr ln nht , gi tr nh nht ca hm s x

xy

ln= trn on [1;e2 ]

BI 3 . Cho hnh vung ABCD c cnh bng a , I l trung im ca AB , l ng thng qua I v

vung gc vi mp(ABCD).Trn ly mt im S sao cho SI = 2

3a.

1.(0.75im) Tnh th tch V ca khi chp S.ABCD theo a. 2.(1im) Gi (N) l hnh nn trn xoay thu c khi quay ng gp khc SAI xung quanh SI . Tnh din tch xung quanh ca hnh nn (N) theo a. 3.(1im) Xc nh tm v tnh theo a bn knh ca mt cu (S) ngoi tip hnh chp S.ABCD. II/PHN DNH RING CHO HC SINH TNG BAN (3im) : Hc sinh hc theo chng trnh no th lm theo ca chng trnh . A.Hc sinh hc theo chng trnh nng cao :

BI 4a. (2im) Gii h phng trnh sau :

+=+

=+1

22

2

3log2log.31

133log2yy

y

xx

x

BI 5a. (1im) Cho phng trnh 09).1(12).12(16 =+++ xxx mm . Tm m phng trnh c hai nghim tri du. B.Hc sinh hc theo chng trnh chun : BI 4b Gii cc phng trnh sau : 1.(1im) 013.83 22 =++ xx . 2.(1im) 8log3)27(log)113(log 555 +=+ xx . BI 5b .(1im) Gii bt phng trnh sau 032log12log2log.2.3log.2 2

22

52

222 >+++

++ xxxx xxx .

-----------------------------------Ht-----------------------------------



S GD&T TT Hu KIM TRA HC K I NM HC 2008 -2009 Trng THPT Cao Thng MN: TON - KHI 12 - BAN C BN Thi gian: 90 pht, khng k thi gian giao ------------------------------------- Cu 1 (3,0 im)

Cho hm s: 23

+=

x

yx

, gi th hm s l (C).

a) Kho st s bin thin v v th (C) ca hm s. b) Vit phng trnh tip tuyn vi th (C) ti giao im ca (C) vi trc tung. Cu 2 (1,0 im) Tm gi tr ln nht v gi tr nh nht ca hm s 3 2( ) 8 16 9f x x x x= + + trn on

[ ]1;3 . Cu 3 ( 2,0 im) Gii cc phng trnh sau: a) 4 2 12 2 5 3.5x x x x+ + ++ = + b) 2 2 2log ( 3) log ( 3) log 7x x+ + = Cu 4 ( 1,0 im) Tnh (1 )sinx x dx Cu 5 ( 3,0 im) Cho hnh chp S.ABC c y ABC l mt tam gic u cnh bng a, SA = a v SA vung gc vi mt phng (ABC). a) Tnh th tch khi chp S.ABC theo a. b) Xc nh tm O v tnh bn knh r ca mt cu ngoi tip hnh chp S.ABC theo a.

-----HT----



S GD-T Tha Thin Hu KIM TRA HC K I ( Nm hc 2008 2009) Trng THCS-THPT Hng Giang Mn : Ton 12- C Bn Thi gian : 90 Pht (Khng k thi gian giao )

Cu 1. ( 3 im)

Cho hm s 3 3 1y x x= + (C) 1. Kho st v v th (C) ca hm s. 2. Bin lun theo k s nghim ca phng trnh 3 3 1x x k + = 3. Vit phng trnh tip tuyn ca th (C) ti giao im ca (C) vi trc tung. Cu 2. ( 1 im) Tm gi tr ln nht v gi tr nh nht ca hm s

4 3 23 -8 6 -1y x x x= + trn on [-2; 2] Cu 3. (2 im) Gii cc phng trnh sau:

1.

2 131 8

8

xx

+ =

2. 2ln 2 ln 3 0x x+ = Cu 4. ( 1 im)

Tm tp xc nh ca hm s sau: 2

1

3

lo g ( 2 )y x x= +

Cu 5. ( 1 im) Ct mt hnh tr bng mt mt phng qua trc ca n ta c mt thit din l mt hnh

vung cnh bng 10cm. Tnh din tch xung quanh ca hnh tr v th tch ca khi tr c to

thnh t hnh tr .

Cu 6. ( 2 im)

Cho hnh chp S.ABC c y ABC l mt tam gic vung ti B, SA (ABC). Bit

SA=BC=2a, AB=a.

1. Tnh th tch ca khi chp S.ABC.

2. Ly im M ty nm trn ng trn ngoi tip tam gic ABC. Chng t rng im M

lun nm trn mt cu ngoi tip hnh chp S.ABC.

-----------------Ht------------------



S GD T THA THIN HU. TRNG THPT HNG LM.

T TON TIN (THPT). KIM TRA HC K I, nm hc: 2008 2009.

Mn: Ton. Lp : 12.

Thi gian: 90 Cu 1: (2 im)

Tm gi tr ln nht, gi tr nh nht ca hm s sau trn on [ -4 ; 2]. y = x3 + 3x2 9x 2.

Cu 2: (3 im) a, Kho st s bin thin v v th ca hm s sau:

2 3

1

xy

x

=

b, Vi gi tr no ca m th phng trnh sau c nghim :

2 3

1

xm

x

=

Cu 3: (2 im) Gii cc phng trnh sau:

a, 2 5 4(0,5) 1x x + = .

b, log7( 2x 5) = log7( 4x 5 ). Cu 4: ( 3 im)

Cho khi chp tam gic S.ABC. M,N,P ln lt l trung im ca cc cnh AB, BC, CA tm t s th tch ca khi chp S.MNP v th tch ca khi chp S.ABC?

-----------------Ht------------------



S GD - T THA THIN HU KIM TRA HC K I NM HC 2008 - 2009 TRNG THPT TAM GIANG Mn: TON - LP 12 Thi gian: 90 pht (khng k thi gian giao ) I. PHN CHUNG CHO TT C HC SINH: ( 7 IM ) Cu I: (2 im) Cho hm s y = x3 - 3x2 + 5 (1) 1) Kho st s bin thin v v th (C) ca hm s (1). 2) Da vo th (C) ca hm s (1), tm tham s m phng trnh: 23t - 3.4t + 5 = m (t l n) c nghim. Cu II: (2 im) 1) Tm gi tr nh nht v gi tr ln nht ca hm s y = x4 - 8x2 + 15 trn on [-1; 3]. 2) Tnh o hm ca cc hm s sau: a) y = x2.e4x b) y = ex.ln(2 + sinx) Cu III: (1 im) Gii cc phng trnh sau:

1) 2x x 14 64 + = . 2) 3 3log x log (x 2) 1+ =

Cu IV: (2 im) Cho hnh lng tr u t gic ABCD.ABCD c di cnh y l 2a, cnh bn l a. 1) Chng minh hai khi t din ABDA v CBDC bng nhau. 2) Tnh theo a th tch ca khi lng tr ABCD.ABCD. 3) Gi M l trung im ca cnh AD, S l tm ca hnh vung ABCD. Tnh theo a th tch ca khi chp S.MBCD. II. PHN RING: ( 3 IM )

A. Phn dnh cho hc sinh hc theo sch Ton 12 nng cao Cu Va: (3 im)

1) Vit phng trnh tip tuyn ca th hm s 2x x 2

yx 2

=

+ bit tip tuyn song song

vi ng thng 3x + y - 2 = 0.

2) Gii phng trnh: 26 ln x

2 2log e 5.log x+ = .

3) Cho hnh chp u t gic S.ABCD c tt c cc cnh u bng a 2 . Tnh theo a din tch ca mt cu v th tch ca khi cu ngoi tip hnh chp S.ABCD cho.

B. Phn dnh cho hc sinh hc theo sch Ton 12 chun Cu Vb: (3 im)

1) Vit phng trnh tip tuyn ca th hm s x 4

yx 1

=

bit tip tuyn song song vi

ng thng 3x - 4y = 0.

2) Gii phng trnh: 2x x log26 2 5.10+ = . 3) Cho hnh chp u t gic S.ABCD c tt c cc cnh u bng a 2 . Tnh theo a din tch xung quanh v th tch ca hnh nn ngoi tip hnh chp S.ABCD cho.

. Ht



PHN II: TUYN TP CC THI HC K I

MT S S GIO DC TRN TON QUC



S GIO DC V O TO

QUNG NGI

CHNH THC

KIM TRA HC K I NM HC 2012-2013 MN: TON - LP12

Thi gian lm bi: 120 pht (Khng k giao )

========================================================== I/ PHN CHUNG CHO TT C TH SINH: (7.0 im) Cu 1: (3.0 im) Cho hm s 3( ) 3 2y f x x x= = + 1) Kho st s bin thin v v th (C) ca hm s cho.

2) Da vo th (C), bin lun theo m s nghim ca phng trnh sau: 3 3 0x x m + = . Cu 2: (1.0 im) Tm gi tr ln nht, nh nht ca hm s 2( 3) xy x e= trn on [ ]0;2 . Cu 3: (3.0 im) Cho hnh chp S.ABC c y l tam gic ABC vung ti B. Cnh bn SA vung gc vi mt phng

(ABC) v SA = 2a, 2 3 .AB BC a= = Gi I l trung im ca cnh SC. 1) Tnh th tch khi chp S.ABC.

2) Trn cnh SB ly im M sao cho 2

3SM SB= . Tnh th tch khi t SAMI.

3) Chng minh rng I l tm mt cu ngoi tip hnh chp S.ABC. Tnh din tch mt cu v th tch khi cu c to nn bi mt cu . II/PHN RING:(3.0 im) Th sinh ch c lm mt trong hai phn ring. (Phn A hoc phn B) Phn A. Theo chng trnh chun Cu 4a: (1.0 im)

Tnh o hm ca hm s : 23 1 ln. xy x e +=

Cu 5a: (2.0 im)

1) Gii phng trnh: 29 3 8 0x x+ + = .

2) Gii bt phng trnh: 12

1log 0

3

x

x

+

.

Phn B. Theo chng trnh nng cao Cu 4b: (1.0 im)

Cho hm s sin xy e= . Chng minh rng: .cos .sin 0y x y x y + = .

Cu 5b: (2.0 im)

1) Gii bt phng trnh:

22 33 2

2 3

x x >

.

2) Gii h phng trnh: 3

42

log (2 1)

log 3 1 2log ( 2) 4y

x y

x

=

+ + + =.

----------------------------------------------------Ht----------------------------------------------------- (Cn b coi thi khng gii thch g thm)



S Gio dc v o to KIM TRA HC K I NM HC 2012-2013 Qung Nam Mn TON-Lp 12 THPT ====== Thi gian: 120 pht (khng k thi gian giao ) I. PHN CHUNG CHO TT C TH SINH (7,0 im) Cu I (3,0 im) Cho hm s y = x3 - 4x2 + 4x

1) Kho st s bin thin v v th (C) ca hm s cho. 2) Da vo th (C), hy bin lun theo m s nghim ca phng trnh x3 - 4x2 + 4x + m = 0 , m R

Cu II (2,0 im) 1) Tm gi tr ln nht v gi tri nh nht ca hm s y = x4 -8x2 + 10 trn on [ -3 ; 1 ]. 2) Gii phng trnh 52x+1 11 .5x + 2 = 0 .

Cu III (2,0 im) Cho hnh chp S.ABC c SA = SB = SC = a, cnh bn nghing vi mt phng y mt gc bng 600 . Mt y ABC l tam gic vung cn ti A.

1) tnh th tch khi chp S.ABC theo a. 2) Xc nh tm v tnh th tch khi cu ngoi tip hnh chp cho theo a.

II. PHN RING (3,0 im) Hc sinh ch c lm mt trong hai phn sau: 1. Theo chng trnh chun chn Cu IV.a v Cu V.a: Cu IV.a (2,0 im)

1) Rt gn biu thc A =

++

3

4

3

2

3

1

3

2

3

2

3

1

bbaaba , vi a,b >0.

2) Gii phng trnh 2loglog3log2

122

2=++ xxx .

Cu V.a (1,0 im) Cho hnh nn nh S, bn knh ng trn y bng a. Thit din ca hnh nn qua nh S l

tam gic SAB v cch O mt khong bng 3

a, gc BAO bng 300 vi O l tm ca ng trn y .

Tnh th tch khi nn chi theo a. 2. Theo chng trnh Nng cao chn Cu IV.b v Cu V.b: Cu IV.b (2,0 im)

1) Rt gn biu thc A=

+

+

2

1

2

1

4

1

4

1

4

1

4

1

bababa , vi a,b >0

2) Gii phng trnh 10)1(log)1(log 3222

4 =+++ xx . Cu V.b (1,0 im) Cho hnh nn nh S,chiu cao SO = a. vi O l tm ca ng trn y. Thin din ca hnh

nn qua nh S l tam gic SAB v cch O mt khong bng 2

a , gc BAO bng 600 . Tnh th tch

khi nn cho theo a.

= = = = =Ht= = = = =



S GIO DC V O TO KIM TRA HC K I LP 12 THPT KIN GIANG MN : TON ( thi c 01 trang) Ngy kim tra: 13/12/2012

Thi gian lm bi : 90 pht I.PHN CHUNG CHO CC TH SINH

Cu I: (3,0 im) Cho hm s y = .12

1

4

1 24 + xx

1) Kho st s bin thin v v th ( C) ca hm s 2) Xc nh m phng trnh x4 2x2 + 4 m = 0 c bn nghim phn bit

Cu II (3,0 im) Cho hinh chp S.ABC c SA vung gc vi mt phng (ABC), y ABC l tam giac u, cnh a v SB = a 2

1) Tnh th tch khi chp S.ABC theo a 2) Tnh in tch mt cu qua cc nh hnh chp S.ABC theo a 3) Tnh khong cch gia hai ng thng AB v SC, theo a

Cu III: (1 im) Tm cc tr ca hm s y=x

x

ln

II PHN RING (3,0 im) Th sinh ch c lm mt trong hai phn ( phn 1 hoc phn 2) 1. Theo chng trnh Chun: Cu IV.a (2,0 im) 1) Gii phng trnh 9x+1 + 324.3x-2 + 27 = 0 2) Gii bt phng trnh .0)7(log)34(log 2

2

2

1



S GIO DC V O TO AN GIANG

THI HC K I Nm hc: 2012- 2013

Mn: TON 12 Thi gian: 150 pht (Khng k thi gian pht )

( chung cho c chng trnh Chun v Nng cao) CHNH THC A. PHN CHUNG CHO TT C TH SINH (8,0 im) Bi 1: (3,0 im) Cho hm s

4 22 2y x mx= + (1) a) Kho st v v th hm s (1) khi 2m = . b) Tm m hm s (1) c cc i ti 0.x =

Bi 2: (1,0 im)

Tm gi tr ln nht v gi tr nh nht ca hm s 1

2

xy

x

+=

trn on [ ]1;1 . T suy ra:

cos 12

cos 2

a

a

+

vi mi a .

Bi 3: (2,0 im)

a) Rt gn: 33 4 5log 25.log 3 .log 2A = .

b) Gii phng trnh: 2 213.9 4.3 9 0.x x + =

Bi 4: (2,0 im) Cho hnh chp tam gic u S.ABC c di cnh y bng a . Tam gic SAB vung cn ti S.

a) Tnh th tch khi chp S.ABC theo a . b) T B k ng cao BH ca tam gic ABC. Tnh theo a th tch khi t din HSBC, t

suy ra khong cch t H n mt phng (SBC). B. PHN T CHN (Th sinh ch c chn mt trong hai phn sau): (2,0 im) Phn I: Bi 5.I:

a) (1,0 im) Gii phng trnh: ( ) ( )2 2log 1 log 1 2x x+ =

b) (1,0 im) Tm im cc tr hm s: 2

1ln

3

xy

x

=

+

Phn II: Bi 5.II:

a) (1,0 im) Gii phng trnh: ( ) ( )2 2log 1 log 1 2x x+ =

b) (1,0 im) Tnh ( ) 82 4 10,5 .log 2A = ----- Ht -----

SBD:. S PHNG:



S GIO DC V O TO THNH PH NNG

KIM TRA HC K I NM HC 2012-2013

MN: TON - LP12

Thi gian lm bi: 90 pht (Khng tnh thi gian giao ) I. PHN CHUNG CHO TT C TH SINH (7,0 im) Cu I (2,5 im)

Cho hm s ( ) 4 21 2 3.4

y f x x x= = +

1) Kho st s bin thin v v th (C) ca hm s. 2) Vit phng trnh tip tuyn ca th (C) ti im c honh l nghim ca

phng trnh ( )// 0f x = . Cu II (1,5 im)

1) Cho hm s 2x m

yx

+= ( m l tham s). Xc nh m hm s ng bin trn mi khong

xc nh ca n.

2) Gii phng trnh: 1 12 24 4 3

x x+ = .

Cu III (3,0 im) Cho khi chp t gic u S.ABCD c cnh y bng a , ng cao SH v mt bn to vi

y mt gc 060 . Gi M l trung im ca on SB. 1) Tnh th tch khi chp S.ABCD. 2) Tnh din tch mt cu ngoi tip hnh chp S.ABCD. 3) Gi O l tm mt cu ngoi tip hnh chp S.ABCD, tnh t s th hai khi chp M.ABH v

S.AMO. II. PHN RING (3,0 im): Th sinh ch c chn mt trong hai phn (phn 1 hoc phn 2) 1. Theo chng trnh chun Cu IVa (3,0 im)

1) Cho hm s ( ) ( )3 23 1y f x x m x m= = + + + ( m l tham s). Xc nh m hm s t cc tiu ti 1.x =

2) Gii bt phng trnh: ( ) ( )22 12

log 5 10 log 6 8 0.x x x+ + + +

3) Tm nguyn hm ca hm s ( ) 2 32 1.f x x x= 2. Theo chng trnh nng cao Cu IVb (3,0 im)

1) Tm cc im cc tr ca th hm s ln 2 .y x x= +

2) Gii h phng trnh: 2 2 22log 2log 5log 2

2

x y

xy

=

=

3) Cho hm s sin .xy e= Chng minh rng: // /sin cos .y y x y x= ----- Ht -----



S GIO DC V O TO QUNG TR

CHNH THC

KIM TRA HC K I LP 12 THPT Kha ngy 27 thng 12 nm 2012

Mn: Ton. Thi gian: 90 pht (Khng k giao )

I. PHN CHUNG CHO TT C TH SINH (7,0 im)

Cu 1. (3,0 im) Cho hm s ( ) 4 22 1y f x x x= = + + (1) 1) Kho st s bin thin v v th (C) ca hm s (1).

2) Tm m phng trnh 4 2 32 log 0x x m + = c 4 nghim phn bit. Cu 2. (1,5 im)

1) Vit phng trnh tip tuyn ca th (C): 2 1

1

xy

x

=

+ bit tip tuyn song song vi ng

thng d: 4.y x= +

2) Tm gi tr ln nht, nh nht ca hm s ( ) 3 23 9 3y f x x x x= = + + trn on [ ]2;2 . Cu 3. (2,5 im) Cho hnh chp t gic u S.ABCD, y ABCD l hnh vung cnh a , gc gia mt bn v mt y bng 600.

1) Tnh th tch khi chp S.ABCD theo a 2) Gi M, N ln lt l trung im ca cnh y AB v cnh bn SD. Tnh th tch khi chp

CDNM. II. PHN RING (3,0 im) Th sinh c chn mt trong hai phn sau: 1. Theo chng trnh Chun Cu 4. 1) (1,5 im) Gii phng trnh: ( ) ( )3 33log 2 1 log 1 2.x x =

2) (1,5 im) Gii phng trnh: ( ) ( )2 1 2 1 2 2 0x x+ + = . 2. Theo chng trnh Nng cao

1) (2,0 im) Gii phng trnh: 2 24 16 10.2x x + = .

2) (1,0 im) Tm m phng trnh ( ) ( )2lg lg 1 0x mx x+ = c nghim. ----- Ht -----



S GD&T NG NAI

CHNH THC

KIM TRA HC K I LP NM HC 2012-2013 Mn: Ton (phn t lun) Thi gian lm bi: 90 pht

ny gm 1 trang I/ PHN CHUNG CHO TT C TH SINH: (5,0 im) Cu 1: (3.0 im) Cho hm s 3 2( ) 6 12 6y f x x x x= = +

1) Kho st s bin thin v v th (C) ca hm s cho. 2) Vit phng trnh tip tuyn ca th (C) ti im c honh 2x = .

Cu 2: (2,0 im)

1) Cho hm s 4 22 9y x mx= + + , vi m l tham s thc. Tm cc gi tr ca m th hm s cho v trc honh c 4 giao im phn bit.

2) Cho hnh chp tam gic S.ABC c SA vung gc vi mt phng (ABC), gc gia ng thng SC vi mt phng (ABC) bng 600. Bit y ABC l tam gic vung cn ti B v BA BC a= = , vi a l s thc dng cho trc. Tnh th tch khi chp S.ABC theo a .

II. PHN RING- PHN T CHN (2,5 im) Th sinh ch c lm mt trong hai phn (phn A hoc phn B) Phn A (Theo chng trnh Chun) Cu 3: (2,5 im)

1) Cho hnh nn trn xoay c chiu cao bng 8 (cm) v di ng sinh bng 10 (cm). Tnh bn knh r ca ng trn y hnh nn trn xoay cho. Tnh din tch ton phn ca hnh nn trn xoay cho.

2) Gii phng trnh 2 13 8.3 3x x+ = + . Phn B (Theo chng trnh Nng cao) Cu 3b: (2,5 im)

1) Cho mt cu (S) c tm O v bn knh bng R. Cho mt phng (P) ct mt cu (S) theo giao tuyn l ng trn c bn knh bng 9r = (cm), bit khong cch t tm O n mt phng (P) bng 12d = (cm). Tnh bn knh R ca mt cu (S) cho. Tnh din tch ca mt cu (S) cho.

2) Cho hai hm s 3 5

1

xy

x

=

+ c th l (E) v 2y x m= + c th l (P), vi m l tham s

thc. Tm cc gi tr ca m th (E) tip xc vi th (P). ----- Ht -----

H v tn th sinh:................................................. Ch k gim th 1:.......................................... S bo danh:.........................................................



S GIO DC V O TO NG THP

CHNH THC

( thi gm c 01 trang)

KIM TRA CHT LNG HC K I Nm hc 2012- 2013

Mn thi: TON Lp 12 Thi gian: 120 pht (khng k thi gian pht )

Ngy thi: 14/12/2012 I. PHN CHUNG CHO TT C TH SINH (7,0 im)

Cu I (3,0 im). Cho hm s 4 22 1y x x= (1) 1) Kho st v v th (C) ca hm s (1).

2) Vi gi tr no ca m th phng trnh 4 22 0x x m = c 2 nghim. Cu II (2,0 im).

1) Tnh gi tr biu thc ( )4

55 2 3 2log 125

.

aM

a a += + , ( )0a > .

2) Tm gi tr ln nht, gi tr nh nht ca hm s 3 23 9 7y x x x= + trn on [ ]2;2 . Cu III (2,0 im). Cho hnh chp t gic u S.ABCD c cnh y bng a , gc gia cnh bn SA v mt y bng 600.

a) Tnh th tch khi chp S.ABCD theo a . b) Tnh din tch xung quanh v th tch hnh nn ngoi tip hnh chp S.ABCD.

II. PHN RING- PHN T CHN (3,0 im) Th sinh ch c lm mt trong hai phn (phn 1 hoc phn 2) 1. Theo chng trnh Chun Cu IV.a (2,0 im).

1) Gii phng trnh: ( ) ( )2 2log 5 log 2 3.x x + + =

2) Gii bt phng trnh:

2 11 1

12.3 3

x x + >

2. Theo chng trnh Nng cao Cu IV.b (2,0 im).

1) Cho hm s ( )2ln 1y x x= + + , chng minh rng: 2/1 1xy = + . 2) Cho hm s

1

1

xy

x

+=

c th (C) v ng thng d: 2 0x y m + = , nh m ng

thng d ct (C) ti hai im phn bit A, B sao cho di AB ngn nht.

Th sinh khng c s dng ti liu. Gim th khng gii thch g thm.

----- Ht -----

H v tn th sinh:.......................................................... S bo danh:................................. Ch k gim th:.........................................................



S GIO DC V O TO LNG SN

THI CHNH THC

KIM TRA HC K I LP 12 THPT NM HC 2012-2013 MN: TON

Ngy thi: 28/12/2012 Thi gian: 120 pht (Khng k thi gian giao )

thi gm 01 trang, 5 cu I. PHN CHUNG DNH CHO MI TH SINH (3 cu, t cu 1 n cu 3) Cu 1 (3,0 im)

Cho hm s: 2 3

1

xy

x

+=

+

1. Kho st s bin thin v v th hm s. Gi th l (C). 2. Xc nh a ng thng d: 2y ax= l tip tuyn ca th (C).

Cu 2 (3,0 im)

1. Gii phng trnh: 125 5 6 0.x x+ = 2. Gii phng trnh: ( )22log log 2 1.x x= + +

3. Tm gi tr ln nht v gi tr nh nht ca hm s: 225y x= . Cu 3 (1,0 im)

Tm m phng trnh: ( ) ( )22 2 2 4 2 2 3m x x x x x m+ = + c nghim. II. PHN RING: Th sinh chn mt trong 2 phn: phn A hoc phn B Phn A: Theo chng trnh chun Cu 4a (2,0 im) Cho hnh chp S.ABC c y AB l tam gic u cnh 2a , SAB l tam gic u v mt phng (SAB) vung gc vi mt phng (ABC).

1. Tnh th tch khi chp S.ABC theo .a 2. Tnh khong cch gia hai ng thng AB v SC theo .a

Cu 5a (1,0 im)

Tnh ( )328 1 dx x x+ Phn B: Theo chng trnh nng cao Cu 4b (2,0 im) Cho hnh chp S.ABC c y AB l tam gic u cnh 2a , SAB l tam gic u v mt phng (SAB) vung gc vi mt phng (ABC).

1. Tnh th tch khi chp S.ABC theo .a 2. Tnh din tch mt cu ngoi tip hnh chp S.ABC theo .a

Cu 5b (1,0 im) Tnh ( )3 sin dx x x x+

----- Ht -----



S GIO DC V O TO THNH PH CN TH

chnh thc

KIM TRA GIA HC K I NM HC 2012-2013

MN: TON LP 12

Thi gian: 150 pht (Khng k thi gian pht ) I. PHN CHUNG DNH CHO TT C CC TH SINH (7,5 im) Cu 1 (3,0 im)

Cho hm s ( )4 2 29 10.y mx m x= + + 1) Kho st s bin thin v v th ca hm s khi 1.m = 2) Vi nhng gi tr no ca m th th ca hm s c ba im cc tr,

Cu 2 (3,0 im)

1) Tm cc tim cn ng v tim cn ngang ca th hm s: ( )2

2

2 3

2

x xy f x

x x

+= =

.

2) Tm gi tr ln nht, gi tr nh nht ca hm s: ( ) 22

2

xy f x

x x

+= =

+ + vi [ ]1;1x .

3) Tm cc tr ca hm s: ( ) ( )2 21 .y f x x x= = Cu 3 (2,0 im) Mt hnh chp S.ABCD c y ABCD l hnh vung cnh a , hai mt bn (SAB)

v (SAD) vung gc vi y, gc gia SC v mt (SAB) l vi 04

< < .

1) Chng minh rng: .CSB = 2) Tnh theo a v th tch ca khi chp S.ABCD.

II. PHN RING (2,0 im) Th sinh ch c chn mt phn ring thch hp, nu lm c hai phn ring th c hai phn ring u khng c chm. 1. Theo chng trnh Chun:

Cu 4a (1,0 im) Tm m hm s ( )3

2 2 5 20113

xy x m x= + + + nghch bin trn tp xc

nh ca n. Cu 5a (1,0 im) Cho hm s cosy x x= c th (C). Vit phng trnh tip tuyn ca (C) ti

im ( )0 2x C

= .

2. Theo chng trnh Nng cao:

Cu 4b (1,0 im) Chng minh hm s ( )1

xy f x

x= =

+ ng bin trn mi khong xc nh ca

n, t chng minh: 1 1 1

a b a b

a b a b

+ +

+ + + +.

Cu 5b (1,0 im) Vit cc phng trnh tip tuyn ca ng cong (C): 3 24 4y x x x= + , bit cc tip tuyn ny vung gc vi ng thng d: .y x=

----- Ht ----- Th sinh khng c s dng ti liu. Gim th khng gii thch g thm.

H v tn th sinh:..............................................S bo danh:.............................................. Ch k gim th 1: .................................... Ch k gim th 1: ...........................................

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