BAB IIIDATA PERENCANAAN
PEMBEBANAN
Bentang Jembatan = 14 m
A Beban Mati2 Pelat = 2 x 0.2 x 2400 = 960 kg/m
Aspal = 2 x 0.05 x 2200 = 220 kg/mKerb = 2 x 0.05 x 1000 = 100 kg/mBeban Sendiri = 1 x 0.4 x 2400 = 960 kg/m +
2240 kg/m
Mn = = 3920 kg.m
B Beban Hidupq = 2.2 t/m = 2200 kg/mp = 12 t = 12000 kgq' = = 0.800 t/m = 800.00 kg/m
k = 1 + 20/(50+16) = 1.313
p' = = 5.727 t = 5727.27 kg/m
Mu = = 73945.45 kg.m
C Beban Trotoirq = = 300 kg/m
Mu = = 7350 kg.m
D AnginP = 150 kg/m
= = 300 kg/m= = 165 kg/m= = 82.5 kg/m= = 1.1 kg/m= = 3.1 kg/m= = 1.1 kg/m
q = = 795.62 kg/m
Mu = = 19492.66 kg.m
E Beban Rem
1/8 x 2240 x 162
1/8*2200*162 + 1/4*5685.95*16
1/8*2200*162
q1
q2
q3
l2
l1
l3
1/8*795.62*162
H = = 1700 kgZ = = 2.9 mMu = H.Z = 4930 kg.m
F DiafragmaP = = 270 kgRa = Rb = = 675 kg
Mmax = (675 x (0.5 x 10)) – (270 x (2.5 x 2.5 + 2.5 x 1.5 + 2.5 x 0.5))
= 1687.5 kg.m
= 111325.61392 kg.m= 1,113,256,139 N.mm
Mtotal
PERHITUNGAN DIAFRAGMA
DATA :
qu = 2200 kg Mu= 111325.6139 kgm1113256139 Nmm
fc' 25 Mpal = 2 m fy 400 Mpa
b = 450 mm2 D 16
d2' = 30mm
d = 1050 mm
d1' = 30mm
6 D 32
As = 4825.4863159 -352263042
As' perlu = -863a = 201.850 mm
Dicoba :Ts x Z As' pakai = 2D16
1,465,519,181
Cek : As' pakai = 402.1As' pakai > As' perlu
> Mu OkOk
f Mn perlu = Mu - f Mn
mm2 f Mn perlu = Nmm2
mm2
f Mn =
Nmm2
mm2
f Mn
Ts = CcAs x fy = 0.85 x fc' x a x b
d - d2'
Ts = As x fy
a
Z = d - 1/2 a
Cs' = As' x fy
Cc = 0.85 x fc' x a x b
BALOK T PERSEGI
Mu = 1,113,256,139
fc' 20 Mpafy 400 Mpa
b eff = 4000 mm
hf =200 mm
850 mm
d' = 30 mm6 D 32
bw = 450 mm
As = 4825.49
a = 28.385 mma < hf
Tinggi balok tekan masuk plat
Ts x Z1599447809 Nmm
Cek :
> MuOk
mm2
f Mn =
f Mn
4.00
Cc = 0.85 x fc' x a x b eff
Ts = As x fy
a
Z = d - 1/2 a
Ts = CcAs x fy = 0.85 x fc' x a x b eff
BALOK T MURNI
Mu = 1113256139 Nmm
fc' 20 Mpafy 400 Mpa
b eff = 4000 mm
hf =200 mm
850 mm
d' = 30 mm6 D 32
bw = 300
Cc1 (d-1/2hf) + Cc2 (d-hf-1/2 (a-hf))
As = 4825.49 13055471773 Nmm
Cek :> Mu
a = 28.385 mm Oka < hf
Tinggi balok tekan masuk plat
Cc1 = 13600000 Nmm
Cc2 = 144764.6 Nmm
f Mn =
mm2
f Mn
1.85
Ts = CcAs x fy = 0.85 x fc' x a x b eff
Cc1 = 0.85 x fc' x hf x b eff
Ts = As x fy
Z1 = d - 1/2 hf
Cc2 = 0.85 x fc' x a x bw
Z2 = d - hf-1/2 (a-hf)
Cc1 = 0.85 x fc' x hf x b eff
Cc2 = 0.85 x fc' x a x bw
PELAT
fc' = 30 Mpafy = 240 Mpa
d = 200d' = 30 mm
mm
b = 5420 mm
Mu = 111325.61392 kgm1113256139 Nmm
Rn = 6.4186816144
m = 9.4117647059
0.0313777433
As =
34013.473757
As pakai = 40 D 1280 D 1260 D 1220 D 12
As pakai = 38453.09408As pakai > As perlu
Ok
Jarak :12 - 135.5 mm
ρ =
ρ* b*d
mm2
mm2