. s1 H2O2 50ml C1=56 10-3 mol/L 1ml 3mol/L 50ml S2 (aq) K+(aq)+I- C2=0.2 mol/L

:

123 (aq) I2

n(I2) 2.8 10-3_ Xmax=010-2_ 2Xmax=0Xmax= 2.8 10-3

I -H2o2H+ (mlmol)102.86

10ml (trempage) :

c=0.04mol/L 2Na(aq)+S2O3-2(aq)

tetrathionate

=0=0

n(S2o3-2)_2Xeq=0n(I2)-Xeq=0n(S2o3-2)=2 n(I2)n(S2o3-2)n(I2)=C.Veq /2I2=C.Veq /2V 10mL 2=n(I2)

n(I2)V =n(I2) V I2n(I2)V = 4.49.61315182123252728

XMAX=0.28 mmol

aA +bB Cc +DD

Va a=VD dVC cVB b==

0xmax/2t1/2 t1/2 t=t1/2 .a a 4 7

20 60 1234

0.5mol/L1 1mol/L 234

: X