Embed Size (px)
DESCRIPTION
AMPLIFIERS. Presenter : 王智偉 Advisor : Chih-Kuo Liang. Outline. NONINVERTING SUMMING AMPLIFIER AC-COUPLED AMPLIFIER CURRENT AMPLIFIER HIGH-CURRENT AMPLIFIER. R F. R I. R out. R in. V O. A OL. V I. NONINVERTING SUMMING AMPLIFIER. Numerical Analysis Voltage Gain. 2.7kΩ. 3.9kΩ. - PowerPoint PPT Presentation
Citation preview
AMPLIFIERS
Presenter :王智偉 Advisor : Chih-Kuo Liang
OutlineNONINVERTING SUMMING AMPLIFIERAC-COUPLED AMPLIFIERCURRENT AMPLIFIERHIGH-CURRENT AMPLIFIER
NONINVERTING SUMMING AMPLIFIER
Numerical Analysis Voltage Gain
1I
FV R
RA
RI RF
Rin
Rout
AOL
VI
VO
2.7kΩ 3.9kΩ
=3.9k/2.7k +1
=2.44 3.25v
(2.28)
NONINVERTING SUMMING AMPLIFIER
Output Voltage
I
OV V
VA
IV VAVo
=2.44*3.25 V
=7.93 V
(2.1)
AC-COUPLED AMPLIFIER
Voltage Gain
I
FV Z
RA
CXRZ 22
fcX C 2
1
Rf
RIVI
CI
0.02uF27k
68k
-+
Co
0.02uF
RL39kΩ
(2.37)
AC-COUPLED AMPLIFIER
CXRZ 22 fc
X C 21
Xc=1/(62.8*800 Hz*0.02uF)
=9.95kΩ
22 95.927 Z
=28.8kΩ
AC-COUPLED AMPLIFIER
I
FV Z
RA
=-(68 kΩ/28.80kΩ)
=-2.4
Bandwidth
=(1 MHz*27 kΩ)/(68 kΩ+27 kΩ)
=284 kHz
(2.37) (2.40)IF
IUGu RR
Rff
AC-COUPLED AMPLIFIER
RCfC 2
1
=1/(6.28*27 kΩ*0.02 uF)
=295 Hz
2
1
fcfc
index
=295 Hz/204 Hz
=1.45
(2.41) (2.42)
AC-COUPLED AMPLIFIER
kff CL
=295 Hz*1.32
=389 Hz
LU ffbw
=284 kHz-389 kHz
=283.6 kHz
(2.43)
CURRENT AMPLIFIER
Numerical Analysis Current Gain
11
2 RRAgaincurrent I
-+
I1
I1
R1
R2
1 kΩ
56 kΩ RL 3 kΩ
IL
=56 kΩ/1 kΩ+1
=57 10~50uF
(2.45)
CURRENT AMPLIFIER
IIL Aii (min)(min) IIL Aii (max)(max)
=10 uA*57
=570uA
=50 uA*57
=2.85 mA
CURRENT AMPLIFIER
Numerical Analysis Range of Acceptable Input Currents
LL
SATL RRRRR
VRi
221
1
)((max)
=(1 kΩ*13 V)/〔 1 kΩ(56 kΩ+3 kΩ)+(56 kΩ*3 kΩ)〕=57.3 uA
(2.46)
CURRENT AMPLIFIER
Numerical Analysis Maximum Load Resistance
III
SATL A
RiA
VR 2(max)
=13 V/(57*50 uA)-56 kΩ/57
=3.58 kΩ
CURRENT AMPLIFIER
Numerical Analysis Input Resistance
21
21
2
)1()(
RRRRR
RARRRRR
X
LVX
LXIN
(2.47)
CURRENT AMPLIFIER
LVX
LXIN RAR
RRRR
)1()(2
21
21
RRRRRX
=(1.0 kΩ*56 kΩ)/(1.0 kΩ+56 kΩ)
=982 Ω
=〔 56 kΩ(982 Ω+3 kΩ)〕 /〔 982 Ω(1+50000)+3 kΩ〕
=4.54 Ω
(2.47)
CURRENT AMPLIFIER
Numerical Analysis Output Resistance
XV RARo =50000*982 Ω
=49.1 MΩ
(2.48)
HIGH-CURRENT AMPLIFIER
Numerical Analysis
-+
+ V5kΩ
RP
RB 22kΩVI
22uF 27kΩ
CI RI
RF
220kΩ
RL 4Ω
+15V
LL RR '
=750*4
=3000 Ω
Vo
(MJE1103)(2.49)
HIGH-CURRENT AMPLIFIER
BESAT VVpeakVo )(
=10 V-2.5 V
=7.5 V
))(()(L
L RspeakVospeaki
=7.5 V/4 Ω
=1.88 A
(2.50)
HIGH-CURRENT AMPLIFIER
L
Oiampopi )(
=1.88 A/750
=2.51 mA
(2.51)
HIGH-CURRENT AMPLIFIER
2)( BESAT
BIASVV
outputV
=(10 V+2.5 V)/2
=6.25 V
BESAT VVampopVo ) (=10 V-2.5 V
=7.5 V peak-to-peak
(2.52)
HIGH-CURRENT AMPLIFIER
HIGH-CURRENT AMPLIFIER
I
FV R
RA
=-(220 kΩ/27 kΩ)
=-8.15
(2.6)
HIGH-CURRENT AMPLIFIER
V
O
I
OV A
Vor
RV
A(max)
(max)V I
=7.5/8.15
=0.92 V peak-to-peak
(2.1)
Thanks for your attention
