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AI HC BCH KHOA Tp.HCMKHOA IN IN TB MN H THNG INNhom mon hoc: CAO AP VAT LIEU
Mn hc
K THUT CAO PQU IN P TRONG H
THNG IN
________________________________________________
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Ti liu tham khaoK thut cao p II TS. HONG VIT
Bi tp KTCA TS. H VN NHTCHNG
Extra High Voltage AC Transmission
Engineering ( 3rd edition)Rakosh DasBegamudre
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MC TIU CA MN HC
NGUN GC, C IM V TC HICA CC DNG QU IN P XYRA TRONG H THNG IN
CC BIN PHP NGN NGA,HN CH TC HI CA QU IN PI VI CC THIT B TRONG H
THNG IN
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QU IN P(OVERVOLTAGE) ?
L THNH PHN IN P C THI
GIAN BIN THIN RT NGN ( 10-6 s)V BIN LN
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NGUN GC SINH RA QUIN P TRONG H THNG
IN?
HIN TNG PHNG IN ST
QU TRNH NG CT CC THIT BTRONG H THNG IN
CC S C XY RA TRONG H THNG
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CHNG I:
HIN TNG PHNG IN ST
Set la hien tng phong ien trong kh quyen giaam may dong mang ien tch vi at hoac gia cacam may dong mang ien tch trai dau nhau. ienap gia may dong va at co the at ti tr so hangchuc, tham ch hang tram trieu volt. Chieu dai trungbnh cua khe set khoang 3 5 km, phan ln chieu
dai o phat trien trong cac am may dong.
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1.1 NGUN GC SINH RA PHNG IN ST
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1.2 CC DNG PHNG IN ST
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Phng
in st
my-t
Phng inbn trong
m my
Phng in
my-my
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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1.3 MT S HNH NH PHNG IN ST
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Giai oan 1Thoat tien xuat phat t may dong mot day sang mkeo dai tng t gian oan ve pha mat at vi toc otrung bnh khoang 105 107 m/s. ay la giai oanphong ien tien ao tng t c goi la tien ao
bac.
1.4 CC GIAI ON PHNG IN ST
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Giai oan 1Kenh tien ao la mot dong plasma mat o ientch khong cao lam, khoang 1013 1014 ion/m3.Mot phan ien tch am tran vao kenh va phanbo tng oi eu doc theo chieu dai cua no.
1.4 CC GIAI ON PHNG IN ST
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Giai oan 1Di tac dung cua ien trng cua ien tch am tren
am may va trong kenh tien ao, vung at ben dise co s tap trung cac ien tch cam ng trai dau.V tr tap trung ien tch cam ng co the ngay bendi am may, hay nhng ni co ien dan cao
1.4 CC GIAI ON PHNG IN ST
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Giai oan 1Trong giai oan au, hng phat trien cua cac tia tienao la ngau nhien tuan thu theo nguyen tac la phattrien theo hng co cng o ien trng cao nhat
1.4 CC GIAI ON PHNG IN ST
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Giai oan 1Khi kenh tien ao at en mot o cao nhat nh,goi la o cao nh hng, th hng phat trien cua
tia tien ao se chu anh hng cua cac vat bendi mat at, ni co s tap trung ien tch camng caoDo o, v tr o bo cua dong set co tnhchon loc
1.4 CC GIAI ON PHNG IN ST
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Giai oan 1 cac v tr tap trung ien tch trai dau vimat o cao, cng o ien trng cuc botrong khong kh tai o cao lam xuat hien sion hoa khong kh, tao nen dong tien ao phattrien t ben di hng len am may, chieudai cua kenh tien ao ngc nay co the lenen vai tram m. ay chnh la qua trnh phongien on set, tao ieu kien nh hng dongset vao v tr o
1.4 CC GIAI ON PHNG IN ST
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Giai oan 2Giai oan phong ien chnh, hay phong ienngc.Khi kenh tien ao xuat phat t am may dongtiep can mat at hay kenh tien ao ngc,cng o ien trng trong khoang cach kh
tang cao gay ion hoa manh liet khong kh danen s hnh thanh dong plasma mi, co mat oien tch tang cao hn nhieu so vi ban au1016 en 1019 ion/m3.
1.4 CC GIAI ON PHNG IN ST
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Giai oan 2Cac ien tch cam ng di matat tran len trung hoa cac ientch trong kenh tien ao t ammay.Cac ien tch cam ng nay tieptuc i theo ng cua phong ientien ao ban au, tiep tuc hnglen am may, hnh thanh nen
kenh phong ien chnh
1.4 CC GIAI ON PHNG IN ST
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Giai oan 2Mat o ien tch trong kenhphong ien chnh rat cao, lam ot
nong manh liet kenh phong iennay, nhiet o co the len ti 2-3chuc ngan o C(gap 3 lan nhiet obe mat mat tri). Chnh v vay,kenh phong ien chnh sang choichang, ma ta thay di dang cactia chp.
1.4 CC GIAI ON PHNG IN ST
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Giai oan 2Vi lng nhiet khong lo nay, lpkhong kh xung quanh kenh phong
ien chnh b ot nong, gian not ngot tao ra nhng t song ammanh liet, ma ta goi la sam
1.4 CC GIAI ON PHNG IN ST
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Giai oan 2Khi kenh phong ien chnh len
en am may dong, dong set cogia tr ln nhat, ay chnh la dongngan mach khoang cach kh giamay va at, co gia tr trong
khoang t 1kA en hang tram kA
1.4 CC GIAI ON PHNG IN ST
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Giai oan 3Giai oan ket thucKhi kenh phong ien chnh len
en am may dong, cac ien tchcam ng t mat at len theo, tranvao va trung hoa cac ien tch traidau tren am may, cac ien tch
(am) con tha tren am may setheo kenh phong ien chay xuongmat at.Dong set co tr giam dan
1.4 CC GIAI ON PHNG IN ST
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1.4 CC GIAI ON PHNG IN ST
1-Giai on phng in tin o
1
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.4CC
G
IAIONP
HNGINST(20-50ms)2-Giai on phng in ngc 3-Giai on kt thc phng in
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Phng th nghim nghin cu v hin tng phng in st
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1.5 CC THNG S DNG IN ST
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Bieu thc toan hoc c viet nh sau
Trong o : I : hang so co th nguyen la dong ien (kA).1, 2 : hang so co th nguyen la thi gian (s).
s : thi gian au song (s). s : thi gian song (s).
1.5 CC THNG S DNG IN ST
I( / )m
ds
a kA s
o doc au song cua dong set
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Xac suat xuat hien dong set co bien o ln hn Im(kA)
26
13
,
,
m
mm
I
I I
e DBv
e DN
1.5 CC THNG S DNG IN ST
0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.90
10
20
30
40
50
60
70
80
90
100
Vis
Is(kA)
Dong bang
Mien nui
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Xac suat xuat hien dong set co o doc au song a(kA/s)
15,7
7,82
,
,
a
a a
e DB
v
e DN
1.5 CC THNG S DNG IN ST
0 0.1 0.2 0.3 0.4 0.5 0.60
10
20
30
40
50
60
70
80
90
100
Va
a(kA/s)
Dong bang
Doi nui
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1.6 CNG HOT NG CA ST V MT ST
Cng hot ng ca set la so ngay co dong settrung bnh trong nam: n (ngay set/nam)Vung cc: 2-3, on i: 30-50, nhiet i: 75-100, xchao 100-150 (ngay set/nam)
Mat o set la so lan set anh trung bnh tren 1 n vdien tch mat at trong 1 ngay co dong set: m(lan/km2.ngay set)
Mat o set trung bnh trong nm:m.n (lan/km2/nm)
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S li i d h
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S liu v mt st ti cc a danh Vit Nam (2007)
S li t t t i d h
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S liu v mt st ti cc a danh Vit Nam (2007)
S li t t t i d h
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S liu v mt st ti cc a danh Vit Nam (2007)
S li t t t i d h
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S liu v mt st ti cc a danh Vit Nam (2007)
S li t t t i d h
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S liu v mt st ti cc a danh Vit Nam (2007)
S li t t t i d h
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S liu v mt st ti cc a danh Vit Nam
S liu v mt st ti cc a danh
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S liu v mt st ti cc a danh Vit Nam (2007)
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THE END
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AI HC BCH KHOA Tp.HCMKHOA IN IN T
B MN H THNG IN
Mn hc
K THUT CAO P
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9/9/2011 2
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CHNG II
BO V CHNG ST NH TRCTIP CHO H THNG IN
/ / / / / // / / / / /
R X
(1)
(2)
(3)
Bo phan thu set
(100mm2)
Bo phan dan dong set
(50mm2)
Bo phan noi at
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M hnh A.Kopian:
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p
H
h
R=3,5h
Khu vc c xc sut100% st nh vo ct
thu st: R=3,5h
M hnh A.Kopian:
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p
rx
Phng php thc nghimtrn m hnh ny ara c cng thc xc
nh phm vi bo v cact thu st s c trnh
by phn sau
M hnh A.Kopian:
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M hnh A.Kopian:
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I. CACH XAC NH PHAM VI BAO VE CUA CTS1. Pham vi bao ve cua mot CTS(
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I. CACH XAC NH PHAM VI BAO VE CUA CTS
1,6 x
x
h hh p
h h
xr
p = 1 khi h 30m.
30p = khi 30m < h < 60m.
h
1. Pham vi bao ve cua mot CTS (
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1,5 (1 )
0,8
xx
hr h p
h
0,75 (1 )xxh
r h ph
, khi hx 2h/3 rx = (1,5h 1,875hx).p
,kh ihx > 2h/3 rx = (0,75h 0,75hx).p
I. CACH XAC NH PHAM VI BAO VE CUA CTS1. Pham vi bao ve cua mot CTS (
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0,2h
h
hx
2h/3
0,75ph
1,5ph
1,5 (1 )
0,8
xx
hr h p
h
0,75 (1 )xxh
r h ph
, khi hx 2h/3 rx = (1,5h 1,875hx).p
,kh ihx > 2h/3 rx = (0,75h 0,75hx).p
I. CACH XAC NH PHAM VI BAO VE CUA CTS1. Pham vi bao ve cua mot CTS: (
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I. CACH XAC NH PHAM VI BAO VE CUA CTS1. Pham vi bao ve cua mot CTS: (>60m)
St khng nhng nh vo nh m cn nh vo phn thn ct gnnh
0,5( 60)h h
i vi ct thu st c chiu cao t 60m n 100m:
i vi ct thu st c chiu cao t 100m n 250m:
0,2h h
Nu chiu cao hiu dng ha h, th phm vi bo v ca ct thu stc tnh vi chiu cao hiu chnh h=h-h
2. Pham vi bao ve cua hai CTS
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7
a
p
p7a
0,2h
hhx
2h/3
0,75hp
1,5hp
a/2a/2rx
7
a
hh0
RCot thu set Cot thu set
rx
rxr0x
r0x
Trng hp hai cot co o cao bang nhauTa co the xac nh c rang neu hai CTS at cach nhau mot khoang
cach a th chung co the bao ve vat co o cao h0 at gia chung, vi h0
c xac nh theo cong thc: h0 = h
a/7p
2. Pham vi bao ve cua hai CTS
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0,75h 1.5h0,75h
rx
xhxh
rx
1.5h 1.5h O 0,75h O 0,75h O O1.5hrOX
R
a
ho
Trng hp hai cot co o cao bang nhau
2. Pham vi bao ve cua hai CTS
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Neu hai cot thu set co o cao khac nhau, v du h1 < h2 th phamvi bao ve cua chung c xac nh nh sau
- Pham vi bao ve pha ngoai hai cot thu set giong nh pham vi
bao ve cua tng cot rieng le.- Pham vi bao ve gia hai cot thu set co c bang cach quanh cot thap (h1) ve mot ng thang ngang, no cat ng sinhcua pham vi bao ve cua cot cao h2 mot iem , iem nay c coinh nh cua cot thu set gia tng h = h1 va khu vc bao ve giacot thap h va h1 cach nhau khoang a nh gia hai cot co o caobang nhau.
Trng hp hai cot co o cao khac nhau
3. Pham vi bao ve cua he nhieu CTS (n>2)
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Khi cong trnh can bao ve chiem mot dien tch rong ln thngi ta thng dung mot he thong nhieu cot thu set e bao
ve. e xac nh pham vi bao ve, ngi ta chia he thong cotthu set thanh tng nhom 3 hoac 4 cot thu set. Ben ngoai dientch cua a giac i qua chan cac cot thu set ( hnh tam giachoac hnh ch nhat ) pham vi bao ve c xac nh nh gia
tng oi cot thu set vi nhau. Con tat ca cac thiet b co o caoln nhat hx at trong dien tch cua a giac se c bao ve antoan neu ieu kien sau c thoa man :
D 8 (h hx ) pTrong o:h : o cao cua cot thu set.hx : o cao ln nhat cua cao trnh.D : ng knh ng tron ngoai tiep a giac.
3. Pham vi bao ve cua he nhieu CTS (n>2)
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1
2 3
4
a
b
r0X1
r0X2D
1 2
3
a
b c
rX
r0X12
r0X13 r0X23
rX
1500
4000
A
Xa
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RANH CAP LC 22 KV
RANH CAP IEU KHIEN
PHONG THIET BPHAN PHOI 22 KVPHONG VAN HANH
2T60 MVA
1T60 MVA
2500
2500
300
0
3000
3000
3000
3000
3000
1500
1000
1000
3000
3000
3000
300
0
4000
4500
7000
5000
10000
4000
10000
35000
78,5m
B B
A
GVHD
TRNG I HC BCH KHOA TP . H CH MINHKHOA IN -IN T
B MN H THNG IN
Ngy 12/11/2006 Bn v s : 1
Ngi v ng Nh Tn MT BNG B TRTRM BIN P 110/22 kV
N MN HCCAO P
Xa day
Xa thanhgop
3 00 0 3 00 07000
1500 2500 25003000 30002500 25003 00 0 3 00 02500 25003 000 300 02500 2500 15001500 3000 3000 3000 1500 700015001500
Chu thch :
9,75 m1,77 m 5,04 m9,75 m4,125 m 6,54 m2,52 m
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RANH CAP LC 22 KV
RANH CAP IEU KHIEN
PHONG THIET BPHAN PHOI 22 KV
PHONGVAN HANH
2T60 MVA
78,5m
51,79
m
35,23m
1T60 MVA
55,9
2m
55
,92
m48
,09
m
48,09
m
22 m15 m22m
Vung bao ve cao o 6m
Vung bao ve cao o 8m
Vung bao ve cao o 11m1 2 3 4
67
5
35,23m
51,7
9m
Vung I
VungII
Vung III Vung IV
Vung V
13,875 m
9,75 m
4,125 m
2,4 m
0,6375 m
36,18 m
32,56 mGVHD
TRNG I HC BCH KHOA TP. H CH MINHKHOA IN -IN T
B MN H THNG IN
N 12/11/2006 Bn v s : 3
V Phan T
N MN HCCAO P
PHM VI BO V CA KIM THU ST
TRM BIN P 110/22 kVNgi v ng Nh Tn
MSSV:402HT039
Cot anten
Cot enchieu sang
Cot enchieu sang
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CHU THCH :- CB : MA Y CA T SF6- DS : DAO CA CH LY- ES : DAO NOI AT- BI : MAY BIEN DONG IEN- BU : MAY BIEN IEN AP- LA : CHONG SET VAN
MA T CA T A -A
MA T CAT B-B
BU
BU BIS/ES
LA/ES
14m
11m
8m
4000 1500 3000 3000 3000 3000 3000 40003000 2500 3000 3000 4500
BIS/ES
1500 3000 1000 2500 1000 3000
BU BU BUADS/ES BI
CBDS/ES DS/ES DS/ES
CBLA
LA BUDS/ES DS/ES
LAU
7000
N MN HC CAO P
MT CT TRM BIN P 110/22 kVGVHD
TRNG I HC BCH KHOA TP. H CH MINHKHOA IN -IN T
B MN H THNG IN
Ngy 12/11/2006 Bn v s :
Ngi v ng Nh Tn
N MN HCCAO P
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II. CACH XAC NH PHAM VI BAO VECUA DCS:1. Pham vi bao ve cua mot DCS:
DCS
DDkhongc
bao ve
DD c bao ve
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II. CACH XAC NH PHAM VI BAO VECUA DCS:1. Pham vi bao ve cua mot DCS:
a) Trng hp DCS co o treo cao (h) nho hn 30m :
xx
x
h hb 1,2h
h hp
xx x
xx x
h2h > h: b 0,6h(1 )p
3 hh2
h: b 1,2h(1 )p3 0,8.h
h
Hay
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II. CACH XAC NH PHAM VI BAO VECUA DCS (tt):1. Pham vi bao ve cua mot DCS:
b) Trng hp DCS co o treo cao (h) ln hn 30m :
30m h 100m
h 0,29(h-30)
100m h 250m
h 0,2h
Pham vi bao ve theo chieucao (mat cat ng) giam motkhoang tnh t nh:
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II. CACH XAC NH PHAM VI BAO VECUA DCS (tt):2. Pham vi bao ve cua hai DCS:Khi hai day chong set at cach nhau S = 2B = 4h th moiiem tren mat at nam gia hai day chong set se c baove an toan. Neu S < 4h th gia hai day chong set co thebao ve c o cao:
0
S
h h 4p
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II. CACH XAC NH PHAM VI BAO VECUA DCS (tt):2. Pham vi bao ve cua hai DCS:
Khi day dan 3 pha cua ng day tai ien cung nam trenmot mat phang ngang th ieu kien e day dan gia hai cotc bao ve la khoang cach S gia hai day chong set phaithoa man ieu kien:
4. .( )DCS DDs p h h
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II. CACH XAC NH PHAM VI BAO VECUA DCS (tt):2. Pham vi bao ve cua hai DCS:
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II. CACH XAC NH PHAM VI BAO VECUA DCS (tt):3. Cach xac nh pham vi bao ve cua day
chong set cua ng day tai ien cao ap:
031gh
c
hlg 4
90
III. CC YU CU K THUT KINH TKHI DNG H THNG CTS BO V
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KHI DNG H THNG CTS BO VCHNG ST NH THNH CHO TRM
BIN P V NH MY IN:Ct thu st c th t ngay trn cc kt cu cngtrnh (ct x, ng khi, ct n pha) ca TBAvNM khi tha mt s iu kin nht nh. Vict CTS trn kt cu trm ch cho php khi trmc mc cch in xung ln v in tr ni tb.VD:
-TBA 110kV tr ln d dng tha mn c yucu ny-TBA 35kV ch cho php t CTS trn kt cutrm khi R
n4 Ohms
III. CC YU CU K THUT KINH TKHI DNG H THNG CTS BO V
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KHI DNG H THNG CTS BO VCHNG ST NH THNH CHO TRM
BIN P V NH MY IN:Chn kt cu t CTS phi c ni theo ngngn nht vo HTNi t an ton ca trm ti imgiao ca cc thanh cn bng th, ng thi tng
cng thm cc ni t b sung (cc thanh, cctng cng)
III. CC YU CU K THUT KINH TKHI DNG H THNG CTS BO V
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KHI DNG H THNG CTS BO VCHNG ST NH THNH CHO TRM
BIN P V NH MY IN:Khi cc iu kin trn khng tha mn th CTS phi tcch ly vi cc kt cu trong trm v ni t ca CTS
phi c tch ring khi ni t an ton ca trm.
Khong cch trong khng kh gia CTS v cc vt cnbo v trong trm phi ln.Tng t, khong cch trong t gia ni t CTS v nit an ton trm cng phi ln.
III. CC YU CU K THUT KINH TKHI DNG H THNG CTS BO V
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KHI DNG H THNG CTS BO VCHNG ST NH THNH CHO TRM
BIN P V NH MY IN:
kS 0,3 0,1x AR l dS 0,5 xR
lA
h
VBV
Sk
Sd Rx
Chng 3:
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1
NI T TRONG HTHNG IN
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Trao i trc tuyn ti:
http://www.mientayvn.com/chat_box_li.html
3.1 KHI NIM
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3
Cc ni t: c ng
thng xung mt t su t 0,5m n 0,8m
t
Khng kh
chnsu t0
dy dn dngs c, dng st
Cc ni tbng ng haythp m km
3.1 KHI NIM
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4
Thanh ni t: c chn
trong t su t 0,5mn 0,8m
t
Khng kh
chnsu t0
dy dn dngs c, dng st
Thanh ni tbng ng haythp m km
3.1 KHI NIM
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5
Li ni t: do nhiu cc hay thanh
ghp ni vi nhau, chn trong t su 0,5m n 0,8m
cc thanh nit hay dy cp
kt ni thnh
li
Cc ni tng ven chu vi(hc dc theong cho)
3.1 KHI NIM
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6
Cc mi ghp k thut
3.1 KHI NIM
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7
Ni t lm vic: l ni t im trungtnh ca my pht, my bin p cng sut,
TI, TUm bo s lm vic ca trangthit b in lc bnh thng v s c.
Ni t an ton: l ni t v trang thit
b in hoc kt cu kim loi. m bo anton cho ngi vn hnh khi c s c rcch in.
Ni t chng st: l ni t cc b phnthu st ( KTS, DCS) Nhm tn dng stvo t, trnh phng in ngc t phn t n cc b phn mang in.
C
B
R
A
N
Mun in p ti N = 0
R
R
KTS
3.1 KHI NIM
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8
Cu to ca ni t: thng thng c thc hin bng mt hthng nhng cc bng thp hoc ng ( c th trn hoc dt) ngvo t, hoc nhng thanh ngang chn vo t. Hoc cc v thanh
ni lin vi nhau v chn vo t.
Trm phn phi: 3 h thng ni t phi c ni ring l.
Trm truyn ti ( >=110 kV): 3 h thng ni t c dng chung.
in tr ni t R l t s gia in p trn ccU v dng in qua n I . in trRbao gmin tr ca bn thn in cc v in tr tn trong
t. Khi tn dng mt chiu hay xoay chiu th in tr bn thn incc rt b c th b qua.
R
IU
3.1 KHI NIM
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9
Khi tn dng mt chiu hay xoay chiu th in tr bn thn incc rt b c th b qua.
Hnh : M hnh in cc ni t n gin ( thanh hay cc ni t)
3.1 KHI NIM
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10
Khi tn dng st, qu trnh truyn sng trn cc ni t tng tnh trn ng dy ti in. Do c in cm cn tr dng in i su
vo chiu di in cc nn in th phn b khng u trn in cc.
T< =Ts ( l ln): Ni t ko di ( ni t phn b). Rx R
Rx ()
t (s)
R
nh hng ca in cm s gim dn theo thi gian. in tr tnca cc ni t ln nht gn ng vo lc dng st t gi tr cc
i.
T=L0.g0.l2Ts
3.1 KHI NIM
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11
Hnh : Qu in p ti cc v tr trn cc thanh ni 20 m v 100m
3.1 KHI NIM
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12
Khi tn dng st, ngoi nh hng ca in cmL lm gimkh nng tn dng st ca htn, cn c nh hng phi tuyn bihin tng phng in tia la trong t khi dng st c bin ln. Vng t quanh in cc tr nn dn in tt, lm tng khnng tn dng st, tc lm in tr tn xung gim.
3.1 KHI NIM
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13
Hnh: Bn knh ca cc phn on trn thanh ti cc thi im a) 0.2 s v b) 0.5s
a) b)
3.1 KHI NIM
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14
Hnh: Qu in p ti v tr vo dng st v v tr cui trn thanh t a) FEM v b) FDTD
a) b)
3.1 KHI NIM
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15
i vi ni t chng st cn phn bit in tr tn xung Rx vi
in tr tn n nh R. R cng chnh l in tr tn dng xoaychiu ( R~ ) hay dng mt chiu.
x
x
R
R
Ni t tp trung: x < 1, nh hng ca phng in tia la
chim u thNi t ko di: x 1, nh hng ca in cm dc theo chiudi ca thanh dn trong HTN chim u th
3.1 KHI NIM
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16
Mt s phng php o in tr sut t
2 UaI
Phng php Wenner
2
4ln
l U
l I
d
Phng php Driven Rod
3.2 IN TR TN DNG XOAY CHIU R~
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17
Khi dng in xoay chiu chy qua in cc tn vo t, tonn trong t quanh n mt in trng. Mi im trong in
trng k c trn mt t c mt in th nht nh.
Utx
Ub
Gim Utx , Ub
Trn mt t khu vc ni t
c ri mt lp si hoc gim s chn lch in th.
U
r/U
Gim in p trn in cc Uhay gim in tr tip t.
3.2 IN TR TN DNG XOAY CHIU R~
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18
i vi in cc ni t n gin: cng thc xc nh in trtn tn s cng nghip ca mt s dng in cc thng dng
(Bng 4.1, 4.2)4
ln2
tt
c
lR
l d
Cc chn ni:
0
2 1 4
(ln ln )2 2 4
2
tt
c
l t l
R l d t l
lt t
Cc chn chm:
2
0
ln2
tt
t
lR
l dt
Thanh chn chm:
0
8(ln ln )
2 . 4
tt
V
D DR
D d t
Thanh hnh xuyn chn chm:
2
0
ln
2
tt
t
kLR
L dt
Thanh c hnh dng c bit:
d
dang trn
b
b
dang gc
d=0,95b
dang dpd=0,5b
dott mk in tr sut tnh ton ca t:
3.2 IN TR TN DNG XOAY CHIU R~
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19
i vi in tr ni t ca t hp nhiu in cc:
Hiu ng mn che lm mo dng vng
ng th gia hai in cc, lm gim khnng tn ca h thng ni t.
c trng cho hiu ng mn che,ngi ta dng h s ~. ~ l h s s dng
khi tn dng in xoay chiu tn s cngnghip. y l i lng ton hc th hin
bn cht vt l l hiu ng mn che.
R1 R2 R3
B qua hiu ng mn che Rt= R1//R2//R3
Xt n hiu ng mn che Rth~=Rt/~ > Rt ~~
1td
th
R
R
3.2 IN TR TN DNG XOAY CHIU R~ d h h l i i l h
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20
H s s dng ph thuc vo vo loi in cc, s lng v cchb tr chng. N c th tra cu trong cc bng s hoc cc ng
cong cho trong cc ti liu hng dn(SBT PL 4 n PL 7).Xt t hp thanh v cc
cc n
Rc, Rt: in tr ca tng cc ring l v thanh.
c,t h s s dng ca cc v thanh trong t hp
12 m
3 m c = 0.7 , t = 0.74VD
c t
c t c t
th
c t c t t c
c t
R R
n R RR
R R R R nn
3.3 IN TR TN NI T CHNG ST3 3 1 i d i
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21
3.3.1 in tr tn xung ca dng ni t tp trung Kch thc tht ca in cc c th
thay th bng kch thc ca khu vcphng in tia la.
Rx = xR~ (x < 1 )
x= f(Is,): c trng cho phng
in trong t v gin n in cc nit.
Khi chiu di ca in cc tng lnth x tng ln do nh hng ca incm.
Phng in trong t
E > Ep()
IS
Bin ln
E = Ep()
Nu ni t l t hpRthx = Rtx/x >Rtx
x: th hin hiu ng mn che ca t hpkhi tn dng in xung.
3.3 IN TR TN NI T CHNG STT h h i h i
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22
Trnh t tnh ton in tr tn xung ca mt t hp ni t tp trung
B1: Chn km (ni t chng st) . tt = km.o
B2: Tnh R~ ca tng loi in cc ring l. (R~c,R~t)
B3: TnhRx ca tng loi in cc rring l (Rxc,Rxt)
- Tnh dng st phn b qua mi in cc ring l- Tnh x : c th tra bng hoc tnh bng cng thc
Rxc = xcR~c ; Rxt= xtR~t
B4: in tr tn xung ca c t hp
1 1xc
xtxc xt
th
xc x xc xt xxt
RR
R RnRR R n R
R
n
n : s cc
x : h s s dng xungca t hp. (
x
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23
BT 1: Chng ta c mt thanh st trn di40 m ng knh 20 mm. Hi dng
ni t no sau y, c in tr tnxoay chiu nh nht? Bit ni tc chn su 0.8 m trong t. tc in tr sut o vo ma ma l100 m.
a) b)
c)
l1
l2 = 2l1
BT 2: Cho mt h t hp phc nh hnh gm5 cc, mi cc di 3 m, ng knh 30mm, ng cc dc theo thanh dng trnng knh 20 mm di 12 m. C t hpnm su trong t 0.8 m c in tr suto lc kh ro l 120 m. B qua hiung mn che. Tnh in tr tn xoaychiu ca t hp.
3.3 IN TR TN NI T CHNG STBT 3: Cho mt h t hp phc nh hnh gm 3
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24
BT 3:
BT 4:
Cho mt h t hp phc nh hnh gm 3cc, mi cc di 3 m, ng knh 25 mm,
ng cc dc theo thanh dng trn ngknh 15 mm di 12 m. C t hp nm sutrong t 0.5 m c in tr sut o lc khro l 150 m. Tnh in tr tn xoay chiuv tn xung ca t hp.
Xc nh in trxoay chiu v xung kch ca ba thanh nit lmbng thp dt 4x40 mm2, mi thanh di 15 m chnsu trong t 0.8 m. in tr sut t o vo ma m l 200
m. Gi s dng st chy qua h thng ni t l 120 kA.
Is = 100kA
1500
320 45
t
tt t
l
I
Is
It
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3.3 IN TR TN NI T CHNG ST3 3 2 i t t i t k di b th h
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26
3.3.2 in tr tn xung ca ni t ko di bng thanh ngang
a. Khi b qua qu trnh phng in trong t ( ln, is nh)
in p ti v tr bt k theo thi gian t:
1 210
1 210
1( , ) 2 1 os
1(0, ) 2 1
k
k
t
T
k
t
T
k
a k xu x t t T e c
g l k l
au t t T eg l k
Tng tr tn xung u vo ti mt thi im bt k t:
12
10
2(0, ) 1 1(0, ) 1 1(0, )
k
t
T
ks
Tu tZ t e
i t g l t k
2
0 0 11 2 2
;k
L g l TT T
k Hng s thi gian ca qu trnh truyn
sng iu ha bc 1 v bc k
3.3 IN TR TN NI T CHNG ST3 3 2 i t t i t k di b th h
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27
3.3.2 in tr tn xung ca ni t ko di bng thanh ngang
a. Khi b qua qu trnh phng in trong t ( ln, is nh)
Mt cch gn ng khi dng st t tr s cc i (t = Ts)th tng tr xung du vo c tr s ln nht.
s
1s 2
10 s
21 1(0, ) 1 1
d
k
T
T
d
kd
TZ T e
g l T k
Trng hp Ts/T1 > 3
2
1 1s 2
10 s s
0s
21 1(0, ) 1 1
3
(0, )3
d
kd d
d
ds
T TZ T R
g l T k T
L lZ T R
T
3.3 IN TR TN NI T CHNG ST3 3 2 in tr tn ng ca ni t ko di bng thanh ngang
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3.3.2 in tr tn xung ca ni t ko di bng thanh ngang
b. Khi xt n qu trnh phng in trong t
Phng in dc theo chiu di thanh lm cho khuvc phng in thu hp dn, dn n in dn tn xungkhng cn l hng s. H phng trnh truyn sng tr
nn khng tuyn tnh v c gii bng phng phpgn ng hoc phng php s.
ng vi mt tr s v Is nht nh c mt tr sgii hn ca chiu di in cc m vt qu gii hn
, tng tr xung khng gim khi tng chiu di incc na
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