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Nguyeãn Duy Khanh TN MAÏCH ÑIEÄN I BAÙO CAÙO THÍ NGHIEÄM BAØI 13: MAÏCH LOÏC ÑIEÄN THUÏ ÑOÄNG I. Maïch loïc thoâng cao R-L: 1. Maïch thí nghieäm: Duøng maùy phaùt soùng choïn soùng sin coù bieân ñoä 2V, taàn soá 1Khz, offset laø 0, taïo nguoàn kích thích cho ngoõ vaøo cuûa maïch. (Dao ñoäng kyù choïn Time/Base (Time/Div) = 0,2 ms hoaëc 0,1 ms) 2. Xaùc ñònh caùc ñaëc tuyeán bieân – taàn, pha – taàn: - Ñaëc tuyeán bieân - taàn: Trang 40

Bai13_Mach Loc Dien Thu Dong

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TRNG HBK TP

Nguyen Duy Khanh

TN MACH IEN I

BAO CAO TH NGHIEM

BAI 13: MACH LOC IEN THU ONGI. Mach loc thong cao R-L:

1. Mach th nghiem:

Dung may phat song chon song sin co bien o 2V, tan so 1Khz, offset la 0, tao nguon kch thch cho ngo vao cua mach.

(Dao ong ky chon Time/Base (Time/Div) = 0,2 ms hoac 0,1 ms)2. Xac nh cac ac tuyen bien tan, pha tan:

- ac tuyen bien - tan:

- ac tuyen pha tan:

3. Tan so cat cua mach loc:

ac tuyen bien o cua mach (K(j()( cho ta thay ay la mang 2 ca co tnh loc ien. Tan so cat cua mach loc la tan so ma o mach chuyen t dai thong sang dai chan, c xac nh khi (K(j()( = (K(j()(max. Khi o o suy hao bien o se co gia tr tng ng vi K(j() = -3,03dB va tan so cat xac nh c la fc = 1,58Khz.

Theo ly thuyet: v (K(j()(max = 1

=> (C =

=> fC = = = 1,591 Khz.

Ta thay tan so cat o c ten th nghiem gan bang vi tnh toan theo ly thuyet. Co sai so rat nho trong th nghiem.

4. o lech pha cua hai tn hieu vao va ra cua mach loc tai tan so cat, nhan xet:

Tai tan so cat fc = 1,58Khz, ta xac nh c o lech pha nh sau:

b = 2,743

Y0 = 1,996

Goc lech pha c xac nh bang cong thc:

Sin ( = = = 0,7276 => ( = 46,70Theo ly thuyet: tai ( - (C = 2(f ta co:

.j(L;

Vi (CL = 2(.1,591.103.10.10-3 = 99,965 ( 100

Gia s

=>

.j(L = => ( = 450

= => ( = -450

T gian o vec t ta thay tn hieu ra nhanh pha 450 so vi tn hieu vao.

=> Ket qua Ly thuyet va thc nghiem phu hp nhau.

5. Thiet ke bo loc thong cao, dung mach R-L, co tan so cat fC = 3Khz, biet gia tr L = 2mH.

fC = => R = 2fCL = 2.3.103. .2.10-3 = 37,68 (

II. Mach loc thong dung R-C:

1. Mach th nghiem:

Dung may phat song chon song sin co bien o 2V, tan so 1Khz, offset la 0, tao nguon kch thch cho ngo vao cua mach.

2. Ve gian o Bode, xac nh cac ac tuyen bien tan va pha tan, tan so cat cua mach loc.

- ac tuyen bien tan:

- ac tuyen pha tan:

3. Tan so cat cua mach loc.

- Theo ly thuyet: Ham truyen mach co dang:

K(j() = = =

ac tuyen bien o theo tan so cho ta ay la mot mach loc thong thap, va tan so cat cua mach loc cung c xac nh t:

((CRC)2 = 1 => (C = => fC = = = 159,2 Hz.

- o bang thc nghiem: khi K(j() = -3,02dB, tan so cat o c 160Hz.

=> Ket qua Ly thuyet va thc nghiem phu hp nhau.

4. o lech pha cua hai tn hieu vao va ra cua mach loc tai tan so cat, nhan xet:

b = 1,998V

Y0 = 2,82V

Goc lech pha c xac nh bang cong thc:

Sin ( = = = 0,7085 => ( = 45,10Theo ly thuyet: tai (C = 2(fC = 2(.160= 1005 ( 1000 (rad/s)

=> = = 100

Gia s

= =

=

Ta ve c gian o vec t:

Qua gian o ta thay tn hieu ra cham pha hn 450 so vi tn hieu vao.=> Ket qua Ly thuyet va thc nghiem phu hp nhau.

5. Thiet ke bo loc thong thap, dung mach R-C, co tan so cat fC = 1,7Khz, biet gia tr C = 0,01(F.

fC = => R = = = 9,366.103 ( = 9,366 K(

III. Mach loc thong dai R-L-C:

1. Mach th nghiem:

Dung may phat song chon song sin co bien o 2V, tan so 1Khz, offset la 0, tao nguon kch thch cho ngo vao cua mach.

2. Ve gian o Bode, xac nh cac ac tuyen bien tan va pha tan cua mach loc. Xac nh tan so trung tam, bang thong va he so pham chat cua mach loc.

- ac tuyen bien tan:

- ac tuyen pha tan:

* Theo ly thuyet:

Ham truyen at ien ap cua mach:

K(j() =

Va ta co:

(K(j()( =

(K(j()( se at cc ai tai (C = c goi la tan so trung tam cua mach loc thong dai. Khi o gia tr (K(j()( at cc ai la 1. Bang thong cua mach loc c xac nh khoang ma (K(j()( ( 0,707.

BW = (2 - (1 = = = 9090,91

- He so pham chat:

Q = = 2,19

f0 = = 3183 Hz = 3,183 Khz.

- Hai tan so cat la nghiem cua phng trnh:

=

=> 2L2 = - = 0 [ - ][ + ] = 0

- = 0

=>

+ = 0

(2LC - ( - 1 = 0

(2LC + ( - 1 = 0

(loai)

(loai)

= 2,458.104 (rad/s); = 7,75.104(rad/s)

=> f1 = 2,467 Khz; f2 = 3,912 Khz

* Ket qua thc nghiem:

- mach nay ta xac nh c 2 gia tr tan so cat:

f1 = 2,51Khz; f2 = 3,98Khz.

- Tan so trung tam: f0 = 3,16 Khz.

- Bang thong:

BW = (2 - (1 = 2(( f2 - f1) = 2((3,98 2,51).103 = 9236,3 (rad/s)

- He so pham chat:

Q = = 2,15

* Ta nhan thay ke qua ly thuyet va thc nghiem la tng oi nh nhau, co sai so nho do phep o.

6. Dung dao ong ky xac nh o lech pha cua hai tn hieu vao va ra cua mach loc tai tan so cat, nhan xet:

* Tai fC1 = 2,51Khzo c:

b = 2,724;

Y0 = 1,999

Goc lech pha: sin( = = 0,733=> ( = 47,20

* Tai fC2 = 3,98 Khz o c:

b = 2,972;

Y0 = 1,998

Goc lech pha: sin( = = 0,672 => ( = 42,20

* Tai fC0 = 3,16 khz o c:

b = 4;

Y0 = 0,2

Goc lech pha: sin( = = 0,05=> ( = 2,8660

Theo ly thuyet, tai fC0 th ien ap vao trung pha vi ien ap ra, nhng thc te o c lec nhau 2,8660. Nguyen nhan do sai so phep o. o lech pha tai 2 tan so cat gan bang nhau.

7. Thiet ke bo loc thong dai, dung mach R-L-C, f = 1200Hz ( 2700Hz, biet gia tr C = 0,022(F.

- Xac nh bang thong:

BW = (2 - (1 = 2((f2 f1) = 2((2700 1200) = 9420 (rad/s)

- Xac nh tan so trung tam:

f0 = = =1950 Hz

- Xac nh L:

f0 = => L = = 0,3H

- Xac nh R:

BW = => R = = = 768,4 (

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