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Combinational Circuit Design and Simulation Using Gates. 3 Input NAND GATE. Combinational Circuit Design and Simulation Using Gates. Introduction to Digital Integrated Circuits. V CC , Power Supply Voltage Voltage supplied to integrated circuit, Nominal V CC is +5V - PowerPoint PPT Presentation
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3 Input NAND GATE
Combinational Circuit Design and Simulation Using Gates
VCC, Power Supply Voltage• Voltage supplied to integrated circuit, Nominal VCC is +5V
ICCH, Power Supply Current • Supply current required to operate IC, Output logic is “1”
ICCL, Power Supply Current • Supply current required to operate IC, Output logic is “0”
IOS, Short Circuit Output Current • Amount of current TTL output circuit can deliver into S.C
IOL, Output Current Low • Maximum output terminal sink current, Output logic is “0”
IOH, Output Current High • Maximum output terminal source current, Output logic is “1”
IIH, Current Input High • Maximum current at input terminal, Input logic is “1”
Introduction to Digital Integrated Circuits
Combinational Circuit Design and Simulation Using Gates
IIL, Current Input Low• Maximum input current, Input voltage logic is “0”
VOL, Voltage Output Low • Maximum allowable output voltage, Output logic is “0”
VOH, Voltage Input High• Minimum output voltage, Output logic is “1”
VIH, Voltage Input High• Minimum logical 1 input voltage, VIH is 2 V
VIL, Voltage Input Low• Maximum logical 1 input voltage, VIL is 0.8 V
tpLH, Propagation delay time • From Output “Low” to “High”
tpHL, Propagation delay time • From Output “High” to “Low”
Introduction to Digital Integrated Circuits
Combinational Circuit Design and Simulation Using Gates
Introduction to Digital Integrated Circuits
Signal Delay Times
2 Input NAND(74xxx00) Parameter Values
Introduction to Digital Integrated Circuits
A.L=w’z+x’yz’
C.L=wx’y’z’
D.L=xy’z+w’z+x’yz’
E.L=z+x’y
B.L=xy’z’+x’yz
F.L=wx’y’+y’z
G.L=xy’z+w’
3 input NAND
4 input NAND
2 input NANDINV
Consider power consumption and switching speed P=(ICCave)(VCC), assume VCC=5 V
74LS00, 74LS10, 74LS20, and 74LS04
LD00 LS10 LS20 LS04ICCH 0.8mA 0.6mA 0.4mA
1.2mAICCL 2.4mA 1.8mA 1.2mA
3.6mAICCave 1.6mA 1.2mA 0.8mA
2.4mA Total average supply current is found
ICCave = 8(1.6)+6(1.2)+2(0.8)+6(2.4)=36mA
P=5.0V(36mA)=180mW
Introduction to Digital Integrated Circuits
Power Consumption Considerations