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8/12/2019 WaterDistributionDesignAndModeling V8i SS3 SI QandA
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WaterCAD/GEMS, Water
Distribution Design and Modeling -Results Tables/Questions/Answers
Version: V8i (SELECTseries 3)Units: Metric
This document has been created so that you
can easily input your answers into the resultstables and questions.
8/12/2019 WaterDistributionDesignAndModeling V8i SS3 SI QandA
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Feb-12 2 Building a Network with Fire Flows - Q and A
Copyright 2012 Bentley Systems, Incorporated
Building a Network with Fire
Flows - Q and A
Results Table
Run 1 Run 2 Run 3
Pressure at J-1 (kPa)
Pressure at J-6 (kPa)
Pressure at J-9 (kPa)
HGL at J-5 (m)
Velocity in P-1 (m/s)
Velocity in P-6 (m/s)
Flow in P-3 (L/s)
Flow in P-7 (L/s)
Pipe with highest Headloss Gradient
Headloss Gradient in that pipe (m/m)
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Feb-12 3 Building a Network with Fire Flows - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Why is the pressure so high at J-9 even though it is far from the source?
2 Why must you rely so heavily on pipes greater than 150 mm in this fairly
small subdivision?
3 What would really happen if you used the system from run 2 and had a
fire at J-6 that needed 63 L/s?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 4 Building a Network with Fire Flows - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 How does the split in flow between pipes 3 and 7 change as you change
pipe diameters? Why?
5 If another source of water were available along the highway at J-9, how
might that source affect the design?
6 What else could you do to help the pressures during normal demand
periods?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 5 Building a Network with Fire Flows - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
* Some answers may vary between users due to the nature of this schematic
model
1 Why is the pressure so high at J-9 even though it is far from the source?
It is located at the lowest elevation in the system.
2 Why must you rely so heavily on pipes greater than 150 mm in this fairly
small subdivision?
Streets are not laid out with water distribution in mind. More loops would
result in smaller pipes/greater reliability.
3 What would really happen if you used the system from run 2 and had a
fire at J-6 that needed 63 L/s?
You would not be able to get 63 L/s. You would have lower flow with
higher pressures.
4 How does the split in flow between pipes P-3 and P-7 change as you
change pipe diameters? Why?
Initially they are the same but there is more flow through P-3 as it is
increased.
Run 1 Run 2 Run 3
Pressure at J-1 (kPa) 131 26 125
Pressure at J-6 (kPa) 247 -183 163
Pressure at J-9 (kPa) 515 210 462
HGL at J-5 (m) 202 171 197
Velocity in P-1 (m/s) 0.64 4.14 1.49
Velocity in P-6 (m/s) 0.07 3.57 2.01
Flow in P-3 (L/s) 4.3 35.7 48.0
Flow in P-7 (L/s) 4.5 34.9 22.5
Pipe with highest Headloss Gradient P-1 P-1 P-5
Headloss Gradient in that pipe (m/m) 0.003 0.081 0.016
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Feb-12 6 Building a Network with Fire Flows - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
5 If another source of water were available along the highway at J-9, how
might that source affect the design?
You might need to make P-10 larger so it would not be a bottleneck for
the future source.
6 What else could you do to help the pressures during normal demand
periods?
If possible:
Put the tank at a higher elevation (higher static head)
Operate the tank with more water in the tank (higher static head).
Increase the system looping
Add a fire pump to maintain adequate flow/pressure
8/12/2019 WaterDistributionDesignAndModeling V8i SS3 SI QandA
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Feb-12 7Building a Network with Pumps, Tanks, and PRVs - Q and A
Copyright 2012 Bentley Systems, Incorporated
Building a Network with
Pumps, Tanks, and PRVs - Qand A
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions Run 1 AVG Daily
1 What is the hydraulic grade line elevation at junction J-6? At J-4?
2 Which PRVs will be the main feed to the lower zone? As the pressure
drops, which PRV will open last: PRV-1, PRV-2, or PRV-3? Why?
Enter your answer below:
Enter your answer below:
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Feb-12 8Building a Network with Pumps, Tanks, and PRVs - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
3 Is tank T-1 filling or draining?
4 Are there any hydraulic problems in the system?
5 What can you say about the capacity of the system if this output is for
average flow conditions?
6 If the pump is a nominal 63 L/s pump, what can you generally say about its
efficiency?
Enter your answer below:
Enter your answer below:
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Feb-12 9Building a Network with Pumps, Tanks, and PRVs - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Questions Run 2 - Industry Demand of 95 L/s
1 What is the hydraulic grade line elevation at junction J-6? At J-4?
2 Is the pressure adequate in the lower zone?
3 Is tank T-1 filling or draining?
4 Are there any hydraulic problems in the system?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 10Building a Network with Pumps, Tanks, and PRVs - Q andA
Copyright 2012 Bentley Systems, Incorporated
Workshop Review
5 What can you say about the capacity of the system if this output is for
average flow conditions?
6 If the pump is a nominal 63 L/s pump, what can you generally say about its
efficiency?
7 How much more would the pump PMP-1 need to produce to keep the
tank T-1 from draining?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 11Building a Network with Pumps, Tanks, and PRVs - Q andA
Copyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers Run 1
1 What is the hydraulic grade line elevation at junction J-6? At J-4?
J-6 has HGL at 320.5 m
J-4 has HGL at 286.5 m
2 Which PRVs will be the main feed to the lower zone? As the pressure
drops, which PRV will open last: PRV-1, PRV-2, or PRV-3? Why?
PRV-1 will open last because it has a lower HGL setting.
3 Is tank T-1 filling or draining?
Filling
4 Are there any hydraulic problems in the system?
No
5 What can you say about the capacity of the system if this output is foraverage flow conditions?
The system is adequate to meet capacity for average daily conditions.
6 If the pump is a nominal 63 L/s pump, what can you generally say about its
efficiency?
Good efficiency, because it is operating close (within 65.5 L/s) and 39.1 m
of head which is very close to the design point on the pump curve. A more
accurate efficiency % can be determined by consulting the efficiency
curves in the pump manufactures catalog.
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Feb-12 12Building a Network with Pumps, Tanks, and PRVs - Q andA
Copyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers Run 2
1 What is the hydraulic grade line elevation at junction J-6? At J-4?
J-6 has HGL at 304.7 m
J-4 has HGL at 284.8 m
2 Is the pressure adequate in the lower zone?
Yes.
3 Is tank T-1 filling or draining?
Draining
4 Are there any hydraulic problems in the system?
Yes. The pump cannot keep up with demands.
5 What can you say about the capacity of the system if this output is for
average flow conditions?The system is not adequate to meet capacity for average daily conditions
because the tank is draining.
6 If the pump is a nominal 63 L/s pump, what can you generally say about its
efficiency?
The pump does not appear to be operating efficiently. It is operating at
approximately 8.4 L/s above its design operation point. A more accurate
efficiency % can be determined by consulting the efficiency curves in the
pump manufactures catalog.
7 How much more would the pump PMP-1 need to produce to keep thetank T-1 from draining?
Approximately 47.6 L/s
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Feb-12 13Steady State Calibration of Field Measurements - Q and A
Copyright 2012 Bentley Systems, Incorporated
Steady State Calibration of
Field Measurements - Q and A
Results Tables
Static Condition
Node HGLObserved (m)
HGL Run 1 (m) HGL Q=2x (m) HGL C=80%(m)
HGL User 1(m)
HGL User 2(m)
J-1 56.7
J-2 47.5
J-4 48.5
J-8 48.5
J-12 47.9
J-13 47.9
J-23 48.2
J-32 47.9
Fire Flow at J-10
Node HGLObserved (m)
HGL Run 1(m)
HGL Q=2x (m) HGL C=80%(m)
HGL User 1(m)
HGL User 2(m)
J-1 53.6
J-10 39.3
J-13 41.1
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Feb-12 14Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
Fire Flow at J-31
Node HGLObserved (m)
HGL Run 1(m)
HGL Q=2x (m) HGL C=80%(m)
HGL User 1(m)
HGL User 2(m)
J-1 53.3
J-13 38.4
J-31 32.9
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Feb-12 15Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Did adjusting the nodal demands make a difference in the HGL? Why?
2 After which node did you notice a fairly abrupt drop in HGL in the
observed data?
3 Did changing the C-factors have a bigger effect on the static or fire flow
runs?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 16Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 What did you end up adjusting and why?
5 If you could get more data, what data would you get?
Enter your answer below:
Enter your answer below:
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Feb-12 17Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
Static Condition
Node HGL Observed (m) HGL Run 1 (m) HGL Q=2x (m) HGL C=80% (m)
J-1 56.7 50.6 49.2 51.3
J-2 47.5 49.2 47.5 49.4
J-4 48.5 48.8 48.3 48.8
J-8 48.5 48.9 48.6 48.9
J-12 47.9 49.7 48.4 50.1
J-13 47.9 49.4 48.2 49.6
J-23 48.2 49.0 48.3 49.1
J-32 47.9 49.4 48.1 49.6
Fire Flow at J-10
Node HGL Observed (m) HGL Run 1 (m) HGL Q=2x (m) HGL C=80% (m)
J-1 53.6 47.4 43.1 46.8
J-10 39.3 44.4 40.8 42.3
J-13 41.1 45.8 41.5 44.4
Fire Flow at J-31
Node HGL Observed (m) HGL Run 1 (m) HGL Q=2x (m) HGL C=80% (m)
J-1 53.3 45.9 41.7 44.8
J-13 38.4 42.9 38.1 40.2
J-31 32.9 37.9 32.2 32.6
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Feb-12 18Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 Did adjusting the nodal demands make a difference in the HGL? Why?
It had little effect on the static condition run.
It made a significant change on the fire flow runs.
The extra flow caused extra head loss but in the static condition scenario
the velocity was so low the HGL was flat.
2 After which node did you notice a fairly abrupt drop in HGL in the
observed data?
J-1
Closed valve suspected downstream of that valve.
3 Did changing the C-factors have a bigger effect on the static or fire flowruns?
It had a bigger effect on the fire flow runs.
The velocity was too low in static run.
4 What did you end up adjusting and why?
Closed pipe P-22.
Lowered C factors for cast iron to 60%
Changed demands as shown in the table on the next page
5 If you could get more data, what data would you get?
Another fire flow test with several residual gages downstream of P-22.
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Feb-12 19Steady State Calibration of Field Measurements - Q and ACopyright 2012 Bentley Systems, Incorporated
Adjusted Demands (L/s)
Adjusted Demands (L/s)
Node Initial Demand (L/s) Adjusted Demand (L/s)
1 6.3 7.6
2 5.0 6.3
3 3.5 3.5
4 6.3 7.6
8 0 0.6
9 0.9 1.5
10 0 0.6
11 0.6 0.9
12 0.5 2.0
13 0.9 3.2
14 0 1.2
15 0 1.7
16 0.6 0.8
17 1.6 2.2
18 0 1.3
19 0 0.9
20 0 0.8
21 0 1.3
22 0.6 1.6
23 0.3 0.924 0 1.9
25 0.9 1.3
26 0 1.9
27 1.3 1.9
28 0.9 1.3
29 0.9 1.3
30 2.2 2.6
31 0 1.3
32 0.6 1.3
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Feb-12 20 System Design Improvements - Q and A
Copyright 2012 Bentley Systems, Incorporated
System Design Improvements -
Q and A
Results Tables
Diameters
Pipe # Run 1 Run 2 Run 3 Run 4 Run 5 Run 6 Run 7 Run 8
P-2
P-3
P-4
P-5
P-6
P-7
P-8
P-9
P-10
P-11
P-12P-13
P-14
P-15
P-16
P-17
P-18
P-19
P-20
P-21
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Feb-12 21 System Design Improvements - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
Run 1 Run 2 Run 3 Run 4 Run 5 Run 6 Run 7 Run 8
Avg., Max, or Peak?
Fire at
Fire Q (L/s)
Pressure (min) (kPa)
@ node #
HGL @ node (m)
Velocity (max) pipe #
Velocity (max) (m/s)
Cost ($)
Check?
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Feb-12 22 System Design Improvements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Explain why you selected the pipes you did.
2 Do you think the head loss in the 900 mm pipe is significant?
3 Why was node J-14 so troublesome? How did you resolve this problem?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 23 System Design Improvements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Why were 150 mm pipes not seriously considered in this system?
5 Why did node J-4 give you trouble at peak hour?
Enter your answer below:
Enter your answer below:
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Feb-12 24 System Design Improvements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
Diameters
Pipe # Run 1 Run 2 Run 3 Run 4 Run 5 Run 6
P-2 300 400
P-3 300
P-4 300
P-5 300
P-6 300
P-7 300
P-8 200 300
P-9 200 300
P-10 200 300
P-11 200 300
P-12 200 300
P-13 200 300
P-14 200 300
P-15 200 400
P-16 200 300
P-17 200
P-18 200
P-19 200
P-20 200
P-21 200
Run 1 Run 2 Run 3 Run 4 Run 5 Run 6
Avg., Max, or Peak? Peak Peak Peak Avg Max Max
Fire at J-14 J-14
Fire Q (L/s) 230 230
Pressure (min) (kPa) 195 216 249 291 -662 162
@ node # J-4 J-4 J-4 J-4 J-14 J-14
HGL @ node (m) 285 287 291 295 191 276
Velocity (max) pipe # P-8 P-2 P-2 P-2 P-16 P-16
Velocity (max) (m/s) 1.95 1.66 1.30 0.53 7.32 3.25
Cost ($) 3.597 M 4.148 M 4.546 M 4.546 M 4.546 M 4.922 M
Check? OK OK OK
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Feb-12 25 System Design Improvements - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 Explain why you selected the pipes you did.
Used trial and error to meet requirements without excess capacity.
2 Do you think the head loss in the 900 mm pipe is significant?
It is not too bad in this problem.
3 Why was node J-14 so troublesome? How did you resolve this problem?
It is a dead end line at a high elevation.
4 Why were 150 mm pipes not seriously considered in this system?
Too much demand and high fire flows for that pipe size.
5 Why did node J-4 give you trouble at peak hour?
It has the highest elevation.
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Feb-12 26 Automated Fire Flow Analysis - Q and A
Copyright 2012 Bentley Systems, Incorporated
Automated Fire Flow Analysis -
Q and A
Results Tables
Max Day Base Physical Scenario
Junction Node Pressure (kPa) HGL (m)
J-83
J-114
J-138
Fire Flow Analysis - Fire flow analysis run with the existingdistribution system
Node Fire Flow(Available) (L/s)
Pressure(Calculated Residual) (kPa)
Junction withMinimum Pressure(Zone)
Pressure(Calculated ZoneLower Limit) (kPa)
J-115
J-136
J-197
J-237
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Feb-12 27 Automated Fire Flow Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
Auxiliary Results Pipe Data - List pipes with Velocity greater than3 m/s when fire flow node is J-115
Pipe Number Flow (L/s) Velocity (m/s)
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Feb-12 28 Automated Fire Flow Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 In reviewing the pressures from the max day steady state run, what would
you conclude about the pressures in this system?
2 In the fire flow analysis for this system the node which limited the fire flow
was not near the fire, why was this the case?
3 Is the situation described in question #2 typical for most systems?
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Feb-12 29 Automated Fire Flow Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 What pipe(s) had the highest velocity and were most responsible for
limiting fire flows?
5 What was the source of the water during the Max Day run vs. the source
for the Fire Flow run?
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Enter your answer below:
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Feb-12 30 Automated Fire Flow Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
Max Day Base Physical Scenario
Junction Node Pressure (kPa) HGL (m)
J-83 284 558
J-114 643 557
J-138 960 557
Fire Flow Analysis - Fire flow analysis run with the existingdistribution system
Node Fire Flow
(Available) (L/s)
Pressure
(Calculated Residual) (kPa)
Junction with
Minimum Pressure(Zone)
Pressure
(Calculated ZoneLower Limit) (kPa)
J-115 68.01 136 J-114 130
J-136 107.17 387 J-83 130
J-197 72.89 131 J-144 148
J-237 107.17 178 J-83 130
Auxiliary Results Pipe Data - List pipes with Velocity greater than
3 m/s when fire flow node is J-115Pipe Number Flow (L/s) Velocity (m/s)
P-162 73.54 4.2
P-163 73.32 4.2
P-164 73.21 4.1
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Feb-12 31 Automated Fire Flow Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 In reviewing the pressures from the max day steady state run, what would
you conclude about the pressures in this system?
Pressures are generally quite high. More than half of the node pressures
are greater than 600 kPa.
2 In the fire flow analysis for this system the node which limited the fire
flow was not near the fire, why was this the case?
High points other than at the flowed hydrant can control available fire
flow.
3 Is the situation described in question #2 typical for most systems?
This is not typical of systems in flatter terrain.
4 What pipe(s) had the highest velocity and were most responsible for
limiting fire flows?
Non-looped pipes had the highest velocity (e.g. P-162, P-163, and P-164).
However for some cases, head loss back in the other part of the system
controlled fire flow.
5 What was the source of the water during the Max Day run vs. the source
for the Fire Flow run?
Max day flows came from the pump while fire flows came primarily from
the tank. Pumps are limited by their curve.
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Feb-12 32 EPS Modeling and Energy Costing Analysis - Q and A
Copyright 2012 Bentley Systems, Incorporated
EPS Modeling and Energy
Costing Analysis - Q and A
Results Table
Please use graphs and data tables to complete the results table with approximate
values. Do not record zero hour values. Complete this first table after the
extended period simulation runs.
After you complete the energy costing runs, fill in the table below.
Attribute With Tank No Tank ConstandSpeed
No Tank VariableSpeed
Max Pressure J-1 (kPa)
Min Pressure J-1 (kPa)
Max Pressure J-3 (kPa)
Min Pressure J-3 (kPa)
Attribute With Tank No Tank ConstantSpeed
No Tank VariableSpeed
Max W-toW EfficiencyPMP-4 (%)
Min W-to-W EfficiencyPMP-4 (%)
Max Head PMP-4 (m)
Min Head PMP-4 (m)
Daily Energy Cost ($)
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Feb-12 33 EPS Modeling and Energy Costing Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 In the tank control run, why does the pressure vary more at J-1 than J-3?
2 In the variable speed pump run, why does pressure vary more at J-3 than
J-1?
3 What is the number of pump starts during the day for the scenario with
the tank? Is it excessive?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 34 EPS Modeling and Energy Costing Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Do you think the pumps have enough capacity for this application?
5 Which scenario had the lowest energy costs? Which do you think would
have the lowest life-cycle cost?
6 Why was the energy use for the no tank constant head scenario the
greatest? What did the other two scenarios do to lower costs?
7 What was the range of relative speeds for the variable speed pump? If the
target head were increase, how do you think the speed would change?
Enter your answer below:
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 35 EPS Modeling and Energy Costing Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
Attribute With Tank No Tank Constant
Speed
No Tank Variable
Speed
Max Pressure J-1 (kPa) 579 702 537
Min Pressure J-1 (kPa) 406 630 537
Max Pressure J-3 (kPa) 481 692 527
Min Pressure J-3 (kPa) 438 589 495
Attribute With Tank No Tank ConstantSpeed
No Tank VariableSpeed
Max W-toW EfficiencyPMP-4 (%)
71.2 68.9 70.3
Min W-to-W EfficiencyPMP-4 (%)
70.5 43.9 48.8
Max Head PMP-4 (m) 54.9 65.9 50.0
Min Head PMP-4 (m) 51.6 59.6 49.1
Daily Energy Cost ($) 691 985 729
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Feb-12 36 EPS Modeling and Energy Costing Analysis - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 In the tank control run, why does the pressure vary more at J-1 than J-3?
The tank tends to keep pressure constant. The cycling of pumps affects J-
1 the most because of location.
2 In the variable speed pump run, why does pressure vary more at J-3 than
J-1?
Pressure is controlled to be constant at J-1.
3 What is the number of pump starts during the day for the scenario with
the tank? Is it excessive?
5, not excessive.
4 Do you think the pumps have enough capacity for this application?
Yes, pumps turn off or run at less than full speed.
5 Which scenario had the lowest energy costs? Which do you think would
have the lowest life-cycle cost?
Tank had lowest energy cost, while variable speed will probably have
lowest life-cycle cost. Must compare VFD costs with tank costs and
benefits.
6 Why was the energy use for the no tank constant head scenario the
greatest? What did the other two scenarios do to lower costs?
Constant speed pump cannot turn off if there is no storage or slow down
if there is no variable speed drive.
7 What was the range of relative speeds for the variable speed pump? If
the target head were to increase, how do you think the speed would
change?
0.87 to 0.92, speed would increase if target head increased.
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Feb-12 37 Analysis of Valving and Critical Segments - Q and A
Copyright 2012 Bentley Systems, Incorporated
Analysis of Valving and Critical
Segments - Q and A
Results Table
Result
Original Valves Max number of Isolation Elements
Outage Segments Length of the third longest outage segment (m)
Criticality System Demanded Flow (L/s)
Criticality System Supplied Flow for third largest segment (L/s)
Outage Segments Length of second longest outage segment (m) (Improved System)
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Feb-12 38 Analysis of Valving and Critical Segments - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Why is it undesirable to have segments where a large number of valves are
needed to shut down the segment?
2 What do outage segments show?
3 Would you expect there to be a correlation between the length of
distribution segments and system shortfall.
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 39 Analysis of Valving and Critical Segments - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Would you expect the same results for a steady state and an EPS criticality
analysis?
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Feb-12 40 Analysis of Valving and Critical Segments - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 Why is it undesirable to have segments where a large number of valves
are needed to shut down the segment?
More difficult to shut down system making it more likely that some valves
will be inoperable, thus spreading the outage to additional customers.
2 What do outage segments show?
They show the impact of an outage. Sometimes, even in looped systems,
there may be significant number of downstream customers out of service.
3 Would you expect there to be a correlation between the length of
distribution segments and system shortfall.
In general, the shortfalls will be correlated with the length of the segment
because larger segments have more demand. However, a failure of a key
segment, no matter how small, can place a large number of customers out
of service. The size of the outage segment is more important in terms of
criticality than the size of the segment.
4 Would you expect the same results for a steady state and an EPS criticality
analysis?
For this system, yes, because no storage tanks were involved. If there
were storage tanks, the EPS and steady results would be very different
once the tanks drained.
Result
Original Valves Max number of Isolation Elements 9
Outage Segments Length of the third longest outage segment (m) 2,185
Criticality System Demanded Flow (L/s) 38.5
Criticality System Supplied Flow for third largest segment (L/s) 28.1
Outage Segments Length of second longest outage segment (m) (Improved System) 994
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Feb-12 41 Automating Model Building using ModelBuilder - Q and A
Copyright 2012 Bentley Systems, Incorporated
Automating Model Building
using ModelBuilder - Q and A
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 What was the pressure (kPa) at the following nodes?
2 There were some fields in the data file that were not mapped to an
attribute in WaterGEMS. Why was this the case?
Node Pressure (kPa) (Run Values)
A-26
A-162
J-8
Enter your answer below:
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Feb-12 42 Automating Model Building using ModelBuilder - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
3 The data could have been exported to a standard MS Access file and then
imported into WaterGEMS. Why was this not a good idea?
4 Instead of entering tank level information in WaterGEMS Modeler, how
else could you have brought that data into the model?
5 Explain the difference in the tolerance specified in ModelBuilders Specify
Spatial Options dialog and the tolerance specified in Network Navigator.
In general which should be lower?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 43 Automating Model Building using ModelBuilder - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 What was the pressure (kPa) at the following nodes?
2 There were some fields in the data file that were not mapped to an
attribute in WaterGEMS. Why was this the case?
These fields were not needed in WaterGEMS and did not have a
corresponding attribute.
3 The data could have been exported to a standard MS Access file and then
imported into WaterGEMS. Why was this not a good idea?
Importing the feature classes directly into WaterGEMS enabled bends, (x,
y) coordinates, and topology to be automatically imported (preserved).
4 Instead of entering tank level information in WaterGEMS Modeler, how
else could you have brought that data into the model?
You could have created fields in your source file for tank elevations and
used ModelBuilder to bring in the data.
5 Explain the difference in the tolerance specified in ModelBuilders Specify
Spatial Options dialog and the tolerance specified in Network Navigator.
In general which should be lower?
In ModelBuilder, if the tolerance is met, the nodes are merged
automatically, while in Drawing Review, if the tolerance is met, the user is
given a chance to edit the nodes. As such, the ModelBuilder tolerances
should be set finer (Drawing Review larger). Drawing review will allow you
to double-check that other connections were not missed because of too
small a value in ModelBuilder.
Node Pressure (kPa) (Run Values)
A-26 262.7
A-162 495.5
J-8 497.8
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Feb-12 44 Pump Selection - Q and A
Copyright 2012 Bentley Systems, Incorporated
Pump Selection - Q and A
Results Tables
Operating Points
Scenario Element Time Property Initial Design Alternate Design
Summer Big1 6:00 am Flow (L/s)
Summer Big1 6:00 am Head (m)
Peak Big1 3:00 pm Flow (L/s)
Peak Big1 3:00 pm Head (m)
Winter Small1 12:00 pm Flow (L/s) N/A
Winter Small1 12:00 pm Head (m) N/A
Pump Station Capacity
Topology Type Initial Design Alternate Design
Existing Rated 140 N/A
Existing Total 265 N/A
New Rated 461
New Total 580
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Feb-12 45 Pump Selection - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
Energy Costs
Scenario Property Initial Design Alternate Design
PeakEPS221-61CS1 Daily cost
PeakEPS221-61CS1 Cost/ML
SummerEPS221-61CS1 Daily cost
SummerEPS221-61CS1 Cost/ML
WinterEPS126-61CW1 Daily cost N/A
WinterEPS126-61CW1 Cost/ML N/A
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Feb-12 46 Pump Selection - Q and ACopyright 2012 Bentley Systems, Incorporated
Module Review
Module Review
Now that you have completed this module, lets measure what you have learned.
Questions1 Why did the tank level fluctuate so much in the peak day but not on the
winter day?
2 Why could you conclude that the piping was adequately sized?
3 Could a small and large pump be run simultaneously with good efficiency?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 47 Pump Selection - Q and ACopyright 2012 Bentley Systems, Incorporated
Module Review
4 What would you like to change to make the system work better?
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Feb-12 48 Pump Selection - Q and ACopyright 2012 Bentley Systems, Incorporated
Module Review
Answers
Operating Points
Scenario Element Time Property Initial Design Alternate Design
Summer Big1 6:00 am Flow (L/s) 235 266
Summer Big1 6:00 am Head (m) 58 59
Peak Big1 3:00 pm Flow (L/s) 244 276
Peak Big1 3:00 pm Head (m) 56 56
Winter Small1 12:00 pm Flow (L/s) 145 N/A
Winter Small1 12:00 pm Head (m) 55 N/A
Pump Station Capacity
Topology Type Initial Design Alternate Design
Existing Rated 140 N/A
Existing Total 265 N/A
New Rated 460 470
New Total 580 630
Energy Costs
Scenario Property Initial Design Alternate Design
PeakEPS221-61CS1 Daily cost 600 629
PeakEPS221-61CS1 Cost/ML 22 23
PeakEPS221-69CS1 Daily cost N/A 629
PeakEPS221-69CS1 Cost/ML N/A 23
SummerEPS221-61CS1 Daily cost 499 527
SummerEPS221-61CS1 Cost/ML 23 24
SummerEPS221-69CS1 Daily cost N/A 526
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Feb-12 49 Pump Selection - Q and ACopyright 2012 Bentley Systems, Incorporated
Module Review
1 Why did the tank level fluctuate so much in the peak day but not on the
winter day?
Tank was sized right for the winter day but was small for the peak day
demand. System may need additional tank capacity.
2 Why could you conclude that the piping was adequately sized?
Velocities were reasonable, even on peak day. Plus, system head curvewas relatively flat.
3 Could a small and large pump be run simultaneously with good efficiency?
Yes, in this case they are compatible because their operating points are at
roughly 61 m of head and the best efficiency point of each pump is around
61 m.
4 What would you like to change to make the system work better?
SummerEPS221-69CS1 Cost/ML N/A 24
WinterEPS126-61CW1 Daily cost 243 N/A
WinterEPS126-61CW1 Cost/ML 22 N/A
Energy Costs
Scenario Property Initial Design Alternate Design
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Feb-12 50Automating Demand Allocation using LoadBuilder - Q and
A
Automating Demand
Allocation using LoadBuilder -Q and A
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Results Table
Questions
1 How would you get metering data for a model run for demands in the year
2040?
Node Location Near Node Pressure(kPa)
Near Pipe Pressure(kPa)
Population & Land UsePressure (kPa)
C_028 North
D1_078 East
D1_091 Near Source
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Feb-12 51Automating Demand Allocation using LoadBuilder - Q andA
Copyright 2012 Bentley Systems, Incorporated
Workshop Review
2 Why did small changes in demand make big differences in pressure in this
model?
Enter your answer below:
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Feb-12 52Automating Demand Allocation using LoadBuilder - Q andA
Copyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 How would you get metering data for a model run for demands in the year
2040?
You do not have a good source of meter data, so you need to use another
source such as population or land use to drive demands.
2 Why did small changes in demand make big differences in pressure in this
model?
This was a dead end system with a pump and no tank. Therefore any
change in demand affected not only head loss but the operating point on
the pump curve.
Node Location Near Node Pressure
(kPa)
Near Pipe Pressure
(kPa)
Population & Land Use
Pressure (kPa)
C_028 North 573 573 728
D1-078 East 366 366 520
D1-091 Near Source 589 589 741
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Feb-12 53 Importing Elevations using TRex - Q and A
Copyright 2012 Bentley Systems, Incorporated
Importing Elevations using
TRex - Q and A
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Results Table
Questions
1 For a model this size, how long do you think it would take to read off all
the 2000+ elevations manually?
Node Elevation (m) Pressure (kPa)
Node-1
Node-1374
Node-1836
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Feb-12 54 Importing Elevations using TRex - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
2 Look at the number of digits past the decimal place that elevation data are
reported. Is that precision justified?
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Feb-12 55 Importing Elevations using TRex - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 For a model this size, how long do you think it would take to read off all
the 2000+ elevations manually?
At 2 minutes per node, about a week.
2 Look at the number of digits past the decimal place that elevation data are
reported. Is that precision justified?
No, most of those digits are meaningless.
Node Elevation (m) Pressure (kPa)
Node-1 2555.0 440
Node-1374 2566.2 325
Node-1836 2549.3 489
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Feb-12 56 Skeletonizing a Large Model using Skelebrator - Q and A
Copyright 2012 Bentley Systems, Incorporated
Skeletonizing a Large Model
using Skelebrator - Q and A
Results Tables
Note: You may round your answers.
Smart Pipe Removal
Action Pipes Left Nodes Left Pressure A-100(kPa) Base
Pressure A-100(kPa) Fire
System HeadCurve PMP-1(m) Base
Start
Remove < 150 mm
Remove
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Feb-12 57 Skeletonizing a Large Model using Skelebrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Why did the pressures during the Base scenario not change much as pipes
were removed?
2 Why did the pressures during the Fire at A-100 scenario seem more
sensitive?
3 Why were the effects less dramatic in the runs using the series, parallel,
and branch removal operations?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 58 Skeletonizing a Large Model using Skelebrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Do you think you can generate system head curves with a fairly highly
skeletonized model?
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Feb-12 59 Skeletonizing a Large Model using Skelebrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 Why did the pressures during the Base scenario not change much as pipes
were removed?
The velocities (and hence head losses) in the system were so low that it
was difficult to see impact.
2 Why did the pressures during the Fire at A-100 scenario seem more
sensitive?
This scenario had much higher velocities so that the impact of removing a
pipe was more dramatic.
3 Why were the effects less dramatic in the runs using the series, parallel,
and branch removal operations?
These operations maintain hydraulic capacity.
4 Do you think you can generate system head curves with a fairly highly
skeletonized model?
Yes, the results show that you can skeletonize a model and still obtain anaccurate system head curve.
Smart Pipe Removal
Action Pipes
Left
Nodes
Left
Pressure A-100
(kPa) Base
Pressure A-100
(kPa) Fire
System Head Curve
PMP-1 (m) Base
Start 656 517 291.3 208.7 60.4
Remove < 150 mm 504 451 291.3 108.2 60.6
Remove
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Feb-12 60 Pipe Renewal Planner - Q and A
Copyright 2012 Bentley Systems, Incorporated
Pipe Renewal Planner - Q and A
Results Tables
1 Report the number of isolation elements, length of segment, and system
demand shortfall (%) to isolate these segments.
2 In the fire flow report, what was the available fire flow at the following
nodes:
Segment Number of IsolationNodes (Base)
Segment Length (m)(Base)
System DemandShortfall (%) (Criticality)
1
2
16
Node Fire Flow Available (L/s)
J-47
J-85
J-91
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Feb-12 61 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
3 In the pipe break results, find the 4 pipe elements with break rate scaled
greater than 0.6 breaks/yr/km. What are the rates?
4 Excluding pipes P-130 and P-131, what were the three pipes with the
highest score in the Pipe Renewal Planner, and which aspect was the
highest one for each (i.e. what was its major problem).
Pipe Break rate scaled(breaks/yr/km)
Initial Run
Pipe Score Worst Aspect
Including Material in Score
Pipe Score Worst Aspect
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Feb-12 62 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Do you think segment 2 is excessively large? What would you do to reduce
its size?
2 What would you do with the fire flow nodes that can not provide the
needed flow at 140 kPa?
3 What type of pipe were the pipes with the highest break rates?
Enter your answer below:
Enter your answer below:
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Feb-12 63 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Why did we downplay the importance of pipes P-130 and P-131 in the
scoring?
5 Even though asbestos cement pipes had a high break rate, why did they
not show up especially high in the pipe score?
Enter your answer below:
Enter your answer below:
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Feb-12 64 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
1 Report the number of isolation elements, length of segment, and system
demand shortfall (%) to isolate these segments.
2 In the fire flow report, what was the available fire flow at the following
nodes:
3 In the pipe break results, find the 4 pipe elements with break rate scaled
greater than 0.6 breaks/yr/km. What are the rates?
4 Excluding pipes P-130 and P-131, what were the three pipes with the
highest score in the Pipe Renewal Planner, and which aspect was the
highest one for each (i.e. what was its major problem).
Segment Number of IsolationNodes (Base) Segment Length (m)(Base) System DemandShortfall (%) (Criticality)
1 9 411 3.3
2 9 835 4.9
16 6 415 24.6
Node Fire Flow Available (L/s)
J-47 62.1
J-85 67.6
J-91 34.3
Pipe Break rate scaled(breaks/yr/km)
P-68 1.24
P-59 0.74
P-40 0.70
P-60 0.69
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Feb-12 65 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 Do you think segment 2 is excessively large? What would you do to reduce
its size?
Very large with a lot of valves to close to isolate it. Need to insert some
additional valves to subdivide the segment into smaller ones.
2 What would you do with the fire flow nodes that can not provide the
needed flow at 140 kPa?
Use color coding to look at nodes that do not meet needed fire flow.
These turn out to be primarily on dead end parts of the system. For an
existing system, find the bottlenecks and try to improve hydraulic
capacity. In this case, some of the old cast iron lines could be cleaned or
replaced. For a new system, look for places to provide looping or upsize
pipes to 200 mm.
3 What type of pipe were the pipes with the highest break rates?
Asbestos cement
Initial Run
Pipe Score Worst Aspect
P-68 55 Pipe Break
P-34 54 Capacity
P-11 50 Criticality
Including Material in Score
Pipe Score Worst Aspect
P-11 63 Criticality and Material
P-115 61 Criticality and Material
P-133 60 Criticality and Material
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Feb-12 66 Pipe Renewal Planner - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 Why did we downplay the importance of pipes P-130 and P-131 in the
scoring?
These are the pump suction and discharge lines and there is a parallel
pump and pipes in case these should fail. However, that pump was off for
the analysis.
5 Even though asbestos cement pipes had a high break rate, why did they
not show up especially high in the pipe score?
That part of the system was well looped so the criticality was not great
and the looping helped the fire flow since no single pipe had a very high
velocity.
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Feb-12 67Automating Calibration using Darwin Calibrator - Q and A
Copyright 2012 Bentley Systems, Incorporated
Automating Calibration using
Darwin Calibrator - Q and A
Results Tables
Average Day
Node HGLObserved(m)
Initial Run(m)
1/2 C-factor(m)
Adjust Conly (m)
Optimal(m)
DataError(m)
Optimizedw/Error
J-1 50.6 50.3
J-2 47.9 48.5
J-4 48.8 49.4
J-8 48.8 48.2
J-12 49.4 50.0
J-13 49.1 49.1
J-23 48.8 47.2
J-32 48.8 47.9
PUMP (L/s) 42.8 43.5
Fire Flow at J-10
Node HGLObserved(m)
Initial Run (m) 1/2 C-factor (m) Adjust C only(m)
Optimal (m)
J-1 45.7
J-10 42.1
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Feb-12 68Automating Calibration using Darwin Calibrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Results Tables
J-13 43.6
PUMP (L/s) 48.1
Fire Flow at J-31
Node HGLObserved(m)
Initial Run (m) 1/2 C-factor (m) Adjust C only(m)
Optimal (m)
J-1 43.9
J-13 40.2
J-31 33.8
PUMP (L/s) 49.8
Adjustment Factors
Initial 1/2 C-Factor Adjust C-only Optimized Optimized w/error
Cast Iron
Ductile Iron
Commercial
Residential
Fitness
Fire Flow at J-10
Node HGLObserved(m)
Initial Run (m) 1/2 C-factor (m) Adjust C only(m)
Optimal (m)
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Feb-12 69Automating Calibration using Darwin Calibrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 What would happen if you relied on a model that only adjusted C-factor?
2 Did changing the C-factors have a bigger effect on HGL in the static or fire
flow runs? Why?
3 What was the lesson learned when you tried to run optimal calibration at
low demand with some small errors in the data?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 70Automating Calibration using Darwin Calibrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
4 If you could get more data, what data would you get?
5 In a real system would you expect all the commercial customers to have
the same demand adjustments?
6 What accuracy would you expect to get with real HGL measurements?
Enter your answer below:
Enter your answer below:
Enter your answer below:
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Feb-12 71Automating Calibration using Darwin Calibrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
Answers
Average Day
Node HGLObserved(m)
Initial Run(m)
1/2 C-factor(m)
Adjust Conly (m)
Optimal(m)
DataError(m)
Optimizedw/Error
J-1 50.6 50.7 53.9 50.8 50.3 50.3 50.3
J-2 47.9 49.3 49.5 49.3 48.2 48.5 48.3
J-4 48.8 48.8 48.7 48.8 48.7 49.4 48.6
J-8 48.8 48.9 49.0 48.9 48.8 48.2 48.8
J-12 49.4 49.8 51.2 49.7 49.3 50.0 49.1
J-13 49.1 49.4 50.2 49.4 48.9 49.1 48.8
J-23 48.8 49.0 49.2 49.0 48.8 47.2 48.7
J-32 48.8 49.4 50.2 49.4 48.9 47.9 48.8PUMP (L/s) 42.8 42.9 39.0 42.8 43.3 43.5 43.2
Fire Flow at J-10
Node HGLObserved(m)
Initial Run (m) 1/2 C-factor (m) Adjust C only(m)
Optimal (m)
J-1 45.7 47.3 45.1 46.6 45.5
J-10 42.1 44.1 32.8 43.0 42.1
J-13 43.6 45.6 38.6 44.7 43.5
PUMP (L/s) 48.1 46.6 48.7 47.3 48.4
Fire Flow at J-31
Node HGLObserved(m)
Initial Run (m) 1/2 C-factor (m) Adjust C only(m)
Optimal (m)
J-1 43.9 45.7 40.4 44.9 43.9
J-13 40.2 42.4 28.3 40.4 40.1
J-31 33.8 37.0 8.7 33.3 33.8
PUMP (L/s) 49.8 48.2 53.2 49.0 50.0
Adjustment Factors
Initial 1/2 C-Factor Adjust C-only Optimized Optimized w/error
Cast Iron 1.0 0.5 1.2 0.8 0.9
Ductile Iron 1.0 0.5 0.8 1.0 0.8
Commercial N/A N/A N/A 1.5 1.4
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Feb-12 72Automating Calibration using Darwin Calibrator - Q and ACopyright 2012 Bentley Systems, Incorporated
Workshop Review
1 What would happen if you relied on a model that only adjusted C-factor?
You would end up adjusting the wrong parameter to get calibration. HGL
would be right but C and demand are wrong. This is an example of
calibration by compensating error.
2 Did changing the C-factors have a bigger effect on HGL in the static or fire
flow runs? Why?
Much more dramatic effect on fire flow runs because of higher velocity.
3 What was the lesson learned when you tried to run optimal calibration at
low demand with some small errors in the data?
When head loss is on same order of magnitude as error in head loss, the
calibration does not know what to adjust.
4 If you could get more data, what data would you get?
Would run some actual C-factor tests on cast iron pipes.
5 In a real system would you expect all the commercial customers to have
the same demand adjustments?
No, they would be different.
6 What accuracy would you expect to get with real HGL measurements?
It depends on care taken and instruments used. With GPS elevations and
quality gages you can get +/- 0.6 m accuracy; with topo map and average
quality gage, +/- 3.0 m.
Residential N/A N/A N/A 1.3 1.5
Fitness 20.175 579.356 4.419 0.218 5.726
Adjustment Factors
Initial 1/2 C-Factor Adjust C-only Optimized Optimized w/error
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Feb-12 73 Automating Design using Darwin Designer - Q and A
Copyright 2012 Bentley Systems, Incorporated
Automating Design using
Darwin Designer - Q and A
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 For each of the first set of Design Runs, list the pipe sizes and cost (leave
blank if pipe not installed), Round cost to thousands of dollars.
2 For the multi-objective run, list the sizes, costs and benefits for 5 non-
inferior solutions.
Solution Internal West North South Total Cost($1000)
1
2
3
4
5
Solution Internal West North South Total Cost($1000)
Benefit
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3 What solution would you recommend?
4 If you were adding another subdivision on the opposite side of town,
should you include sizing those pipes with the pipe sizing for this problem
or should you create a new design study?
5 Why did the South piping not get selected as the least cost alternative?
6 How would you force the South pipes not to be eliminated from the
solution?
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7 What do you think would have happened if you included a node that
could not reach 130 kPa for any combination of pipe sizes (e.g. a node on
the suction side of a pump) and what would you need to do to handle that
node?
8 How would you decide between non-inferior solutions in the tradeoff
analysis?
9 What would happen if you included a lot of nodes on the south side of the
system in calculating benefits?
10 Why would you not have used Average Day demands as an event in
Designer?
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Answers
1 For each of the first set of Design Runs, list the pipe sizes and cost (leave
blank if pipe not installed), Round cost to thousands of dollars.
2 For the multi-objective run, list the sizes, costs and benefits for 5 non-
inferior solutions.
3 What solution would you recommend?If your budget is limiting consider solution 4. Otherwise choose on budget
limit.
4 If you were adding another subdivision on the opposite side of town,
should you include sizing those pipes with the pipe sizing for this problem
or should you create a new design study?
It depends on whether there likely to be interactions between the piping
used to solve each problem.
5 Why did the South piping not get selected as the least cost alternative?
It contained the longest (and hence most costly) piping.
Solution Internal West North South Total Cost
($1000)1 200 200 175
2 150 200 182
3 200 200 187
4 250 200 196
5 250 200 208
Solution Internal West North South Total Cost($1000)
Benefit
1 200 300 250 412 2.12
2 300 250 254 1.78
6 200 300 200 380 2.07
7 200 250 222 1.56
17 400 300 310 1.95
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6 How would you force the South pipes not to be eliminated from the
solution?
Not allowing them a zero diameter in the cost table.
7 What do you think would have happened if you included a node that
could not reach 130 kPa for any combination of pipe sizes (e.g. a node on
the suction side of a pump) and what would you need to do to handle that
node?
You would get a no feasible solution message and you would need to
set a very low pressure as the pressure constraint for that node (or only
enforce pressure constraints for a smaller selection set and not all nodes).
8 How would you decide between non-inferior solutions in the tradeoff
analysis?
You would need to consider available budget and amount of safety factor
you want to build in.
9 What would happen if you included a lot of nodes on the south side of the
system in calculating benefits?
Those solutions bigger pipes on the south side would tend to have higher
benefits and are more likely to show up as non-inferior.
10 Why would you not have used Average Day demands as an event in
Designer?
For most situations average day demands do not control pipe sizing.
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Feb-12 78Multisource Mixing, Chlorine Residual, and Age Analysis -
Q and A
Multisource Mixing, Chlorine
Residual, and Age Analysis - Qand A
Results Table
Choose the minimum and maximum values by looking at the last 24 hours of each
simulation.
Node Condition Run 1 Run 2 Run 3
Constituent TDS-300 (mg/L) Chlorine Residualw/wall (mg/L)
Age (hours)
Initial values at T-1 300 0
Initial values at T-2 300 0
J-13 Min Value
J-13 Max Value
J-3 Min Value
J-3 Max Value
T-1 Min Value
T-1 Max Value
T-2 Min Value
T-2 Max Value
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Feb-12 79Multisource Mixing, Chlorine Residual, and Age Analysis -Q and A
Copyright 2011 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 Why were initial conditions at the tanks maintained so long in comparison
with those at the nodes?
2 How long did it take to reach the equilibrium pattern of TDS at nodes:
3 What is the maximum water age at the two tanks (T1 and T2)? What type
of problems could result in tanks with water that is this old?
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Node Hours
J-13
J-3
T-1
T-2
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Feb-12 80Multisource Mixing, Chlorine Residual, and Age Analysis -Q and A
Copyright 2011 Bentley Systems, Incorporated
Workshop Review
4 If you were deciding where to live in town based on water supply, which
area would you choose and why?
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Copyright 2011 Bentley Systems, Incorporated
Workshop Review
Answers
1 Why were initial conditions at the tanks maintained so long in comparison
with those at the nodes?
There is a much greater volume in the tanks than in pipes to flush out the
initial conditions.
2 How long did it take to reach the equilibrium pattern of TDS-300 at nodes:
3 What is the maximum water age at the two tanks (T1 and T2)? What type
of problems could result in tanks with water that is this old?
Maximum age in Tank T-1 is 3.5 days and the maximum age in Tank T-2 is
6 days. Especially in water as old as 5 days, you can lose your chlorine
residual and bacterial re-growth can occur.
4 If you were deciding where to live in town based on water supply, whicharea would you choose and why?
In the area served directly by Reservoir R-1 (near nodes J-1, J-14, J-12,
etc.) because it is always served by a single source, the water is very
young, the TDS is lower, and the pressure is reasonable (420 kPa).
Node Condition Run 1 Run 2 Run 3
Constituent TDS-300 (mg/L) Chlorine Residualw/wall (mg/L)
Age (hours)
Initial values at T-1 300 0 72
Initial values at T-2 300 0 144
J-13 Min Value 250 0.8 0.71
J-13 Max Value 440 0.9 1.32
J-3 Min Value 250 0.4 1.20
J-3 Max Value 398 0.8 65.87
T-1 Min Value 303 0.3 75.17
T-1 Max Value 305 0.4 83.32
T-2 Min Value 376 0.2 142.30
T-2 Max Value 378 0.2 150.81
Node Hours
J-13 10
J-3 10
T-1 250
T-2 300
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Feb-12 82 Developing System Flushing Routines - Q and A
Copyright 2011 Bentley Systems, Incorporated
Developing System Flushing
Routines - Q and A
Results Tables
Pipe Velocity (Normal) (m/s) Maximum velocity (m/s)
(from Flushing Report)
P-675
P-665
P-455
P-294
Flushing TL-107 (Conventional)
Flushing TL-107 (UDF)
Normal Hydraulic Grade (Scenario Steady)
Zone Pump Discharge HGL (m)
Upper PMP-12
Lower PMP-1
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Feb-12 83 Developing System Flushing Routines - Q and ACopyright 2011 Bentley Systems, Incorporated
Workshop Review
Workshop Review
Now that you have completed this workshop, lets measure what you have
learned.
Questions
1 What could have been done to improve flushing?
2 Why did the velocity at P-103 change so much between normal and
flushing demands?
3 What could you do to flush the short dead end pipes in the cul-de-sacs
without hydrants?
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4 Would you expect unidirectional flushing to be beneficial for TL-107?
Why?
5 In flushing P-294, the velocity was very high. What warning would you
give to operators that would be especially true for this pipe?
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Workshop Review
Answers
1 What could have been done to improve flushing?
Turn on stand-by pumps at the sources.
2 Why did the velocity at P-103 change so much between normal and
flushing demands?
It was a dead end with virtually no demand on normal day.
3 What could you do to flush the short dead end pipes in the cul-de-sacswithout hydrants?
Install blow offs at end of line.
4 Would you expect unidirectional flushing to be beneficial for TL-107?
Why?
You would expect that but the impact was marginal because the pipes
being closed did not carry much flow to the flowed hydrant during
conventional flushing. The main being flushed is 300 mm which is going to
be difficult to flush in any case, especially when it is far from the source
and head loss between the source and flowed hydrant would be large.
5 In flushing P-294, the velocity was very high. What warning would you
give to operators that would be especially true for this pipe?
Be very cautious in closing and opening hydrants in these dead end pipes
to minimize water hammer.
Pipe Velocity (Normal) (m/s) Maximum velocity (m/s)(from Flushing Report)
P-675 0.0 0.0
P-665 0.0 0.0
P-455 0.02 1.66
P-294 0.01 4.24
Flushing TL-107 (Conventional) 0.01 0.72
Flushing TL-107 (UDF) 0.01 0.80
Normal Hydraulic Grade (Scenario Steady)
Zone Pump Discharge HGL (m)
Upper PMP-12 435.9
Lower PMP-1 382.1
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Feb-12 86 Leakage Detection and Model Calibration - Q and A
Copyright 2012 Bentley Systems, Incorporated
Leakage Detection and Model
Calibration - Q and A
Module Review
Now that you have completed this module, lets measure what you have learned.
Questions
1 What time period of field data is good for leakage detection?
2 Which type of demand adjustment operation is used for leakage
detection?
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3 What setting do you need to adjust when the detected number of leakage
nodes is the same as the prescribed maximum number of leakage nodes?
4 What is likely to be expected for the fitness values of optimized solutions
when increasing the maximum trials?
5 How are the final solutions affected when using a smaller value of Flow
per Fitness Point for flows and Head per Fitness Point?
6 What do you need to export for a leakage detection run? Whats not to
export for a leakage detection run?
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Module Review
7 Which type of demand adjustment operation should be used for
optimizing the pattern at low demand hours?
8 Why should roughness and demand be optimized at the same time for a
high demand time step?
9 What should be exported to a scenario for the roughness and demand
optimization at high demand hour?
10 Which scenario should be used as representative for optimizing the
demand only at the high demand hours after roughness is calibrated?
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Module Review
Answers
1 What time period of field data is good for leakage detection?
Minimum demand hours or minimum night flow hours, usually from 1:00
AM to 4:00 AM.
2 Which type of demand adjustment operation is used for leakage
detection?
Detect Leakage Node.
3 What setting do you need to adjust when the detected number of leakage
nodes is the same as the prescribed maximum number of leakage nodes?
Increase the maximum number of leakage nodes for each demand group.
4 What is likely to be expected for the fitness values of optimized solutions
when increasing the maximum trials?
Fitness value will be likely further minimized with more trials.
5 How are the final solutions affected when using a smaller value of Flow
per Fitness Point for flows and Head per Fitness Point?
Fitness val may be evaluated for a greater value, but the solution is likely
getting better because the possible solutions are better differentiatedwith scaled-up fitness.
6 What do you need to export for a leakage detection run? Whats not to
export for a leakage detection run?
You need to export emitter coefficients, but not demand.
7 Which type of demand adjustment operation should be used for
optimizing the pattern at low demand hours?
Multiply with Original Demand.
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8 Why should roughness and demand be optimized at the same time for a
high demand time step?
At the high demand hour, flow velocity is relatively high; head loss is
sensitive to the change of pipeline roughness values. To minimize the
compensation error, both demand and roughness should be calibrated
together.
9 What should be exported to a scenario for the roughness and demand
optimization at high demand hour?
Roughness value only, the optimized demand factor should be applied to
the demand pattern factor at the corresponding time step.
10 Which scenario should be used as representative for optimizing the
demand only at the high demand hours after roughness is calibrated?
The scenario that includes the calibrated roughness values.