113902035-biến-tần-siemens-MM440

Ti liu cho ngi lp my

MICROMASTER 440 0,12 kW 250 kW

Hng dn vn hnh Thng 07/05

Cnh bo, Lu v Ch Thng 7/05

2

Cnh bo, lu v ch

Cc cnh bo, lu v ch c a ra m bo an ton cho ngi s dng v trnh h hi cho sn phm hoc cc b phn ca thit b c ni. Cc cnh bo, lu v ch c th p dng cho tng hot ng c lit k phn u ca cc chng lin quan v c nhc li hoc b sung ti cc im quan trng trong cc phn ny. Hy c thng tin cn thn, v n gip bo v an ton cho bn thn ngi s dng v cng s gip ko di tui th ca b bin tn MICROMASTER 440 v cc thit b i km. CNH BO Thit b ny c mc in p nguy him v iu khin cc b phn c kh quay c nguy

him cao. Nu khng tun theo cc cnh bo hoc khng thc hin theo cc hng dn trong ti liu ny th s nh hng n tui th ca my, gy nguy him cho ngi s dng hoc thit hi ln v ti sn.

Ch ngi no c trnh chuyn mn ph hp mi c vn hnh thit b ny, v ch sau khi nm c tt c cc ch an ton, cc quy trnh ci t, vn hnh v bo dng trong ti liu ny. vn hnh c thit b tt v an ton ph thuc vo vic thao tc, lp t, vn hnh v bo dng hp l.

T trn mch lc vn cn in trong vng 5 pht sau khi tt ngun nn khng c php m thit b trong khong thi gian ny. Cc t in t phng in trong khong thi gian ny.

Thit b ny c kh nng bo v qu ti ng c theo UL508C phn 42. Theo thng s P0610 v P0335, i2t c bt theo mc nh. Cng c th bo v qu ti ng c bng PTC hoc KTY84 bn ngoi (khng kch hot theo mc nh bng thng s P0601).

Thit b ny dng ph hp trong mch c dng khng qu 10000 A, in p ln nht 230 V / 460V / 575V khi c bo v bi cc cu ch loi H, J, K, p-t-mt hoc b iu khin ng c c bo v.

Ch dng dy ng Loi 1 60/75 oC c tit din c ghi c th trong ti liu hng dn vn hnh.

Cc u vo chnh, DC v cc u ni ng c c th c in p nguy him ngay c khi bin tn khng hot ng. Lun lun ch 5 pht thit b phng ht in sau khi tt ngun trc khi thc hin bt k ci t no.

CH Hy c cc hng dn an ton, cc cnh bo v tt c cc nhn cnh bo gn trn thit b

cn thn trc khi thc hin lp t v ci t. Hy gi tt c cc nhn cnh bo cn thn c th d dng c c v hy thay cc nhn

b mt hoc b hng. Nhit mi trng xung quanh cho php ln nht l:

- C v A-F: 500C mmen khng i (CT) v dng in ra cho php 100%. 400C mmen thay i (VT) v dng in ra cho php 100%.

- C v FX v GX: 400C vi dng in ra cho php 100%.

Mc lc Thng 7/05

MICROMASTER 440 3 Hng dn vn hnh (Bn rt gn)

Mc lc

1 Lp t c kh........................................................................................................................... 5 1.1 Khong cch lp t ...................................................................................................................5 1.2 Kch thc lp t.......................................................................................................................5 2 Lp t phn in .................................................................................................................... 6 2.1 Cc thng s k thut ..................................................................................................................6 2.2 Cc u ni mch lc .............................................................................................................. 13 2.3 Cc u dy iu khin............................................................................................................ 21 2.4 S nguyn l ....................................................................................................................... 22 3 Ci t mc nh .................................................................................................................... 23 3.1 Kho chuyn i DIP 50/60 HZ ............................................................................................... 23 4 Truyn thng .......................................................................................................................... 24 4.1 Thit lp truyn thng MICROMASTER 440 Phn mm STARTER.................................. 24 4.2 Thit lp truyn thng MICROMASTER 440 AOP.............................................................. 24 4.3 Giao din BUS (CB) ................................................................................................................. 25 5 BOP/AOP (Tu chn) ............................................................................................................. 26 5.1 Cc nt v cc chc nng ....................................................................................................... 26 5.2 Thay i cc thng s .............................................................................................................. 27 6 Ci t thng s ..................................................................................................................... 28 6.1 Ci t thng s nhanh............................................................................................................ 28 6.2 Nhn dng ng c ................................................................................................................. 32 6.3 Dng t ho ............................................................................................................................. 32 6.4 Ci t ng dng ..................................................................................................................... 34 6.4.1 Giao din ni tip ..................................................................................................................... 34 6.4.2 Chn ngun lnh...................................................................................................................... 34 6.4.3 u vo s (DIN) ..................................................................................................................... 35 6.4.4 Cc u ra s (DOUT) ............................................................................................................. 36 6.4.5 Chn gi tr im t tn s ..................................................................................................... 37 6.4.6 u vo tng t (ADC).......................................................................................................... 38 6.4.7 u ra tng t (DAC) ............................................................................................................ 39 6.4.8 Chit p xung (MOP) ............................................................................................................... 40 6.4.9 Tn s c nh (FF).................................................................................................................. 41 6.4.10 Chy nhp................................................................................................................................ 42 6.4.11 B pht hm to dc (RFG)................................................................................................ 43 6.4.12 Cc tn s quy chiu / gii hn ............................................................................................... 44 6.4.13 Bo v b bin tn ................................................................................................................... 45 6.4.14 Bo v nhit ng c ............................................................................................................... 45 6.4.15 Encoder.................................................................................................................................... 47 6.4.16 iu khin V/f ........................................................................................................................... 48 6.4.17 iu khin nh hng trng (FCC)...................................................................................... 50 6.4.17.1 iu khin vect khng sensor (SLVC)................................................................................... 51 6.4.17.2 iu khin vect c encoder (VC)........................................................................................... 53 6.4.18 Cc chc nng c th ca bin tn ......................................................................................... 55 6.4.18.1 Khi ng bm......................................................................................................................... 55 6.4.18.2 T khi ng............................................................................................................................ 55 6.4.18.3 Phanh hm c kh ca ng c............................................................................................... 56 6.4.18.4 Hm mt chiu (DC) ................................................................................................................ 58

Thng 7/05 Mc lc

MICROMASTER 440 Hng dn vn hnh (Bn rt gn)

4

6.4.18.5 Hm hn hp ........................................................................................................................... 59 6.4.18.6 Hm ng nng........................................................................................................................ 60 6.4.18.7 B iu khin Vdc .................................................................................................................... 60 6.4.18.8 B iu khin PID .................................................................................................................... 61 6.4.18.9 Cc khi chc nng t do (FFB) ............................................................................................. 62 6.4.19 Tp d liu lnh v truyn ng .............................................................................................. 63 6.4.20 Thng s chn on ................................................................................................................ 66 6.5 Ci t ni tip ......................................................................................................................... 67 6.6 Ci t li cc thng s mc nh ............................................................................................ 67 7 Cc ch hin th v cnh bo .......................................................................................... 68 7.1 Hin th trng thi LED............................................................................................................. 68 7.2 Cc thng bo li v cnh bo ................................................................................................ 69

8 Danh mc Thut ng vit tt ................................................................................................ 70

1 Lp t c kh Thng 7/05


5

1 Lp t c kh 1.1 Khong cch lp t Cc b bin tn c th c lp st nhau. Trong t iu khin, khi lp cc b bin tn thnh cc hng theo chiu thng ng, cc iu kin mi trng khng c vt qu gii hn cho php. Ngoi ra cng cn phi lu cc khong cch ti thiu thng gi: C v A, B, C khong cch pha trn v pha di ti thiu:100mm C v D khong cch pha trn v pha di ti thiu:300mm C v F khong cch pha trn v pha di ti thiu:350mm C v FX, GX khong cch ti thiu pha trn: 250mm

pha di: 150mm pha trc:40mm (FX), 50mm (GX)

1.2 Kch thc lp t

Kch thc l khoan Mmen xit H W Bulng Nm

C v mm (Inch) mm (Inch) (ibf.in) A 160 (6.30) - 2xM4 B 174 (6.85) 138 (5.43) 4xM4 C 204 (8.03) 174 (6.85) 4xM5

2,5 (22.12)

D 486 (19.13) 235 (9.25) 4xM8 E 616,4 (24.27) 235 (9.25) 4xM8 F 810 (31.89) 300 (11.81) 4xM8

3,0 (26.54)

FX 1375,5 (54.14) 250 (9.84) 6xM8

13,0 (115,02)

GX 1508,5 (59.38) 250 (9.84) 6xM8

13,0 (115,02)

Hnh 1-1 Cc kch thc lp t

Thng 7/05 2 Lp t phn in


6

2 Lp t phn in 2.1 Cc thng s k thut Di in p u vo 1 AC 200 V- 240 V, 10% (Khng c b lc v c km b lc cp A)

2AB 11 12 13 15 17 21 21 22 23 M hiu t hng 6SE6440- 2UC 2AA1 5AA1 7AA1 5AA1 5AA1 1BA1 5BA1 2BA1 0CA1C v A B C Cng sut nh mc CT [kW] 0,12 0,25 0,37 0,55 0,75 1,1 1,5 2,2 3,0 Cng sut u ra [kVA] 0,4 0,7 1,0 1,3 1,7 2,4 3,2 4,6 6,0 Dng in vo CT -1 [A] 4,6 6,2 8,2 11,0 14,4 20,2 35,5 Dng in ra CT [A] 0,9 1,7 2,3 3,0 3,9 5,5 7,4 10,4 13,6 Cu ch [A] Khuyn co loi 3NA 3803 3803 3803 3805 3805 3807 3807 3812 3817Theo chun UL * * * * * * * * * Tit din cp u vo min 16 16 14 14 12 10 Tit din cp u vo max [mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 Tit din cp u ra min [mm2] 1,0 1,0 1,0 1,0 1,0 1,0 1,0 1,0 1,5 Tit din cp u ra max [mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 Trng lng (khi km b lc cp A)

[kg] 1,3 1,3 1,3 1,3 1,3 3,4 3,4 3,4 5,7

Trng lng (khi khng c b lc)

[kg] 1,3 1,3 1,3 1,3 1,3 3,3 3,3 3,3 5,5

Mmen xit cho cc u mch lc

[Nm] 1,1 1,5 2,25

1) Cc iu kin th cp: Dng in ti im hot ng nh mc p dng cho ngun c in p ngn

mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 240V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 55% n 70%.

2 Lp t phn in Thng 7/05


7

Di in p u vo 3 AC 200 V- 240 V, 10% (c km b lc cp A)

M hiu t hng 6SE6440- 2AC23-0CA1 2AC24-0CA1

2AC25-5CA1

C v C Cng sut nh mc CT [kW] 3,0 4,0 5,5 Cng sut u ra [kVA] 6,0 7,7 9,6 Dng in vo CT- 1 [A] 15,6 19,7 26,5 Dng in ra CT [A] 13,6 17,5 22,0 Dng in vo VT -1 [A] - 28,3 34,2 Dng in ra VT [A] - 22,0 28,0 Cu ch [A] 25 32 35 Khuyn co loi 3NA 3810 3812 3814 Theo chun UL * * * Tit din cp u vo min [mm2] 2,5 4,0 4,0 Tit din cp u vo max [mm2] 10,0 10,0 10,0 Tit din cp u ra min [mm2] 1,5 4,0 4,0 Tit din cp u ra max [mm2] 10,0 10,0 10,0 Trng lng [kg] 5,7 5,7 5,7 M men xit cho cc u mch lc [Nm] 2,25





8

Di in p u vo 3 AC 200 V - 240 V, 10% (Khng c b lc )

2UC11 2UC12 2UC13 2UC15 2UC17 2UC21 2UC21 2UC22 2UC23M hiu t hng 6SE6440- -2AA1 -5AA1 -7AA1 -5AA1 -5AA1 -1BA1 -5BA1 -2BA1 -0CA1

C v A B C Cng sut nh mc CT [kW] 0,12 0,25 0,37 0,55 0,75 1,1 1,5 2,2 3,0 Cng sut u ra [kVA] 0,4 0,7 1,0 1,3 1,7 2,4 3,2 4,6 6,0 Dng in vo CT- 1 [A] 1,1 1,9 2,7 3,6 4,7 6,4 8,3 11,7 15,6 Dng in ra CT [A] 0,9 1,7 2,3 3,0 3,9 5,5 7,4 10,4 13,6 Cu ch [A] 10 10 10 16 16 20 20 25 25 Khuyn co loi 3NA 3803 3803 3803 3805 3805 3807 3807 3810 3810Theo chun UL * * * * * * * * *

Tit din cp u vo min [mm2] 1,0 1,0 1,0 1,5 1,5 2,5 2,5 2,5 4,0

Tit din cp u vo max [mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 Tit din cp u ra min [mm2] 1,0 1,0 1,0 1,0 1,0 1,0 1,0 1,0 1,5 Tit din cp u ra max [mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 Trng lng [kg] 1,3 1,3 1,3 1,3 1,3 3,3 3,3 3,3 5,5 Mmen xit cho cc u mch lc

[Nm] 1,1 1,5 2,25

2UC24 2UC25 2UC27 2UC31 2UC31 2UC31 2UC32 2UC33 2UC33 2UC34M hiu t hng 6SE6440 -0CA1 -5CA1 -5DA1 -1DA1 -5DA1 -8EA1 -2EA1 -0FA1 -7FA1 -5FA1

C v C D E F Cng sut nh mc CT [kW] 4,0 5,5 7,5 11,0 15,0 18,5 22,0 30,0 37,0 45,0 Cng sut u ra [kVA] 7,7 9,6 12,3 18,4 23,7 29,8 35,1 45,6 57,0 67,5 Dng in vo CT-1 [A] 19,7 26,5 34,2 38,0 50,0 62,0 71,0 96,0 114,0 135,0 Dng in ra CT [A] 17,5 22,0 28,0 42,0 54,0 68,0 80,0 104,0 130,0 154,0Dng in vo VT- 1 [A] 28,3 34,2 38,0 50,0 62,0 71,0 96,0 114,0 135,0 164,0Dng in ra VT- 1 [A] 22,0 28,0 42,0 54,0 68,0 80,0 104,0 130,0 154,0 - Cu ch [A] 32 35 50 80 80 100 125 200 200 250Khuyn co loi 3NA 3812 3814 3820 3824 3824 3830 3032 3140 3142 3144Theo chun UL SNP * * 1817 -0

1820 -0

1820 -0

1021 -0

1022 -0

1225 -0

1225 -0

1227-0

Tit din cp u vo min 4,0 4,0 10,0 16,0 16,0 25,0 25,0 70,0 70,0 95,0Tit din cp u vo max [mm2] 10,0 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0Tit din cp u ra min [mm2] 4,0 4,0 10,0 16,0 16,0 25,0 25,0 50,0 70,0 95,0Tit dn cp u ra max [mm2] 10,0 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0Trng lng [kg] 5,5 5,5 17,0 16,0 16,0 20,0 20,0 55,0 55,0 55,0Mmen xit cho cc u mch lc

[Nm] 2,25 10 50





9

Di in p u vo 3 AC 380 V- 480 V, 10% (c km b lc cp A)

M hiu t hng 6SE6440- 2AD22-2BA1 2AD23-0BA1

2AD24-0BA1

2AD25-5CA1

2AD27-5CA1

2AD31-1CA1

2AD31-5DA1

C v B C D Cng sut nh mc CT [kW] 2,2 3,0 4,0 5,5 7,5 11,0 15,0 Cng sut u ra [kVA] 4,5 5,9 7,8 10,1 14,0 19,8 24,4 Dng in vo CT- 1 [A] 7,5 10,0 12,8 15,6 22,0 23,1 33,8 Dng in ra CT [A] 5,9 7,7 10,2 13,2 18,4 26,0 32,0 Dng in vo VT- 1 [A] - - - 17,3 23,1 33,8 37,0 Dng in ra VT- 1 [A] - - - 20,2 29,0 39,0 45,2 Cu ch [A] 16 16 20 20 32 35 50 Khuyn co loi 3NA 3805 3805 3807 3807 3812 3814 3820 Theo chun UL 3NE * * * * * * 1817-0Tit din cp u vo min 1,5 1,5 2,5 2,5 4,0 6,0 10,0 Tit din cp u vo max [mm2] 6,0 6,0 6,0 10,0 10,0 10,0 35,0 Tit din cp u ra min [mm2] 1,0 1,0 1,0 2,5 4,0 6,0 10,0 Tit din cp u ra max [mm2] 6,0 6,0 6,0 10,0 10,0 10,0 35,0 Trng lng [kg] 3,4 3,4 3,4 5,7 5,7 5,7 17,0 Mmen xit cho cc u mch lc [Nm] 1,1 1,5 2,25

M hiu t hng 6SE6440- 2AD31-8DA1 2AD32-2DA1

2AD33-0EA1

2AD33-7EA1

2AD34-5FA1

2AD35-5FA1

2AD37-5FA1

C v D E F Cng sut nh mc CT [kW] 18,5 22,0 30,0 37,0 45,0 55,0 75,0 Cng sut u ra [kVA] 29,0 34,3 47,3 57,2 68,6 83,8 110,5 Dng in vo CT- 1 [A] 37,0 43,0 59,0 72,0 87,0 104,0 139,0 Dng in ra CT [A] 38,0 45,0 62,0 75,0 90,0 110,0 145,0Dng in vo VT- 1 [A] 43,0 59,0 72,0 87,0 104,0 139,0 169,0Dng in ra VT- 1 [A] 45,0 62,0 75,0 90,0 110,0 145,0 178,0Cu ch [A] 63 80 100 125 160 200 250 Khuyn co loi 3NA 3822 3824 3830 3832 3836 3140 3144 Theo chun UL 3NE 1818-0 1820-0 1021-0 1022-0 1224-0 1225-0 1227-0Tit din u vo min [mm2] 10,0 16,0 25,0 25,0 35,0 70,0 95,0 Tit din cp u vo max [mm2] 35,0 35,0 35,0 35,0 150,0 150,0 150,0Tit din cp u ra min [mm2] 10,0 16,0 25,0 25,0 50,0 70,0 95,0 Tit din cp u ra max [mm2] 35,0 35,0 35,0 35,0 150,0 150,0 150,0Trng lng [kg] 17,0 17,0 22,0 22,0 75,0 75,0 75,0 Mmen xit cho cc u mch lc [Nm] 10 50





10

Di in p u vo 3 AC 380 V- 480 V, 10% (khng km b lc) M hiu t hng 6SE6440- 2UD31-1CA1

2UD31-5DA1

2UD31-8DA1

2UD32-2DA1

2UD33-0EA1

2UD33-7EA1

2UD34-5FA1

2UD35-5FA1

2UD37-5FA1

C v C D E F Cng sut ra nh mc CT [kW] 11,0 15,0 18,5 22,0 30,0 37,0 45,0 55,0 75,0 Cng sut ra nh mc [kVA] 19,8 24,4 29,0 34,3 47,3 57,2 68,6 83,8 110,5Dng in vo CT 1) [A] 23,1 33,8 37,0 43,0 59,0 72,0 87,0 104,0 139,0Dng in ra CT [A] 26,0 32,0 38,0 45,0 62,0 75,0 90,0 110,0 145,0Dng in vo VT 1) [A] 33,8 37,0 43,0 59,0 72,0 87,0 104,0 139,0 169,0Dng in ra VT [A] 32,0 38,0 45,0 62,0 75,0 90,0 110,0 145,0 178,0Cu ch [A] 35 50 63 80 100 125 160 200 250 Khuyn co loi [3NA] 3814 3820 3822 3824 3830 3832 8036 3140 3144Theo chun UL [3NE] * 1817-0 1818-0 1820-0 1321-0 1022-0 1224-0 1225-0 1227-0Tit din cp u vo min [mm2] 6,0 10,0 10,0 16,0 25,0 25,0 35,0 70,0 95,0 Tit din cp u vo max [mm2] 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0Tit din cp u ra min [mm2] 6,0 10,0 10,0 16,0 25,0 25,0 35,0 70,0 95,0 Tit din cp u ra max [mm2] 10,0 35,0 35,0 35,0 35,0 35,0 150,0 150,0 150,0Trng lng [kg] 5,5 16,0 16,0 16,0 20,0 20,0 56,0 56,0 56,0 M men xit cho cc u mch lc

[Nm] 2,25 10 50

1) Cc iu kin th cp:Dng in ti im hot ng nh mc p dng cho ngun c in p ngn


M hiu t hng 6SE6440- 2UD13-7AA1

2UD15-5AA1

2UD17-5AA1

2UD21-1AA1

2UD21-5AA1

2UD22-2BA1

2UD23 -0BA1

2UD24 -0BA1

2UD25-5CA1

2UD27-5CA1

C v A B C Cng sut ra nh mc CT [kW] 0,37 0,55 0,75 1,1 1,5 2,2 3,0 4,0 5,5 7,5

Cng sut ra nh mc [kVA] 0,9 1,2 1,6 2,3 3,0 4,5 5,9 7,8 10,1 14,0Dng in vo CT- 1 [A] 2,2 2,8 3,7 4,9 5,9 7,5 10,0 12,8 15,6 22,0Dng in ra CT [A] 1,3 1,7 2,2 3,1 4,1 5,9 7,7 10,2 13,2 19,0Dng in vo VT 1) [A] - - - - - - - - 17,3 23,1Dng in ra VT [A] - - - - - - - - 19,0 26,0Cu ch [A] 10 10 10 10 10 16 16 20 20 32 Khuyn co loi [3NA] 3803 3803 3803 3803 3803 3805 3805 3807 3807 3812Theo chun UL [3NE] * * * * * * * * * * Tit din cp u vo min

[mm2] 1,0 1,0 1,0 1,0 1,0 1,5 1,5 2,5 2,5 4,0

Tit din cp u vo max

[mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 10,0

Tit din cp u ra min [mm2] 1,0 1,0 1,0 1,0 1,0 1,0 1,0 1,0 2,5 4,0 Tit din cp u ra max [mm2] 2,5 2,5 2,5 2,5 2,5 6,0 6,0 6,0 10,0 10,0Trng lng [kg] 1,3 1,3 1,3 1,3 1,3 3,3 3,3 3,3 5,5 5,5 M men xit cho cc u mch lc [Nm] 1,1 1,5 2,25



11

Di in p u vo 3 AC 380 V- 480 V, 10% (khng km b lc) M hiu t hng 6SE6440- 2UD38

-8FA1 2UD41 -1FA1

2UD41-3GA1

2UD41-6GA1

2UD42- 0GA1

C v FX GX Cng sut ra nh mc ( CT) [kW] 90 110 132 160 200 Cng sut ra nh mc [kVA] 145,4 180 214,8 263,2 339,4 Dng in vo CT 1) [A] 169 200 245 297 354 Dng in ra CT [A] 178 205 250 302 370 Dng in vo VT 1) [A] 200 245 297 354 442 Dng in ra VT [A] 205 250 302 370 477 Cu ch [A] 250 315 400 450 560 Khuyn co loi [3NA] 1227-0 1230-0 1332-0 1333-0 1435-0 Hp cp theo chun DIN 46235 [mm] 10 10 10 10 10 Tit din cp u vo min [mm2] 1x95 hoc

2x35 1x150 hoc

2x50 1x185 hoc

2x70 1x240 hoc

2x70 2x95

Tit din cp u vo max [mm2] 1x185 hoc 2x120

1x185 hoc 2x120 2x240 2x240 2x240

Tit din cp u ra min [mm2] 1x95 hoc 2x35

1x150 hoc 2x50

1x185 hoc 2x70

1x240 hoc 2x70 2x95

Tit din cp u ra max [mm2] 1x185 hoc 2x120

1x185 hoc 2x120 2x240 2x240 2x240

Trng lng [kg] 110 110 170 170 170 M men xit cho cc u mch lc [Nm] 25


mch Vk 2,33 % l dng in tng ng vi cng sut nh mc ca b bin tn v in p li 400V trong trng hp khng c cun khng chuyn mch.



12

Di in p u vo 3 AC 500 V- 600 V, 10% (khng km b lc) M hiu t hng 6SE6440- 2UE17-

5CA12UE21-5CA1

2UE22-2CA1

2UE24-0CA1

2UE25-5CA1

2UE27-5CA1

2UE31-1CA1

2UE31-5DA1

C v C D Cng sut ra nh mc ( CT) [kW] 0,75 1,5 2,2 4,0 5,5 7,5 11,0 15,0

Cng sut ra nh mc [kVA] 1,3 2,6 3,7 5,8 8,6 10,5 16,2 21,0 Dng in vo CT 1) [A] 2,0 3,7 5,3 8,1 11,1 14,4 21,5 24,9 Dng in ra CT [A] 1,4 2,7 3,9 6,1 9,0 11,0 17,0 22,0 Dng in vo VT 1) [A] 3,2 4,4 6,9 9,4 12,6 18,1 24,9 30,0 Dng in ra VT [A] 2,7 3,9 6,1 9,0 11,0 17,0 22,0 27,0 Cu ch [A] 10 10 10 16 16 25 32 35 Khuyn co loi [3NA] 3803-6 3803-6 3803-6 3805-6 3805-6 3810-6 3812-6 3814-6

Theo chun UL [3NE] * * * * * * * 1803-0Tit din cp u vo min [mm2] 1,0 1,0 1,0 1,5 1,5 2,5 4,0 6,0 Tit din cp u vo max [mm2] 10,0 10,0 10,0 10,0 10,0 10,0 10,0 35,0 Tit din cp u ra min [mm2] 1,0 1,0 1,0 1,0 1,0 2,5 4,0 4,0 Tit din cp u ra max [mm2] 10,0 10,0 10,0 10,0 10,0 10,0 10,0 35,0 Trng lng [kg] 5,5 5,5 5,5 5,5 5,5 5,5 5,5 16,0 M men xit cho cc u mchlc

[Nm] 2,25 10

M hiu t hng 6SE6440- 2UE31-

8DA1 2UE32-2DA1

2UE33-0EA1

2UE33-7EA1

2UE34-5FA1

2UE35-5FA1

2UE37-5FA1

C v D E F Cng sut ra nh mc CT [kW] 18,5 22,0 30,0 37,0 45,0 55,0 75,0

Cng sut ra nh mc [kVA] 25,7 30,5 39,1 49,5 59,1 73,4 94,3 Dng in vo CT- 1 [A] 30 35,0 48,0 58,0 69,0 83,0 113,0 Dng in ra CT [A] 27,0 32,0 41,0 52,0 62,0 77,0 99,0 Dng in vo VT- 1 [A] 35,0 48 58,0 69,0 83,0 113,0 138,0 Dng in ra VT [A] 32,0 41,0 52,0 62,0 77,0 99,0 125,0 Cu ch [A] 50 63 80 80 125 160 160 Khuyn co loi [3NA] 3820-6 3822-6 3824-6 3824-6 3132-6 3136-6 3136-6Theo chun UL [3NE] 1817-0 1818-0 1820-0 1820-0 1022-0 1024-0 1224-0Tit din cp u vo min [mm2] 10,0 10,0 16,0 25,0 25,0 50,0 50,0 Tit din cp u vo max [mm2] 35,0 35,0 35,0 35,0 150,0 150,0 150,0 Tit din cp u ra min [mm2] 6,0 10,0 16,0 16,0 25,0 35,0 50,0 Tit din cp u ra max [mm2] 35,0 35,0 35,0 35,0 150,0 150,0 150,0 Trng lng [kg] 16,0 16,0 20,0 20,0 56,0 56,0 56,0 M men xit cho cc u mchlc

[Nm] 10 50


mch Vk = 2% l dng in tng ng vi cng sut nh mc ca b bin tn trong h truyn ng v in p li 500V trong trng hp khng c cun khng chuyn mch. Nu dng cun khng chuyn mch, cc gi tr c th trong bng gim i trong khong t 80% n 90%.



13

2.2 Cc u ni mch lc C th tip cn vi cc u ni ngun in vo v cc u ni ca ng c bng cch tho cc phn v my pha trc.

C v A ( Hnh 2-1) C v B v C ( Hnh 2-2) C v D v E ( Hnh 2-3) C v F ( Hnh 2-4) C v FX v GX ( Hnh 2-5) Cc u ni ca c v A F ( Hnh 2-6) Tng quan v cch ni i vi c v FX (Hnh 2-7) Tng quan v cch ni i vi c v GX (Hnh 2-8)

C v A

Hnh 2-1 Tho phn mt trc v my (C v A)



14

C v B v C

Hnh 2-2 Tho v phn trc v my (C v B v C)



15

C c D v E

Hnh 2-3 Tho phn trc v my ( C v D v E)



16

C v F

Hnh 2-4 Tho phn trc v my (C v F)



17

C v FX v GX

Hnh 2-5 Tho phn trc v my (C v FX v GX)



18

C th tip xc vi cc u ni ngun vo v cc u ni ng c bng cch tho cc phn v my pha trc.

C v A C v B v C

C v D v E

C v F Hnh 2-6 Cc u ni cho cc c v t A F.



19

Hnh 2-7 Hnh v tm lc cc u ni b bin tn c v FX

Cc l treo

u ni mt cp u vo ngun lc PE

Cc l cho cc cp mch lc U1/L1, V1/L2, W1/L3 i qua

Cc l cho cp DCPA, DCNA ni vi b hm ngoi i qua

Cc u cp mch lc pha U1/L1, V1/L2, W1/L3

u ni tu Y

Cc u ni cp DCPA, DCNA vi b hm ngoi

Thanh ray iu chnh pha trn

Bng hin th trng thi

Hp cha mch iu khin

Thanh ray iu chnh pha di

ai c hm pha di

Cc ai c qut

Qut

Tip a cc u dy iu khin

Cc cu ch qut

Bin p qut Cp pha ng c U2, V2, W2

u ni mt cp ng c PE

Cc u ni vi b lc dv/dt DCPS, DCNS

ai c hm pha trn



20

Hnh 2- 8 : Hnh v tm lc cc u ni b bin tn c v GX

Cc l treo

u ni mt cp u vo ngun lc PE

Cc l cho cc cp mch lc U1/L1, V1/L2, W1/L3 i qua

Cc l cho cp DCPA, DCNA ni vi b hm ngoi i qua

Cc u cp mch lc pha U1/L1, V1/L2, W1/L3

u ni t Y

Cc u ni cp DCPA, DCNA vi b hm ngoi

Thanh ray iu chnh pha trn ai c hm pha trn

Cc u ni vi b lc dv/dt DCPS, DCNS

Bng hin th trng thi

Hp cha mch iu khin

Thanh ray iu chnh pha di ai c hm pha di

Cc ai c qut

Qut

Tip a cc u dy iu khin

Cc cu ch qut

Bin p qut Cp pha ng c U2, V2, W2

u ni mt cp ng c PE



21

2.3 Cc u dy iu khin u dy K hiu Chc nng 1 - u ngun ra +10V 2 - u ngun ra 0V 3 ADC1+ u vo tng t s1(+) 4 ADC1- u vo tng t s 1(-) 5 DIN1 u vo s s 1 6 DIN2 u vo s s 2 7 DIN3 u vo s s 3 8 DIN4 u vo s s 4 9 - u ra cch ly +24V/max. 100 mA 10 ADC2+ u vo tng t s 2 (+) 11 ADC2- u vo tng t s 2 (-) 12 DAC1+ u ra tng t s 1 (+) 13 DAC1- u ra tng t s 1 (-) 14 PTCA u dy ni cho PTC / KTY 84 15 PTCB u dy ni cho PTC / KTY 84 16 DIN5 u vo s s 5 17 DIN6 u vo s s 6 18 DOUT1/NC u ra s s 1/ tip im NC 19 DOUT1/NO u ra s s 1/ tip im NO 20 DOUT1/COM u ra s s 1/ chn chung 21 DOUT2/NO u ra s s 2/ tip im NO 22 DOUT2/COM u ra s s 2/ chn chung 23 DOUT3/NC u ra s s 3/ tip im NC 24 DOUT3/NO u ra s s 3/ tip im NO 25 DOUT3/COM u ra s s 3/ chn chung 26 DAC2+ u ra tng t s 2 (+) 27 DAC2- u ra tng t s 2 (-) 28 - u ra cch ly 0 V/max. 100 mA 29 P+ Cng RS485 30 N- Cng RS485

Hnh 2-9 Cc u dy iu khin ca MICROMASTER 440



22

2.4 S nguyn l

Hnh 2-10 S nguyn l

Ni ti khi phanh in tr ngoi

Cc

h ly

qua

ng

u ra +24V max.100mA (cch ly)u ra 0V max. 100mA (cch ly)

30 V DC/ 5A (ti thun tr) 250 V AC/ 2 A

(ti cm)

Bo v nhit ng

c

C v t A n F

C v FX v GX

Ni ti b lc dv/dt

B

Dng in 0-20 mA in p 0-10 V

Kho chuyn tn s DIP (trn bng I/O)

Kha DIP (trn bng iu

khin)

t ng

Ngun ngoi 24V

hoc

3 Ci t mc nh Thng 7/05


23

3 Ci t mc nh

B bin tn MCROMASTER 440 c ci t mc nh khi xut xng sao cho c th vn hnh c m khng cn ci t thm bt k thng s no na. t c iu ny, cc thng s ca ng c c kt ni vi bin tn phi c thng s nh mc ph hp vi thng s ci t mc nh (P0304, P0305, P0307, P0310) tng ng vi ng c 1LA7 4 cc ca Siemens (hy xem cc thng s nh mc ghi trn nhn). Cc thng s mc nh khc: Cc ngun lnh P0700 = 2 (u vo s, xem hnh 3-1) Ngun im t P1000 = 2 (u vo tng t, xem hnh 3-1) Ch lm mt ng c

P0335 = 0 Gii hn dng in

P0640 = 150% Tn s nh nht

P1080 = 0 Hz Tn s ln nht

P1082 = 50 Hz Thi gian tng tc

P1120 = 10 s Thi gian gim tc

P1121 = 10 s Ch iu khin

P1300 = 0

u vo/ u ra Cc u ni Thng s Chc nng u vo s 1 5 P0701 = 1 ON/OFF1 (I/O)

u vo s 2 6 P0702 = 12 o chiu u vo s 3 7 P0703 = 9 Xa li u vo s 4 8 P0704 = 15 im t c nh (trc tip) u vo s 5 16 P0705 = 15 im t c nh (trc tip) u vo s 6 17 P0706 = 15 im t c nh (trc tip)

u vo s 7 thng qua u tng t s 1

P0707 = 0 Khng s dng

u vo s 8 thng qua u tng t s 2

P0708 = 0 Khng s dng

3.1 Kho chuyn i DIP 50/60 HZ

Tn s nh mc mc nh cho ng c ca b bin tn MICROMASTER l 50 Hz. i vi ng c c thit k chy tn s nh mc 60Hz, cc b bin tn c th c t tn s ny nh s dng kho chuyn DIP 50/60 Hz. V tr OFF: cc thng s mc nh ca

Chu u (tn s nh mc ca ng c = 50 Hz, cng sut tnh theo kW)

V tr ON: Cc thng s mc nh ca Bc M (tn s nh mc ca ng c = 60 Hz, cng sut tnh theo hp.).

Hnh 3-1 Cc u vo gn mc nh

u ra tng t

Thng 7/05 4 Truyn thng


24

4 Truyn thng 4.1 Thit lp truyn thng MICROMASTER 440 Phn mm STARTER

thit lp cc truyn thng gia phn mm STARTER v MICROMASTER 440, cn c thm cc b phn tu chn di y: B kt ni gia b bin tn vi PC BOP nu nh cc gi tr chun USS ca b bin tn MICROMASTER 440 thay i (xem phn

6.4.1 Giao din ni tip (USS)). B kt ni gia bin tn v PC MICROMASTER 440

Cc ch ci t USS, xem phn 6.4.1 Giao din ni tip (USS)

Phn mm STARTER

Vo Menu, chn Option chn Ci t Giao din PG/PC Chn Cng PC COM (USS) Vo Properties chn giao din COM1, chn tc baud (n v tc truyn d liu)

CH : Cc thng s ci t USS trong b bin tn MICROMASTER 440 phi ph hp vi ch ci t ca phn mm STARTER.

4.2 Thit lp truyn thng MICROMASTER 440 AOP Truyn thng gia AOP v MM440 da trn giao thc USS, tng t nh STARTER v

MM440. Khc vi BOP, cc thng s truyn thng thch hp phi c ci t cho c MM440 v

AOP nu nh qu trnh t ng d tm giao din khng thc hin c (xem bng 4-1). S dng cc thnh phn tu chn, AOP c th c kt ni vi cc giao din truyn thng

khc nhau (xem bng 4-1). Bng 4-1 AOP ti ng truyn BOP AOP ti ng truyn COM

Cc thng s MM440 - tc baud - a ch bus

P2010[1] -

P2010[0] P2011

Cc thng s AOP - tc baud - a ch bus

P8553 -

P8553 P8552

Tu chn - kt ni trc tip - kt ni gin tip

Khng cn thit c tu chn Ph kin gn cnh t BOP/AOP (6SE6400-0PM00-0AA0)

Khng th Ph kin gn cnh t BOP/AOP (6SE6400-0MD00-0AA0)

4 Truyn thng Thng 7/05


25

Khi AOP hot ng nh mt b iu khin

Thng s/ u dy AOP trn ng truyn BOP AOP trn ng truyn COM Ngun lnh

P0700 4 5

P1000 1 P1035 2032.13 (2032.D) 2036.13 (2036.D) P1036 2032.14 (2032.E) 2036.14 (2036E)

im t tn s (MOP)

Tng tn s t MOP

Gim tn s t MOP Xa li

P2104 2032.7 2036.7

Li c th c gii tr thng qua AOP m khng ph thuc vo P0700 hoc P1000

4.3 Giao din BUS (CB) * Cn quan st kho chuyn mch DIP dng xc nh phn cng M un DeviceNet M un CANopen M un PROFIBUS

P2041[0] Chiu di PZD Gi tr trng thi/ thc Kiu truyn d liu t T_PD0_1, T_PD0_5

P2041[1] Chiu di PZD iu khin/ im t

Kiu truyn d liu T_PD0_6 R_PD0_1 R_PD0_5 R_PD0_6

P2041[2] Tc 0:125 kbaud

1:250 kbaud 2:500 kbaud

Xc nh ng truyn CANopen MM4

P2041[3] Chn on Xc nh ng truyn CANopen MM4

P2041[4] - - pht hin cc li truyn thng - tc baud

-Khng cn ci t (tr cc trng hp c bit). Hy xem cc hng dn vn hnh m un tu chn PROFIBUS

Giao din BUS (CB)

M un DeviceNet M un CANopen M un PROFIBUS

P0918 P0918 P0918*)

Tc baud c b bin tn xc nh t ng

P2040 P2040 P2040

P2041 P2041 P2041

P2051 P2051 P2051

Thng 7/05 5 BOP/AOP (Tu chn)


26

5 BOP/AOP (Tu chn) 5.1 Cc nt v cc chc nng

Bng iu khin/ Nt Chc nng ngha

Hin th

trng thi Mn hnh LCD hin th cc ch ci t hin hnh ca b bin tn.

Khi ng b bin tn

n nt ny lm cho b bin tn khi ng. Nt ny khng tc dng mc nh Kch hot nt: BOP: P0700 = 1 hoc P0719 = 1016 AOP: P0700 = 4 hoc P0719 = 4046 trn ng truyn BOP P0700 = 5 hoc P0719 = 5056 trn ng truyn COM

Dng b bin tn

OFF1 n nt ny khin ng c dng theo c tnh gim tc c chn. Kch hot nt: hy xem nt Khi ng b bin tn. OFF2 n nt ny hai ln (hoc n mt ln v gi mt khong thi gian)

khin ng c dng t do. BOP: Nt ny lun lun c tc dng (khng ph thuc vo thng s P0700 hoc P0719)

o chiu n nt ny lm ng c o chiu quay. o chiu c hin th bng du (-) hoc im chm nhy. Nt ny khng tc dng mc nh Kch hot nt: hy xem nt Khi ng b bin tn.

Chy nhp ng c

trng thi sn sng chy, khi n nt ny, ng c khi ng v quay vi tn s chy nhp c ci t trc. ng c dng khi th nt ny ra. n nt khi ng c ang lm vic khng c tc ng g.

Nt chc

nng

Nt ny c th dng xem thm thng tin Khi ta n v gi khong 2 giy nt ny hin th cc thng tin sau, bt u t bt k thng s no trong qu trnh vn hnh: 1. in p mt chiu trn mch DC (hin th bng d- n v V). 2. Dng in ra (A). 3. Tn s ra (Hz). 4. in p ra (hin th bng o- n v V). 5. Gi tr c chn trong thng s P0005 (Nu nh P0005 c ci t hin th bt k gi tr no trong s cc gi tr t1-4 th gi tr ny khng c hin th li). n thm s lm quay vng cc gi tr trn bng hin th. n gi trong khong 2 giy quay v ch hin th thng thng. Chc nng nhy T bt k thng s no (v d rxxxx hoc Pxxxx), n nhanh nt Fn s ngay lp tc nhy n r0000, sau ngi s dng c th thay i thng s khc, nu cn thit. Nh tnh nng quay tr v r0000, n nt Fn s cho php ngi s dng quay tr v im ban u. Gii tr Nu xut hin cc cnh bo v cc thng bo li, th cc thng tin ny c th c gii tr bng cch n nt Fn.

Truy nhp thng s n nt ny cho php ngi s dng truy nhp ti cc thng s.

Tng gi tr n nt ny lm tng gi tr c hin th.

Gim gi tr n nt ny lm gim gi tr c hin th.

Trnh n

AOP Gi trnh n AOP ngay lp tc (chc nng ny ch c AOP).

5 BOP/AOP (Tu chn) Thng 7/05


27

5.2 Thay i cc thng s V d thng s P0004- b lc thng s Bc Kt qu hin th

1 n truy nhp thng s

2 n n khi P0004 c hin th

3 n ti cc mc gi tr thng s

4 n hoc t gi tr mong mun

5 n xc nhn gi tr v lu li gi tr

6 Ngi s dng ch c th nhn thy cc thng s v lnh (bt u bng 7)

Thng 7/05 6 Ci t thng s


28

6 Ci t thng s 6.1 Ci t thng s nhanh

B bin tn tng thch vi ng c nh s dng chc nng ci t thng s nhanh, v cc thng s k thut quan trng s c ci t. Ci t nhanh khng cn c thc hin nu thng s nh mc ca ng c ghi trong b bin tn FU (v d ng c tiu chun 1LA 4 cc ca Siemens) thch hp vi thng s nh mc ghi trn nhn ca ng c ang ni vo bin tn.

Cc thng s c k hiu * c kh nng ci t nhiu hn cc kh nng c lit k di y. Hy xem danh sch thng s bit thm cc kh nng ci t khc.

Gi tr mc nh P0003 =3 Mc truy nhp ca ngi dng* 1

1 Mc c bn: Cho php truy nhp ti nhng thng s thng dng nht 2 M rng: V d truy nhp n cc cc chc nng I/O

3 Chuyn gia (ch dnh cho chuyn gia) P0004 = 0 Lc thng s * 0 0 Tt c cc thng s

2 Bin tn 3 ng c 4 Cm bin tc

P0010 = 1 0

Ci t thng s * 0 Sn sng 1 Ci t nhanh

30 Ci t ti nh my Ch P0010 nn c 1 ci t thng s nh mc trn nhn ca ng c Tiu chun Chu u/ Bc M 0

0 Chu u [KW], tn s mc nh 50Hz 1 Bc M [hp], tn s mc nh 60Hz 2 Bc M [kW], tn s mc nh 60Hz

Ch i vi P0100 = 0 hoc 1, gi tr P0100 c xc nh khi ci t kho

chuyn DIP 50/60

OFF = kW, 50 Hz ON = hp, 60Hz

P0205 = P0205 = ng dng b bin tn (nhp vo kiu mmen yu cu) 0 0 Mmen khng i (v d thang my, my nn, my gia cng) 1 Mmen bin i (v d bm, qut) Ch

P010

0 =

1,2

P01

00 =

0

Thng s ny ch c tc dng i vi b bin tn trong h truyn ng 5.5 kW / 400V

P0300 = P0300 = Chn kiu ng c 1

1 ng c khng ng b (hay ng c d b) 2 ng c ng b

Ch i vi P0300 = 2 (ng c ng b), ch c php iu khin kiu V/f

(P1300< 20)

P0100 =

Bt u

6 Ci t thng s Thng 7/05


29

P0304 = P0304 = in p nh mc ng c thng s FU

in p nh mc [V] ghi trn nhn ca ng c in p nh mc ghi trn nhn phi c kim tra, t bit c cu hnh mch Y/ m bo ph hp vi cch ni mch trn bng u ni ca ng c

P0305 = P0305 = Dng in nh mc ng c thng s FU

Dng in nh mc [A] ghi trn nhn ca ng c P0307 = P0307 = Cng sut nh mc ng c thng s FU

Cng sut nh mc [kW/hp] ghi trn nhn ca ng c

Nu P0100 = 0 hoc 2, gi tr tnh theo n v kW Nu P0100 = 1, gi tr tnh theo n v hp

V d mt loi nhn ghi thng s nh mc ca ng c in hnh (thng s cho cu hnh mch )

P0308 = ... P0308 =... H s Cos nh mc ng c thng s FU H s cng sut nh mc (cos) ghi trn nhn Nu nh ci t l 0, gi tr c t ng tnh ton Nu P0100 = 1,2 th P0309 khng c ngha nn khng cn nhp P0309 = P0309 = Hiu sut nh mc ng c thng s FU Hiu sut nh mc ca ng c theo [%] c ghi trn nhn

Ci t l 0, gi tr c tnh bn trong Nu P0100 = 0 th P0309 khng c ngha, khng cn nhp P0310 = Tn s nh mc ng c 50.00Hz Tn s nh mc ca ng c tnh theo [Hz] ghi trn nhn S i cc c t ng tnh ton li nu thng s thay i P0311 = Tc nh mc ng c thng s FU Tc nh mc ca ng c tnh theo [v/ph] ghi trn nhn Ci t l 0, gi tr c tnh bn trong

Ch : Cn phi nhp thng s trong trng hp iu khin vect mch kn, iukhin V/f vi FCC v b trt P0320 = Dng t ho ng c 0.0 (Dng ny c nhp theo % ca P0305) Dng in t ho ng c tnh theo % P0305 (dng in nh mc ng c).

Vi P0320 = 0, dng t ho ng c c tnh ton s dng P0340 = 1 hoc sdng P3900 = 1-3 (kt thc qu trnh ci t nhanh)- v c hin th trong thngs r0331.

P0335 = Ch lm mt ng c 0 (Chn h thng lm mt ng c) 0 Lm mt t nhin: S dng trc g qut c gn vi ng c 1 Lm mt cng bc: S dng qut lm mt cp ngun ring 2 Lm mt t nhin v qut bn trong 3 Lm mt cng bc v qut bn trong P0640 = H s qu ti ng c 150% (H s qu ti ca ng c tnh theo [%] tng ng vi P0305)

H s ny xc inh gii hn dng in vo ln nht bng % dng in nh mcca ng c (P0305). Bng vic s dng P0205, thng s ny c ci t ti150% i vi mmen khng i v ti 110% i vi mmen thay i

P0700 = Chn ngun lnh (nhp ngun lnh) 2 0 Ci t mc nh 1 BOP (bn phm) 2 u ni 4 USS trn ng chuyn BOP 5 USS trn ng chuyn COM (cc u ni 29 v 30) 6 CB trn ng chuyn COM (CB = mun truyn thng)



30

P1000 = La chn im t tn s * 2 (nhp vo ngun im t tn s) 1 im t MOP 2 im t tng t 3 Tn s c nh 4 USS trn ng chuyn BOP 5 USS trn ng chuyn COM ( cc u dy iu khin 29 v 30) 6 CB trn ng chuyn COM ( CB l mun truyn thng) 10 Khng c im t chnh + im t MOP 11 im t MOP + im t MOP 12 im t tng t + im t MOP

76 CB trn ng chuyn COM + im t tng t 2 77 im t tng t 2 + im t tng t 2

P1080 = Tn s nh nht 0.00 Hz ( nhp tn s nh nht cho ng c, n v Hz) t tn s ng c nh nht ti ng c s chy m khng tnh n tn s im t. Gi

tr c ci t y c tc dng cho c quay thun v quay ngc P1082 = Tn s ln nht 50.00 Hz

( nhp tn s ln nht cho ng c, n v Hz) t tn s ng c ln nht ti ng c s chy m khng tnh n tn s im t. Gi

tr c ci t y c tc dng cho c quay thun v quay ngc P1120 = Thi gian tng tc 10.00 s

( nhp thi gian tng tc, n v s) Thi gian tng tc l thi gian ng c tng tc t im dng n im c tn s ln

nht (P1082) khi khng dng cch tng tc c dng ng cong. Nu thi gian tng tc c ci t qu nh, iu ny c th lm xut hin cnh bo A0501 ( gi tr gii hn dng) hoc lm cho b bin tn ca h truyn ng b dng vi li F0001 (qu dng).

P1121 = Thi gian gim tc 10.00 s ( nhp thi gian gim tc, n v s) Thi gian gim tc l thi gian ng c gim tc t im c tn s ln nht (P1082) n

im dng khi khng dng cch gim tc c dng ng cong. Nu thi gian tng tc c ci t qu nh, iu ny c th lm xut hin cc cnh bo A0501 ( gi tr gii hn dng), A0502 (gi tr gii hn qu p) hoc lm cho b bin tn ca h truyn ng b dng vi cc li F0001 (qu dng) hoc F0002 (qu p).

BOP

Cc u ni

USS BOP link

USS COM link

CB COM link

iu khin tun t

Knh imt

iu khin ng c

P0700 = 2

MOP

ADC

FF

USS BOP link

USS COM link

CB COM link

ADC2

im t b sung

im t chnh

Knh im t

iu khin ng c

iu khin tun t



31

P1135 = 5.00 s

OFF3 Thi gian gim tc ( nhp thi gian gim tc dng nhanh bng s)

V d nhp thi gian ng c gim t tn s ln nht P1082 xung trng thi dng hn thc hin lnh OFF3 (dng nhanh). Nu t thng s thi gian gim tc qu thp th s xut hin n bo A0501 (gi tr dng in gii hn), A0502 (gi tr in p vt qu gi tr cho php) hoc khng hot ng c do b li F0001 (qu dng) hoc F0002 (qu in p).

P1300 = Mode iu khin 0 ( Nhp mode iu khin theo yu cu) 0 V/f kiu tuyn tnh 1 V/f FCC 2 V/f kiu ng parabol 3 V/f kiu c th lp trnh c 5 V/f cho cc ng dng kiu my dt 6 V/f kiu FCC cho cc ng dng kiu my dt 19 V/f ch iu khin qua im t hiu in th c lp 20 Ch iu khin vect khng sensor 21 Ch diu khin vector c sensor 22 iu khin mmen xon vector khng sensor 23 iu khin mmen xon vector c sensor P1500 = Chn im t mmen xon* 0

(nhp ngun cho im t mmen xon) 0 Khng c im t chnh 2 im t kiu tng t 4 USS trn ng truyn BOP 5 USS trn ng truyn COM ( Cc u iu khin 29 v 30) 6 CB trn ng truyn COM (CB: mun truyn thng) 7 im t kiu tng t 2 P1910 = Chn d liu cho ng c* 0

0 Khng hot ng P 1960 = Ti u ho thit b iu khin tc 0 0 Hm

ti u ho thit b iu khin tc , phi bt ch iu khin vect vng kn (P1300=20 hoc 21). Sau khi chn xong ch ti u ho (P1960 =1), th n bo A0542 khng hin th.

P 3900 = Kt thc qu trnh ci t nhanh thng s 0 ( bt u qu trnh tnh ton ng c) 0 Khng ch ci t nhanh thng s (khng c qu trnh tnh ton mt)

1 Qu trnh tnh ton cc thng s ca ng c v t li tt c cc thng s khc theoch ca nh my, nhng thng s khng c trong qu trnh ci t nhanh (gn"QC"= 0)

2 Qu trnh tnh ton cc thng s mt v ci t li ch I/O theo ch nh mc 3 Ch tnh ton cc thng s ca mt. Khng ci t lai cc thng s khc CH Vi P3900= 1,2,3 P0340 t t ti 1 v cc d liu ph hp c tnh ton.

Kt thc ci t nhanh Nu mun thc hin thm cc chc nng khc ca b bin tn, hy s dng phn Ci t ng dng (xem mc 6.4). Khch hng nn p dng cch ny i vi cc h truyn ng yu cu nhiu tnh nng hot ng cao.

Kt thc



32

6.2 Nhn dng ng c

20o C Nhit mi trng xung quanh ng c (c nhp theo n v oC)

Nhit mi trng xung quanh ng c c nhp vi gi tr ng thi m d liu ca ng c ang c xc nh (gi tr mc nh l : 20o C) S chnh lch gia nhit ca ng c v nhit mi trng xung quanh ng c P0625 phi nm trong khong dung sai xp x 5 o C. Nu chnh lch trn khng nm trong khong dung sai ny th chu trnh xc nh d liu cho ng c ch din ra sau khi ng c ngui i.

0

Qu trnh nhn dng ng c vi P1910=1 P1910=1: Nhn dng ng c v thay i thng s tng ng. Cc thng s ny c b iu khin chp nhn v thc hin.

Khi P1910=1 c chn, xut hin cnh bo A0541 (cho bit qu trnh xc nh d liu cho ng c ang c thc hin) v thng s P0340 t t l 3.

Bt u qu trnh nhn dng ng c vi P1910=1

Qu trnh o cc gi tr c bt u vi lnh ON lin tc (trng thi n nh). ng c t chnh v tr rotor v dng in c chy qua. C th xem dng bng thng s r0069 (CO: Dng pha). Sau khi hon tt chu trnh xc nh d liu cho ng c, th thng s P1910 c t li (P1910=0, tc l ngng chu trnh xc nh d liu) v cnh bo A0541khng hin th na.

chuyn b bin tn sang trng thi mi, phi thc hin lnh OFF1 trc khi chuyn sang bc tip theo.

0

Nhn dng ng c vi P1910=3 P1910=3: Xc nh c tnh bo ho ng c v thay i cc thng s tng ng.

Khi P 1910=3 c chn, xut hin cnh bo A0541 (cho bit qu trnh xc nh d liu cho ng c ang c thc hin) v thng s P0340 t t l 2.

Bt u qu trnh nhn dng ng c vi P1910=3 Qu trnh o cc thng s c bt u vi lnh ON ln tip.

Sau khi hon tt chu trnh xc nh d liu cho ng c, th thng s P1910 c t li (P1910=0, tc l ngng chu trnh xc nh d liu) v cnh bo A0541khng hin th na.

chuyn b bin tn sang trng thi mi, phi thc hin lnh OFF1 trc khi chuyn sang bc tip theo.

6.3 Dng t ho Gi tr ca dng t ho r0331/ P0320 c nh hng ln ti cht lng iu khin vng kn. Khng

th o c gi tr ny trng thi dng. iu ny c ngha l gi tr ny c c tnh cho chun ng c 4 cc 1LA7 theo tiu chun ca Siemens thng qua qu trnh t ng t thng s P0340 = 1 (P0320 = 0; kt qu r0331).

Nu lch ca dng t ho qu cao, th cc gi tr in khng v cc gi tr in tr ca ng c s khng th xc nh mt cch chnh xc c.

c bit i vi cc loi ng c ca nh cung cp th ba, vic kim tra k dng t ho c xc nh l rt quan trng v nu cn thit th phi iu chnh cho hp l.

Cch thc xc nh dng t ho bng th cng v tnh ton li d liu s mch tng ng khi h truyn ng c iu khin theo phng php vect vng kn (P1300 = 20/21) c minh ho theo bng di y.

KHI NG

P0625 = ?

|Nhit ng c -P0625 5

Cho php lm mt

P1910 = 1

A0541

ON

OFF1

P1910 =3

A0541

ON

OFF1

KT THC

C Khng



33

Chu trnh ci t nhanh

Nh c qu trnh ci t nhanh, b bin tn hiu v iu chnh thng s ph hp vi ng c. Cc thng s cng ngh cng c ci t. Nhn dng ng c

Nh c qu trnh nhn dng ng c, d liu s mch in ng c tng tng (m phng trong bin tn) c xc nh bng k thut o. Xc nh dng t ho

xc nh dng t ho (P0320/r0331), cn tng tc ng c ti tc c gi tr gn bng 80% tc nh mc trong iu kin khng ti.

Trong qu trnh ny, cc iu kin sau phi c duy tr cn thn: - Phng php iu khin vect phi hot ng, P1300=20/21 - Khng c vn hnh thiu t thng (r0056,8 = 0) - im t t thng, r1598= 100% - Khng c lm vic ch ti u ho hiu sut, P1580 =0%

Ch hot ng khng ti c ngha l ng c ang hot ng khng ti (trc ng c khng c ni vi ti).

Trong iu kin trng thi n nh, dng in r0027 t c xp x tng ng vi dng t ho nh mc r0331. (Dng in ny lun lun thp hn dng khng ti cho ch iu khin n thun V/f).

Qu trnh tnh ton mi cc d liu s mch tng ng ca ng c lin quan n vic o v nhp dng in t ho l mt qu trnh lp.Qu trnh ny phi lp i lp li t nht 2-3 ln cho ti khi t c cc tiu chun sau :

C Khng - Gi tr dng t ho c nhp vo cng chnh xc th im t t thng (r1598

=100%) cng ph hp hn vi gi tr thc ca t thng (r0084 = 96..104%) ly t m hnh b quan st.

- Gi tr hiu chnh u ra Xm (r1787) ca m hnh quan st nn cng thp cng tt. Cc gi tr ph hp nm trong khong 1-5%. Gi tr hiu chnh Xh m b quan st phi thc hin cng t th nhy ca cc thng s ng c sau s c mt in cng gim.

CH

hin th r0084 trn BOP/AOP, b lc thng s phi m ti cp 4 v thng s phc v P3950 = 46. P0320 = Tnh ton P0320 0

Lc ny, gi tr mi c th dc nhp theo P0320 t phn t dng in sinh t thng c xc nh r0029 bng thng thc sau. P0320 = r 0029*100 / P0305 P0340 = Tnh ton cc thng s ng c 0

Cc gi tr d liu ca s mch tng ng c tnh ton t d liu nh mc ghi trn nhn c nhp.Ngoi ra cc thng s ca cc ch iu khin c t t trc, (do c ti u ho) (P0340 =3).

Khi ng

Ci t nhanh

Nhn dng ng c

Hot ng trong iu

khin khng ti

Tho mn cc iu

kin khng?

Kt thc



34

6.4 Ci t ng dng Ci t ng dng iu chnh/ ti u ho s kt hp gia b bin tn v ng c cho mt ng dng c th. B bin tn c nhiu tnh nng nhng khng phi tt c cc tnh nng u cn thit cho mt ng dng c th. C th b qua cc tnh nng ny khi ci t ng dng. Phn ln cc tnh nng c th c m t y; hy xem danh sch cc thng s cho cc tnh nng ph. Cc thng s c nh du * th c nhiu ch ci t hn cc ch c lit k ra y. Hy xem danh sch thng s khi mun ci t thm cc ch khc.

P0003 = 3 Mc truy nhp ca ngi s dng* 1

1 Cp c bn: cho php truy cp ti cc thng s hay s dng nht 2 Cp m rng: cho php m rng kh nng truy cp, v d ti chc nng I/O ca b

bin tn. 3 Cp chuyn gia: ( ch dnh cho cc chuyn gia s dng )

6.4.1 Giao din ni tip P2010 = Tc baud USS 6 Cc ch ci t c th

Ci t tc baud cho truyn thng USS. 4 2400 Baud 5 4800 Baud

P2011 = a ch USS 0 6 9600 Baud Ci t a ch duy nht cho b bin tn. 7 19200 Baud 8 38400 Baud

P2012 = Chiu di PZD USS 2 9 57600 Baud Xc nh s t c di 16 bit PZD trong mt ln

truyn d liu theo kiu USS. 10 76800 Baud

P2013 = Chiu di PKW USS 127 11 93750 Baud Xc nh s t c di 16 bit PKW trong mt ln

truyn d liu theo kiu USS. 12 115200 Baud

6.4.2 Chn ngun lnh P0700 = Chn ngun lnh 2

Chn ngun lnh s 0 Ch ci t li khi xut xng 1 BOP (bn phm) 2 u ni 4 USS trn ng truyn BOP 5 USS trn ng truyn COM 6 CB trn ng truyn COM

Khi ng

BOP

Cc u ni

USS BOP link

USS COM link

CB COM link

iu khin tun t

Knh im t

iu khinng c

P0700 = 2



35

6.4.3 u vo s (DIN) P0701 =... Chc nng u vo s s 1 1 Cc ch ci t c th

u ni s 5 ON/OFF1

1

P0702 =... Chc nng u vo s s 2 12 u ni s 6

12 o chiu

P0703 =... Chc nng u vo s s 3 9 u ni s 7 9 Nhn bit li

P0704 =... Chc nng u vo s s 4 15 u ni s 8 15 im t c nh ( chn trc tip)



0 1 2 3 4 9 10111213141516172125293399

u vo s khng hot ng ON/OF1 ON + o chiu/OFF1 OFF2- Dng t do OFF3- Gim tc nhanh Nhn bit li Chy nhp, bn phi Chy nhp, bn tri o chiu Tng MOP (Tng tn s) Gim MOP (Gim tn s) im t c nh (chn trc tip) im t c nh (chn trc tip+ ON) im t c nh (chn m nh phn + ON) Ti ch/ T xa Kch hot hm DC Li h thng bn ngoi Khng cho php im t tn s b sung Cho php ci t thng s BICO

P0707 = 0 Chc nng u vo s s 7 0 Qua u vo tng t, u ni s 3 0 u vo s khng hot ng

P0708 = 0 Chc nng u vo s s 8 0 Qua u vo tng t, u ni s 10 0 u vo s khng hot ng

P0724 =... Thi gian tr i vi cc u vo s Xc nh thi gian tr (thi gian lc) dng cho u vo s

0 1 2 3

Khng c thi gian tr Thi gian tr 2.5 ms Thi gian tr 8.2 ms Thi gian tr 12.3 ms

P0725 =... u vo s PNP/NPN Chuyn i gia trng thi tch cc cao (PNP) v tich cc thp (NPN). Qu trnh ny p dng vi tt c cc u vo s cng mt lc.

0 1

Ch NPN ==> Tch cc thp Ch PNP ==> Tch cc cao

Thi gian tr: DIN

Knh DIN



36

6.4.4 Cc u ra s (DOUT)

P0731= BI: Chc nng ca u ra s s 1 52.3 Cc ch ci t thng thng

Xc nh ngun ca u ra s s 1. 52.0 B truyn ng sn sng 0

P0732= BI: Chc nng ca u ra s s 2 52.7 0

52.1 B truyn ng sn sng hot ng

Xc nh ngun ca u ra s s 2.

52.2 B truyn ng ang hot ng 0 P0733= BI: Chc nng ca u ra s s 3* 0.0 0

52.3 Kch hot ch pht hin li ca

b truyn ng 52.4 OFF2 hot ng 1

Xc nh ngun ca u ra s s 3.

52.5 OFF3 hot ng 1 P0731= o u ra s 0 52.6 Ch hm hot ng 0

0 52.7 Ch cnh bo ca b truyn ng hot ng

1 52.8 chnh lch gia gi tr im t v gi tr thc t

0 52.9 iu khin t PLC ( iu khin PZD)

52.A Tn s ln nht t c 0 1 52.B Cnh bo: Dng in ca ng c

ang ti gi tr gii hn 0 52.C Ch hm c kh (MHB) hot

ng 52.D ng c qu ti 1

0 52.E Chiu quay ca ng c, theo chiu kim ng h

52.F B bin tn qu ti 1

Xc nh trng thi cao v thp ca rle cho mt chc nng nht nh.

53.0 Kch hot hm DC 0

R le:

Knh DOUT

Thi gian ng / m ln nht



37

6.4.5 Chn gi tr im t tn s P1000 = Chn Gi tr t tn s 2

0 Khng c Gi tr t chnh 1 Gi tr t MOP 2 Gi tr t tng t 3 Tn s c nh 4 USS trn ng truyn BOP 5 USS trn ng truyn COM 6 CB trn ng truyn COM 7 Gi tr t tng t 2 10 Khng c Gi tr t chnh + Gi tr t MOP 11 Gi tr t MOP + Gi tr t MOP 12 Gi tr t tng t + Gi tr t MOP

...

76 CB trn ng truyn COM + Gi tr t tng t 2 77 Gi tr t tng t 2 + Gi tr t tng t 2 CH Ngoi Gi tr t chnh, c th nhp mt Gi tr t ph bng P1000 V d P1000=12: P1070 CI: Gi tr t chnh P1000=12P1070=755 r0755 CO: ADC thc t sau khi ly thang t l [4000h] P1075 CI: Gi tr t ph P1000=12P1075=1050 r1050 CO: Tn s u ra thc t ca MOP

P1074 = BI: Gi tr t ph khng hot ng 0:0

P1075 = CI: Gi tr t ph 0:0 Xc nh ngun ca Gi tr t ph (c thm vo Gi tr t chnh ) Cc ch ci t thng thng

755 1024 1050

Gi tr t u vo tng t Gi tr t tn s c nh Gi tr t MOP

P1076 = CI: nh thang gi tr t b sung 1:0 Xc nh ngun chia cho Gi tr t ph. Cc ch ci t thng thng

1 755

1024 1050

nh thang bng 1.0 (100%) Gi tr t u vo tng t Gi tr t tn s c nh Gi tr t MOP

MOP

ADC

FF

USS BOP link

USS COM link

CB COM link

ADC2

Gi tr t ph

Gi tr t chnh

Knh im t

iu khin tun t

iu khin ng c

P1000 = 12

P 1000 = 12



38

6.4.6 u vo tng t (ADC)

P0756 = Kiu ADC 0 Xc nh kiu u vo tng t v kch hot chc nng theo di ca u vo tng t

0 u vo in p n cc (t 0 n +10 V) 1 u vo in p n cc vi chc nng theo di (t 0 n 10 V) 2 u vo dng in n cc (t 0 n 20mA) 3 u vo dng in n cc vi chc nng theo di (t 0 n 20mA) 4 u vo in p lng cc (t -10 ti +10 V) CH T P0756 n P0760, th p dng cc ch s sau: Ch s 0: u vo tng t s 1 (ADC1), u ni 3,4 Ch s 1: u vo tng t s 2 (ADC2), u ni 10, 11

P0757 = Gi tr x 1 ca nh thang ADC 0 V

P0758 = Gi tr y1 ca nh thang ADC 0.0%

Thng s ny biu th gi tr x1 bng a% ca P2000.(Tn s quy chiu). P0759 = Gi tr x2 ca nh thang ADC 10 V

P0760 = Gi tr y2 ca nh thang ADC 100.0%

Thng s ny biu th gi tr x2 bng a% ca P2000.(Tn s quy chiu). P0761 = Chiu rng ca di cht ADC 0 V

Xc nh chiu rng ca di tn hiu cht trn u vo tng t.

P0762 = Thi gian tr, mt tn hiu ADC 10 ms

Xc nh thi gian tr t thi im mt tn hiu im t tng t n khi xut hin thng bo li F0080 .

Knh ADC

Kho chuyn mch DIP

Kiu ADC

nh thangADC

Vng cht ADC

im t

Cm bin li t dy

Chc nng



39

6.4.7 u ra tng t (DAC) P0771 = CI: DAC 21

Xc nh chc nng ca u ra tng t t 0 n 20 mA

21 24 25 26 27

CO: CO: CO: CO: CO:

Tn s u ra (c ly thang t l theo P2000) Tn s u ra ca b bin tn (c ly thang t l theo P 2000) in p u ra (c ly thang t l theo P2001) in p ng trung gian DC (c ly thang t l theo P2001) Dng in u ra (c ly thang t l theo P2002)

CH i vi P0771 n P0781, th p dng cc ch s sau:

Ch s 0 : Ch s 1 :

u ra tng t s 1 (DAC1), u ni 12, 13 u ra tng t s 2 (DAC1), u ni 26, 27

P0773 = Hng s thi gian lc DAC 2ms Xc nh thi gian lc [ms]cho tn hiu u ra tng t.Thng s ny cho php lc DAC nh

b lc PT1. P0776 = Kiu DAC 0

Xc nh kiu u ra tng t

0 1

Dng in u ra in p u ra

CH P0776 thay i t l ca r0774 (t 0-20mA n 0-10 V) Cc thng s t l P0778, P 0780 v vng cht tlun c nhp trong khong 0-20mA DAC l in p u ra th phi ng cc u ra DAC bng mt in tr 500.

P0777 = Gi tr x1 ca thang t l DAC 0.0%

Xc nh gi tr u ra x1 l a%. Thng s ny biu th gi tr tng t nh nht l a% ca P200x (ph thuc vo ch ci t P0771).

P0778 = Gi tr y1 ca thang t l DAC 0 Thng s ny biu th gi tr cho x1 theo n v mA.

P0779 = Gi tr x2 ca thang t l DAC 100.0%

Xc nh gi tr c tnh u ra x2 l a%. Thng s ny biu th gi tr tng t nh nht l a% ca P200x (ph thuc vo ch ci t P0771).

P0780 = Gi tr y2 ca thang t l DAC 20 Thng s ny biu th gi tr x2 theo mA.

P0781 = Chiu rng ca di cht DAC 0 t chiu rng ca di cht theo n v [mA] cho u ra tng t.

Knh DAC

nh thang DAC

Vng cht DAC

Chc nng



40

6.4.8 Chit p xung (MOP) P1031 = B nh im t ca MOP 0

Lu li im t ca chit p xung (MOP) hot ng trc khi ra lnh OFF hoc ngt in.

0 1

im t MOP s khng c lu li. im t MOP s c lu li. (Gi tr P1040 c cp nht)

P1032 = Khng cho php cc im t MOP m 1 Cho php t MOP c gi tr m

0 1 Khng cho php im t MOP c gi tr m.

P1040 = im t MOP 5.00 Hz Xc nh im t cho chit p xung.

Thi gian tng tc v thi gian gim tc MOP c xc nh bng thng s P1120 v P1121. Cc ch ci t c th khi chn MOP:

Ch la chn Tng MOP Gim MOP

DIN

P0719=0, P0700=2, P1000=1, hoc P0719=1, P0700=2

P0702=13 (DIN2) P0703=14 (DIN3)

BOP

P0719=0, P0700=1, P1000=1, hoc P0719=11

Nt UP Nt DOWN

US trn ng truyn BOP

P0719=0, P0700=4, P1000=1, hoc P0719=41

T iu khin USS r2032 Bit 13


US trn ng truyn COM

P0719=0, P0700=5, P1000=1, hoc P0719=51



CB

P0719=0, P0700=6, P1000=1, hoc P0719=61

T iu khin CB r2090 Bit 13

T iu khin CB r2090 Bit 14



41

6.4.9 Tn s c nh (FF) P1001 = Tn s c nh s 1 0.00 Hz

C th c chn trc tip qua DIN1 (P0701=15,16)

P1002 = Tn s c nh s 2 5.00 Hz

Khi xc nh chc nng ca cc u vo s (P0701 ti P0706), c th la chn ba kiu khc nhau cho cc tn s c nh:

C th c chn trc tip qua DIN2 (P0702=15,16) Chn trc tip (P0701-P0706 =15)

P1003 = Tn s c nh s 3 10.00 Hz


P1004 = Tn s c nh s 4 15.00 Hz

15 = ch c bit ny, mi u vo s lun chn tn s c nh tng ng, v d: u vo s s 3 s chn tn s c nh s 3Nu nhiu u vo hot ng cng mt lc th cc gi tr c cng li. Mt lnh ON cn c b sung. Vd. FF1+FF2+FF3+FF4+FF5+FF6


Chn trc tip + lnh ON (P0701-P0706=16)

P1005 = Tn s c nh s 5 20.00 Hz

C th c chn trc tip qua DIN5 (P0705 =15,16)

16 =

ch ny, cc tn s c nh c chn ging nh cho 15, tuy nhin cc tn s ny c kt hp vi mt lnh ON. Vd. FF1+FF2+FF3+FF4+FF5+FF6

P1006 = Tn s c nh s 6 25.00 Hz

C th c chn trc tip qua DIN6 (P0706 =15,16)

17= Chn ch m nh phn + Lnh ON ( c m BCD + ON/OFF1) C th chn 16 tc c nh ch ny.

P1007 = Tn s c nh s 7 30.00 Hz

P1008 = Tn s c nh s 8 35.00 Hz

P1009 = Tn s c nh s 9 40.00 Hz

P1010 = Tn s c nh s 10 45.00 Hz

P1011 = Tn s c nh s 11 50.00 Hz

P1012 = Tn s c nh s 12 55.00 Hz

P1013 = Tn s c nh s 13 60.00 Hz

P1014 = Tn s c nh s 14 65.00 Hz

P1015 = Tn s c nh s 15 65.00 Hz

.

P1016 = M tn s c nh - Bit 0 1

Xc nh phng php la chn cc tn s P1017 = M tn s c nh - Bit 1 1

1 2 3

Chn trc tip Chn trc tip + Lnh ON Chn ch m ho nh phn+ lnh ON

P1018 = M tn s c nh - Bit 2 1

P1019 = M tn s c nh - Bit 3 1

CH i vi cc ch ci t 2 v 3, tt c cc thng s t P1016 n P1019 phi c t ti gi tr chn b bin tn chp nhn lnh .

P1025 = M tn s c nh - Bit 4 1

1 2

Chn trc tip Chn trc tip + Lnh ON

P1027 = M tn s c nh - Bit 5 1



42

6.4.10 Chy nhp

P1058 = Tn s chy nhp bn phi 5.00Hz Tn s c o bng n v Hz khi ng c

quay theo chiu kim ng h ch chy nhp.

P1059 = Tn s chy nhp bn tri 5.00Hz Tn s c o bng n v Hz khi ng c

quay ngc chiu kim ng h ch chy nhp.

P1060 = Thi gian tng tc chy nhp 10.00s Thi gian tng tc (n v s) t l khong thi

gian tn s tng t 0 n gi tr ln nht (P1082). Thi gian tng tc khi chy nhp c gii hn bi P1058 hoc P1059.

P1061 = Thi gian gim tc chy nhp 10.00s Thi gian gim tc (n v s) l khong thi

gian tn s gim t gi tr ln nht (P1082) xung 0.



43

6.4.11 B pht hm to dc (RFG) P1091 = Tn s nhy 1 (n v Hz) 0.00Hz Xc nh tn s nhy 1 trnh cc nh

hng ca hin tng cng hng chc v kh cc tn s trong khong P1101 (di tn s nhy)

P1092 = Tn s nhy 2 0.00Hz

P1093 = Tn s nhy 3 0.00Hz

P1094 = Tn s nhy 4 0.00Hz P1101 = Di tn s nhy (n v Hz) 2.00 Hz

P1120 = Thi gian tng tc (n v s) 10.00 s

P1121 = Thi gian gim tc (n v s) 10.00 s

P1130 = 00.0 s

Thi gian tng tc ban u theo phng php ng cong (n v tnh theo s)

P1131 = 00.0 s

Thi gian tng tc cui cng theo phng php ng cong (n v tnh theo s)

P1132 = 00.0 s

Thi gian gim tc ban u theo phng php ng cong (n v tnh theo s)

P1133 = 00.0 s

Thi gian gim tc cui cng theo phng php ng cong (n v tnh theo s)

P1134 = Phng php ng cong 0 0 Lin tc

1 Gin on

Cc thi gian tng/ gim tc theo phng php ng cong nn s dng v c th trnh c cc phn ng t ngt, nh gim c ng sut v h hng cho phn c. Thi gian tng tc v thi gian gim tc c ko di nh phng php tng/ gim on c tuyn ng cong.

P1135 = Thi gian gim tc theo lnh OFF3 5.00s Xc nh thi gian gim tc t im c tn s ln nht n im dng i vi lnh OFF3

Di tn s nhy

Tn s nhy



44

6.4.12 Cc tn s quy chiu / gii hn

P1080 = Tn s nh nht (n v Hz) 0.00 Hz t tn s nh nht cho ng c [Hz], ti ng c s chy m khng ph thuc vo gi tr t tn s. Nu im t c gi tr nh hn gi tr ca thng s P1080, th tn s u ra c t P1080 v o du.

P1082 = Tn s ln nht (n v Hz) 50.00 Hz t tn s ln nht cho ng c [Hz], ti ng c s chy m khng ph thuc vo gi tr t tn s. Nu im t vt qu gi tr ca thng s P1082, th tn s u ra c gii hn. Gi tr t y c tc dng cho c hai trng hp ng c quay thun v ngc.

P2000= Tn s quy chiu (n v Hz) 50.00 Hz Tn s quy chiu (n v Hz) tng ng vi gi tr 100%. Nn thay i ch ci t khi tn s ln nht cn c gi tr ln hn 50Hz. Ch ny c t ng thay i n gi tr 60Hz nu tn s chun 60Hz c chn nh thng s P0100. Ch : Tn s quy chiu c nh hng n tn s im t v cc im t tn s thng qua giao thc USS v mun PROFIBUS (FB100) (4000H hex 100% P2000) u c lin quan n gi tr ny.

P2001 = in p quy chiu (n v V) 1000V

in p quy chiu theo n v V (in p ra) tng ng vi gi tr 100%. Ch Ch nn thay i ch ci t ny nu cn a ra in p theo mt thang t l khc.

P2002= Dng in quy chiu (n v A) 0.10 A

Dng in quy chiu tnh theo n v A (dng in ra) tng ng vi gi tr 100%. im t mc nh = 200% dng in nh mc ca ng c (P0305). Ch Ch ci t ny ch nn c thay i nu dng in ra cn thit tnh theo mt thang t l khc.

P2003 = Mmen quy chiu (n v A) 0.12 Mn

Mmen quy chiu tnh theo n v Nm tng ng vi gi tr 100%. Ch ci t mc nh = 200% mmen inh mc ca ng c chy mmen khng i c xc nh t d liu tng ng ca ng c. Ch Ch nn thay i ch ci t nu mmen u ra cn thit tnh theo mt thang t l khc.



45

6.4.13 Bo v b bin tn P0290 = Ch phn ng qu ti ca b bin tn 0

Chn ch phn ng cho b bin tn i vi hin tng qu nhit bn trong. 0 Gim tn s u ra 1 Dng (F0004/ F0005) 2 Gim tn s xung v tn s u ra 3 Gim tn s xung sau dng (F0004)

P0292 = Ch cnh bo nhit ca b bin tn 15oC Xc nh s chnh lch nhit (n v oC) gia ngng tc ng qu nhit v ngng

cnh bo ca bin tn. Ngng cnh bo c b bin tn lu gi bn trong v ngi s dng khng th thay i c.

Ngng cnh bo nhit ca b bin tn: T_warm Twarn = Ttrip - P0292 Ngng tc ng do nhit ca bin tn T_trip MM440, C v A - C D - F F FX GX 600V 95kW 110kW 132kW 160kW 200kW

Nhit

CT CT CT CT CT B tn nhit 110oC 95oC 80oC 88oC 91oC 80oC 82oC 88oC IGBT 140oC 145oC 145oC 150oC 150oC 145oC 147oC 150oC B chnh lu vo - - - 75oC 75oC 75oC 75oC 75oC Khng kh lm mt - - - 55oC 55oC 55oC 55oC 50oC Bng iu khin - - - 65oC 65oC 65oC 65oC 65oC

P0295 = Thi gian tr tt qut 0s Thng s ny xc nh thi gian tr tnh bng giy t thi im tt ngun bin tn n thi

im tt ngun qut. Nu t bng 0 th qut s tt ngay lp tc khi tt ngun.

6.4.14 Bo v nhit ng c Ngoi vic bo v qu nhit ng c, nhit ng c cng c tnh ton trong qu trnh hiu chnh d liu s mch tng ng ca ng c. c bit i vi ng c mang ti ln nhit cao, s hiu chnh ny c nh hng ng k ln n nh ca iu khin vng kn. i vi MM440, nhit ca ng c ch o c nh s dng b sensor KTY84. i vi gi tr thng s P0601 = 0,1, nhit ca ng c c tnh ton hoc c lng nh s dng m hnh nhit ng c. Nu bin tn lun lun c cp in p ngoi l 24 V, th nhit ng c cng c theo di/hiu chnh nh hng s thi gian nhit ca ng c, ngay c khi khi in p li tt. i vi phng php iu khin vng kn trong trng hp ng c ti ln nhit cao v khi ngun in li phi thng xuyn ng/ngt, th:

r0037

r0036 i2t

P0294

Nhit trong b tn nhit P0292

Nhit IGBT P0292

iu khin i_max (U/f) iu khin dng

(SLVC,VC)

iu khin xung f

A0504

Theo di b bin tn

Phn ng qu ti b bin tn P0290

A0505

A0506

F0004

F0005



46

-cn dng mt sensor KTY84 hoc - cn ni mt ngun in p ngoi 24V.

P0335 = Ch lm mt ng c (chn h thng lm mt cho ng c) 0

0 Lm mt t nhin: S dng qut c gn trn trc ca ng c 1 Lm mt cng bc: S dng qut lm mt c cp ngun ring 2 Lm mt t nhin v s dng qut bn trong 3 Lm mt cng bc v s dng qut bn trong

P0601 = Sensor nhit cho ng c 0 Chn sensor nhit cho ng c 0 Khng c sensor 1 Nhit in tr PTC 2 KTY84 Khi chn ch "Khng c sensor" hoc "ch nhit in tr PTC" , nhit ca ng c c xc nh da trn gi tr c c lng bi m hnh nhit ng c

P0604 = Ngng cnh bo v qu nhit ca ng c 130 oC

Xc nh ngng cnh bo bo v ng c khi qu nhit . Ngng cnh bo ny lun lun c gi tr thp hn 10% so vi ngng m ti hoc ch tc ng hoc ch gim Imax c khi ng (P0610). trip = 1,1 warm = 1,1 P0604 warm : ngng cnh bo (P0604) trip : ngng tc ng (nhit ln nht c th)

Ngng cnh bo nn c t mc ln hn nhit xung quanh P0625 t nht l 40oC. P0604 P0625 + 40 oC.

P0610 = Tc ng theo nhit ca bin tn 2 Xc nh ch tc ng khi nhit ca ng c ti ngng cnh bo 0 Khng tc ng, ch cnh bo 1 Cnh bo v gim Imax (dn n tn s u ra thp hn) 2 Cnh bo v tc ng (F0011)

P0640 = H s qu ti ca ng c [%] 150,0%

Xc nh gii hn dng qu ti cho ng c, n v [%], tng ng vi P0305 (dng in nh mc ca ng c). Gi tr gii hn c ly l gi tr thp hn trong hai gi tr sau: hoc dng in ln nht ca bin tn hoc 400% dng in nh mc ca ng c (P0305).

Li F0015

pht hin mt tn hiu

D liu mch tng ng

Tn tht in nng

Pv,mot

M hnh nhit

ng c

Khng sensorTc ng theo nhit



47

6.4.15 Encoder P0400 = Chn kiu encoder 0 Thng s u dy Dng ng xung u ra Encoder

Chn kit encoder P0400 = 1 A Dng n 0 Khng dng A Dng i 1 B encoder mt ng xung AN 2 B encoder hai ng xung P0400 = 2 A Dng n B A Dng i

Bng bn cho thy gi tr ca P0400 l hm ca s cc dng ng xung AN

B BN m bo hot ng tt, cc kho chuyn mch DIP trn mun encoder phi c t

da vo kiu encoder (TTL, HTL) v u ra encoder nh sau: Kiu Ngun

Encoderu ra

Dng n Dng i TTL (v d 1xP8001-2) 5V 111111 010101 HTL(v d 1xP8001-1) 24V 101010 000000

P0408 = S xung encoder trn mt vng quay 1024 Xc nh s lng xung encoder pht ra khi trc ng c quay mt vng.

P0491 = Tc ng khi mt tn hiu tc 0 Xc nh phng php tnh tc sau khi mt tn hiu encoder 0 Khng chuyn sang SLVC 1 Chuyn sang ch SLVC

P0492 = Sai lch tc cho php 10.00Hz Thng s P0942 xc nh ngng sai lch tn s khi tn hiu encoder b mt (bo li F0090) Ch :

'Vi P0492 = 0, H thng khng theo di hin tng mt tn hiu encoder. P0494 = Thi gian tr tc ng khi mt tn hiu tc 10ms

P0492 c dng d tm tn hiu encoder b mt cc tn s thp. Nu tc ca ng c nh hn gi tr ca thng s P0492, th hin tng mt tn hiu encoder c xc nh nh dng thut ton thch hp. P0494 xc nh thi gian tr tnh t thi im d tm tn hiu tc b mt n lc bt u c tc ng tng ng.

Ch P0494 = 0 ( khng c chc nng theo di): Vi P0492 = 0, mt tn hiu encoder cc tn s thp khng c kch hot. Do , cc

tn s ny, mt tn hiu encoder khng c d tm (mt tn hiu encoder tn s cao vn c kch hot min l P0492 > 0).



48

6.4.16 iu khin V/f P1300 = Ch iu khin V/f 0

Dng thng s ny chn ch iu khin. i vi ch iu khin "c tnh V/f", t s gia in p ra ca bin tn vi tn s ra ca bin tn c xc nh.

0 V/f tuyn tnh 1 V/f FCC 2 V/f vi c tnh parabol (xem thm trong danh sch cc thng s)

P1310 = B tng lin tc (n v %) 50, 00% Tng in p theo % tng ng vi P0305 (dng in nh mc ca ng c) v P0350

(in tr stato) cc tn s ra thp duy tr t thng ca ng c v cc gi tr in tr c tc dng ca cun dy khng th b qua.

P1311 = B tng gia tc (n v %) 0, 0%

Tng in p tng tc hm theo % tng ng vi P0305 v P0350. P1311 ch lm tng in p khi tng tc/ gim tc v lm tng thm mmen tng tc/ hm. Nu nh thng s P1312 ch c tc dng cho qu trnh tng tc u tin sau lnh ON, th thng s P1311 c tc dng sau mi thi im m h truyn ng tng tc hoc hm.

B tng in p c tnh tuyn tnh V/f

Di gi tr

B tng in p

V/f thng thng (P1300 = 0)

P1310 kch hot

B tng in p c tnh tuyn tnh V/f

Di gi tr B tng in p

V_tng thc

in p ra

V/f thng thng (P1300 = 0)

P1310 kch hot



49

P1312 = B tng khi khi ng (n v %) 0.0%

Tng in p khi khi ng (sau lnh ON) theo % tng ng vi P0305 (dng in nh mc ng c) hoc P0350 (in tr stato), khi s dng c tnh V/f tuyn tnh hoc bnh phng. in p tng n khi

1) t n im t ln u tin 2) im t gim n gi tr nh hn u ra b pht hm to dc tc thi.

P1320 = 0.0Hz

To tn s th nht ca lut V/f c th lp trnh c

t cc to V/f (t P1320/1321 n P1324/1325 xc nh c tnh V/f.

P1321 = 0.0Hz

To in p th nht ca lut V/f c th lp trnh c

P1322 = 0.0Hz

To in p th hai ca lut V/f c th lp trnh c

P1323 = 0.0Hz

To in p th hai ca lut V/f c th lp trnh c

P1324 = 0.0Hz

To tn s th ba ca lut V/f c th lp trnh c

P1325 = 0.0Hz

To in p th ba ca lut V/f c th lp trnh c

P1333 = Tn s khi khi ng cho FCC 10,0% ( n v %) Xc nh tn s khi khi ng FCC nh l hm ca

tn s nh mc ca ng c (P0310).

Ch Mc b in p khng i P1310 s gim dn khi

chuyn sang ch FCC.

P1335 = B trt (tnh theo %) 0,0% Di b trt: iu chnh ng tn s ra ca bin tn sao cho

tc ng c khng i khi ti ng c thay i

P1338 = H s suy gim cng hng V/f 0,00 H s suy gim cng hng V/f

chuyn mch



50

6.4.17 iu khin nh hng trng (FCC) Cc gii hn P0640 = H s qu ti ng c [%] 150,0%

Gii hn dng in qu ti ng c tnh theo % ca P0305 (dng in nh mc ng c). Gi tr gii hn c ly l gi tr thp hn trong hai gi tr sau: hoc dng in ln nht ca bin tn hoc 400% dng in nh mc ca ng c (P0305).

P1520 = CO: Mmen gii hn trn FC-spec. Xc nh gi tr c nh cho mmen gii

hn trn. P1520 def = 1,5x r0333 P1520max = 4x r0333

P1521 = CO: Mmen gii hn di FC-spec. Nhp gi tr c nh cho mmen gii hn

di. P1521 def = - 1,5x r0333 P1521 max = 4x r0333

P1530 = Gii hn cng sut ch ng c FC-spec.

Xc nh gi tr c nh cho cng sut tc dng cho php ln nht ch ng c

P1530 def = 2,5xP0307 P1530 max = 3 x P0307

P1531 = Gii hn cng sut ch my pht FC-spec.

Nhp gi tr c nh cho cng sut pht tc dng cho php ln nht ch my pht.

P1531 def = -2,5x P0307 P1531 max = -3x P0307

Gii hn cng sut ch ng c my pht

Gii hn dng Gii hn dng

Gii hn cng sut

Gii hn mmen

Gii hn mmen t c

Mmen khng i

Cng sut khng i

Cng sut dng

f_dng

f_thc t



51

6.4.17.1 iu khin vect khng sensor (SLVC) P1300 =20 Ch iu khin 0

20 iu khin tc vect vng kn khng c encoder SLVC c th rt c hiu qu trong cc ng dng sau: Cc ng dng yu cu mmen ln Cc ng dng yu cu p ng nhanh khi ti thay i t ngt Cc ng dng yu cu duy tr mmen khi qua tn s 0 Hz Cc ng dng yu cu duy tr tc chnh xc cao Cc ng dng yu cu bo v trc ng c khng b trt.

P1452 = Hng s thi gian b lc cho tn s thc (SLVC) 4ms t hng s thi gian ca b lc PT1 dng cn du sai s ca khu iu khin tc khi

lm vic ch vect khng sensor (SLVC). Vic gim gi tr ny lm tng cht lngng ca qu trnh iu chnh tc . Nu t gi tr thp hoc gi tr cao th s gy ra smt n nh. C th t P1452 =2 trong hu ht cc ng dng.

P1470 = H s khuch i ca khu iu khin tc (SLVC) 3.0 Nhp h s khuch i ca khu iu khin tc trong ch iu khin vect khng

sensor (SLVC). P1472 = Hng s thi gian tch phn ca khu iu khin tc (SLVC) 400ms

Nhp hng s thi gian tch phn ca khu iu khin tc trong ch iu khin khng sensor (SLVC).

P1610 = B tng mmen lin tc (SLVC) 50.0% t tng mmen di tn s thp hn SLVC (iu khin vect khng sensor). Nhp gi

tr ny theo % ca mmen nh mc ca ng c r0333. P1610 ch c tc dng ch iu khin vng h t 0Hz n xp x p1755.

P1611 = B tng mmen khi tng tc (SLVC)ttt 0.0% t tng mmen di tn s thp hn SLVC (iu khin vect khng sensor). Nhp gi

tr ny theo % ca mmen nh mc ca ng c r0333. P1611 ch c tc dng ch iu khin vng h t 0Hz n xp x p1755. Khc vi P1610 tng mmen P1611 ch c tc dng khi tng/gim tc.

Khu tin iu khin

*) ch c tc dng nu c khu tin iu khin (P1469 >0)

Mmen t

Tn s thc

Tn s t

San ti

t m hnh tnh ton



52

P1750 = T iu khin ca m hnh ng c 1

Thng s ny iu khin hot ng ca ch iu khin vect khng sensor (SLVC) cc tn s rt thp. Do , thng s ny c cc iu kin sau:

Bit00 Start SLVC open loop 0 NO 1 YES (Hot ng trc tip sau khi c lnh ON) Bit01 Zero Crossing SLVC open loop 0 NO 1 YES (vng tc i qua 0)

Trong hu ht cc ng dng, gi tr ci t ca thng s P2750 = 0 c kt qu tt nht tn s thp

P1755 = Tn s khi ng ca m hnh ng c (SLVC) 5.0Hz Nhp tn s khi ng ca ch iu khin vect khng sensor (SLVC), do SLVC

chuyn t vng h sang vng kn ti tn s .

Vng tc qua im 0

Vng kn

Vng h P1755

Vng kn

Vng h

Khi khi ng

P1755

Khu tin iu khin

Vng h/ kn

B iu khin tc

im t t thng cho vng kn

im t t thng cho vng

h Xc nh dng

in p ra thc

Gc thc

Tn s ra thc

B iu khin dng

Tn s thc

Tn s trt

M hnh tnh ton cho vng kn

im t tn s

Gii hn mmen

P1425 P1470 P1472 P1750/ P1755



53

6.4.17.2 iu khin vect c encoder (VC) Bc 1: Ci t thng s cho b encoder (xem phn 6.4.15) Khi ci t ch iu khin vect c phn hi encoder (VC), u tin nn t h truyn

ng ch V/f (xem thng s P1300). Cho chy h truyn ng v so snh r0061 vi r0021. Chng phi ging nhau v:

- du

- bin (vi sai lch nh ch bng vi %)

Ch khi p ng hai iu kin trn, thay i P1300 v chn VC (P1300 = 21/23).

Khng c kch hot chc nng d tm mt tn hiu encoder (P0492 = 0) nu mmen ti b gii hn bn ngoi., v d nh:

- iu khin vng kn my qun dy

- ti chy ngang hoc di chuyn n im dng c nh

- khi s dng phanh c kh ca ng c P1300 =21 Ch iu khin 0

21 iu khin vect c sensor P1442 = Hng s thi gian lc cho tc thc 4ms

t hng s thi gian lc ca b lc PT1 lc tc cho b iu khin tc . Vic gim gi tr ny lm tng cht lng ng ca qu trnh iu chnh tc . Nu t gi

tr thp th s gy ra s mt n nh. C th t P1422 =2 trong hu ht cc ng dng. P1460 = H s khuch i ca b iu khin tc 3.0

Nhp h s khuch i ca b iu khin tc P1462 = Thi gian tch phn ca b iu khin tc 400ms

Nhp thi gian tch phn ca b iu khin tc

Tn s t

t encoder

Tn s thc ch c tc dng nu c khu tin iu khin

Khu tin iu khin

Mmen t

San ti



54

Gi tr im t mmen b sung

ch iu khin vect c/ khng c encoder, b iu khin tc c th ph thuc vo lng mmen b sung khng i hoc bin i.

Gi tr im t b sung c th c dng h tr c cu nng h trong trng hp ma st thc t ca h thp khi khi ng theo chiu thng ng. Gi tr b sung m-men phi lun lun h tr hng nng ln (xin hy quan st du!). Nh c khi h xung, ch trt c thit lp v lm n nh thm ch iu khin vng kn (ti khng b tt nhiu).

Khi xc nh du ca gi tr im t mmen b sung, phi ch cn thn v xem xt n tt c cc quy tc an ton lin quan. C th xc nh du ca gi tr im t mmen b sung trong khu ci t nh sau: Nng ti c trng lng ti thiu s dng c cu nng v ghi li du t thng s r0079 (du ca r0079 tng ng vi du ca im t mmen b sung.

Gi tr thc nghim ca m-men b sung bng xp x 40% gi tr mmen nh mc ng c r0333 m bo hot ng tt cho c cu nng (hy quan st du cn thn).

P1511 = CI: Gi tr im t M-men b sung 0.0 Cc gi tr im t

Chn ngun gi tr im t mmen b sung. 2889 im t c nh 1 theo % 2890 im t c nh 2 theo % 755.0 u vo tng t s 1 755.1 u vo tng t s 2 2015.2 USS (ng truyn BOP) 2018.2 USS (ng truyn COM) 2050.2 CB (v d mun PROFIBUS)

Ti Kp Tn *) Ch c tc dng nu c tin iu khin SLVC: P1452 P1470 P1472 (P1496 > 0) VC: P1442 P1460 P1462

San ti

B iu khin tc PI

Khu tin iu khin

Tn s t

Tn s thc

CI : im t mmen thc

Mmen t



55

6.4.18 Cc chc nng c th ca bin tn 6.4.18.1 Khi ng bm P1200 = Khi ng bm (Flying start - FS) 0

Khi ng b bin tn khi ng c ang quay bng cch thay i nhanh chng tn s ra ca b bin tn cho n khi xc nh c tc thc ca ng c.

0 Ch FS khng c kch hot 1 Ch FS lun lun c kch hot, khi ng theo chiu im t 2 Ch FS c kch hot, nu trong trng hp c cp ngun tr li, gii tr li,

OFF2 th khi ng theo chiu im t 3 Ch FS c kch hot, nu trong trng hp gii tr li, OFF2 th khi ng theo

chiu im t 4 Ch FS lun lun c kch hot, ch theo chiu im t 5 Ch FS c kch hot, nu trong trng hp c cp ngun tr li, gii tr li,

OFF2 th ch khi ng theo chiu im t 6 Ch FS c kch hot, nu trong trng hp gii tr li, OFF2 th ch khi ng theo

chiu im t P1202 = 100%

Dng ng c trong ch khi ng bm (tnh theo %) Xc nh dng in tm kim cho ch khi ng khi ng c ang quay.

P1203 =? Di tm kim trong ch khi ng bm (tnh theo %) 100% t h s tn s ra thay i theo trong ch khi ng khi ng c ang quay ng b

vi ng c ang quay.

6.4.18.2 T khi ng P1210 = T khi ng 1 t cu hnh chc nng t khi ng 0 Khng tc dng 1 Li c gii tr sau khi cp ngun tr li 2 Khi ng li sau s c mt ngun 3 Khi ng li sau s c thp p li hoc cc li khc 4 Khi ng li sau s c thp p li 5 Khi ng li sau s c mt ngun v cc li khc 6 Khi ng li sau s c thp p/ mt ngun hoc li khc



56

6.4.18.3 Phanh hm c kh ca ng c Ci t cho cc ti nguy him

- H ti xung t - Khi thay b bin tn, khng b bin tn thc hin chc nng iu khin phanh hm ng c - m bo an ton cho ti trng hoc dng hn vic iu khin ch hm ng c ( b hm khng b iu khin), ri sau mi thc hin ci t nhanh v/hoc ti thng s xung nh cng c trn PC (v d nh phn mm STARTER hay AOP)

Ci t thng s cn bng trng lng i vi cc ng dng nng h - Thi gian t ho P0346 ln hn 0. - Tn s nh nht P1080 nn gn bng tn s trt ca ng c r0330 (P1080 r0330). - Hiu chnh in p b tng theo ti. a) V/f (P1300 = 03): P1310, P1311 b) SLVC (P1300 = 20): P1610, P 1611

Khng nu ch chn tn hiu trng thi r0052 bit 12 phanh hm ng c c kch hot gn cho P0731- P0733. Ngoi ra kch hot phanh hm ng c, thng s P1215 phi c t 1.

Khng c php dng phanh hm ng c lm phanh hot ng thng xuyn. V phanh ny thng thng ch c thit k cho mt s lng gii hn s ln phanh khn cp.

Thi gian ng/m phanh c th c ly t ti liu th nghim ph hp. Cc gi tr in hnh di y c ly t ti liu th nghim Motor Catalog M11 2003/2004, trang 2/51:

C ng c Kiu phanh Thi gian m [ms] Thi gian ng [ms]

63 2LM8 005-1NAxx 25 56 71 2LM8 005-2NAxx 25 56 80 2LM8 010-3NAxx 26 70 90 2LM8 020-4NAxx 37 90 100 2LM8 040-5NAxx 43 140 112 2LM8 060-6NAxx 60 210 132 2LM8 100-7NAxx 50 270 160 2LM8 260-8NAxx 165 340 180 2LM8 315-0NAxx 152 410 200 225 2LM8 400-0NAxx 230 390

P1215 = BI: Kch hot phanh hm ngoi 0

0 Phanh hm ng c hot ng 1 Phanh hm khng hot ng CH Mun iu khin phanh hm bng u ra

r le s th:P0731 = 52.C (=52.12) (hy xem phn 6.4.4 "Cc u ra s (DOUT)").



57

P0731=52.C BI: Chc nng u ra s s 1 52.3 Cc ch ci t thng thng

Xc nh ngun ca u ra s s 1 52.0 Sn sng cp ngun 0 ngCH 52.1 Sn sng chy 0 ng

52.2 H truyn ng ang chy 0 ng 52.3 Kch hot ch pht hin li 0 ng

52.4 Phm OFF2 hot ng 1 ng 52.5 Phm OFF3 hot ng 1 ng 52.6 Kho chuyn mch khng c

hot ng 0 ng

52.7 Ch cnh bo hot ng 0 ng

Cng c th iu khin rle phanh t u ra s khc (nu c). Tng t nh DOUT1, nn m bo rng I/Os c iu khin bng bit trng thi "MHB c kch hot"

52.8 chnh lch gia gi tr im t v gi tr thc t

1 ng

52.9 iu khin PLC/PZD 0 ngP0748 = 0 o cc u ra s 0 52.A Tn s ln nht t dc 0 ng Thng s ny cho php o cc tn

hiu ra 52.B Cnh bo: Gii hn dng in ca

ng c 1 ng

52.C Phanh hm ng c hot ng 0 ng

52.D ng c qu ti 1 ng

52.E Chiu quay ca ng c, cng chiu kim ng h

0 ng

52.F Qu ti bin tn 1 ng 53.0 Mun hm DC hot ng 0 ng 53.1 Tn s thc f_act > P2167 (f_off) 0 ng

:

Thi gian tr nh phanh (n v s) 1.0s

P1216 = Thi gian tr nh phanh (n v s) 1.0s Xc nh khong thi gian m b bin tn chy vi tn s nh nht P1080 sau khi t

ho v trc khi bt u tng tc.

P1216 thi gian m phanh + thi gian m rle P1217 = Thi gian hm sau khi gim tc (n v s) 1.0s Xc nh thi gian b bin tn chy tn s nh nht (P1080) sau khi gim tc P1217 thi gian ng phanh + thi gian ng rle

Knh DOUT

Chc nng xxxx.y

Bin i DOUTs

Rle:

CO/BO: DOUTs trng thi

- thi gian ng / m ln nht



58

6.4.18.4 Hm mt chiu (DC) P1230 = BI: Kch hot hm DC

Thng s ny cho php hm DC hot ng s dng tn hiu ly t ngun ngoi. Chc nng ny c duy tr vi iu kin tn hiu bn ngoi c kch hot. Hm DC lm cho ng c dng nhanh bng cch bm dng DC vo ng c

Ch : C th dng hm DC khi bin tn cc trng thi r0002 = 1,4,5 P1232 = Dng hm DC (theo %) 100%

Xc nh mc dng hm DC theo % tng ng vi dng in nh mc ca ng c (P0305).

P1233 = Thi gian hm DC 0s Xc nh khong thi gian m hm bng dng DC c kch hot sau lnh OFF1 hoc OFF3.

Hm DC

Hm DC hot ng

f_t

f_thc

BI: Kch hot hm DC

Hm DC hot ng

Hm DC



59

P1234 = Tn s bt u phanh DC (n v Hz) 650Hz t tn s bt u phanh DC.

6.4.18.5 Hm hn hp P1236 = Dng in cho hm hn hp (theo %) 0%

Xc nh mc dng in DC t ln trn sng AC sau khi vt qu ngng in p DC t cho hm hn hp. Gi tr dng nhp theo [%] tng ng vi dng in nh mc ca ng c (P0305). (hy xem phn 6.4.12). Nu P1254 = 0 :

Ngng in p t cho hm hn hp UDC_Comp = 1,13 x 2 Vmains = 1,13 2 P0210 Hoc: Ngng in p t cho hm hn hp UDC_Comp = 0,98.r1242 P1236 = 0 P1236 > 0 Khng c hm hn hp C hm hn hp

Phanh

dc OFF

Phanh DC hot ng

DC

f_thc t f_thc t

f_t f_t

Thng 7/05 6 Ci t thng

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113902035-biến-tần-siemens-MM440