ف1د2 ج.م.ع 2

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ف1د2 ج.م.ع 2

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  • . .

    06/03/2014

    : 2 ..

    (6): 1

    = : 3 +1

    22

    13

    2 + 3

    (P(x) . (1 2

    = : c b a 2 (2 + + ) . (1.5)

    (x+3)(.1) (Q(x

    2 : (Q(x + + = + 3 () . (1.5)

    (1). (P(x

    (9.5):2

    = : 22 7 + 3 (2 2)

    : IR (1

    2x 2 = 22 0 7 + 3 = 3 0 + 2 + 2 = (1+1.5+0.5).0

    22 - 7 + (1) .3

    2: - + 1 2 7( + 1) + 3 = (1).0

    (S(x).(1.5 (2

    2x: - (3 2 < 22 0 3 + 1 (( 0 (2).0

    3 : IR (4 70 > (1).40

    : 3

    (4.5): IR

    5 + 4 = 4

    2y +5

    2x 2 = 0

    2 + 3 + 10 = 0

    x =3

    2y +

    5

    2

    4 = 3

    x + 2y = 8

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