7

Sir d\lng kich thu'oc k. A

'va'" kh':" oa let

Trang Rev,it@ Architecture, b~1il slI dl,1ng kfChrhl\toc de tf,inh bay va kiem saat vi trf cua vat th€'. B-i;ln cung co the SU' dl)ng kh6a ket (constraint) de khoa hal thalilh phan Iqi vol nhau amQt khoang cach nhat djnh, duy tri cae tkhaang dlCh bang nhau cua rnQt day v~t the hay khoa hai rhanh phan luon luon ngamg hilng nhau. Ca hal cong cl:! cha phep b911

dieu khien va d!nh vi tl! oQng V! tri eua cae v~t the trong thie't ke eua minh. Trang ehu!dng nay, b911 hoc ve each Stf dl::mg kieh thl10e va 'khoa kt?'t (constraint).

IMyc tieu

Sau kh'j haim tat chL1dng !nay bi;m se co the:

• Bo tri kich thl10c trang mQt c6ng trinh. Ap dl:mg va thao do cae kh6a l<.et (oonstraint) trang mQt c6ng tdnh.

219

---

--

......./Bili: 'Lam v:i~c vai k,ich thLtac .....;

N

Tong quan

B~i hQc nay me til cach b5 tri kioh thu'ac trong mQt ceng trllilb. B(;m bat dau' bai hQc ve ph'an hQc kich thu'oc thLioc t~m thai va kkh thu(oc tlnliong xuyen. Tiep theo, b'~n hQc ve cae thao lac '-/

nen dung khi lam vj~c vOl' kich thu'oc. 'Bai hQc dLit;1c kat thuc :bang mot ba,j ~p vai' nQi dung lam vi~c vail kich thLic:1C trong lmQt ceng tliinh.

l8(;1n b5 tr1 kich thu'ac de quy d!nh va hi~u cfninh khoang each gilra hai thanh phan trong mQt ­cong trinh. Hinh dl1ai day minh hQa mot kichl thLiOC lien Quan <len mQt t,hanh phan tLiOng.

20'· 0"

,r,( i:::::;;

Jf

MI}C tieu

Sau khi hoan thanh bai nay, b(;ln se co the:

Hieu dLiQC kkh thu'ac t~m thai.

Hieu du'Qc kkil thLioc thU'ong Xl;Jyen. ........-Xac dinh cae thao tac. 'oen dunQl khi lam vi~c vai kich thLioc.

Lam vi~c vai ikich thl10c trong mQt c60g trinh.

--.;

'-'"

........­

--./

'--./

220 • Chlfd!7g 7: St!dflng k/ch thu'6c va kh6a kef

Khai qualt- ve, Iki'ch thifoc t,ri1 thai Kkh thu'ac la cac chung IO'.li (family) h~ thong c6 thu~c tinh v~t chQn (il1stance properties) va thuQC tlnh I09i {type properlies) , Bc;1n co the d,nh d~n9' 191 cac thuQc tinh nay de tc;lO I~p cac lo9'i kkfl thl10c mOL phu hl1lP hdn voi yeu cau cua bc;ln. Vii dl,l, bc;l1i1 c6 the thay doi ky hi~u dau dong kich thu'ejc (ttck mark), dQ day net vel va mim sac cua kich thl1DC. Hdn nU'a, bQn c6 the dieu khien dl10ng dong cltal klcn thl1Qc. Bi;1n ding c6 t'h<~ quy d,nh kieu chu, ca chG' va adn V! cJho phan chCi' eua dong klch thttac.

Kkh ttilLfac cabhe la lii10t trong hai IIOi;li, t~m thai va thu'ang xuyen. Kich thuOc t9m t,hai tv oong xuat hi~n khi b9n chqn mot thanh ph'an trong e6ng trinh. Chung eho phep ban b6 trl cae thanh phan vao 'c:cng ttrinh m9t each chlnh xac..

f)!nh nghia ella kich thu'oc t~m thai

Klch thl10c t9m thb,j la, n'hU'li1g klch thl1ac xuat hl~11> cTe tham c,hleu vcH nhG'ng thanh p'han thang goe hay s,ong song gall nha"t thallh rphan rna b9n dang, t~:IO l'~p hay chQn.

Hlnh dual day minh hQa kich thtfOc t9m thai ella cae v~t the 'khclc nhau.

= '"..

t9

Klich trutoc t;lm thoi cho mot blic tliong sap t~o I~p Klch thLfac tam thai cho thanh phan dLJ'c;1C chQn

Kfc'h thl1o.c 't~m thai bien mat khi b9n them thanh phan kn,3c v~J() trong thie"t kef de giam bOt 51! r,61 ram cua kkh thl10c. De blefl t~p mot t9m thai klch ttur'ac, bi;jn can chQn thanh phan va thay doi gia trl cua l{ich thl1ac.

Listeningl dimension (kich thu'oc chi drnh)

Kloh thl1ac t9m thai dtfQC xuat hi~n khi b9n t9.o I~p cae thanh phan du'<;Jc 99i la cae listening dimension. Listening Dimensions xuat Ihi~n voi net chG' d~m (Bold) va thay d6i khi b9n t~o I~p mot tharnh phan nhl1 tl10ng. B~n sLr dl,lng listening dimension de <lieu ch'inh chi,eu dai hay vi td cua cae thanh phan.

Hinh dl10i da.y minh hQa' kich thl10c chil dinh (listening dimension) xuat hi~n ~hil b91i1 ve mQt but tuong. ChiJ y ranQl kich thl1i:k chi dlnh (listening dimension} cll1<1c xuat hi~1il tU cJau den cuoi but tu'ang.

f, .9/ .. .F -If"

1.11

BJi: stJd'lng klch thlJ'OC • 221

--

~ S·· S·

10' - 6~

B~n e6 the hi~,u ehinh kidl thu'd!;: chi dlnh (listening dimension) trong qua trinn t90 I~p hay sau --"

khi bo tri mQt thanh phan vaa ban ve bang each nh~p tnjC tiep tv bim phfm kfeh thu'oc yeu CaU,

'-" Hinh du'o'j day minh hQa kfeh thu'de chi d!nh (listening dimension) clla mQt but ttJ6'ng du'9'c hi~u chinh bang each dung bim phfm cho kfch thu'oc moi.

II ~

...-/

[, O' 6"

Diem bat dau ella tllang BU'c tuang da duQ'c ve cae tuang ben tri3i mot

~ d~n la 10' 6" .

A Khi b,;m nh~p gia tri kich thu'ac bang don vi h~ Anh, bqn c6 the nh~p bang ky hi~u eua .~ feet va inch, VI dl) nhu' 10' 6 3/4"hay chi la can sO gia trj cua feet va inch nhu'ng each

./ J nhau mQt khoimg vi dl,J nhLf 10 6 3/4. Neu bi;m nh~p ma kh6ng kem thea don vi, vi dl) nhu' 10, n6 se dLf<;1c hieu 103 10 feet (10').

T~O I,p cae tbanh phil" Yoi kich thu'ac t~ml thaii

8;;ln co xac I'~p Cae quy djnnl eua kieh thl!foc t9m thai va gia tri tang dan ella kfch thu'oc,

9jnh ro cae quy dinh cho kich thu'ac t,m thai '.-'

B9n co the dinh ra cac quy dinh nhLi'ng dl\~m truy bat d~e bi~t (snapping POlliltS) cho kich '......./'

thu'oc t9m thai. Vi dlil, b.;m eo the quy d!nh rang kfch thl1de t<;lm thai bruy bat du'ong trim hay m~.t eGa mQt but tl1ong. De quy dlnh nh[(ng, tham chieul nhu' v~y b~m su dl,lng hQp tho9i Temporary Dimension Properties. B~m co the quy d!nh cae. tham chieu nieng bi~t cho tl16'ng, '--' cU'a di va eU'a so.

-......,;Kkh thu'oc g,i'a ta'ng (increments dimensions)

Khi b~n t~o l'~p mQt tfilanh phBn, gia' tr! Ikich thl1dC t~m thai cua no se gia tang t~y thuQc vao mLtc dQ bi;ln thUl ph6ng hinh ehieu. MUte dQ gial tangeunQl tuy tliluQc vao kfd~ thu'oc cua snap --­increment du'9C quy drrnh rieng tmng h9P tho91Snaps. 891il co the QUY dinh gia tri gia tang nay cho kich thu'dt ghi ,chieu dai hay kfch thlJde ghi cho goe rieng bi~t du'<;1c quy djnh trong h9P thogi Snaps.

-.-'Xem kich ~hU'ac t~un thai

~n xem kich tliuloe t<;lm thoi eua mQt tihillnh phan bang tuy,ehQn Modify tren Design Bar. f)i€u '--' nay se cham dUt ho~t 09ngl oua cae I~nh khc3c de eho bc;ln chQn thimh pnan mong mu6n ..

Kich thu'dC tC,lm th6'i eho mQt thanh ph'an co the kMe vdi kich thu'oc tam bho,i khi b.;:l'n dang t90 I~p mQt thanh phan. Di€u nay xay ra vi khi bc:m dang ti;lo I~p. mQt thann ph'an thi kich thu'oc

-../

t9m th6'i eGa no tham ,chieu vdi trhanh phEIn gan nhat, va d'ieu nay thl co the tliLay dOi.

222 j ChLfdng 7: Sitdl,mg k(ch lhlf6c va kh6a ket

-.../

Hj~u chi'nh kich thu'oc t~m thai

Bc?n co the ojn'h !19i ikfGh co hay di enuyen cac thanh phan bang cach hi~u chinh kieh thLioc ~f1il '- thail cua chung va 1b9n co the di ehuyen duong dong klch bhuac de tham chieu vai cac thanh

phan mong muon. De lam du'qc afeu nay, b<;ln su d\,mg flinh vuong mau xanh dfel!J khien Qu'ong dong. Chc;m hinn vuong niw eho phep 'bc;ln Ibi;Hl thay doi Itheo chILI kY YI tri aua no, nhu' chQn ttl tim tl10ng sang m~t tu'ong. NhG'ng thay d'oil eho duang, d.on91 knolilg d\1q:c Itful l<;Ii.

Hinh dlJai day minh hQa mQt bU'c tLfong dl1Qc d,nh Ic?i bang each hi~u chinh khleh thlJoc t9m thdi.

10'· IT' 8' - 0"10'- 0" 12'- 0" I I.

T

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Tnloc khi hi~u chinh kich thl10c ~m thai Sau khi hi~u chinh kich thu'6c tQm thoi

Vi dl:l eua kieh thuoc t~m thai

Hinh duai day minh Ihoa cae kieh tnu'oc t9m thai cua mQt but tu'ong dl1QC chQn. Kfch thu'ae t<;lm thbi ,chi flO chfeu dal cua tl1(1ng va moi lien h~' vj trf doi, val Ci3c tLfong khik trong bim ve.

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Khai qjuat kich thLtac thu'ang xuy,en

B~n sli 'dl:Jng kich thlioe thu'ong xuyen neu b',?!n luon luon muon thay kfeh thu'ac eua cae thanh phfm trong mQt cong tr,inh. Cae kfch thl10c dfeu chinn theo tV I~ ella Ji!]nln chieu. B~m khong can ti;lo I~p Iloai kich thu'ac cho cae tV I~ hinh chie"u tieu chuan. Co hai phu'ong phap de b<;ln lien k~t cae kfch thuOc thuong }(uyen vo,l mQt ttrlanh phan. B~n Cio. th-e I~p kfch thl10c t9m thai thanh thu'ong xlJyen bang deh sUi dl,Jng ky hi~u ella kich thu'ac hay bc?n co the ,them kfch thu'ac thtrong xuyen 'bang each su dl,ln9 I~nh Dimension.

Bai: SU'df!ng kk:h thU'dC • 223

---

-.../f>jnh 'nghia cua kich thu'oC' thu'o'ng xuyen

Kieh thu'ck tht1ong, xuyen 103 nhifng kfch thu'oc ma b~n co the be tri them vao cae tMnh phan sau khi d:a be tri chung vaa, trong cong trinh. Kh6ng gi'Ong nhLl' kich thu'oc t~m thOb, kfeh thu'ac thu'ong xuyen luon lu6n hi~n di~n du cae thanh ph'an ~h6ng dl1qe ,chon.

Kich thttoc thLiang xuyen co hai tr<;3ng thai, co the hi~l.i chin'h va kh6ng the hi~LlI chinh. Kich tlll10e thu'O'ng xuyen cua mgt thi:Jnll phfm co the' dl1qc hi~u chinh dQe I~p chil khi thanh phan au'qc chQn. Trang tr9-ng thai kh6ng the hi~u ehlnhJ b,;1rI kh6ng th§ bien t~p gial trj cua kich thl10c thl10ng xuyen bai vi bhanh phan co lien h~ den voi thanh phan klnac khong du'Q'c It/a chl;)n. Bqn co the chQn cae kich thu'oc va thay dol cae thuQc tJnh cua no, kh6a hay ma kh6a eno ehungJ va ,~p c1t,Jng knoa ket (constraint) bafilg nhau.

Hinh du'O'i day minh hQa hai tr~ng thai cua kJch thu'cJc thtfong xuyen.

~12' - 0" 10'· 0"

12'.0" 10'Ii0"I, I,

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Tinh lJrang c6 the ni~u ohlnh Tinh tn;mg kh6ng the hi~U chlnh

SU' dl}ng,kY hi~u eua lkich thu'ac .-.../

MQt ky ihi~u ella kich thuoc xuat hi~lil gan Ikich thVOc t(,3m thai Qua mQt thanh phan. B~n chQn ky hi~u nay de doi rmQt kfeh thu'dc t~m tho:j thanh kich thu'dc thu'ong' xuyen.

Hinh du'Oi day mililh hQa each sU' dl,lnQl mQt ky hi~u eua kich thu'oc.

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Tn/oc khi nhap vilO kY hi~u kich thu'dc Sau khi nhap vilO ky hi~u kfch thu'DC .../

-/

224 • Chl/dng 7: SU'di)ng kich thmfc va kh6a ket

Sit dl:ln9 I~nh dimension (kich thu'oc)

B~n c6 the bo trf them ba ,IOi;li kkh thudC thuoli1g xuyen voi I~nn Dimelils'ion tren Desigh Bar.

Ban sau aa,y rna till ba: IOc;Jj [kich thu'ac thu'ong. xuyen ma b~n: c6 the su dll,mg.

Lo~i Mota

Linear Du'Q'c b5 tri giGfa hai diem chQn la tung phu'cing voi tn,lc ngang Ihay tn,lc dUng cua hinh ch,ieu.

Radial DUQc bo td vao Kich thU'de kich thu'O'c ban kinh cua mQt cung,.

Angular f)u'Qc bo tri tren nhieu diem tham chieu c6 chung mQt giao diem.

Sinh ra tham chieu cho kich thu'oc ella tu~an9

~n c6 the d!nh ro phu'dng each bat diem khi bi,in gan kich thUdC thu'ong xuyen cho mQt bLfC Wang. Vi dl,l, b~n c6 the dinh r6 duang tham chieu nao nen doi mau tru'oc tien. B<?n cOng co the dinh r6 vi uri ndi bat diem dau tien khi b~n di chuyen con tr6 tren rnQt blfc luang. B9n co the thl1c hi~n nhiIhg dreu nay bang eBch ,chon nhU'ng tuy chon thfch hQ'p tLr danh sach cua Prefer.

.dgJ~ fJ~ Pre/et Wall centerrll'leS v

Danh saeh Prefer dUc,1e kleh ho~t eho ~t ca cae 101;li kich thuDC ngo1;li tns kich thuDC Unear. /

Tim tuangl (w'all centerlines)

SLr' dl:Jng tuy chon nay, bi;m h;tn c6 the lam tho tu'dng co the du'QC do til t,jm tu'bng.

E - ~; - - - - - - - 3

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E - ---=jf- - - - - - - - "J

Sal: SLrdl,Jng kich thi/oc • 225

--

-....J'M~t tLfong (wan faces)

Su dl,Jn9 tuy ch<;>n nay, b;;m co, the quy dinh kfch thliOc cua mot bLtc tL1dng dlja tren m~t ngoa1 hay m~t trong clla tuang.

.-...../

I .,l I

I

r4 .....,/

I

Tim eua lap loi (center of core) oJ

50' dl:Jn9 tluy enQ.n nay, b~n co the lam cho tuang du'Qc do tLr' du'dng n~m giQ'a clla hai dlfang 'blel1 lop loi. Tuy chQn nay duqc ap dl:Jng ch© nhCr'ng tu'dng co nhieu hcm m9t IJ{jp nnu'tu'dng nhieu lap (Compound Walls).

M~t cua lap loi (faces of core) -­Sit dung buy chQn nay, b~n eo the lam cho tu'dng du'Qc do tLr' giO'a m~t trong hay m~t ngoai eua! hat du'drng bien Idp loi.

'-"

(0

'-"

Khoa lkich thu'oc thu'ong xuyen '-"

Khi b9n bo tni tlhem mot kich thu'ac thl10ng xuyen vao mot thanh phan, m{>t moe khoa khong kh6a xuS't hi~n gan dllong klch thu'ac. Moe: I<h6;3 chi dinh rang b9n co the 1ili~l.l chinh chieu dai clla tu'O'ng do va khoang tach gjua cac blic t,ual1g. VI dl,J, lJi;ln c6 the' re cae clau tu'ang ra xa --../

tJidn9 de gia tang e'hieu d'ai ella Wongl. B~n cung c6 the re but tu'ong len hay xuong de xem xet 'kho~n9 cach ,giO'a cae blic tu'bng. Sau khi thl/c hi~n nhUng hi~u chinh can thiet, de tranh cho vi~c kkh thuac cua mot but tu'ang bi tlha.y doi, bi;lO co the kh6a klch tlhuoc thuang xuyen bang each su dl,mg moe kh6a.

-./

226 • Chl/f1ng 7: Slid,!ng k/ch thl/de va khda ket

......."

I khongr bi k_hoa c:ua mQt tuang.

-f - - \)

;f

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Co khoa klch thli6'c thlidhg xuyen KJnong khoa, kfch tJiHl6'c thvang xuyen

Ghi ,de kich thu'ac: thliong xuyen

B~n co the doi gia tri .ella kich tlillfdc- thLiang xuyen bang each SlI dl:Jn9 h9P tho~i, Dimension ~ext. B<:ln co the tai bo tri so kich bhu'oc bang chD', quy djnh vi tri ,cUa. chQ' nam a phia tren (above), tru'dc (before), sau (a.fter) hay du'di (below) rcua g'ia tri tht/c.

on model aeometry.

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HQp th~i Dimensioll Text

Bien ~p d'u'ong dong kich thu'ac

B.;tn co the them cac du'ong dong viw mQt kich thlioc th'llong xuyen voi 'tuy chQn Edit Witness Lines treril Options Bar. B"9n co the SlI dl,Jng tuy chQn nay de ma F9n9 mQt kiclil thu'ac hi~ hlfU bang cikh b6 tri them cac dJiang kich thLfaC. Day kkh thu'ac ket qua fa mQt v~t the.

Ba,:- Slfdt,mg kfch thl/oc • 227

---

Hinh dl10i day minh hQa each slf dl,mg Itfa chQn Edit Witness Lines de phat trien mQt day kfch --'" thlfoc cho cae v~t the khac.

12' -•0" '-'" I. I. ~ • -------J

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Mot kich thlfoc

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Them cae dlfong dong voi tuy ehQn Edit Witness Lines

12'.0 '--"

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Cliluoi .kich thl50c cuoi cung ...­

Vi d\J ella, kich thu'oe thu'o:ng xuyen

Hililh dlfdi' day minh hQa mQt but tU'O'lilg, nam nganQi voi kich thu'oc thu'O'ng xuyen. Chieu dai Gua tLJ'ong ngang la 11 feet, va khoa-ng each tLt buc tl10nQi dU'ng den dau trai ella Wong ngang: bi ~h6a 191voi gia trj Iii 5 feet.

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128 Ii Chl.fCfng 7: SiJ'dl.mg klch thl.f6'c va k.hda ket

'--'

Hinh dUal day minh hQa vj td clla hal hue tliang sa'u khi but tU'ang dung dU<;1e: dl1 e:huyelil sang trail. Chieu dai cva tu'ong nam ngang bay gia la 13 feet, nhiJng khoimg cach giua buc tu'ang dUng va aau trai ella tLfong ngang van cx:m co d[nh.,

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13'·0"

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Hu'olng d~n khi lam vi~,c voi krch thttoc

NhQ'ng thao tac toi Lfu sau day se giu.p b~m l!am vi~c co hi~U qua vcH kich thl1oc.

Thay doi kich thl10c t~m thai sang thl1C1n9 xuyen khi b~n ~Irl tham khao thLtong xuyen khoang each: giua cae v~t the trong lue lam vi~C. Sit dung kid~ thrLti.k thl1ang x1uyen s€ nhanh han la dWn cung mQt v~t the nhieu Ian de tim ra [<hoiwg eacrt giua chung v6~ tae v~t tile kh~e:. B9n co th€ XQ9 bo c~c kich thu'ck S9U nay.

B6 bri them cac m~t tham chieu song song, hay cac dLf6ng model (modell lines) Iilgay cae gQe cua, mQt can IOhomg khi b<;m muon b6 tri cae :kich thu'oe ngang, qua cae goe na,y. Sau do bi?TI co tile b6 tri cae :kfch thl10c giua cile m~t phan9 tham chieu song song nay va d~rucae m~t phang tham chieUJ n'ay di. B6 tri them cae m~t phallg tham cnieu song song nay la yeu c:au bat bUQc bOi vi b<;ln chi' co the bo tni kich thl10c giCr'a hai bue tu'ong song song.

Cl1u y:, TUy theo II/a ehQn, b<;ln co sLr' dl,mg eong Cl,J Tape 'Measure de xae o!nh khoang each giUg cae: e9nh CUg mQt g6c.

Them IO<;li kich thLfOc vao t~p till dlj an m~u de' trimh vi~c phai t90 I~p ilhfeu lo~i kich thLfoe cho moi dl/ an.

S(( d\;lng tuy ehQn Duplicate View> Duplicate de t<;lO I~p mQt pnien ban hinh chieu ma b<;ln (fa dalJ kich ttn16't va cac ghi c!liu rna b<;ln cla b~n bo tni khi lam vi~e voi mQt corng trinh. Dieu nay ge)Up b<;l1l1 trinh bay m9t hinh chieu gQrl glmg ma khong mat cae chi tiet.

Chu y: B9n ding co the 'dau nhung kich thlloc riel'lg eGJa minh.

Die.u c:hi'nh tV 1$ hinh chi'eu ti:nioc khi bo tri kich thuoe va chU. Kich thu'oc v-a chu tl/ dong clieu chinh kJch CO' thea tV 11$ hhn.h chieu ma chung da clU9C b6 tri vao, nhu'ng neu b9n thay doi tV 1$ Ilinh chieLi sau khi d~j' bo tri kkh thl10c va cac ghi. dill, b<;l[J c6 the can phai I<iem tra vi~c bo tri c'hG' ella kieh thuoc va cae ghi chu van con -r5 rang.

Ba/' stJdl/I?9 k/ch thi/de Iii·229

Bai t~p: rLiutr1' vi~c voi kich -­thu'ac'

Trang bili t~p nay, bc,;m b5 trf kfch thu'oe de hi~u 2. ehinh vi tri cac bCre tl1dn91 trang rnQt c6ng trinh. ~n cCmg b5 trf Gk ohu6i kfclil thu'oe chung qu-anh m~t ngoall ella Gong brinh

Bi;ln phai tai b5 trl cae bU'c tltdng trangJ mQt c:6n9' trinh. De lam dietu nay, bi;ln bo tr,i kich thl10c eho uk bU'c tu'ong va thay doi kfch thu'oc de hi~U chinh v~ tlii' c,ua cae bCrt tl1dng nay.

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3.

4.

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ff 5.

6. Bai ~p hoan tat

Holm tit bili ~p

De haim tat bai ~p, thea c.ae bl10e trong Quyen s<.kh nay ho~-c trang baj t~p tren man l1inh. Trang damn sach cae chl1ang va bili t~p tren man hinh, nhap vao Chaptr;r 7: Using Dimensions and Constr.ail]ts. Nhap vao Exercise: Work with Dimensions.

80 tri kich thu'oc thuang d~h,g tuyen (linear)

1. _Mo ~p tin Ldiemensioms,rvt hCJY m_dimensions.rvt T~p tin du'Q'c mo ra voi hinh chieu m~t bang san Level 1.

ChQn but tl1dng ngan nam 0 t~n euog ella phia ben tn3i. Kfch thu'GC t9m thai xual hi~n.

10'·

I Nlhap vao ky hj~u kklh thl10c de thanh kich thU'ac th'l1ong xuyen.

10' - 0'

........

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........

-./

"-'"

.-.-'

Tren Design Bar, Basics tab, nhap vao Modify de xoa Sl/ II/a ch<;>n .

Trang cua so hinh chl€'u, nnap VaG dl10ng kfch thliac de chQn no.

De hi~u chinh kich thl16'e da chc;m:

Di ehuyen con tro tren dl1dng kfch thu'oc de no dei thanh hinh hai mGi ten.

~Re dl1O'ng kfch thl16'c ra xa but tu'ong.

~

Tha du'ang kich thl1ac phfa tren auang eG mqt it. v, td ohinh xac khong can thiet.

"'-"

230 • Cht.ldng 7: SLr dl,mg kiM tht.ldc va khda ket

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7.

8.

De thay doi' V! tri eua du'ong dong ben traf, nhap hinh vuong dieu khien oua du'ong dong ben trc3i.

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T .0· 10' ..:. 0·

Chu y du'ong dong da di chuyen vaa m~t trong eua tl10ng ben trai. Neu no dieh chuyen ra m~t ngaai, nhap no rnQt Ian nU'a, Gia tri cua kich thu'oe eGng du'QC cap Iilh~t

Nhap voao hinh vuong dieu khien cua dl10ng dong ngay giO'a hai ran de di chuyen no sang m~t trai ella tu'ang tham chieu.

~

II' • 1L3118" 10'.0­

Chu y c13 hai kieh thl10e deLi dLiQe ~p

nh~t.

9. ChQn tllfong ngan phia bern trat. Chu y klein thu'Ge t<,lm thai xLJat hi~n de doi thanh kfch thl1ac thuong xuyen,

11 '·"23/15· 10' - •• ,

12' - 0­ 10'.- 0"

bf I•I J'"'. v- I

g

~

------, h -, I .r-­10. De bien t~p kJch thu'oe tc;lm thail:

Nha'p vaa so eua Ikfeh thu'oe trai, 12' 0" (3600), ella kfch lhuoc tc;lm ttndL

Nh~p vim 8' ,0" (2400 mrn).

Nhan ENTER. TLiong ngan ben trai dil di ehuyen sang brai.

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sai: SlI dljng kkh thtfac • 231

11. Trang cua so hinh chieu: 15. Di chuyen eon bra ve goe duOi trai ella cong trinh cho den Khi thay dtJ'ang tim euaNhap V~lO 56 ella kic-h thu'oc ben phai; tuang nam ngang ph(a du'oi xuat hi~n. .....J14' 0" (4200), cua kich thuDc t~m iKieh thuoe chi dlnh (Ustenjng DimensIon) thoi de bien t~p no. xu&t hi~n tuy rhea con tr6. Cae kich thu6'c

Nh~p VaG 10' 0" (3000 mm). co net d~m va b~n [0 the bi~rn t~p ChUllg "' Nhan ENTER. TLl'ong ngan Deli! trai da trtlfc: tiep.

di chuyen sang ben phai.

11'- 2 3J16" 10'- 4" ,

10'- D"12'- 0" H--.

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f ­

'- ­~

II I I r ­'·6"

16. Nh~p 12' 0" (3600 mrn), va nhan ENTER.12. Trang cua so hinh chiew, de hi~u chinh V! Con tro, bat diem t~i vii tri center-ta.-center tri eua tl10ng ng2ln CJ gili'a:

'-'"(to" t.im d~n tim) voi khoanQl each 12' 0" ChQn tuong a gili'a cua ba tuang (3600 mm) tfnh tu bu'c tuong ben trcii. ngan.

17. Dj c:huyen con tro fen phfa tn§n de ve rnQt• Thay doi kich thu6'c ~m thai thanh 8'

buc tUdng va noi no voj bUc tU'ong nam0" (2A'00 mm), va nhan ENTER. But

ngangr d g"iU'a. Nhap de b6 td h/ong.tl!l'ong duQ'c chQn da d~ chuyen sang phai.

--.,;

......."

13. Tn~n Des-ign Bar, Basics tab, nhap vao Wall.

14. Ch2k chan ralilg Basic Wall': Generic - 8" (Basic Wall: Generk - 200mm) du<;1c chQIil trong danh sikh euaType Selector.

18. Tren Design Bar, Basics tab, nhap vao Dimension.

19. Tn~1il Op'rions Bar, ch~k rang Wall Faces J

dUQc chQn trang danh SiKh eLla Prefer.

232 a, Chl/dng 7: 5((d/,mg kich thl/cfc va khoa kef

20. De bo trf rnQt kich thu'oc tli m~t ngoai cua hfang baa ben tra.l delll 'l11~t trong eua Wong nay:

~ Phorng Ion goc du'oi tra; eLla, cong' trinh.

N_hap vao m~t ngoai cua Wang.

Nhap vao m~t trong ella tuong.

0' ­

2_1. Tiep tl,lC de ghf Fa kfch thuoc eua cac but tuang va cae phong bang each nhap vao cae m~t ella tuang nhu' hinh hu'ong dan.

!;j

22. Khi bQn den liT1~t ngoai cua tu'ong xa nhat pilla ben phai, di clr1uyen ,can tra den vung trong ciJai ella so hlnh chieu p'hia ben du'oi cua tu'ang nam ngang de khong con tuang tham chieu nao dOi mau nua.- Nhap de hoim tat vi~c bo tri k:iohbhuoc.

23. Tren Options Bar;

Chc;m Entire Walls tli danh sach cua Pick.

Nhap vao Options de rna h9P thoq;j Auto Dimension OptiOIlS.

24. Trong h9P tho<;ii Auto Dimension Options:

ChQn h9P kiem Openillgs.

• ChQn Widths.

• Nhap viw OK.

25. Trong cU'a so hinh chieu, ae bo bri kkh th,u'Oc cho '16 Clla tren tuang:

ChQn bU'c Wong nam ngang rna b9n vLr'a bo trf kich bhllfdc.

• Re con tro ve phai dU'oi dong kich tlhlioc dau tien va Nhap de be tri dL1C1ng 'kfch thlfoc khi;lc.

26. Tren Options Barl nhap VaG 'Elemelilt Propertie.s.

27. Trang ih9P th09i Element Propertiesl nhap vao Edit/New de ma h9P thoi;li Type Properties.

28. Trang hQp tho~ll Type Properties, dL10i Type Parameters, Graphics, phan Witness ILine Control, cnc;m Fixed to Dimension Line.

29. Nhap OK de dong tat ca cae hQp tho~i.

Dliong kieh thu'oc du'Qc ~P I1lh~t.

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BiJl~' Sif dt,mg loch thlldc • 233

30. Trt?n Options Bar, nhap vao Element Properties.

3.1.< Trong hqp thQ~i Element Properties, nhap vaa Edit/New Gh~ ma h9P tho~i Type Properties. ...J

3'2.. Trang, h9P tho<;li Type Properties, du'ai Type Parameters, Text, ph~m Units Format, nhap vao 6 gia trio

33. [rn the Format dialog box:

Xoa ch9n trong h9P kiem Use Project Settings. Ph'~in Rounding (lam tron so), chQn To the Nearest 1/4" (To the Nearest 10).

• Nhap vao OK.

34. Nhap vao OK de dong tat ca cae h9P thO<;li.

3,5. Trang, ella so hinl1 chieu, eh~k chan rang tat ca cae :kfch tnl1cJc dil dL1<;1C c:~p nh~t. -...J

36. Oong ~p tin ma kl16ng can lu'u.

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234 • Chlfdng 7: Stfd~ng k/ch thlfoc va khoa ket ---­

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Bail: ,Ap d\lnlg val ~oa b6 khoa"ket (constraInt)

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Tong quan

Bal hoc nay mo til cach ap dl,H'l9 v'a p!)~ b6 kh6a Ket (constraint) tlt' mQt cong: trinh. B9n bat dau bili hoc banQi phan ho.c ve khoa ket (constraint) va cac IOc;li khoa ke-t (constraint).. Ke tiepI b~n bi;ln hQc cac bu'oc de ap dl,mg va pha be khoa ket (constraint) cung mQt vai thao tac nen dung khiap d~ng kboa ke't (constraint). Bai hQc ket thuc Ibang m(>t !bai' t~p voi nQi dung ap d~n9 kh6a ket (constraint) cho cac thanh phan trong rnQt cong, trinh.

Khioa ket (constraint) c:ho phep bc;ln kh6a 19i vi trf cua' cac thanh phan trong m(>t cong trinh. Khoa cac thanh phan ngan ngU'a vi~c vo tinh thay doi vi trf. B~n co tihe kh6a hai thanh phEln voi mQt khoang cach nhat dinh va trong vi~c dong hang. Bi;ln co ~he' duy tri khnang cach giO'a cac thanh phan luon luon b~lng nhau.

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KMa ket (constraint) de hai cU'a sO doi di~n nhau trong mQt ~n phong luan luan thang h~mg

M\lC tieu

Sau ~hi: h02ln tat bai hoc nay, bqn co the~

~ Hieu dU'l;1C: kh6a ket (cQl1straint) va, cac 10000i kh6a ket (constraint).

Ap d~ng va pha bo kh6a ket (constraint).

Xac dinh cac tlhao tac nen dung khi ap dl,mg kh6a ket {wnstraint).

Ap dI,mg, kh6a k€t (constraint) cho cac thanh phan tr;ong mQt cong trinh.

BJi: Ap dlJng va pha bd khoa ket (constraint) '. 235

• •

Khai quat ve kh6a ket (cpflstraint) --"

Bi;Hl co the Sl1 dyng khoa ke't (constraint) de khoa moi lien h~ ve vi t,f hay V! tri tuy~t doi eua ..J

mQt hay nhieu thanh phan trong mQt eong trinh. Moi lien h~ eua khoa ket (constraint) giup Dqn duy tri nhU'ng y do tlhJet Ike, nhu' d'uy tri mQt dJl.tang ella tuang ngan nhieu b~e clla mQt eong trinh Inai tang. Bi;l'!il co the 'kh6a cac kieh thl!fac va dong val khQa ket (constraint) ~hi tqO

'-" r~p Gang trinh. 'KhJ bi;m kh6a cae kieh thLfoC, bqn co the khoa kich thU:oc ehieu d2li hay vi tri hay qIJy djn'h cae dOqn eua mQt ehu6J kfeh thuoc chu6i co oung (hieu dai,

'-" f)!nh nghia cua khoa ket (constraint)

Khoa ket (constrgint) la nhU'ng v~t the dieu khien co kha nang khoa mQt hay nhieu thanh ph'an de xac L~p mQt moi quan h~. Khoa 'ket (constraint) cung co the khoa vj trl eua cac v~t the du'c;1c dl(;m. Chung xuat hi~n trong mQi hinh chieu ma eac tharn chieu cua no hien dj~n. Bi;lllr thl10ng sU' dl,lfllg cae kfeh thu'oc de ap dl:Jng khoa ket (constraint) vao cac thanh phan .(\Ja cong trlnh. Tuy nlnien, khoa ket (constraint) c6 the thl/C hi~n cho cae kich thl1ac dQc I~p.

Bqn leam cho m~t khoa ket (constraint) hi~n di~n bang each IchQn tham chieu clla n6. BQn cungl c6 the dieu ikhien su' hi~n di~n clla khoa ket (constraint) bang each b~t hay Uh vai tuy ehpn Visibi I1ty/ CJ r.a,ph ics.

Khoa ket (constraint) co ba IloqL

'" Klch til u'ac ,. Dong

.. Chot

Kh6a kit (c,o~nstr,aint) ,kich thu'O'c

Hai 1Q9i ella khoa ket (constraint) kich thL1ac la chieu dai va bang nhau. IBql1l tqO I~p kiloa ket '-' (constraint) kloh thudc ho~c bang each be tni va khoa cae kfch thl10e ho~c :khoa rnQtr dong ihang. vi dV, khi bqn be tri kich thuoe rhuang xuyen, bi,m co the khoa n'hli'ng kich thl1dc nay de chieu dai hay V! trf c-ua cae thanh phan khong thay doL Khi bi;3n kho8, mQt kfch thuac, mQt thanh ph'fln khoa ket xua't hi~n duBi dc;mg mQt moc khoa du'c;1c tqo I~'P.

Kh6a kit (constrai,nt) chieu dili

Kni bc;m Ikh6a mQt kic'h thu'dc vail mQt khoa ket (constraint), b~n ngan ngua vi~c kfch thu'ac do thay doL Trang hinh mifilh hQa duo:i day, 'khoang each giua cU'a oi va tu'bl1lg ben trai dlfq.C ......." khoal ket (constrain). Kiloimg cach gi;G'a cU'a di va tl1ang ben phai khol1g dLJ'c;1c khoa ket. Neu b9n di chuyelil tuang ben trai, cLta di cOng se di: chuyen nhllfog khoang each nay luon l!!.Jon co ....J

dinh. Tuy nhien, neu b911 di chuye:n bU'c tuang <ben phai', vi trr cLia ctr'a oi khong thay doi vi kfch thlfac Iiern qtJan 'khong dl1~c kh6a ket (constraint).

T- 31' 8' - 3"

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236- Chu'dng 7: Kich thu'ac va kh6a ket (constraint)

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Khoa ,ket (constraint) ,bang nhau

MQ't kh6'a ki~t (constraint) bang nhau kh6a m6i ~himh ph'an trong chuoi thanh ph'an ella kich thl10c co chunQl mQt chfeu di3L Khi b~m chQn rnQt oLtong ikfcl1 th110C, mQt dau hi~u mau xanh equal' (=') 'xuat hi,~11 pflia tren dl10ng kfch thl1ac de bieu hi~n cho khoa ket (constraint) bang nhau.

Khoa ket (constraint) dong ha,ng

SI! dong himg giCr'a ihai thanh phalil co the bj kh6a I~i boi khoa ke"t (constraint) dong himg, dliQ'c xuat hi~n nhl1 hinh moe khoa c~;mh du'ong khuat dang' noi giU'a hai thanh plnan Ithang htmg. Neu b~n oi chuy-en cae thanh phan dang al1gc dong himg n:ay hay thanh phan khi3c di clnuyen, m6i lien h~ dong hang nay v~n con duybri nhl1 hinh ve.

io .·I~ CD

@ I­ -, ,­ _ -, 0­ - ~ -

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Khoa ket (constraint) chat

B~n co the chQn cac thanh phan va chot V! tri hay kich co hi~n t9i cua chung bang each dung oong Cl,l Pin tren Edit toolbar. Khi bt;ln chot mQt thanh phan, no se xua'f hf~n mQt ky hi~u chot 'khi n6 dl1<;tc chQn. 89n co the Ilhap vim ky hi~u nay de thao chat cho thaoh phan ma b~li1 di c:huyen hay thay dfiil kfch co cua 106. Ky hi~u van tOn t9i vai thanh phan nhu' la m<i)t c6ng tac sau khi chot hay tlhao duSt.

Hinh du'oi day minh hQa rnQt khoa ket (constraint) chot ap dl,lng cho mQt but tu'ong trong cae hinh ohieu khck Ilhau.

r/l

Tu'ong du'<;Ic chat trorng hllilh chi€u m~t ba-ng Tu'ong b! (hot tu'o'hg tl'.! trong m~t dung

Bai: Ap dvng va phi bo kh6a ket (constraint) '. 237

Hinh sau day minh hc;>a mQt tL1(jng khong bj chot. Chu y rang kY hi~u dieu khil~n chat van hi~n --' di~n v,a cae diem dieu ~hien kkh co van h09l: dQog.

40'.0"

I .,..: ~, I

-..../-:8--,----r-r­.0;,

/y~ Khi b~n xoa bo cae v~t the b! chot, mQt thong tin ctmh bao se xuat hi~n.

....."

Quyen ~u tiencua cae khoa ket (constraint) Khi D9n quy o!nh nhieu khoa ket (con~raint), vai kh6a ket (constraint) se chiem qu.yeli1 LIU tien. Kh6a ket (constraint) don9hang lit! tien hon (override) kh<ba ket (constraint) chieu dai, va ikh6a iket (constraint) chieu dai uu tjen hdn kh6a ke't (constraint) bang nllau.

Nell b9n quy (jf'jnh c:a hai ikhoa ket (constraint) dong himg va kiloa ke"t (constraint) chieu Gai cho m9t I09t cae thanh ph:an va GO di chuyen mQt trong nhUn9 thanh phan do, D9n se nh~n mQt canh bilO co nQi du:ng Ci~1 hai 109i' klloa ket (constraint) Ikhong the duy tr1. Khl bc;H1 nhap vao Remove wnstraint (pha bo khoa ket) trang h9P canh bao, khoa 'ket (constraint) chieu dai se bi pha bo va kh.6a ket (constraint) dong himg c6 the se tOn t9j. Tu'dng tlir, neu b9n quy djnh kh6a ket chieu dai va. bang nhau cho mQt IOi;lt cac thanh phIm va, co gang di chuyan mQt thanh phan, b9n se nh~n mQt canh bao co nQi, dung eEl hoi IO;;ti khoa ket (constraint) khong the d'uy tri... Khi 'bi;ln nhap vao 'Remove constra!nt (pha DO kh6a ket) trong hQp tho91 dmh baa, kh6a ket (constraint) bang nhat!J se tii pha bo va !<hoa, ket (constraint) clni'eu dai c6 the v§n dlf<;1c duy tri.

Vii dl} cua khoa ket (,constraint)

IHai CUd oi cua hai dau hanh ,lang dai cllf<;1c kh6a thang himg Ilhlf hinh ve.

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238 • Chuang 7: Kl'ch tht/ac va kh6a kef (constraint)

Alp d~ng v,a x6a be kh6a ket (constraint)

B~n co th~', khoa ket (constrain) cac kfch thuoc val dong hfmg bang cach be> tvi va khoa chung 19i. B~m co the pha \)6 khoa ket (constraint) bang cach hi~u chinh kh6a ket (constraint) cac thfmh pl\an. B~n co the hi~U chinh khoa ket (constraint) cae thimh ph'fln mi;>t caoh aQe l~p va pha bo no khi b,;;rn xoa b6 cac kkh thuoe.

Quy trinh: Ap d~ng mQt khoa Ike't (constraint) Ikich thu'ac

Cac buck sau day me til cach ap dl,mg mQt khoa ket (constraint) kfeh thu'oc vao cac thanh phIm trong mQt ceng trinh.

1. Ch9n thanh ph'an rna b~m muon ap dl:mg khoa ket kich thuoc. Nhap vao ky hi~u kich thlltoc nam ke du'ong ~ic:1:1 thuoc de chuyen kfch thl10e t9m thai sang kfch thuoc thliang xuyen.

2. Ch9n kich thu'oc ma bi;ln muon khoa ket (constrain).

3. Nhap vilO moe khoa dang rna de khoa kich thl10c do 1<;Ii.

Quy trinh: Ap dVng mQt khoa ket (constraint) dong hang,

Cae: buoc sou day me ti3 cach ap dl,mgl mQt khoa iket (constraint) dong himg vao cac thanh phan trong rtilQt eong trllilfl. ~

1. Tr;en Tools too'lbar, nhap vilO AHgn.

2. Ch<;m thanh phan th-li nhat de dong hang.

~ 3. Ch9n cae thanh ph'fln khac de dong hang voi thanh ph"an thU' nhat.

------.------·c I

4. Nha'p vao mac khoa de khoa ket (constrain) slf dong himg nay.

B J- - - -J -.- -- - - . ~ IIn -

Quy trinh: ,Pha bo mQt :khoa ket (constraint)

C~c bli?C sau day rna til each pha be mqt khoa ket (constraint) tLt cae thanh phalil ttong mQt c:ong trlnh.

1. De kh6a bo mQt kho8, kel (constraint), e:h9n thanh phan ci kh6a ket va thlfC hi~n m9t trong cae dieu saUl:

Nhap vao moc khoa de pha bo khoa ket dong himg hay kh6a ket kfch thu'oc.

Nhap vao dau hi~u ;; de xoa b6 khoa. ket (const,aint) _bang nhau.

Nhap vila dau hi~U chat (pin) d~ phil b6 khoa ket (constraint) chot.

Bai~" Ap dung va phd bd kh6a ket (constraint) • 239

2. Ch(;m kkh thlfoc bi khoa chat va nhan DELETE de xoa b6.

Chu y: Khi bi;m )(loa b6 mQt kfch thl10c da bllkh6a chot, b~fil se thay mQt c2lnh bao voi nQi dung la b~n dang xoa 06 m(>t kfoh thu'ac dang bj kh6a va/hay kh6a keto

3. Nhap vao Unconstrain de pha be khoa ket (constraint).

Hu'ang din cho vl~c ap d\lng kh6a ket (constraint)

NhiIng thao tae nen dung sau day se giup bi;m tiet ki~m thai gian khi bi;ln sU' dt:mg khoa ket (constraint) trong m(>t I(ong trinh.

80 trl va kh6a kfch thl10c thlfong xuyen giG'a hai thanh phan. Dieu nay dam biw rang mot thanh phan se duy tri khoimg each co d!nh vol thanh phan khc3c, nhLf Idli b«;ln quy dinh chlieu IrQrlg Cl) the' oJa himh lang, va muon giG' kfoh thlioc tnay khi bi;ln thl!C hi~rn cae:. thay doi tren m~t bang.5u dl:Jng m(>t kh6a ket (constraint) bang nhau tren kfch thl10c thuang xuyen giCIa hai trong mQt day cac t:Mnh phan de ch~k chan rang cae thanh ~ph2ln d'uy ttl dli<i1e IkhOang akh bang nhau. Vf dl,l, voi m(>t quy d!nh cae ctia so clilo mQt Pi"l0I19, ikhoang caeh bang nhau v~m dl1qe duy tri eho du can p~ong thay dol kkh ca. Tililh toan tnu eong de bo trf thanh phan se m~t m6i va de gay r-al IO'i.

5ti dl\Jng congi Cl;J Align de bo tri mot khoa ket (constraint) giG'a hai thanh phan de dam bim rang cae thanh phfln du'qc dong h~mg d&ng hay d6ng hang: tngang voi cae m~t tuang. 51! d6nQl han9 nay se hi~n dj~n khl tMnh ph'an dligc cln~m.

I<hoa cae d6ng hang mot each' can th~n de' dam bilO rang kfli bi;m thay doi toim bQ m~t dting eua e6n9 trinh thl tat ca tuang, san, di~n rich phong va bang ~hang k@ thay doi mot eaeh tv OQIilQi.

ChQIII mQt hay hai nguyen tac thiet ke quan trQn9 nhat ma b~n ap dl;Jng va SLt dl,lng khoa ket (constraint) de lbo' sung aho chun9', De <$am bao sl/ uyen chuyen trong qua tdnh hi~U dhinfl, co gang dltng 19m dl,Jng kh6a ket (colilstraint) trong thiet ke e!l.a b~n, Dreu nay se tranh gay 16i, va ti.et ki~m thai gian cua bi;ln khi phai x6a b6 cae kh6a ket cae thanh phan ---..;de hi~u ehinh mQt thiet ke.

Ghat (pin) cae rn~t bang khu Vl/c eong trinh du'<;1C nh~p vao sou khi bc;m bat oau stf dl,lng chung de ti;lO ral cae be m~t (lla hinh va ehl!l v,j cua cOlilg trinh. Chot (pin) m~t bang luai dinh vi' sau khl b<;m da khai t-rien. Vi~e chot cae m~t bang va 1110i o!nfl vi se ngan ngU'a Jlien tt1qng bo trv nham se rat kh6 do tim sat! nay tron9 mQt dl/ an.

Vid~ ...J

Trang VI dt,J duol day, hai tu'ang trong m(>t eon9' trinh da. bi kh6a voi khoa k€'t (constraint) dong hang. Du'cfng dong se xua't hr~1l khi b9n ohQn m(>t bitc Wong bj kh6a ket ...-/

.Ji 1- ---J-----1 ~ t 240 • Chu'Cfng 7: Klch thu'rJc va khda ket (constraint)

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iii t,p: Khoa: ket (constraint)

Trong bili t~p nay, bc:m ap dl,mg khoa ket dong 2. himg va kfch th110C cho cae bh~mh ph'an trong mQt c6nQl trinh. Ngoai ra, bqn ap dl,mg mot kh6a Iket (constraint) c'hot.

~n can dong cae cita di 0 cuoi himh lang giua vCii nhau, 8i;lf1 cung can djnh tim cua clia di trLmg vC1i hanh lang I'oi viw va dong m~t eua cae bile tl1ang eau thalilg (j hai tang khae filhal!J. Ngoai ra, b1jln can khoa t9m vi tri ella mot bU'c tu'dng ngan.

Bqn lam nhl1 sou: 3.

Ap dl:Jng mQt khoa ket dong himg de dong 4.hang cae eua di.

Ap dl,mg fIl9t khoa ket bang nhau.

Ap d\Jli1g mot khoa ket dong himg de dOllg CCl.c bue bu'ong.

0, Ap d\,mg va pha bo khoa ket chot.

5~

Bai tap hoim tat

Hoan tat bai ~p

De hoim tat bai t~p, thea cac bl1Cfc trong QLlyen sach na,y ha~c kong

6.bi'li t~p tren man hinh. Trang danh sach cae chU'dngl 'Va bai ~p tn§n mim hifilh, nhap vaa Chijpter 7: Using Dimensions and Constraints. Nhap vim Exercise: Apply Constraints.

Ap d~n9 khoa ket dong hang de dong hang ,cae ell's c.1i

1. Mo ~p tin Lconstraint.rvt ha.y 7.m:-constraint.rvt. T~p tin rno ra voi hinh chieu Ground Floor.

Phong Ion khu vl/c cua di ben tn§i.

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l-I

Tren Tools toolbar, nhap vao Align.

Trong c\fa so 'hinh ehieu, chQn dl10ng tim ella ella di 56 4 a phfa ClJIoi ben tn§i Clla: himh lang.

Cuon mim hinh sang phai va ehQn du'ong t1jm eua clla di so S dang nam cuo!] ben pha'i clla himh !Iang. Olsa nay dl chuyen lende thang hang vor cua oi s64.

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I

Nha'p vila moe khoa de khoa 19i khoa ket dong hanQl. Ky hi~u moe khoa ohuyen tLr' md sang khoa.

Tren Design Bar, nhap vao Modify.

sal:.4',O dl)nq va jJha b6 kh6a ket (constraint) I. 241

Ap d~ng khoa kit bang nhau -./7. Thu nho I~i, de b9n c6 the' tha'y dl1Qe cac cU'a dj CJ hai dau himh lang.. Chu y rang,

1. Ph6ng Ion cU'a di so 4. cU'a iben pna'j 55 5 da di chuyen ra, kh6t tu'ong dmg mc)t khoimg nhu' cU'a ben trai'

2. Tren Design Bar, Basics tab, nhap vim so 5. Dimension.

......."

3. Tr,en Options Bar, chac chan rang Wall Faces du'Qc chQn tu danh sach clla Prefer.

4. Trang CLra so hlnh chieu:

ChQn m~t phia du'oi C:lIa tl10ng nam ngang gan ctJ:a di so 4.

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.. OhQn C9nh phfa tren ella cU'a ai. so 4.

Keo COn tro sang ph'fa phai ella eU'a di va nhap de bo trfkfch thl1oc.

"-'n CD 8. Trong cU'a so hlnh chieu:

• ChQn kfch thl10c (khong phai chQn chl1 so) tren cU'a di ben tra'i.

Nhap vao moe khoa dang rnd de no dong 19i va kh6a ket kfch tilLfoc nay.

-..../

5. Tren Desj~/il Bar, nhap Modify.

6. Trang cU'a so hinh chieu:

• ChQn cl1a di $.6 4.

Nhap viw so ella kich thl10c ma b9n viI'a bo trf trong bl10c 4 va nh~p 0' 8"

........,(200 mm). Nhan DELETE de xoa b6 kfeh thLfoc.

9. Trong hc)p thoi;li cimh bao, nhap vim OK de xoa b6 kfch thtiac nhLfng v~n de li;li cae -' thanh phan b! kh6a keto

'---"

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----­ 0'- ­ !:­

• Nhan ENTER.

--" 242 • Chu'dng 7: Klch thU'elc v.a kh6a ket (constrt;J/nt)

10. Trong eua so hlnh ehieu: 3. Trang th9P thO<;li Element Properties,:

• Thu nh6 c'ho den khi thay eU'a di hai DLioi Instance Parameters, chQn eanh 56 1 Ci phia nam xual hi~n. Ground Floor tJ(r danh siICh ella

Underlay.• Chon eua eli nay. Nhap vao OK... Re no ra kh6i diem giG'a nhlt hinh ve

hlfong d~n. Chti y: cae but tu'dng ella tang tr~t xua't

l..=.. hi~n va co mau xam..

4. Chon tliong ngan oam gec dlfdi trilL Re no sang phai de' but tu'ong nam phfa dlfdi tang tr~t dlfQC xl!.Jat hi~n"

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11. Trong eua so hloh ehieu:

Nhap vao ky hi~u kich gao elliong kieh ~hlioc de' doi tV' kich thudc ti;lm thai sang Ikleh thl/oe thu'ang xuyen.

.. Chon du'ong kfch thlidc.

Nlhap vim !<y hi~Ui EQ de oin'h V! l<;Ii eua eli ngay giCfa va khoal I<et no l<;Ii t~1 vi trf nay.

_IN'_ '5

L 5. Treen Tools toolbar, nh~p vaa Align.

6. Tren Options Bar, chOnl Wall Centerlines tV danh silCh ell'a Prefer.

7. Trong 'cua so hlnn ohieu, chon buc bl1ang eua tang'tr~t.

E.P

d

Ap d~ng kh6a ket dong hangl de dong IlIu10'g, cae. bue tu'ong

1. Trong Project Browser, du'ai Views (All), Floor Plans, nnap cJup van Main Floor.

2. Nhap vao View menu> View Properties.

E.P ~=

sal:- At:' d(Jng va oha bo khoa ket (constraint) • 243

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8. Chc;m OU! tuang ella tang ehinh.

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L..=.

Cbu y: Sue tuang ella tang ehinh bat di~m hen trai vao dung vi tri ngay phia trelil dra' tI!J~ang tang tn~t.

9. Nhap vao moe khoa dang rna de d6ng kh6a l<;li va khoa ihail but tuang Iluon thang h~mg.

-­

~

II

L..=.

10. Tren Design Bar, nhap VaG M'Odify,

Ap dl}n9 va pha bo khoa ket cho't --"

1. Ch~n bLic tuang ngan co phuong dung ........,I

nam ben pMl but tuang mal lbqn "Ilia dong himg trong cae bucJc vU'a rei. Kich UllfcJc t;lm thai eua t110ng xuat hj~n.

f ........

8'-6" I 'j'-13"

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2. Tren Edit toolbar, nhap vao Pin. MQt ky hi~u pin xuat hi~n tren tuong, va kieh thuoc ti;lm thai bien mat.

3.

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'-...../

II L

Trern Edit toolbar, nhap vim Move. '-'

244 • ChU'dng 7: Kfch thi/ac va kh6a ket (constraint) .~

4. Trang cLta so hJnh chieu, de di chuyen tttong da bj chot:

Nhap vao bat eU' ndi dau de ti;lO I~p diem bat dau.

Re can tro song phai hay trai va nh~l'p

de \:.90 I~p diem cuBi cung, MQt thong baa se xuat hj~n nhu hinh ve,

Can't move pinned element.

pand »~hoYII

~ancel

Nhap vao Cancel.

5. Trc>nQi C:lla so hil"lh c!hieu, de pha bo 'kh6a ket chot:

ChQn ICili but tLtOng.

Nhap vao Iky hi~u pin. Chu, y mQt net 9i;lch cheo mau do xua"t hi~n ngang qua kY hi~u pin, va kfcll tnudc ti;lm thol' t~m tha.i cwa tuong xuat Ihi~n.

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E 8'-6" 15'-6"

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Chu y: Neu can thiet, bay giG b9n c6 the hi~u chinh V! trf, phtJdng, chieu dai, va chieu cao.

6. Dong ~p tin rna khong can lL1u.

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Bai: Ap dunq va oha bd khoa ke1 (constraint) • 2.45

"­

Tom tat Cih'u'Olng

Den day D<;ln d'a IhQc each ghi kich thLfoc va kh6a ket cac v~t bhe tro,ng thiet Ike C'ua minh, b9n co the ling dl,mg nhCi'ng hieu biet nay vab nhl'rng thlE~t ike nhu' v~y.

Trong chudng nay, bc;ln 05 hQC de:

OJ SO' trf kfch thuO'c trong m9t c6ng trinh.

Ap dl:mg va pha be kh6a ket (constraint) trong m9t cong trinh. .......,

"-"

'-./

'-./

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246 ... Chlfong 7: Kfch thlfoC va khoa kef (coiJstraint)

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